An alfisol is most closely related to ________.

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Answer 1

Transitional environments

Related Questions

A printer is connected to a 1.0 m cable. if the magnetic force is 9.1 × x10-5 n, and the magnetic field is 1.3 × 10-4 t, what is the current in the cable

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The magnetic force on a current-carrying wire due to a magnetic field is given by
[tex]F=ILB[/tex]
where
I is the current
L the wire length
B the magnetic field strength

In our problem, L=1.0 m, [tex]F=9.1 \cdot 10^{-5} N[/tex] and [tex]B=1.3 \cdot 10^{-4}T[/tex], so we can re-arrange the formula to find the current in the wire:
[tex]I= \frac{F}{LB}= \frac{9.1 \cdot 10^{-5} N}{(1.0 m)(1.3 \cdot 10^{-4} T)} =0.7 A [/tex]

you drop a glass on the floor and it shattters chemical or physical change ?

Answers

This describes a physical change. The glass shattering changes its physical shape and appearance only, as it retains its chemical composition.

This is Physical change.

Hope this helps!

If a chromosome on unfolds itself how is transcription enhanced

Answers

Sorry that I'm late the answer is the DNA region is easily accessible

Rebekah finds that a solution of sugar in water has a volume of 1.32 fl. oz. How should she report this amount using the metric system? (1 fl. oz. = 29.6 mL)

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its D i just finished the test

39.1 mL is correct answer

A canister containing air has a volume of 85 cm 3 and a pressure of 1.45 atm when the temperature is 310 k. what is the pressure when the volume is increased to 180 cm 3 and the temperature is reduced to 280 k?

Answers

We can solve the problem by using the ideal gas law, which states:
[tex]pV=nRT[/tex]
where
p is the gas pressure
V is the volume
n is the number of moles
R is the gas constant
T is the absolute temperature

The initial conditions of the gas in the problem are:
[tex]p=1.45 atm =1.47 \cdot 10^5 Pa[/tex]
[tex]V=85 cm^3 = 85 \cdot 10^{-6} m^3[/tex]
[tex]T=310 K[/tex]
So we can use the previous equation to find the number of moles of the gas:
[tex]n= \frac{pV}{RT}= \frac{(1.47 \cdot 10^5 Pa)(85 \cdot 10^{-6} m^3)}{(8.31 J/mol K)(310 K)} =4.9 \cdot 10^{-3} mol [/tex]

The final conditions of the gas are:
[tex]V=180 cm^3 = 180 \cdot 10^{-6} m^3[/tex]
[tex]T=280 K[/tex]
and since the number of moles didn't change, we can find the final pressure by using again the ideal gas law:
[tex]p= \frac{nRT}{V}= \frac{(4.9 \cdot 10^{-3} mol)(8.31 J/mol K)(280 K)}{180 \cdot 10^{-6} m^3}=0.63 \cdot 10^5 Pa [/tex]

Jupiter‘s great red spot is believed to be a

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The Great Red Spot is an anticyclonic (high pressure) storm that rotates around the planet at about 22°.

Cyclonic storm -gradpoint

In a physics laboratory experiment, a coil with 250 turns enclosing an area of 10.5 cm2 is rotated during the time interval 3.10×10−2 s from a position in which its plane is perpendicular to earth's magnetic field to one in which its plane is parallel to the field. the magnitude of earth's magnetic field at the lab location is 5.30×10−5 t .

Answers

I guess the problem is asking for the induced emf in the coil.

Faraday-Neumann-Lenz states that the induced emf in a coil is given by:
[tex]\epsilon = -N \frac{\Delta \Phi}{\Delta t} [/tex]
where
N is the number of turns in the coil
[tex]\Delta \Phi[/tex] is the variation of magnetic flux through the coil
[tex]\Delta t[/tex] is the time interval

The coil is initially perpendicular to the Earth's magnetic field, so the initial flux through it is given by the product between the magnetic field strength and the area of the coil:
[tex]\Phi_i = BA=(5.30 \cdot 10^{-5}T)(10.5 \cdot 10^{-4} m^2)=5.57 \cdot 10^{-8} Wb[/tex]
At the end of the time interval, the coil is parallel to the field, so the final flux is zero:
[tex]\Phi_f = 0[/tex]

Therefore, we can calculate now the induced emf by using the first formula:
[tex]\epsilon = -N \frac{\Delta \Phi}{\Delta t}=- (250) \frac{5.57 \cdot 10^{-8} Wb - 0}{3.10 \cdot 10^{-2} s} = -4.5 \cdot 10^{-4} V[/tex]

Two moles of an ideal gas are compressed in a cylinder at a constant temperature of 80.0 ∘c until the original pressure has tripled. calculate the amount of work done by gas.

