Answer:
A. Chlorine (Cl2) is the limiting reactant.
B. 6.77g of AlCl3
Explanation:
The balanced equation for the reaction. This is given below:
2Al + 3Cl2 —> 2AlCl3
Next, we shall determine the masses of Al and Cl2 that reacted and the mass of AlCl3 produced from the balanced equation. This is illustrated below:
Molar Mass of Al = 27g/mol
Mass of Al from the balanced equation = 2 x 27 = 54g
Molar Mass of Cl2 = 2 x 35.5 = 71g/mol
Mass of Cl2 from the balanced equation = 3 x 71 = 213g
Molar Mass of AlCl3 = 27 + (3x35.5) = 133.5g/mol
Mass of AlCl3 from the balanced equation = 2 x 133.5 = 267g
Thus, from the balanced equation above,
54g of Al reacted with 213g of Cl2 to produced 267g of AlCl3.
A. Determination of the limiting reactant. This is illustrated below:
From the balanced equation above,
54g of Al reacted with 213g of Cl2.
Therefore, 3.2g of Al will react will react with = (3.2 x 213)/54 = 12.52g of Cl2.
We can see that it will take a higher mass of Cl2 ( i.e 12.52g) than what was given ( i.e 5.4g) to react with 3.2g of Al.
Therefore, Cl2 is the limiting reactant.
B. Determination of the mass of AlCl3 produced from the amount of the limiting reactant available.
This is illustrated below:
The limiting reactant is Cl2 with a mass of 5.4g
From the balanced equation above, 213g of Cl2 reacted to produced 267g of AlCl3.
Therefore, 5.4g of Cl2 will react to produce = (5.4 x 267)/213 = 6.77g of AlCl3.
Therefore, 6.77g of AlCl3 is produced from the amount of the limiting reactant available.
The correct answer is that chloride is the limiting reactant and 13.25 grams of aluminium chloride can be produced from the amount of limiting reactant available.
To determine the limiting reactant and the amount of aluminium chloride that can be produced, we need to use stoichiometry. The balanced chemical equation for the reaction between aluminium (Al) and chloride (Cl) to form aluminium chloride (AlCl3) is:
[tex]\[ 2\text{Al} + 3\text{Cl}_2 \rightarrow 2\text{AlCl}_3 \][/tex]
First, we need to calculate the moles of Al and Cl2 available:
- For aluminium (Al):
[tex]\[ \text{Moles of Al} = \frac{\text{Mass of Al}}{\text{Molar mass of Al}} = \frac{3.2 \text{ g}}{26.98 \text{ g/mol}} \approx 0.12 \text{ mol} \][/tex]
- For chloride (Cl2):
[tex]\[ \text{Moles of Cl}_2 = \frac{\text{Mass of Cl}_2}{\text{Molar mass of Cl}_2} = \frac{5.4 \text{ g}}{35.45 \text{ g/mol}} \approx 0.15 \text{ mol} \][/tex]
Next, we use the stoichiometry of the balanced equation to determine which reactant is limiting:
- The ratio of the moles of Cl2 to Al required by the balanced equation is 3:2.
- For the given moles of Al (0.12 mol), the required moles of Cl2 would be:
[tex]\[ \text{Required moles of Cl}_2 = \frac{3}{2} \times 0.12 \text{ mol} = 0.18 \text{ mol} \][/tex]
Since we only have 0.15 mol of Cl2, chloride is the limiting reactant.
Now, we calculate the amount of AlCl3 that can be produced from the limiting reactant (Cl2):
- From the balanced equation, 3 moles of Cl2 produce 2 moles of AlCl3.
