Answer:
3.26 atm will the tire’s pressure be when the temperature is 25.0°C.
Explanation:
To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1\text{ and }T_1[/tex] are the initial pressure and temperature of the gas.
[tex]P_2\text{ and }T_2[/tex] are the final pressure and temperature of the gas.
We are given:
[tex]P_1=3.04 atm\\T_1=5.00^oC=5.00+273 K=278.00 K\\P_2=?\\T_2=25^oC=25.0+273K=298.0K[/tex]
Putting values in above equation, we get:
[tex]\frac{3.04 atm}{278.00 K}=\frac{P_2}{298.0 K}\\\\P_2=3.26 atm[/tex]
3.26 atm will the tire’s pressure be when the temperature is 25.0°C.
Using Gay-Lussac's Law, we find that when the temperature of the tire increases from 5.00 C to 25.0 C, the pressure in the car tire will increase from 3.04 atm to approximately 3.26 atm, assuming the volume and amount of gas remain constant.
To determine the tire's air pressure at a higher temperature, we can use the Gay-Lussac's Law which states that the pressure of a gas of fixed mass and fixed volume is directly proportional to the gas's absolute temperature.
The law's formula is given by P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature respectively. Remember to convert temperatures to Kelvin by adding 273.15 to the Celsius value.
Let's calculate the final pressure, P2, when the temperature changes from 5.00 C (278.15 K) to 25.0 C (298.15 K):
P2 = (P1 x T2) / T1
Substituting the given values:
P2 = (3.04 atm x 298.15 K) / 278.15 K = (3.04 atm x 1.0719) = 3.26 atm
So, when the temperature of the tire increases to 25.0 C, the pressure in the car tire will be approximately 3.26 atm, assuming the volume and the amount of gas remain constant.
Aluminium reacts with chloride to produce aluminium chloride if you begin with 3.2g of aluminium and 5.4g of chloride which is the limiting reactant and how many grams of aluminium chloride can be produced from the amount of limiting reactant available
Answer:
A. Chlorine (Cl2) is the limiting reactant.
B. 6.77g of AlCl3
Explanation:
The balanced equation for the reaction. This is given below:
2Al + 3Cl2 —> 2AlCl3
Next, we shall determine the masses of Al and Cl2 that reacted and the mass of AlCl3 produced from the balanced equation. This is illustrated below:
Molar Mass of Al = 27g/mol
Mass of Al from the balanced equation = 2 x 27 = 54g
Molar Mass of Cl2 = 2 x 35.5 = 71g/mol
Mass of Cl2 from the balanced equation = 3 x 71 = 213g
Molar Mass of AlCl3 = 27 + (3x35.5) = 133.5g/mol
Mass of AlCl3 from the balanced equation = 2 x 133.5 = 267g
Thus, from the balanced equation above,
54g of Al reacted with 213g of Cl2 to produced 267g of AlCl3.
A. Determination of the limiting reactant. This is illustrated below:
From the balanced equation above,
54g of Al reacted with 213g of Cl2.
Therefore, 3.2g of Al will react will react with = (3.2 x 213)/54 = 12.52g of Cl2.
We can see that it will take a higher mass of Cl2 ( i.e 12.52g) than what was given ( i.e 5.4g) to react with 3.2g of Al.
Therefore, Cl2 is the limiting reactant.
B. Determination of the mass of AlCl3 produced from the amount of the limiting reactant available.
This is illustrated below:
The limiting reactant is Cl2 with a mass of 5.4g
From the balanced equation above, 213g of Cl2 reacted to produced 267g of AlCl3.
Therefore, 5.4g of Cl2 will react to produce = (5.4 x 267)/213 = 6.77g of AlCl3.
Therefore, 6.77g of AlCl3 is produced from the amount of the limiting reactant available.
The correct answer is that chloride is the limiting reactant and 13.25 grams of aluminium chloride can be produced from the amount of limiting reactant available.
