Alkynes are hydrocarbons that have.. O a.... at least one triple bond between carbon atoms O b. None of the above. O c. ...all single bonds between carbon atoms. O d....at least one double bond between carbon atoms

Explanation:

Actual value = 102.0 mg/dL

Calculation of absolute error and relative error for the measured value, 98.4 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 98.4 | = 3.6

Relative error = [tex]\frac{Absolute\ error}{Actual\ value}[/tex]

                       = [tex]\frac{3.6}{102.0} = 0.03529[/tex]

Calculation of absolute error and relative error for the measured value, 104.3 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 104.3 | = 2.3

Relative error = [tex]\frac{Absolute\ error}{Actual\ value}[/tex]

                       = [tex]\frac{2.3}{102.0} = 0.02255[/tex]

Calculation of absolute error and relative error for the measured value, 97.4 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 97.4 | = 4.6

Relative error = [tex]\frac{Absolute\ error}{Actual\ value}[/tex]

                       = [tex]\frac{4.6}{102.0} = 0.04509[/tex]

Calculation of absolute error and relative error for the measured value, 106.7 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 106.7 | = 4.7

Relative error = [tex]\frac{Absolute\ error}{Actual\ value}[/tex]

                       = [tex]\frac{4.7}{102.0} = 0.04607[/tex]

Calculation of absolute error and relative error for the measured value, 93.0 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 93 | = 9

Relative error = [tex]\frac{Absolute\ error}{Actual\ value}[/tex]

                       = [tex]\frac{9}{102.0} = 0.08823[/tex]

Answer:

[tex]Mg(s) + HCl(aq) \rightarrow MgCl_2(aq) + H_2(g)[/tex]

[tex]MgO(s) + HCl(aq) \rightarrow MgCl_2(aq) + H_2O(l)[/tex]

Explanation:

When Mg reacts with HCl, magnesium chloride and hydrogen is formed. Mg is an active element and displaces hydrogen from HCl. So, this is a type of single displacement reaction.

[tex]Mg(s) + HCl(aq) \rightarrow MgCl_2(aq) + H_2(g)[/tex]

When magnesium oxide (MgO) reacts with HCl, magnesium chloride and water is formed. This reaction is a type of neutralization reaction. MgO is a water insoluble base and HCl is acid. So. in this reaction, acid reacts with base to form salt [tex]MgCl_2[/tex]

[tex]MgO(s) + HCl(aq) \rightarrow MgCl_2(aq) + H_2O(l)[/tex]

The equation for the reaction between HCl and MgO is 2HCl(aq) + MgO(s) → MgCl2(aq) + H2O(l). The equation for the reaction between HCl and Mg is 2HCl(aq) + Mg(s) → MgCl2(aq) + H2(g). The reactions differ in terms of the reactants involved.

The equation for the reaction between HCl and MgO is:

2HCl(aq) + MgO(s) → MgCl2(aq) + H2O(l)

The equation for the reaction between HCl and Mg is:

2HCl(aq) + Mg(s) → MgCl2(aq) + H2(g)

The reactions differ in terms of the reactants involved. In the reaction with MgO, the reactant is an oxide compound (MgO) while in the reaction with Mg, the reactant is a pure metal (Mg).

Answer:

Binding affinity measures the strength of the interaction between a molecule to its ligand; it is expressed in terms of the equilibrium dissociation constant; and the higher value of this constant, the more weaker the binding between the molecule and the ligand is. On the other hand, small constans means that the interaction is tight. So "C" binds most tightly to the enzyme and "D" binds least tightly.

Answer:

a) HCN  - hybridization sp

b) C(CH₃)₄ - hybridization sp³

c) H₃O⁺  - hybridization sp³

d) - CH₃ - hybridization sp³

Explanation:

Hybridization occurs to allow an atom to make more covalent bonds than the original electronic distribution would allow or to allocate ligands in an energetically stable geometry.

Carbon can have thre hybridization states: sp³ , sp² and sp.

Oxygen usualluy has an sp³ hybridization.

In order to determine the hybridization, we need to consider the number of atoms attached to the central atom and the number of lone pairs.