Answers

The work done by a gas during an isothermal process is given by:
[tex]W=nRT ln \frac{V_f}{V_i} [/tex] (1)
where
n is the number of moles of the gas
R is the gas constant
T is the absolute temperature of the gas
[tex] \frac{V_f}{V_i} [/tex] is the ratio between the final volume and the initial volume of the gas

We need to calculate this ratio, and we can do it by using the gas pressure. In fact, for an isothermal process, Boyle's law states that the product between pressure and volume of the gas is constant:
[tex] pV=k [/tex]
which can be rewritten as
[tex] p_i V_i= p_f V_f[/tex]
which is equivalent to
[tex] \frac{V_f}{V_i}= \frac{p_i}{p_f} [/tex]
The problem says that the pressure of the gas is tripled, therefore the ratio between final and initial volume is:
[tex] \frac{V_f}{V_i} = \frac{p_i}{3 p_i} = \frac{1}{3} [/tex]

Now we can use eq.(1) to calculate the work done by the gas. The absolute temperature is
[tex]T=80.0^{\circ}C+273 = 353 K[/tex]
The number of moles is n=2, therefore the work done is
[tex]W=nRT ln \frac{V_f}{V_i}=(2 mol)(8.31 J/mol K) (353 K) \ln \frac{1}{3}= -6445 J[/tex]
And the work is negative, because it is done by the environment on the gas (the gas is compressed)

Final answer:

The work done by two moles of an ideal gas compressed isothermally in a cylinder can be calculated using the formula W = nRT ln(V1/V2). The work is generally negative as the gas does work on its surroundings during the process.

Explanation:

When an ideal gas is compressed in a cylinder, the work done by the gas can be calculated using the principles of thermodynamics. Specifically, if the gas is compressed isothermally (at a constant temperature), the work done by the gas during this process can be calculated using the formula W = nRT ln(V1/V2), where n represents the number of moles of gas, R is the universal gas constant, T is the temperature in Kelvin, and V1 and V2 are the initial and final volumes of the gas respectively.

In the scenario presented, we have 2 moles of gas, a temperature of 80.0°C, and the original pressure being tripled during the compression. This tripling of pressure corresponds to reduction in volume to one third. From these values, we can calculate the work done by the gas during compression. However, we do not have specific information about the volumes or pressures, so we cannot calculate a numerical value. In general, though, we can say the work done by the gas during an isothermal process is negative, as it is compressed and does work on its surroundings.

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Discuss five ways human activity has accelerated soil erosion

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Answer:

road erosion, house construction, steep slope cultivation, tourism development, and animal trampling.

Explanation:

What is the resistance of a 1500 w ( 120 v) hair dryer?
b. what is the current in the hair dryer when it is used?

Answers

a) power = IV
From ohms law. I =V/R
So, Power = VV/R

Therefore, R (resistance) = VV ÷ Power

R = (120×120) ÷ 1500
= 9.6 ohs.

b) From ohm's law, V=IR
So, I = V/R
= 120 ÷ 9.6
= 12.5 A

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

(a) The resistance of the hairdryer will be 9.6 ohms.

(b)the current in the hairdryer will be 12.5 A.

When all physical parameters and temperature are constant,

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

This current-voltage connection may be expressed mathematically as,

The Equation of Ohm's Law

V=IR

(a)

The following data are given as

P = 1500 w

v = 120 v

The power generated in the hairdryer

[tex]\rm{P = vI}\\\\I=\frac{P}{v} \\\\I=\frac{1500}{120}\\\\I=12.5 A}[/tex]

To obtained the resistance

[tex]\rm R=\frac{v}{I} \\\\\rm R=\frac{120}{12.5} \\\\R= 9.6 ohm}[/tex]

Hence the resistance of the hairdryer will be 9.6 ohms.

(b)

The Equation of Ohm's Law

V=IR

[tex]\rm I =\frac{V}{R} \\\\\rm I =\frac{120}{9.6}\\\\\ I= 12.5 A[/tex]

Hence the current in the hairdryer will be 12.5 A.

