Given that a student works no more than 25 hours per week, and that work is performed every day of a 7-day week, the maximum number of hours they can work per day is approximately 3.57, making it fair to say they can work up to 3 hours each day. This scenario can be represented by the inequality h ≤ 3.
Explanation:To answer your question, we need to find an inequality that represents how many hours the student can work each day given they work no more than 25 hours every week.
If we assume a typical week encompasses 7 days, and the student works every day of the week, then we should distribute the maximum hours worked per week over these seven days.
This results in 25 hours ÷ 7 days ≈ 3.57 hours/day. However, since you can't work a fraction of an hour, the student can work up to 3 hours a day.
The inequality representing this scenario would be h ≤ 3, where 'h' represents the number of hours the student can work each day.
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PLEASE HELP!!
At 6:00 p.m. the temperature was -5*F outside. By midnight the temperature had dropped 12 degrees. What was the temperature at midnight?
A) -7*F
B) -17*F
C) 17*F
-5-12=-17 so it is b)
What is the area of polygon IJKL?
A.
120 square units
B.
125 square units
C.
130 square units
D.
140 square units
E.
150 square units
ANSWER
The correct answer is E
EXPLANATION
Polygon IJKL is a rectangle.
The area is given by;
[tex]Area=l\times w[/tex]
The coordinates of I are [tex](5,8)[/tex] and L[tex](-5,8)[/tex].
This is a horizontal line so it will be faster using the absolute value method rather than the distance formula
The length is
[tex]|IL|=|5--5|[/tex]
[tex]|IL|=|5+5|[/tex]
[tex]|IL|=|10|[/tex]
[tex]|IL|=10[/tex]
units
The coordinates of K are [tex](-5,-7)[/tex] and L[tex](-5,8)[/tex].
The width is
[tex]|LK|=|8--7|[/tex]
[tex]|LK|=|8+7|[/tex]
[tex]|LK|=|15|[/tex]
[tex]|LK|=15[/tex]
units
Therefore
[tex]Area=10\times 15[/tex]
[tex]Area=150[/tex] square units
The coordinates of K are [tex](-5,-7)[/tex] and L[tex](-5,8)[/tex].
Answer:
The correct answer option is E. 150 square units.
Step-by-step explanation:
A polygon is figure with at least 3 straight or definite sides or typically 5 or more straight sides.
Here the polygon we are given is a rectangle.
We know that,
Area of a rectangle = l x w
so we need to measure the length and width of the rectangle to find its area.
If we look closely, we can see the length of the rectangle above the x-axis is 8 units and the length below the x-axis 7 units which makes a total og 15 units.
While the width is 10 units (5 units on each side of the y-axis).
Area of the rectangle = 15 x 10 = 150 square units.
Therefore, the area of the polygon is 150 square units.
what is the sum: (1−5q)+2(2.5q+8)
The answer is seventeen
The figure below shows rectangle ABCD:
The following two-column proof with missing statement proves that the diagonals of the rectangle bisect each other:
Which statement can be used to fill in the blank space?
(A) ∠ABD ≅ ∠DBC
(B) ∠CAD ≅ ∠ACB
(C) ∠BDA ≅ ∠BDC
(D) ∠CAB ≅ ∠ACB
B would be the answer because if you were to search up a picture of alternate interior angles, it would be the same as <CAD and <ACB
Answer:
(B) ∠CAD≅∠ACB
Step-by-step explanation:
Given in the question quadrilateral ABCD is a rectangle and a table of two-column proof with missing statement for proves that the diagonals of the rectangle bisect each other.
If we want to prove that the diagonals bisects to each other, then for this first we will prove that ΔADE≅ΔCBE. But given in the two-column proof
∠ADB≅∠CBE , side BC= side AD . ∠CAD ≅ACD must be necessary for to prove that ΔADE≅ΔCBE (ASA postulate). Hence statement ∠CAD ≅ACD can be used to fill in the blank space.
Lilliana’s hair was originally 48 inches long. She asked her hair dresser to cut 2/3 of her hair off. How long was her hair after her haircut.
Lilliana's hair was 48 inches long and she cut off 2/3 of it. After calculating 2/3 of 48, which is 32 inches, we subtract this from the original length. Lilliana's hair was 16 inches long after her haircut.
The student's question concerns the length of Lilliana's hair after she has asked her hairdresser to cut 2/3 of it off. If we know that Lilliana's hair was originally 48 inches long, we need to calculate 2/3 of this length and then subtract it from the original length to find the new length of her hair after the haircut.
