An analytical chemist is titrating of a solution of hydrazoic acid with a solution of . The of hydrazoic acid is . Calculate the pH of the acid solution after the chemist has added of the solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of solution added. Round your answer to decimal places.

Answer:

instantaneous rate at 40 s= 0.0035 M /s.

Explanation:

Instantaneous rate at 40 s is the slope of the line (tangent to the curve)

=  Δp/Δt

From, the straight orange line

ΔP = (0.48 - 0.16) M.

Δt = (92 -0) s

Now, instantaneous rate at 40 s

=  0.48 - 0.16/92 - 0

instantaneous rate at 40 s= 0.0035 M /s.

Answer:

0.0035

Explanation:

check the picture

Answer:

Explanation:

given that

mass of Ba(NO3)2 = 1.40g

mass of NH2SO3H = 2.50 g

1)to determine the mole of  Ba(NO3)2

2) to determine the mass of all three product formed in the reaction

reaction

Ba(NO3)2 + 2NH2SO3H → Ba(NH2SO3)2 + 2HNO3

Solution

we calculate the molar mass of each species by using their atomic masses

BA = 137.33g/mol

N = 14g/mol

O= 16g/mol

H = 1g/mol

S = 32g/mol

calculation

Ba(NO3)2 = Ba + 2N + 6O

= 137.33 + 2X 14 + 6 X 16

= 261.33g/mol

NH2SO3H = N + 3H + S+ 3O

=14 + 3X1 + 32 + 3X 16

= 97g/mol

Ba(NH2SO3)2 = Ba + 2N + 4H +2S +6O

= 137.33 + 2 X 14 + 4 X1 + 2X32 + 6 X 16

= 329.33g/mol

HNO3 = H + n + 3O

= 1 + 14 + 3 X 16

= 63g/mol

The distraction during Kinetic Trial 2 will not affect the slope of the log (rate) vs log [I-]0. The relationship between the log of the rate and the log of the initial concentration of I- is determined by the reaction kinetics and is not influenced by external factors like distractions.

The distraction that Alicia experienced when the color change occurred during Kinetic Trial 2 will not affect the slope of the log (rate) vs log [I-]0.

This is because the distraction only affected the timing of the color change, not the actual reaction rate.

The relationship between the log of the rate and the log of the initial concentration of I- is determined by the reaction kinetics and is not influenced by external factors like distractions.

This question relates to Boyle's Law from Physics, which deals with the inverse relationship of gas pressure and volume. However, without the initial volume and pressure of the balloon, we can't calculate the new volume.

The subject matter pertains to the concept of Boyle's Law from Physics, specifically gas laws. It appears that this question is about a balloon that is released into the air and reaches an altitude where the atmospheric pressure and temperature are known. The student is required to calculate the new volume of the balloon. Boyle's Law states that the pressure and volume of a gas have an inverse relationship when temperature is held constant. In this case, as the balloon rises and atmospheric pressure drops, its volume should increase. However, we cannot proceed without necessary data such as the initial volume and pressure of the balloon.

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Answer:

Explanationis the long-distance transportation of a liquid or gas through a system of pipes—a pipeline—typically to a market area for consumption. The latest data from 2014 gives a total of slightly less than 2,175,000 miles (3,500,000 km) of pipeline in 120 countries of the world.[1] The United States had 65%, Russia had 8%, and Canada had 3%, thus 75% of all pipeline were in these three countries.[1]

Pipeline and Gas Journal's worldwide survey figures indicate that 118,623 miles (190,905 km) of pipelines are planned and under construction. Of these, 88,976 miles (143,193 km) represent projects in the planning and design phase; 29,647 miles (47,712 km) reflect pipelines in various stages of construction. Liquids and gases are transported in pipelines and any chemically stable substance can be sent through a pipeline.[2] Pipelines exist for the transport of crude and refined petroleum, fuels – such as oil, natural gas and biofuels – and other fluids including sewage, slurry, water, beer, hot water or steam for shorter distances. Pipelines are useful for transporting water for drinking or irrigation over long distances when it needs to move over hills, or where canals or channels are poor choices due to considerations of evaporation, pollution, or environmental impact.:

Answer: 2Mg (s) + O2 (g) ----> 2MgO (s)

Explanation:

Lets write the equation of the reaction.