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Picturing the way a volcano erupts to remember how a volcano functions is called a. Visualizing c. Keywording b. Categorizing d. All of these

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the answer is A visual

Making a mental picture of the way a volcano erupts to remember how a volcano functions is called visualization.

What is visualization?

Visualization is the process whereby a person makes or forms a mental picture of a particular situation or occurrence in order to better understand that occurrence.

Picturing the way a volcano erupts to remember how a volcano functions is a process of visualization.

A mental picture of the volcano is made by the individual.

Therefore, Picturing the way a volcano erupts to remember how a volcano functions is called visualization.

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Marie notices that most of her friends have MP3 players that are all made by a certain brand. She wants one, too, but not just any MP3 player. Marie wants to buy the exact same brand that her friends have. She thinks this is the way to fit in. Which term describes why Marie only wants a certain brand of MP3 player

Answers

the term is conformity

The measurement of an exoplanet's radius is measured in units compared to ________.

the Sun's radius
planet Earth's radius
planet Jupiter's radius
the moon's radius

Answers

the eaths radius is the correct answer, if you need proof look at nasa's website

Planet Earth's radius

A proton and an electron are held in place on the x axis. The proton is at x = -d, while the electron is at x = +d. They are released simultaneously, and the only force that affects their motions is the electrostatic force of attraction that applies to the other. Which particle reaches the origin first? Give your reasoning.

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The protons and electrons are held in place on the x axis.
The proton is at x = -d and the electron is at x = +d. They are released at the same time and the only force that affects movement is the electrostatic force that is applied on both subatomic particles. According to Newton's third law, the force Fpe exerted on protons by the electron is opposite in magnitude and direction to the force Fep exerted on the electron by the proton. That is, Fpe = - Fep. According to Newton's second law, this equation can be written as
Mp * ap = -Me * ae
where Mp and Me are the masses, and ap and ae are the accelerations of the proton and the electron, respectively. Since the mass of the electron is much smaller than the mass of the proton, in order for the equation above to hold, the acceleration of the electron at that moment must be considerably larger than the acceleration of the proton at that moment. Since electrons have much greater acceleration than protons, they achieve a faster rate than protons and therefore first reach the origin.

Final answer:

The electron will reach the origin first due to its greater acceleration, which is a result of its much smaller mass compared to the proton, despite the forces on both particles being equal in magnitude.

Explanation:

The question is asking which particle, a proton at x = -d or an electron at x = +d that are released simultaneously under the influence of electrostatic force, will reach the origin first. According to Newton's second law, force equals mass times acceleration (F = ma). Because the proton and the electron have equal and opposite charges, the magnitude of the force acting on them due to their electrical interaction will be the same. However, the mass of the proton is much greater than that of the electron, resulting in much smaller acceleration for the proton. Consequently, the electron, given its smaller mass and therefore larger acceleration, will reach the origin first.

A battery charger delivers a current of 5.8 a for 2.9 h to a 12-v storage battery. what is the total charge that passes through the battery in that time

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The current is defined as the amount of charge Q that flows through a given point of a circuit in a given time [tex]\Delta t[/tex]:
[tex]I= \frac{Q}{\Delta t}[/tex]

In our problem, the time interval considered is
[tex]\Delta t= 2.9 h = 10440 s[/tex]
while the current is
[tex]I=5.8 A[/tex]
Therefore, if we re-arrange the previous equation, we can calculate the amount of charge that passes through the battery in that time:
[tex]Q=I \Delta t=(5.8 A)(10440 s)=6.05 \cdot 10^4 C[/tex]

A camera with a 50.0-mm focal length lens is being used to photograph a person standing 3.00 m away. if the film is 36.0 mm high, what fraction of a 1.75-m-tall person will fit on it?

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f = 50.0mm = 5.0cm
d₀ = 3.00m = 3.00cm
1/f = 1/d₀ + 1/di
= 1/di = 1/5 - 1/325 = 5.078 cm
m= hi/h₀ = di/d₀ = 5.078/300
hi/h₀ = 169.29
hi = 1692.9 cm

Determine the absolute pressure on the bottom of a swimming pool 30.0 m by 9.0 m whose uniform depth is 1.9 m . express your answer using two significant figures.

