A wire runs left to right and carries a current in the direction shown.

A horizontal line representing a wire. There is a vector right labeled I. There is a point labeled Z below the line.
What is the direction of the magnetic field at point Z?

Answer:

0.635 Ω

Explanation:

Using

E-E' = IR.................... Equation 1

Where E = total Emf of the of the batteries, E' = back emf of the motor, I = current of the motor, R = combined resistance of the battery and the motor.

Make R the subject of the equation

R = E-E'/I.............. Equation 2

Given: E = 6.3 V, E' = 2.1 V, I = 3.1 A.

Substitute into equation 2

R = (6.3-2.1)/3.1

R = 4.2/3.1

R = 1.355 Ω

Since the motor and the batteries are connected in series,

R = R'+r'....................... Equation 3

Where R' = Resistance of the motor, r' = resistance of the batteries.

make R' the subject of the equation

R' = R-r'...................... Equation 4

Given: R = 1.355 Ω, r' = 0.18×4 (four batteries) = 0.72 Ω

Substitute into equation 4

R' = 1.355-0.72

R' = 0.635 Ω

Hence the resistance of the motor = 0.635 Ω

To find the motor's resistance, subtract the back emf from the total emf to get the effective voltage, then divide by the current and subtract the total internal resistance of the batteries. The resistance of the motor is found to be 1.35 Ω.

The question involves a toy car motor that is powered by four batteries producing a total electromotive force (emf) of 6.3 V, with each battery having an internal resistance of 0.18 Ω. Upon running, the motor develops a 2.1 V back emf and draws a current of 3.1 A. To find the resistance of the motor, one can use the net emf equation and Ohm's law.

The total emf minus the back emf is the effective voltage across the motor. Thus, the effective voltage (Veff) is 6.3 V - 2.1 V = 4.2 V. The total internal resistance (Rint) in series is 4 batteries × 0.18 Ω = 0.72 Ω. Applying Ohm's law, V = IR where I is the current and R is the resistance, we solve for the resistance (Rmotor) of the motor:

Veff = I(Rmotor + Rint)
Rmotor = Veff/I - Rint
Rmotor = 4.2 V / 3.1 A - 0.72 Ω
Rmotor = 1.35 Ω

Therefore, the resistance of the motor is 1.35 Ω.

Answer:

636.619772368 A

Explanation:

[tex]\tau[/tex] = Torque = [tex]1\times 10^{-3}\ N/m[/tex]

B = Magnetic field of Earth = [tex]5\times 10^{-5}\ T[/tex]

A = Area

d = Diameter = 20 cm

Current is given by

[tex]I=\dfrac{\tau}{BA}\\\Rightarrow I=\dfrac{1\times 10^{-3}}{5\times 10^{-5}\times \dfrac{\pi}{4}\times 0.2^2}\\\Rightarrow I=636.619772368\ A[/tex]

The current is 636.619772368 A

Answer:

there pieces of leftover comets :)

Explanation:

Final answer:

A car with tires of radius 0.280 m decelerating at 7.00 m/s² has an angular acceleration of 25 rad/s². To find the number of revolutions before stopping, kinematic equations for rotational motion are used with an initial angular velocity of 95.0 rad/s.

Explanation:

A car decelerating at 7.00 m/s² with tires of radius 0.280 m requires an understanding of the relationship between linear acceleration and angular acceleration. The formula linking these two is α = a/r, where α is the angular acceleration, a is the linear acceleration, and r is the radius of the tire. Using these values, the angular acceleration is calculated to be 25 rad/s².

For part (b), to find out how many revolutions the tires make before coming to rest, we need to use kinematic equations for rotational motion. Initially, we have an angular velocity (ω) of 95.0 rad/s and we want to find the total angle (θ) covered by the tires. Using the equation θ = (ω0²)/(2*α), we calculate the angle in radians and then convert this to revolutions by dividing by 2π. After finding the revolutions, the car's tires will have stopped rotating completely.

The voltage drop across each wire in the extension cord with a resistance of 0.04 ohms and a current of 15 A flowing through it is calculated using Ohm's Law (V = I x R) to be 0.6 volts.