- Therefore, 0.15 moles of Cl2 will produce:
[tex]\[ \text{Moles of AlCl}_3 = \frac{2}{3} \times 0.15 \text{ mol} = 0.1 \text{ mol} \][/tex]
- The molar mass of AlCl3 is:
[tex]\[ \text{Molar mass of AlCl}_3 = 26.98 \text{ g/mol (Al)} + 3 \times 35.45 \text{ g/mol (Cl)} \approx 133.23 \text{ g/mol} \][/tex]
- Finally, the mass of AlCl3 produced is:
[tex]\[ \text{Mass of AlCl}_3 = \text{Moles of AlCl}_3 \times \text{Molar mass of AlCl}_3 \][/tex]
[tex]\[ \text{Mass of AlCl}_3 = 0.1 \text{ mol} \times 133.23 \text{ g/mol} \approx 13.323 \text{ g} \][/tex]
Rounding to the appropriate number of significant figures, we get approximately 13.25 grams of aluminium chloride.
Which of the following best describes how chemical changes differ from physical changes?
A. Physical changes produce no new substances and chemical changes do.
B. Physical changes always involve the formation of a gas while chemical changes may not.
C. Physical changes can occur inside or outside the substance; chemical changes always occur outside.
D. Physical changes involve a change of state; chemical changes involve a change of shape.
Answer:
A is the answer.
Explanation:
Physical changes do not change the substance's composition but just the outside qualities. However, chemical changes change the composition of the substance and it's chemical properties.
Answer:
A
Explanation:
Bonding between two elements of equal electronegativity would be
The given question is incomplete. The complete question is :
Bonding between two elements of equal electronegativity would be
a.100% covalent
b.50% ionic
c. metallic in character
d. primarily ionic
Answer: a. 100% covalent
Explanation:
An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element or the metal and the element which accepts the electrons is known as electronegative element or non metal.
A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals. When the two non metals have equal electronegativities, the bond is called as non polar covalent.
Metallic bonding is the type of chemical bonding occurs between the atoms of a metals.In this type of bonding arises due to electrostatic interaction between the electron cloud of de-localized electrons with positively charges metal ions.
Final answer:
A bond between two elements with equal electronegativity is termed a pure or nonpolar covalent bond, characterized by equal sharing of electrons without charge separation on the molecule.
Explanation:
Bonding between two elements of equal electronegativity results in a pure covalent bond, also known as a nonpolar covalent bond. This type of bond forms when electrons are shared equally between the atoms. Since there is no significant difference in electronegativity, there are no stable regions of net negative or positive charge on the molecule's surface, meaning the bond is nonpolar.
what acid occurs naturally in the body and performs important regulatory functions
Answer: carbonic acid
Chemical formula for sodium chloride
Answer:NaCl
Explanation:
Final answer:
The chemical formula for sodium chloride is NaCl. It is composed of sodium cations and chloride anions in a 1:1 ratio.
Explanation:
The chemical formula for sodium chloride is NaCl. Sodium chloride is an ionic compound composed of sodium cations, Nat, and chloride anions, Cl-, combined in a 1:1 ratio. The formula mass for sodium chloride is calculated as 58.44 amu.
Write the formula for the binary compound iron (III) oxide. (a)FeO , (b)Fe(III)O (c),Fe3O2 ,(d)Fe2O3
Final answer:
The correct formula for iron (III) oxide is [tex]Fe_{2}O_{3}[/tex], where the subscript numbers indicate the ratio of iron to oxygen atoms required to balance the charges of the iron cations and oxide anions in the compound.
Explanation:
The formula for the binary compound iron (III) oxide is [tex]Fe_{2}O_{3}[/tex]. This compound is composed of iron and oxygen, where iron has a +3 oxidation state, known as iron (III). The correct formula is obtained by balancing the charges of the iron cations and oxide anions.
To balance the charges, we need two iron (III) cations (each with a charge of +3) to combine with three oxide anions (each with a charge of -2) to achieve electrical neutrality. The formula reflects the smallest whole number ratio of ions. Therefore, for every two iron ions, there are three oxide ions, giving us [tex]Fe_{2}O_{3}[/tex], which makes answer (d) the correct choice.
How many ml of 2.50 M NaOH solution are required to make a 525 mL of 0.150 M?