Calculate 2/3 of 48 inches: (2/3) times 48 = 32 inches.
Subtract the amount cut from the original length: 48 inches - 32 inches = 16 inches.
Therefore, after Lilliana's haircut, her hair was 16 inches long.
Pls help I don’t under stand this
Hello Queengirl0
Past tense:
Melissa has a full chocolate bar 8/8
At lunch:
Melissa ate 2/8 of the candy bar, 8/8 - 2/8 = 6/8
After school:
Melissa ate 3/8 of the candy bar, 6/8 - 3/8 = 3/8
Melissa has 3/8 of a chocolate bar left
:)
For inequalities. Greater Than, >, and Less Than, <, mean the solution does NOT contain the number. So would you use and open circle or a closed circle to graph on a number line ___________________ For inequalities. Greater Than or Equal TO, >, and Less Than or Equal TO, <, mean the solution does contain the number. So would you use and open circle or a closed circle to graph on a number line?____________________
a number d minus 2 is less than -1 ?
d - 2 < -1 is how this inequality would be displayed.
However, we can solve for the value of d by treating this like a standard algebraic equation.
d - 2 < -1
Add 2 to both sides.
d < 1
The value of d is less than 1.
Let me know if you have any other questions.
Answer:
Given phrase,
a number d minus 2 is less than -1
∵ '-' is the sign of minus,
⇒ d minus 2 = d - 2
Also, '<' is the sign of less than,
⇒ d minus 2 is less than -1 = d - 2 < - 1
Hence, the required inequality would be,
[tex]d-2 < -1[/tex]
Now, by further solving,
Add 2 on the both sides of inequality ( additive property of inequality )
[tex]d < -1 + 2\implies d < 1[/tex]
⇒ d ∈ ( -∞, 1 )
in a triangle, if the second angle is 2 times the first angle and the third angle is 3 times the first angle,find the angles of the triangle.
a + b + c = 180
b = 2a
c = 3a
a + 2a + 3a = 180
6a = 180
a = 30
b = 2(30)
b = 60
c = 3(30)
c = 90
Answer:
a = 30
b = 60
c = 90
I need help with 23 please!!!
Answer:
28 questions
Step-by-step explanation:
In the first 10 mins she answered 2/5 of 40 which is 16. The remaining amount is 24 questions and half of that is 12. So she answered 12 questions in 15 mins. Finally you add them to get 28 questions in 25 minutes.
Let g be the function given by g(x)=-3x^2-2x+3 evaluate g(-2)
g(x) = -3x² - 2x + 3
g(-2) = -3(-2)² - 2(-2) + 3
g(-2) = -12 + 4 + 3 = -5
I need help with this.
10 POINTS!
what is 7.08 as mixed number
7 8/100 or 7 2/25 in lowest terms
7 2/25 is your answer
your welcome
Find the product. -2 x ( x2 - 3) -2 x3 - 6 x -2 x3 + 6 x -2 x2 + 6 x 6 x3
[tex]-2x(x^2-3)\qquad|\text{use distributive property}\\\\=(-2x)(x^2)+(-2x)(-3)=-2x^3+6x[/tex]
If f(x) varies directly with x and f(x)=40 when x=8, find the value of f(x) when x=2.
A. 2
B. 5
C. 10
D. 15
f(x)=40
x=8
so if x=2 it would be 40/8 which is 5
C
since the quantities vary directly then
x = kf(x) ( where k is the constant of variation )
to find k use the given condition , f(x) = 40 when x = 2
k = [tex]\frac{x}{f(x)}[/tex] = [tex]\frac{8}{40}[/tex] = [tex]\frac{1}{5}[/tex]
thus x = [tex]\frac{1}{5}[/tex]f(x)
when x = 2
f(x) = [tex]\frac{x}{k}[/tex] = [tex]\frac{2}{\frac{1}{5} }[/tex] = 10
True or False: The following relation is a function. {(−5,−7),(0,4),(−5,3),(9,4)}
the answer is that it is false
Can anyone help me please?? I’m so stuck
∠DAB and ∠BAD form a linear pair, so ∠DAB + ∠BAD = 180°
116° + ∠BAD = 180° substituted
∠BAD = 64° subtracted 116° from both sides
ΔABC
∠A + ∠B + ∠C = 180° triangle angle sum theorem
64° + x + 60° = 180° substitution
x + 124° = 180° added like terms
x = 56° subtraction property
Answer: 56°
Antoni has read 147 pages of a book.He has completed 70% of the book.How many more pages does he need to read to finish the book
What are the steps for using a compass and straightedge to construct the bisector of ∠G? Two rays share a common endpoint labeled G, forming an obtuse angle. One ray is horizontal and points right. The second ray is inclined to horizontal in upward-left direction. Drag the steps and drop them in order from start to finish. Without changing the opening of the compass, place the point of the compass on point J and draw another arc in the interior of the angle.Use the straightedge to draw GK−→−.Place the point of the compass on point H and draw an arc in the interior of the angle.Label the intersection of the arcs in the interior of the angle as point K.Place the point of the compass on point G and draw an arc that intersects the sides of ∠G. Label the points of intersection as points H and J.
