A unicellular, prokaryotic organism is discovered by scientists. Are these characteristics enough to place it in a domain, or is more information needed?
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Answer:

Your answer is ANION

Answer:

Temperature increase with the increasing Kinetic energy of the molecule.

Explanation:

When Kinetic energy of the molecule increases, the number of collisions increases between the molecule. Hence, By speeding up the molecule temperature increases.

Answer:

The answer is 1.5 moles.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law:

P * V = n * R * T

where n is the number of moles and R is the molar constant of the gases.

In this case:

Replacing:

1 atm*33.6 L= n* 0.082 [tex]\frac{atm*L}{mol K}[/tex] *273 °K

Solving:

[tex]n=\frac{1 atm* 33.6 L}{0.082\frac{atm*L}{mol K}*273K }[/tex]

n= 1.5 moles

So, the answer is 1.5 moles.

Answer:

1.5 moles

Explanation:

Answer:

Explanation:

The dilution equation is:

Where C₁ and C₂ are concentrations and V₁ and V₂ are volumes of the concentrated and diluted solutions.

First, convert the 75. mL volume into liters:

Now, substitute the data into the dilution formula:

The molarity of the new 2.0 L solution made by diluting 75 mL of 17.6M acetic acid is 0.66M, calculated using the dilution equation M1 x V1 = M2 x V2.

To calculate the molarity of the diluted acetic acid solution, we can use the concept of dilution, which is described by the equation

M1 x V1 = M2 x V2, where:

Using the provided information, M1 = 17.6M, V1 = 75 mL, and V2 = 2,000 mL (as 2.0 L is equivalent to 2,000 mL). We need to solve for M2, the molarity of the new solution:

M1 x V1 = M2 x V2

17.6M * 75 mL = M2 * 2,000 mL

M2 = (17.6M * 75 mL) / 2,000 mL

M2 = 0.66M (rounded to two decimal places)

Therefore, the molarity of the diluted acetic acid solution is 0.66M.

The term associated with the solution is saturated.

The term associated with a solution that is saturated at 25°C and then slowly cooled to 20°C with no change to its appearance is saturated.

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In the precipitation reaction, the ion that would NOT be present in the complete ionic equation is the iodide ion (I-).

In the precipitation reaction Pb(NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq), the ions Pb2+ and NO3- are present in the complete ionic equation because they are soluble in water and dissociate into ions. However, the solid PbI2 that forms is insoluble in water and does not dissociate into ions. Therefore, the iodide ion (I-) is the ion that would NOT be present in the complete ionic equation.

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In the given precipitation reaction, all ions mentioned would be present in the complete ionic equation because soluble compounds turn into ions in such reaction. However, the potassium ion (K+) and the nitrate ion (NO3-) do not partake in the formation of the solid lead iodide, so they are omitted from the net ionic equation.

The question is asking about a precipitation reaction, which is when an insoluble compound forms in an aqueous solution. For the reaction given (2KI(aq) + Pb(NO3)2(aq) → PbI₂ (s) + 2KNO3(aq)), the insoluble compound that forms is lead iodide (PbI₂), which is why it is denoted with an (s) for solid. Soluble compounds break down into ions in aqueous solutions, meaning Pb(NO3)2(aq) becomes Pb²⁺ + 2NO3⁻, and 2KI(aq)  becomes 2K⁺ + 2I⁻. The products would then be K⁺ + NO3⁻ from KNO3(aq) and PbI₂(s), which stays unbroken because it is insoluble. Therefore, the complete ionic equation would be Pb²⁺(aq) + 2NO3⁻(aq) + 2K⁺(aq) + 2I⁻(aq) → PbI₂(s) + 2K⁺(aq) + 2NO3⁻(aq).

In such an equation, the ions that are on both sides of the equation (i.e., do not participate in generating the solid) are spectator ions and can be omitted to achieve the net ionic equation. For our reaction, the spectator ions are K⁺ and NO3⁻. Thus, they would NOT be present in the net ionic equation, but they would still be present in the complete ionic equation.

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Answer:

0.925 mole

Explanation:

From the question given, the following were obtained:

Volume = 1.0L

Molarity = 0.925 M

Number of mole of Nickel (II) chloride =?

Molarity is simply defined as the mole of solute per unit litre of the solution.

