Answer:
The red ball
Explanation:
The red ball has greater kinetic energy, because it has a greater mass.
A force of 75 N is applied to a spring, causing it to stretch 0.3 m. What is the spring constant of the spring?
0.004 N/m
22.5 N/m
75.3 N/m
250 N/m
Answer:
D 250
Explanation:
EDGE
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Which describes the difference between a bowling ball sitting in the rack waiting to be used and the bowling ball knocking pins down? A. In the rack, the bowling ball has only potential energy. As it knocks pins down, its potential energy has decreased, while its kinetic energy has increased. B. In the rack, the bowling ball has no energy at all. As it knocks down the pins the energy is 75% kinetic and 25% potential. C. In the rack and when knocking down pins, the potential energy and the kinetic energy of the bowling ball are equal. D. In the rack, the bowling ball has only kinetic energy. As it knocks pins down, its potential energy has increased, while its kinetic energy has decreased.
High-voltage power lines are a familiar sight throughout the country. the aluminum (resistivity = 2.82 x 10-8Ï m) wire used for some of these lines has a cross-sectional area of 4.1 x 10-4 m2. what is the resistance of 8.2 kilometers of this wire?
Which has more thermal energy: lake or a cup of hot chocolate?
Answer:
A cup of hot chocolate
Explanation:
A cup of hot chocolate will have more thermal energy has the hot cocoa would have a higher temperature, the lake would have more thermal energy because it has more molecules with a greater total internal energy.Know more :
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True or false A physical change occurs when matter changes state as from a liquid to a gas Becuase
Johnny was playing baseball with his friends and they noticed a bolt of lightning. They heard thunder seven seconds later. How far away is the storm?
To estimate the distance to a lightning strike, divide the number of seconds between seeing lightning and hearing thunder by five. With a 7-second delay, the storm is approximately 1.4 miles away.
The storm that Johnny and his friends experienced is associated with lightning and thunder. Light from lightning travels much faster than sound from thunder. This difference can be used to estimate the distance to a lightning strike. Since light travels at 3 × 108 meters per second, we see the lightning almost immediately. However, sound travels much slower, and for every 5 seconds we count after seeing lightning before hearing thunder, the storm is approximately 1 mile away.
In Johnny's case, they heard thunder 7 seconds after seeing lightning. Using the rule of thumb that every 5 seconds corresponds to about 1 mile, we can estimate the distance to the storm. 7 seconds divided by 5 gives us 1.4, so the storm is about 1.4 miles away from Johnny and his friends. This is a practical application of basic physics and the differences between light and sound velocity.
Calculate the total force on the Earth due to Venus, Jupiter, and Saturn, assuming all four planets are in a line. The masses are Mv=0.815ME, MJ=318ME, Msat=95.1ME, Msun=1.99x10^30kg, ME=5.98x10^24kg and the mean distances of the four planets from the Sun are 108, 150, 778, and 1430 million km. Apparently the answer is 9.56x10^17 N but I'm not sure how to get to that .-.,
Answer: Total Force = [tex]9.56*10^{17}[/tex]
Explanation:
Line points are: Sun - Venus - Earth - Jupiter - Saturn
Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. This means:
[tex]F=G\frac{m_{1} m_{2}}{r^{2} }[/tex]
Where,
G is the gravitational constant,
m1 and m2 are the masses of the objects,
and r is the distance between the centers of their masses.
So, if G value is [tex]6.674*10^{-11} [\frac{m^{3}}{kg*s^{2}}][/tex], then we replace the equation with the corresponding values:
[tex]F=6.674*10^{-11} (-\frac{0.815ME^{2}}{(4.2*10^{10})^{2}} + \frac{318ME^{2}}{(6.28*10^{11})^{2}} + \frac{95.1ME^{2}}{(1.28*10^{12})^{2}})[/tex]
To get the distances we subtract the distances between the sun and earth and the distances between the other planets and the sun.
A positive charge of 6.0 × 10-4 C is in an electric field that exerts a force of 4.5 × 10-4 N on it. What is the strength of the electric field
The magnitude of the electric force exerted on a charge in an electric field is given by
[tex] F=qE [/tex]
where
q is the charge
E is the magnitude of the electric field
In this problem, we have a charge of [tex] q=6.0 \cdot 10^{-4} C [/tex], while the force exerted on it is [tex] F=4.5 \cdot 10^{-4}N [/tex], so we can rearrange the previous formula to calculate the magnitude of the electric field:
[tex] E=\frac{F}{q}=\frac{4.5 \cdot 10^{-4} N}{6.0 \cdot 10^{-4} C}=0.75 N/C [/tex]
Answer:
0.75
Explanation:
What is the frequency of a microwave that has a wavelength of 0.050 m?
