Where is tge vertex of the graph of y=-x^2
A rectangular field has a diagonal of 360 feet. One of the side of the field is 160 feet long. What is the perimeter of the field? Enter your answer, rounded to the nearest hundredth, in the box.
Answer:
Perimeter of rectangle rounded to the nearest hundredth is 964.98 feet.
Step-by-step explanation:
Given : A rectangular field has a diagonal of 360 feet. One of the side of the field is 160 feet long.
To find : What is the perimeter of the field? Enter your answer, rounded to the nearest hundredth, in the box.
Formula used : perimeter = 2* length + 2√[tex]d^{2} -l^{2}[/tex].
Solution : We have diagonal of 360 feet and length = 60 feet .
plugging all the values of d and , l in formula .
perimeter = 2* 160 + 2√[tex]360^{2} -160^{2}[/tex].
perimeter = 320 + 2√[129600 -25600].
perimeter = 964.98 feet = nearest hundredth = 964.98 feet.
Therefore, Perimeter of rectangle rounded to the nearest hundredth is 964.98 feet.
WILL GIVE BRAINLIEST ANSWER
PLEASE HELP WITH 9 & 10
Solve 3x - 4 ≤ 2 or 2x + 11 ≥ -1.
Answer:
[All reals]............
You roll an fair number cube. The six possible outcomes when rolling are one, two, three, four, five, six. What are the favorable outcomes when rolling an odd number?
1, 3, 5
2, 4, 6
1, 2, 3, 4, 5, 6
1, 2, 3
Which of the following are necessary when proving that the opposite sides of a parallelogram are congruent? Check all that apply.
A. Corresponding parts of similar triangles are similar.
B. Alternate interior angles are supplementary.
C. Alternate interior angles are congruent.
D. Corresponding parts of congruent triangles are congruent.,
The opposite sides of a parallelogram can be proved congruent by joining the diagonal of the parallelogram and proving the two triangles congruent by ASA .In any parallelogram opposite sides are parallel.We prove the triangles to be congruent by taking the property of parallel lines that Alternate interior angles are congruent.
When the triangles are proved congruent the opposite sides of parallelogram can be proved equal by using the property Corresponding parts of congruent triangles are congruent.,
The options which hold true to prove opposite sides of a parallelogram are congruent are options C and D.
C. Alternate interior angles are congruent.
D. Corresponding parts of congruent triangles are congruent.,
Which of the following problem types CANNOT be solved using the law of sines?
**Choose ALL that apply!!!***
A. SAA
B. SSS
C. AAA
D. SAS
E. ASA
**I'm confused :( can you please explain? thank you :)
Answer:
B) SSS C AAA D) SAS
Step-by-step explanation:
The sine rule is used when we are given
a) Two angles and one side (SAA)
b) Two angles and included side (ASA)
Sine rule can not be used in SSS,AAA or SAS.
Among the given options sine rule can not be used in cases B) SSS C AAA D) SAS
Find the solution set. (x+9) (x+9) = 0
Answer:
The solution set is [tex]x=-9[/tex]
Step-by-step explanation:
we have
[tex](x+9)(x+9)=0[/tex]
we know that
[tex](x+9)(x+9)=x^{2}+18x+81[/tex]
so
[tex]x^{2}+18x+81=0[/tex]
The formula to solve a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] is equal to
[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]
in this problem we have
[tex]x^{2}+18x+81=0[/tex]
so
[tex]a=1\\b=18\\c=81[/tex]
substitute in the formula
[tex]x=\frac{-18(+/-)\sqrt{18^{2}-4(1)(81)}} {2(1)}[/tex]
[tex]x=\frac{-18(+/-)\sqrt{0}} {2}[/tex]
The radicand is equal to zero, therefore, the solution has only one real solution
[tex]x=\frac{-18} {2}=-9[/tex]
The area of a rectangular classroom is given by the trinomial 10x^2 + 3x - 4
What are the possible dimensions of the classroom? Use Factoring.
A.(5x - 4) and (2x + 1)
B.(5x - 4) and (2x - 1)
C.(5x + 4) and (2x - 1)
D.(5x + 4) and (2x + 1)
which law would you use to simplify the expression (x^4)^9?
The law that will be used to simplify the expression is the law of exponents.
What are Exponents?Exponents are the powers of the base numbers.