To determine the limiting reactant and the amount of aluminium chloride that can be produced, we need to use stoichiometry. The balanced chemical equation for the reaction between aluminium (Al) and chloride (Cl) to form aluminium chloride (AlCl3) is:
[tex]\[ 2\text{Al} + 3\text{Cl}_2 \rightarrow 2\text{AlCl}_3 \][/tex]
First, we need to calculate the moles of Al and Cl2 available:
- For aluminium (Al):
[tex]\[ \text{Moles of Al} = \frac{\text{Mass of Al}}{\text{Molar mass of Al}} = \frac{3.2 \text{ g}}{26.98 \text{ g/mol}} \approx 0.12 \text{ mol} \][/tex]
- For chloride (Cl2):
[tex]\[ \text{Moles of Cl}_2 = \frac{\text{Mass of Cl}_2}{\text{Molar mass of Cl}_2} = \frac{5.4 \text{ g}}{35.45 \text{ g/mol}} \approx 0.15 \text{ mol} \][/tex]
Next, we use the stoichiometry of the balanced equation to determine which reactant is limiting:
- The ratio of the moles of Cl2 to Al required by the balanced equation is 3:2.
- For the given moles of Al (0.12 mol), the required moles of Cl2 would be:
[tex]\[ \text{Required moles of Cl}_2 = \frac{3}{2} \times 0.12 \text{ mol} = 0.18 \text{ mol} \][/tex]
Since we only have 0.15 mol of Cl2, chloride is the limiting reactant.
Now, we calculate the amount of AlCl3 that can be produced from the limiting reactant (Cl2):
- From the balanced equation, 3 moles of Cl2 produce 2 moles of AlCl3.
- Therefore, 0.15 moles of Cl2 will produce:
[tex]\[ \text{Moles of AlCl}_3 = \frac{2}{3} \times 0.15 \text{ mol} = 0.1 \text{ mol} \][/tex]
- The molar mass of AlCl3 is:
[tex]\[ \text{Molar mass of AlCl}_3 = 26.98 \text{ g/mol (Al)} + 3 \times 35.45 \text{ g/mol (Cl)} \approx 133.23 \text{ g/mol} \][/tex]
- Finally, the mass of AlCl3 produced is:
[tex]\[ \text{Mass of AlCl}_3 = \text{Moles of AlCl}_3 \times \text{Molar mass of AlCl}_3 \][/tex]
[tex]\[ \text{Mass of AlCl}_3 = 0.1 \text{ mol} \times 133.23 \text{ g/mol} \approx 13.323 \text{ g} \][/tex]
Rounding to the appropriate number of significant figures, we get approximately 13.25 grams of aluminium chloride.
Glucose (C6H12O6)(C6H12O6) can be fermented to yield ethanol (CH3CH2OH)(CH3CH2OH) and carbon dioxide (CO2).
C6H12O6⟶2CH3CH2OH+2CO2
The molar mass of glucose is 180.15 g/mol,180.15 g/mol, the molar mass of ethanol is 46.08 g/mol,46.08 g/mol, and the molar mass of carbon dioxide is 44.01 g/mol.
a) What is the theoretical yield (in grams) of ethanol from the fermentation of 97.5 g of glucose?
b) If the reaction produced 23.4 g of ethanol, what was the percent yield?
Answer: a) 49.8 gram
b) 47.0 %
Explanation:
First we have to calculate the moles of glucose
[tex]\text{Moles of glucose}=\frac{\text{Mass of glucose}}{\text{Molar mass of glucose}}=\frac{97.5g}{180.15g/mole}=0.54moles[/tex]
The balanced chemical reaction will be,
[tex]C_6H_{12}O_6\rightarrow 2CH_3CH_2OH+2CO_2[/tex]
From the balanced reaction, we conclude that
As,1 mole of glucose produce = 2 moles of ethanol
So, 0.54 moles of glucose will produce = [tex]\frac{2}{1}\times 0.54=1.08[/tex] mole of ethanol
Now we have to calculate the mass of ethanol produced
[tex]\text{Mass of ethanol}=\text{Moles of ethanol}\times \text{Molar mass of ethanol}[/tex]
[tex]\text{Mass of ethanol}=(1.08mole)\times (46.08g/mole)=49.8g[/tex]
Now we have to calculate the percent yield of ethanol
[tex]\%\text{ yield of ethanol}=\frac{\text{Actual yield}}{\text{Theoretical yield }}\times 100=\frac{23.4g}{49.8g}\times 100=47.0\%[/tex]
Therefore, the percent yield is 47.0 %
Final answer:
The theoretical yield of ethanol from the fermentation of 97.5 g of glucose is 49.3 g. The percent yield is 47.4% if the actual yield of ethanol is 23.4 g.