It is represented mathematically as:

Molarity = mole /Volume

With the above equation, we can easily find the mole of Nickel (II) chloride present in the solution as follow:

Molarity = mole /Volume

0.925 = mole / 1

Mole = 0.925 x 1

Mole of Nickel (II) chloride = 0.925 mole

Answer:

Fatty acids have an even number of carbons because they are synthesized from a starting material (acetyl-CoACoA) that has an even number of carbons.

Explanation:

Fatty acids are carboxylic acids and are known to have even number of carbon atoms because they are synthesized from a 2 carbon atom acetyl Co-A molecules which are assembled together. It contains a carboxylate group covalently joined with an hydrophobic head of CH3-(CH2)n and may have an unsatireated CH=CH group within its CH2 chain. The synthesis of fatty acids from acetyly Co-A involves the activation reaction of an enzyme acetyl Co-A synthetase with an acid. It involves dehydrogebation, hydration, oxidation and thiolysis. Fatty acids vary in length of its chain, the number of carbon-carbon double bonds attached to its CH2 chain nd also the location of those double bonds in the carbon chain. Saturated fatty acids are those without carbon-carbon double bond in its chain while unsaturated have carbon- carbon double bonds. Monounsaturated fatty acids have one carbon-carbon double bonds and polyunsaturated fatty acids have two or more carbon-carbon double bonds.

Fatty acids are the building blocks of fat molecules. The fat when broken down into simpler forms, yields fatty acids and glycerol.

The correct answer is:

Option C. Fatty acids have an even number of carbons because they are synthesized from a starting material (acetyl-CoACoA) that has an even number of carbons.

The fatty acids are generally even numbers because of the even precursor.

The metabolism of fatty acids starts with the two molecules of the acetyl coenzyme A, which on assembling yields the even-numbered of fatty acids.

The acetyl coenzyme A is an even-numbered two-carbon molecule, which undergoes enzyme-catalyzed reactions to yield an even number of fatty acids.

The even number of fatty acids can be saturated (made up of single bonds) or can be unsaturated (presence of double or triple bonds).

Therefore, Option C is correct.

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Answer: punnet square

Explanation:

3.41 is  the pH value of a sample that has ten times fewer hydronium ions than an equal volume of a vinegar sample with a pH value of 2.4.

Explanation:

pH of the first sample of acetic acid = 2.4

to know the [H+] concentration in the acetic acid solution, the equation used is:

pH = -log [H+]

[H+] = [tex]10^{-pH}[/tex]

[H+] = [tex]10^{-2.4}[/tex]

[H+]  = 3.98 X [tex]10^{-3}[/tex] M

The concentration of H+ ion in first case is 3.98 X [tex]10^{-3}[/tex] M, the second sample has ten times less hydronium ion so concentration of first case is divided by 10.

3.98 x [tex]10^{-4}[/tex] M

Now pH of the sample having 10 times fewer ions of acetic acid:

pH = -log [H+]

putting the values in the above equation:

pH = -log [3.98 x [tex]10^{-4}[/tex] M]

pH = 3.41

If solution has ten times less hydronium ion the pH will change to 3.41.

3.41 is the pH value of a sample that has ten times fewer hydronium ions. pH gives the concentration of Hydronium ion.

What information we have:

pH of the first sample of acetic acid = 2.4

To know the [H+] concentration in the acetic acid solution, the equation used is:

[tex]pH = -log [H^+]\\\\H^+ = 10^{-pH}\\\\H^+ = 10^{-2.4}\\\\H^+ = 3.98 *10^{-4} M[/tex]

The concentration of H+ ion in first case is [tex]3.98 *10^{-4} M[/tex], the second sample has ten times less hydronium ion so the concentration of first case is divided by 10.

[tex]3.98 *10^{-4} M[/tex],

Now pH of the sample having 10 times fewer ions of acetic acid:

pH = -log [H+]

pH = -log [ [tex]3.98 *10^{-4} M[/tex],]

pH = 3.41

If the solution has ten times less hydronium ion the pH will change to 3.41.

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Final answer:

The symbol notation for the silicon isotope with 16 neutrons is ¹⁴Si, where 14 is the atomic number and 30 is the mass number (sum of protons and neutrons).

