An automobile insurance company divides customers into three categories, good risks, medium risks, and poor risks. Assume that 78% of the customers are good risks, 20% are medium risks, and 2% are poor risks. Assume that during the course of a year, a good risk customer has probability 0.005 of filing an accident claim, a medium risk customer has probability 0.01, and a poor risk customer has probability 0.025. A customer is chosen at random. What is the probability that the customer has filed a claim? Round the answer to four decimal places.

Answers

Answer 1

Answer:

There is a 0.64% probability that the costumer has filed a claim.

Step-by-step explanation:

Probability:

What you want to happen is the desired outcome.

Everything that can happen iis the total outcomes.

The probability is the division of the number of possible outcomes by the number of total outcomes.

Our problem has these following probabilities:

-78% that a costumer is a good risk.

-20% that a costumer is a medium risk.

-2% that a costumer is a poor risk.

Also:

- 0.5% of a good risk costumer filling an accident claim

- 1% of a medium risk costumer filling an accident claim.

-2.5% of a poor risk costumer filling an accident claim.

The question is:

What is the probability that the customer has filed a claim?

[tex]P = P_[1} + P_{2} + P_{3}[/tex], in which:

-[tex]P_{1}[/tex] is the probability that a good risk costumer is chosen and files a claim. This probability is: the probability of a good risk costumer being chosen multiplied by the probability that a good risk costumer files a claim. So:

[tex]P_[1} = 0.78*0.005 = 0.0039[/tex]

-[tex]P_{2}[/tex] is the probability that a medium risk costumer is chosen and files a claim. This probability is: the probability of a medium risk costumer being chosen multiplied by the probability that a medium risk costumer files a claim. So:

[tex]P_[2} = 0.20*0.01 = 0.002[/tex]

-[tex]P_{3}[/tex] is the probability that a poor risk costumer is chosen and files a claim. This probability is: the probability of a poor risk costumer being chosen multiplied by the probability that a poor risk costumer files a claim. So:

[tex]P_[3} = 0.02*0.025 = 0.0005[/tex]

[tex]P = P_[1} + P_{2} + P_{3} = 0.0039 + 0.002 + 0.0005 = 0.0064[/tex]

There is a 0.64% probability that the costumer has filed a claim.

Answer 2
Final answer:

The probability that a randomly selected customer has filed a claim is calculated using the total law of probability, which yields a result of 0.0064 or 0.64%, after considering the probabilities of each risk group filing a claim.

Explanation:

To calculate the probability that a randomly chosen customer has filed a claim, we need to use the total law of probability. This involves multiplying the probability of a customer being in each risk group by the probability that a customer in that risk group files a claim, and then summing these products.

For good risks, this probability is 0.78 (the percentage of good risk customers) multiplied by 0.005 (the probability a good risk customer files a claim): 0.78 * 0.005 = 0.0039.

For medium risks, the calculation is 0.20 * 0.01 = 0.0020.

For poor risks, the calculation is 0.02 * 0.025 = 0.0005.

Adding these probabilities together gives us the total probability that a customer has filed a claim: 0.0039 + 0.0020 + 0.0005 = 0.0064, or 0.64% if expressed as a percentage.

Therefore, the probability that a randomly selected customer from the insurance company has filed a claim is 0.0064 or 0.64%, rounded to four decimal places.


Related Questions

how to make a number line from -6.2 to -9.1

Answers

Answer:

3.1

Step-by-step explanation:

because u have to take away the - sign if it is two negatives :3

Step-by-step explanation:

you draw a line (don't forget to put arrows on the end) then you put the point farthest to the left :(-9.1) and the point farthest to the right (-6.2).

in between these points you add the ponts -9,-8,-7-,6 respectively.

Northwest Molded molds plastic handles with a variable cost of $1.00 per handle. The fixed cost to run the molding machine is $2560 per week. If the company sells the handles for $3.00 each, how many handles must be molded weekly to break even? What is the profit if 1500 handles are produced and sold?

Answers

Answer:

To break even it  must be molded 1280 handles weekly.

The profit if 1500 handles are produced and sold is $440

Step-by-step explanation:

To break even, the amount of total cost must be the same as the amount of revenues.  

Total Cost is Fixed cost plus unitary variable cost multiplied by the produce quantity.  

