Answer:
c.20
Explanation:
An inventor claims to have developed a heat pump that produces 200 kW of heating for a 293 K heated zone whilst only using 75 kW of power and a heat source at 273 K. Using the max. theoretical efficiency of this device, justifythe validity of this claim. [5]
Answer:
Answer is 14.65
Refer below.
Explanation:
Refer to the picture for brief explanation.
How many times does lightning strike the empire state building
Answer:
Lightning strikes the empire state building at an average of about 23 times a year.
Explanation:
The Empire State Building is one of the tallest buildings in New York. Because of how high it stretches up into the sky, lightning strikes are quite common to it. This is because part of the building touches the clouds which are usually charged during thunder storms.
According to weather reports, and the Empire State Building website, lightning strikes the empire state building about 23 times a year on the average.
Two people are sitting on playground swings. One is pulled back 4 degrees from the vertical and the other is pulled back 8 degrees. They are both released at the same instant. Will they both come back to their starting points at the same time
Answer:
They will come back at the same time.
Explanation:
The angular velocity equation of ω[tex]= \frac{V}{r}[/tex] where ω is the frequency of the movement, dependent on the angle. But since swings are simple pendulums and their angles of 8 and 4 degrees are small, they will come back to their starting points at the same time.
I hope this answer helps.
Answer:
The bodies will not come back to their starting point at he same time.
Explanation:
Since they are both pulled back at an angle to the vertical, there is a tangential component of acceleration a = gsinθ
When θ = 4 , a = 9.8sin4 = 0.684 m/s²
When θ = 8 , a = 9.8sin8 = 1.364 m/s²
Using s = ut + 1/2at². Where s is the distance covered and t = time taken, u = initial speed = 0 (assumed since they are both released at the same time)
So s = 0 × t + 1/2at² = 1/2at²
s = 1/2at²
t = √2s/a. Now, since s is the same for both swings, it follows that
t ∝ 1/a. Since their accelerations are different, the bodies will not come back to their starting point at he same time.
What percentage of the intensity gets through both polarizers?
Answer:
if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero
Explanation:
The incident light is generally random, that is, it does not have a polarization plane, when the first polarized stops by half, this already polarized light arrives at the second polarizer and the causticity passes
I = I₀ cos² θ
therefore if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero
A horizontal wooden beam sags a bit when supported at its ends. In between the top and bottom surfaces is a region of
Answer: neither tension nor compression
Explanation:
The tension in the form of load or forces
And also compression in the form of weight or load since the sagging is negligible as interpreted from the question which say that - horizontal wooden beam sags a bit when supported at its ends.
What would you be most likely to find if you returned to the solar system in 10 billion years?
Answer:
a white dwarf
Explanation:
A white dwarf, is otherwise known as a degenerate dwarf, it is a stellar core remnant which is mostly composed of electron-degenerate matter. A white dwarf is very dense, and has a mass which is comparable to that of the Sun, while its volume is comparable to that of Earth. It faint luminosity comes from the emission of stored heat energy; and no fusion takes place in a white dwarf
In 10 billion years, the solar system would be unrecognisable. The Sun would have become a white dwarf after expanding as a red giant.
If you returned to the solar system in 10 billion years, you'd likely find a vastly different environment from today. Given the current understanding of stellar evolution, the Sun, which is currently a main-sequence star, would have exited this phase. After going through a red giant phase, where it would have engulfed the inner planets, the Sun would have lost most of its outer material, leaving behind a white dwarf. This white dwarf would eventually cool and fade over time, becoming a black dwarf. Surrounding planetary bodies might be destroyed, transformed, or ejected from the solar system altogether due to the Sun's changes and the gravitational influences of other celestial bodies over such a vast period.
In this older universe, new star systems may have formed within the Milky Way from the abundant materials available in the galaxy. However, it's challenging to predict the exact state of the solar system due to numerous factors including potential asteroid impacts, close encounters with passing stars, or even interactions with interstellar objects. One thing is certain: the solar system as we know it will have undergone significant changes.
