A woman is looking for a bigger square office. She finds an office twice the area of her current office. if the perimeter of her current office is 88feet, how many square feet is the new office?

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Answer:

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Tony's gross pay for 46 hours of work, including 6 hours of overtime, is $563.50. The Social Security tax on this amount is $34.94, and the Medicare tax is $8.17.

Calculating Tony's Gross Pay

Tony's regular pay for 40 hours at an hourly rate of $11.50 is calculated by multiplying the hourly rate by the number of regular hours he worked. Therefore, his regular pay is 40 hours × $11.50/hour = $460. To calculate the overtime pay, we must first determine the overtime rate. The overtime rate is 1.5 times the normal hourly rate, thus the overtime hourly rate is 1.5 × $11.50/hour = $17.25/hour. Tony worked 6 hours overtime, so his overtime pay is 6 hours × $17.25/hour = $103.50. Tony's gross pay is the sum of his regular pay and overtime pay, which is $460 + $103.50 = $563.50.

Calculating Deductions for Social Security and Medicare

The Social Security tax and Medicare tax are calculated as percentages of the gross pay. The Social Security tax at 6.2% of $563.50 is $563.50 × 0.062 = $34.937, which rounds to $34.94. The Medicare tax at 1.45% of $563.50 is $563.50 × 0.0145 = $8.17075, which rounds to $8.17.

Answer:

C.

Step-by-step explanation:

The 12 inches wire costs 60 cents, so the cost of 1 inch of wire is

Rate = 60/12 = 5 cents

So the cost of 1 inch of wire which is the rate is 5 cents.

Now we have to find the cost (in cents) of 27 inches wire.

We know the cost of 1 inch of wire is 5 cents so the cost of 27 inches of wire is

= Total inches of wire * Price of 1 inch of wire

= 27 * 5

= 135

The cost of 27 inches of wire is 135 cents

The ratio of tulips to daffodils in Robert's garden is 3:2. This is obtained by dividing the number of tulips by the number of daffodils (36/24), and simplifying the result.

This problem pertains to ratios. Given that Robert planted 24 daffodil bulbs and 36 tulip bulbs, the ratio of tulips to daffodils is obtained by dividing the number of tulips by the number of daffodils. Thus, the ratio is 36/24. This simplifies to 1.5 when expressed as a decimal. However, we need the ratio in its simplest form, so let's convert 1.5 into a whole number. By multiplying both numbers by 2, we get the ratio 3:2. Therefore, the ratio of tulips to daffodils in Robert's garden is 3:2

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Final answer:

By establishing a relationship between the total number of aquatic plants and animals and knowing that animals are 80% of the plants, we can determine that there are 72 aquatic animals in the eco-garden.

Explanation:

To calculate the number of aquatic animals in the eco-garden, we need to first establish the relationship between the number of animals and plants. According to the information, the number of aquatic animals is 80% of the number of aquatic plants. If we denote the number of aquatic plants as 'P' and aquatic animals as 'A', then A = 0.80 × P.

Given that there are a total of 162 aquatic plants and animals, we can represent this as A + P = 162. Since A is 80% of P, we can substitute the first relationship into the second equation, which gives us 0.80 × P + P = 162. Simplifying this, we get 1.80 × P = 162.

To find the value of P, we divide both sides by 1.80 to get P = 162 / 1.80, which yields P = 90. This indicates there are 90 aquatic plants. To determine the number of aquatic animals, we use the relationship A = 0.80 × P, so A = 0.80 × 90, resulting in A = 72.

Therefore, there are 72 aquatic animals in the eco-garden.

Answer:

(y - 8x) (y + 7x)

Step-by-step explanation:

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Have a blessed day!

A multiplication problem shows the process of calculating the product when one number is multiplied by another. This can be represented using an array model, an area model, or a multiplication sentence. Specific representation will depend on the model provided.

In mathematics, a multiplication problem represents the process of finding the product or result when one number is multiplied by another.

However, without a specific model being given in the question, providing a precise answer becomes challenging. In general terms, a multiplication model could be in the form of an array, an area model, or a multiplication sentence. To understand this better, let's illustrate with an example.

In all the cases, the multiplication problem is demonstrating how to find the product of two numbers or quantities.

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Answer:

Perimeter = 182 cm, area = 2,028 cm^2

Step-by-step explanation:

The absolute maximum and minimum values of the function f(x) = ln(x^2 + 5x + 12) on the interval [-3, 1] are f(1) = ln(18) (maximum) and f(-2) = ln(4) (minimum).

To find the absolute maximum and absolute minimum values of the function f(x) = ln(x2 + 5x + 12) on the interval [-3, 1], we first need to find the critical points of the function within this range. The critical points are those at which the derivative equals zero or does not exist.

The absolute maximum value within the interval is ln(18) and the absolute minimum value is ln(4).

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The absolute maximum value of f(X)  on the interval [-3, 1] is approximately ( 2.890), which occurs at ( x = 1), and the absolute minimum value is approximately (1.749 ), which occurs at ( x = -5/2).

To find the absolute maximum and minimum values of[tex]\( f(x) = \ln(x^2 + 5x + 12) \)[/tex] on the interval [tex]\([-3, 1]\)[/tex], we first need to find the critical points and check the values of the function at those points and at the endpoints of the interval.

1. Find the critical points: Critical points occur where the derivative of the function is zero or undefined.

First, let's find the derivative of (f(x):

[tex]\[ f'(x) = \frac{1}{x^2 + 5x + 12} \cdot (2x + 5) \][/tex]

Setting ( f'(x)) equal to zero:

2x + 5 = 0

x = -5/2

Since this value x = -5/2 lies within the interval [-3, 1], it's a critical point.

2. Check the endpoints and critical point:

[tex]- \( f(-3) = \ln((-3)^2 + 5(-3) + 12) = \ln(9 - 15 + 12) = \ln(6) \)[/tex]

[tex]- \( f(1) = \ln(1^2 + 5(1) + 12) = \ln(1 + 5 + 12) = \ln(18) \)[/tex]

[tex]- \( f\left(-\frac{5}{2}\right) = \ln\left(\left(-\frac{5}{2}\right)^2 + 5\left(-\frac{5}{2}\right) + 12\right) = \ln\left(\frac{25}{4} - \frac{25}{2} + 12\right) = \ln\left(\frac{25 - 50 + 48}{4}\right) = \ln\left(\frac{23}{4}\right) \)[/tex]

3. Compare the values:

  - ln(6) = 1.792

  - ln(18) = 2.890

  - [tex]ln\left(\frac{23}{4}\right)[/tex] = 1.749

So, the absolute maximum value of f(X)  on the interval [-3, 1] is approximately ( 2.890), which occurs at ( x = 1), and the absolute minimum value is approximately (1.749), which occurs at ( x = -5/2).

Frank finished 5/8 of the report.

To find the fraction of the book report that Frank finished, you need to add together the fractions of the report he wrote before and after dinner. Frank wrote 1/2 of the report before dinner and 1/8 of the report after dinner. To add these fractions, you need to find a common denominator. The least common multiple of 2 and 8 is 8, so you can rewrite 1/2 as 4/8. Adding 4/8 and 1/8 gives you a total of 5/8.

Therefore, Frank finished 5/8 of the report.