Answers

The relative pressure at the bottom of a column of fluid is given by
[tex]p_r = \rho g h[/tex]
where
[tex]\rho[/tex] is the fluid density
g is the gravitational acceleration
h is the height of the column of fluid

At the bottom of the swimming pool, h=1.9 m, and the water density is
[tex]\rho = 1000 kg/m^3[/tex], therefore the relative pressure is
[tex]p_r = (1000 kg/m^3)(9.81 m/s^2)(1.9 m)=1.86 \cdot 10^4 Pa[/tex]

To find the absolute pressure, we must add to this the atmospheric pressure, [tex]p_a[/tex]:
[tex]p= p_r + p_a= 1.86 \cdot 10^4 Pa + 1.01 \cdot 10^5 Pa =1.2 \cdot 10^5 Pa[/tex]

What potential increase vac must an electron be accelerated through if the most energetic photon it can emit will scatter off of a stationary electron at an angle ϕ=60∘ with wavelength 8.4×10−12m?express your answer in kilovolts to two significant digits?

Answers

Referring to Compton scattering
Δλ = h/m₀c (I- cos Ф)
λ' =λ = (0,0242×10⁻¹⁰) (1- cos 60°)
λ= λ' -(0.0242 × 10⁻¹⁰) (1- cos 60°)

7.19 ˣ 10⁻¹²m

The increased potential is given by
Vₐc = hc/eλ = 6.625 × 10 ⁻³⁴ J,s) ( 3× 10⁸ m/s ( 1.6 ˣ 10 ⁻¹⁰C)
(7.19 ˣ 10⁻¹²m)

173kV.

A steam turbine operates at a boiler temperature of 450 k and an exhaust temperature of 300 k. what is the maximum theoretical efficiency of this system?

Answers

The maximum theoretical efficiency of the system is the one corresponding to the efficiency of a Carnot cycle operating between the same temperatures of the system:
[tex]\eta=1- \frac{T_c}{T_h} [/tex]
where [tex]T_c[/tex] and [tex]T_h[/tex] are the cold and hot temperatures, respectively.
In our problem, [tex]T_c=300 K[/tex] and [tex]T_h=450 K[/tex], therefore the maximum theoretical efficiency is
[tex]\eta=1- \frac{300 K}{450 K}=0.33 [/tex]
So, 33%.

Final answer:

The maximum theoretical efficiency of a steam turbine operating at a boiler temperature of 450 K and an exhaust temperature of 300 K, as calculated by the Carnot efficiency, is approximately 33%.

Explanation:

The efficiency of a heat engine like a steam turbine can be evaluated using the Carnot efficiency formula. The Carnot efficiency formula is 1 - Tc/Th where Tc is the cold reservoir temperature (exhaust temperature) and Th is the hot reservoir temperature (boiler temperature). Given in the problem, Tc=300K and Th=450K:

Efficiency = 1 - Tc/Th

= 1 - 300 K / 450 K = 1 - 0.67 approximately

So, the maximum theoretical efficiency of the steam turbine would be about 33% according to the Carnot efficiency.

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Which step in an investigation of arson helps insurance claims the most?

Answers

The step in an investigation of arson that help the insurance claims the most is the samples of ignition sources or the processing of evidence at the scene. The people with the insurance claims are careful in gathering investigation data for they will used it as a basis for their claim.

Answer:

Since it is for insurance purposes, inventory would be required.

Explanation: inventory is needed to file a claim. Also, I took the test and got it correct ;)

If a muon is traveling at 70% of the speed of light, how long does it take to decay in the observer's rest frame (i.e., what is the observed lifetime τμ of the muon)? express your answer in microseconds to two significant figures.

Answers

The muon lifetime in the muon reference frame is
[tex]\tau_0 = 2.2 \mu s[/tex]

In the observer's rest frame, the muon lifetime is instead given by
[tex]\tau = \gamma \tau_0[/tex]
where
[tex]\gamma = \frac{1}{ \sqrt{1- \frac{v^2}{c^2} } } [/tex] is the relativistic factor, with v being the muon speed and c the speed of light.

Since the muon is traveling at 70 % of the speed of light,
[tex]v=0.70 c[/tex]
and the relativistic factor is
[tex]\gamma = \frac{1}{ \sqrt{1- \frac{(0.70 c)^2}{c^2} } }=1.4 [/tex]

Therefore, the muon lifetime in the observer's rest frame is
[tex]\tau = \gamma \tau_0 = (1.4)(2.2 \mu s)=3.1 \mu s[/tex]

Answer:

Observed lifetime [tex]= 3.0\mu s[/tex]

Explanation:

The lifetime of muon in the muon’s reference frame.