Answer:
31.5 mL of a 2.50M NaOH solution
Explanation:
Molarity (M) is an unit of concentration defined as moles of solute (In this case, NaOH), per liter of solvent. That is:
Molarity = moles solute / Liter solvent
If you want to make 525mL (0.525L) of a 0.150M of NaOH, you need:
0.525L × (0.150mol / L) = 0.07875 moles of NaOH
If you want to obtain these moles from a 2.50M NaOH solution:
0.07875mol NaOH × (1L / 2.50M) = 0.0315L = 31.5 mL of a 2.50M NaOH solution
Answer:
The correct answer is 31.5 ml
Explanation:
We have to dilute the more concentrated solution (2.50 M) to obtain a solution with a molarity of 0.150 M. We have the following data:
Initial concentration = Ci = 2.50 M
Final concentration = Cf = 0.150 M
Final volume = Vf = 525 ml
We consider the final and initial states and use the following expression to calculate the initial volume (Vi) in ml:
Ci x Vi = Cf x Vf
Vi= (Cf x Vf)/Ci = (0.150 M X 525 ml)/2.50 M = 31.5 ml
PLEASE HELP
A 700.0 mL gas sample at STP is compressed to a volume of 200.0 mL, and the temperature
is increased to 30.0°C. What is the new pressure of the gas in Pa?
(5 Points)
394 kPa
532 Pa
3.94 x 10^5 Pa
Answer:
P2≈393.609Kpa so I think the answer is 394 kPa
Explanation:
PV=mRT Ideal Gas Law
m and R are constant because they dont change for the problem. That means
PV/T=mR = constant
so P1*V1/T1=P2*V2/T2 and note that the temperatures are in absolute temperatures (Kelvin) because you can't divide by zero.
So P2 = P1*V1*T2/(V2*T1) = 101325 Pa * 700 mL * 303K/(200 mL*273K)
P2 = 393609 Pa
Answer:
3.94 x 10⁵ pascals
Explanation:
combined gas law problem
P₁V₁/T₁ = P₂V₂/T₂ => P₂ = P₁(V₂/V₁)(T₁2T₁)
P₁ = 1 atm at STP P₂ = unknown
V₁ = 700 ml V₂ = 200 ml
T₁ = 0°C = 273K T₂ = 30°C = 303K
P₂ = 1atm(700ml/200ml)(303K/273K) = 3.89 atm
3.89 atm = 3.89 atm(1.01 x 10⁵Pa/atm) = 3.94 x 10⁵ pascals
what is an example of chemical weathering
1. acid rain falls on rocks
2. chemicals from plants on rocks
3. water reacting with minerals on rock
4. All
The pressure of a gas is reduced from 1200 torr to 760 torr as the volume of its container is increased from 0.650 L to 1.1 L. What would the final temperature be in Celsius if the original temperature was 15 C?
Answer:
The final temperature would be 308.7 K or 35.7 °C
Explanation:
Step 1: Data given
The initial pressure = 1200 torr
The pressure is reduced to 760 torr
The initial volume = 0.650 L
The increased volume is 1.1 L
The initial temperature is 15 °C = 288 K
Step 2: Calculate the new temperature
(P1*V1)/T1 = (P2*V2)/T2
⇒with P1 = the initial pressure = 1200 torr
⇒with V1 = the initial volume = 0.650 L
⇒with T1 = initial temperature is 15 °C = 288 K
⇒with P2 = the reduced pressure = 760 torr
⇒with V2 = the increased volume = 1.1 L
⇒with T2 = the final temperature = TO BE DETERMINED
(1200 torr * 0.650 L) / 288 K = (760 torr * 1.1 L) / T2
T2 = (760 * 1.1 * 288) / (1200 * 0.650)
T2 = 308.7 K
The final temperature would be 308.7 K or 35.7 °C
Answer:
-272.99K = 0.0032°C
Explanation:
Applying (P1V1)/T1 = (P2V2)/T2
(1200×0.65)/288 = (760 × 1.1)/T2
Simplify
T2 = 0.0032°C
The gas molecules that make up air are in two rooms. The gas molecules in the kitchen are moving faster than the gas molecules in the bedroom. What does this mean?
A.The kitchen is smaller than the bedroom.
B. the temperature is higher in the bedroom.
C. The temperature is higher in the kitchen.
D.The rooms have two different kinds of air.