Mg(s) + O2 (g) ----> MgO (s)

Counting the number of atoms for each element we have:

Left hand side: Mg =1 O = 2

Right hand side : Mg = 1, O =2

To balance this equation input "2" as coefficient for "MgO" on the right hand side and "2", as coefficient for "Mg" on the left hand side of the equation. Hence our balanced equation will be

2Mg (s) + O2 (g) -----> 2MgO (s)

Final answer:

The balanced chemical equation for the combination reaction between magnesium metal and gaseous oxygen to form magnesium oxide is: 2Mg (s) + O₂(g) → 2MgO (s). This reaction follows the conservation of mass.

Explanation:

The reaction between magnesium metal and gaseous oxygen is a combination reaction in which magnesium is oxidized. When magnesium (Mg) combines with oxygen (O₂), it forms magnesium oxide (MgO). The equation representing this exothermic reaction is written as:

2Mg (s) + O₂(g) → 2MgO (s)

This reaction adheres to the law of conservation of mass, meaning the total mass of the reactants equals the total mass of the products. During the reaction, magnesium atoms lose electrons (are oxidized) and the oxygen molecule gains electrons.

Answer:

The answers that represent a decrease in entropy are:

-CO2 gas is dissolved in water to make a carbonated beverage

-NO2(g) → N2O4(g)

Explanation:

Since in carbonated drinks, carbon dioxide is in its liquid form, since a pressure is applied to said gas, in this way, when carbon dioxide dissolves in a liquid, its entropy decreases, thus producing a negative change in entropy (the entropy of a gas is higher than the entropy of a liquid).

The number of gaseous reagents is equal to 1-2 = -1. Since it is negative, therefore, entropy is also negative.

Answer:

2.08moles

Explanation:

Given parameters:

Volume of solution = 800mL   = 0.8L

Molarity  = 2.6M

Unknown:

Number of moles of sugar in the solution = ?

Solution:

We need to understand the relationship between number of moles, volume and molarity of a solution.

The molarity of a solution is the number of moles of solute of a substance dissolved in a given solvent.

         Molarity  = [tex]\frac{number of moles }{volume}[/tex]

   Number of moles of solute  = molarity x volume of solution

Now input the parameters and solve;

            Number of mole of solute  = 2.6 x 0.8  = 2.08moles

The number of moles of sugar is 2.08moles

Answer: Please see answer below

Explanation:

Mecury vapor lamp is better to use than Sodium vapor light, this is because  because

---The Filaments of the lamp in sodium  emit fast moving electrons, which causes valence electrons of the sodium atoms to excite to higher energy levels which when electrons after being excited, relax by emitting yellow light which concentrates on the the  monochromatic bright yellow part of the visible spectrum which is about  580-590 or about (589nm) which will fall incident on the calibrations making it difficult to see

While

In Mercury vapor lamp, The emitted  electrons from the filaments, after having been excited  by high voltage, hit the mercury atoms but the excited electrons of mercury atoms relax and emits an  ultraviolet  uv invisible lights falling on the mecury vapour lamp to produce white light  covering  a wide range of  (380-780 nm) which is visible that is why it is used for calibrations purposes in  lightening applications.

Answer:

10.1 g of FeCl₃ are formed by the reaction

Explanation:

First step is to determine the reaction where the reactants are Fe₂O₃ and HCl  in order to produce FeCl₃ and H₂O.

Equation is: Fe₂O₃ + 6HCl → 2FeCl₃ + 3H₂O

We assume the acid is in excess, so the limiting reagent will be the oxide.

Let's work with mass:

1 mol of Fe₂O₃ is 159.7 g

2 mol of FeCl₃ is 162.2 g

So now we propose a rule of three:

159.7 g of oxide can produce 162.2 grams of chloride

Then, 10 g of oxide will produce (10 . 162.2) / 159.7 = 10.1 g of FeCl₃

Answer:

20.3 grams of FeCl3 will be formed

Explanation:

Step 1: Data given

iron(III) oxide = Fe2O3

hydrochloric acid = HCl

iron (III) chloride = FeCl3

water = H2O

Mass of Fe2O3 = 10.0 grams

Molar mass Fe2O3 = 159.69 g/mol

Step 2: The balanced equation

Fe2O3 +6HCl → 2FeCl3 + 3H2O

Step 3: Calculate moles Fe2O3

Moles Fe2O3 = mass Fe2O3 / molar mass Fe2O3

Moles Fe2O3 = 10.0 grams/ 159.69 g/mol

Moles Fe2O3 = 0.0626 moles

Step 4: Calculate moles of FeCl3

For 1 mol Fe2O3 we need 6 moles HCl to produce 2 moles FeCl3 and 3 moles H2O

For 0.0626 moles Fe2O3 we'll have 2*0.0626 = 0.1252 moles FeCl3

Step 5: Calculate mass FeCl3

Mass FeCl3 = moles FeCl3 * molar mass FeCl3

Mass FeCl3 = 0.1252 moles * 162.2 g/mol

Mass FeCl3 = 20.3 grams

20.3 grams of FeCl3 will be formed

Answer : The half-life of the reaction in seconds is, 244

Explanation :

The expression used for zero order reaction is:

[tex]t_{1/2}=\frac{[A_o]}{2k}[/tex]

where,

[tex]t_{1/2}[/tex] = half-life of the reaction = ?

[tex][A_o][/tex] = initial concentration = 5.90 M

k = rate constant = 0.725 M/min

Now put all the given values in the above formula, we get:

[tex]t_{1/2}=\frac{5.90}{2\times 0.725}[/tex]

[tex]t_{1/2}=4.069min=244.14s\approx 244s[/tex]

conversion used : (1 min = 60 s)

Thus, the half-life of the reaction in seconds is, 244

Answer:

14 H⁺ + Cr₂O₇²⁻ + 6Cl⁻ → 3Cl₂ + 2Cr³⁺ + 7H₂O

The coefficient that will be used for Cl₂ in this reaction is 3

Explanation:

We use the method of electron-ion to the balance.

We assume that the redox reaction is happening at acidic medium.

Cr₂O₇²⁻ + Cl⁻ → Cl₂ + Cr³⁺

Chloride is raising the oxidation state from -1 in the chloride, to 0 in the chloride dyatomic. This is the half reaction of oxidation

2Cl⁻ → Cl₂ + 2e⁻         Oxidation

In the dichromate anion, chromium acts with +6 in oxidation state, and we have 2 Cr, so the global charge of the element is +12. To change to Cr³⁺ it has release 3 electrons, but we have 2 Cr, so it finally released 6 e-. The oxidation state was decreased, so this is the reduction half reaction.

14 H⁺ + Cr₂O₇²⁻ + 6e⁻ → 2Cr³⁺ + 7H₂O   Reduction

As we have 7 O in the product side, we add 7 water, to the opposite place. In order to balance the H (protons) we, add the amount of them, in the opposite side, again.

(2Cl⁻ → Cl₂ + 2e⁻) ₓ3        

(14 H⁺ + Cr₂O₇²⁻ + 6e⁻ → 2Cr³⁺ + 7H₂O)  ₓ1    

We multiply the half reactions, in order to remove the electrons and we sum, the equations:

14 H⁺ + Cr₂O₇²⁻ + 6e⁻ + 6Cl⁻ → 3Cl₂ + 6e⁻ + 2Cr³⁺ + 7H₂O

Now, that we have the same amount of electrons, they can cancelled, so the balanced redox reaction is:

14 H⁺ + Cr₂O₇²⁻ + 6Cl⁻ → 3Cl₂ + 2Cr³⁺ + 7H₂O

To balance the given redox reaction, follow the steps: assign oxidation states, balance the elements undergoing oxidation or reduction, balance the elements not involved in redox, balance the charge, balance oxygen atoms, combine H2O molecules, and finally, balance the equation. The coefficient for Cl2 (g) is 3.

