Final answer:
To find the distance Serena can hit a golf ball with her driver, we can multiply the distance with her 9-iron by 2.
Explanation:
To find the expression that represents the distance Serena hit the golf ball with her 9-iron, we know that the ball stopped x yards in front of the 100-yard marker. So, the distance Serena hit the ball with her 9-iron is 100 - x yards. To find how far Serena can hit a golf ball with her driver, which is twice as far as her 9-iron, we can multiply the distance with her 9-iron by 2. Therefore, the expression that represents the distance Serena can hit the golf ball with her driver is 2(100 - x) yards.
How many solution(s) are there
for this system?
6y=12x+36
15y=45x60
Final answer:
The given system of equations has one unique solution because the lines represented by the equations have different slopes, hence they intersect at exactly one point.
Explanation:
To answer how many solutions there are for the given system of equations:
6y=12x+36
15y=45x+60 (Assuming the '+60' was meant instead of '60', as '+60' makes it a linear equation)
We first simplify both equations to determine if they are identical, parallel, or intersecting.
For the first equation, we divide by 6:
y = 2x + 6
For the second equation, assuming a typo and it should be '+60', we divide by 15:
y = 3x + 4
Since the slopes (2 and 3) are different, the lines are not parallel and will intersect at exactly one point. Therefore, there is one unique solution to this system.
A small accounting firm has 444 accountants who each earn a different salary between \$50{,}000$50,000dollar sign, 50, comma, 000 and \$60{,}000$60,000dollar sign, 60, comma, 000, and a 5^{\text{th}}5 th 5, start superscript, start text, t, h, end text, end superscript accountant who works part-time for tax season and earns \$10{,}000$10,000dollar sign, 10, comma, 000. [Show data] 1010 5252 5454 5656 5858 The firm decides to get rid of the part-time accountant and keep the other 444 salaries the same. How will getting rid of the part-time accountant affect the mean and median? Choose 1 answer: Choose 1 answer: (Choice A) A Both the mean and median will increase, but the median will increase by more than the mean. (Choice B) B Both the mean and median will increase, but the mean will increase by more than the median. (Choice C) C The mean will increase, and the median will decrease. (Choice D) D The median will increase, and the mean will decrease.
Answer:
The correct option is;
(Choice B) Both the mean and median will increase, but the mean will increase by more than the median.
Step-by-step explanation:
Here, we are expected to show the differences (advantages/properties) of the mean and median
Note that the definition of the mean is the sum of the value of all data points divided by the number of data points
Assuming the four accountants each earn $ 55,000.00
Therefore, initial mean before getting rd of the part-time accountant is
(55+ 55+ 55 + 55 + 10)/5 = 46
Final mean after the part-time accountant is gone =(55+ 55+ 55 + 55 )/4 = 55
Therefore the mean increases
However, the median is given by the middle value when the list of values are arranged in increasing order as
55, 55, 55, 55, 10
Therefore the initial median is 55
Final median after the part-time accountant is gone is
55, 55, 55, 55
Therefore, final = (55 + 55)/2 = 55
That is the median remains the same that is little or increase.
Therefore, since the range of values for the full time accountants salaries weigh less than the difference between the average full time salary and a single part time, both the mean and the median will increase but the mean will increase more than the median
Answer:
b
Step-by-step explanation:
Graham sold 6 magazines less than double what Adrianne sold, a. Which of the following expressions represents Graham's sales?
6a − 2
2(a − 6)
a^2 − 6
2a − 6
For a school fundraiser, Ayana needs to sell 40 rolls of wrapping paper. So far, she has sold 7 rolls to her grandmother, 2 rolls to her uncle, and 9 rolls to a neighbor. How many more rolls of wrapping paper does Ayana need to sell?
Answer:
22?
Step-by-step explanation:
Just take 40 and subtract the 7 to get 33 and then 2 to get 31 and 9 to get 22.
Answer:
22 more rolls
Step-by-step explanation:
if she needs to sell 40 and she has sold 9+7+2=18 than you subtract 18 from 40 getting 22 more rolls
Simplify the expression 2(-9+9v)
A right triangle whose hypotenuse is 3 centimeters long is revolved about one of its legs to generate a right circular cone. Find the radius, height, and volume of the right cone that will have the greatest volume when constructed this way.
Answer:
The height of the right circular cone when constructed this way is [tex]\sqrt3[/tex] cm.