Explanation:
To determine the theoretical yield of ethanol, we need to calculate the molar ratio between glucose and ethanol. According to the balanced equation, for every mole of glucose, two moles of ethanol are produced. Therefore, we can set up a proportion and solve for the theoretical yield:
(97.5 g glucose / 180.15 g/mol) x (2 mol ethanol / 1 mol glucose) x (46.08 g/mol) = 49.3 g ethanol
For the percent yield, we can divide the actual yield (23.4 g) by the theoretical yield (49.3 g) and multiply by 100:
(23.4 g / 49.3 g) x 100 = 47.4%
Is 12.0 mv at 25 °c. calculate the concentration of the zn2 (aq) ion at the cathode?
Answer:
the concentration of the Zn²⁺ (aq) ion at the cathode is 0.255 M
Explanation:
The voltage generated by the zinc electric cell that is discribed by the following relation;
[tex]Zn(s)\mid 0.1MZn^{2+(aq)}\parallel 0.2 Zn^{2+}(aq)\mid Zn(s)[/tex]
The Nernst equation is given as follows;
[tex]E = E^0 - \frac{RT}{nF} ln(\frac{a^b_B}{a^a_A} )[/tex]
[tex]E_{anode} = E^0 - \frac{0.0591}{2} logZn^{2+}[/tex]
[tex]E_{anode}-E_{cathode} =-\frac{0.0591}{2} log\frac{[Z^{2+}]}{[x]}[/tex]
[tex]0.012 =-\frac{0.0591}{2} log\frac{0.1}{[x]}[/tex]
x = 0.255 M.
Therefore the concentration of the Zn²⁺ (aq) ion at the cathode = 0.255 M.
Which of these salts is most likely to be soluble? Potassium nitrate OR Iron carbonate OR Copper oxide
Final answer:
Potassium nitrate is the most likely to be soluble among the options given because all nitrates are known to be soluble in water, while Iron carbonate and Copper oxide are typically insoluble.
Explanation:
Among the given options of salts—Potassium nitrate, Iron carbonate, and Copper oxide—the one most likely to be soluble is Potassium nitrate. This is due to the general solubility rule that all nitrates are soluble in water. Salts containing the large, singly charged NO₃⁻ ion, such as Potassium nitrate, tend to form highly soluble compounds, while carbonates (like Iron carbonate) and oxides (like Copper oxide) are often less soluble or insoluble except in the presence of certain cations like potassium, sodium, and ammonium.
Iron carbonate and Copper oxide are generally insoluble in water. For instance, iron(II) carbonate is not soluble except when combined with cations like potassium, sodium, or ammonium. Similarly, Copper oxide's solubility is very low in water. On the contrary, even though Copper sulfate is not provided as an option, it is worth mentioning that many sulfates, unlike carbonates and oxides, are generally soluble, with few exceptions.
As relative humidity goes up, what do you predict will happen to the wet bulb/dry bulb temperatures?
Answer:
the wet bulb will get warmer because their will be a smaller difference between the the dry/wet bulb temps.
Explanation:
At any given ambient temperature, less relative humidity results in a greater difference between the dry-bulb and wet-bulb temperatures; the wet-bulb is colder.
For your problem, this is opposite, therefore it will get warmer.
Which statement is true about sodium chloride (NaCl)?
It is a salt because it decreases the concentration of metallic ions.
It is an acid because it is formed by the reaction of a salt and an acid.
It is a salt because it is formed by the reaction of an acid and a base.
It is an acid because it increases the concentration of nonmetallic ions
Answer:
The correct answer is : It is a salt because it is formed by the reaction of an acid and a base.
Explanation:
Sodium chloride is formed from the neutralization reaction between a strong acid (hydrochloric acid) and a strong base (sodium hydroxide):
HCl + NaOH ---> NaCl + H20
By reacting strong acid and base, they neutralize each other resulting in a salt (NaCl) and water.
Corresponds to an exothermic reaction (heat is released).
The statement that is true about sodium chloride (NaCl) is:
"It is a salt because it is formed by the reaction of an acid and a base."