To balance the redox reaction Cr2O72- + Cl- → Cl2 + Cr3+ in an acidic solution, we need to follow these steps:

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Answer:

V= 48L

Explanation:

Moles of N2 = m/M = 30/28= 1.07moles

From the equation of reaction

N2 +3H2 → 2NH3

1mole of N2 produces 2mole of NH3

Hence

1.07moles will produce 1.07×2= 2.14 moles

At STP, 1mole occupy 22.4L

Hence volume of N2 produced = 2.14×22.4= 48 L

Answer:

For N₂F₂:

Molar fraction = 0.84

Partial pressure = 1.12 atm

For SF₄:

Molar fraction = 0.16

Partial pressure = 0.208 atm

Explanation:

It seems your question is missing the values required to solve the problem. However, an internet search showed me the following values for your question. If the values in your problem are different, your answer will be different as well, however the solving method will remain the same:

" A 5.00L tank at 0.7°C is filled with 16.5g of dinitrogen difluoride gas and 5.00g of sulfur tetrafluoride gas. You can assume both gases behave as ideal gases under these conditions. "

First we calculate the moles of each gas, using their molar mass:

Total mol number = 0.25 + 0.0463 = 0.2963 mol

Now we use PV=nRT to calculate the partial pressure of each gas:

P = ?

V = 5.00 L

T = 0.7 °C ⇒ 0.7 + 273.16 = 273.86 K

For N₂F₂:

For SF₄:

Final answer:

To calculate the mole fraction, you divide the number of moles of a gas by the sum of the moles of all gases in the mixture. The partial pressure of a gas is the pressure that the gas would exert if it were alone in the container. The total pressure in the tank is the sum of the partial pressures of each gas.

Explanation:

The mole fraction of a gas is the ratio of the moles of that gas to the total moles of all gases in the mixture. To calculate the mole fraction of dinitrogen difluoride (N2F2), divide the moles of N2F2 by the sum of the moles of N2F2 and CO2:

Mole fraction of N2F2 = moles of N2F2 / (moles of N2F2 + moles of CO2)

To calculate the mole fraction of carbon dioxide (CO2), divide the moles of CO2 by the sum of the moles of N2F2 and CO2:

Mole fraction of CO2 = moles of CO2 / (moles of N2F2 + moles of CO2)

The partial pressure of a gas is the pressure that the gas would exert if it were alone in the container. To calculate the partial pressure of N2F2, multiply its mole fraction by the total pressure in the tank:

Partial pressure of N2F2 = mole fraction of N2F2 * total pressure

To calculate the partial pressure of CO2, multiply its mole fraction by the total pressure in the tank:

Partial pressure of CO2 = mole fraction of CO2 * total pressure

The total pressure in the tank is the sum of the partial pressures of N2F2 and CO2:

Total pressure = partial pressure of N2F2 + partial pressure of CO2

Answer:

The weakest oxidizing agent is Zn^2+(aq)

The strongest reducing agent is Zn(s)

The strongest oxidizing agent is I2(s)

The weakest reducing agent is I^-(aq)

I^- cannot reduce Zn^2+ to Zn(s)

I2(s) can be reduced by hydrogen gas

Explanation:

In looking at oxidizing and reducing agents, our primary guide is the reduction potentials of each specie. The more negative the reduction potential of a specie, the better its function as a reducing agent. Zn has a very negative reduction potential hence it a very good reducing agent. Similarly, iodine has a very positive reduction potential hence it is a good oxidizing agent.

Only a specie having a more negative reduction potential than zinc can reduce it in aqueous solution. Similarly, the reaction potential of hydrogen is less than that of iodine hence hydrogen gas can reduce iodine.

Final answer:

In electrochemistry, the strongest reducing agent is Zn(s) and the weakest oxidizing agent is Zn2+(aq). I2(s) is the strongest oxidizing agent, while I-(aq) is the weakest reducing agent. I-(aq) cannot reduce Zn2+(aq) to Zn(s), and none of the species provided can be reduced by H2(g).

Explanation:

To determine the oxidizing and reducing agents, we refer to their standard electrode potentials (E°). A strong oxidizing agent has a higher positive E° value, indicating a greater tendency to gain electrons and be reduced. Conversely, a strong reducing agent has a lower (more negative) E° value, reflecting a higher tendency to lose electrons and be oxidized.

The weakest oxidizing agent is Zn²+(aq) because it has the most negative E° value (-0.763V), meaning it is the least likely to gain electrons. The strongest reducing agent is Zn(s) because zinc in its solid state is more willing to be oxidized (lose electrons) as indicated by its half-reaction (Zn(s) → Zn²+(aq) + 2e⁻).

