a table cost 5 times as much as a chair. for $40000 a trader can buy 20 more chairs than tables. find the cost of a chair and number of tables.​

Answer:

B = 45

Step-by-step explanation:

B/3 - 6 = 9

B/3 = 15

B = 45

Tell me if I am wrong.

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Answer:

1) Null hypothesis:[tex]\mu \leq 500[/tex]  

Alternative hypothesis:[tex]\mu > 500[/tex]  

[tex]z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90[/tex]  

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

[tex]z_{crit}= 2.33[/tex]

For this case we see that the calculated value is higher than the critical value

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

2) Since is a right tailed test the p value would be:  

[tex]p_v =P(z>5.90)=1.82x10^{-9}[/tex]  

If we compare the p value and the significance level given [tex]\alpha=0.01[/tex] we see that [tex]p_v<\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

Step-by-step explanation:

Part 1

Data given

[tex]\bar X=640[/tex] represent the sample mean

[tex]\sigma=150[/tex] represent the population standard deviation

[tex]n=40[/tex] sample size  

[tex]\mu_o =500[/tex] represent the value that we want to test  

[tex]\alpha=0.01[/tex] represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

[tex]p_v[/tex] represent the p value for the test (variable of interest)  

Step1:State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 500, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 500[/tex]  

Alternative hypothesis:[tex]\mu > 500[/tex]  

Step 2: Calculate the statistic

[tex]z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}[/tex] (1)  

We can replace in formula (1) the info given like this:  

[tex]z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90[/tex]  

Step 3: Calculate the critical value

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

[tex]z_{crit}= 2.33[/tex]

Step 4: Compare the statistic with the critical value

For this case we see that the calculated value is higher than the critical value

Step 5: Decision

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

Part 2

P-value  

Since is a right tailed test the p value would be:  

[tex]p_v =P(z>5.90)=1.82x10^{-9}[/tex]  

If we compare the p value and the significance level given [tex]\alpha=0.01[/tex] we see that [tex]p_v<\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

The area of a circle can be calculated by formula πr^2...

radius(r)=4inches

therefore,

Area(A)=3.14×4

=12.56

Final answer:

To calculate the area of a circle with an 8-inch diameter using 3.14 for π, the formula A = πr² gives us 50.24 square inches, which rounds to 50.2 square inches to the nearest tenth.

Explanation:

The student is asking for the area of a circle with a diameter of 8 inches using 3.14 for π (Pi). The area of a circle is given by the formula A = πr², where 'r' is the radius of the circle. Since the diameter is twice the radius, we have that the radius 'r' is 4 inches (half of 8 inches). Plugging this into the formula we get A = 3.14 × 4².

To find the area to the nearest tenth, we perform the calculation: A = 3.14 × 16 = 50.24. Therefore, the area of the circle is 50.2 square inches when rounded to the nearest tenth.

Answer:

The standard error( X1 − X2 ) = 0.547

Step-by-step explanation:

Step:-(1)

Given a procurement specialist has purchased 23 resistors

Given normally and independently distributed with mean 120 ohms and standard deviation 1.7

mean of the Population of the vendor 1 is μ₁ =  120 ohms

Standard deviation of the Population the vendor 1 is σ₁ = 1.7 ohms

similarly represent the vendor 2 observed resistances, which are assumed to be normally and independently distributed with mean 125 ohms and standard deviation of 2.0

mean of the Population of the vendor 2 is μ₂ =  120 ohms

Standard deviation of the Population the vendor 2 is σ₂ = 1.7 ohms

The standard error of the  difference of two means

 Se( X1 − X2) = [tex]\sqrt{\frac{σ^2_{1} }{n_{1} } +\frac{σ^2_{2} }{n_{1} } }[/tex]

 Here σ₁ = 1.7 ohms and σ₂ = 2 ohms and n₁=n₂ =n = 23 resistors

se(X1 − X2) = [tex]\sqrt{\frac{1.7^2}{23 } +\frac{2^2 }{23} }[/tex]

se(X1 − X2) = √0.2995

                   = 0.547

Conclusion:-

The standard error of X1 − X2 = 0.547

Final answer:

Explains the standard error of sample means for two vendors and the distribution of sample means.

