A water pump is a positive displacement-type pump true or false

Answers

Answer 1

Answer: True

A water pump belong to a positive displacement pump that provides constant flow of water at fixed speed, regardless of changes in the counter pressure. The two main types of positive displacement pump are rotary pumps and reciprocating pumps.

Moreover, water pump is a reciprocating positive displacement pump that have an expanding cavity on the suction side and a decreasing cavity on the discharge side. In water pumps, the liquid flows into the pumps as the cavity on the suction side expands and then the liquid flows out of the discharge as the cavity collapses providing water in a pail.


Related Questions

which planet rotates different from the others

Answers

Venus spins the opposite direction.

type of circuit does charge move in only one direction

Answers

diode is a device that allows charges to move in only one direction. A diod consists of a PN-junction, with a semiconductor N-type region (with excess of electrons) bonded with a semiconductor P-type region (excess of holes). The region closed to the junction is called 'depletion zone', where electrons from the n-region recombine with holes from the p-region, and acts as an insulating zone. 

The n-region is then connected to the negative terminal of a battery, and the p-region to the positive terminal. This way, if the applied potential difference is strong enough, electrons will start to flow from the n-region (and then also from the depletion region) to the posititive terminal of the battery, while the holes will flow to the negative terminal, so a net current is flowing through the junction.

Vicceversa, if the two n-region is connected to the positive terminal and the p-region to the negative terminal, nothing happens through the junction, because both electrons and holes of the two regions are attracted by the "wrong side": in the n-region, electrons will flow to the negative terminal (so, not crossing the junction), and in the same way the holes of the p-region will flow to the positive terminal without crossing the junction, so no current is flowing through it.

What is the magnitude of a star that's 10 times brighter than a fifth magnitude star?

Answers

The apparent magnitude [tex]m_i[/tex] of a star i measured with respect to the magnitude [tex]m_{ref}[/tex] of another star is given by
[tex]m_i -m_{ref}=-2.5 \log_{10}( \frac{I_i}{I_{ref}} )[/tex]
where [tex]I_i[/tex] and [tex]I_{ref}[/tex] are the brightnesses of the two stars.

In our problem, the star used as reference has magnitude 5, so [tex]m_{ref}=5[/tex]. We also know that the star i is 10 times brighter than the star of magnitude 5, so 
[tex] \frac{I_i}{I_{ref}}=10 [/tex]
therefore, we can rewrite the original equation as:
[tex]m_i-5 = -2.5 \log_{10}(10)=-2.5[/tex]
And so, the magnitude of the star i is
[tex]m_i = 5-2.5 = 2.5[/tex]

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