. A water balloon is thrown horizontally at a speed of 2.00 m/s from the roof of a building that is 6.00m above the ground. At the same instant the balloon is released; a second balloon is thrown straight down at 2.00 m/s from the same height. Determine which balloon hits the ground first and how much sooner it hits the ground than the other balloon

Answers

Answer 1

Answer:

Explanation:

Height of building

H = 6m

Horizontal speed of first balloon

U1x = 2m/s

Second ballot is thrown straight downward at a speed of

U2y = 2m/s

Time each gallon hits the ground

Balloon 1.

Using equation of free fall

H = Uoy•t + ½gt²

Uox = 0 since the body does not have vertical component of velocity

6 = ½ × 9.8t²

6 = 4.9t²

t² = 6 / 4.9

t² = 1.224

t = √1.224

t = 1.11 seconds

For second balloon

H = Uoy•t + ½gt²

6 = 2t + ½ × 9.8t²

6 = 2t + 4.9t²

4.9t² + 2t —6 = 0

Using formula method to solve the quadratic equation

Check attachment

From the solution we see that,

t = 0.9211 and t = -1.329

We will discard the negative value of time since time can't be negative here

So the second balloon get to the ground after t ≈ 0.92 seconds

Conclusion

The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.

. A Water Balloon Is Thrown Horizontally At A Speed Of 2.00 M/s From The Roof Of A Building That Is 6.00m
Answer 2

Answer:

Second balloon hits ground Δt = 0.185 seconds sooner than first balloon

Explanation:

Given:-

- The first balloon is thrown horizontally with speed, u1 = 2.0 m/s

- The second balloon is thrown down with speed, u2 = 2.0 m/s

- The height from which balloon are thrown, si = 6.0 m (above ground)

Find:-

Determine which balloon hits the ground first and how much sooner it hits the ground than the other balloon

Solution:-

- We will first determine the time taken (t1) for the first balloon thrown horizontally with speed u1 = 2.0 m/s from top of building from a height of s = 6.0 m from ground to it the ground.

- Using the second kinematic equation of motion in vertical direction:

                         si = 0.5*g*t1^2

Where,     g: The gravitational constant = 9.81 m/s^2

                        6.0 = 4.905*t1^2

                        4.905*t1^2 - 6.0 = 0

- Solve the quadratic equation:

                        t 1 = 1.106 s

- Similarly, the time taken (t2) for the second balloon thrown down with speed u2 = 2.0 m/s from top of building from a height of s = 6.0 m from ground to it the ground.

- Using the second kinematic equation of motion in vertical direction:

                         si = u2*t2 + 0.5*g*t1^2

Where,     g: The gravitational constant = 9.81 m/s^2

                        6.0 = 4.905*t1^2 + 2*t2

                        4.905*t1^2 + 2*t2 - 6.0 = 0

- Solve the quadratic equation:

                        t 2 = 0.9208 s

- We see that the second balloon thrown down vertically hits the ground first. The second balloon reaches ground, t1 - t2 = 0.185 seconds, sooner than first balloon.


Related Questions

**URGENT, I WILL PAY 30 POINTS, PLEASE HELP**
Which wave has the shortest wavelength, assuming the axis for each wave is identical?

Answers

All three windows are the same size.

A has 10 complete waves visible through the window. B has 3, and C has 4.

So A must have the smallest wavelengths.

The answer is A.

The wavelength is the length to each curve. Each answer choice has the same length of a box so we can count the amount of curves in each option.

Option A has 10 visible curves.

Option B has 3 visible curves.

Option C has 4 visible curves.

Since option A has the most curves, that means that it has the shortest wavelengths.

Best of Luck!

What are the methods that are used for heat transfer

Answers

Answer:

Heat can travel from one place to another in three ways: Conduction, Convection and Radiation. Both conduction and convection require matter to transfer heat. If there is a temperature difference between two systems heat will always find a way to transfer from the higher to lower system.