Explanation:

The standard error of the sample mean in this scenario, rounded to two decimal places, is calculated as follows:

For vendor 1: standard error = 1.7 / sqrt(23)

For vendor 2: standard error = 2.0 / sqrt(30)

The distribution of the sample mean X: Since the sample means are normally distributed, the sampling distribution of X is approximately normal.

The standard error of X1 − X2: The standard error of the difference between sample means X1 and X2 is calculated using the formula for the standard error of the difference between two independent sample means.

Answer:

During the test for any significant difference in the means for the three assembly methods, there is significant evidence to reject the claim of equal population means

Step-by-step explanation:

Let;

SS be sum of square

MS be Mean Square

d.f be degree of freedom

trt be treatment

w be workers

Pls see attached files for detail step by step solutions as typing the explanation is not possible because of tables involved.

Using a one-way ANOVA test, it is determined that at least one of the assembly methods differs significantly from the others in terms of units assembled correctly by the randomly assigned workers.

The question involves the use of a one-way Analysis of Variance (ANOVA) to explore any significant difference in the means of the three proposed assembly methods. The given data are: SST (Total Sum of Squares) = 10800, SSTR (Sum of Squares between groups) = 4560. We can calculate SSE (Sum of Squares within groups) using the formula: SSE = SST - SSTR, which gives 10800 - 4560 = 6240.

The degrees of freedom (df) for between groups is k - 1 = 3 - 1 = 2 (where k is the number of groups). Similarly, the total degrees of freedom is n - 1 = 30 - 1 = 29 (where n is the total number of observations). The within groups degrees of freedom is df(total) - df(between) = 29 - 2 = 27.

Next, calculate Mean Square Between (MSB) = SSTR/df(between) = 4560/2 = 2280 and Mean Square Error (MSE) = SSE/df(within) = 6240/27 = 231.112. The F-statistic is given by F = MSB/MSE = 2280/231.112 = 9.869.

For a one-way ANOVA test at alpha = .05 with df(between) = 2 and df(within) = 27, checking an F distribution table, the critical value of F is approximately 3.354. Since our calculated F(9.869) > F critical(3.354), there is evidence to reject the null hypothesis. This indicates that at least one assembly method has a significantly different mean than the others.

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Answer:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(58,21)[/tex]  

Where [tex]\mu=58[/tex] and [tex]\sigma=21[/tex]

The z score for this case is given by this formula:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

We know that the value of z = 1.78 and we want to estimate the value of X. If we solve for X from the z formula we got:

[tex] X= \mu +1.78 \sigma= 58 +1.78*21= 95.38[/tex]

So the corresponging weight for a z score of 1.78 is 95.38 grams

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(58,21)[/tex]  

Where [tex]\mu=58[/tex] and [tex]\sigma=21[/tex]

The z score for this case is given by this formula:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

We know that the value of z = 1.78 and we want to estimate the value of X. If we solve for X from the z formula we got:

[tex] X= \mu +1.78 \sigma= 58 +1.78*21= 95.38[/tex]

So the corresponging weight for a z score of 1.78 is 95.38 grams

A chicken egg with a z-score of 1.78 in a normal distribution model N(58, 21) will weigh approximately 95.38 grams.

The normal model N(58, 21) describes that weights of chicken eggs are normally distributed with a mean of 58 grams and a standard deviation of 21. Given a z-score of 1.78 for a randomly selected egg, we can calculate the egg's weight according to the Z-score formula, Z = (X - µ)/σ, where X is the value we want to find, µ is the mean, σ is the standard deviation, and Z is the z-score.

Let's apply the z-score value to the formula and solve for X:

Therefore, the weight of the egg with the z-score of 1.78 is approximately 95.38 grams.