The radius of the right circular cone when constructed this way is [tex]\sqrt6[/tex] cm.
The volume of the right circular cone when constructed this way is [tex]6\sqrt3 \pi[/tex] cm³.
Step-by-step explanation:
Given that,
A right triangle whose hypotenuse is 3 cm long is revolved .
Then other two legs of the triangle will be radius and height of the cone.
Assume the height and radius of the cone be h and r respectively.
From Pythagorean Theorem :
h²+r²=3²
⇒ r²= 9 - h²
Then the volume of the cone is
V= π r²h
⇒ V= π(9-h²)h [ ∵ r²= 9 - h²]
⇒V= π(9h - h³)
Differentiating with respect to h
V'=π(9 - 3h²)
Again differentiating with respect to h
V''= π(-6h)
⇒V''= (-6πh)
To maximum or minimum ,we set V'=0
π(9 - 3h²)=0
⇒3h²=9
⇒h²=3
[tex]\Rightarrow h=\sqrt3[/tex]
Now, [tex]V''|_{h=\sqrt3}=-6\pi (\sqrt3)<0[/tex].
Since at [tex]h=\sqrt3[/tex],V''<0.
The volume of cone is maximum at [tex]h=\sqrt3[/tex] cm when constructed this way.
The height of the right circular cone when constructed this way is [tex]\sqrt3[/tex] cm.
The radius of the right circular cone when constructed this way [tex]r=\sqrt{9-(\sqrt3)^2[/tex]
= [tex]\sqrt{9-3}[/tex]
[tex]=\sqrt6[/tex] cm.
The volume of the right circular cone when constructed this way is
=π r²h
[tex]=\pi (\sqrt6)^2\sqrt3[/tex]
[tex]=6\sqrt3 \pi[/tex] cm³
Find the length of the radius in a circle if the diameter is 10 feet
Sarah is fighting a sinus infection her doctor prescribed a nasal spray and I know a biotic to fight the infection the active ingredient in milligrams remaining in the bloodstream from the nasal spray in, tea, and the anabiotic a comity, our models in the functions below where tea is the time in hours and some medications were taken
Answer:
a) The antibiotic is made with a greater initial amount of active ingredient
b) The two medications will have the same amount of active ingredients in the blood stream at exactly 8 hours after first taking the medication.
Step-by-step explanation
Active ingredient of Nasal spray left in the bloodstream is modelled as
n(t) = ((t + 1)/(t + 5)) + (18/(t² + 8t + 15))
Active ingredient of Antibiotic left in the bloodstream is modelled as
a(t) = 9/(t+3)
with t in hours.
a) At the instance of usage, the active ingredient for both drugs are at their initial concentration as they appear in the drugs.
So, we find the amount of active ingredient for each drug in the bloodstream at t=0 and compare.
For nasal spray,
n(t) = ((t + 1)/(t + 5)) + (18/(t² + 8t + 15))
At t = 0
n(0) = (1/5) + (18/15) = 1.4
For antibiotics,
a(t) = 9/(t+3)
At t=0
a(0) = (9/3) = 3
3 > 1.4
Hence, the antibiotic is made with a greater initial amount of active ingredient.
b) when both medications will have the same amount of active ingredients in the bloodstream, n(t) = a(t)
n(t) = ((t + 1)/(t + 5)) + (18/(t² + 8t + 15))
a(t) = 9/(t+3)
Note that (t² + 8t + 15) = (t + 3)(t + 5)
When n(t) = a(t)
((t + 1)/(t + 5)) + (18/(t² + 8t + 15)) = 9/(t+3)
Multiplying through by (t² + 8t + 15) or more properly written as (t + 3)(t + 5)
(t+1)(t+3) + 18 = 9(t+5)
t² + 4t + 3 + 18 = 9t + 45
t² - 5t - 24 = 0
Solving the quadratic equation
t = 8 or t = -3
Time can't be negative, hence, t = 8 hours.
Hope this Helps!!!
Please help!!!!!!!!!!!!!!!
Answer:
150
Step-by-step explanation:
1 box is 5 x 5 which=25 x 6 boxes=150
150 squared is your answer
Answer: 150
Step-by-step explanation:
The side of one cube is 5. 5 * 5 = 25 So 25 is the surface area of one cube side. A cube a 6 sides, and 25 * 6 = 150. Therefore, 150 is the surface area of the cube.