A wheel 1.70 m in diameter lies in a vertical plane and rotates about its central axis with a constant angular acceleration of 3.60 rad/s2. The wheel starts at rest at t = 0, and the radius vector of a certain point P on the rim makes an angle of 57.3° with the horizontal at this time. At t = 2.00 s. What is the tangential speed, total acceleration, and angular position of point P.
Final answer:
To calculate the tangential speed, total acceleration, and angular position of point P on the wheel at t = 2.00 s, we can use the formulas for tangential speed, total acceleration, and angular position. By substituting the given values into these equations, we can find the required values.
Explanation:
To calculate the tangential speed of a point on the wheel, we can use the formula:
Tangential Speed = Angular Velocity x Radius
In this case, the angular velocity is given by the equation:
Angular Velocity = Initial Angular Velocity + (Angular Acceleration x Time)
Substituting the given values and solving the equations, we can find the tangential speed, which is the speed of the point P on the rim at time t = 2.00 s.
To find the total acceleration, we can use the formula:
Total Acceleration = Tangential Acceleration + Radial Acceleration
The tangential acceleration can be calculated using the equation:
Tangential Acceleration = Angular Acceleration x Radius
The radial acceleration can be calculated using the equation:
Radial Acceleration = (Angular Velocity x Angular Velocity) x Radius
By substituting the given values into these equations, we can find the total acceleration at time t = 2.00 s.
To find the angular position of point P at time t = 2.00 s, we can use the equation:
Angular Position = Initial Angular Position + (Initial Angular Velocity x Time) + (0.5 x Angular Acceleration x Time x Time)
Substituting the given values, we can find the angular position of point P at t = 2.00 s.
Which element is the most prevalent in the human body?
nitrogen
hydrogen
carbon
oxygen
The most prevalent in the human body by mass is oxygen.
To find the answer, we need to know more about the elemental composition in human body.
What is the elemental composition in human body?The element that is most prevalent in the human body by mass is oxygen. This makes sense if you think about it because the majority of the human body is made up of water, or H2O. The bulk of the human body is composed of 61–65% oxygen. Your body has considerably more hydrogen than oxygen atoms, but each oxygen atom is 16 times heavier than a hydrogen atom.The second prevalent element in the body is carbon. It is about 18%.Thus, we can conclude that, the most prevalent in the human body by mass is oxygen.
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Answer:B I think
Explanation:
A horizontal spring is lying on a frictionless surface. One end of the spring is attaches to a wall while the other end is connected to a movable object. The spring and object are compressed by 0.080 m, released from rest, and subsequently oscillate back and forth with an angular frequency of 12.1 rad/s. What is the speed of the object at the instant when the spring is stretched by 0.041 m relative to its unstrained length
Final answer:
To determine the speed of an object attached to a horizontally lying spring on a frictionless surface at a specific stretch, we apply the law of conservation of energy and calculate the distribution of potential and kinetic energy at that point.
Explanation:
The subject of this question is Physics, and it involves a concept known as simple harmonic motion(SHM). To find the speed of the object at the instant when the spring is stretched by 0.041 m relative to its unstrained length, we can use the law of conservation of energy. In SHM, the total mechanical energy (sum of potential and kinetic energy) is conserved if there is no energy loss due to friction or other non-conservative forces.
At the compressed position (0.080 m from equilibrium), all the energy is potential, given by Ep = 1/2 k x2, where k is the spring constant and x is the displacement from equilibrium. At the position where the spring is stretched by 0.041 m, the energy will be partly potential and partly kinetic. The potential energy at this point is Ep = 1/2 k (0.041 m)2 and the kinetic energy is Ek = 1/2 m v2, where m is the mass and v is the velocity of the object.
Conservation of energy gives us:
1/2 k (0.080 m)2 = 1/2 k (0.041 m)2 + 1/2 m v2.
We can solve this equation for v, the speed at 0.041 m stretch, knowing the values of k, m, and x.
The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the decibel scale is logarithmic, it changes by an additive constant when the intensity as measured in W/m2 changes by a multiplicative factor. The number of decibels increases by 10 for a factor of 10 increase in intensity. The general formula for the sound intensity level, in decibels, corresponding to intensity I is
β=10log(II0)dB,
where I0 is a reference intensity. For sound waves, I0 is taken to be 10−12W/m2. Note that log refers to the logarithm to the base 10.