The law of exponents will be used to simplify the expression (x⁴)⁹
According to the law of exponents,
(aⁿ )ˣ = [tex]\rm a^{xn}[/tex]
So,
(x⁴)⁹ = x³⁶
Therefore, the law that will be used to simplify the expression is the law of exponents.
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ALGEBRA 2 FOR JIMTHOMPSON!
FUNCTIONS! HELP! Math!
Please help 17 points!!!
what is the image of n for a 144° counterclockwise rotation about the center of the regular pentagon
A. A
B. E
C. P
D. T
Answer:
The correct option is C. The image of N for a 144° counterclockwise rotation about the center is P.
Step-by-step explanation:
The number of vertices of a regular pentagon is 5.
The central angle between two consecutive vertices is
[tex]\frac{360}{5}=72[/tex]
It means the central angle between two consecutive vertices is 72 degrees.
We have to find the image of N for a 144° counterclockwise rotation about the center.
If pentagon rotates 72 degree counterclockwise rotation about the center, then the image of N is E.
If pentagon rotates (72+72) degree counterclockwise rotation about the center, then the image of N is P.
The image of N for a 144° counterclockwise rotation about the center is P.
Therefore the correct option is C.
The figure was created by repeatedly reflecting triangle NMP. What is the perimeter of the figure? 36 in. 42 in. 44 in. 48 in.
Answer:
Perimeter = 42 inches
Explanation:
The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides. In case of any diagram or figure, we add all the outer sides of the figure to get perimeter.
Here, outer sides are :
4, 4, 4, 4, 4, 4, 4, 6, 8
Now add all the sides together.
Permeter = 4 + 4 + 4 + 4 + 4 + 4 + 4 + 6 + 8 = 42 inches.
Final answer is 42 inches
Answer:
42 inches
Step-by-step explanation:
The velocity of a 150 kg cart changes from 6.0 m/s to 14.0 m/s. What is the magnitude of the impulse that acted on it?
(Points : 1)
900 kgm/s
1,200 kgm/s
3,000 kgm/s
2,100 kgm/s
Line VW is to be drawn on the graph such that it is perpendicular to line . If the coordinates of point W are (–1, y), what is the value of y?
Y=
The value of y is 3
Further explanationSolving linear equation mean calculating the unknown variable from the equation.
Let the linear equation : y = mx + c
If we draw the above equation on Cartesian Coordinates , it will be a straight line with :
m → gradient of the line
( 0 , c ) → y - intercept
Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :
[tex]\large {\boxed {m = \frac{y_2 - y_1}{x_2 - x_1}} }[/tex]
If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :
[tex]\large {\boxed {y - y_1 = m ( x - x_1 )} }[/tex]
Let us tackle the problem.
Firstly , we will calculate the gradient of the line that passes through the point S( -5 , 0 ) and T( 5 , 2 ) .
[tex]m_{ST} = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex]m_{ST} = \frac{2 - 0}{5 - (-5)}[/tex]
[tex]m_{ST} = \frac{2}{10}[/tex]
[tex]\large {\boxed {m_{ST} = \frac{1}{5} } }[/tex]
Next , we will calculate the gradient of the line that passes through the point V( 0 , -2 ) and W( -1 , y ) .
[tex]m_{VW} = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex]m_{VW} = \frac{y - (-2)}{-1 - 0}[/tex]
[tex]\large {\boxed {m_{VW} = \frac{y + 2}{-1} } }[/tex]
The conditions of the line perpendicular to each other will satisfy the following formula.
[tex]m_{ST} \times m_{VW} = -1[/tex]
[tex]\frac{1}{5} \times \frac{y + 2}{-1} = -1[/tex]
[tex]\frac{y + 2}{-5} = -1[/tex]
[tex]y + 2 = -5 \times -1[/tex]
[tex]y + 2 = 5[/tex]
[tex]y = 5 - 2[/tex]
[tex]\large {\boxed {y = 3} }[/tex]
Learn moreInfinite Number of Solutions : https://brainly.com/question/5450548System of Equations : https://brainly.com/question/1995493System of Linear equations : https://brainly.com/question/3291576Answer detailsGrade: High School
Subject: Mathematics
Chapter: Linear Equations
Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point
Please help asap!!! 13 points!
What is the sum of the geometric series rounded to the nearest whole number?