PLEASE HELP!!! AND EXPLAIN IF YOU CAN !!!
sin(-295°) = _____. sin 65° sin 295° sin 25° -sin 65°
Answer:
Step-by-step explanation:
sin(-295°)=-sin (295)=-sin (360-65)=-(-sin 65°)=sin (65°)
Fill in the numbers that go into the blank boxes. The numbers have to multiply to be the top number and add to be the bottom number.
Answer: 6 and 6
Step-by-step explanation:6x6=36
6+6=12
The half-life of a radioactive element is 130 days, but your sample will not be useful to you after 80% of the radioactive nuclei originally present have disintegrated. About how many days can you use the sample? Round to the nearest day.
Answer:
We can use the sample about 42 days.
Step-by-step explanation:
Decay Equation:
[tex]\frac{dN}{dt}\propto -N[/tex]
[tex]\Rightarrow \frac{dN}{dt} =-\lambda N[/tex]
[tex]\Rightarrow \frac{dN}{N} =-\lambda dt[/tex]
Integrating both sides
[tex]\int \frac{dN}{N} =\int\lambda dt[/tex]
[tex]\Rightarrow ln|N|=-\lambda t+c[/tex]
When t=0, N=[tex]N_0[/tex] = initial amount
[tex]\Rightarrow ln|N_0|=-\lambda .0+c[/tex]
[tex]\Rightarrow c= ln|N_0|[/tex]
[tex]\therefore ln|N|=-\lambda t+ln|N_0|[/tex]
[tex]\Rightarrow ln|N|-ln|N_0|=-\lambda t[/tex]
[tex]\Rightarrow ln|\frac{N}{N_0}|=-\lambda t[/tex].......(1)
[tex]\frac{N}{N_0}=e^{-\lambda t}[/tex].........(2)
Logarithm:
[tex]ln|\frac mn|= ln|m|-ln|n|[/tex] [tex]ln|ab|=ln|a|+ln|b|[/tex][tex]ln|e^a|=a[/tex] [tex]ln|a|=b \Rightarrow a=e^b[/tex] [tex]ln|1|=0[/tex]130 days is the half-life of the given radioactive element.
For half life,
[tex]N=\frac12 N_0[/tex], [tex]t=t_\frac12=130[/tex] days.
we plug all values in equation (1)
[tex]ln|\frac{\frac12N_0}{N_0}|=-\lambda \times 130[/tex]
[tex]\rightarrow ln|\frac{\frac12}{1}|=-\lambda \times 130[/tex]
[tex]\rightarrow ln|1|-ln|2|-ln|1|=-\lambda \times 130[/tex]
[tex]\rightarrow -ln|2|=-\lambda \times 130[/tex]
[tex]\rightarrow \lambda= \frac{-ln|2|}{-130}[/tex]
[tex]\rightarrow \lambda= \frac{ln|2|}{130}[/tex]
We need to find the time when the sample remains 80% of its original.
[tex]N=\frac{80}{100}N_0[/tex]
[tex]\therefore ln|{\frac{\frac {80}{100}N_0}{N_0}|=-\frac{ln2}{130}t[/tex]
[tex]\Rightarrow ln|{{\frac {80}{100}|=-\frac{ln2}{130}t[/tex]
[tex]\Rightarrow ln|{{ {80}|-ln|{100}|=-\frac{ln2}{130}t[/tex]
[tex]\Rightarrow t=\frac{ln|80|-ln|100|}{-\frac{ln|2|}{130}}[/tex]
[tex]\Rightarrow t=\frac{(ln|80|-ln|100|)\times 130}{-{ln|2|}}[/tex]
[tex]\Rightarrow t\approx 42[/tex]
We can use the sample about 42 days.
Final answer:
The radioactive sample can be used for approximately 390 days.
Explanation:
The half-life of a radioactive element is the time it takes for half of the radioactive nuclei to decay. In this case, the half-life is 130 days. The sample is considered no longer useful when 80% of the nuclei have decayed. To determine how many days the sample can be used, we need to find the number of half-lives it takes for 80% of the nuclei to decay.
80% is the same as 0.8, which means 20% (or 0.2) of the nuclei remain. Each half-life reduces the amount of nuclei by half, so we can set up an equation:
0.2 = (1/2)^n
where n is the number of half-lives.