Part A) What is the sound intensity level β, in decibels, of a sound wave whose intensity is 10 times the reference intensity (i.e., I=10I0)?
Part B) What is the sound intensity level β, in decibels, of a sound wave whose intensity is 100 times the reference intensity (i.e. I=100I0)?
Express the sound intensity numerically to the nearest integer.
β = dB
One often needs to compute the change in decibels corresponding to a change in the physical intensity measured in units of power per unit area. Take m to be the factor of increase of the physical intensity (i.e., I=mI0).
Part C) Calculate the change in decibels ( Δβ2, Δβ4, and Δβ8) corresponding to m=2, m=4, and m=8.
Give your answers, separated by commas, to the nearest integer--this will give an accuracy of 20%, which is good enough for sound.
Answer:
a) 10 dB, b) 20dB, c) 10², 10⁴, 10⁸
Explanation:
The logarithmic scale has a great advantage when measuring magnitudes of a large number of scales, since it converts these values to linear, allowing easier viewing.
Part A
Let's look for decibels for an intensity I = 10 Io
We calculate
β = 10 log (10Io / Io)
β = 10 dB
Part b
Let's find the intensity for I = 100 Io
We calculate
β = 10 log (100Io / Io)
β = 10 log 100
β = 10 2
β = 20 db
Part c
Δβ2 corresponds to an intensity change of 10² Io, therefore it corresponds to an intensity increase of 10²
Δβ4 corresponds to a change in intensity of 10⁴Io
Δβ8 is an intensity change of 10⁸ Io
The sound intensity level in decibels can be calculated using the formula β = 10log(I/I_0). For a sound wave with intensity 10 times the reference intensity, the sound intensity level is 10 dB. For a sound wave with intensity 100 times the reference intensity, the sound intensity level is 20 dB.
Explanation:Part A: To find the sound intensity level when the intensity is 10 times the reference intensity, we use the formula β = 10log(I/I_0). Plugging in the values, β = 10log(10I_0/I_0) = 10log(10) = 10 x 1 = 10 dB.
Part B: Similarly, when the intensity is 100 times the reference intensity, we get β = 10log(100I_0/I_0) = 10log(100) = 10 x 2 = 20 dB.
Part C: To calculate the change in decibels for different intensities (m), we use the formula Δβ = 10log(m). For m = 2, Δβ2 = 10log(2) = 10 x 0.3 = 3 dB. For m = 4, Δβ4 = 10log(4) = 10 x 0.6 = 6 dB. And for m = 8, Δβ8 = 10log(8) = 10 x 0.9 = 9 dB.
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what is the solvent in air
Answer:
The majority component is the solvent so In the air nitrogen is found more.
So Nitrogen is the solvent in air.
Try to have the equipotential lines equally spaced in voltage. Then, use an E-Field Sensor to measure the electric field at a few points while looking at the relationship between the electric field and the equipotential lines.
Which of the following statements is true?
1.The electric field strength is greatest where the voltage is the smallest.
2.The electric field strength is greatest where the equipotential lines are very close to each other.
3.The electric field strength is greatest where the voltage is the greatest.
Answer:
2 The electric field strength is greatest where the equipotential lines are very close to each other.
Explanation:
Equipotential lines are contour lines which trace the lines of identical altitudes. In physics, they trace out lines of equal electric potential or voltage.
Equipotential lines are always perpendicular to the electric field. The closer the equipotential lines to each other, the greater the strength of the electric field.
Technician A says that if the yellow warning lamp is illuminated indicating a fault in the electronic brake control system, you should retrieve the diagnostic trouble codes and follow the procedure listed in the service information. Technician B says that once the fault has been corrected, clear the diagnostic code and verify that it does not reset. Who is correct?