Explanation:

Hope this helps

(a) Neil A. Armstrong was the first person to walk on the moon. The distance between the earth and the moon is . Find the time it took for his voice to reach the earth via radio waves. (b) Someday a person will walk on Mars, which is from the earth at the point of closest approach. Determine the minimum time that will be required for a message from Mars to reach the earth via radio waves.

Answers

Answer:

a) It took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves.

b) The minimum time that will be required for a message from Mars to reach the Earth via radio waves is 192 seconds.

Explanation:

The electromagnetic spectrum is the distribution of radiation due to the different frequencies at which it radiates and its different intensitie. That radiation is formed by electromagnetic waves, which are transverse waves formed by an electric field and a magnetic field perpendicular to it.

The distribution of the radiation in the electromagnetic spectrum can also be given in wavelengths, but it is more frequent to work with it at frequencies:

Gamma rays X-rays Ultraviolet rays Visible region InfraredMicrowave Radio waves.

Any radiation that belongs to electromagnetic spectrum has a speed in vacuum of [tex]3x10^{8}m/s[/tex].  

a) Find the time it took for his voice to reach the Earth via radio waves.

To know the time that took for Neil Armstrong's voice to reach the Earth via radio waves, the following equation can be used:

[tex]c = \frac{d}{t}[/tex]  (1)

Where v is the speed of light, d is the distance and t is the time.

Notice that t can be isolated from equation 1.

[tex]t = \frac{d}{c}[/tex]  (2)

The distance from the Earth to the Moon is [tex]3.85x10^{8} m[/tex], therefore.

[tex]t = \frac{3.85x10^{8} m}{3x10^{8}m/s}[/tex]

[tex]t = 1.28s[/tex]

Hence, it took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves.

b) Determine the minimum time that will be required for a message from Mars to reach the Earth via radio waves.

The distance from the Earth to the Mars at its closest approach is [tex]5.76x10^{10}m[/tex], therefore.

[tex]t = \frac{5.76x10^{10}m}{3x10^{8}m/s}[/tex]

[tex]t = 192s[/tex]

Hence, the minimum time that will be required for a message from Mars to reach the Earth via radio waves is 192 seconds.

When the person ran that blue light over the beads they_________,
The blue light bar that the person was using must therefore be emitting_____________.

A. Changed Colors; UV light
B. Exploded; Heat
C. Stayed White; Energy

Answers

Answer:

A Changed colors: UV light

Explanation:

Was a uv light, reacted just like the sun did.

Answer:

A changed colors

Explanation:

please mark me as brainliest

____is the only item that exists on earth at standard pressures as a solid, liquid, and gas.

Answers

Answer:

Plasma

Explanation:

Answer:

I think the answer is water.

Explanation:

It becomes a solid when frozen, when it's at it's true form it's a liquid, and when it evaporates it becomes water vapor (which is basically gas).

A penny rides on top of a piston as it undergoes vertical simple harmonic motion with an amplitude of 4.0 cm. If the frequency is low, the penny rides up and down without difficulty. If the frequency is steadily increased, there comes a point at which the penny leaves the surface.

1) At what point in the cycle does the penny first lose contact with the piston?

A. midpoint moving up

B. midpoint losing down

C. highest point

D. lowest point

Answers

Answer: C

Explanation:

Highest Point

As matter changes state from gas to liquid, which of these statements is true?

Answers

Answer:

it is condensing , intermolecular forced are getting stronger

Explanation:

condensation is gas to liquid and intermolecular forces are attaction and liquid molecules are colser together so they have more intermolecular forces hope this helps god bless

Water occupies two main fluid compartments within the body, the intracellular fluid compartment and the extracellular fluid compartment. Which of the following statements is true concerning the volume of intracellular fluidA. The ICF fluid compartment changes, so there is no way to determine the amount of water at a given timeB. Approx. One third of the water is in the ICF compartmentC. Approx. Two thirds of the water is in the ICF compartmentD. All of the water is in the ICF compartment

Answers

Answer:

C. Approx. Two thirds of the water is in the ICF compartment

Explanation:

The body cells are bathed in fluids internally and externally. The water inside the cells make up about 42% of the total body weight and is called the intracellular fluid (ICF). The rest of the fluid outside the cells is called extracellular fluid (ECF) and is separated from the intracellular fluid by a semipermeable membrane that surrounds the cell, and only allows fluid to flow in and out of the cells, but prevents unwanted molecules or materials from getting in.