To solve for n, we can take the logarithm of both sides:
n = log_base(1/2)(0.2)
Using a calculator, we find n ≈ 2.737.
Since we can't have a fraction of a half-life, we round up to the nearest whole number, which gives us n = 3.
Now, we can find the number of days by multiplying the half-life by the number of half-lives:
Number of days = 130 days * 3 = 390 days.
Therefore, the sample can be used for approximately 390 days.
What is the solution to this system of equations?
x − 2y = 15
2x + 4y = -18
Answer:
The answer to your question is (3, -6)
Step-by-step explanation:
Data
x - 2y = 15 Equation l
2x + 4y = -18 Equation ll
Solve the system of equations by elimination
-Multiply equation l by 2
2x - 4y = 30
2x + 4y = -18
4x + 0 = 12
4x = 12
x = 12/4
x = 3
-Substitute x in equation l
3 - 2y = 15
-Solve for y
-2y = 15 - 3
- 2y = 12
y = 12/-2
y = -6
-Solution
(3, -6)
Answer:
C. x = 3, y = -6
Step-by-step explanation
Answer is correct from Plato
What is the least common denominator for:
3/x and 2/4xy
Answer:
the least common denominator is 4xy
The fish population of a lake is decreasing each year. A study is conducted. But, unfortunately some data was lost. The researcher found in her notes that in year one the fish population was 18000 fish and in year three the fish population was 8000 fish. Assume a constant rate of decay. Find a formula F
Answer:
[tex]F(t) = 18000(0.6666)^{t}[/tex]
Step-by-step explanation:
The fish population after t years can be modeled by the following equation:
[tex]F(t) = F(0)(1-r)^{t}[/tex]
In which F(0) is the initial population and r is the constant rate of decay.
Year one the fish population was 18000
This means that [tex]F(0) = 18000[/tex]
In year three the fish population was 8000 fish.
Two years later, so [tex]F(2) = 8000[/tex]
[tex]F(t) = F(0)(1-r)^{t}[/tex]
[tex]8000 = 18000(1-r)^{2}[/tex]
[tex](1-r)^{2} = 0.4444[/tex]
[tex]\sqrt{(1-r)^{2}} = \sqrt{0.4444}[/tex]
[tex]1 - r = 0.6666[/tex]
[tex]r = 0.3334[/tex]
So
[tex]F(t) = 18000(0.6666)^{t}[/tex]
In a right triangle, the value of cos B = 3/5. What is the value of sin B?
[Leave your answer as a fraction]
Answer:
4/5
Step-by-step explanation:
cos B = 3/5
cos Ф = adjacent/hypothesis
hypothesis ² = adjacent² + opposite²
5²= 3²+ o²
25 = 9+o²
25-9=o²
16 = o²
√16 = o = 4
Sin B = opposite/hypothesis = 4/5
4. 4csc^2x+3cscx-1=0
Answer: 8cxs^c= -3 csc (x) +1
Step-by-step explanation:
To solve for c you need to simplify both sides of the equation, then isolating the variable
Answer:
x = - π/2 or x = - π/2 + 2nπ n = integer
Step-by-step explanation:
4csc²x+3cscx-1=0
(csc x + 1) (4csc x - 1) = 0
csc x = - 1 or csc x = 1/4
1/ sin x = - 1 or 1 / sin x = 1/4
sin x = - 1 or sin x = 4 (x no solution when sin x = 4)
sin x = - 1
x = - π/2 or x = - π/2 + 2nπ n = integer
A high-speed bullet train accelerates and decelerates at the rate of 4 ft/s 2 . Its maximum cruising speed is 90 mi/h . (Round your answers to three decimal places.) (a) What is the maximum distance the train can travel if it accelerates from rest until it reaches its cruising speed and then runs at that speed for 15 minutes
Answer:
22.9 miles
Step-by-step explanation:
We are given that
Acceleration=Deceleration=a=[tex]4ft/s^2[/tex]
Maximum cruising speed,v=[tex]90mi/h=90\times \frac{5280}{3600}=132ft/s[/tex]
1 hour=3600 s
1 mile=5280 feet
Time,t=15 minutes=[tex]15\times 60=900 s[/tex]
1 min=60 s
Initial speed,u=0
[tex]v=u+at[/tex]
Substitute the values
[tex]132=0+4t[/tex]
[tex]t=\frac{132}{4}=33 s[/tex]
[tex]s=u+\frac{1}{2}at^2=0+\frac{1}{2}(4)(33)^2=2178 ft[/tex]
Distance,d=[tex]speed\times time=vt=132\times 900=118800ft[/tex]
Total distance=s+d=2178+118800=120978ft
Total distance=[tex]\frac{120978}{5280}=22.9miles[/tex]
Hence, the maximum distance traveled by train =22.9 miles
One of the largest cookies on record had a diameter of 78.75 feet. What is the approximate circumference of the cookie? Use 3.14 for n. Round to tenths place.