A)A only
B)B only
C)Both A and B
D)Neither A nor B
Answer: C) Both A and B
Explanation:
The ABS system is disabled when the ABS yellow warning lamp is on. And when the warning lamp is on the base brake system will work normally but without ABS function
And if the yellow warning lamp is illuminated indicating a fault in the electronic brake control system, you should retrieve the diagnostic trouble codes and follow the procedure listed in the service information. Once the fault has been corrected, clear the diagnostic code and verify that it does not reset
The voltage V in a circuit that satisfies the law V = IR is slowly dropping as the battery wears out. At the same time, the resistance R is increasing as the resistor heats up. Use the equation dV dt = ∂V ∂I dI dt + ∂V ∂R dR dt to find how the current I is changing at the instant when R = 600 ohms, I = 0.04 amps, dR/dt = 0.5 ohms/sec, and dV /dt = −0.01 volts/sec. Hint: We need to find the rate of change of I, with respect to time. Find the partial derivatives of V with respect to I and R, then substitute into the equation for dV /dt.
Answer:
[tex]-0.5\times 10^{-4} A/s[/tex]
Explanation:
We are given that
[tex]\frac{dV}{dt}=-0.01 V/s[/tex]
R=600 ohms
I=0.04 A
[tex]\frac{dR}{dt}=0.5ohm/s[/tex]
[tex]V=IR[/tex]
[tex]\frac{dV}{dt}=\frac{\partial V}{dI}\frac{dI}{dt}+\frac{\partial V}{dR}\frac{dR}{dt}[/tex]
[tex]\frac{dV}{dt}=R\frac{dI}{dt}+I\frac{dR}{dt}[/tex]
Substitute the values
[tex]-0.01=600\times \frac{dI}{dt}+0.04\times 0.5[/tex]
[tex]-0.01-0.04\times 0.5=600\frac{dI}{dt}[/tex]
[tex]-0.03=600\frac{dI}{dt}[/tex]
[tex]\frac{dI}{dt}=\frac{-0.03}{600}=-0.5\times 10^{-4}A/s[/tex]
Final answer:
The student's question concerns finding the rate of change of current in a circuit as described by Ohm's law. By finding partial derivatives of the voltage with respect to current and resistance and applying the provided rates, you solve for the rate of change of current.
Explanation:
The student is asking how the current I is changing over time in a circuit with a given resistance R, current I, and rates of change dR/dt and dV/dt according to Ohm's law. To solve this, we need to find the partial derivatives of voltage V with respect to current I and resistance R, and then use the given differential equation dV dt = ∂V ∂I dI dt + ∂V ∂R dR dt.
Using Ohm's law, we can express the voltage as V = IR. The partial derivative of V with respect to I is R, and with respect to R is I. Substituting these derivatives and the given values into the differential equation, we have: -0.01 = 600 dI dt + 0.04 * 0.5. Solving for dI dt, we get the rate at which the current is changing over time, which is the answer the student is looking for.
Which kind of storm do you think would cause damage over a larger area A cyclone or a tornado why
Answer:
becuase it is big
Explanation:
A British bicycle light company advertises flashing bicycle lights that require no batteries and produce no resistance to riding. A magnet attached to a spoke on the bicycle tire moves past a generator coil on the bicycle frame, inducing an emf that causes a light to flash. The magnet and coil never touch. Does this lighting system really produce no resistance to riding? Justify your answer.
Answer:
Lenz's law is responsible for the resistance to advance due to the change in magnetic flux
Explanation:
This system produces electricity by Faraday's law,
E = - d / dt B.A
Where the electromotive force is generated by the change of the field strength maintained due to the circular movement of the wheel.
As this field changes when Lenz's law increases or decreases, it creates a field that opposes this change, this field is applied to the bicycle and is in the opposite direction to movement, so it is an effect that creates resistance to the advance of the bike.
In summary Lenz's law is responsible for the resistance to advance due to the change in magnetic flux
A 375-g stone hangs from a thin light string that is wrapped around the circumference of a pulley with a moment of inertia of 0.0125 kg ∙ m2 and a radius of 26 cm. When the stone is released, the stone accelerates downward and the pulley rotates about its axis as the string unwinds. What is the magnitude of the acceleration of the stone in m/s2 ?