Total cost= FC + vc*Q

Where

FC=Fixed cost

vc=unitary variable cos

Q=produce quantity

Revenue= Price * Q

Break even FC + vc*Q=Price * Q

Isolating Q

FC=(Price * Q)-(vc*Q)

FC=(Price-vc) * Q

Q= FC/(Price-vc)

Q= $2560/($3.00-$1.00)=1280

If we sold 1500 handles

Profit = Revenue- Total cost =(Price * Q)-(FC + vc*Q)

P=$3.00 *1500-$2560 - $1.00*1500=

P=$4500-$2560-$1500=440

Final answer:

Northwest Molded must sell 1,280 handles to break even, based on their fixed weekly costs of $2,560 and a variable cost of $1.00 per handle with a selling price of $3.00 each. If they produce and sell 1,500 handles, they will make a profit of $440.

Explanation:

To calculate the break-even point for Northwest Molded, we need to determine the number of handles that must be sold to cover the total costs, which include both fixed and variable costs.

The fixed cost to operate the molding machine is $2,560 per week, and the variable cost per handle is $1.00.

Each handle is sold for $3.00. The break-even point is reached when total cost equals total revenue, which can be found using the break-even formula:

Break-even point in units = Fixed costs / (Selling price per unit - Variable cost per unit)

Thus, for Northwest Molded:

Break-even point in units = $2,560 / ($3.00 - $1.00) = $2,560 / $2.00 = 1,280 handles

To calculate the profit for producing and selling 1,500 handles, we need to compute the total revenue and subtract the total costs:

Total Revenue = Selling price per unit × Number of units sold = $3.00 × 1,500 = $4,500

Total Costs = Fixed costs + (Variable cost per unit × Number of units sold) = $2,560 + ($1.00 × 1,500) = $4,060

Profit = Total Revenue - Total Costs = $4,500 - $4,060 = $440

Therefore, in order to break even, Northwest Molded must mold and sell 1,280 handles weekly, and the company would make a profit of $440 if they produced and sold 1,500 handles.

Determine if each statement would relate to a lean manufacturing system or a traditional manufacturing system.

a. Employees are cross-trained for several machines in one division.

b. Management emphasizes that defects should not occur.

c. Products are manufactured based upon estimated sales.

Answers

Answer:

answered

Step-by-step explanation:

A)lean

B)lean

C)traditional

In Lean manufacturing system works are done reduce inventory levels below what  would be found in a traditional manufacturing system. The company does so by reducing batches into smaller batch sizes rather than large batch sizes. Goods are produced through product  cells rather than departments.

Within-batch wait time is time that product waits in a product cell for the other products in a batch, it is calculated by multiplying the value-added time per unit by number of other products ,one less the total batch size

Find the area of the triangle

Answers


Answer: 20x+3

Explanation:
We find the area of a triangle by multiplying and then dividing by 2. In this problem, I decided to split the triangle in half. So now. We have two equations to find area.
3x(2x)(5)
2x(x+6)(5)
Multiplying the first problem, we get 30x. With the second problem, we get 10x+6. Adding these areas, we get 40x+6. Though, we have to divide by two because it is a triangle. That is how I got my answer of 20x+3

Answer:

A ≈ 14.079 square units

Step-by-step explanation:

Area of a triangle is one half the base times the height.

A = ½ bh

A = ½ (10) (2x)

A = 10x

We need to find the value of x.

Starting with the triangle on the left, use Pythagorean theorem to find the length of the base.

(3x)² = (2x)² + a²

9x² = 4x² + a²

a² = 5x²

a = x√5

Repeat for the triangle on the right:

(x + 6)² = (2x)² + b²

x² + 12x + 36 = 4x² + b²

b² = -3x² + 12x + 36

The two bases add up to 10:

a + b = 10

Subtract a from both sides, then square both sides:

b = 10 − a

b² = 100 − 20a + a²

Substitute and simplify:

-3x² + 12x + 36 = 100 − 20(x√5) + 5x²

0 = 64 − (12 + 20√5) x + 8x²

0 = 2x² − (3 + 5√5) x + 16

Solve with quadratic formula:

x = [ -b ± √(b² − 4ac) ] / 2a

x = [ (3 + 5√5) ± √((-(3 + 5√5))² − 4(2)(16)) ] / 2(2)

x = [ (3 + 5√5) ± √(9 + 30√5 + 125 − 128) ] / 4

x = [ (3 + 5√5) ± √(6 + 30√5) ] / 4

x ≈ 1.4079, 5.6823

If we substitute 5.6823 into our a and b equations, we find that a = 12.706 and b = 7.322, which add up to 20.028, not 10.

So x ≈ 1.4079.

Therefore the area is:

A ≈ 14.079

1. In a college, each student ID card is linked with a unique 5-digit pin from the set {0,1,2,3,4,5,6,7,8,9}. A) Find the number of ID cards possible. B) Find the number of ID cards possible if the 5-digit number is an odd number? C) Recalculate A&B if the digits are not allowed to be repeated

Answers

The total number of ID cards possible without repeating digits is 10 x 9 x 8 x 7 x 6 = 30,240.