Answer:
c.) the temperature is higher in the kitchen
Explanation:
What are three anticipated uses of nitrogen when it is compressed to 2.4 million atmospheres?
Answer:
Explosive, Propellant and Semiconductor
Explanation:
Hbr(aq)+h2o(l)→h3o+(aq)+br−(aq) express your answers as a chemical expressions. enter your answers in order given in the question separated by commas.
This is an incomplete question, here is a complete question.
For each reaction, identify the Bronsted-Lowry acid, the Bronsted-Lowry base, the conjugate acid, and the conjugate base.
[tex]HBr(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+Br^-(aq)[/tex]
Express your answers as a chemical expressions. Enter your answers in order given in the question separated by commas.
Answer : The given equilibrium reaction will be,
[tex]HBr(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+Br^-(aq)[/tex]
Acid Base Conjugate Conjugate
acid base
Explanation :
According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.
Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.
The given equilibrium reaction will be,
[tex]HBr(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+Br^-(aq)[/tex]
Acid Base Conjugate Conjugate
acid base
In this reaction, [tex]HBr[/tex] is an acid that donate a proton or hydrogen to [tex]H_2O[/tex] base and it forms [tex]Br^-[/tex] and [tex]H_3O^+[/tex] are conjugate base and acid respectively.
The formula HBr(aq)+H2O(l)→H3O+(aq)+Br−(aq) represents a Brønsted-Lowry Acid-Base reaction where HBr donates a proton to H2O, forming H3O+ and Br-. This is an acid-base reaction in an aqueous solution.
Explanation:The provided chemical reaction between Hydrobromic acid and water is a characteristic of Brønsted-Lowry Acid-Base reaction. In this reaction, HBr (Hydrobromic acid) donates a proton (H+) to H2O (water), which is a proton acceptor. This process results in the formation of Hydronium Ion (H3O+) and Bromide Ion (Br-).
Expressing the reaction step by step, we start with HBr(aq)+H2O(l), wherein the Hydrobromic acid dissociates into a proton (H+) and a bromide ion (Br-). Similarly, water dissociates into Hydronium Ion (H3O+). Hence, HBr(aq)+H2O(l)→H3O+(aq)+Br−(aq). This is an example of an acid-base reaction in aqueous solutions.
Learn more about Acid-Base Reaction here:https://brainly.com/question/15209937
#SPJ6
PLZ HELP
Which of the following factors increases the reaction rate by increasing particle speed? increasing concentration increasing temperature insreasing surface area
Increasing temperature increases the reaction rate by increasing the speed of particles. Although increasing concentration and increasing surface area can also speed up a reaction, they do so by increasing the probability of collisions, not particle speed.
Explanation:The three factors you have listed, namely, increasing concentration, increasing temperature, and increasing surface area, are indeed factors that can increase the rate of a chemical reaction. However, if we're specifically looking at the factor that increases the reaction rate by increasing the particle speed, then the answer would be increasing temperature.
Increasing the temperature causes particles to move faster, and because they're moving faster, they're more likely to collide with each other and react.
On the other hand, increasing concentration increases the number of reactant particles in a given volume, hence, increasing the chance of collisions. Whereas, increasing the surface area of solid reactants increases the area available for collisions to occur. Both will result in a higher rate of reaction, but not by specifically increasing particle speed.
Learn more about Reaction Rate here:https://brainly.com/question/13440548
#SPJ3
According to Le châtelier’s principle, what happens if heat is added to a system
It depends on whether the system is endothermic or exothermic. If it is endothermic, then adding heat to the system will cause the equilibrium to shift right. Additionally, the k value will increase. Likewise, if the reaction is exothermic, adding heat will cause the equilibrium to shift left. Increasing temperature in an exothermic reaction cause k to decrease.
Le Châtelier's principle explains how a system at equilibrium responds to added heat by shifting to consume the heat, helping predict changes in a chemical equilibrium due to temperature disturbances.
Le Châtelier's principle states that if heat is added to a system at equilibrium, the system will shift to consume the heat. For example, in a liquid-vapor equilibrium, adding heat will cause the system to convert liquid to vapor, increasing the equilibrium vapor pressure.