Similarly, the strongest oxidizing agent is I₂(s) due to its higher E° value (0.535V), which demonstrates its greater ability to take up electrons. The weakest reducing agent in this set is I⁻(aq) because it is derived from I₂(s), which is a strong oxidizer, thus its conjugate, I⁻, would be the weakest reducer.

Regarding whether I⁻(aq) can reduce Zn²+(aq) to Zn(s), the answer is no, because I⁻(aq) is the weakest reducing agent and Zn²+(aq) is not a strong oxidizer. Lastly, H₂(g) has an E° value of 0.000V, making it neutral in this context, and therefore it will not reduce any of the species provided in the question.

Answer : The good buffer systems are, (a), (b), (c) and (e)

Explanation :

Buffer : It is a solution that prevent any changes in the pH of the solution on the addition of an acidic and basic components.

Or, it is a solution that maintain the pH of the solution by adding the small amount of acid or a base.

There are two types of buffer which are acidic buffer and basic buffer.

Acidic buffer : It is the solution that have the pH less than 7 and it contains weak acid and its salt. For example : Acetic acid (weak acid) and sodium acetate (salt).

Basic buffer : It is the solution that have the pH more than 7 and it contains weak base and its salt. For example : Ammonia (weak base) and ammonium chloride (salt).

The conditions for a good buffer system is:

(1) a weak acid and its conjugate base.

(2) a weak base and its conjugate acid.

(a) 0.37 M hydrocyanic acid + 0.24 M sodium cyanide

It is a combination of weak acid and its conjugate base. So, it is a good buffer.

(b) 0.14 M sodium nitrite + 0.27 M nitrous acid

It is a combination of weak acid and its conjugate base. So, it is a good buffer.

(c) 0.21 M hypochlorous acid + 0.13 M potassium hypochlorite

It is a combination of weak acid and its conjugate base. So, it is a good buffer.

(d) 0.20 M nitric acid + 0.22 M potassium nitrate

It is a combination of strong acid. So, it will not form buffer solution.

(e) 0.32 M ammonium bromide + 0.31 M ammonia

It is a combination of weak base and its conjugate acid. So, it is a good buffer.

Hence, the good buffer systems are, (a), (b), (c) and (e)

Good buffer systems are those that consist of a weak acid and its conjugate base or a weak base and its conjugate acid. The given combinations that are good buffer systems include hydrocyanic acid and sodium cyanide, sodium nitrite and nitrous acid, hypochlorous acid and potassium hypochlorite, and ammonium bromide and ammonia.

The aqueous solutions that are good buffer systems from the provided options are:

A good buffer system consists of a weak acid and its conjugate base or a weak base and its conjugate acid. These pairs are capable of neutralizing small amounts of added acid or base, thus maintaining a relatively stable pH in the solution. In contrast, solutions like 0.20 M nitric acid + 0.22 M potassium nitrate do not form a buffer because nitric acid is a strong acid and does not create a conjugate weak acid-base pair needed for buffering.

Answer:

Molarity = 2.25M

Explanation:

n= m/M= 56/26=2.15mol, V= 959ml= 0.959L

n=C×V

2.15= C× 0.959

Simplify

C= 2.25M

Answer:

2.2M

Explanation:

Answer:

increasing the temperature

Explanation:

Now look carefully at the reaction equation, notice the inclusion on an energy term on the left hand side;

PCl5(g) + energy ⇌ PCl3(g) + Cl2(g)

The inclusion of an energy term means that the reaction is endothermic. Energy is absorbed as the reaction goes from left to right.

Since energy is absorbed, increasing the temperature (supplying energy in the form of heat) will favour the forward reaction over the reverse reaction in accordance with Le Chatelier's principle. Hence the answer.

Answer:

Option (4) increasing the temperature

Explanation:

PCl5(g) + energy ⇌ PCl3(g) + Cl2(g)

The reaction above clearly indicates endothermic reaction since heat is required for the reaction to proceed to product.

As the heat is supplied, the temperature of reaction increases thereby making the reaction to proceed forward at a much faster rate and hence the equilibrium position will shift to the right. This is in accordance with Le Chatelier's principle will explained that for an endothermic reaction, an increase in temperature will cause the equilibrium position to shift to the right.