Answer:
247.3 Ft
Step-by-step explanation:
c=3.14(78.75)
c=247.245 *rounded*
The question was about calculating the circumference of a circle using its diameter. The diameter was given, and the formula for circumference 'C = πd' was used, where 'd' was 78.75 feet and 'π' was approximated at 3.14. The circumference comes out to be approximately 247.35 feet when rounded to the nearest tenth.
Explanation:The subject in this question is the measurement of the circumference of a cookie given its diameter, a basic concept in geometry in the field of Mathematics. Circumference which is the distance around a circle can be calculated using the formula 'C = πd', where 'C' is the circumference, 'd' is the diameter and 'π' is a constant approximately equal to 3.14.
In this case, the diameter 'd' of the cookie is 78.75 feet. So, by substituting the values into the formula, we get: C = 3.14 * 78.75.
After performing this calculation, you'll find that the approximate circumference of the cookie is 247.35 feet when rounded to the nearest tenth.
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I need to k ow number four
Answer:
Step-by-step explanation:
Find the volume of the composite solid. Round your answer to the nearest tenth.
Answer: I think it's 50.2 but I might be wrong
Suppose you select a ball by first picking one of two boxes at random and then selecting a ball from this box. The first box contains two white balls and three blue balls and the second box contains four white balls and one blue ball. What is the probability that you picked a ball from the first box if you have drawn a blue ball
Answer:
Probability of selecting a ball from the first ball if it is a blue ball = = 0.75
Step-by-step explanation:
Number of blue balls in the first box = 3
Number of blue balls in the second box = 1
Total number of blue balls = 3 + 1
Total number of blue balls = 4
Probability = (Number of possible outcomes)/(Number of total outcomes)
Probability of selecting a ball from the first ball if it is a blue ball = 3/4
Probability of selecting a ball from the first ball if it is a blue ball = = 0.75
Which expressions are equivalent to the one below click all that apply 21x/3x
After simplifying [tex]\(\frac{{21^x}}{{7^x}}\)[/tex], we find it equivalent to [tex]\(3^x\)[/tex], confirming options a, b, and f as correct.
To simplify the expression [tex]\(\frac{{21^x}}{{7^x}}\)[/tex], we can use the property of exponents which states that [tex]\(a^m/a^n = a^{m-n}\)[/tex]. Applying this property, we get:
[tex]\[\frac{{21^x}}{{7^x}} = \frac{{(7 \cdot 3)^x}}{{7^x}} = \frac{{7^x \cdot 3^x}}{{7^x}} = 3^x\][/tex]
So, the simplified expression is [tex]\(3^x\).[/tex]
Now, let's check each option:
a. [tex]\(\frac{{7^x \cdot 3^x}}{{7^x}} = 3^x\)[/tex]. This expression is equivalent to the simplified form.
b. [tex]\((\frac{{21}}{{7}})^x = 3^x\)[/tex]. This expression is equivalent to the simplified form.
c. [tex]\(3\)[/tex]. This expression is not equivalent to the simplified form.
d. [tex]\((21 - 7)^x = 14^x\)[/tex]. This expression is not equivalent to the simplified form.
e. [tex]\(3^{x-7}\)[/tex]. This expression is not equivalent to the simplified form.
f. [tex]\(3^x\)[/tex]. This expression is equivalent to the simplified form.
Therefore, the expressions equivalent to [tex]\(\frac{{21^x}}{{7^x}}\)[/tex] are options a, b, and f.
The question probable maybe:
Given in the attachment
A green die and a red die are tossed. What is the probability that a "4" shows on the green die and a "5" shows on the red die?