Answer:
[tex]6x10^9Hz[/tex]
Explanation:
we use a formula that relates the frequency and the wavelength:
[tex]f=\frac{c}{\lambda}[/tex]
where [tex]f[/tex] is the frequency of the wave, [tex]c[/tex] is the speed of light [tex]c=3x10^8m/s[/tex], and [tex]\lambda[/tex] is the wavelength.
We know that the wavelength is: [tex]\lambda=0.050m[/tex], so substituting the known values in the equation for the frequency we get:
[tex]f=\frac{3x10^8m/s}{0.05m} \\f=6x10^9s^{-1}=6x10^9Hz[/tex]
The frequency is:
[tex]6x10^9Hz[/tex]
Final answer:
The frequency of a microwave with a wavelength of 0.050 m is [tex]6*10^9[/tex] Hz, or 6000 MHz, calculated using the speed of light and the wavelength-to-frequency formula.
Explanation:
To calculate the frequency of a microwave that has a wavelength of 0.050 m, you can use the formula
c = λf, where c is the speed of light in a vacuum (approximately [tex]3*10^8[/tex] m/s), λ is the wavelength, and f is the frequency. Solving for f, the equation becomes
f = c / λ.
Let’s plug in the values:
f = ([tex]3*10^8[/tex] m/s) / (0.050 m)
After calculating, the frequency f is [tex]6*10^9[/tex] Hz, or 6000 MHz.
If a material is a good conductor of electricity, it is a ______
A. Metal
B. Nonmetal
C. Metalloid
Answer:
Metal
Explanation:
If a material is a good conductor of electricity, it is a metal, therefore the correct answer is option A.
What are metalloids?The elements of the periodic tables that behave as metal, as well as the nonmetal in some chemical or physical aspects, are known as metalloids. Some examples of metalloids are Boron, silicon, germanium, arsenic, antimony, tellurium, etc.
Metals are very good conductors of heat and electricity while on the other hand nonmetals are very poor conductors of heat and electricity.
Metalloids are semiconducting materials that behave as the intermediate behavior between metal and nonmetal.
Thus, If a material is a good conductor of electricity, it is a metal, therefore the correct answer is option A.
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A 0.40 kg ball is suspended from a spring with spring constant 12 n/m . part a if the ball is pulled down 0.20 m from the equilibrium position and released, what is its maximum speed while it oscillates?
The maximum speed of the 0.40 kg ball while it oscillates is approximately 1.10 m/s. This is found using the conversion of potential energy into kinetic energy at the equilibrium position. The mechanical energy principles of simple harmonic motion are applied.
To determine the maximum speed of a ball oscillating on a spring, we can use principles from simple harmonic motion. Given:
Mass of the ball, m = 0.40 kgSpring constant, k = 12 N/mDisplacement from equilibrium, x = 0.20 mWe start by calculating the total mechanical energy when the ball is at maximum displacement. The potential energy at maximum displacement is given by:
U = 0.5 * k * x2 = 0.5 * 12 N/m * (0.20 m)2 = 0.24 JSince there is no damping, this total mechanical energy converts entirely into kinetic energy at the equilibrium position where the speed is maximum. The kinetic energy K at this point is:
K = 0.5 * m * [tex]v_{max}^2[/tex] = 0.24 JSolving for [tex]v_{max}[/tex] :
[tex]v_{max}[/tex] = √((2 * K) / m) = √((2 * 0.24 J) / 0.40 kg) = √(1.2) ≈ 1.10 m/sTherefore, the maximum speed of the ball while it oscillates is approximately 1.10 m/s.
With a quarter-turn flick of the wrist, a student sets the frisbee rotating at 570 rpm . what is the magnitude of the torque, assumed constant, that the student applies?
Due to missing information such as the time of the wrist flick or the frisbee's moment of inertia, we cannot calculate the exact torque that the student applied to the frisbee. To find the torque, we would need to determine the angular acceleration based on the provided angular velocity and the additional data.
To answer the question about the magnitude of the torque applied by a student to a frisbee rotating at 570 revolutions per minute (rpm), we need to consider several factors, including the angular velocity, the moment of inertia, and the time during which the torque was applied. However, the problem statement does not provide all the necessary information (like the time duration and the moment of inertia of the frisbee).