Diffuse reflection occurs when the size of surface irregularities is

Answers

Diffuse reflection occurs when the irregularities of a surface are comparable to or larger than the wavelength of the incident light, causing light to scatter in multiple directions.

Diffuse reflection occurs when light reflects off a surface that has irregularities comparable to or larger than the wavelength of the incident light. The surface's unevenness causes the incoming light rays to reflect in multiple directions, giving a non-glossy or matte appearance to the surface. This should be contrasted with specular reflection, where a smooth surface reflects light in a singular, coherent direction, maintaining the angle of incidence equal to the angle of reflection.

A familiar example of diffuse reflection is the way sunlight illuminates a room; the light is scattered by the walls and objects, which have microscopically rough surfaces. In contrast, a mirror provides a clear image due to specular reflection because its surface irregularities are much smaller than the wavelength of visible light. This principle of diffuse versus specular reflection is fundamental in understanding how different materials and surfaces affect the quality of reflected light.

A 10.5- resistor, a 15.9-μF capacitor, and a 15.2-mH inductor are connected in series with a 203-V generator. (a) At what frequency is the current a maximum? (b) What is the maximum value of the rms current? Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise.

Answers

(a) The resonant frequency where current is maximum is: f_res = 1 / (2π√(LC)) ≈ 323.74 Hz.

(b) The maximum rms current is: I_max = V / √(R^2 + (1 / (2πf_resC))^2 + (2πf_resL)^2) ≈ 4.51 A.


Here's a step-by-step solution for both parts of the problem:

(a) Finding the resonant frequency:

Identify the formula: The resonant frequency (f_res) of a series RLC circuit is given by:

f_res = 1 / (2π√(LC))

Plug in values: Substitute the given values of inductance (L = 15.2 mH = 0.0152 H) and capacitance (C = 15.9 μF = 15.9 × 10^-6 F) into the formula:

f_res = 1 / (2π√(0.0152 H × 15.9 × 10^-6 F))

Calculate: Use a calculator to evaluate the expression:

f_res ≈ 323.74 Hz

Therefore, the current is maximum at a frequency of approximately 323.74 Hz.

(b) Finding the maximum rms current:

Identify the formula: The rms current (I) in a series RLC circuit is given by:

I = V / √(R^2 + (X_L - X_C)^2)

where:

V is the generator voltage (203 V)

R is the resistance (10.5 Ω)

X_L is the inductive reactance (2πfL)

X_C is the capacitive reactance (1 / (2πfC))

Calculate reactances at resonant frequency:

X_L = 2πf_resL ≈ 30.15 Ω

X_C = 1 / (2πf_resC) ≈ 30.15 Ω (at resonance, X_L and X_C are equal)

Plug in values: Substitute the values into the formula:

I = 203 V / √(10.5 Ω^2 + (30.15 Ω - 30.15 Ω)^2)

Simplify and calculate:

I ≈ 203 V / 10.5 Ω ≈ 4.51 A

Therefore, the maximum rms current in the circuit is approximately 4.51 A.

The frequency at which the current is maximum in the given RLC circuit is approximately 326 Hz, and the maximum value of the RMS current is about 19.3 A.

To solve the question, we need to work with the concepts of an RLC circuit driven by an AC source.