In a college, the number of ID cards possible can be found by calculating the number of possible options for each digit in the 5-digit pin.

Since each digit can be any number from the set {0,1,2,3,4,5,6,7,8,9}, there are 10 options for each digit. Therefore, the total number of ID cards possible is 10 x 10 x 10 x 10 x 10 = 100,000.

If the 5-digit number is to be an odd number, then the last digit can only be one of the odd numbers {1, 3, 5, 7, 9}. So there are 5 options for the last digit, and for each of the other four digits, there are still 10 options. Therefore, the total number of ID cards possible with an odd 5-digit number is 10 x 10 x 10 x 10 x 5 = 50,000.If the digits are not allowed to be repeated, then for the first digit, there are still 10 options. But for each of the other four digits, there are now 9 options since one digit has been used already. Therefore, the total number of ID cards possible without repeating digits is 10 x 9 x 8 x 7 x 6 = 30,240.

Convert 72degrees into radians

Answers

Answer:

72° = 1.25 radians

Step-by-step explanation:

As we know that,

[tex]1 degree = \frac{\pi}{180} radians[/tex]

Thus, [tex]72^{\circ} = 72\times\frac{\pi}{180}radians[/tex]

⇒ [tex]72^{\circ} =\frac{2\pi}{5}radians[/tex]

⇒ 72° = 1.25 radians    {∵ Using π = 22÷ 7 or 3.14}

Both degrees and radians are used to measure the angle. They are units of angle.

Problem 8 - Simple and Compound Interest

At an effective annual rate of interest of 5.3%, the present value of $7425.70 due in t years is $3250. Determine t

Problem 4 - Simple and Compound Interest

How much would you invest today to have $9500 in 8 years if the effective annual rate of interest is 4%?

Problem 8 - Simple and Compound Interest

At an effective annual rate of interest of 5.3%, the present value of $7425.70 due in t years is $3250. Determine t ?

Answers

Answer:

P8) [tex]t=7.02 years[/tex]

P4) Today you have to invest $6941.55

P8) Is the same P8 above

Step-by-step explanation:

P8) First of all, we can list the knowns [tex]VP=7425.70[/tex], [tex]I=3250[/tex] and [tex]i=5.3[/tex]%, so we use [tex]VF=VP+I=7425.70+3250=10675.70[/tex] then we use [tex]t=\frac{ln(VF/VP)}{ln(1+i)}=\frac{ln(10675.70/7425.70)}{ln(1+0.053)}  =\frac{0.363}{0.051}=7.02 years[/tex]

P4) First of all, we can list the knowns [tex]VF=9500[/tex], [tex]t=8[/tex] and [tex]i=4[/tex]%, so we use [tex]VP=\frac{VF}{(1+i)^{t} } =\frac{9500}{(1+0.04)^{8} } =6941.55[/tex]

P8) Is the same P8 above

What is the rate of heat transfer required to melt 1-ton of ice at 32 F in 24 hours?

Answers

Answer:

3865.74 J/s

Step-by-step explanation:

mass of ice, m = 1 ton = 1000 kg

time , t = 24 hours

latent heat of fusion of ice, L  = 334000 J/kg

Heat required to melt, H = m x L

where, m is the mass of ice and L be the latent heat of fusion

So, H = 1000 x 334000 = 334 xx 10^6 J

Rate of heat transfer = heat / time = [tex]\frac{334\times 10^{6}}{86400}[/tex]

Rate of heat transfer = 3865.74 J/s

thus, the rate of heat transfer is 3865.74 J/s.

One-half liter of solution for intravenous infusion contains 2 g of drug. How many milliliters of the solution would contain 0.5 mg of drug?

Answers

Final answer:

To find out how many milliliters of the solution would contain 0.5 mg of the drug, we can set up a proportion using the given information. The solution would contain 0.125 mL of the drug.