Typically, to calculate the torque, you would use the formula: torque (\(\tau\)) = moment of inertia (I) \(\times\) angular acceleration (\(\alpha\)). The angular acceleration could be found if we had the time duration for the quarter-turn and the final angular velocity.
Since these key pieces of data are missing in the student's problem, we cannot calculate the exact torque without additional information. If the time duration of the wrist flick or the moment of inertia of the frisbee were provided, we could find the angular acceleration using \(\alpha = \Delta\omega / \Delta t\), where \(\Delta\omega\) is the change in angular velocity and \(\Delta t\) is the change in time. From there, the torque could be calculated.
The torque applied by the student on the frisbee can be calculated using the formula torque = moment of inertia x angular acceleration. The primary force acting on the student when flicking the frisbee is the force applied perpendicular to the frisbee's radius.
Calculating the torque: To find the torque applied by the student on the frisbee, we can use the formula for torque, which is given by torque = moment of inertia × angular acceleration. First, convert the frisbee's initial angular velocity of 570 rpm to radians per second by multiplying by 2π/60.
Forces acting on the student: The primary force acting on the student when flicking the frisbee is the force applied perpendicular to the frisbee's radius. This force creates a torque and initiates the rotational motion of the frisbee.
Calculate δe, if the system absorbs 7.24 kj of heat from the surroundings while its volume remains constant (assume that only p−v work can be done). express your answer using three significant figures.
Answer:
[tex]\delta Q = \delta E = 7.24 kJ[/tex]
Explanation:
Heat absorbed by the system is given as
[tex]\delta Q = 7.24 kJ[/tex]
now from first law of thermodynamics we know that
[tex]\delta Q = \delta E + W[/tex]
here
W = work done by the system
[tex]\delta E[/tex] = change in internal energy
also we know that when volume of the system remains same then work done by the system must be zero
[tex]W = 0[/tex]
so from above equation
[tex]\delta Q = \delta E = 7.24 kJ[/tex]
The mass of a bucket full of water is 15 Kg. It is being pulled up from a 15m deep well. Due to a hole in bucket 6 Kg of water flows out. Find the work done in pulling it out of the well.,
The work done in pulling a bucket full of water with a weight of 15 kg that lost 6 kg of it from the hole from a well 15 m deep is 1350 Joules
Further Explanation;Work done Work done refers to the measure of energy when a body is moved by a force through a certain distance.Work done is therefore equivalent to energy transferred.Work done is given by the product of force acting on an object and distance moved by the object.Therefore; Work done = Force × distanceForce refer to a pull or a push and is measured in Newtons, N.Distance is measured in meters, m.Thus; Work done is measured in Joules, J, or Nm
In this case;
Mass of the bucket is 15 Kg
However, 6 kg of water flew out due to the whole, therefore the remaining mass is 9 kg.
Force or Weight = Mass (kg) × 10 N/kg
Therefore;
Force = 90 Newtons
Distance = 15 m
Therefore;
Work done = 90 N × 15 m
= 1350 Joules
Hence; Work done pulling out the bucket from the well is 1350 Joules.
Key words: Work done, Force, Distance
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Subject: Physics
Topic: Work, power and simple machines
Two Jupiter-size planets are released from rest 1.40×10^11m apart. What is their speed as they crash?,
To solve this problem, we derive Newton’s Law of Universal Gravitation as the basis of computation
Where: M₁ = mass of planet #1
M₂ = mass of planet #2
M = total mass
R₁ = radius of planet #1
R₂ = radius of planet #2
d₁ = initial distance between planet centers
d₂ = final distance between planet centers
a = semimajor axis of plunge orbit
v₁ = relative speed of approach at distance d₁
v₂ = relative speed of approach at distance d₂
To determine velocity during the impact of two heavenly bodies, the solution is as follows:
M₁ = M₂ = 1.8986e27 kilograms
M = M₁ + M₂ = 3.7972e27 kg
G = 6.6742e-11 m³ kg⁻¹ sec⁻²
GM = 2.5343e17 m³ sec⁻²
d₁ = 1.4e11 meters
a = d₁/2 = 7e10 meters
R₁ = R₂ = 7.1492e7 meters
d₂ = R₁ + R₂ = 1.42984e8 meters
v₁ = 0
v₂ = √[GM(2/d₂−1/a)]
v₂ = 59508.4 m/s
The final answer is 59508.4 m/s.
Answer:
this verified kid is way too smart for his own good
Explanation:
Which has a higher acceleration: a 10-kg object acted upon with a net force of 20 N or an 18-kg object acted on by a net force of 30 N?