The figure attached shows the species and the hybridization of their central atoms.

Answer : The time taken will be 25 min.

Explanation :

First we have to determine the amount of fluid.

As, 1 mL contains 30 gtt

So, 500 mL contains [tex]\frac{500mL}{1mL}\times 30gtt=1500gtt[/tex]

Now we have to determine the time taken.

As, 60 gtt takes time = 1 min

So, 1500 gtt takes time = [tex]\frac{1500gtt}{60gtt}\times 1min=25min[/tex]

Therefore, the time taken will be 25 min.

Final answer:

To administer 500 mL of fluid with a drop factor of 30 gtt/mL at a drip rate of 60 gtt/min, the calculation reveals it will take 250 minutes.

Explanation:

To calculate the time required to administer exactly 500 mL of fluid through an IV with a drop factor of 30 gtt/mL at a drip rate of 60 gtt/min, we must first understand the given terms. The drop factor (gtt/mL) is a measure indicating the number of drops (gtt) that make up 1 mL of fluid. The drip rate (gtt/min) specifies how many drops of fluid are administered per minute.

First, we calculate the total number of drops in 500 mL of fluid, using the drop factor:

Next, to find out how long it will take to administer these 15000 drops at a rate of 60 drops per minute, we divide the total number of drops by the drip rate:

Therefore, it will take 250 minutes to administer exactly 500 mL of fluid through the IV at the specified conditions.

Answer:

1-condensation of ethanol

2-evaporation of ethanol

Explanation:

According to the question ,

Answer:

x = 0.01503 = 1.503 × 10⁻² , four significant figures

Explanation:

Significant figures refer to the digits of a number that have meaning and contribute to the precision of the given number.

Since the given equation is:

[tex]\frac{1}{x}=\:66.54[/tex]

Cross-multiplying to solve for the value of x:

[tex]x \times 66.54 = 1[/tex]

⇒ [tex]x = \frac{1}{66.54}[/tex]

⇒ x = 0.01503 = 1.503 × 10⁻² , has four significant figures.

Answer : The correct option is, (c) 79.62

Explanation :

The formula used for percent humidity is:

[tex]\text{Percent humidity}=\text{Relative humidity}\times \frac{p-p^o_v}{p-p_v}\times 100[/tex]   ..........(1)

The formula used for relative humidity is:

[tex]\text{Relative humidity}=\frac{p_v}{p^o_v}[/tex]       ...........(2)

where,

[tex]p_v[/tex] = partial pressure of water vapor

[tex]p^o_v[/tex] = vapor pressure of water

p = total pressure

First we have to calculate the partial pressure of water vapor by using equation 2.

Given:

[tex]p=750mmHg[/tex]

[tex]p^o_v=17.5mmHg[/tex]

Relative humidity = 80 % = 0.80

Now put all the given values in equation 2, we get:

[tex]0.80=\frac{p_v}{17.5mmHg}[/tex]

[tex]p_v=14mmHg[/tex]

Now we have to calculate the percent humidity by using equation 1.

[tex]\text{Percent humidity}=0.80\times \frac{750-17.5}{750-14}\times 100[/tex]

[tex]\text{Percent humidity}=79.62\%[/tex]

Therefore, the percent humidity is 79.62 %

Answer:

No, it doesn't.

Explanation:

To convert ppb to mg/m³ we first need to convert to ppm, by just divide the amount by 1,000, so the concentration in the sample is 4.8 ppm.

mg/m³ = (ppm x molar mass)/molar volume

Using the molar mass in gram and the molar volume in liters, multiplying by the parts per million, we will get the concentration in mg/m³.

Molar mass of C = 12 g/mol; molar mass of Cl = 35.5 g/mol

Molar mass of CCl4 = 12 + 4x35.5 = 154 g/mol

Assuming, 25ºC and 1 atm, the molar volume of an ideal gas is 24.45 L, so:

mg/m³ = (4.8 x 154)/24.45

mg/m³ = 30.2

Which is higher than the limit of 12.6 mg/m³

Answer:

Sample is greater than the standard (32.96 mg/m³ > 12.6 mg/m³)

Explanation:

Please look at the solution in the attached Word file

Light travels a distance of 3.69 meters within the given time frame of 12.3 nanoseconds.