When a system at equilibrium is disturbed by a change in temperature, it will respond in a way to counteract the disturbance, following Le Châtelier's principle. This principle helps predict how changing conditions like temperature, pressure, or concentration can affect a chemical equilibrium.
Shifting Equilibria: Systems at equilibrium can be disturbed by changes in temperature, concentration, volume, or pressure; Le Châtelier's principle describes how the system will respond to these disturbances to establish a new equilibrium.
The enclosed cabin of a submarine has a volume of 2.4 x 105 liters, a temperature of 312 K, and a pressure of 116 kPa. As people in the cabin breathe, carbon dioxide gas, CO2(g), can build up to unsafe levels. Air in the cabin becomes unsafe to breathe when the mass of CO2(g) in this cabin exceeds 2156 grams. State what happens to the average kinetic energy of the gas molecules if the cabin temperature decreases.
Question:
1 State what happens to the average kinetic energy of the gas molecules if the cabin
temperature decreases.
2 Show a numerical setup for calculating the pressure in the submarine cabin if the cabin
temperature changes to 293 K.
3 Determine the number of moles of CO₂(g) in the submarine cabin at which the air
becomes unsafe to breathe. The gram-formula mass of CO₂ is 44.0 g/mol.
4 Convert the original air pressure in the cabin of the submarine to atmospheres.
Answer:
1) The average kinetic energy of the gas molecules will decrease
2) P₂ = 293 K × 116 kPa/312 K = 108.94 kPa
3) 49 mols
4) 116 kPa = 1.145 atm
Explanation:
(1) When the cabin temperature decreases, the pressure within the cabin will decrease because the average kinetic energy of the gas molecules will decrease. That is the gas particles will have a lower speed.
(2) P₁V₁/T₁ = V₂P₂/T₂
Since the volume is constant we have
116 kPa/312 K = P₂/293 K
P₂ = 293 K × 116 kPa/312 K = 108.94 kPa
(3)
Since CO₂ is 44.0 g/mol, we have
2156/44 = 49 mols
(4) 1 atm = 101325 Pa
Therefore 116 kPa = 1/101325 ×116000 = 1.145 atm
Answer:
1) The average kinetic energy of the gas molecules will decrease
2) P₂ = 293 K × 116 kPa/312 K = 108.94 kPa
3) 49 mols
4) 116 kPa = 1.145 atm
Explanation:
Read the following description of a sample of gas and identify the pressure, volume, temperature and number of particles of the gas. 0.25 mol of neon is at 256 mmHg and at a temperature of 35º C. The volume is 19,000 ml
Answer:
In order: particles, pressure, temperature, and volume.
Explanation:
The mole gives a number of atoms or molecules in a substance. mmHg is millimeters of mercury and that is a type of unit of pressure. Celcius is a unit of temperature so it is the temperature. milliliter is a measurement of volume.
2Na+Cl 2 →2NaCl2, start text, N, a, end text, plus, start text, C, l, end text, start subscript, 2, end subscript, right arrow, 2, start text, N, a, C, l, end text How many grams of \text{NaCl}NaClstart text, N, a, C, l, end text will be produced from 18.0 \text{ g}18.0 g18, point, 0, start text, space, g, end text of \text{Na}Nastart text, N, a, end text and 23.0 \text{ g}23.0 g23, point, 0, start text, space, g, end text of \text{Cl}_2Cl 2 start text, C, l, end text, start subscript, 2, end subscript?
The given reaction is a synthesis reaction which will generate approximately 45.5g of NaCl, following conversion from moles to grams.
Explanation:The reaction in question is a synthesis reaction between sodium (Na) and chlorine (Cl_2) to produce sodium chloride (NaCl). The balanced chemical equation for this reaction is 2Na + Cl_2 → 2NaCl, which tells us that the ratio of moles of sodium to moles of sodium chloride is 1:1. Thus, the moles of sodium is equal to the moles of sodium chloride produced.
To calculate this, you would first need to convert grams of sodium to moles using its molar mass (approximately 23 g/mol). Therefore, 18.0 g of Na equals about 0.78 moles. Since the ratio of Na to NaCl in the reaction is 1:1, this means that the reaction would yield 0.78 moles of NaCl.