A.4
B.0
C.2
D.3
Answer:
Option A. [tex]4[/tex]
Step-by-step explanation:
we know that
The sum of a geometric series is equal to
[tex]Sum=a(\frac{1-r^{n}}{1-r})[/tex]
where
a is the first term
r is the common ratio
n is the number of terms
In this problem we have
[tex]a=2,r=0.5,n=16[/tex]
substitute the values
[tex]Sum=2(\frac{1-0.5^{16}}{1-0.5})=4[/tex]
Which rational number is one-half of the way between 2 and 6.5: 2.25, 4.25, 4.5, or 4.75? And please explain.,
Suppose the velocities of golf swings for amateur golfers are normally distributed with a mean of 95 mph and a standard deviation of 3.9 mph.
What is the difference in velocities between a golfer whose z-score is 0 and another golfer whose z-score is −1?
1.95 mph
2.9 mph
3.9 mph
7.8 mph
1. What is the value of x? Show all of your work.
which letter has at least one line of symmetry?
D
J
G
P
DOES ANYONE HAVE THE WHOLE QUIZ???? UNIT 4 Compositions of Isometries
A builder has 7200kg of sand.
A) write 7200 in grams
B) Give our answer in standard form,
In 2000 the population of a city was 588292 people. in 2002 the population of the city increased to 599656, what is the population in 2008
A pile of sand is in the shape of a cone. The diameter of the sand pile is 18 feet and the height is 10 feet.
What is the volume of the sand pile?
Use 3.14 for pi.
Enter your answer as a decimal
The volume of pile of sand having diameter of 18 feet and height of 10 feet is 847.8[tex]feet^{3}[/tex].
What is volume?Volume is basically the amount of something which the container can hold in its capacity or the amount of material with the help of which it is formed.
How to determine volume?It is told that the pile of sand is of cone shaped and it is having diameter 18 feet and height 10 feet. So the volume of sand pile will be
Volume=1/3π[tex]r^{2} h[/tex]
Radius=diameter/2
=18/2
=9 feet
Volume=1/3*3.14*[tex]9^{2}[/tex]*10
=1/3*3.14*81*10
=254.34/3
=847.8 [tex]feet^{3}[/tex]
Hence the volume of the sand pile of diameter 18 feet and height 10 feet is 847.8 [tex]feet^{3}[/tex].
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The graph shown is the graph of which function?
Answer:
The function of the graph is y = f(x) = x².
Step-by-step explanation:
From the graph we have
At x = 0, y = 0
Therefore f(x) = ax + c where c = 0
At x = 1 y = 1
At x = 4 y = 2
At x = 9 y = 3
At x = 16 y = 4
Therefore the graph is of the form, y= f(x) = x²
That is the graph can be plotted with a slope given by dy/dx = 2x an an intercept of c = 0.
Values of the graph are as follows
x y
1 1
2 √2
3 √3
4 2
5 √5
6 √6
7 √7
8 2√2
9 3.
Matt's Ice Cream Shoppe has 7 cups of sprinkles to use on sundaes for the rest of the day. If each sundae is served with
1/8
cup of sprinkles, how many sundaes can they serve?
The number of sundaes they can serve with 7 cups of sprinkles is 56.
What is the unitary method?The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
Given that, Matt's Ice Cream Shoppe has 7 cups of sprinkles to use on sundaes for the rest of the day.
Number of sundaes = Total quantity of sprinkles/Number of cups of sprinkles in each serving
= 7÷ 1/8
= 7×8
= 56
Therefore, the number of sundaes they can serve with 7 cups of sprinkles is 56.
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A bakery receives an order for 1600 cookies if 12 cookies are packed in each bag how many bags are needed
134 bags are needed to pack all the cookies.
To solve this problem, you need to divide the total number of cookies by the number of cookies that fit in each bag.
Start with the total number of cookies:
1600 cookies.
Each bag can hold 12 cookies:
1 bag= 12 cookies
Divide the total number of cookies by the number of cookies per bag:
1600 ÷ 12.
Using division:
1600 ÷ 12
= 133.33.
Since you can't have a partial bag, you need to round up to the next whole number.
So, you will need 134 bags to pack all the cookies.
How can transposable elements promote functional genetic diversity in a population?
Insertion into a regulatory sequence may alter the strength of transcription.
Insertion into an intro may provide an alternative splice site, producing a protein with a new exon.
Insertion into an mRNA strand may change the amino acid sequence produced.,