Explanation:

The silicon isotope that contains 16 neutrons has a symbol notation that includes the element's atomic number, which is 14 for silicon (Si), and its mass number. The mass number is the sum of the number of protons and neutrons in the nucleus. For this isotope of silicon with 14 protons and 16 neutrons, the mass number is 14 + 16 = 30. Therefore, the symbol notation for this isotope is ¹⁴Si.

The final temperature of the gas is 234K. As the volume of the increases to the given value, the temperature of the gas also increases.

Charle's law states that the volume of an ideal gas is directly proportional to the absolute temperature provided pressure is kept at constant.

It is expressed as;

V₁/T₁ = V₂/T₂

Given the data in the question;

Initial volume V₁ = 62.0mL = 0.062L

Initial temperature T₁ = 175K

Final volume V₂ = 82.9mL = 0.0829L

Final temperature T₂ = ?

To calculate the final temperature, we subtsitute our given values into the expression above.

V₁/T₁ = V₂/T₂

V₁T₂ = V₂T₁

T₂ = V₂T₁ / V₁

T₂ = ( 0.0829L × 175K ) / 0.062L

T₂ = 14.5075LK / 0.062L

T₂ = 234K

The final temperature of the gas is 234K. As the volume of the increases to the given value, the temperature of the gas also increases.

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Answer:

The answer to your question is 0.57 moles

Explanation:

Data

volume = 1.9 L

[NaCl] = 0.3

moles of NaCl = ?

Process

1.- To solve this problem use the formula of Molarity.

Molarity = moles/ volume (l)

-Solve for moles

moles = Molarity x volume

-Substitution

 moles = 0.3 x 1.9

-Result

 moles = 0.57

-Conclusion

There are 0.57 moles of NaCl in 1.90 L of a 0.3 M solution.

Answer:

It's the middle one, B. H+ and OH-

Explanation:

I just did the question online

The solution with a pH of 2 has 100 times more protons in it than the solution with a pH of 4.

The pH scale is a logarithmic scale that quantifies a solution's acidity or alkalinity based on the concentration of hydrogen ions (protons) in it. Each unit on the pH scale reflects a tenfold change in hydrogen ion concentration. When compared to a solution with a pH of 4, a solution with a pH of 2 has a larger concentration of hydrogen ions. In particular, for every pH unit reduction, the concentration of hydrogen ions increases by a factor of ten. As a result, a pH 2 solution contains 102 (100) times more hydrogen ions than a pH 4 solution.

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A solution with a pH of 2 has a hundred times more protons than a solution with a pH of 4. PH measures the concentration of hydrogen ions (protons) in a solution in a logarithmic scale, where each unit decrease indicates a tenfold increase.

The pH scale is a logarithmic measure of the concentration of hydrogen ions (protons) in a solution. A solution with a pH of 2 has a hundred times (102) more protons than a solution with a pH of 4, because each unit decrease on the pH scale represents a tenfold increase in proton concentration. Therefore, a decrease from pH 4 to pH 2 constitutes a hundredfold increase in proton concentration.

Answer:

The specific heat of alloy  [tex]C_{alloy} = 1.007 \frac{KJ}{Kg K}[/tex]

Explanation:

Mass of the alloy = 30.5 gm = 0.0305 kg

Initial temperature = 93 °c = 366 K

Mass of water = 50 gm = 0.05 kg

Initial temperature = 22 °c = 295 K

Final temperature of the mixture = 31.1 °c = 304.1 K

From the energy conservation principal the heat lost by the alloy is equal to heat gain by the water.

Heat lost by alloy

[tex]Q_{alloy} = m C (T_{f}- T_{i} )[/tex]

[tex]Q_{alloy} = (0.0305) C_{alloy} (366-304.1)[/tex]

[tex]Q_{alloy} = (1.88795) C_{alloy}[/tex]  ------- (1)

Heat gain by water

[tex]Q_{w} = (0.05) (4.18) (304.1 - 295)[/tex]

[tex]Q_{w} = 1.9019 \frac{KJ}{kg K}[/tex]  ------- (2)

Equation (1) = Equation (2)

[tex](1.88795) C_{alloy} = 1.9019[/tex]

[tex]C_{alloy} = 1.007 \frac{KJ}{Kg K}[/tex]

This is the specific heat of alloy.

Taking into account the definition of calorimetry,  the specific heat capacity of the alloy is 1.063 [tex]\frac{kJ }{kgK}[/tex]

In first place, calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

In this way, between heat and temperature there is a direct proportional relationship.