To convert this to grams, you multiply by the molar mass of NaCl (approximately 58.44 g/mol). So, approximately 45.5g of NaCl would be produced from 18.0 g of Na and sufficient Cl_2
Learn more about Synthesis Reaction here:https://brainly.com/question/25004705
#SPJ12
The volume of a gas at 155.0 kPa changes from 22.0 L to 10.0 L. What
is the new pressure if the temperature remains constant?
Answer:
V1P1=V2P2
155(22L)=P(10L0
P=341kPg
Explanation:
The following format is copied directly from your notes for how to solve these!!!
1) Analyze problem statement to find knowns and unknowns for each gas variable
V1 = 22.0 L P1 = 155.0 kPa T1 = T2 n = constant (same sample of gas)
V2= 10.0 L P2 = ? kPa T2 = T1 temperature is constant
2) Decide which of the gas laws to use and write its formula.
Only P and V are given, so Boyle's law is used P1V1 = P2V2
3) Change any temperature values to Kelvin (if T is needed) not needed
4) Plug in the knowns - INCLUDING UNITS!!
P1V1 = P2V2
(155.0 kPa) (22.0 L) = P2 (10.0 L)
P2 = (155.0 kPa)(22.0 L) = 341 kPa
(10.0 L)The following format is copied directly from your notes for how to solve these!!!
1) Analyze problem statement to find knowns and unknowns for each gas variable
V1 = 22.0 L P1 = 155.0 kPa T1 = T2 n = constant (same sample of gas)
V2= 10.0 L P2 = ? kPa T2 = T1 temperature is constant
2) Decide which of the gas laws to use and write its formula.
Only P and V are given, so Boyle's law is used P1V1 = P2V2
3) Change any temperature values to Kelvin (if T is needed) not needed
4) Plug in the knowns - INCLUDING UNITS!!
P1V1 = P2V2
(155.0 kPa) (22.0 L) = P2 (10.0 L)
P2 = (155.0 kPa)(22.0 L) = 341 kPa
(10.0 L)
Final answer:
By applying Boyle's law, which states the inverse relationship between volume and pressure at constant temperature, we can calculate the new pressure of a gas when its volume changes. The new pressure is of 341.0 kPa.
Explanation:
The question provided discusses the behavior of gases under different conditions of pressure, volume, and temperature. This is a chemistry concept known as Boyle's law when temperature is constant, or Gay-Lussac's law when pressure is constant, or the combined gas law when neither are constant.
With the information given, we are asked to calculate the new volume or pressure of a gas sample when one of the other variables changes, while holding the other constant.
If the temperature remains constant (Boyle's law), the pressure of a gas is inversely proportional to its volume (P1V1 = P2V2). In the first example, to find the new pressure when the volume decreases from 22.0 L to 10.0 L, while starting at 155.0 kPa, the formula is rearranged to P2 = (P1V1) / V2.
Thus the new pressure is (155.0 kPa × 22.0 L) / 10.0 L, resulting in a new pressure of 341.0 kPa.
What do the SUBSCRIPTS in a compound represent? *
10 points
The sum of the atoms or ions in the compound
The mole ratio of atoms or ions in the compound
The sum of the species in a chemical reaction
The mole ratio of species in a chemical reaction
Answer: The mole ratio of atoms or ions in the compound
Explanation:
Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass. It can be decomposed into simpler constituents using chemical reactions. Example: water with chemicl formula [tex]H_2O[/tex]
The subscript 2 in [tex]H_2O[/tex] represents that the ratio of hydrogen atom is twice that of oxygen atom.
Thus SUBSCRIPTS in a compound represent the mole ratio of atoms or ions in the compound
Phosphorous acid, H3PO3(aq) , is a diprotic oxyacid that is an important compound in industry and agriculture. The p????a values of phosphorous acid are p????a1 p????a2 1.30 6.70 Calculate the pH for each of the given points in the titration of 50.0 mL of 1.5 M H3PO3(aq) with 1.5 M KOH(aq) .
