An equation is given. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.) 2 sin(2θ) = 1 (a) Find all solutions of the equation. θ = (b) Find the solutions in the interval [0, 2π). θ =

Answers

Answer 1

To solve the equation 2 sin(2θ) = 1, find the angles θ where sin(2θ) equals 1/2. The solutions for θ are π/12 + kπ, where k is any integer.

To solve the equation 2 sin(2θ) = 1, we can divide both sides of the equation by 2 to get sin(2θ) = 1/2. Since the range of sin function is -1 to 1, we need to find the angles θ where sin(2θ) equals 1/2.

Using the inverse sine function, we can find the principal value of 2θ which is π/6 radians. This gives us one solution for θ: π/12.

Since sin function is periodic with period of 2π, we can find additional solutions by adding integer multiples of π to the principal value. Therefore, the solutions for θ are π/12 + kπ, where k is any integer.

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Related Questions

7,945\100 Is the equal as which number?

Answers

Answer:

79.45

Step-by-step explanation:

7945/100 the answers is 79.45


Is 8 a solution to 3x + 9 = 13?

Answers

Answer:

No

Step-by-step explanation:

3x + 9 = 13

Subtract 9 from each side

3x + 9-9 = 13-9

3x = 4

Divide each side by 3

3x/3 = 4/3

x = 4/3

8 is not a solution

80% of 25 is equal to what

Answers

Answer:

20

Step-by-step explanation:

Of means multiply and is means equals

80% * 25 = ?

Change to decimal form

.80 *25 =

20

You are at a campus party where there are a total number of n people. The host asked everyone to put their phones in a bowl while walking in. A noise complaint ends the party abruptly, and everyone heads for the door, hastily grabbing their phones from the bowl Assume every guest has one and exactly one phone, and that they pick a phone at random (so that every assignment of a phone to a person is equally likely). What is the probability that: a. Every person gets their phone back? b. The first m persons to pick each get their own phones back? c. The first m persons to pick each get a phone belonging to the last m persons to pick? Hint: Try this thought experiment with a few choices of mand n to get a feel for the numbers that show up.)

Answers

Answer:

1, [tex]\frac{m}{n}[/tex], [tex]\frac{1-m}{n}[/tex].

Step-by-step explanation:

probability = [tex]\frac{Number of Possible Outcomes}{Total Outcomes}[/tex]

Total number of persons in the party = n

a) Pr ( every person gets their phone back) = Pr (each person picks his phone ) multiplied by number of person

   = [tex]\frac{1}{n}[/tex] × n = 1.

     No of first m persons to pick = m

     No of last m persons to pick = 1 - m

b) Pr (first m persons to pick each gets their phones back) = [tex]\frac{m}{n}[/tex]

c) Pr( first m persons get a phone belonging to last m persons) = [tex]\frac{1-m}{n}[/tex]

In a population of 10,000, there are 5000 nonsmokers, 2500 smokers of one pack or less per day, and 2500 smokers of more than one pack per day. During any month, there is an 8% probability that a nonsmoker will begin smoking a pack or less per day, and a 2% probability that a nonsmoker will begin smoking more than a pack per day. For smokers who smoke a pack or less per day, there is a 10% probability of quitting and a 10% probability of increasing to more than a pack per day. For smokers who smoke more than a pack per day, there is an 8% probability of quitting and a 10% probability of dropping to a pack or less per day. How many people will be in each group in 1 month, in 2 months, and in 1 year? (Round your answers to the nearest whole number.)

Answers

Answer:

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

Step-by-step explanation:

We have to write the transition matrix M for the population.

We have three states (nonsmokers, smokers of one pack and smokers of more than one pack), so we will have a 3x3 transition matrix.

We can write the transition matrix, in which the rows are the actual state and the columns are the future state.

- There is an 8% probability that a nonsmoker will begin smoking a pack or less per day, and a 2% probability that a nonsmoker will begin smoking more than a pack per day. Then, the probability of staying in the same state is 90%.

-  For smokers who smoke a pack or less per day, there is a 10% probability of quitting and a 10% probability of increasing to more than a pack per day. Then, the probability of staying in the same state is 80%.

- For smokers who smoke more than a pack per day, there is an 8% probability of quitting and a 10% probability of dropping to a pack or less per day. Then, the probability of staying in the same state is 82%.

The transition matrix becomes:

[tex]\begin{vmatrix} &NS&P1&PM\\NS& 0.90&0.08&0.02 \\ P1&0.10&0.80 &0.10 \\ PM& 0.08 &0.10&0.82 \end{vmatrix}[/tex]

The actual state matrix is

[tex]\left[\begin{array}{ccc}5,000&2,500&2,500\end{array}\right][/tex]

We can calculate the next month state by multupling the actual state matrix and the transition matrix:

[tex]\left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4950&2650&2400\end{array}\right][/tex]

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

To calculate the the state for the second month, we us the state of the first of the month and multiply it one time by the transition matrix:

[tex]\left[\begin{array}{ccc}4950&2650&2400\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4912&2756&2332\end{array}\right][/tex]

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

If we repeat this multiplication 12 times from the actual state (or 10 times from the two-months state), we will get the state a year from now:

[tex]\left( \left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] \right)^{12} =\left[\begin{array}{ccc}4792.63&3005.44&2201.93\end{array}\right][/tex]

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

Deandre just bought 9 bags of 15 cookies each. He already had 6 cookies in a jar. How many cookies does deandre have now?