To calculate the voltage drop across each wire in the extension cord, we can apply Ohm's Law, which states that voltage (V) is the product of current (I) and resistance (R). Given that each wire has a resistance of 0.04 Ω and a current of 15 A is flowing through it, we can calculate the voltage drop by multiplying these two figures:

V = I × R

V = 15 A × 0.04 Ω = 0.6 V

Therefore, the voltage drop across each wire in the extension cord is 0.6 volts.

The amplitude of the induced emf can be calculated by first finding the magnetic field within the solenoid using the formula B = µonI, calculating the magnetic flux through the coil, and then applying Faraday's law to find the time derivative of the flux. This result is then multiplied by the number of turns in the coil.

The amplitude of the electromagnetic force (emf) induced in a coil located inside a solenoid can be calculated using Faraday's law. The first step in solving this problem involves obtaining the magnetic field B of the solenoid by using the formula B = µonI, where µo is the vacuum permeability, n represents the number of turns per unit length of the solenoid, and I is the amplitude of the current. Here, n can be obtained by converting the given number of turns per cm into turns per meter. This magnetic field B is then multiplied by the area of the coil to obtain the magnetic flux Φ through the coil.

Next, using Faraday's law, we take the time derivative of the obtained magnetic flux. Since the only variable in time here is the current I, we apply the derivative to it, with the rest of the quantities being treated as constant. Lastly, we multiply the result by the number of turns in the coil to determine the induced emf. Remember that the magnitude of the emf is the peak or 'amplitude' of the sinusoidal function associated with the time-varying current I.

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Answer:

2.3 m/s

Explanation:

A fisherman notices that one wave passes the bow of his anchored boat every 3 seconds. The speed of the wave traveling is 2.83 m/s. The correct option is 1.

Velocity is a vector expression of an object's or particle's displacement with respect to time. The meter per second (m/s) is the standard unit of velocity magnitude (also known as speed). The meter per second (m/s) is a unit of velocity magnitude (also known as speed).

Speed is the rate at which an object moves along a path in time, whereas velocity is the rate and direction of movement. In other words, velocity is a vector, whereas speed is a scalar value.

Frequency = 1/time

Time = 3 seconds

λ = 8.5 meters.

Putting the value in the formula:

v = f x λ

v = 1/3 x 8.5 = 2.83 m/s

Therefore, the speed of the wave traveling is 2.83 m/s. The correct option is 1.

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The question is incomplete. Your most probably complete question is given below:

1.)2.83m/s

2.)0.283m/s

3.)28.3m/s

Answer:

they are both equal

Explanation:

check the laws of reflection

Answer:

A. The one with the circular cross section will stretch more.

Explanation:

According to the given data:

Two rods are made of brass and have the same length

Both rods having circular and square cross-section

Diameter of circular cross-section given is 2 a

therefore, Cross-section = [tex]A_c=\frac{\pi (2a)^2}{4}=\pi a^2[/tex]

If the length of square=2 a

then, Cross-section = [tex]A_{s}[/tex] = (2a)²=>4a²

Change in Length of rod = PL / AE

δL[tex]\alpha \frac{1}{A}[/tex]

Now, we are considering other factors same

the area of cross-section of square rod is more than Area of cross-section of circular rod

thus, the one with the circular cross section will stretch more

Answer:

The correct option is;

A. The one with the circular cross section will stretch more.

Explanation:

Here we have the cross section as being

1. Circular, with diameter, D = 2·a

2. Square cross section with each side  length = 2·a

The area of the circular rod is then

Area of circle = π·D²/4 which is equal to

π×(2·a)²/4 = π·4·a²/4 = π·a²

The area of the rod with square cross section is

Area of square = Side² which gives

Area of cross section = (2·a)² = 4·a²

Therefore, since π = 3.142, the cross sectional area of the circular rod is less than that of the one with a square cross section

That is,  π·a² = 3.142·a² < 4·a²

We note that the elongation or extension is directly proportional to the force applied as shown as follows

[tex]\frac{P}{A} = E\frac{\delta}{L}[/tex]

Where:

P/A = Force and

δ = Extension

The force is inversely proportional to the area, therefore a rod with less cross sectional area experiences more force and more elongation.

Answer:

Part(a): The expression for the velocity of the billiard ball is [tex]\bf{v_{2f} = \dfrac{2m_{1}v}{m_{1}+m_{2}}}[/tex]

Part(b): The value of the velocity of the billiard ball is [tex]\bf{5.57~m/s}[/tex].