Answer:
Explanation:
find the solution below.
Phosphorous acid (H3PO3), a diprotic oxyacid, has points of pH change that will happen at equimolar points of the titration with a base of equal concentration (KOH). The pH will vary depending upon the pKa values
Explanation:The subject in question pertains to Chemistry, specifically acid-base titrations. Here Phosphorous acid ( H3PO3 ), a diprotic oxyacid , is being titrated with an equal concentration base which is Potassium Hydroxide (KOH). A diprotic acid is an acid that can donate two protons per molecule.
In the given scenario, since the concentrations of the acid and the base are the same, the points of pH changes will happen at the equimolar points of the titration. Thus, the first equivalence point will be when 50.0 mL of KOH is added, and the second equivalence point will be at 100.0 mL of KOH.
How much the pH changes after the addition of each portion of KOH depends on the pKa values. After 50.0 mL of KOH (but before 100.0 mL), the major species is HPO3^2- (pKa2 = 6.7). So, the pH should be approximately equal to this value. After 100.0 mL of KOH, the phosphorous acid has been fully neutralized, so the solution now contains mostly OH-, and the pH should be high, depending on how much extra OH- is in solution.
Learn more about Acid-Base Titration here:https://brainly.com/question/34855887
#SPJ6
The brown solid that formed is zinc copper oxygen iron
Answer: Copper
Explanation:
Just took it on Edgen
Answer:
copper
Explanation:
can someone please answer this I’ll give you 10 points!!
Where on Earth is acid rain a problem? Where is it less of a problem?
No where.. unless there are places that have very heavy rain fall and pollution at the same time like New York (sometimes). A place where it is not really a problem could be like Hawaii, were there is less industrial pollution getting released into the air. I hope this helps!! lol
Answer:
China and india is more of the problem and the part is least of the problem is North Eastern United States, Eastern Europe
Explanation:
place the following in order of increasing ionization energy: I, F, Br, Cl
Answer:
I, Br, Cl, F
Lowest --> Highest
Fluorine has the highest ionization energy due to less electron shielding compared to the other elements in the list.
Compared to a 1.0-liter aqueous solution with a pH of 7.0, a 1.0-liter aqueous solution with a pH of 5.0 contains10 times more hydronium100 times more hydronium10 times more hydroxide100 times more hydroxide
A 1.0-liter aqueous solution with a pH of 5.0 contains 100 times more hydronium ions than a solution with a pH of 7.0, since the pH scale is logarithmic and a change of 1 unit corresponds to a tenfold change in ion concentration.
Explanation:The question concerns the comparison of hydronium ion concentrations in aqueous solutions with different pH levels. To analyze the difference between a pH of 7.0 and a pH of 5.0, we need to understand that the pH scale is logarithmic; a change of 1 unit on the pH scale corresponds to a tenfold change in hydronium ion concentration.
For a solution with a pH of 7.0, which is neutral, the concentration of hydronium ions is 1.0 × 10-7 M. An acidic solution with a pH of 5.0 has a higher concentration of hydronium ions because each unit decrease in the pH value corresponds to a tenfold increase in [H3O+]. So, moving from a pH of 7.0 to a pH of 5.0 (a difference of 2 pH units), the hydronium ion concentration increases by a factor of 10 for each unit decrease in the pH. This means that a pH of 5.0 represents a hydronium ion concentration that is 10 × 10 or 100 times greater than that of a solution with a pH of 7.0.
Therefore, compared to a 1.0-liter aqueous solution with a pH of 7.0, a 1.0-liter aqueous solution with a pH of 5.0 contains 100 times more hydronium ions. Hydroxide ions are not directly mentioned in this comparison, but if they were, their concentration would be 100 times less, as they are inversely related to the concentration of hydronium ions.
The process of photosynthesis converts _____ energy into _____ energy.
A. light; chemical
B. chemical; light
C. mechanical; thermal
D. thermal; mechanical
Which compound is soluble in water PbS BaS Na2S Fe2S3
Answer:
The answer to your question is Na₂S, if you need to choices the other one is BaS
Explanation:
As a general rule, all the compounds that have sulfur, are insoluble in water, but the are some exceptions.