The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body.

So, the equation that allows to calculate heat exchanges is:

Q = C× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance C and where ΔT is the temperature variation.

In this case, you know:

for alloy:

for water:

Replacing in the expression to calculate heat exchanges:

for alloy:

for water:

On the other hand, the heat of the calorimeter can be expressed as:

Qcalorimeter= Ccalorimeter×ΔT

Being:

and replacing you get:

Qcalorimeter= 0.0092 [tex]\frac{kJ}{K}[/tex]× 9.2 K

It should be taken into account that a system at different temperatures evolves spontaneously towards a state of equilibrium in which all bodies have the same temperature. Then, mixing two quantities of liquids at different temperatures generates an energy transfer in the form of heat from the hottest to the coldest. Said energy transit is  held until temperatures equalize, when it is said to have reached thermal equilibrium.

So the heat released by the sample is absorbed by the calorimeter and the water.

Qalloy= Qcalorimeter + Qwater

Replacing the corresponding expressions and solving:

Calloy× 0.0305 kg× 61.9 K= 0.0092 [tex]\frac{kJ}{K}[/tex]× 9.2 K + 4.18 [tex]\frac{kJ}{kgK}[/tex]× 0.050 kg× 9.2 K

Calloy× 1.88795 kg× K= 0.08464 kJ + 1.9228 kJ

Calloy× 1.88795 kg× K= 2.00744 kJ

[tex]Calloy=\frac{2.00744 kJ }{1.88795 kgK}[/tex]

Calloy= 1.063 [tex]\frac{kJ }{kgK}[/tex]

Finally, the specific heat capacity of the alloy is 1.063

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Answer:

P₃ = 594.1 mmHg

Explanation:

Given data:

Total pressure of container = 1439 mmHg

Partial pressure of 1st gas = 523.3 mmHg

Partial pressure of 2nd gas = 509.8 mmHg

Partial pressure of 3rd gas = ?

Solution:

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ ............+Pₙ

Now we will solve this  problem by using this law.

P(total) = P₁ + P₂ + P₃

439 mmHg =  523.3 mmHg +  509.8 mmHg + P₃

439 mmHg =  1033.1 mmHg + P₃

P₃ = 1033.1 mmHg -439 mmHg

P₃ = 594.1 mmHg

Answer: All of them are right there’s no wrong answer

Explanation:

Masses for the metal and the water in the calorimeter, temperature changes for the water and the metal, and the known specific heat of the water.

First, the masses of both the metal and the water within the calorimeter are crucial, as they determine the amount of substance undergoing the temperature change. Second, the temperature changes (Tw, final​ −Tw, initial​  and T metal, final −T metal, initial​ ) are necessary to quantify the heat exchange during the experiment. Lastly, the known specific heat of water (C water​ ) plays a role in the calculation, as it is a fundamental constant representing the amount of heat needed to raise the temperature of water.

The first law of thermodynamics, which states that the heat lost by the metal equals the heat gained by the water, and the ability of heat to flow from a hot object to a cooler one are overarching principles guiding the experimental setup and the interpretation of results. However, these principles are not directly inputted into the formula but are fundamental concepts in calorimetry and thermodynamics that inform the experimental design and the interpretation of the calculated specific heat values.

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Answer:

BeO

Explanation:

The chemical formula for beryllium oxide is BeO, following the combination of beryllium (Be2+) cations with oxide (O2-) anions in a 1:1 ratio, reflecting the stoichiometry of the compound and its ionic character.

The chemical formula for beryllium oxide is BeO. Beryllium oxide forms when beryllium, an alkaline earth metal with an atomic number of 4, combines with oxygen. Each beryllium atom releases two electrons, forming a Be2+ cation to Oxide2-. The resultant ionic compound, BeO, is a reflection of this 1:1 charge balance between beryllium and oxygen.

Beryllium compounds generally exhibit a significant degree of covalency. In particular, beryllium forms covalent bonds in different environments, as seen in compounds like beryllium hydride (BeH2) and basic beryllium acetate [tex](Be_{4} O(CH_{3}CO_{2} )_6)[/tex].

Although beryllium's tendency to form covalent bonds might suggest a preference for complex molecular structures, BeO is a simple, stable compound with each beryllium atom adopting an electron configuration similar to that of helium, the noble gas that precedes it in the periodic table.