[tex]t^{_{0}}=2.2\mu s[/tex]

The lifetime of muon in observer’s rest frame.

[tex]t=\gamma t_{0}[/tex]

Here the

[tex]\gamma =\dfrac{1}{\sqrt{1-\frac{V^2}{C^2}}}[/tex]

[tex]\gamma[/tex] is the relativistic factor.

V = Speed of muon

C = Speed of light

The muon’s speed of 70% of light speed.

Hence,

[tex]V=\dfrac{70}{100}C[/tex]

V = 0.7C

[tex]=\dfrac{1}{\sqrt{1-\frac{(0.7C)^2}{C^2}}}[/tex]

[tex]=\dfrac{1}{\sqrt{1-0.49}}[/tex]

[tex]=\dfrac{1}{\sqrt{0.51}}[/tex]

[tex]=\dfrac{1}{0.71}[/tex]

= 1.4

The lifetime of muon in observer’s rest frame.

[tex]t=\gamma t_{0}[/tex]

[tex]t=1.4\times 2.2\mu s[/tex]

[tex]t=3.0\mu s[/tex]

Further explanation:

The muon is a lepton which decays to form an electron or positron. The lifetime of the muon is 2.20 microseconds. The muon lifetime in the muon reference frame is .

But the observed lifetime [tex]= \gamma =\frac{1}{\sqrt{1-\frac{V^2}{C^2}}}[/tex]

Learn more:

1. Speed of muon https://brainly.com/question/10048817 (answer by skyluke89)

2. Muon https://brainly.com/question/13198853 answer by skyluke89 )

Keywords: Muon, Speed of light, life time.

Earth is closest to the sun at what part of its orbit?

Answers

Earth is closest to the sun at the point in its orbit called the "perihelion" .

Our planet passes that point in its orbit sometime during the first few days
of January.

Here the dates of perihelion passage in 2018 and the next few years.
The times are Central Daylight Time (Chicago & Dallas time).

2018 January 2, 2018 11:34 pm
2019 January 2, 2019 11:19 pm
2020 January 5, 2020 1:47 am
2021 January 2, 2021 7:50 am
2022 January 4, 2022 12:52 am

These are the moments when the Earth will be
CLOSEST to the sun in its orbit.

Thermodynamics is the study of the relationship between thermal energy and mass. other forms of energy. types of engines. temperature.

Answers

Thermodynamics is a branch of physics concerned with heat and temperature and their relation to other forms of energy and work. The behavior of these quantities is governed by the four laws of thermodynamics, irrespective of the composition or specific properties of the material or system in question. The laws of thermodynamics are explained in terms of microscopic constituents by statistical mechanics. Thermodynamics applies to a wide variety of topics in science and engineering, especially physical chemistry, chemical engineering and mechanical engineering.

Other forms of energy.

Apply: what will be the total resistance and current in a parallel circuit with a 15-volt battery and three 10-ohm resistors? test your answers with the gizmo.

Answers

1) Total resistance

the total resistance of a circuit with n resistors in parallel is given by
[tex] \frac{1}{R_{eq}} = \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n} [/tex]
where [tex]R_i[/tex] are the single resistances.

In our circuit, we have 3 resistors of [tex]10.0 \Omega[/tex] each, so the total resistance of the circuit is given by
[tex] \frac{1}{R_{eq}}= \frac{1}{10 \Omega}+ \frac{1}{10 \Omega}+ \frac{1}{10 \Omega}= \frac{3}{10 \Omega} [/tex]
which means a total resistance of
[tex]R_{Eq} = \frac{10 \Omega}{3}=3.33 \Omega [/tex]

2) Current in the circuit

The current in the circuit can be found by using Ohm's law:
[tex]I= \frac{V}{R_{Eq}} [/tex]
where V is the voltage of the battery and Req is the total resistance we found before. By using V=15 V, we find
[tex]I= \frac{15 V}{3.33 \Omega}=4.5 A [/tex]

The total resistance in the parallel circuit with three 10-ohm resistors and a 15-volt battery is approximately 3.33 ohms. The total current through the circuit is approximately 4.50 amps.