Part(c): The expression for the velocity of the cue ball is [tex]\bf{v_{1f} = \dfrac{(m_{1} - m_{2})v}{m_{1}+m_{2}}}[/tex]

Part(d): The value of the velocity of the cue ball is [tex]\bf{1.93~m/s}[/tex].

Explanation:

Given:

The mass of the cue ball, [tex]m_{1} = 0.34~kg[/tex].

The mass of the billiard ball, [tex]m_{2} = 0.575~kg[/tex].

The initial velocity of the cue ball, [tex]u_{1} = 7.5~m/s[/tex]

The initial velocity of the billiard ball, [tex]u_{2} = 0[/tex]

(a)

Consider the final velocity of the cue ball be [tex]v_{1}[/tex] and the final velocity of the billiard ball be [tex]v_{2}[/tex].

From the conservation of linear momentum , we can write

[tex]~~~~&& m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}\\&or,& m_{1}(u_{1} - v_{1}) = m_{2}(v_{2} - u_{2})~~~~~~~~~~~~~~~~~~~~~~(1)[/tex]

From the conservation of energy, we can write

[tex]~~~&& \dfrac{1}{2}m_{1}u_{1}^{2} + \dfrac{1}{2}m_{2}u_{2}^{2} = \dfrac{1}{2}m_{1}v_{1}^{2} + \dfrac{1}{2}m_{2}v_{2}^{2}\\&or,& \dfrac{1}{2}m_{1}(u_{1}^{2} - v_{1}^{2}) = \dfrac{1}{2}m_{2}(v_{2}^{2} - u_{2}^{2})~~~~~~~~~~~~~~~~~~~~~~~(2)[/tex]

Dividing equation (1) by equation (2), we have

[tex]~~~&& \dfrac{m_{1}(u_{1} - v_{1}) }{m_{1}(u_{1}^{2} - v_{1}^{2})} = \dfrac{m_{2}(v_{2} - u_{2})}{m_{2}(v_{2}^{2} - u_{2}^{2})}\\&or,& u_{1} + v_{1} = u_{2} + v_{2}~~~~~~~~~~~~~~~~~~~~~~~~(3)[/tex]

Rearranging equation (3) for [tex]v_{1}[/tex], we have

[tex]v_{1} = u_{2} + v_{2} - u_{1}~~~~~~~~~~~~~~~~~~~~(4)[/tex]

Substitute equation (4) in equation (1), we can write

[tex]v_{2} = \dfrac{2m_{1}u_{1}}{m_{1}+m_{2}} + \dfrac{m_{2} - m_{1}}{m_{1} + m_{2}}u_{2}~~~~~~~~~~~~~~(5)[/tex]

Substituting [tex]0[/tex] for [tex]u_{2}[/tex], [tex]v[/tex] for [tex]u_{1}[/tex] and [tex]v_{2f}[/tex] for [tex]v_{2}[/tex] in equation (5), we have

[tex]v_{2f} = \dfrac{2m_{1}v}{m_{1}+m_{2}}~~~~~~~~~~~~~~~~~~~~~~~~(6)[/tex]

(b)

Substituting [tex]0.34~kg[/tex] for [tex]m_{1}[/tex], [tex]7.5~m/s[/tex] for [tex]v[/tex] and [tex]0.575~kg[/tex] for [tex]m_{2}[/tex] in equation (6), we have

[tex]v_{2f} &=& \dfrac{2(0.34~kg)(7.5~m/s)}{(0.34 + 0.575)~kg}\\~~~~~&=& 5.57~m/s[/tex]

(c)

Rearranging equation(3) for [tex]v_{2}[/tex], we have

[tex]v_{2} = u_{1} + v_{1} – u_{2}~~~~~~~~~~~~~~~~~~~~(7)[/tex]

Substitute equation (7) in equation (1), we can write

[tex]v_{1} = \dfrac{2m_{2}u_{2}}{m_{1}+m_{2}} + \dfrac{m_{1} - m_{2}}{m_{1} + m_{2}}u_{2}~~~~~~~~~~~~~~(8)[/tex]

Substituting [tex]0[/tex] for [tex]u_{2}[/tex], [tex]v[/tex] for [tex]u_{1}[/tex] and [tex]v_{1f}[/tex] for [tex]v_{1}[/tex] in equation (8), we have