Speed is the measure of how quickly an object changes its position concerning a specified frame of reference. It's a scalar quantity, indicating both magnitude and direction.

Common units for speed include meters per second (m/s) or kilometers per hour (km/h). This fundamental concept plays a pivotal role in various domains like travel, sports, and transportation.

If light travels at a constant speed of [tex]3.0 * 10^8 m/s[/tex] and continues for 12.3 nanoseconds, the distance covered can be calculated:

Distance = Speed × Time

Distance = [tex]3.0 * 10^8 m/s* 12.3 * 10^{-9} s[/tex]

Distance = 3.69 meters

In this instance, light travels a distance of 3.69 meters within the given time frame of 12.3 nanoseconds.

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Answer: An aqueous solution will contains both hydrogen ion and hydroxide ion.An here we are talking about free hydrogen ions, which means the description will be related to the pH. If the ratio of ion are equal then the pH will be 7 i.e. neutral. But if there are free hydrogen atoms in the solution we have, the pH of solution will be less than 7 and the solution will be described ad acidic. So the inaccurate description for a solution containing free hydrogen ion is that it is basic in nature.

Answer:

19

Explanation:

1240.64/64

This is a simple division that can easily be evaluated using any form of calculator.

Here, the main challenge is in expressing the answer in the proper number of significant figure.

The approach here is to express the answer to the which is least precise. This is usually the number with the lower significant values.

Here, 64 has two significant figures and it is of a lower rank. Our answer should be expressed this way:

      [tex]\frac{1240.64}{64}[/tex] = 19.385 = 19

Answer:

36.5 lbs weight of child able to take 413.91 mg/ day dose

Amoxicillin should be stored in temperature 0°C to 20°C, therefore it must be stores  in refrigerator as it provided temperature only between 0°C to 5°C.

Explanation:

Given data:

Dosage of Amoxicillin as prescribed is  25 mg/kg-day

Weight of the Child weight  = 36.5 lbs

As We know  1 lbs = 0.4536 kg

therefore, the weight of Child is  36.5\times 0.4536 kg = 16.5564 kg

From the information about  dosage,

1 kg of body takes = 25 mg/day

so, for 16.556 kg body [tex]16.5564\  kg \ body\  takes = 25\times 16.5564 = 413.91 mg/day[/tex]

Therefore 36.5 lbs weight of child able to take 413.91 mg/ day dose

Amoxicillin should be stored in temperature 0°C to 20°C, therefore it must be stored  in refrigerator as it provided temperature only between 0°C to 5°C.

Final answer:

To calculate the amoxicillin dosage for a child, convert the child's weight to kilograms, multiply by the prescribed mg/kg dosage, then divide by the tablet strength. Amoxicillin should be stored in a refrigerator, not a freezer.

Explanation:

The question relates to the prescription and administration of amoxicillin dosage based on a patient's weight. To determine the number of tablets to administer, you will need to convert the child's weight from pounds to kilograms (1 pound = 0.453592 kg), multiply the child's weight in kilograms by the prescribed dosage per kilogram and then divide the total dosage by the amount of medicine per tablet.

Using the information provided, if a doctor prescribes amoxicillin at 30mg/kg to a child weighing 73.5 lbs, first convert the weight: 73.5 lbs × 0.453592 = 33.3 kg approximately. Next, calculate the total dosage: 33.3 kg × 30 mg/kg = 999 mg. Since amoxicillin is available in 500 mg tablets, divide the total dosage by the tablet strength: 999 mg / 500 mg/tablet = about 2 tablets (always round to the nearest whole number when it involves whole tablets).

Amoxicillin should be stored between 0 °C and 20 °C, which is typically within the temperature range of a refrigerator, not a freezer. Therefore, amoxicillin should be stored in the refrigerator to maintain its efficacy.

Answer:

Rate in terms of formation of [tex]O_{3}[/tex] is [tex]1.45\times 10^{-5}mol/L.s[/tex]

Explanation:

The rate of formation is the time taken by the reaction to yield the product by the chemical change in the reactants. The rate of the formation of the ozone is [tex]1.45 \times 10^{-5} \;\rm mol/Ls[/tex].