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Answer:

87.74

Step-by-step explanation:

Answer:

ernie=X  so Daniel = X-6

Step-by-step explanation:

The variable, the number of hours Daniel worked, is modeled by an orange x tile. Working 3 times as many hours is modeled with 3 orange x tiles. The multiplication expression that represents the situation is 3x.y-

Step-by-step explanation:

R'(x) = 5x³ − 60x²

A) R"(x) = 15x² − 120x

0 = 15x² − 120x

0 = 15x (x − 8)

x = 0 or 8

B) R"(-1) = 135

R"(1) = -105

R"(x) changes signs around x = 0, so x = 0 is an inflection point.

R"(7) = -105

R"(9) = 135

R"(x) changes signs around x = 8, so x = 8 is an inflection point.

Answer:

The current is decreasing at a rate 0.000209 ampere per second.

Step-by-step explanation:

We are given the following in the question:

[tex]R = 337\Omega\\I = 0.01 A\\\\\dfrac{dV}{dt} = -0.07\text{ V/s}\\\\\dfrac{dR}{dt} = 0.06\text{ ohm/s}[/tex]

According to the Ohm's Law:

V = IR

Differentiating we get,

[tex]\dfrac{dV}{dt} = I\dfrac{dR}{dt} + R\dfrac{dI}{dt}[/tex]

Putting values, we get,

[tex]-0.07 = (0.01)(0.06)+ (337)\dfrac{dI}{dt}\\\\(337)\dfrac{dI}{dt} = -0.07-(0.01)(0.06) =-0.0706\\\\\dfrac{dI}{dt} = \dfrac{-0.0706}{337} = -0.000209\text{ A/s}[/tex]

Thus, the current is decreasing at a rate 0.000209 ampere per second.

Answer: 1/8

Step-by-step explanation: If you convert 1/4 to eighths, it becomes 2/8. 3/8-2/8 is 1/8

Answer:

Step-by-step explanation:

Reduction to normal from using lambda-reduction:

The given lambda - calculus terms is, (λf. λx. f (f x)) (λy. Y * 3) 2

For the term, (λy. Y * 3) 2, we can substitute the value to the function.

Therefore, applying beta- reduction on "(λy. Y * 3) 2" will return 2*3= 6

So the term becomes,(λf. λx. f (f x)) 6

The first term, (λf. λx. f (f x)) takes a function and an argument, and substitute the argument in the function.

Here it is given that it is possible to substitute the resulting multiplication in the result.

Therefore by applying next level beta - reduction, the term becomes f(f(f(6)) (f x)) which is in normal form.

Answer:

Cube and cuboid

Both have 6 faces

Answer:

Cube and cuboid

Both have 6 faces

Step-by-step explanation:

Area, A = Length,x × Breadth,y

A=xy

When x and y are independent, E(xy) = E(x)E(y)

As x and y have the same distribution, U[L-A,L+A], they have the same mean.

We could argue by symmetry that E(x) = L and E(y) + L, also.

We can also reason this from the fact that, if X ~ U[L-A, L+A], f(x) = 1/(2A) from L-A to L+A

Therefore

[tex]E(x)= \int\limits {f(x)} \, dx \\\\=\int\limits^{(L+A)}_{(L-A)} {\frac{1}{2A}x } \, dx[/tex]

[tex]=\int\limits^{(L+A)}_{(L-A)} {\frac{1}{2A}x } \, dx \\\\=[\frac{1}{4A}x^2 ]\limits^{(L+A)}_{(L-A)}[/tex]

=1/(4A)(L+A)2 - 1/(4A)(L-A)2

= 1/(4A)(L2 + 2AL + A2) - 1/(4A)(L2 - 2AL + A2)

=1/(4A)(2AL+2AL)

= 1/(4A)(4AL)

= L

Thus, E(xy) = E(x)E(y) = L×L = L²

Answer:

Step-by-step explanation:

The mean of the set of data given is

Mean = (29.7 + 29.4 + 31.7 + 29.0 + 29.1 + 30.5 + 29.1 + 29.8)/8 = 29.788 = $29788

Standard deviation = √(summation(x - mean)/n

n = 8

Summation(x - mean) = (29700 - 29788)^2 + (29400 - 29788)^2 + (31700 - 29788)^2 + (29000 - 29788)^2 + (29100 - 29788)^2 + (30500 - 29788)^2 + (29100 - 29788)^2 + (29800 - 29788)^2 = 5888752

Standard deviation = √(5888752/8) = 857.96

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ < 30000

For the alternative hypothesis,

µ > 30000

It is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 8,

Degrees of freedom, df = n - 1 = 8 - 1 = 7

t = (x - µ)/(s/√n)

Where

x = sample mean = 29788

µ = population mean = 30000

s = samples standard deviation = 857.96

t = (29788 - 30000)/(857.96/√8) = - 0.7

We would determine the p value using the t test calculator. It becomes

p = 0.253

Since alpha, 0.05 < than the p value, 0.253, then we would fail to reject the null hypothesis. Therefore, At a 5% level of significance, the sample data did not show evidence that the mean wedding cost is not less than $30,000 as advertised

Answer:

  C.  Consumer Price Index

Step-by-step explanation:

The Consumer Price Index is based on the cost of a specific shopping list of goods. It is published monthly by the US Bureau of Labor Statistics.

Answer:

1/12

Step-by-step explanation:

Probability is the result of the number of possible outcome divided by the number of total outcome.

Given that the box contains a red shirt, a blue shirt, a black trouser, and a red trouser, the number of total outcome is

= 1 + 1 + 1 + 1

= 4

The possibility of picking;

a black trouser is

= 1/4

then a red (without replacement, the total outcome drops to 3)

= 1/3

Hence, the probation choosing the black trouser and the red shirt without replacement

= 1/4 * 1/3

= 1/12

Answer:

The unit price is $5.

Answer:

$5.00.

Step-by-step explanation:

This is 22.5 / 4.5

= $5.00

Answer:

-0.36666666666...

Step-by-step explanation:

not sure how to explain, that's a repeating number.

The total value of the German shareholding is 202500 million dollars.

Given that, the total number of shares is 45 million.

We need to find the total value of the German shareholding.

Germany holds 15% of the shares, which is 15% of 45 million

=15/100×45000000=67,50,000

Number of shares Germany holds=67,50,000

Now, the total value of the German shares=67,50,000×30=$20,25,00,000

Therefore, the total value of the German shareholding is 202500 million dollars.

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Final answer:

The total value of the German shareholding in Tazon Insurance is $202.5 million as of April in Year 1.

Explanation:

The student is asking for the calculation of the total value of German shareholdings in Tazon Insurance when each share is valued at $30. To find this, we need to calculate the number of shares held by Germany and then multiply by the share price.

Therefore, the total value of the German shareholding in Tazon Insurance is $202.5 million as of April in Year 1.

Answer:

In the image, you can observe a diagram representing this problem.

We know by given that [tex]g \parallel h[/tex] and [tex]\angle 2 \cong \angle 3[/tex].

From the parallelism between line g and line h, we deduct several congruence between angles.

[tex]\angle 2 \cong \angle 1[/tex], by corresponding angles (same side of the transversal, one interior, the other exterior to parallels).

Now, to demonstrate [tex]e \parallel f[/tex], we must demonstrate a congruence between angle 2 and an angle on the intersection between line g and line f.

In the parallelogram formed, we know

[tex]\angle 2 + \angle 3+ 180-\angle 1 + x =360[/tex]

Where [tex]x[/tex] is the angle at the intersection line g and line f.

But, we know [tex]\angle 2 \cong \angle 3[/tex] and [tex]\angle 2 \cong \angle 1[/tex], so

[tex]\angle 2 + \angle 2 +180 - \angle 2 +x=360\\\angle 2 + x=180[/tex]

Notice that we don't have a congruence, however there's theorem which states that the same-side interior angles of parallels are supplementary.