To calculate the total resistance in a parallel circuit with three resistors of 10 ohms each, we use the formula for parallel resistance:

[tex]\frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}[/tex]

Substituting the values:

1/Rtotal = 1/10 + 1/10 + 1/10

1/Rtotal = 3/10

Therefore, Rtotal = 10/3 = 3.33 ohms

Next, we calculate the total current using Ohm's Law:

I = V/Rtotal

Given the battery voltage is 15 volts:

I = 15/3.33 ≈ 4.50 amps

The total resistance in the parallel circuit with three 10-ohm resistors and a 15-volt battery is approximately 3.33 ohms. The total current through the circuit is approximately 4.50 amps.

Even at such low fractions of the speed of light these stars are moving quite quickly (thousands of kilometers a second) compared to the standard velocity dispersion in the milky way galaxy (which is around 300km/s). suppose the star was actually moving toward the earth at a more reasonable 300km/s. what wavelength λ would the 656.46-nm line move to? use 299,792km/s for the speed of light. express your answer in nanometers to five significant figures.

Answers

According to Doppler Effect, an observer at rest will perceive a shift in the wavelength or frequency of the radiation emitted by a source in movement.This shift is given by the formula:
[tex] \frac{ \lambda - \lambda_{0} }{ \lambda_{0} } = \frac{-v}{c} [/tex]

where:
[tex] \lambda[/tex] = observed wavelength
[tex] \lambda_{0}[/tex] = wavelength at rest
v = speed of source (positive if towards the observer, negative if away from the observer)
c = speed of light

Therefore, we can solve for the observed wavelength:
[tex]\lambda = \lambda_{0} (\frac{-v}{c}) + \lambda_{0} \\ \lambda = \lambda_{0} (1 - \frac{v}{c})[/tex]

Substituting the given data:
[tex]\lambda = 656.46 (1 - \frac{300}{299792})[/tex]
= 655.80 nm

Hence, the observed wavelength of the line would be 655.80 nm. Note that this value is smaller than the one at rest, which means that we have a blue-shift, as expected for an approaching source.

The hydrogen line at 656.46 nm shifts to about 655.80 nm if a star is traveling 300 km/s toward Earth.

Using the Doppler Effect to Determine the Wavelength Shift

First, note the speed of light: c = 299,792 km/s.Original wavelength of the hydrogen line: λ₀ = 656.46 nm.Star's velocity towards Earth: v = -300 km/s (negative because the star is approaching).

Use the Doppler shift formula for wavelengths:

[tex]\[\lambda = \lambda_0 \sqrt{\frac{c - v}{c + v}}\][/tex]

Plugging in the values:

[tex]\[\lambda = 656.46 \, \text{nm} \sqrt{\frac{299,792 - 300}{299,792 + 300}}\][/tex]

Calculate the ratio:

Ratio = √(299,492 / 300,092) ≈ √(0.998)

Evaluate the square root:

[tex]\[\frac{299,492}{300,092} \approx 0.998\][/tex][tex]\[\sqrt{0.998} \approx 0.999\][/tex]

Compute the shifted wavelength:

[tex]\[\lambda \approx 656.46 \, \text{nm} \times 0.999\][/tex] ≈ 655.80 nm

The 656.46-nm line would shift to approximately 655.80 nm if the star were moving towards Earth at 300 km/s.

Complete question:

Suppose that you'd like to find out if a distant star is moving relative to the earth. The star is much too far away to detect any change in its brightness as it moves toward or away from the earth. Instead we can use the Doppler effect to determine its relative speed. For this problem we are going to look at the spectral lines from hydrogen, specifically the one with a wavelength of 656.46 nm. Even at such low fractions of the speed of light these stars are moving quite quickly (thousands of kilometers a second) compared to the standard velocity dispersion in the Milky Way galaxy (which is around 300 km/s). Suppose the star was actually moving toward the earth at a more reasonable 300 km/s. What wavelength I would the 656.46-nm line move to? Use 299, 792 km/s for the speed of light. Express your answer in nanometers to five significant figures.

Which forces tend to slow down an object

Answers

The answer is "friction and air resistance" gravity does some of the work by keeping the object from floating away, but friction and air resistance does the biggest part. Friction is how rough the ground it meaning on tile, dirt, grass, etc... that would slow down the object and air resistance is the gravity pushing on the object also making it stop.

Hope this helps!

1) A substance has a half life of 20 years. what percentage would be left after 40 years?

2)After 4 half lifes of uranium, 10 grams of the uranium remains. how much uranium did you start with?