A. Both accelerate at the same rate.
B. the 10-kg object
C. the 18-kg object
Answer:
the answer is B, 10-kg object
Explanation:
Because of Newton we know that if a force is applied to an object, it will have an acceleration on the same direction of the force applied.
[tex]F=m*a\\\\where:\\m=mass\\a=acceleration[/tex]
in order to obtain the acceleration we have to reordenate the formula:
[tex]a=\frac{F}{m}[/tex]
The acceleration of the 10 kg object is:
[tex]a=\frac{20N}{10kg}=2\frac{m}{s^2}[/tex]
The acceleration of the object of 18 kg is:
[tex]a=\frac{30N}{18kg}=1.67\frac{m}{s^2}[/tex]
The biggest acceleration was for the object with less mass.
Which of these observations of galileo refuted ptolemy's epicycles? the craters on the moon the rotation of sunspots across the sun's surface the revolution of jupiter's moons around it the complete cycle of venus' phases the visibility of many more stars with the telescope?
The answer is : the complete cycle of venus' phases. This is the observation of Galileo that refuted ptolemy's epicycles. . Using his telescope, Galileo found that Venus went through phases, just like our Moon. But, the nature of these phases could only be explained by Venus going around the Sun, not the Earth.
Galileo's observations that refuted Ptolemy's epicycles were the complete cycle of Venus' phases and the revolution of Jupiter's moons. These observations showed that these bodies were orbiting the Sun and Jupiter respectively, not the Earth as Ptolemy's model suggested.
Explanation:The observation Galileo made that refuted Ptolemy's epicycles was the complete cycle of Venus' phases. Ptolemy's model suggested that all planets revolved in small circles, or 'epicycles', around a point that in turn orbited Earth. However, Galileo's observation showed that Venus goes through a set of phases similar to the Moon's, which could only occur if Venus orbits the Sun, not Earth. This discovery was incompatible with Ptolemy's model which largely placed Earth as the center of the universe. Galileo's discovery of the revolution of Jupiter's moons around it, instead of Earth, also offered further proof against Ptolemy's model.
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When red light and green light shine on the same place on a piece of white paper, the spot appears t obe?
Answer:
yellow
Explanation:
red + green light makes yellow
Which of the following describes the role of a refrigerant in an air conditioner? to absorb heat flow from air molecules circulating around the refrigerant tubing cools the air molecules by adding cool energy to the air as it is circulated around the refrigerant tubing increases the specific heat of the air molecules and allows them to release more heat once cooled decreases the specific heat of the air molecules and allows them to absorb more heat before cooling
Answer:
to absorb heat flow from air molecules circuling around the refrigerant tubing
Explanation:
I know this is correct because I just had this question and this was the correct answer.
What is the velocity of the object at 20.0s
in a lab investigation. one group of students (group A) measures the speed of a 0.1-kilogram car at 2.5 m/sec at the bottom of a hill. Another group of students (group B) measures the speed of the car at 3 m/sec at the bottom of the hill. the car's starting position at the top of the hill is one-meter high. what is the potential energy of the car at the beginning of the experiment before its speed is measured?
The potential energy of the car at the beginning of the experiment, before its speed is measured, is approximately 0.98 Joules.
To calculate the potential energy of the car at the beginning of the experiment, we can use the formula for gravitational potential energy:
Potential energy (PE) = mass (m) × gravitational acceleration (g) × height (h)
Given:
Mass of the car (m) = 0.1 kg
Height of the hill (h) = 1 meter
Gravitational acceleration (g) = 9.8 m/s² (approximately)
The potential energy (PE) is as follows:
PE = m × g × h
= 0.1 × 9.8 × 1
= 0.98 Joules
Therefore, the potential energy of the car at the beginning of the experiment, before its speed is measured, is approximately 0.98 Joules.
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Which best describes the current atomic theory?
A since it is only a theory it shouldn’t be used in practice
B it has not been tested enough to be useful for developing technology
C it is the most powerful explanation scientist have to offer at this time
D there is very lil change it will be changed in the future
C. it is the most powerful explanation scientists have to offer at this time. I am 100% right, I just finish the test and got it right.
A laser beam of wavelength 439.4 nm is inci- dent on two slits 0.306 mm apart.
How far apart are the bright interference fringes on a screen 6.08 m away from the double slits?
Answer in units of cm.