The law of mass action states that the rate of the reaction is proportional to the product of the reactant masses.

Rate according to the law of mass action:

[tex]\rm -\dfrac{1}{3}\dfrac {\Delta[O_{2}]}{\Delta t} = \rm \dfrac{1}{2}\dfrac{\Delta [O_{3}]}{\Delta t}[/tex]

Here,

Substituting values in the above equation:

[tex]\begin{aligned}\rm \dfrac{\Delta [O_{3}]}{\Delta t} &= \dfrac{2}{3}\times - \rm \dfrac{\Delta [O_{2}]}{\Delta t}\\\\&= \dfrac{2}{3} \times (2.17 \times 10^{-5})\\\\&= 1.45 \times 10^{-5}\;\rm mol/Ls\end{aligned}[/tex]

Therefore, the rate of formation in the terms of ozone is [tex]1.45 \times 10^{-5} \;\rm mol/Ls.[/tex]

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Answer:

a) k = [tex]\frac{[C][D]}{[A][B]}[/tex]

b) A value of 45000 means that tendency of your reaction is to have more products in a ratio of 45000:1

c) No, the products are more stable than reactants.

Explanation:

a) For a reaction:

A + B → C + D

The equlibrium constant (k) is:

k = [tex]\frac{[C][D]}{[A][B]}[/tex]

Where [x] is the molar concentration of x. Always the expression of equilibrium constant is molar concentration of products over molar concentration of reagents.

b) Having in mind the expression of equilibrium constant when k>1 the concentration of products is higher than concentration of reagents. Thus, when k<1 concentration of reagents is higher than concentration of products.

A value of 45000 means that tendency of your reaction is to have more products in a ratio of 45000:1

c) Again, a value of 45000 means that tendency of your reactants is react to produce products. Thus, the products are more stable than reactants.

I hope it helps!

Answer:

2.5 militers (mL) of digoxin solution

Explanation:

if         1 microgram = 0.001 miligram

then   62.5 micrograms = X miligrams

X = (62.5 × 0.001) / 1 = 0.0625 miligrams

the we calculate the number of militers of digoxin needed by the patient:

if we have           0.0250 miligrams of digoxin in 1 mililiter of solution

then we have     0.0625 miligrams of digoxin in X mililiters of solution

X = (0.0625 × 1) / 0.0250 = 2.5 militers (mL) of digoxin solution

To calculate the amount of digoxin in milliliters, divide the amount of digoxin in milligrams by the concentration of the liquid form in milligrams per milliliter. In this case, the prescription is for 62.5 mcg of digoxin, and the concentration of the liquid form is 0.0250 mg/mL. The calculated volume of digoxin to be given is 2.5 mL.

To calculate the amount of digoxin in milliliters that should be given, we need to use the given information and convert units. The prescription is for 62.5 mcg (micrograms) of digoxin, and the concentration of the liquid form is 0.0250 mg/mL. To convert micrograms to milligrams, we divide by 1000. Then, we can use the formula: Volume (in mL) = Amount (in mg) / Concentration (in mg/mL).

Amount of digoxin in mg = 62.5 mcg / 1000 = 0.0625 mg

Volume of digoxin in mL = 0.0625 mg / 0.0250 mg/mL = 2.5 mL

Answer:

H2 SO4 (Sulfuric acid) - HMnO4 (Permanganic acid) - HNO2 (Nitrous acid) HClO4 (Perchloric acid) - H2 SO3 (Sulphurous acid) - H2CrO4 (Chromic acid)  H2CO3 (Carbonic acid) - HClO3 (Chloric acid) - H3BO3 (boric acid) - HClO2 (Chlorous acid) H3PO4 (Phosphoric acid)  HNO3 (Nitric acid) - HClO (Hypochlorous acid) - CH3 COOH (acetic acid) - H2S2O3 (Thiosulfuric acid)- H2C2O4 (oxalic acid)

Explanation:

To name the ternary acid, they have to obbey the following formula

Hx - Non metal - Oy

where the oxidation state in H and O are +1 y -2 respectively.