Let's break down the steps:

The frequency at which the current is a maximum in an RLC circuit is the resonant frequency. This can be calculated using the formula:

[tex]F(resonant) = \( \frac{1}{2 \pi \sqrt{LC}} \)[/tex] \)

Given:

Inductance, L = 15.2 mH = 15.2 × 10⁻³ HCapacitance, C = 15.9 μF = 15.9 × 10⁻⁶ F

Plugging in these values:

[tex]F(resonant) = \( \frac{1}{2 \pi \sqrt{(15.2 \times 10^{-3})(15.9 \times 10^{-6})}} \)[/tex])}} \)[tex]F(resonant) = 326 Hz[/tex]

At resonance, the impedance Z is equal to the resistance R. The maximum RMS current can be calculated using Ohm's Law:

[tex]I(max) = \( \frac{V(rms)}{R} \)[/tex]

Given:

Resistance, R = 10.5 ΩVoltage, V(rms) = 203 V

Plugging in these values:

[tex]I(max) = \( \frac{203}{10.5} \)\\I(max) = 19.3 A[/tex]

Therefore, the frequency at which the current is maximum is approximately 326 Hz, and the maximum value of the RMS current is approximately 19.3 A.

How is the solubility of a gas in a liquid normally affected by temperature?

Answers

Answer:

Increase in temperature decrease the solubility of games in liquid

Explanation:

Solubility simply means the amount of solute that can be dissolved in a given amount of solute at a given temperature.Gases when heated gains extreme kinetic energy which gives rise to an exothermic reaction,the kinetic energy breaks the individual bonds holding gas molecules leading to their escape,so an increase in temperature decrease the solubility of gas in liquid

Una muestra de 500g de agua se calienta desde 10°C hasta 80°C. Calcula la cantidad de calor absorbido por líquido si su calor específico es 4186J/kg ×K

Answers

Answer:

Q = 142.324kJ

Explanation:

Data:

M = 500g = 0.5kg

T1 = 10°C = (10 + 273.15)K = 285.15K

T2 = 80°C = (80 + 273.15)K = 353.15K

Q = ?

C = 4186J/kg.K

Q = mc(T2 - T1)

Q = 0.5 * 4186 * (353.15 - 285.15)

Q = 0.5 * 4186 * 68

Q = 142324J

Q = 142.324kJ.

Final answer:

The heat absorbed by a 500g sample of water when heated from 10°C to 80°C is calculated using the heat transfer formula q=mcΔT. Here m is mass ie, 0.5kg, c is specific heat capacity i.e., 4186 J/kg*°C, and ΔT is change in temperature i.e., 70°C. After substituting these values in the formula, we find that the heat absorbed, q, is approximately 146300 J.

Explanation:

The question refers to the equation q = mcΔT for calculating heat transfer, where 'q' represents the heat absorbed, 'm' denotes mass, 'c' represents specific heat capacity, and 'ΔT' denotes the change in temperature. In this case, by inserting the values into equation, we have q = (0.5 kg) * (4186 J/kg*°C) * (80°C - 10°C). After resolving this, we find q equals approximately to 146300 J, which is the amount of heat absorbed by the water.

Learn more about Heat Transfer here:

https://brainly.com/question/31065010

#SPJ3

Which kind of weather usually forms over the northwest united states in the summer because of maritime polar air masses?

Answers

Answer:

Cloudy and damp weather

Explanation:

Maritime Polar can form anytime of the year and because they are not as cold as continental polar which brings hot and humid air

The cool and moist Maritime Polar air masses brings cloudy and damp weather to the USA.

Maritime polar air masses form over the northern Atlantic and the northern Pacific oceans. They most often influence the Pacific Northwest and the Northeast.

Answer:

Fog

Explanation:

variable.
Use the drop-down menus to complete each sentence.
To run the physics cart, the fan speed of the cart is manipulated. This is the
The cart accelerates due to the speed of the fan. Acceleration is therefore thinder
A"constant" is a parameter that stays the same regardless of the variables.
dependent
constant
constant is the
of the cart that is held
) Intro
Done

Answers

Answer:

Independent

Dependent

Mass

Explanation:

A holiday ornament in the shape of a hollow sphere with mass 0.015 kg and radius 0.055 m is hung from a tree limb by a small loop of wire attached to the surface of the sphere. If the ornament is displaced a small distance and released, it swings back and forth as a physical pendulum.
Calculate its period. (You can ignore friction at the pivot. The moment of inertia of the sphere about the pivot at the tree limb is 5MR²/3.)
Take the free-fall acceleration to be 9.80 m/s². Express your answer using two significant figures.