Sodium chloride is a classic example of a salt, which is a chemical compound formed when an acid reacts with a base through a neutralization reaction. In the case of NaCl, it is formed by the reaction of hydrochloric acid (HCl), which is an acid, and sodium hydroxide (NaOH), which is a base:
HCl + NaOH → NaCl + H2O
In this reaction, HCl (an acid) reacts with NaOH (a base) to produce NaCl (sodium chloride) and water (H2O). The formation of NaCl is a result of the combination of the positive sodium ions (Na+) from the base and the negative chloride ions (Cl-) from the acid. This reaction is an example of neutralization, where the acidic and basic properties are neutralized to form a salt and water.
So, NaCl is indeed a salt because it is formed by the reaction of an acid (HCl) and a base (NaOH).
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Sr(OH)2 will dissociate into what ions with what charge
Answer : [tex]Sn(OH)_2[/tex] will dissociate into strontium ion, [tex]Sr^{2+}[/tex] with a (+2) charge and hydroxide ion, [tex]OH^-[/tex] with a (-1) charge.
Explanation :
As we know that when strontium hydroxide, [tex]Sn(OH)_2[/tex] dissociates then it gives strontium ion, [tex]Sr^{2+}[/tex] and hydroxide ion, [tex]OH^-[/tex].
The dissociation reaction will be:
[tex]Sr(OH)_2\rightarrow Sr^{2+}+2OH^-[/tex]
[tex]Sn(OH)_2[/tex] will dissociate into strontium ion, [tex]Sr^{2+}[/tex] with a (+2) charge and hydroxide ion, [tex]OH^-[/tex] with a (-1) charge.
Strontium hydroxide, Sr(OH)2, dissociates into one Sr2+ ion and two OH- ions when it dissolves in water.
Explanation:When Sr(OH)2 (strontium hydroxide) dissociates in water, it separates into ions with specific charges. The chemical equation representing this dissociation is:
Sr(OH)₂ → Sr²⁺ (aq) + 2OH⁻(aq)
This means that one molecule of strontium hydroxide will produce one Sr²⁺ ion and two OH⁻ ions. The Sr²⁺ ion has a plus two charge and each of the OH⁻ ions has a negative one charge.
Ling decided to do a science project on exercise. She wanted to find out how long it takes for a person's heart rate to slow down to normal after exercise.Which of the following was likely the scientific prediction Ling made about her project?
A.
My heart beats 60 times each minute.
B.
Exercise is important.
C.
A person's heart rate slows down in three minutes.
D.
I found out that my heart beat slows down after five minutes.
Final answer:
Ling's scientific prediction was most likely that a person's heart rate slows down to normal in three minutes after exercise, as this directly pertains to the expected outcome of her science project. Option C is correct.
Explanation:
The scientific prediction that Ling likely made about her project is related to the time it will take for a person's heart rate to return to normal after exercise. Based on the options provided, the most relevant prediction is C. A person's heart rate slows down in three minutes. This is because it refers directly to the expected outcome of the experiment regarding heart rate recovery time, while the other options are either base rate information or observations that don't predict the outcome of the experiment.
You want to create 14.0 g of copper to meld into a piece of jewelry. You
know that when copper (II) chloride reacts with aluminum, copper is a
product. How much aluminum would you need to start your reaction with
to get 14.0 g of copper? *
2Al + 3CuCl2 + 2AlCl3 + 3Cu
Answer:
3.4g of Al
Explanation:
you would need to start with 3.4 g of Al
How many moles are in 6.99 x 1020 formula units of magnesium bromide (MgBr2)? Round your answer to 2 decimal places and, if needed, enter scientific notation like this 6.02e23 (would mean 6.02 x 1023.)
Answer:
1.16x10^–3 mole
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 formula units. This implies that 1 mole of MgBr2 also contains 6.02x10^23 formula units.
Now, if 1 mole of MgBr2 contains 6.02x10^23 formula units,
Then Xmol of MgBr2 will contain 6.99x10^20 formula units i.e
Xmol of MgBr2 = 6.99x10^20/6.02x10^23
Xmol of MgBr2 = 1.16x10^–3 mole
Given the reaction at equilibrium:N2(g) + 3H2(g) 2NH3(g) + 91.8kJWhat occurs when the concentration of H2(g) is increased?A)The rate of the forward reaction increases and the concentration of N2(g) decreases.B)The rate of the forward reaction decreases and the concentration of N2(g) increases.C)The rate of the forward reaction and the concentration of N2(g) both increase.D)The rate of the forward reaction and the concentration of N2(g) both decrease.