Answer:6.0 ML

Explanation:

Answer:

See explaination

Explanation:

EDTA is a chemical that binds and holds on to (chelates) minerals and metals such as chromium, iron, lead, mercury, copper, aluminum, nickel, zinc, calcium, cobalt, manganese, and magnesium. When they are bound, they can't have any effects on the body and they are removed from the body.

Check attachment for the step by step solution of the given problem.

Answer:

Mass of CaCl₂ produced from the reaction = 21.31 g

Explanation:

The balanced equation for the reaction

CaCO₃(s) + 2HCl(aq) ⟶ CaCl₂(aq) + H₂O(l) + CO₂(g)

How many grams of calcium chloride will be produced when 25.0 g of calcium carbonate is combined with 14.0 g of hydrochloric acid

First of, we need to recognize the limiting reagent in this reaction.

The limiting reagent is the reagent that is totally used up in the chemical reaction; it determines the amount of other reactants that react and the amount of products that will be formed.

To know the limiting reagent, we convert the masses of the reactants given to number of moles.

Number of moles = (mass)/(molar mass)

25.0 g of calcium carbonate

Molar mass of CaCO₃ = 100.0869 g/mol

Number of moles of CaCO₃ present at the start of the reaction = (25/100.0869) = 0.250 moles

14.0 g of hydrochloric acid

Molar mass of HCl = 36.46 g/mol

Number of moles of HCl present at the start of the reaction = (14/36.45) = 0.384 moles

But from the stoichiometric balance of the reaction,

1 mole of CaCO₃ reacts with 2 moles of HCl

If CaCO₃ was the limiting reagent,

0.25 moles of CaCO₃ at the start of the reaction would require 0.50 moles of HCl; which is more than the available number of moles of HCl available at the start of the reaction (0.384 moles)

So, CaCO₃ isn't the limiting reagent.

If HCl is the limiting reagent,

0.384 moles of HCl would require 0.192 moles of CaCO₃ to react with. This is within the limit of CaCO₃ present at the start of the reaction. (0.250 moles)

Hence, HCl is the limiting reagent, it is the reactant that is used up in the reaction and determines the amount of products formed.

Again, from the stoichiometric balance of the reaction,

2 moles of HCl gives 1 mole of CaCl₂

0.384 moles of HCl will give (0.384/2) moles of CaCl₂; that is, 0.192 moles of CaCl₂

We then convert this number of moles to mass.

Mass = (number of moles) × (molar mass)

Molar mass of CaCl₂ = 110.98 g/mol

Mass of CaCl₂ produced by the reaction = 0.192 × 110.98 = 21.30816 g = 21.31 g

Hope this Helps!!!

Answer: 21.09g of Calcium chloride is produced

Explanation: Please see the attachments below

Answer:

See detailed mechanism in the image attached

Explanation:

The mechanism shown in detail below is the synthesis of serine in steps.

The first step is the attack of the ethoxide ion base on the diethyl acetamidomalonate substrate giving the enolate and formaldehyde.

The second step is the protonation of the oxyanion from (1) above to form an alcohol as shown.

Acid hydrolysis of the alcohol formed in (3) above yields a tetrahedral intermediate, a dicarboxyamino alcohol.

Decarboxylation of this dicarboxyamino alcohol yields serine, the final product as shown in the image attached.

Question:

Question 3 is not complete. here is the complete question;

3. With respect to GC, what effect would raising the column temperature have on the retention time?

Answer:

See the attached file for the structures

Explanation:

Find attached of question 1 and 2.

3. Raising the column temperature enhances the internal energy of the analyse. Therefore, it will escape from the liquid phase faster and predominantly be present in the vapour phase. On increasing temperature, retention time will be DECREASED, because analyte would not be able to interact with stationary phase efficiently.

The Zaitsev product from the dehydration of 1-methylcyclohexanol would have the double bond between the carbon connected to the OH group and the adjacent more substituted carbon. The mechanism of acid-catalyzed dehydration of cyclohexanol involves protonation, departure of a water molecule forming a carbocation, and subsequent loss of a proton which forms a pi bond. Changes in temperature and pressure in Gas Chromatography (GC) can impact analysis outcomes.