-Molecules with ammonia
-If the molecule has alkali metals is soluble
-If the molecule has Ca⁺², Sr⁺² and Ba⁺² is soluble in water.
From the compounds given, following the rules, the compound that is soluble in is Na₂S and perhaps BaS.
Among PbS, BaS, Na2S, and Fe2S3, Na2S is the compound that is soluble in water, as sodium is a Group I element and its sulfide does not follow the general rule of insolubility for sulfides.
Explanation:The question concerns the solubility of compounds in water, which is a topic in Chemistry. Among the compounds listed (PbS, BaS, Na2S, Fe2S3), Na2S (sodium sulfide) is the one that is soluble in water. This is because Na+ is a Group I element, and as per solubility rules, sulfides are generally insoluble except for those of Group I elements and also calcium, strontium, and barium to a lesser extent. Despite barium being part of the exception, BaS tends to hydrolyze and form Ba(OH)2 and H2S, making it not truly soluble in water for practical purposes. On the other hand, PbS (lead sulfide), Fe2S3 (iron(III) sulfide), and BaS (barium sulfide) are typically insoluble due to their placement on the periodic table as transition metals or heavy metals, which generally form insoluble sulfides.
In which species does nitrogen have the highest oxidation number?
Select one:
a. NH3
b. N2
c. NaNO3
d. NO2-
e. HNO2
Answer:
NaNO3
Explanation:
The species where nitrogen has the highest oxidation number is NaNO3, where nitrogen has an oxidation number of +5.
Explanation:The species where nitrogen has the highest oxidation number is NaNO3. In this compound, the oxidation number of nitrogen is +5. We can determine this by understanding that the oxidation number for oxygen is usually -2, and for sodium it is usually +1. Therefore, to balance the charge in the compound NaNO3(sodium nitrate), nitrogen must have an oxidation state of +5.
Learn more about Oxidation Number here:https://brainly.com/question/29100691
#SPJ6
Why is ice less dense than water?
A. When water freezes, it forms a crystal structure with less volume than liquid water.
B. Ice crystallizes with an open structure, and the gaps that form between the water molecules in ice increase its volume.
C. Water molecules slow their vibrations and move closer together when water freezes.
D. Some water molecules are lost when water freezes.
Answer:
Your answer is number A.
Why is it that answer:
When water freezes, water molecules form a crystalline structure maintained by hydrogen bonding. Solid water, or ice, is less dense than liquid water.
Ice is less dense than water due to the open crystalline structure formed by hydrogen bonds when water freezes, resulting in gaps between molecules and an increased volume.
Ice is less dense than water because of the hydrogen bonds that form when water freezes. At lower temperatures, water molecules slow down sufficiently to allow hydrogen bonds to hold the water molecules in a crystalline lattice. Ice crystallizes with an open structure, creating gaps between the molecules, which increases the volume of ice compared to liquid water. This unique molecular arrangement in ice causes it to have a density of approximately 0.92 g/cm³, compared to fresh water's density of 1.0 g/cm³. The expansion of ice relative to liquid water is critical as it allows ice to float, forming a surface layer that insulates the water below and enables aquatic life to survive during cold seasons.
Calculate the enthalpy of the formation of butane, C4H10, using the balanced chemical equation and the standard value below:
4C(s) + 5H2(g) => C4H10(g)
Standard enthalpy of formation values:
(Delta Triangle)H^0 of C(s)= -393.5kJ/mol
(Delta triangle)H^0f of H2(g)=-285.8 kJ/mol
(Delta triangle)H^0f of C4H10(g)=-2877.6kJ/mol
Answer:
+125.4 KJmol-1
Explanation:
∆H C4H10(g) = -2877.6kJ/mol
∆H C(s)=-393.5kJ/mol
∆H H2(g) = -285.8
∆H reaction= ∆Hproducts - ∆H reactants
∆H reaction= (-2877.6kJ/mol) - [4(-393.5kJ/mol) +5(-285.8)]
∆H reaction= +125.4 KJmol-1