Answer:
A
Explanation:
N2(g) + 3H2(g) -> 2NH3(g)
According to Le Chatelier's principle, and since H2(g) is on the left side and a reactant, if it's concentration is increased, the equilibrium shifts to the right and the forward reaction is favoured, leading to the production of more NH3(g). The rate of the forward reaction increases.
As the concentration of H2(g) is increased, the concentration of the other reactant, N2(g) decreases as more of it is used up to react with the excess H2(g)
The forward reaction would increase to start reducing the concentration of N2.
Explanation:
If it takes 43.32 ml of 0.1 M NaOH to neutrlize a 50 ml HCI solution, how many moles of HCI were originally present?
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WILL MARK BRAINLIEST and 30 points The table lists the number of protons, electrons, and neutrons in a certain radioactive nuclide.
Electrons 11
Protons 11
Neutrons 13
Which is the symbol of this radioactive nuclide?
Superscript 24 subscript 11 upper N a.
Superscript 22 subscript 11 upper N a.
Superscript 13 subscript 11 upper Al.
Superscript 24 subscript 13 upper A l.
Answer:
It is given that number of electrons is 11.
It is known that when an atom is neutral then the number of protons equals number of electrons. Also, atomic number means number of protons an atom holds.
Whereas mass number equals number of protons + number of neutrons. Thus, mass number of given atom is 11 + 13 = 24.
The symbol for this element will be as follows 24/11x . This atom sodium has atomic number 11 and mass number 24.
Therefore, symbol of this radioactive nuclide is as follows . A)Superscript 24 subscript 11 upper N a.
Answer:
Answer Is A
Explanation:
24/11 NA: This answer was correct
Cloudy nights can be warmer than clear nights because clouds trap heat
Answer:
Cloudy nights can be warmer than clear nights because clouds trap heat absorbed by Earth during daylight hours.
Cloudy nights can be warmer than clear nights because clouds trap heat absorbed by Earth during daylight hours.
What is heat?In thermodynamics, heat is defined as the form of energy crossing the boundary of a thermodynamic system by virtue of a temperature difference across the boundary.[1] A thermodynamic system does not contain heat. Nevertheless, the term is also often used to refer to the thermal energy contained in a system as a component of its internal energy and that is reflected in the temperature of the system. For both uses of the term, heat is a form of energy.
Another example of informal usage is the term heat content, used despite the fact that physics defines heat as energy transfer. More accurately, it is thermal energy that is contained in the system or body, as it is stored in the microscopic degrees of freedom of the modes of vibration.
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WILL MARK BRAINLIEST AND 30 POINTS
A radioactive nuclide that is used to label blood platelets has 49 protons and 62 neutrons. Which is the symbol of this nuclide?
Superscript 49 subscript 62 upper I n.
Superscript 62 subscript 49 upper I n.
Superscript 49 subscript 111 upper I n.
Superscript 111 subscript 49 upper I n.
Answer:
The symbol is 111/49 or D
Explanation:
Answer:
The Correct answer here Is D
Explanation:
The answer was 111/49 and i got It right.
There are three groups that contain carbon but are not organic compounds:
•carbon chlorides
•carbon oxides
•carbon iodides
•carbides
•carbonates
Answer:
Carbonates, Carbides, Carbon oxides
Explanation: Its the answer I promise!!
Find Number 6. After Titration, Calculate and Enter Molarity of Base
To calculate the molarity of your base, you will first need to write out the balanced equation for the reaction between your acid and base . You will then use the Molarity of Acid , Volume of Acid, and Volume of Base Used to determine the Molarity of the Base. Your sig figs should match with the sig figs used in the Molarity of the Acid.
I’ll give Brainliest
Answer:
where in the book is it
Explanation:
Describe a main goal of secondary treatment in a modern sewage treatment plant.