The basis of your question involves the Zaitsev product from the dehydration of 1-methylcyclohexanol, the mechanism of the acid-catalyzed dehydration of cyclohexanol using hydronium, and effects in relation to Gas Chromatography (GC).

1) When dehydrating 1-methylcyclohexanol, the Zaitsev rule tells us that the most substituted alkene will be the major product. Because you are dehydrating 1-methylcyclohexanol, the Zaitsev product will have the double bond between the carbon connected to the OH group and the adjacent carbon which is more substituted.

2) The second part of the question relates to the acid-catalyzed dehydration of cyclohexanol.

Firstly, in the presence of acid, the hydroxyl group on cyclohexanol is protonated forming a good leaving group. The water molecule leaves creating a carbocation. A proton is then lost resulting in the pi bond of the cyclohexene. Water acts as a base to receive this proton.

3) With respect to Gas Chromatography (GC), changes in temperature and pressure can affect the results. Higher temperatures can increase resolution but at the risk of over-separation.

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Answer:

The factor is 2

Explanation:

Van't Hoff factor is defined as the ratio between the species of a solute before the addition to the solvent and particles produced when the substance is dissolved. It is used, principally, in colligative properties.

Before solution, potassium bromide, KBr, has just one specie, that is, KBr. When KBr is dissolved (As a salt):

KBr(aq) → K⁺(aq) + Br⁻(aq)

There are produced two species, K⁺ and Br⁻. By definition of Van't Hoff factor, for this salt, the factor is 2.

Answer:

Solution is 4.67% by mass of salt

Explanation:

% by mass is the concentration that defines the mass of solute in 100g of solution.

In this case we have to find out the mass of solution with the data given:

Mass of solution = Mass of solute + Mass of solvent

Solute:  Salt → 14.2 g

Solvent: Water → 290 g

Solution's mass = 14.2 g + 290g = 304.2 g

% by mass = (mass of solute / mass of solution) . 100

(14.2 g / 304.2g) . 100 = 4.67 %

Answer:

14 H⁺(aq) + Cr₂O₇²⁻(aq) + 6 e⁻ → 2 Cr⁺³ + 7 H₂O(l)

Explanation:

Let's consider the half-reaction for the reduction of dichromate ion Cr₂O₇²⁻ to chromium ion Cr⁺³ in acidic aqueous solution.

Cr₂O₇²⁻(aq) → Cr⁺³

Step 1: Perform the mass balance adding H₂O(l) and H⁺(aq) where appropriate.

14 H⁺(aq) + Cr₂O₇²⁻(aq) → 2 Cr⁺³ + 7 H₂O(l)

Step 2: Perform the charge balance adding electrons where appropriate.

14 H⁺(aq) + Cr₂O₇²⁻(aq) + 6 e⁻ → 2 Cr⁺³ + 7 H₂O(l)

Answer:

Explanation:

During titration indicators are often used to identify chemical changes between reacting species.

For colorless solutions in which no noticeable changes can easily be seen, indicators are the best bet. Most titration processes involves a combination of acids and bases to an end point.

Indicators are substances whose color changes to signal the end of an acid-base reaction. Examples are methyl orange, methyl red, phenolphthalein, litmus, cresol red, cresol green, alizarin R3, bromothymol blue and congo red.

Most of these indicators have various colors when chemical changes occur.

Also, there are heat changes that accompanies most of these reactions. These are also indicators of chemical changes.

Final answer:

An observation indicative of a chemical change during titration could include temperature change, light emission, unexpected color change, or the formation of bubbles signaling the production of gas, any of which suggest that a new substance has been formed.

Explanation:

For instance, if the student added an indicator to the acid and after titrating with a base, noticed a color change, this would be evidence of a chemical change. Similarly, if the student observed the solution fizzing but it was not reaching boiling temperature, it could indicate the formation of a gaseous product.

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If all of the energy from the pancake is transferred into the water, the temperature of the water will increase by 0.02 °C

From the question given above, the following data were untainted:

The increase in temperature can be obtained as follow:

Q = MCΔT

Divide both side by MC

ΔT = Q / MC

ΔT = 61 / (2500 × 1)

ΔT = 61 / 2500

ΔT = 0.02 °C

Thus, the temperature of the water will increase by 0.02 °C

Learn more about heat transfer:

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