[tex]v_{1f} = \dfrac{(m_{1} - m_{2})v}{m_{1}+m_{2}}~~~~~~~~~~~~~~~~~~~~~~~~(9)[/tex]

(d)

Substituting [tex]0.34~kg[/tex] for [tex]m_{1}[/tex], [tex]7.5~m/s[/tex] for [tex]v[/tex] and [tex]0.575~kg[/tex] for [tex]m_{2}[/tex] in equation (9), we have

[tex]v_{1f} &=& \dfrac{(0.34 - 0.575)~kg(7.5~m/s)}{(0.34 + 0.575)~kg}\\~~~~~&=& -1.93~m/s[/tex]

Negative sign indicates that the cue ball will bounce back.

The expressions for the horizontal component of the billiard ball's velocity after the collision and the cue ball's velocity after the collision are given. The velocities can be calculated using the provided equations and given values.

a) The expression for the horizontal component of the billiard ball's velocity, vr after the collision is given by:

vr = (m1 - m2) * (v1 / (m1 + m2))

b) Substituting the given values into the equation, we find that the horizontal component of the billiard ball's velocity after the collision is approximately 4.02 m/s.

c) The expression for the horizontal component of the cue ball's velocity, vr after the collision is given by:

vr = (2 * m2 * v1) / (m1 + m2)

d) Substituting the given values into the equation, we find that the horizontal component of the cue ball's final velocity is approximately 2.48 m/s.

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Answer:

[tex]2\Omega[/tex]

Explanation:

(Assuming the cell in the circuit has 0 internal resistance)

Ohm's Law is given as:

[tex]V=IR[/tex]

Voltage is Current multiplied by Resistance.

We can rearrange this formula to give us:

[tex]R=\frac{V}{I}[/tex]

Now we can plug in our values

[tex]R=\frac{6}{3}=2\Omega[/tex]

I= 3A

V= 6V

R=?

V=IR

R=V/I

R=6/3

Therefore R = 2ohms

Hope this will help u mate :)

Answer:

1) not so long (maybe an hour or two)

2) access to information through the internet will be most affected if my computer and mobile phone run out of battery power.

3) yes, one should prepare for power outage. This can be done by having a standby alternative source of power like the use of inverters that stores electrical energy in form of chemical energy, and small internal combustion engine powered electric generators.

4) solar panels can be used to draw power from incident sun rays, this power can be stored in an inverter for future use in case of a power outage.

5) energy from the sun is converted into direct current which is then supplied to an accumulator in the opposite direction to its flow of current. When the energy is needed, it can be used directly, or converted to an alternating current. This is achieved by connecting its terminal to the supply. Electric field is generated by flow of ions and electrons within the working chemical (e.g lithium).

Explanation:

Answer:

If there was a power outage, you could survive normally using older ways of life and with proper preparations; some ways to prepare is having canned foods that don't require heating or refrigeration, since you wouldn't have electronic means of preparing it, and supplies for starting camp fires. Some ways your life would be affected is lack of simple methods of day-to-day tasks that you have become accustomed to: no warm water, to refrigerators, or heating systems such as electronic kettles, microwaves or ovens. A backup system you and/or your family/community could install would be solar panels, to collect power during the day to then be used at night or when needed. Solar panels collect solar energy by catching the sun-rays in the cells of the panels and turning the energy into a direct current (DC), then the panels convert the direct current into usable alternating current (AC) energy with the help of inverter technology. That current is then distributed throughout the building accordingly.

Answer:

Explanation:

Angular momentum is the product of inertial and angular frequency

L = I × ω

Where

L is angular momentum

I is inertia

ω is angular frequency

So, given that

Vinyl record has a massz

M = 0.115kg

Radius R = 0.0896m

Angular velocity of vinyl record

ω(initial) = 5.58 rad/s

Rotational inertial of vinyl record.