Answer:
Explanation:
The main goal of secondary treatment is the further treatment of the liquid waste from primary treatment to remove the residual organics and suspended solids. Most times, secondary treatment follows primary treatment and involves the removal of biodegradable dissolved and colloidal organic matter using aerobic biological treatment processes. Aerobic biological treatment as the name implies, it is performed in the presence of oxygen by aerobic microorganisms (principally bacteria) that metabolize the organic matter in the wastewater, thereby producing more microorganisms and inorganic end-products majorly CO2, NH3, and H2O.
Answer:
A wastewater treatment plant serves to evacuate solids, reducing organic matter and present pollutants, thus restoring oxygen. Bacteria and other microorganisms are used to reduce organic matter and pollutants, so that they consume the organic matter present in the waste water.
The primary purpose of secondary treatment is to improve the process so that at least 90% of all contaminants are evacuated. The equipment used for this purpose is an aeration tank, which supplies large amounts of air to a mixture of wastewater, bacteria and microorganisms. The oxygen found in the injected air increases the growth of microorganisms, so that they consume the organic matter found in the waste water.
Explanation:
A small, jagged particle with a density of 1.2 g/cm3 deposits on the ground before a large, round particle with a density of 0.82 g/cm3.
Which most likely influences the rate of deposition of the jagged particle?
large size
low density
high density
irregular shape
Answer:
C
Explanation:
A small, jagged particle with a density of 1.2 g/cm³ deposits on the ground before a large, round particle with a density of 0.82 g/cm³. The one that is most likely influences the rate of deposition of the jagged particle is high density and the correct option is option 3.
What is Density?Density is the degree of how closely the mass of matter is compacted. The more compacted the mass is in relation to the amount of volume the matter occupies, the higher its density will be. Conversely, matter that has a low density, has a smaller ratio of mass per amount of volume the matter occupies.
To determine the density of a solid that has regular side lengths, it is first needed to calculate the volume of the solid using the equation volume = length x width x height.
The density of a material depends on the molecular packing.
Therefore, A small, jagged particle with a density of 1.2 g/cm³ deposits on the ground before a large, round particle with a density of 0.82 g/cm³. The one that is most likely influences the rate of deposition of the jagged particle is high density and the correct option is option 3.
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Which statement describes how Earth compares to the moon?
Answer:
Earth has more inertia than the moon. The moon has more gravitational pull than Earth. The moon rotates at a constant speed while Earth's speed varies.
Explanation:
Answer:its a
Explanation:
5. A gas occupies 2000. L at 100.0 K and exerts a pressure of 100.0 kPa. What volume will the gas occupy if the temperature is increased to 400. K and the pressure is increased to 200. kPa?
Answer:
The gas will occupy a volume of 4000L
Explanation:
V1 = 2000L
T1 = 100K
P1 = 100kPa = 100*10³Pa
T2 = 400k
P2 = 200kPa = 200*10³kPa
V2 = ?
To solve this question, we need to use combined gas equation
[(P₁ * V₁) / T₁] = [(P₂ * V₂) / T₂]
V₂ = (P₁ * V₁ * T₂) / (P₂ * T₁)
V₂ = (100*10³ * 2000 * 400) / (200*10³ * 100)
V₂ = 8.0*10¹⁰ / 2.0*10⁷
V₂ = 4000L
The new volume of the gas is 4000L
Answer:
The volume that the gas will occupy when the temperature is increased to 400.0 K and the pressure is increased to 200. kPa is 4000. L
Explanation:
Here we are required to utilize the combined gas equation as follows;
[tex]\frac{P_{1}\times V_{1}}{T_{1}} = \frac{P_{2}\times V_{2}}{T_{2}}[/tex]
Where:
P₁ = Initial pressure of the gas = 100.0 kPa
V₁ = Initial volume of the gas = 2000. L
T₁ = Initial temperature of the gas = 100.0 K
P₂ = Final pressure of the gas = 200.0 kPa
V₂ = Final volume of the gas = Required
T₂ = Final temperature of the gas = 400.0 K
Making V₂ the formula subject of the combined gas equation, we have;
[tex]V_{2}}{} = \frac{P_{1}\times V_{1}\times T_{2} }{T_{1}\times P_{2}}[/tex]
Therefore, by plugging the values, we have;
[tex]V_{2}}{} = \frac{100.0\times 2000\times 400.0 }{100.0 \times 200.0 } = 4000. \, L[/tex]
The volume that the gas will occupy when the temperature is increased to 400.0 K and the pressure is increased to 200. kPa = 4000. L.