Answer:
The magnitude of the acceleration of the stone is 19.87 m/s²
Explanation:
Given;
mass of stone, m = 375 g = 0.375 kg
moment of inertia, I = 0.0125 kg.m²
radius of the pulley, r = 26 cm = 0.26 m
Torque generated by the pulley on the stone is given as;
τ = F x r = Iα
where;
F is applied force on the stone due to its weight
r is the radius of the pulley
I is moment of inertia
α is angular acceleration (rad/s²)
Force, F = mg = 0.375 x 9.8 = 3.675 N
Torque, τ = F x r
τ = 3.675 x 0.26
τ = 0.9555 N.m
τ = Iα
Angular acceleration, α = τ / I
α = 0.9555 / 0.0125
α = 76.44 rad/s²
Finally, determine linear acceleration, a, in m/s²
a = αr
a = 76.44 x 0.26
a = 19.87 m/s²
Therefore, the magnitude of the acceleration of the stone is 19.87 m/s²
The stone's acceleration, calculated using Newton's second law for rotational and linear systems, and the relationship between linear and angular acceleration for a non-slip condition, is 3.53 m/s².
Explanation:To determine the magnitude of the acceleration of the stone, we need to apply Newton's second law for rotational and linear systems. Specifically, we should set up equations for torque and force.
1. Sum of forces in the vertical direction (y-axis): T - mg = ma, where T is the tension in the string, m is the mass of the stone (0.375 kg), g is the acceleration due to gravity (9.81 m/s²), and a is the linear acceleration of the stone.
2. Sum of torques about the pulley's axis: τ = Iα, where I is the moment of inertia of the pulley (0.0125 kg · m²), α is the angular acceleration, and τ is the torque due to the tension (T·r, with r being the radius of the pulley).
Because the string unwinds without slipping, we have a relationship between linear and angular acceleration: a = αr.
Combining the equations, we can solve for the acceleration 'a' of the stone:
T = Iα/r = Ia/r²
So, T - mg = ma becomes:
Ia/r² - mg = ma
And by solving for 'a', we get:
a = (mg)/(m + I/r²)
Substituting the given values:
a = (0.375 kg × 9.81 m/s²)/(0.375 kg + 0.0125 kg m²/ (0.26 m)²) = 3.53 m/s²
Thus, the stone's acceleration is 3.53 m/s².
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These mystery elements are at the top of their families on the periodic table. An element that is in the same family as element C is likely to have which properties?
1.) The atomic radius of the elements in a group or family increase from the top to the bottom.
2.) The ionization energy decrease going down from the top to the bottom of the group.
3.) Electron affinity becomes less negative from the top to the bottom
4.) Element with high ionization energy has high electronegativity. Therefore, electronegativity decreases from top to the bottom of the group.
Periodic table tells us of the arrangement of elements and also the periodic properties of the elements as they are arranged in groups, periods and families.
some of the properties are :
1. Atomic radius
2. Ionization Energy
3. Electron Affinity
4. Electronegativity
5. Metallic character
6. e.tc
1.) The atomic radius of the elements in a group or family increase from the top to the bottom.
2.) The ionization energy decrease going down from the top to the bottom of the group.
3.) Electron affinity becomes less negative from the top to the bottom
4.) Element with high ionization energy has high electronegativity. Therefore, electronegativity decreases from top to the bottom of the group.
Due to the reason mention above, i can conclude the mystery elements are at the top of their families on the periodic table. An element that is in the same family as element C is likely to have all properties mentioned above.
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An electron is accelerated from rest by a potential difference of 412 V. It then enters a uniform magnetic field of magnitude 188 mT with its velocity perpendicular to the field. Calculate (a) the speed of the electron and (b) the radius of its path in the magnetic field.
Explanation:
Given that,
Potential difference, V = 412 V
Magnitude of magnetic field, B = 188 mT
(a) The potential energy of electron is balanced by its kinetic energy as :
[tex]eV=\dfrac{1}{2}mv^2[/tex]
v is speed of the electron
[tex]v=\sqrt{\dfrac{2eV}{m}} \\\\v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 412}{9.1\times 10^{-31}}} \\\\v=1.2\times 10^7\ m/s[/tex]
(b) When the charged particle moves in magnetic field, it will move in circular path. The radius of the circular path is given by :
[tex]r=\dfrac{mv}{eB}\\\\r=\dfrac{9.1\times 10^{-31}\times 1.2\times 10^7}{1.6\times 10^{-19}\times 188\times 10^{-3}}\\\\r=3.63\times 10^{-4}\ m[/tex]
Hence, this is the required solution.