Answer : The limiting reagent in this reaction is, [tex]Al_2(SO_4)_3[/tex] and number of moles of excess reagent is, 1.69 moles

Explanation : Given,

Mass of [tex]Al_2(SO_4)_3[/tex] = 500.0 g

Mass of [tex]Ca(OH)_2[/tex] = 450.0 g

Molar mass of [tex]Al_2(SO_4)_3[/tex] = 342.15 g/mol

Molar mass of [tex]Ca(OH)_2[/tex] = 74.1 g/mol

First we have to calculate the moles of [tex]Al_2(SO_4)_3[/tex] and [tex]Ca(OH)_2[/tex].

[tex]\text{Moles of }Al_2(SO_4)_3=\frac{\text{Given mass }Al_2(SO_4)_3}{\text{Molar mass }Al_2(SO_4)_3}[/tex]

[tex]\text{Moles of }Al_2(SO_4)_3=\frac{500.0g}{342.15g/mol}=1.461mol[/tex]

and,

[tex]\text{Moles of }Ca(OH)_2=\frac{\text{Given mass }Ca(OH)_2}{\text{Molar mass }Ca(OH)_2}[/tex]

[tex]\text{Moles of }Ca(OH)_2=\frac{450.0g}{74.1g/mol}=6.073mol[/tex]

Now we have to calculate the limiting and excess reagent.

The given chemical reaction is:

[tex]Al_2(SO_4)_3(aq)+3Ca(OH)_2(aq)\rightarrow 2Al(OH)_3(s)+3CaSO_4(s)[/tex]

From the balanced reaction we conclude that

As, 1 mole of [tex]Al_2(SO_4)_3[/tex] react with 3 mole of [tex]Ca(OH)_2[/tex]

So, 1.461 moles of [tex]Al_2(SO_4)_3[/tex] react with [tex]1.461\times 3=4.383[/tex] moles of [tex]Ca(OH)_2[/tex]

From this we conclude that, [tex]Ca(OH)_2[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]Al_2(SO_4)_3[/tex] is a limiting reagent and it limits the formation of product.

Number of moles of excess reagent = 6.073 - 4.383 = 1.69 moles

Therefore, the limiting reagent in this reaction is, [tex]Al_2(SO_4)_3[/tex] and number of moles of excess reagent is, 1.69 moles

Most nonmetals do not lose electrons when bonding with metal atoms; instead, they tend to gain electrons, forming anions. They share electrons in covalent bonds with other nonmetals.

The characteristic that is not typical of most nonmetals is their atoms lose electrons when bonding with metal atoms. When bonding occurs, nonmetals usually do the opposite; they tend to gain electrons to achieve more stable electron configurations. This is often seen in ionic bonds, where metals lose electrons to become positively charged cations, and nonmetals gain electrons to become negatively charged anions. However, in the case of bonding with other nonmetals, they typically share electrons, resulting in covalent bonds. Furthermore, nonmetals do indeed readily form compounds with other elements, either through ionic or covalent bonding.

Final answer:

Most nonmetals gain electrons when bonding with metal atoms to achieve stability, and they can also share electrons with other nonmetal atoms.

Explanation:

The characteristic that is not a characteristic of most nonmetals is that their atoms lose electrons when bonding with metal atoms. Nonmetals tend to gain electrons when bonding with metal atoms in order to achieve a stable electron configuration. They can also share electrons with other nonmetal atoms to form covalent bonds. Additionally, nonmetals readily form compounds with other elements.

Answer:

The correct answer is option a.

Explanation:

When aluminum hydroxide reacts with of nitrous acid it gives of aluminum nitrite and of water.

[tex]Al(OH)_3+3HNO_2\rightarrow Al(NO_2)_3+3H_2O[/tex]

According to above reaction ,when 1 mole of aluminum hydroxide reacts with 3 moles of nitrous acid it gives 1 mole of aluminum nitrite and 3 moles of water.

Hence, the correct answer is option a.

Answer:

[tex]H_{rxn} = -93.52 \frac{KJ}{mol}[/tex]

The final temperature [tex]T_{2} = 50.21[/tex]  ° c

Explanation:

(a).