When the oxidation state of the central Non metal is odd, the atomicity of H is 1 and in the O is deduced in such a way that the sum of oxidation states is 0.

When the oxidation state of the central No metal is even, the atomicity of H is 2 and in the O is deduced in such a way that the sum of oxidation states is 0.

IV V VI VII  

- - 1 Hypo ……. Ous  

- 3 4 3 … ous  

4 5 6 5 … ic  

  7 Per …… Ous  

The  oxalic acid is an organic compound of two carboxyl groups, so it is also called ethanedioc acid; It is actually known as oxalic by some plants of the genus oxalis. (prefix et (2 carbons))

The acetic acid that comprises a carboxylic group and a methyl group is also an organic compound. It is popularly known as acetic acid but it is actually called methylcarboxylic acid or having two carbons, ethanoic acid.

Answer:

True

Explanation:

Carlos Santana

Carlos Santana is a famous american - mexico musician and even a guitarist  with some unique music categories like , jazz , Latin , salsa . He started off in late late 1960's with the brand name Santana , which consists of a fusion of rock and roll and even Latin American jazz . And then after his career grows and he became famous .

Hence , the statement is correct .

Answer:

10,93% of a carrot is carbohydrate.

Explanation:

In order to solve this you just have to create a rule of three where 64g is the 100% and you want to calculate how much is 7g in percentage:

[tex]\frac{64}{100}= \frac{7}{x}\\ x=\frac{7*100}{64}\\ x=10,9375[/tex]

So there are 10.9375 % carbohydrates in a piece of carrot.

The percent, by mass, of carbohydrate in a medium-sized carrot is approximately 10.9%.

To find the percent, by mass, of carbohydrate in a medium-sized carrot, we can use the following formula:

Percent mass of carbohydrate = (mass of carbohydrate / total mass) × 100

In this case, the mass of carbohydrate is given as 7.0 g and the total mass of the carrot is 64 g. Plugging these values into the formula:

Percent mass of carbohydrate = (7.0 g / 64 g) × 100 = 10.9%

Therefore, approximately 10.9% of the carrot's mass is carbohydrate.

Answer: Option (b) is the correct answer.

Explanation:

A chemical reaction in which heat energy is absorbed by the reactant molecules is known as an endothermic reaction.

Therefore, upon completion of this reaction the container in which reaction is carried out becomes colder.

A chemical reaction in which heat energy is released by the reactant molecules is known as an exothermic reaction.

Therefore, upon completion or during this type of reaction the container in which reaction is carried out becomes hot.

Thus, we can conclude that when the test tube gets colder as the reaction takes place then it means this chemical reaction is endothermic reaction.

Answer:

0.917g/cm^3

Explanation:

Density = Mass/ Volume.

Given,

Mass = 5.5g

Volume of the plastic = L*W*H

        = 1.0 x 2.0 x 3.0 = 6.0cm^3

Density = Mass/volume

            = 5.5g/6.0cm^3

            = 0.9166666666

             = 0.917g/cm^3

Since the density of water is greater than that of the plastic, it means that the plastic will float in water.

Answer:

Sinking of the block in water will not happen.

Explanation:

An object’s (block in this case) density can be found out by dividing the mass of that object from its volume. In the given question the mass of rectangular block is given as 5.5 gram and the sides of the rectangular block is [tex]1, 2 and 3 cm[/tex] so volume will be [tex]6 cm^3[/tex]

[tex]Density = Mass/ Volume[/tex]

Now to calculate the density [tex]5.5/ 6= 0.91g/ml[/tex]

This block will float on water since the block’s density is less than water.

Answer:  Final temperature of the gas will be 330 K.

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

[tex]P\propto T[/tex]     (At constant volume and number of moles)

[tex]{P_1\times T_1}={P_2\times T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas   = 1.00 atm

[tex]P_2[/tex] = final pressure of gas  = 1.13 atm

[tex]T_1[/tex] = initial temperature of gas  = [tex]100^0C=(100+273)K=373K[/tex] K

[tex]T_2[/tex] = final temperature of gas  = ?