I(initial) = 4.84 × 10^-4 kgm²

Putty drop on the record

Mass of putty M' = 0.0484kg

Angular speed after putty drop ω'

Using conversation of angular momentum

Initial angular momentum is equal to final angular momentum

I(initial) × ω(initial) = I(final) × ω(final)

So, we need to find I(final)

Inertia log putty can be determine using MR² by assuming a thin loop

I(putty) = M'R² = 0.0484 × 0.0896

I(putty) = 3.89 × 10^-4 kgm²

I(final) = I(initail) + I(putty)

I(final) = 4.84 × 10^-4 + 3.89 × 10^-4

I(final) = 8.73 × 10^-4 kgm²

Therefore,

I(initial) × ω(initial) = I(final) × ω(final)

ω(final) = I(initial) × ω(initial) / I(final)

ω(final) = 4.84 × 10^-4 × 5.58 / 8.73 × 10^-4

ω(final) = 3.1 rad/s

Answer:

a) final angular speed w2 = 414rpm

b) time to stop t = 312.5s

c) angular distance from start to stop s = s = 1171.88 rev

Explanation:

Average angular speed wa = (w1+w2)/2 = Angular distance/time = s/t

Given;

w1 = 450 rpm = 450/60 rev/s = 7.5 rev/s

s = 180 rev

t = 25s

a)

s/t = (w1+w2)/2

w2 = 2s/t - w1

Substituting the values;

w2 = 2×180/25 - 7.5 = 6.9 rev/s

w2 = 6.9×60rpm = 414rpm

b)

Angular deceleration a = (w1-w2)/t = (7.5-6.9)/25

a = 0.024 rev/s^2

time t for w2 = 0

t = (w1-w2)/a = (7.5-0)/0.024

t = 312.5 s

c)

Angular distance from start to stop s;

s = w1t - 0.5at^2

s = 7.5×312.5s - 0.5×0.024×312.5^2

s = 1171.88 rev

Answer:

La energía es una cualidad o capacidad que tienen los cuerpos materiales y posee diversas funciones. Hay distintos tipos de energía, pero ésta permite que un cuerpo se mueva por ejemplo, cambie de temperatura o de estado.

Explanation:

La Energía de los cuerpos puede ser definida de distintas maneras según la ciencia en la cual estemos trabajando. Para la física, la energía es la capacidad para realizar un trabajo. Esa energía puede ser cinética, térmica, química, y cada una de ellas define distintas propiedades de los cuerpos, que hacen que puedan cambiar de posición, temperatura, estado.

Final answer:

The primary difference between gravitational and electric forces is that electric forces can be both attractive and repulsive, whereas gravitational forces are always attractive. Electric forces dominate on small scales, such as within atoms, while gravitational forces are significant on large scales, like between planets.

Explanation:

Main Differences Between Gravitational and Electric Forces:

A main difference between gravitational and electric forces is that electric forces can be either attractive or repulsive, while gravitational forces are always attractive. Gravitational force is proportional to the masses of the interacting objects and always pulls them together, which is important in interactions between large objects like planets and stars. Conversely, electric force is proportional to the charges of interacting objects and plays a crucial role at the microscopic level within atoms and molecules, often keeping them together. It is much stronger than gravity in most systems where both appear.

Another significant difference is that on a small scale, like that of electrons or protons, the electric force is dominant and significantly exceeds the gravitational force. In contrast, on a large scale, gravitational force typically predominates since most objects tend to be electrically neutral; thus, the net Coulomb forces cancel out.

To summarize, gravitational forces are crucial at cosmological scales, handling the structure of galaxies and the dynamics of celestial bodies, whereas electric forces are on a much smaller scale but are instrumental in the binding of atoms, the functioning of everyday materials, and biological processes.

Answer:

a) [tex]f=0.64 Hz[/tex]

b) [tex]\lambda=62.5 cm[/tex]

c) [tex]y_{m}=5 cm[/tex]

d) [tex]k=0.1 cm^{-1}[/tex]

e) [tex]\omega=4 s^{-1}[/tex]

g) [tex]T=0.064 N[/tex]    

Explanation:

We know that the wave equation is of the form:

[tex]y(x,t) = y_{m}sin(kx \pm \omega t)[/tex]

Comparing with the equation of the sinusoidal wave [tex](y=(5.0cm)sin[1.0−(4.0s^{-1})t])[/tex] we will have:

[tex]\omega = 4 s^{-1}[/tex]

a) ω is the angular frequency and it can writes in terms of frequency as:

[tex]\omega = 2\pi f[/tex] , where f is the frequency.