What is the relationship between atomic radius, ionization energy, and electronegativity? What is the relationship between atomic radius, ionization energy, and electronegativity? @Physics,
The relationship between electronegativity, ionization energy, and atomic radius is that larger atoms are less attracted by nuclear force, which impacts their ability to retain and attract electrons.
Atomic Radius:
It is generally defined as the distance from the nucleus to the outermost electron cloud. Atomic radius tends to increase as you move down a group on the periodic table due to the addition of electron shells.Conversely, it decreases as you move across a period from left to right because of the increasing positive charge in the nucleus, which pulls electrons closer.Ionization Energy:
The energy needed to extract an electron from an atom in the gas phase is known as ionization energy.The first ionization energy refers to the energy needed to remove one electron. This energy increases across a period and decreases down a group. Higher ionization energy indicates that an atom holds its electrons more tightly.Electronegativity:
An atom's capacity to draw in and form bonds with electrons is measured by its electronegativity.It goes higher periodically and down within a group.When an atom has a high electronegativity, it draws electrons toward itself in a chemical connection.Relationship Between the Three Properties:
As the atomic radius increases, ionization energy and electronegativity decrease. This is because larger atoms have more electron shells, resulting in weaker attraction between the nucleus and the outermost electrons.Conversely, as the atomic radius decreases, ionization energy and electronegativity increase. This is due to stronger nuclear attraction in smaller atoms, making it harder to remove electrons and easier to attract electrons from other atoms.Which platform did Mr. Ray’s marketing team advise him to use for the launch of a new product?
Mr. Ray is looking for a platform to launch his product. His marketing team advises him to launch the product via_____ as it is free advertising and improves_____.
1. A. Newspapers A. Product Quality
B.social Media B. Consumer Welfare
C.Billboards C. Brand Reconition
Social Media and Brand Recognition
Please help! A net force of 2.0 N acts on a 2.0-kg object for 10 seconds. What is the object’s kinetic energy after that 10 seconds (assuming the object starts from rest and there is no friction)?
Two very quick questions!!
1) If a pulley system with an actual mechanical advantage of 2 is used in lifting a 2,000 lb. car, what effort would be needed to move the car?
If a pulley system with an actual mechanical advantage of 2,000,000 is used in lifting a 2,000 lb. car, what effort would be needed to move the car?,
Explanation:
1. Mechanical advantage of a pulley system, m = 2
Mechanical advantage of a machine is defined as the ratio of load to the effort force i.e.
[tex]m=\dfrac{F_L}{F_E}[/tex]
Here, [tex]F_L=2000\ lb[/tex]
[tex]F_E=\dfrac{F_L}{m}[/tex]
[tex]F_E=\dfrac{2000\ lb}{2}[/tex]
[tex]F_E=1000\ lb[/tex]
Hence, 1000 lb effort will be needed to move the car.
2. Mechanical advantage of a pulley system, m = 2,000,000
Value of load, [tex]F_L=2000\ lb[/tex]
Mechanical advantage, [tex]m=\dfrac{F_L}{F_E}[/tex]
[tex]F_E=\dfrac{F_L}{m}[/tex]
[tex]F_E=\dfrac{2000\ lb}{2000000}[/tex]
[tex]F_E=0.001\ lb[/tex]
Hence, 0.001 lb effort would be needed to move the car.
a body of mass 1.5kg, traveling along the positive x axis with speed 4.5m/s,collides with another body B of mass 3.2kg which,initially is at rest. A is deflected and moves with a speed of 2.1m/s in a direction which is 30 degrees below the x axis. B Is set in motion at angle b above the x axis. calculate the velocity of B after collision.,
As you add or remove neutrons from the nucleus, isotopes are formed
Highway curves are marked with a suggested speed. If this speed is based on what would be safe in wet weather, estimate the radius of curvaure for a curve marked 50km/h?The coefficient of static friction of rubber on wet concrete is .7, the coefficient of kinetic friction of rubber on wet concrete is .5 .
The radius of curvature for wet weather is required.
The radius of curvature would be 28.1 m.
[tex]\mu_s[/tex] = Coefficient of static friction for wet concrete = 0.7
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
m = Mass of car
v = Velocity of car = 50 km/h
The force balance is
[tex]\dfrac{mv^2}{r}=\mu_s mg\\\Rightarrow r=\dfrac{v^2}{\mu_s g}\\\Rightarrow r=\dfrac{(50\times \dfrac{1000}{3600})^2}{0.7\times 9.81}\\\Rightarrow r=28.1\ \text{m}[/tex]
The radius of curvature would be 28.1 m.
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