Explanation:

To find out how many milliliters of the solution would contain 0.5 mg of the drug, we need to set up a proportion using the given information. We have 2 g of the drug in one-half liter of solution, so the concentration is 4 g/L. We can convert milligrams to grams by dividing by 1000. By setting up the proportion, we have:

4 g/L = 0.5 mg/x mL

Cross-multiplying, we get:

4 g * x mL = 0.5 mg * 1 L

Converting mg to g and mL to L:

4 * x = 0.5 / 1000

x = (0.5 / 1000) / 4

x = 0.000125 L

Since there are 1000 mL in 1 L, we can convert the answer:

x = 0.000125 L * 1000 mL/L

x = 0.125 mL

Solve each of the following equations for x. (a) 5x-7=28 (b) 12-5x= x+30 (c) 5(x+2)= 1-3x
Зx-y=-5 X+2y=3

Answers

Answer:

(a) 7

(b) -3

(c) [tex]-\frac{9}{8}[/tex]

(d) -1

Step-by-step explanation:

(a) 5x - 7 = 28

5x = 28 + 7

5x = 35

x = 7

(b) 12 - 5x = x + 30

-5x = x + 30 - 12

-5x = x + 18

-5x - x = 18

-6x = 18

x = -3

(c) 5(x+2) = 1 - 3x

5x + 10 = 1 - 3x

5x = 1 - 3x - 10

5x + 3x = -9

8x = -9

x = [tex]-\frac{9}{8}[/tex],

(d) Given system of equations,

Зx-y = -5 ------(1),

x + 2y = 3 ----(2),

Equation (2) + 2 equation (1),

x + 6x = 3 - 10⇒ 7x = -7 ⇒ x = -1

A 12-m3 oxygen tank is at 17°C and 850 kPa absolute. The valve is opened, and some oxygen is released until the pressure in the tank drops to 650 kPa. Calculate the mass of oxygen that has been released from the tank if the temperature in the tank does not change during the process.

Answers

Answer:

Released oxygen mass: 15.92 kg

Step-by-step explanation:

ideal gas law : P*V=nRT

P:pressure

V:volume

T:temperature

n:number of moles of gas

n [mol] = m [g] /M [u]

m : masa

M: masa molar = 15,999 u (oxygen)

R: ideal gas constant = 8.314472 cm^3 *MPa/K*mol =

grados K = °C + 273.15

P1*V*M/R*T = m1

P2*V*M/R*T = m2

masa released : m1-m2 = (P1-P2) * V*M/R*T

m2-m1 = 200 * 10^-3 MPa * 12 * 10^6 cm^3 * 15.999 u / 8.314472 (cm^3 * MPa/K *mol) * 290. 15 K

m2-m1= 38 397.6 * 10^3 u*mol / 2412.44 = 15916.5 g = 15.9165 kg

Final answer:

The question involves the use of the Ideal Gas Law to calculate the mass of oxygen released from a tank when the pressure drops. The initial and final number of moles of oxygen is calculated using the Ideal Gas Law, then the difference represents the number of moles of oxygen released. Multiplying this by the molar mass of oxygen gives the mass of oxygen released, which is about 255.808 kg.

Explanation:

The Ideal Gas Law states that PV=nRT, where P is pressure in Pascals, V is volume in m3, n is the number of moles, R is the Universal Gas Constant (8.31 J/(mol.K)), and T is temperature in Kelvin. From the question, we know the initial and final pressures (P1=850 kPa, P2=650 kPa ), Volume (V=12 m3), and temperature (T=17°C = 290 K).

First, we need to calculate the initial (n1) and final (n2) number of moles using the equation n = PV/RT. Substituting the given values to the equation, we get n1= (850000*12) /(8.31*290)= 34974.48 mol and n2= (650000*12) /(8.31*290)= 26980.38 mol.

So, the mass of oxygen that has been released is the difference between the initial and final moles. It equals to 7994.1 mol. Since the molar mass of oxygen is approximately 32 g/mol, the mass of oxygen that has been released is 7994.1 mol * 32 g/mol = 255808 g or 255.808 kg. So, the mass of oxygen released from the tank is approximately 255.808 kg.

Learn more about Ideal Gas Law here:

https://brainly.com/question/1063475

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What percent of 1600 is 2?

Answers

Answer: 0.125%

Step-by-step explanation:

Let 1600 corresponds to the 100% value and 2 is a part of the total 100% value 1600.

The formula to find the percent of a part :_

[tex]\%=\dfrac{\text{Part}}{\text{Total}}\times100[/tex]

Substitute Part= 2 and Total = 1600 in the formula, we get :-

[tex]\%=\dfrac{2}{1600}\times100\\\\\Rightarrow\ \%=\dfrac{1}{8}\%=0.125\%[/tex]

Therefore, 2 is 0.125% of 1600.

Hence, the percent of 1600 is 2 = 0.125%

To find what percent of 1600 is 2, divide 2 by 1600 and multiply by 100, resulting in 0.125%. Thus, 2 is 0.125% of 1600.

To determine what percent of 1600 is 2, you can use the formula for percentage:

Percentage = (Part / Whole) × 100

Here, the part is 2 and the whole is 1600. Plug these values into the formula:

Percentage = (2 / 1600) × 100

First, perform the division:

2 / 1600 = 0.00125

Next, multiply by 100 to convert to a percentage:

0.00125 × 100 = 0.125%

Therefore, 2 is 0.125% of 1600.