[tex]f=\frac{\omega}{2\pi}[/tex]

[tex]f=0.64 Hz[/tex]

b) Let's recall that the speed of the wave is the product between the wave length and the frequency, so we have:

[tex]v=\lambda f[/tex]

[tex]\lambda=\frac{v}{f}[/tex]

v is 40 cm/s

[tex]\lambda=\frac{40}{0.64}[/tex]

[tex]\lambda=62.5 cm[/tex]

If we compare each equation we can find y(m), k and ω:

c) [tex]y_{m}=5 cm[/tex]

d) [tex]kx=1[/tex] and we know that x = 10 cm, so:

[tex]k=\frac{1}{x}=\frac{1}{10}[/tex]

[tex]k=0.1 cm^{-1}[/tex]

e) [tex]\omega=4 s^{-1}[/tex]

f) The minus sign in front of the angular frequency in the equation is the correct choice, just by comparing.

g) We have to use the equation of the speed in terms of tension.

[tex]v=\sqrt{\frac{T}{\mu}}[/tex]

[tex]T=\mu*v^{2}[/tex]

[tex]T=4*40^{2}=6400 g*cm*s^{-2}[/tex]    

[tex]T=0.064 N[/tex]    

I hope it helps you!

(a) The frequency of the wave is 6.37 Hz and (b) the wavelength is 2π cm. (c) The values for y_m, k, and ω are 5.0 cm, (d) 1 cm^-1, and (e) 4.0 s^-1 respectively. (f) The correct choice of sign in front of ω is positive. (g) The tension in the string is 12533.5 g*cm²/s².

(a) To find the frequency of the wave, we can use the formula f = v/λ, where f is the frequency, v is the velocity, and λ is the wavelength. In this case, v = 40 cm/s and we need to find λ. Since y(x,t) = y_m sin(kx ± ωt), we can compare it to the given equation y=(5.0cm)sin[1.0−(4.0s−1)t] to find k and ω. From the comparison, we know k = 1 cm^-1 and ω = 4.0 s^-1. Therefore, the wavelength is given by λ = 2π/k, and plugging in the values, we get λ = 2π cm. The frequency can then be calculated as f = v/λ = 40 cm/s / 2π cm = 6.37 Hz.

(b) the wavelength is 2π cm.

(c) y_m is the amplitude of the wave, which is 5.0 cm.

(d) k is the wave number, which is 1 cm^-1.

(e) ω is the angular frequency, which is 4.0 s^-1.

(f) The correct choice of sign in front of ω depends on the direction of wave propagation. If the wave is traveling in the positive x-direction, the sign should be positive, so ωt is correct.

(g) To find the tension in the string, we can use the formula T = λ²μf², where T is the tension, λ is the wavelength, μ is the linear density, and f is the frequency. Plugging in the values, we get T = (2π cm)² * (4.0 g/cm) * (6.37 Hz)² = 12533.5 g*cm²/s².

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Answer:

No, since they don't have the necessary mass and a high temperature in their core.

Explanation:

There are two forces that play an important role in the stars: the force of gravity in the inward direction due to stars' own mass and the radiation pressure in the upward direction as a consequence of the nuclear reaction in their core.

The superficial layers of the stars compress the core as an effect of their own gravity. Therefore, atoms will be closer to each other in the core, allowing them to combine, increasing the density and temperature.  

A nuclear reaction occurs when light elements combine into heavier elements (that is known as nucleosynthesis). To get fusion reactions that generate heavier elements than carbon high temperature is necessary, which can be gotten by a more massive star for what was already explained in the first paragraph.

Answer:

Technician B is correct

Explanation:

Electrical Switches makes or brakes the flow of signal (current or voltage) in a circuit.

The Technician B that says the switch contacts are closed is correct because it is until when the circuit is continues that voltage flows across the switch and voltmeter will read the amount of voltage present in the circuit. This simply means closed circuit.

Technician A is not correct because when the switch contacts are open, voltage does not flow and no reading will be measured.

Answer:

Technician B is correct

Explanation:

When a circuit is open there is no energy that allows the flux of charge in the cable. Voltage determines the capability of doing a work over charges to generate a charge flux. An open circuit is not able to generate a current in the circuit and concequently, ther is no voltage in the circuit.

Hence, a measurement of 12V in a circuit means that the circuit is closed, store energy and can generate a flux of charge.