Answer:
The Quiz Was Updated This Is It Now
Step-by-step explanation:
DO IN ORDER!
Thee steps for using a compass and straightedge to construct the bisector of ∠G is given in the image attached.
How to construct the bisectorSo, the correct order of the steps from beginning is:
Place the point of the compass on point J and draw another arc in the interior of the angle.Use the straightedge to draw GK.Place the point of the compass on point H and draw an arc in the interior of the angle.Label the intersection of the arcs in the interior of the angle as point K.Place the point of the compass on point G and draw an arc that intersects the sides of ∠G.Label the points of intersection as points H and J.Learn more about bisector from
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Susan uses 15 rolls of ribbon to decorate 10 wedding baskets. Each roll of ribbon is
[tex]5 \frac{3}{8} [/tex]
yards long. After she decorates the baskets, she decides to cut off another
[tex] \frac{3}{4} [/tex]
yard from the ribbons of each basket. Write and simplify an expression to find out how much ribbon was used on the baskets.
Answer:
Amount of ribbon used = [tex]73 \frac{1}{8} yards[/tex] = 73.125 yards.
Explanation:
Number of ribbon rolls = 15
Number of wedding basket = 10
Length of 1 ribbon roll = [tex]5\frac{3}{8}=\frac{5*8+3}{8} =\frac{43}{8}[/tex] yards.
Total length of 15 ribbon roll = [tex]15*\frac{43}{8} =\frac{645}{8}[/tex]yards.
Length of ribbon cutting from each basket = [tex]\frac{3}{4}[/tex]yards.
Total length of ribbon cutting from 10 baskets = [tex]10*\frac{3}{4}=\frac{15}{2}[/tex] yards
Amount of ribbon used
[tex]=\frac{645}{8}-\frac{15}{2}=\frac{645}{8}-\frac{15*4}{2*4}=\frac{645}{8}-\frac{60}{8}\\ \\ =\frac{585}{8} =73 \frac{1}{8} yards[/tex]
Amount of ribbon used = [tex]73 \frac{1}{8} yards[/tex] = 73.125 yards.
17.
Graph the function f(g)=|g−2|+5 . What is the range of this function?
A g≥5
B g≥2
C g≤5
D g≥−5
The correct answer is A) g≥5
This is because when you look at an absolute value function, the constant at the end is the y value of the vertex. Since it is an absolute value equation, we know that the values can only go up. Therefore, it must be greater than or equal to the constant at the end (5)
Convert decimal to fraction: .0167
We are to convert 0.0167 to fraction.
Trick 1: Count the number of decimal values in our number which is 4.
Trick 2: Write 1 followed by 4 zeros (the four you counted to above). This gives 10000 which is our denominator.
Trick 3: Retrieve our denominator by writing down the whole number which can be observed in 0.0167. That whole number is 167.
Trick 4: Now put your results in the fraction form. That is in numerator/denominator form.
This gives 167/10000
Trick 5: Try to simplify further. You can't! So the answer is:
[tex]\frac{167}{10000}[/tex]
Which is a true statement comparing the graphs of x^2/3^2 - y^2/4^2= 1 and y^2/3^2 - x^2/4^2 = 1?
The foci of both graphs are the same points.
The lengths of both transverse axes are the same.
The directrices of = 1 are horizontal while the directrices of = 1 are vertical.
The vertices of = 1 are on the y-axis while the vertices of = 1 are on the x-axis.
Answer: B) The lengths of both transverse axes are the same.
Step-by-step explanation: Given Hyperbola equations :
[tex]\frac{x^2}{3^2}-\frac{y^2}{4^2}=1[/tex] and
[tex]\frac{y^2}{3^2}-\frac{x^2}{4^2}=1[/tex]
First one : [tex]\frac{x^2}{3^2}-\frac{y^2}{4^2}=1[/tex] is a Horizontal Hyperbola.
a = 3 and 2a = 6.