In this case, we use the corolary of that theorem, which states if two same-side interior angles are supplementary, then the lines are parallels.

[tex]\therefore e \parallel f[/tex]

However, according to the choices of the problem, the missin proof is "converse alternate interior angles theorem", because the problem was demonstrate using transitive property, to show that angles 1 and 3 are congruent, there by converse alternate interior angles theorem, lines e and f are parallels.

This is the same case we used, but using converse alternate interior angles theorem.

Answer:

the answer is c-

Step-by-step explanation:

converse alternate interior angles theorem

hope this is helpful

give brainliest to the other dude

Answer:

each friend would get 1/6 when you divide 1/2 by 3

Step-by-step explanation:

Each friend receives 1/6 of the pie.

The student asked how much pie each of three friends would get if they share 1/2 of a blueberry pie. To find the answer, you simply divide the half of the pie by three, since there are three friends sharing it. That is, 1/2 ÷ 3.

You can think of this division as splitting the 1/2 of the pie into three equal parts. Each friend would get 1/6 of the pie, because 1/2 ÷ 3 = 1/6. This intuitively makes sense because if a pie is cut into six equal slices, three slices (which is half the pie) can be shared by three friends, giving each one slice.

Answer:

$4.815

Step-by-step explanation:

4.50 x 7/100=0.315

then add 4.50+0.315=4.815

Answer:

10

Step-by-step explanation:

hope it helps

Answer:

Step-by-step explanation:

The speed of light in a vacuum is 186,282 miles per second (299,792 kilometres per second), and in theory nothing can travel faster than light. In miles per hour, light speed is, well, a lot: about 670,616,629 mph. If you could travel at the speed of light, you could go around the Earth 7.5 times in one second.

186 ,282 x 5  = 931 , 410  for 5 seconds

Answer:

7.64

Step-by-step explanation:

Answer:

We need to sample at least 1069 parents.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.9}{2} = 0.05[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.05 = 0.95[/tex], so [tex]z = 1.645[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

How many parents do you have to sample?

We need to sample at least n parents.

n is found when [tex]M = 4, \sigma = 79.5[/tex]. So

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

[tex]4 = 1.645*\frac{79.5}{\sqrt{n}}[/tex]

[tex]4\sqrt{n} = 1.645*79.5[/tex]

[tex]\sqrt{n} = \frac{1.645*79.5}{4}[/tex]

[tex](\sqrt{n})^{2} = (\frac{1.645*79.5}{4})^{2}[/tex]

[tex]n = 1068.92[/tex]

Rounding up

We need to sample at least 1069 parents.

Answer:

[tex]n=(\frac{1.64(79.5)}{4})^2 =1062.43 \approx 1063[/tex]

So the answer for this case would be n=1063 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

[tex]\bar X[/tex] represent the sample mean for the sample  

[tex]\mu[/tex] population mean (variable of interest)

[tex]\sigma=79.5[/tex] represent the population standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

[tex] ME=z_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]    (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

[tex]n=(\frac{z_{\alpha/2} \sigma}{ME})^2[/tex]   (b)

The critical value for 90% of confidence interval now can be founded using the normal distribution. And in excel we can use this formula to find it:"=-NORM.INV(0.05;0;1)", and we got [tex]z_{\alpha/2}=1.64[/tex], replacing into formula (b) we got:

[tex]n=(\frac{1.64(79.5)}{4})^2 =1062.43 \approx 1063[/tex]

So the answer for this case would be n=1063 rounded up to the nearest integer

Answer:2a + 2b, 2c

Step-by-step explanation:

Answer:

A. Financial data tapes that contain data compiled from the New York Stock

Step-by-step explanation:

Primary data is data that is collected by a researcher from first-hand sources. Data published by the New York Stock Exchange is primary data, which inherently makes the data tapes secondary data, because they contain the data from a source other than original source.