Technician B is correct.

Answer:

15 miles

Explanation:

6 miles per hour

2 1/2 hours

6 x 2 = 12

6 x 1/2 = 3

12 + 3 = 15

Answer:

1.contact force

2. Non contact

Explanation:

1. Because bodies are in contact

2.Bodies are not in contact.

Answer:

1. contact

2. non contact

Explanation:

just did it

Answer:

Decrease

Explanation:

If you crawl to the rim the rotational speed will decrease. The law of conservation of angular momentum supports this answer. And it states that :

"When the net external torque acting on a system about a given axis is. zero , the total angular momentum of the system about that axis remains constant."

Final answer:

When moving toward the edge of a spinning turntable, the rate of rotation decreases due to the principle of conservation of angular momentum, which necessitates a decrease in angular velocity to compensate for an increased moment of inertia.

Explanation:

When you crawl toward the edge of a large turntable at an amusement park while it is spinning, the rate of the rotation decreases. This phenomenon is explained by the principle of conservation of angular momentum, which states that if no external torque acts on a system, the total angular momentum of the system remains constant.

Angular momentum is given by the product of the moment of inertia (I) and the angular velocity (ω), represented by the equation L = Iω. As you move away from the axis of rotation, your moment of inertia increases because the moment of inertia is directly proportional to the square of the distance from the axis of rotation. In order to conserve angular momentum, if the moment of inertia increases, the angular velocity must decrease accordingly.

Answer:

[tex]v_0=17.3m/s[/tex]

Explanation:

In this problem we have three important moments; the instant in which the ball is released (1), the instant in which the ball starts to fly freely (2) and the instant in which has its maximum height (3). From the conservation of mechanical energy, the total energy in each moment has to be the same. In (1), it is only elastic potential energy; in (2) and (3) are both gravitational potential energy and kinetic energy. Writing this and substituting by known values, we obtain:

[tex]E_1=E_2=E_3\\\\U_e_1=U_g_2+K_2=U_g_3+K_3\\\\\frac{1}{2}kd^2=mg(d\sin\theta)+\frac{1}{2}mv_0^2=mgh+\frac{1}{2}m(v_0\cos\theta)^2[/tex]

Since we only care about the velocity [tex]v_0[/tex], we can keep only the second and third parts of the equation and solve:

[tex]mgd\sin\theta+\frac{1}{2}mv_0^2=mgh+\frac{1}{2}mv_0^2\cos^2\theta\\\\\frac{1}{2}mv_0^2(1-\cos^2\theta)=mg(h-d\sin\theta)\\\\v_0=\sqrt{\frac{2g(h-d\sin\theta)}{1-\cos^2\theta}}\\\\v_0=\sqrt{\frac{2(9.8m/s^2)(4.4m-(0.21m)\sin32\°)}{1-\cos^232\°}}\\\\v_0=17.3m/s[/tex]

So, the speed of the ball just after the launch is 17.3m/s.

Answer:

1 -f,2 -b,3-e,4 -g,5-a,6 - d, 7 - h, 8 - c

Explanation:

1.  developed geocentric theory  - Aristotle

2. developed heliocentric theory - Copernicus in 1543

3. founded nursing profession   -  Florence Nightingale

4. invented barometer  -   Evangelista Torricelli in 1643

5. "Father of Modern Science" -  Galileo Galilei

6.law of universal gravitation -Sir Isaac Newton

7. examined the inner workings of the human body - Vesalius

8. developed metric temperature scale  -  Andres Celsius in 1742

Answer:

The radio booth is 0.993 meters above the field.

Explanation:

The pendulum covers 10 complete oscillations to take 20 s. We need to find the height above the radio booth. The time period of the pendulum is given by :

[tex]T=2\pi \sqrt{\dfrac{L}{g}} \\\\L=(\dfrac{T}{2\pi })^2g\\\\L=(\dfrac{(20/10)}{2\pi })^2\times 9.8\\\\L=0.993\ m[/tex]

So, the radio booth is 0.993 meters above the field.

The height of the radio booth is calculated to be approximately 9.9 cm by using the given oscillation period of 0.02 s and applying the pendulum formula.