Which organism is a tertiary consumer?
clownfish
brittle star
killer whale
octopus
Answer:
killer whale
Explanation:
Answer:
c
Explanation:
im taking the test right now
Organisms can reproduce asexually or sexually. All BUT ONE of the steps below is involved in sexual reproduction. Which step
describes asexual rather than sexual reproduction?
The sperm fertilizes the egg to produce a zygote.
Egg and sperm receive chromosomes from each parent.
In some organisms, a piece of the parent may bud off to produce offspring.
The zygote undergoes cell division and cell differentiation to become a
new and different organism from the parents.
The step which best describes asexual rather than sexual reproduction is that "in some organisms, a piece of the parent may bud off to produce offspring." Thus, the correct option for this question is C.
What is Asexual reproduction?Asexual reproduction may be defined as a mode of reproduction in which a new offspring is significantly produced or constructed by a single parent itself. This mode of reproduction does not involve the fusion of gametes or a change in the number of chromosomes.
The new individuals produced through asexual reproduction are genetically and physically identical to each other along with their parents, i.e., they are the clones of their parents. This type of reproduction is mediated via mitosis.
Therefore, the correct option for this question is C.
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Determine the solution of the following system of equations: *
Captionless Image
No solution
(3, 1)
( 1 , -3 )
Infinite Solutions
Answer: N/A
Explanation: You have to write down the equation otherwise we are unable to help you.
How is the size of silver nanoparticles different from normal sized silver?
When it comes to nanoparticles, their size is what gives them their special properties. For example, silver nanoparticles have longer-lasting antibacterial properties than bigger particles of silver. Nanoparticles can be made of many different substances.
The size of silver nanoparticles different from normal sized silver as silver nanoparticles size lies between 1 nm and 100 nm and size of colloidal silver has higher than 100 nm.
What is Colloidal Silver ?Colloidal silver is also called normal silver which is a suspension of silver particles in liquid. The size of colloidal silver particle is higher than 100 nm. Colloidal silver is used in dietary supplements, medication etc.
What is Silver Nanoparticles ?Silver nanoparticles are the nanoparticles of silver the size of these nanoparticles lies between 1nm and 100 nm. Silver nanoparticles are used in medial field, industrial purpose , health care due to their unique physical properties and unique chemical properties.
Thus from the above conclusion we can say that The size of silver nanoparticles different from normal sized silver as silver nanoparticles size lies between 1 nm and 100 nm and size of colloidal silver has higher than 100 nm.
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A chemical reaction in which an acid and a base react to produce salt and water is called a neutralization reaction. In the
neutralization reaction shown below, which substance is the salt?
sulfuric acid + ammonium hydroxide -- ammonium sulfate + water
A. water
B.
sulfuric acid
C. ammonium hydroxide
D.
ammonium sulfate
Reset
Submit
Which of the following is an acid?
Answer:
H2SO4 ( sulfuric acid )
Explanation:
An acid is a substance that releases hydrogen ions in solution. Strong acids like hydrochloric acid ionize completely and are highly likely to participate in chemical reactions, whereas weak acids, like acetic acid, do not ionize completely. Acids are also classified based on their ability to donate protons, which also indicates their strength.
Explanation:An acid is a substance that releases hydrogen ions (H*) in solution. Strong acids, like hydrochloric acid (HCl), ionize completely; releasing all of their H* and are, therefore, more likely to participate in chemical reactions. On the other hand, weak acids, such as acetic acid (vinegar), don't ionize completely meaning some of their hydrogen ions remain bonded within a compound in solution.
Here are examples of acids:
perchloric acidsulfuric acidhydrogen iodidehydrogen bromidehydrogen chloridenitric acidhydronium ionhydrogen sulfate ionphosphoric acidhydrogen fluoridenitrous acidacetic acidcarbonic acidhydrogen sulfideammonium ionThe strength of an acid is determined by how readily it donates its H*. For instance, Hydrochloric acid (HCl) is a strong acid as it completely dissociates into hydrogen and chloride ions, being highly acidic.