[tex]{1.00\times 373}={1.13\times T_2}[/tex]

[tex]T_2=330K[/tex]

Therefore, the final temperature of the gas will be 330 K.

Answer:

(a) 17,178 mg/m3

(b) 11,625 mg/m3

Explanation:

The concentration of CO in mg/m3 can be calculated as

[tex]C (mg/m3) =(P/RT)*MW*C_{ppm}[/tex]

For standard conditions (1 atm and 25°C), P/RT is 0.0409.

Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.

The molecular weigth of CO is 28 g/mol.

(1) For 25°C and 1 atm conditions

[tex]C=(P/RT)*MW*C_{ppm}\\\\C=0.0409*28*15,000=17,178[/tex]

(b) For 200°C and 1.1 atm,

[tex]P/RT=0.0409*(P/P_{std})*(T_{std}/T)\\P/RT=0.0409*(1.1atm/1atm)*(273+15K/273+200K)=0.0277[/tex]

Then the concentration in mg/m3 is

[tex]C=(P/RT)*MW*C_{ppm}\\\\C=0.0277*28*15,000=11,625[/tex]

Answer: Option (a) is the correct answer.

Explanation:

As the given situation shows that water is being added to water. This will liberate heat into the surround as the reaction will be exothermic in nature.

It is known that chemical reactions in which heat is released are known as exothermic reactions.

Hence, when more water is added to this tank the temperature of the system will increase due to release of heat.

Thus, we can conclude that if more water is added to this tank the temperature of the system will increase.

Answer:

Yes, there is a loss of 8350 J of energy in the form of heat

Explanation:

The principle of energy conservation is described mathematically

as the energy conservation equation as follows:

                            ΔK+ΔU=Q+W        

where:

Analyzing each term of the equation:

   [tex]ΔK=\frac{1}{2}mv_{f} ^{2}  - \x]frac{1}{2}mv_{i} ^{2}=\frac{1}{2}*100*15^{2} - \frac{1}{2}*100*0^{2}=11250 J[/tex]

ΔU=[tex]mgh_{f}-mgh_{i}=100*9,8*0-100*9,8*20=-19600[J][/tex]

Q=?

W=0 [J]

Replacing in the main equation:

11250-19600=Q+0

Q= -8350 [J]

So, the answer is YES, there is a loss of 8350 J of  energy in the form of heat.

Answer:

See attached image

Explanation:

An ionic bond is a type of chemical bond in which occurs an electrons transfer, where one of the atoms act as a donor and the other act as the acceptor. Compound with ionic bonds are very stables and strong because of the attraction of the opposite charges. These attractions help ions stay together forming solid nets.

A covalent bond is a type of chemical bond in which the electrons are shared. Unlike the ionic bond, the atoms act at the same time as donors and acceptors sharing their electrons. The covalent bond keeps the atoms together because an electrostatic force, thus this bond is weaker than the ionic bond.

A metallic bond is a force which keeps together metallic atoms. In this type of bond, there is no transfer or sharing of electrons. The atoms are kept together because of an electrostatic force. Since there is no electron exchange involved a metallic bond is weaker than the other two.

In diamond, every carbon atom shared four electrons with other carbon atoms between a covalent bond. These form a regular tetrahedron. On the other side, graphite has a layer structure, in which every layer hold carbon atoms wich shared electrons with other tree atoms. All the layers stay together because of the Van der Waals force. These difference in bonds cause to have different properties, diamond is one of the hardest materials and graphite it is not.

Answer:

First you need to know that the warm air is less dense than the colder air and thus it tends to rise; so snow-caves are constructed in some way that the tunnel entrance is below the main space, and so the warm air can be retained into the cave. In a typical snow-cave, you can reach temperatures over 0°C even when the temperature outside are under zero degrees celsius.