A pendulum's period (T) is given by the formula:

T = 2π√(L/g)

Where:

Given that 1010 complete oscillations take 20.2 seconds, we can find the period:

Now, using the period formula, we rearrange to solve for L:

Square both sides to get:

Then solve for L:

Plugging in the values:

So, the height from which the microphone is hanging is approximately 9.9 cm.

Answer:

Explanation:

Given that,

Assume number of turn is

N= 1

Radius of coil is.

r = 5cm = 0.05m

Then, Area of the surface is given as

A = πr² = π × 0.05²

A = 7.85 × 10^-3 m²

Resistance of

R = 0.20 Ω

The magnetic field is a function of time

B = 0.50exp(-20t) T

Magnitude of induce current at

t = 2s

We need to find the induced emf

This induced voltage, ε can be quantified by:

ε = −NdΦ/dt

Φ = BAcosθ, but θ = 90°, they are perpendicular

So, Φ = BA

ε = −NdΦ/dt = −N d(BA) / dt

A is a constant

ε = −NA dB/dt

Then, B = 0.50exp(-20t)

So, dB/dt = 0.5 × -20 exp(-20t)

dB/dt = -10exp(-20t)

So,

ε = −NA dB/dt

ε = −NA × -10exp(-20t)

ε = 10 × NA exp(-20t)

Now from ohms law, ε = iR

So, I = ε / R

I = 10 × NA exp(-20t) / R

Substituting the values given

I = 10×1× 7.85 ×10^-3×exp(-20×2)/0.2

I = 1.67 × 10^-18 A

Answer: the nasal conchae also known as the turbinates

Explanation:

Explanation:

Given

Force (F) = 500 N

Distance (d) = 2m

Now

Work done = F * d

= 500 * 2

= 1000 joule

Therefore 1000 joule of work is done.

Hope this helps.

The work done by a football player leaping 2 m into the air with a force of 500 N is calculated using the equation W = F * d, resulting in 1000 joules of work.

When calculating work done on an object, it's essential to understand that work (W) is defined as the product of the force (F) applied to an object and the distance (d) that the object moves in the direction of the force. The equation for work is:

W = F * d,

where work (W) is measured in joules (J), force (F) in newtons (N), and distance (d) in meters (m).

For a football player leaping vertically into the air with a force of 500 N over a distance of 2 m:

W = (500 N) * (2 m),

W = 1000 J.

The work done by the football player in leaping 2 meters into the air is therefore 1000 joules.

Answer:

The magnetic field is [tex]2 \times 10^{-4}[/tex] T

Explanation:

Given:

Velocity of electron [tex]v = 5 \times 10^{7} \frac{m}{s}[/tex]

Electric field [tex]E = 10^{4} \frac{V}{m}[/tex]

The force on electron in magnetic field is given by,

 [tex]F = qvB \sin \theta[/tex]                      ......(1)

The force on electron in electric field is given by,

 [tex]F = qE[/tex]                               ......(2)

Compare both equation,

   [tex]qE = qvB \sin \theta[/tex]

Here [tex]\sin \theta = 1[/tex]

  [tex]E = vB[/tex]

  [tex]B= \frac{E}{v}[/tex]

  [tex]B = \frac{10^{4} }{5 \times 10^{7} }[/tex]

  [tex]B = 2 \times 10^{-4}[/tex] T

Therefore, the magnetic field is [tex]2 \times 10^{-4}[/tex] T

Final answer:

The shortest time it takes for the child to catch up with the horse can be found by analyzing the angular motion of the merry-go-round and the child. Using the given values of angular speed and angular acceleration, we can set up an equation and solve for time using the quadratic formula.

Explanation:

To find the shortest time it takes for the child to catch up with the horse, we need to analyze the angular motion of the merry-go-round and the child.

Given that the child's angular speed is 0.233 rad/s and the merry-go-round starts rotating with an angular acceleration of 0.0136 rad/s^2, we can use the equation:
Δθ = ω_0 * t + (1/2) * α * t^2
where Δθ is the angle the child needs to catch up with the horse (π/2 radians in this case), ω_0 is the initial angular speed of the merry-go-round, α is the angular acceleration, and t is the time.

Plugging in the values, we have:
π/2 = 0.233 * t + (1/2) * 0.0136 * t^2

This equation is quadratic in form, so we can solve it using the quadratic formula. The positive root will give us the time it takes for the child to catch up with the horse.