Length of transverse axis = 6.
And second one : [tex]\frac{y^2}{3^2}-\frac{x^2}{4^2}=1[/tex] is a Vertical Hyperbola.
b=3 and 2b = 6
Length of transverse axis = 6.
The lengths of both transverse axes are the same.
Therefore, correct option is B option :
The lengths of both transverse axes are the same.Answer:
B
Step-by-step explanation:
3x567 estimate rounding?
567 would round out to 600. If you are also rounding the three, then that is one. The answer to that would be 600. If you aren't rounding the three, the answer would be 1800.
Answer:
1800
Step-by-step explanation:
567 = 600 rounded to nearest hundred
3 * 600 = 1800
write 156x10^ -7 in standard form
.0000156
Hope I helped!
Good Luck!
algedratic expression for word phrase the quotient of y and 6
we are given
the quotient of y and 6
we always start from left to right order of operation
we know that
quotient means division
so, we can write as
the quotient of y and 6 is
[tex]\frac{y}{6}[/tex]...............Answer
In two weeks, your class collected more than 380 cans of food for the annual food drive. In the first week, 145 cans were collected. How many cans c of food were collected in the second week? Write and solve an inequality.
145 + c = 380
145 - 145 + c = 380 - 145 -Subtract 145 from both sides of the equation
c = 235
So, they collected 235 cans in the second week.
Hope this helps!
To find out how many cans of food were collected in the second week, subtract the number of cans collected in the first week from the total number of cans collected in two weeks. The inequality representing the problem is c + 145 > 380. Solving the inequality, we find that more than 235 cans were collected in the second week.
Explanation:To find out how many cans of food were collected in the second week, we can subtract the number of cans collected in the first week from the total number of cans collected in two weeks. Let's assign a variable, c, to represent the number of cans collected in the second week. The inequality that represents the problem is: c + 145 > 380. To solve this inequality, we need to isolate the variable by subtracting 145 from both sides: c > 380 - 145. Simplifying further, we get c > 235. So, more than 235 cans of food were collected in the second week.
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Write an explicit formula for an arithmetic sequence whose common difference is -4.5
For this case we have:
The general formula of the arithmetic sequence is given by:
[tex]a_n = a_1 + (n-1) d\\[/tex]
Where
[tex]a_n[/tex]: Last term
[tex]a_1[/tex]: First term
n: Number of terms
d: Difference
Rewriting according to the given common difference, we have:
[tex]a_n = a_1 + (n-1) (- 4.5)[/tex]
Answer:
[tex]a_n = a_1 + (n-1) (- 4.5)[/tex]
The explicit formula for an arithmetic sequence whose common difference is -4.5 is:
[tex]a_n=a_1-4.5(n-1)[/tex]
Step-by-step explanation:Explicit formula--
Explicit formula is the formula which is used to find the nth term of a sequence.
We know that the explicit formula for an arithmetic sequence is given by:
[tex]a_n=a_1+(n-1)d[/tex]
where d is the common difference of the sequence and [tex]a_1[/tex] is the first term of the sequence.
We have: d= -4.5
Hence, the explicit formula is given by:
[tex]a_n=a_1-4.5(n-1)[/tex]
I WILL GIVE BRAINLIEST!!! EASY POINTS
Drag an answer to each box to complete this paragraph proof.
Given: Triangle PQR with m∠P=(x)° , m∠Q=(3x)° , and m∠R=(5x)° .
Prove: x = 20
The answer for the first one is (x)°+(3x)°+(5x)°=180° and the answer for the second one is x=20. If you need me to explain how they got the answer, i'm here.
Answer:
Fill the blanks
1) (x)°+(3x)°+(5x)°=180°
2) x°=20°
Step-by-step explanation:
Consider the provided information.
Given: Triangle PQR with m∠P=(x)°, m∠Q=(3x)°, and m∠R=(5x)°.
We need to prove that x = 20
Consider the provided figure.
By the triangle sum theorem the sum of the angles in a triangle is equal to 180. Therefore using the give and triangle sum theorem,
m∠P+m∠Q+m∠R=180°
Now use substitution property.
(x)°+(3x)°+(5x)°=180°
Simplify the equation gets
9x°=180°
Finally, using the division property of equality.
9x°/9=180°/9
x°=20°
Hence proved
You start at (8, 1). You move right 2 unit and left 3 units. Where do you end?
You should end around: (9,1) hope this helps!
if you move right 2 and left 3 one time you get 10.4, do it again you get 11.7 again 13.10