Most of the asteroids in our solar system are located between the orbits of what two objects?
Answer:
Jupiter and Mars.
The asteroid belt is located between those two celestial objects.
:)
Coulomb's law and the universal law of gravity describe different forces in similar ways. Which of these are factors that both have in common
Coulomb's law and the universal law of gravity both have inverse-square relationships, involve a proportionality constant, and describe forces between two objects.
Explanation:The factors that Coulomb's law and the universal law of gravity have in common are:
Both laws are inverse-square laws. This means that the force between two objects decreases with the square of the distance between them.Both laws involve a proportionality constant. In Coulomb's law, it is the constant 'k', also known as Coulomb's constant. In Newton's law of universal gravitation, it is the constant 'G', also known as the gravitational constant.Both laws describe forces between two objects. Coulomb's law describes the electrostatic force between charged objects, while the universal law of gravity describes the gravitational force between two masses.A cell membrane consists of an inner and outer wall separated by a distance of approximately 10nm. Assume that the walls act like a parallel plate capacitor, each with a charge density of 10^(−5) C/m^2, and the outer wall is positively charged. Although unrealistic, assume that the space between cell walls is filled with air.
(A) What is the magnitude of the electric field between the membranes?
a) 1×10^6 N/C
b) 1×10^15 N/C
c) 5×10^5 N/C
d) 9×10^2 N/C
(B) What is the magnitude of the force on a K+ ion between the cell walls?
a) 2×10^13 N
b) 9×10^13 N
c) 2×10^11 N
d) 3×10^12 N
(C) What is the potential difference between the cell walls?
a) 6×10^3 V
b) 1×10^7 V
c) 10 V
d) 1×10^2 V
(D) What is the direction of the electric field between the walls?
a) There is no electric field.
b) Toward the inner wall.
c) Parallel to the walls.
d) Toward the outer wall.
Answer:
1) A
2) A
3) D
Explanation:
For parallel plates,the electric field E is given by:
E = σ / ε(o), where
E = Electric Field
σ = surface charge density
E = 10^-5 / 8.85*10^-12
E= 1.13*10^6 which is approximately 1*10^6 N/C, option A
B) K has a charge of 1.6*10^-19
F= q*E= (1.13*10^6) * (1.6*10^-19)
F= 1.8*10^-13 Which is approximately 2*10^-13 N, option A
C) Potential difference ,V = Ed
d = 10 nm= 1*10^-9
V = 1.13*10^6 * 1**10^-9
V = 0.0113 v
V = 1.13×10^-2 which is approximately 1x10^-2v, option D
The answers are 1) 1×10^6 N/C, 2) 2×10^13 N, 3) 6×10^3 V, 4) Toward the inner wall.
1) The magnitude of the electric field between the membranes can be calculated using the formula for electric field strength in a parallel plate capacitor:
E = σ / ε₀ = 10^(-5) C/m^2 / (8.85 x 10^(-12) F/m)
= 1.13 x 10^6 N/C.
Therefore, the answer is (a) 1×10^6 N/C.
2) The force on a K+ ion between the cell walls can be found using the formula F = qE, where q is the charge of the K+ ion. As K+ has a +1 charge, the force will be 1.13 x 10^6 N/C × 1.6 x 10^(-19) C
= 1.80 x 10^(-13) N.
Therefore, the answer is 2×10^13 N.
3) The potential difference between the cell walls can be calculated by multiplying the electric field strength by the distance between the walls:
V = Ed = 1.13 x 10^6 N/C × 10 x 10^(-9) m
= 1.13 x 10^4 V = 11.3 kV.
Therefore, the answer is (a) 6×10^3 V.
4) The direction of the electric field between the walls is from the outer wall to the inner wall.
Therefore, the answer is (b) Toward the inner wall.
Which two kinds of energy are associated with flames?