Answer:
1 out of 6 for green die and 1 out of 6 for red die
Step-by-step explanation:
As we know there are six numbers on both of the dices
so if we toss a die there is a 1 out of 6 outcomes that a 4 comes out for the green die and 1 out of 6 outcomes again for the red die
The probability that a 4 shows on the green die and a 5 shows on the red die is given by P ( C ) = 1/36
What is Probability?The probability that an event will occur is measured by the ratio of favorable examples to the total number of situations possible
Probability = number of desirable outcomes / total number of possible outcomes
The value of probability lies between 0 and 1
Given data ,
Let the probability that a 4 shows on the green die and a 5 shows on the red die be represented as P ( C )
Now , the number of outcomes in a roll of die = { 1 , 2 , 3 , 4 , 5 , 6 } = 6 outcomes
And , probability that a 4 shows on the green die P ( A ) = 1/6
The probability that a 5 shows on a red die P ( B ) = 1/6
Now , it is an independent experiment
So , the compound probability is P ( C ) = P ( A ) . P ( B )
And , the probability that a 4 shows on the green die and a 5 shows on the red die P ( C ) = ( 1/6 ) ( 1/6 )
The probability that a 4 shows on the green die and a 5 shows on the red die P ( C ) = 1/36
Hence , the probability is P ( C ) = 1/36
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How are the archetypes presented in these two passages
different?
The first passage shows Antigone as a warrior, and the
second passage shows Boadicea as a tragic heroine.
The first passage shows Antigone as a tragic heroine,
and the second passage shows Boadicea as a sage.
The first passage shows Antigone as a rebel, and the
second passage shows Boadicea as a warrior.
The first passage shows Antigone as a villain, and the
second passage shows Boadicea as a sage.
Answer: the third answer. Explanation below.
Step-by-step explanation:
The first passage shows Antigone as a rebel because she chooses to defy the State. The second passage shows Boadicea as a warrior because she "herself led the soldiers, encouraging them with her brave words."
Antigone and Boadicea are presented with different archetypal roles across the passages; Antigone as a warrior, tragic heroine, rebel, and villain; and Boadicea as a tragic heroine, sage, warrior, and sage again.
Explanation:The archetypes presented in these passages are different in the roles and characteristics assigned to Antigone and Boadicea. In the first set of passages, Antigone is depicted as a warrior, then as a tragic heroine, next as a rebel, and lastly as a villain. Conversely, Boadicea is presented as a tragic heroine, followed by a sage, then as a warrior, and finally as a sage once again. These variations represent unique depictions of these mythical figures, giving us different lenses to interpret their actions and significance within their respective narratives.
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What is closest to the difference between the means of the two dot plots?
Answer: The answer is B. 1.0
Step-by-step explanation:
That’s the closest mean
Answer:
A is 15.27 and B is 12.05
Step-by-step explanation:
determine whether the vectors u and v are parallel, orthogonal, or neither. u=(9,0), v=(0,-9)
Answer:
orthogonal
Step-by-step explanation:
If the dot product of the two vectors is 0, then they must be orthogonal.
[tex]u*v=9(0)-9(0) = 0[/tex]
Answer: c
Step-by-step explanation: edge 2021
The video store is having a sale on movie videos. They normally sell for $24.99, but are on sale for $12.99. Mr. Berger purchased 3 videos on sale. How much did he save?
The cross section of a water bin is shaped like a trapezoid. The bases of the trapezoid are 28 feet and 6 feet long. It has an area of 34 square feet. What is the height of the cross section?
Answer:
The height of the cross section if 2 feet
Step-by-step explanation:
To solve this problem recall the formula for the area of a trapezoid of bases B (larger base) and b (smaller base) and height H:
[tex]Area = \frac{(B+b)\,H}{2}[/tex]
Therefore, for our case we have:
[tex]Area = \frac{(B+b)\,H}{2}\\34 \,ft^2 = \frac{(28\,ft+6\,ft)\,H}{2}\\34 \,ft^2 = \frac{(34 \,ft)\,H}{2}[/tex]
So, now we can solve for the height H:
[tex]34 \,ft^2 = \frac{(34 \,ft)\,H}{2}\\2\,*\,34 \,ft^2 =34\,ft\,* H\\H=\frac{2\,*\,34 \,ft^2}{34\,ft}\\ H=2\,ft[/tex]
!3 3/4 as an inproper fraction
Answer:
55/4
Step-by-step explanation:
13 3/4
(13×4 + 3)/4
55/4
Answer:
hope this helps!