Answers

Answer: 0.61 s

Explanation:

Given

Mass of object, m = 0.015 kg

Radius of object, r = 0.055 m

Acceleration of object, g = 9.8 m/s²

In a pendulum,

T = 2π * √[I /(mgd)]

The moment of Inertia, I of a hollow sphere is given by

I(sphere) = 2/3MR² + MR²

I(sphere) = 5/3MR²

Also, d = R

Substituting these into the first equation, we have

T = 2π * √[(5/3MR²) / (mgr)]

T = 2π * √[(5/3r) / (g)]

T = 2 * 3.142 * √(5/3 * 0.055) / (9.8)]

T = 6.284 * √(0.092/9.8)

T = 6.284 * √0.00939

T = 6.284 * 0.097

T = 0.6095 s

To 2 significant figures,

The period is 0.61 s

A light ray in air enters and passes through a block of glass. What can be stated with regard to its speed after it emerges from the block? Speed is less than when in glass. Speed is less than before it entered glass. Speed is same as that in glass. Speed is same as that before it entered glass.

Answers

Answer:

Speed is same as that before it entered glass.

Explanation:

Given:

A light ray enters and passes through the glass as shown in the diagram.

We have to analyze its speed.

Speed of light in air is [tex]3\times 10^8\ ms^-^1[/tex] and speed of light in glass is [tex]2.25\times 10^8\ ms^-^1[/tex]

Whenever a light ray enters a glass block or slab there is bending of light at the interface of the two media.

So speed of light will decrease in glass medium and again it passes to the air.

So

Speed of light in air will again increase or will be equivalent to the earlier speed when it was entering the glass block.

Finally

Speed is same as that before it entered glass as it in the same medium (air).

Speed of light is same as that before it entered glass. Option D is correct.

Refraction:

When a light ray move from one medium to another, it slows down, hence  bend.

Here, light ray from air enters from the air to glass and emerges out of the glass block.

Speed of light in air is [tex]\bold {3x10^8\ m /s}[/tex]

Speed of light in glass is [tex]\bold {2.25 x10^8\ m /s}[/tex]

Since, the light ray was in the air is same before entering in to the glass.

Therefore, speed of light is same as that before it entered glass.

To know more about light ray,

https://brainly.com/question/1030839

If a 2V battery is connected to the wire in one direction, the electrode that was the cathode becomes the anode and vice verse, but when the battery is connected the other way the cathode and anode do not switch. Explain why this is so, and what the voltages of the two situations are.

Answers

Answer:

1. This is so because of the charging and discharging phenomenon of the battery.

2. Voltage when fully charged: approximately 2.15 volts

Voltage when in use: drops below 2.15v

Explanation:

The anode is the electrode where electricity flows into. In contrast, the cathode is the electrode where the electricity flows out of.  When a battery is connected to a load the electricity flows from the positive terminal to the negative terminal. In this case, the positive terminal is the cathode, and the negative terminal is the anode.  Here the cathode and anode do not switch,

But when the battery is being charged, the electricity flows into the positive terminal instead of out of it. In this case, the roles are reversed, the electrode that was the cathode becomes the anode, and the anode becomes that cathode.

A fully charged 2volt battery has a voltage of approximately 2.15 volts. A fully discharged 2 volt battery has a voltage of 1.9 volts

What type of energy is the sum of an object’s potential and kinetic energy?

Answers

Answer: its mechanical energy

Explanation:

Answer:

Mechanical energy edg2021

Explanation:

The sum of an objects potential and kinetic energy is mechanical energy.