Answer: Light and thermal (heat) energy.
Explanation: Flames give off heat and light.
Answer:
Light and thermal (heat) energy are the two kinds of energy associated with flames
Explanation:
Density: Two blocks, A and B, are put in a tank of water. Block A has a density of 1.21 g/cm³. Block B has a density of 1.37 g/cm³. Which will float higher in the water?
Answer:
Block A
Explanation:
Block A will float higher in the water compared to the second Block.
The density of water is 1g/cm³.
According to the principle of floatation "an object that floats in a liquid will displace equal amount of fluid to the weight of the object".
A body will become more submerged in water if it has more density because density is the mass per volume of body.
An object with a higher density than another will sink in the liquid of the one with lesser density.
Object A has lesser density and will float higher up and displace very little water. Object B has higher density and will be more submerged.Two uniform cylinders have different masses and different rotational inertias. They simultaneously start from rest at the top of an inclined plane and roll without sliding down the plane. The cylinder that gets to the bottom first is: A) the one with the larger mass B) the one with the smaller mass C) the one with the larger rotational inertia D) the one with the smaller rotational inertia E) neither (they arrive together)
Option (E) is correct
Neither (they arrive together)
Explanation:
Neither of the cylinders gets to the bottom first, they both will arrive together. Every object can gain speed with time if it is pushed, it is called the acceleration of that object. It the acceleration that decides which object reaches the bottom first.
Acceleration = I / mr^2.
In the case of both the cylinders, the acceleration will be the same, with the same acceleration they will reach the bottom at the same time.
At t=0 a grinding wheel has an angular velocity of 28.0 rad/s. It has a constant angular acceleration of 25.0 rad/s2 until a circuit breaker trips at time t = 1.90 s. From then on, it turns through an angle 436 rad as it coasts to a stop at constant angular acceleration.
(a) Through what total angle did the wheel turn between t= 0 and the time it stopped?
(b) At what time does the wheel stop?
(c)What was the wheel's angular acceleration as it slowed down? Express your answer in radians per second per second.
Answer:
(a) 534.324 rad
(b) 13.45 s
(c) -6.45 rad/s2
Explanation: Please see the attachments below
Final answer:
The grinding wheel's total angle of turn, time to stop, and angular acceleration are calculated using its initial angular velocity, time accelerated, and the angle it turned while coasting.
Explanation:
Calculating Angular Motion of a Grinding Wheel
A grinding wheel starts with an angular velocity of 28.0 rad/s and accelerates for 1.90 s at a constant angular acceleration of 25.0 rad/s2. After a circuit breaker trips, it coasts to a stop through 436 rad.
To find the total angle the wheel turns, calculate the angle turned during the acceleration phase and add the 436 rad it turns while coasting.
The time for the wheel to stop is found by calculating the time from start to when the circuit breaker trips plus the time it takes to coast to a stop.
The angular acceleration during the deceleration phase is determined using the kinematic equations of rotational motion.
Technician A says that the evacuation process will remove dirt and debris from the refrigerant system. Technician B says that the evacuation process will remove moisture and air from the refrigerant system. Who is correct?
Answer: Technician B is right.
Explanation:
Evacuation process is used in refrigeration systems to remove moisture, air and non-profit condensable gases in order to achieve maximum function of the system.
vacuum pump is used to draw the sealed AC system into a vacuum. Evacuation of a refrigerant system also helps to maintain pressure, this is so as pulling a vacuum on the system is simply removing matter (mostly air and nitrogen) from inside the system so that the pressure inside drops below atmospheric pressure.
The speed of a light wave in a certain transparent material is 0.701 times its speed in vacuum, which is 3.00×108 m/s . When yellow light with a frequency of 5.23×1014 Hz passes through this material, what is its wavelength ???? in nanometers?
Answer:
402 nm
Explanation:
First, we find the speed of light in this medium:
v = 0.701 * c
v = 0.701 * 3 * 10^8
v = 2.103 * 10^8 m/s
Speed of a wave is given as the product of wavelength and frequency:
v = λf
Where λ = wavelength
Wavelength, λ, becomes:
λ = v/f
The frequency of the light is 5.23 * 10^14 Hz, therefore, wavelength will be:
λ = (2.103 * 10^8) / (5.23 * 10^14)
λ = 4.02 * 10^(-7) m = 402 nm
The wavelength of the light is 402 nm.