Mr. and Mrs. Wong purchased their new house for $350,000. They made a down payment of 20%, and amortized the rest over 30 years. If the interest rate is 4.2%, which of the following is their correct monthly mortgage payment?

Answers

Answer:

$1,369.25

Step-by-step explanation:

Mr. and Mrs. Wong purchased their new house for $350,000.

They made a down payment of 20%

Down payment = 20% of 350000

                        = $70,000

Loan amount, P = $350,000 - $70,000

                         = $280,000

Rate of interest, r = 4.2% or 0.042

Time, t = 30 years

Number of period, n = 12 ( monthly )

Formula: [tex]E=\dfrac{P\cdot \frac{r}{n}}{1-(1+\frac{r}{n})^{-n\cdot t}}[/tex]

Substitute the values into formula

[tex]E=\dfrac{280000\cdot \frac{0.042}{12}}{1-(1+\frac{0.042}{12})^{-12\cdot 30}}[/tex]

E = $1,369.25

Hence, The monthly payment for their mortgage will be $1,369.25

If A, B, and C are mutually exclusive events with P(A) = 0.21, P(B) = 0.32, and P(C) = 0.43, determine the following probabilities. Round your answers to two decimal places.
​(a)​ P(A U B U C) ​
(b) P(A n B n C) ​
(c)​ P(A n B) ​
(d) P[(A U B) n C]

Answers

By their mutual exclusivity,

[tex]P(A\cup B\cup C)=P(A)+P(B)+P(C)=0.96[/tex]

[tex]P(A\cap B\cap C)=0[/tex]

[tex]P(A\cap B)=0[/tex]

For the last probability, first distribute the intersection:

[tex](A\cup B)\cap C=(A\cap C)\cup(B\cap C)[/tex]

Recall that for two event [tex]X,Y[/tex],

[tex]P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)[/tex]

so that

[tex]P((A\cap C)\cup(B\cap C))=P(A\cap C)+P(B\cap C)-P((A\cap C)\cap(B\cap C))[/tex]

[tex]P((A\cap C)\cup(B\cap C))=P(A\cap C)+P(B\cap C)-P(A\cap B\cap C)=0[/tex]

246, 299, 360, 404, 379, 199, 279, 749, 794, 849, 914

Compute the mean, median, and mode of these prices.

Find the first and third quartiles of the prices.

Answers

Answer:

Mean = 497.5

Median = 379.0

First Quartile = 289

Third Quartile = 771.5

Step-by-step explanation:

Mean is used to measure the central tendency of data which represents the whole data in the best way. It can be found as the ratio of the sum of all the observations to the total number of observations.  

⇒ [tex]Mean=\frac{246+ 299+ 360+ 404+ 379+ 199+ 279+ 749+ 794+ 849+ 914}{11}[/tex]

Mean = 497.5

Median is the middle observation of given data. It can be found by following steps:

Arranging data in ascending or descending order.

Taking the average of middle two value if the total number of observation is even, and this average is our median.

or, if we odd number of observation then the most middle value is our median.  

Here, number of observation is 11.

So the middle value is (11+1)÷2 = 6th term

Median = 379

The mode is the observation which has a high number of repetitions (frequency).

Here frequency of all observation is same. So, it is multi- modal data.

First Quartile is the middle value between Minimum value and Median of data after arranging data in ascending order.

First Quartile (Q₁) = 289

The third Quartile is the middle value between Median and Maximum Value of data after arranging data in ascending order.

Third Quartile (Q₃) = 771.5

(a) How many prime numbers are (b) How many prime numbers are also abundant numbers?

Answers

Answer:

a) There are infinite prime numbers, b) All prime numbers are also abundant numbers

Step-by-step explanation:

To prove a) let's first prove that if n divides both integers A and B then also divides the difference A-B

If n divides A and B, there are integers j, k such that

A = nj and B= nk,

So

A-B= nj - nk = n(j-k)

But j-k is also an integer, which means that n divides also A-B

Now, to prove that there are infinite prime numbers , we will proceed with Reductio ad absurdum.

We will suppose that there are only a finite number of primes and then arrive to a contradiction.

Suppose there are only n prime numbers,

{p1,p2,... pn}

then take P=p1.p2...pn the product of all of them

and consider P+1

If P+1 is prime the proof is complete for P+1 is not in the list.

if P+1 is not prime then by the Fundamental Theorem of Arithmetic there is a prime in the list that must divide P+1, let's say pk

Then pk also divides P+1-P=1 which is a contradiction because no prime divides 1.

b) To prove this, recall that an abundant number is a number for which the sum of its proper divisors is greater than the number itself.