An object becomes charged when the atoms in the object gain or lose. True or False

Answers

Answer:

True.

Explanation:

When an object's atoms gain or lose electrons, it becomes an ion, becoming charged.

describe the relationship that exists between amplitude of a wave and the amount of energy that the wave carries

Answers

The amount of energy a wave is carrying is related to the wave's amplitude. The more displacement the first coil is given, the greater the amplitude it will have.

Explanation:

The greater the disturbance is the correlation that endures between the amplitude of a disruption in the water and amount of wave. The amount of energy a wave is carrying is related to the wave's amplitude. If the wave disturbance increases, the wave's amplitude increases, if the wave's disturbance decreases, the wave's amplitude diminishes. Therefore, at-last the amplitude of every transverse pulse is similar to the energy that is transmitted by that pulse through the medium.

summarize the physical reasons that sound waves travel at different speeds through different mediums ​

Answers

Final answer:

The speed of sound varies in different media due to the rigidity (or compressibility in gases) and density of the medium. More rigid and less compressible media enable faster sound travel, while greater density can slow it down. Temperature also plays a role, with higher temperatures often leading to faster sound propagation.

Explanation:Understanding the Speed of Sound in Different Mediums

Sound waves travel at different speeds through different media because of the medium's rigidity and density. A medium's rigidity, or in the case of gases, compressibility, greatly influences the speed of sound. The more rigid or less compressible a medium is, the faster sound travels through it. Additionally, sound travels through a medium of lower density faster when the materials have similar rigidity, because the energy transfer between particles is more efficient.

Liquids and solids, for instance, are harder to compress and more rigid compared to gases, which accounts for the higher speed of sound in these media. However, the relationship is not straightforward with density, as an increased density can actually slow the propagation of sound, due to the increased mass particles have to move. Finally, temperature also affects the speed at which sound travels; hotter media makes particles more energetic and thus can increase the speed of sound.

It's important to understand these physical principles when considering applications such as medical imaging using ultrasonic waves or studying the properties of materials through acoustic analysis.

A radiographer stands six feet from the x-ray source when performing a portable chest exam and receives an exposure of 2 mGy. If the radiographer performs a repeat exam using the same technical factors standing at a distance of three feet from the source, how much exposure will be received?

Answers

Answer:

  I₂ = 8 mG

Explanation:

The intensity of a beam is

          I = P / A

Where P is the emitted power which is 3) 3

           

Let's use index 1 for the initial position of r₁ = 6 ft and 2 for the second position r₂ = 3 ft

          I₁ A₁  = I₂  A₂

           I₂ = I₁ A₁ / A₂

The area of ​​the beam if we assume that it is distributed either in the form of a sphere is

           A₁ = 4π r²

We substitute

            I₂ = I₁ (r₁ / r₂)²

           I₂ = 2 (6/3)²

           I₂ = 2 4

           I₂ = 8 mG

Answer:

The amount of exposure that will be received at 3 ft is 8 mGy

Explanation:

Here, we note that the  amount of radiation exposure of the radiographer is given by the inverse square law. That is the amount of radiation exposure is directly proportional to the inverse square of the distance that is

[tex]\frac{Old \, \, Intensity}{New \, \, \, Intensity} = \frac{(New\, distance)^2}{(Old\, distance)^2} \therefore \frac{2}{New \, \, \, Intensity} = \frac{3^2}{6^2}[/tex]

Or New intensity = [tex]2\times \frac{36}{9}[/tex]  = 8mGy

Therefore, the amount of exposure that will be received at 3 ft = 8 mGy.

Flasher units are being discussed. Technician A says that only a DOT-approved flasher unit should be used for turn signals. Technician B says that a parallel (variable-load) flasher will function for turn signal usage, although it will not warn the driver if a bulb burns out. Who is right?
a. Technician A onlyb. Technician B onlyc. Both Technicians A and Bd. Neither Technician A nor B

Answers

Answer: C

Both Technicians A and B

Explanation:

Only a DOT-approved flasher unit should be used for turn signals. And a parallel (variable-load) flasher will function for turn signal usage, although it will not warn the driver if a bulb burns out.