A step-down transformer is used for re-charging the batteries of portable devices such as tape players. The ratio of turns inside the transformer is 10:1, and it is used with 120 V (rms) household service. A particular ideal transformer draws 0.350 A from the house outlet.
A) What are the voltage.
B) What are the current supplied to a tape player from the transformer?
C) How much power is delivered?
Answer with Explanation:
We are given that
[tex]\frac{N_1}{N_2}=10[/tex]
[tex]V_1=120 V[/tex]
[tex]I_1=0.350 A[/tex]
a.[tex]\frac{V_1}{V_2}=\frac{N_1}{N_2}[/tex]
Using the formula
[tex]\frac{120}{V_2}=\frac{10}{1}[/tex]
[tex]V_2=\frac{120}{10}=12 V[/tex]
b.[tex]\frac{I_2}{I_1}=\frac{N_1}{N_2}[/tex]
[tex]\frac{I_2}{0.350}=10[/tex]
[tex]I_2=0.350\times 10=3.5 A[/tex]
c.Power delivered,P=[tex]I_2V_2=I_1V_1[/tex]
[tex]P=120\times 0.350=42 W[/tex]
A toy cannon uses a spring to project a 5.24-g soft rubber ball. The spring is originally compressed by 5.01 cm and has a force constant of 8.08 N/m. When the cannon is fired, the ball moves 15.8 cm through the horizontal barrel of the cannon, and the barrel exerts a constant friction force of 0.031 0 N on the ball.With what speed does the projectile leave the barrel of the cannon?
Answer:
Speed will be equal to 1.40 m/sec
Explanation:
Mass of the rubber ball m = 5.24 kg = 0.00524 kg
Spring is compressed by 5.01 cm
So x = 5.01 cm = 0.0501 m
Spring constant k = 8.08 N/m
Frictional force f = 0.031 N
Distance moved by ball d = 15.8 cm = 0.158 m
Energy gained by spring
[tex]KE=\frac{1}{2}kx^2=\frac{1}{2}\times 8.08\times 0.0501^2=0.0101J[/tex]
Energy lost due to friction
[tex]W=Fd=0.031\times 0.158=0.0048J[/tex]
So remained energy to move the ball = 0.0101 - 0.0048 = 0.0052 J
This energy will be kinetic energy
[tex]\frac{1}{2}mv^2=0.0052[/tex]
[tex]\frac{1}{2}\times 0.00524\times v^2=0.0052[/tex]
v = 1.40 m/sec
The toy cannon's projectile leaves the barrel at approximately 1.42 m/s.
To find the speed at which the 5.24-g soft rubber ball leaves the barrel of the toy cannon, we follow these steps:
1.) Determine the Potential Energy in the Compressed Spring:
The potential energy stored in the spring when it is compressed can be calculated using the formula:
Potential Energy = (1/2) * k * x²where
k is the spring constant (8.08 N/m) and x is the compression distance (5.01 cm = 0.0501 m). Potential Energy = (1/2) * 8.08 N/m * (0.0501 m)²
Potential Energy = 0.01017504 J
2.) Calculate the Work Done by Friction:
Friction force is constant at 0.0310 N over a distance of 15.8 cm (0.158 m):
Work = Friction Force * DistanceWork = 0.0310 N * 0.158 mWork = 0.004898 J3.) Find the Net Energy Available:
Net Energy = Potential Energy - Work done by friction:Net Energy = 0.01017504 J - 0.004898 JNet Energy = 0.00527704 J4.) Calculate the Speed of the Ball:
Using the energy conservation principle where Net Energy is converted into kinetic energy:
Kinetic Energy = (1/2) * m * v²The ball's mass (m) = 5.24 g = 0.00524 kg.Solving for velocity (v):
0.00527704 J = (1/2) * 0.00524 kg * v²Thus, the speed at which the ball leaves the barrel of the cannon is approximately 1.42 m/s.