[tex]H_{rxn} = H_{products} - H_{reactents}[/tex]

[tex]H_{reactants}[/tex] = - 813.9 [tex]\frac{KJ}{mol}[/tex]

[tex]H_{Products}[/tex] = - 907.51  [tex]\frac{KJ}{mol}[/tex]

[tex]H_{rxn} = -907.51 + 813.9[/tex]

[tex]H_{rxn} = -93.52 \frac{KJ}{mol}[/tex]

(b).

[tex]H_{rxn} = -93.52 \frac{KJ}{mol}[/tex]

E = 93520 J

C = 3.5 [tex]\frac{KJ}{kg K}[/tex]

Initial temperature [tex]T_{1} = 25[/tex] ° c

Mass (m) = density × volume

m = 1060 × 1

m = 1060 gm

[tex]E = m C (T_{2} - T_{1} )[/tex]

93520 =1060 × 3.5 × ( [tex]T_{2}[/tex] - 298 )

[tex]T_{2} = 50.21[/tex]  ° c

This is the final temperature.

(c).

The density of sulfuric acid is more than the water. so when water is added to acid the mixing process does not takes properly. So we have to add acid in to the water.

Adding water is exothermic process so when we add water to acid than in that case more energy produces and wasted.

Answer : The volume of oxygen occupy at 173° would be, 703.2 mL

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

where,

[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.

[tex]V_2\text{ and }T_2[/tex] are the final volume and temperature of the gas.

We are given:

[tex]V_1=473mL\\T_1=27^oC=(27+273)K=300K\\V_2=?\\T_2=173^oC=(173+273)K=446K[/tex]

Now put all the given values in above equation, we get:

[tex]\frac{473mL}{300K}=\frac{V_2}{446K}\\\\V_2=703.2mL[/tex]

Therefore, the volume of oxygen occupy at 173° would be, 703.2 mL

Answer:

Explanation:

M

Answer:200 c

Explanation:

Final answer:

To raise the temperature of 20 grams of water from 30°C to 40°C, 200 calories of heat are required.

Explanation:

To calculate the amount of heat required to raise the temperature of water, we can use the equation:

heat = mass * specific heat * temperature change

In this case, the mass of water is 20 grams, the specific heat of water is 1 calorie/gram °C, and the temperature change is 10 °C. Substituting these values into the equation:

heat = 20 g * 1 calorie/g °C * 10 °C = 200 calories

Therefore, 200 calories of heat are required to raise the temperature of 20 grams of water from 30 °C to 40 °C.

Answer:

heated crude oil enters a tall fractionating column , which is hot at the bottom and gets cooler towards the top.

vapours from the oil rise through the column.

vapours condense when they become cool enough.

liquids are led out of the column at different heights.

sorry for bad spelling i think this is right

hope this helps :)

Heated crude oil needs to enter a tall fractionating column that is hot at the bottom and cools as it ascends. The oil vapors rise through the column. When vapors cool sufficiently, they condense.

A mixture of liquids is boiled in a fractional distillation, and the resulting vapors travel up a glass tube known as a "fractionating column" and separate.

The fractionating column, which is positioned between the flask containing the mixture and the "Y" adaptor, improves the separation of the liquids being distilled.

In general, the distillation process consists of three major steps: The process of converting a desired liquid from a mixture into vapor. The purified liquid's condensation. The condensed liquid collection.

Heated crude oil enters a tall fractionating column, which is hot at the bottom and cools as it ascends.

The oil vapors rise through the column. When vapors cool sufficiently, they condense. At various heights, liquids are led out of the column.

Thus, these are the steps involved in fractional distillation that used to refine crude oil.

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Answer:

500.65mL

Explanation:

The following information were obtained from the question:

V1 (initial volume) = 461 mL

P1 (initial pressure) = stp = 101325Pa

P2 (final pressure) = 93.3 kPa

Recall: 1KPa = 1000Pa

Therefore, 93.3 kPa = 93.3x1000 = 93300Pa

V2 (final volume) =?

Using the Boyle's law equation P1V1 = P2V2, the final volume of the gas can be obtained as follow:

P1V1 = P2V2

461 x 101325 = 93300 x V2

Divide both side by 93300

V2 = (461 x 101325)/93300

V2 = 500.65mL

Therefore, the volume of Neon at 93.3 kPa is 500.65mL

Answer:

M or mol/[tex]dm^{3}[/tex]

Explanation:

Answer:

Mol/kg

Explanation:

Ape-x