The International Space Station is orbiting at an altitude of about 370 km above the earth's surface. The mass of the earth is 5.976 × 1024 kg and the radius of the earth is 6.378 × 106 m. Assuming a circular orbit, what is the period of the International Space Station's orbit?

Answers

Answer:

T = 5516.63 seconds

Explanation:

Given that,

The International Space Station is orbiting at an altitude of about 370 km above the earth's surface.

Mass of the Earth, [tex]M=5.976 \times 10^{24}\ kg[/tex]

Radius of Earth, [tex]r=6.378\times 10^6\ m[/tex]

We need to find the period of the International Space Station's orbit. It is a case of Kepler's third law. Its mathematical form is given by :

[tex]T^2=\dfrac{4\pi^2}{GM}\times R^3[/tex]

R = r + h

[tex]T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 5.976 \times 10^{24}}\times (370000+6.378\times 10^6)^3\\\\T^2=30433264.1641\ s\\\\T=5516.63\ s[/tex]

So, the period of the International Space Station's orbit is 5516.63 seconds.

There is a Limited amount of energy available on earth. Why is it important that people conserve energy?

Answers

Answer:

If humans conserve energy then we will have energy for alonger amount of time.

Explanation:

When water is boiled at a pressure of 2.00 atm, the heat of vaporization is 2.20×106J/kg2.20×10
6
J/kg and the boiling point is 120∘C120

C. At this pressure, 1.00 kg of water has a volume of 1.00×10−3m31.00×10
−3
m
3
, and 1.00 kg of steam has a volume of 0.824m30.824m
3
. (a) Compute the work done when 1.00 kg of steam is formed at this temperature. (b) Compute the increase in internal energy of the water.

Answers

Answer:

Explanation:

a ) When 1 kg water is boiled at constant pressure of 1  atm , its volume increases by following volume

(.824 - .001 )m³

.823 m³

work done by steam  = increase in volume x pressure

.823 x 10⁵ J

Heat added

=  latent heat of vaporization x mass

= 2260000 J x 1

= 22.6 x 10⁵ J

Increase in internal energy of gas

= heat added - work done by gas

= (22.6 - .823) x 10⁵ J

= 21.777 x 10⁵ J .

A ray of light, traveling through air, is incident on a smooth transparent liquid surface at an angle of 13 degrees with respect to the normal of the surface. What is the refraction angle of the light in the liquid if the index of refraction of the liquid is 1.54? Return the angle in degrees and rounded to 2 decimal places.

Answers

Answer:

The refraction angle of the light in the liquid is 8.40 degrees.

Explanation:

Given:

A ray of light passing through air to liquid.

Air is medium 1 and liquid is medium 2.

Angle of incidence [tex](\theta_1)[/tex] = 13°

Refractive index, [tex](n_2)[/tex] = 1.54

We have to find the angle of refraction:

Let the angle of refraction be "[tex]\theta_2[/tex]" .

Formula to be used:

[tex]n_1\times sin(\theta_1) =n_2\times sin(\theta_2)[/tex]

Note:

Index of refraction of air  [tex](n_1)[/tex] = 1

Accordingly:

Using Snell's law and plugging the values.

⇒ [tex]n_1\times sin(\theta_1) =n_2\times sin(\theta_2)[/tex]

⇒ [tex]1\times sin(13) =1.54\times sin(\theta_2)[/tex]

⇒ [tex]\frac{1\times sin(13)}{1.54} = sin(\theta_2)[/tex]

⇒ [tex]\frac{1\times 0.2249}{1.54} = sin(\theta_2)[/tex]     ...sin(13) =0.2249

⇒ [tex]\theta_2=sin^-^1(\frac{0.2249}{1.54})[/tex]

⇒ [tex]\theta_2=sin^-^1(0.145)[/tex]

⇒ [tex]\theta_2=8.3974[/tex] degrees.