Answers

1) The half-life is the time required for a substance to reduce to half its initial value. In formulas:
[tex] \frac{m(t)}{m_0} = ( \frac{1}{2} )^{t/t_{1/2}}[/tex] (1)
where
m(t) is the amount of substance left at time t
m0 is the initial mass
[tex]t_{1/2}[/tex] is the half-life

In this problem, the half-life of the substance is 20 years:
[tex]t_{1/2} = 20 y[/tex]
therefore, the fraction of sample left after t=40 years will be
[tex] \frac{m(t)}{m_0}=( \frac{1}{2})^ \frac{40 y}{20 y} = ( \frac{1}{2})^2 = \frac{1}{4} [/tex]

So, only 1/4 of the original sample will be left, which corresponds to 25%.

2) We can use again formula (1), by re-arranging it:
[tex]m_0 = \frac{m(t)} {( \frac{1}{2} )^{ \frac{t}{t_{1/2} }}}[/tex]
If we use m(t)=10 g (mass of uranium left at time t), and [tex]t=4 t_{1/2}[/tex] (the time is equal to 4 half lifes), we get
[tex]m_0 = \frac{10 g}{ (\frac{1}{2})^4 } =16 \cdot 10 g = 160 g[/tex]
So, the initial sample of uranium was 160 g.

A ball is thrown vertically upward with a speed of 1.53 m/s from a point 4.21 m above the ground. calculate the time in which the ball will reach the ground.

Answers

The ball moves by uniformly accelerated motion, and its vertical position at time t is described by the following law
[tex]y(t) = h+v_0t - \frac{1}{2}gt^2 [/tex]
where
[tex]h=4.21 m[/tex] is the initial height from which the ball starts its motion
[tex]v_0=1.53 m/s[/tex] is the initial velocity of the ball
[tex]g=9.81 m/s^2[/tex] is the gravitational acceleration

The time in which the ball reaches the ground is the time t at which the vertical position y(t) becomes zero:
[tex]0= h + v_0 t - \frac{1}{2}gt^2[/tex]
Which means
[tex]0=4.21 + 1.53 t - 4.9 t^2 [/tex]

whose solutions are:
[tex]t=-0.78 s[/tex]
[tex]t=1.10 s[/tex]
Neglecting the negative solution (since it has no physical meaning), we can say that the ball reaches the ground after 1.10 s.

The time in which the ball will reach the ground is about 1.10 s

Further explanation

Acceleration is rate of change of velocity.

[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]

[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

This problem is about Kinematics.

We will solve it in the following way

Given:

initial speed = u = 1.53 m/s

initial height = H = 4.21 m

Unknown:

time taken = t = ?

Solution:

[tex]H = ut - \frac{1}{2}gt^2[/tex]

[tex]-4.21 = 1.53t - \frac{1}{2}(9.8)t^2[/tex]

[tex]-4.21 = 1.53t - 4.9t^2[/tex]

[tex]4.9t^2 - 1.53t - 4.21 = 0[/tex]

We will solve the above equation using the following quadratic function formula:

[tex]t = \frac{1.53 + \sqrt{1.53^2 - 4(4.9)(-4.21)}}{2(4.9)}[/tex]

[tex]t \approx 1.10 ~ s[/tex]

Learn moreVelocity of Runner : https://brainly.com/question/3813437Kinetic Energy : https://brainly.com/question/692781Acceleration : https://brainly.com/question/2283922The Speed of Car : https://brainly.com/question/568302

Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

Calculate the weight ofa 58 kg astronaut on the moon where g=1.6 m/s2

Answers

weight = (mass) x (gravity)

On the moon, gravity = 1.6 m/s² .

The astronaut, with his mass of 58 kg, weighs

(58 kg) x (1.6 m/s²) = 92.8 newtons (about 21.1 pounds)

On the Earth, gravity = 9.8 m/s² .

The astronaut, with his mass of 58 kg, weighs

(58 kg) x (9.8 m/s²) = 568.4 newtons (about 127.9 pounds)

The electric current running through the wire coil in an electric motor exerts force directly onto A) the battery. B) an aluminum axle. C) a powerful magnet. D) a rubber insulator.

Answers

C)a powerful magnet.

Answer:

C) a powerful magnet

Explanation:

The electric current running through the wire coil in an electric motor exerts force directly onto A) the battery. B) an aluminum axle. C) a powerful magnet. D) a rubber insulator.

when current is pass to the coil, an electromagnetic force field is produced. The electromagnetic force field produced then have an impact on the magnet which drives the shaft to move

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