Given that a prime number P is only divided by P and 1, the sum of its divisors is P+1 which is greater than P. So P is abundant

Solve the following logarithmic equation: In(x +31)-In(4-3x)-5In2 0 x = 2 1 points x= 0 x-0.5 ○ x=0.25 None of the above to save all

Answers

Answer:

The solution is [tex]x = 1[/tex]

Step-by-step explanation:

We have the following logarithmic properties:

[tex]ln a + ln b = ln ab[/tex]

[tex]ln a - ln b = ln \frac{a}{b}[/tex]

[tex]n ln a = ln a^{n}[/tex]

We have the following logarithmic equation:

[tex]ln(x + 31) - ln (4-3x) - 5 ln 2 = 0[/tex]

Lets simplify, and try to find properties.

[tex]ln(x + 31) - (ln (4-3x) + 5 ln 2) = 0[/tex]

[tex]ln(x + 31) - (ln (4-3x) + ln 2^{5}) = 0[/tex]

[tex]ln(x + 31) - (ln (4-3x) + ln 32) = 0[/tex]

[tex]ln(x + 31) -  ln 32*(4-3x) = 0[/tex]

[tex]ln(x+31) - ln (128 - 96x) = 0[/tex]

[tex]ln \frac{x + 31}{128 - 96x} = 0[/tex]

To eliminate the ln, we apply the exponential to both sides, since e and ln are inverse operations.

[tex]e^{ln \frac{x + 31}{128 - 96x}} = e^{0}[/tex]

[tex]\frac{x + 31}{128 - 96x} = 1[/tex]

[tex]x + 31 = 128 - 96x[/tex]

[tex]97x = 97[/tex]

[tex]x = \frac{97}{97}[/tex]

[tex]x = 1[/tex]

The solution is [tex]x = 1[/tex]

A car and a truck start from rest at the same instant, with the car initially at some distance behind the truck. The truck has a constant acceleration of 2.10 m/s2, and the car has an acceleration of 3.40 m/s2. The car overtakes the truck after the truck has moved 60.0 m. (a) How much time does it take the car to overtake the truck

Answers

Answer:

Time take by car to overtake the truck is 7.6 seconds.

Step-by-step explanation:

Given : A car and a truck start from rest at the same instant, with the car initially at some distance behind the truck. The truck has a constant acceleration of 2.10 m/s², and the car has an acceleration of 3.40 m/s². The car overtakes the truck after the truck has moved 60.0 m.

To find : How much time does it take the car to overtake the truck ?

Solution :

According to question,

Taking the origin to be the truck position when it is at rest.

The car overtakes the truck after the truck has moved 60.0 m.

Using the equation to find time,

[tex]x-x_o=v_ot+\frac{1}{2}at^2[/tex]

Where, [tex]x_o=0[/tex] initial distance

[tex]v_o=0[/tex] initial velocity

a= 2.10 m/s² is the acceleration of the truck

x=60 m is the distance truck moved.

Substitute the value in the formula,

[tex]60-0=0(t)+\frac{1}{2}\times 2.10\times t^2[/tex]

[tex]60=1.05\times t^2[/tex]

[tex]t^2=\frac{60}{1.05}[/tex]

[tex]t=\sqrt{\frac{60}{1.05}}[/tex]

[tex]t=7.55[/tex]

Therefore, Time take by car to overtake the truck is 7.6 seconds.

What is buffer and what is dissolve? (4 pts)

Answers

Answer:

 The buffer is the solution which basically oppose pH change upon the expansion of an acidic or fundamental parts. It can kill limited quantities of included corrosive or base, in this way keeping up the pH of the arrangement generally stable and steady.

Acidic buffer is the arrangements are usually produced using weak acidic nature and also by the sodium salt.

Dissolve is the process of break down is to make a solute go into an solution. Dissolving is likewise called disintegration. Regularly, this includes a strong going into a fluid stage, however disintegration can include different changes too.

For instance, when compounds structure, one strong breaks down into another to frame a strong arrangement.

Convert 500 cubic feet to liters

Answers

Answer:

500 cubic feet is equal to 14158.4 liters.

Step-by-step explanation:

Since, we know that,

1 square feet = 28.3168 liters,

Thus, the number of liters in 500 cubic feet = 500 × number of liters in 1 square feet

[tex]=500\times 28.3168[/tex]

[tex]=14158.4[/tex]

Therefore, 500 cubic feet is equal to 14158.4 liters.

500 cubic feet is 14158.4 liters.