⇒ [tex]\theta_2 = 8.40[/tex] degrees ...Rounded to 2 decimal place.

The refraction angle of the light in the liquid is 8.40 degrees.

A garden hose attached with a nozzle is used to fill a 10‐ gal bucket. The inner diameter of the hose is 2 cm, and it reduces to 0.8 cm at the nozzle exit. If it takes 50 s to fill the bucket with water, determine (a) the volume and mass flow rates of water through the hose, and (b) the average velocity of water at the nozzle exit.

Answers

Answer:

Explanation:

Given

Volume of bucket [tex]V=10\ gallon[/tex]

Time taken to fill the bucket [tex]t=50\ s[/tex]

so volume flow rate is [tex]\dot{V}=\frac{10}{50}=0.2\ gal/s[/tex]

1 gal is equivalent to [tex]0.133\ ft^3[/tex]

[tex]\dot{V}=0.0267\ ft^3/s[/tex]

mass flow rate [tex]\dot{m}=\rho \times \dot{V}[/tex]

[tex]\dot{m}=62.4\times 0.0267[/tex]

[tex]\dot{m}=1.668\ lbs[/tex]

(b)Average velocity through nozzle exit

[tex]\dot{V}=Av_{avg}[/tex]

[tex]v_{avg}=\dfrac{0.0267}{\frac{\pi}{4}\times (0.0262)^2}[/tex]

[tex]v_{avg}=49.51\ ft/s[/tex]

Final answer:

The volume flow rate is 757.082 cm^3/sec and the mass flow rate is 757.082 g/sec. The average velocity of the water at the nozzle exit is approximately 476.677 cm/sec.

Explanation:

To solve this problem, we first need to figure out the volume and mass flow rates of the water. Given that 1 gallon = 3.78541 liters, and 1 liter = 1,000 cm3, a 10-gallon bucket contains 10 * 3.78541 * 1000 = 37,854.1 cm3. If it takes 50 seconds to fill this bucket, we can calculate the volume flow rate as volume/time = 37,854.1 cm3/50 s = 757.082 cm3/s.

The mass flow rate can be determined by multiplying this volume flow rate by the density of water (1 g/cm3), giving a result of 757.082 g/s.

To find the average velocity of the water at the nozzle exit, we use the equation of continuity which states that the volume flow rate must be constant at all points in the pipe. Therefore, the velocity at the nozzle can be found by dividing the flow rate by the cross-sectional area of the nozzle (pi * (d/2)2). This gives an average velocity of about 476.677 cm/s.

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the two forces acting on a falling object are gravity and?....1.force, 2. friction, 3. air resistance, and 4. net force?​

Answers

The two forces acting on a falling object are gravity and air resistance (option 3). Gravity causes the object to accelerate toward Earth, while air resistance acts in the opposite direction, slowing the object down.

The two forces acting on a falling object are gravity and air resistance (option 3). When an object is dropped, it accelerates toward the center of the Earth due to the force of gravity. In a vacuum, where there is no air, the only force acting on a falling object is its weight, which is the force due to gravity acting on an object of mass m. However, in the real world, objects are not in perfect free-fall because they experience air resistance, which opposes the motion of the object as it falls through the air.

How much would a 77.7 kg person weigh (a) on Earth's Moon, where the acceleration of gravity is 1.63 m/s2, and (b) on Mars, where the acceleration of gravity is 3.77 m/s2?

Answers

Answer:

The answer to your question is below

Explanation:

Data

mass of the person = 77.7 kg

gravity on the moon = 1.63 m/s²

gravity on mars = 3.77 m/s²

Process

To find the weight of a person, use Newton's second law.

Formula

        Force = mass x acceleration  but  Weight = mass x gravity

a)  

        Weight = 77.7 x 1.63

        Weight = 126.65 N

b)  

        Weight = 77.7 x 3.77

        Weight = 292.93 N    

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