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What pressure in kPa is exerted by 94.60 g CO2 at 57.00 ℃ in 0.7500 L?
Answer:
The correct answer is 8,026 x 10³ kPa
Explanation:
We have gaseous CO₂ at the following conditions:
mass = 94.60 g
T= 57.00ºC = 330 K
V= 0.7500 L
We can use the ideal gas equation to calculate the pressure (P):
P x V = n x R x T
⇒ P = (n x R x T)/V
We need n, which is the number of moles of the gas. In order to calculate this, we have to calculate first the molecular weight (MM) of CO₂ as follows:
MM(CO₂)= Molar mass C + (2 x Molar mass O) = 12 g/mol + (2 x 16 g/mol) = 44 g/mol
Now, we can calculate the number of moles (n) of CO₂ from the mass and the molecular weight as follows:
n = Mass/MM = 96.60 g/44 g/mol = 2.19 moles
Now we have all the data. So, we introduce the data in the previos equation and calculate the pressure P:
P = (n x R x T)/V = (2.19 mol x 0.082 L.atm/K.mol x 330 K)/0.7500 L = 79.0152 atm
Finally, we have to convert the pressure from atm to kPa. For this, we know that 1 atm = 1,01325 x 10⁵ Pa and 1 kPa= 1000 Pa.
79.0152 atm x 1,01325 x 10⁵ Pa/atm x 1 kPa/1000 Pa = 8,026 x 10³ kPa
Answer:
7859.98 KPa
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Mass of CO2 = 94.60g
Temperature (T) = 57℃
Volume (V) = 0.75 L
Pressure (P) =?
Step 2:
Determination of the number of mole of CO2.
Mass of CO2 = 94.60g
Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol
Number of mole of CO2 =?
Number of mole = Mass/Molar Mass
Number of mole of CO2 = 94.60/44
Number of mole of CO2 = 2.15 moles
Step 3:
Conversion of celsius temperature to Kelvin temperature.
Temperature (Kelvin) = temperature (celsius) + 273
Temperature = 57℃ + 273 = 330K
Step 4:
Determination of the pressure. This is illustrated below:
The pressure can be obtained by using the ideal gas equation as shown below:
PV = nRT
Temperature (T) = 330K
Volume (V) = 0.75 L
Number of mole (n) = 2.15 moles
Gas constant (R) = 0.082atm.L/Kmol
Pressure (P) =?
PV = nRT
0.75 x P = 2.15 x 0.082 x 330
Divide both side by 0.75
P = (2.15 x 0.082 x 330)/0.75
P = 77.572 atm
Step 5:
Conversion of the pressure in atm to KPa. This is illustrated below:
1 atm = 101.325 KPa
Therefore, 77.572 atm = 77.572x101.325 = 7859.98 KPa
1.) A gas occupies 3.5L at 2.5 atm pressure. What is the volume at 10 atm pressure?
Answer:
.875
Explanation:
Use Boyle's Law and rearrange formula.
- Hope this helps! Please let me know if you need further explanation.
Which of the following best helps explain why the first ionization energy of K is less than that of Ca? The electronegativity of K is greater than that of Ca. A The atomic radius of the K atom is less than that of the Ca atom. B The valence electron of K experiences a lower effective nuclear charge than the valence electrons of Ca. C The nucleus of the K atom has fewer neutrons, on average, than the nucleus of the Ca atom has.
Answer:
B. K valence electron of K experiences a lower effective nuclear charge the valence electrons of Ca
Compared to K+, Ca+ has more shielding and shells. The fact that Ca+ has more protons in its nucleus, which results in a weaker nucleus-electron attraction and lower energy requirements for its removal. Thus, option B is correct.
What is ionization energy?Ionization energy, sometimes referred to as ionization potential, is the amount of energy needed to remove an electron from an isolated atom or molecule in physics and chemistry.
The energy required to expel the outermost, or highest energy, electron from a neutral atom in the gas phase is known as the initial ionization energy of an element.
Ionization energy is conceptually the reverse of electronegativity. The atom converts more easily to a cation the lower this energy is. That an atom will become a cation decreases as this energy increases.
Therefore, The valence electron of K experiences a lower effective nuclear charge than the valence electrons of Ca.
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