To convert 500 cubic feet to liters, follow these steps:

Using the conversion factor:

1 ft³ = 28.3168 L

So, to convert 500 cubic feet to liters:

500 ft³ × 28.3168 L/ft³ = 14158.4 L

Show that if A CB, then A = B ( B A ). Show that if A C B, then A U (B \ A) = B. Show, by example, that for sets A, B, and C, AN B = An C does not imply B = C.

Answers

Answer: If A ⊂ B, then A = B \ ( B \ A)

ok, when you do B \ A, you are subtracting all the elements in A∩B from B. So the only elements remaining are those who aren't in A.

If we subtract this of B again, we are subtracting of B all the elements that aren't in A, so the only elements remaining are those who belongs in A.

If A ⊂ B then A U (B \ A) = B.

Again, when you do B \ A you are extracting all the elements that belongs to the A∩B from B. So you are extracting al the elements from A. and when you add all the elements of A again, then you recuperate B.

if AnC = AnC does not imply that B = C.

if A = {1,2}, B = {1,2,3,4,5} and C = {1,2,3}

then AnC = {1,2} and AnB = {1,2} but B and C are different.

Instructions for a chemical procedure state to mix salt, baking soda, and water in a 20:15:10 ratio by mass. How many grams of water would be required to make a mixture that contains 24 grams of baking soda?

Answers

Answer:

16 g of water.

Step-by-step explanation:

salt : baking soda : water =  20 : 15 : 10

If we have  24 g of baking soda that is 24/15 = 8/5 times of 15.

So by proportion the amount of water would be 10 * 8/5 = 16 grams.

The mass of water in the mixture is 16 gm

What is Ratio and Proportion ?

When a number is divisible by another number then they can be written in the form of ratio p :q , When two ratios are equal they are said to be in proportion.

It is given that

salt, baking soda, and water in a 20:15:10 ratio by mass are mixed

mixture contains 24 grams of baking soda

Mass of Water = ?

Baking Soda : Water = 15 : 10

Let the mass of water is x

then the ratio is 24 : x

As both these ratios are equal

15 : 10 = 24 : x

15 / 10 = 24 / x

x = 24 * 10 / 15

x = 16 gm

Therefore the mass of water in the mixture is 16 gm.

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How to do exponents a quicker way!! Please help my brother!

Answers

You need to remember your exponent rules. I don’t know any easier way to do it. These are all the ones I can remember right now

When an object falls through air, there is a drag force that depends on the product of the cross sectional area of the object and the square of its velocity, that is, Fair = CAv2, where C is a constant. Determine the dimensions of C. (Use the following as necessary: M for mass, T for time, and L for length.)

Answers

Answer:

[tex]\textrm{Dimension of C }=\ [ML^{-3}T^{0}][/tex]

Step-by-step explanation:

As given in question drag force depends upon the product of the cross sectional area of the object and the square of its velocity

and drag force can be given by

[tex]F=CAv^2[/tex]          (1)

It is given that

Dimension of mass = [M]

Dimension of length = [L]

Dimension of time = [T]

So, by using above dimension we can write

the dimension of force,

[tex]F=[MLT^{-2}][/tex]

dimension of cross-section area,

[tex]A=[L^2][/tex]

and dimension of velocity

[tex]v=[LT^{-1}][/tex]

now, by putting these values in equation (1), we will get

[tex]F=CAv^2[/tex]

[tex]=>[MLT^{-2}]=C[L^2][LT^{-1}]^2[/tex]

[tex]=>C=[ML^{-3}T^0][/tex]

Hence, the dimension of constant C will be,

[tex]C=[ML^{-3}T^0][/tex]

The dimensions of C from the expression above is ML^-3

Units and Dimension

Given the function that relates drag force with the  cross-sectional area of the object and the square of its velocity expressed as:

[tex]F_{air} = CAv^2[/tex]

Make C the subject of the formula to have:

[tex]C =\frac{F}{Av^2}[/tex]

Given the following dimensions

[tex]M =MLT^{-2}[/tex]

A = L²

v = [tex]LT^{-1}[/tex]

Substitute into the formula. the dimension of C will be given as:

[tex]C=\frac{MLT^{-2}}{L^2L^2T^{ -2}}\\C= ML^{-3}[/tex]

Henc the dimensions of C from the expression above is ML^-3

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Prove that the square of any even number is always a multiple of 4.

Answers

Answer and Explanation:

To prove : The square of any even number is always a multiple of 4.

Proof :

The even numbers is defined as number end with 0,2,4,6,8 or the even number are multiple of 2.

Let the general even number be '2n'.

Squaring the number [tex](2n)^2=2^2\times n^2[/tex]

[tex](2n)^2=4n^2[/tex]

As 4 is the multiple of n².