Answer:

Explanation:

The equilibrium that takes place is:

H₂PO₄⁻ ↔ HPO₄⁻² + H⁺    pka= 7.21 (we know this from literature)

To solve this problem we use the Henderson–Hasselbalch (H-H) equation:

pH = pka + [tex]log\frac{[A^{-} ]}{[HA]}[/tex]

In this case [A⁻] is [HPO₄⁻²], [HA] is [H₂PO₄⁻], pH=7.0, and pka = 7.21

If we use put data in the H-H equation, and solve for [HPO₄⁻²], we're left with:

[tex]7.0=7.21+log\frac{[HPO4^{-2} ]}{[H2PO4^{-} ]}\\ -0.21=log\frac{[HPO4^{-2} ]}{[H2PO4^{-} ]}\\\\10^{-0.21} =\frac{[HPO4^{-2} ]}{[H2PO4^{-} ]}\\0.616 * [H2PO4^{-}] = [HPO4^{-2}][/tex]

From the problem, we know that [HPO₄⁻²] + [H₂PO₄⁻] = 0.1 M

We replace the value of [HPO₄⁻²] in this equation:

0.616 * [H₂PO₄⁻] + [H₂PO₄⁻] = 0.1 M

1.616 * [H₂PO₄⁻] = 0.1 M

[H₂PO₄⁻] = 0.0619 M

With the value of [H₂PO₄⁻]  we can calculate [HPO₄⁻²]:

[HPO₄⁻²] + 0.0619 M = 0.1 M

[HPO₄⁻²] = 0.0381 M

With the concentrations, the volume and the molecular weights, we can calculate the masses:

Answer:

The mean velocity is 13 ft/s.

The Reynolds number is 88,583 and it is dimensionless.

Explanation:

We have water flowing in a pipe of 1.05 in diameter.

The density is ρ=62.3 lb/ft and the viscosity is 1.2 cP.

The mean velocity can be calculated as

[tex]u=\frac{Q}{A}=\frac{Q}{\pi*D^2/4}=\frac{35gpm }{3.14*(1.05in)^2/4}\\\\  u=\frac{35}{0.865}*\frac{gal}{min}\frac{1}{in^2}*\frac{231in^3}{1gal}*\frac{1}{60s} \\\\    u=156\,in/s=13\,ft/s[/tex]

The Reynolds number now can be calculated for this flow as

[tex]Re=\frac{\rho*u*D}{\mu}[/tex]

being ρ: density, u: mean velocity of the fluid, D: internal diameter of the pipe and μ the dynamic viscosity.

To simplify the calculation, we can first make all the variables have coherent units.

Viscosity

[tex]\mu=1.2cP=\frac{1.2}{100}\frac{g}{cm*s}*\frac{1lb}{453.6g}*\frac{30.48cm}{1ft}= 0.0008\frac{lb}{ft*s}[/tex]

Diameter

[tex]D=1.05in*(\frac{1ft}{12in} )=0.0875ft[/tex]

Then the Reynolds number is

[tex]Re=\frac{\rho*u*D}{\mu}\\\\Re=62.3\frac{lb}{ft^3}*13\frac{ft}{s} *0.0875ft*\frac{1}{0.0008}*\frac{ft*s}{lb}\\\\Re=88,583[/tex]

The Reynolds number (Re) and mean velocity (u) for water flowing through a pipe can be calculated using the flow rate, pipe dimensions, fluid density, and viscosity. The Reynolds number is a dimensionless quantity that helps predict the flow pattern in the pipe.

The question relates to the calculation of the Reynolds number and the mean velocity (u) for a given flow rate of water through a pipe. First, to find the mean velocity u, the flow rate needs to be converted to cubic feet per second (ft³/s) and then divided by the cross-sectional area of the pipe. The Reynolds number Re is a dimensionless number used to predict flow patterns in different fluid flow situations. It is calculated using the formula Re = ρuD/μ, where ρ is the fluid density, u is the mean velocity, D is the pipe diameter, and μ is the dynamic viscosity of the fluid.

To proceed with the calculation, the given flow rate of 35 gallons per minute (gpm) is converted to cubic feet per second, the pipe's internal diameter is converted to feet, the density of water (62.3 lb/ft³) is used, and the viscosity (1.2 cP) is converted to lb/(ft·s). The mean velocity u is then calculated, and subsequently, the Reynolds number Re is determined.

The units of the Reynolds number are indeed unitless, as demonstrated by the cancellation of units in its definition, ensuring it is a dimensionless quantity.