So, If we square any even number it is always a multiple of 4.

For example,

[tex]2^2=4=4\times 1\\4^2=16=4\times 4\\6^2=36=4\times 9\\8^2=64=4\times 16[/tex]

Hence proved.

Karen Price has determined that her net worth is $58,000. She has also determined that the face value of her mortgage is $89,000. She has determined that the face value of the rest of her debt is $18,000. What is Karen's debt-to-equity ratio? Multiple Cholce 184 153 3.22 4.94 0.31

Answers

Answer:

A. 1.84

Step-by-step explanation:

We have been given that Karen Price's net worth is $58,000. The face value of her mortgage is $89,000. The face value of the rest of her debt is $18,000.

[tex]\text{Debt to equity ratio}=\frac{\text{Total liabilities}}{\text{Total shareholder's equity}}[/tex]

We know that total liabilities include short term debt and long-term debt.

[tex]\text{Debt to equity ratio}=\frac{\$89,000+\$18,000}{\$58,000}[/tex]

[tex]\text{Debt to equity ratio}=\frac{\$107,000}{\$58,000}[/tex]

[tex]\text{Debt to equity ratio}=1.8448[/tex]

[tex]\text{Debt to equity ratio}\approx 1.84[/tex]

Therefore, Karen's debt-to-equity ratio 1.84 and option A is the correct choice.

Fill in the table in the photo​

Answers

Answer:

  see the attachment

Step-by-step explanation:

If the growth is 7 feet in 2 weeks and the rate is constant, then it will be half that in one week, or 3.5 feet per week. At week 3, it will be 3.5 feet more than at week 2. The table below shows this progression.

The point (0, 0) means there was no measurable growth when time was starting to be measured (at week 0).

The following data describes the magnitude measurements randomly selected from 6 earthquakes recorded in one year from a location in southern Califormia: 6.6 2.2 18.5 7.0 13.7 5.9 The magnitude is measured by MAG on the Richter scale. What type of the data is the magnitude? a) Continuous numeric b) Discrete numeric c) Continuous categorical d) Nominal categorical

Answers

Answer: The magnitude is: a) continuous numeric.

Step-by-step explanation:

The magnitude is a numeric variable because it represents quantities. These are variables that you can measure or count. A numeric variable can be classified into discrete or continuous. In the present problem, the magnitude is a continuous variable. It can take any number within a scale, and you can find infinite values between two values on the scale. For example, you could measure earthquakes of magnitude 2.3, 2.4, 2.5, 2.6… and so on, following a continuous scale.

On the other hand, if the variable is numeric and discrete, it can only take certain finite values. For example, when you count the number of trees per acre. The number of trees will be always an integer. You can find 1, 2, or 3 trees, but you’ll never count 2.5 trees.

Categorical variables don’t represent quantities. They represent attributes. For example, apple colors: green and red.

How many possible ways are there to fill in answers to a
quizwith five multiple choice questions when the choices are a, b,
andc?

Answers

Answer:  There are 15 possible ways to fill in answers  .

Step-by-step explanation:

Given : The number of multiple choice questions = 5

The total number of choices for each question {a, b,

and c} = 3

Now by using the fundamental principle of counting , the number of possible ways to fill in answer is given by :-

[tex]5\times3=15[/tex]

Therefore, there are 15 possible ways to fill in answers  .

Show in fact that 1=9m + 20n for some integers m and n

Answers

Answer:

[tex]1=9\cdot 9+20\cdpt (-4)=81-80[/tex]

Step-by-step explanation:

The greatest common divisor between 9 and 20 is 1, so we know the equation [tex] 1=9m+20n[/tex] has a solution. A solution can be found either by inspection, or by applying Euclidean algorithm.

By inspection we just list some multiples of 9:

9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99

and also list some mutiples of 20:

20, 40, 60, 80, 100, 120

And so we see that we can find a multiple of 9 (81) which is 1 away from a multiple of 20 (80). Which is the solution given at the start.

For the Euclidean algorithm, we should divide the greatest of the two numbers, by the smallest one, and keep track of the remainder:

20 = 9 * 2 + 2

Then we divide 9 by the remainder we got, which is 2:

9 =  2 * 4 + 1

we would continue doing this until getting a remainder of 1 (which we just did). Finally we "solve" for 1, from the last equation:

9 - 2*4 = 1

And then we solve for 2 from the first equation, and plug that in into the previous equation:

20 - 9*2 =2

9 - ( 20 - 9*2)*4 = 1

which does give us the same solution: [tex] 9\cdot 9 +20\cdot (-4)=1[/tex]

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