Answers

Answer:

141 cookies

Step-by-step explanation:

amount of cookies

= 9(15) + 6

= 135 + 6

= 141

f(-4) in the function f(x) = -2x - 3?

Answers

Answer:

5

Step-by-step explanation:

f(-4) f(x)=-2x-3

f(-4)=-2(-4)-3

f(-4)=8-3

f(-4)=5

Answer:

5

Step-by-step explanation:

you imput -4 for x then you proceed as normal solving the equation

-2(-4) - 3 since two negatives when multiplied make a positive

8 - 3

5

Suppose each laptop of a certain type is assigned a series number, which consists of a sequenceof eight symbols: number, letter, letter, letter, number, number, number, number, where aletter is any one of 26 letters and a number is one among 0, 1,. . ., 9. Assume that all series numbers are equally likely.
(a) What is the probability that all symbols are different if one laptop is picked at random with equal probability?
(b) What is the probability that all symbols are different and the first number is the largest among the numbers?

Answers

Answer:

Step-by-step explanation:

There are 5numbers and 3 letters. Each number can be one among the 10 possible.

Each letter is 1 among the 26 available.

a)The number of possible unique serial numbers are

10^5x 26³

The number of 5 number combinations each different (order important) is 5!(10/5)= 30240

The number of 3 letter combinations each different (order important) is 3!(26/3)=15600

The required probability (that all symbols are different if one laptop is picked at random with equal probability) is

15600x3240/ 10^5x 26³=0.2684

b) The first letter must be at least 4 to be largest among the 5 numbers. So the first letter can be one of . 4,5,6,7,8,9..

The number of 5 number combinations each different and starting with 4 (order important) is .

4!=24

The number of 5 number combinations each different and starting with 5 (order important) is .

4!(5/4)= 120

The number of 5 number combinations each different and starting with 6 (order important) is .

4!(6/4)= 360

The number of 5 number combinations each different and starting with 7 (order important) is .

4!(7/4)= 840

The number of 5 number combinations each different and starting with 8 (order important) is

4!(8/4)= 1680

The number of 5 number combinations each different and starting with 9 (order important) is .

4!(9/4)= 3024

Thus, there are

The required probability ( that all symbols are different and the first number is the largest among the numbers) is

15600* 6040/10^5x 26³= 0.0537

Which of the following are examples of limiting factors?
food, water, cell composition
cell composition water sunlight
food water sunlight
sizer water sunlight

Answers

ANSWER:
examples of limiting factors are, food, water and sunlight

Find the x-coordinates of all critical points of the given function. Determine whether each critical point is a relative maximum, minimum, or neither by first applying the second derivative test, and, if the test fails, by some other method. f(x) = 5x^6 − 10x^4

Answers

Answer:

x = 0, local maximumx = ±(2/3)√3, global minima

Step-by-step explanation:

The first derivative is ...

  f'(x) = 30x^5 -40x^3 = 10x^3(3x^2 -4)

This will have zeros (critical points) at x=0 and x=±√(4/3).*

We don't need the second derivative to tell the nature of these critical points. Since the degree is even, the function is symmetrical about x=0. Since the leading coefficient is positive, it generally has a U-shape. This means the "outer" critical points will be minima, and the central one will be a local maximum.

__

However, since we're asked to use the 2nd derivative test first, we find the 2nd derivative to be ...

  f''(x) = 150x^4 -120x^2 = 30x^2(5x^2 -4)

For x=0, f''(0) = 0 -- as we expect for a function with a high multiplicity of the root at that point. For x either side of zero, both the function and the second derivative are negative, indicating downward concavity. That is, x = 0 is a local maximum.

For x² = 4/3, the second derivative is positive, indicating upward concavity. At x = ±√(4/3), we have local minima.

_____

* The "simplified" equivalent to √(4/3) is (2/3)√3.

Final answer:

The critical points of the function f(x) = 5x^6 − 10x^4 are x = 0, x = ±√(4/3). The point at x = 0 is a relative maximum while the points at x = ±√(4/3) are relative minima based on the second derivative test.

Explanation:

Given the function f(x) = 5x^6 − 10x^4, we first find the critical points. This is done by finding the derivative of the function and setting it equal to zero. For this function, the derivative, f'(x), is 30x^5 - 40x^3 = 0. Solving this equation for x, we get x = 0, and x = ±√(4/3).

Next, we apply the second derivative test by taking the second derivative of the original function, f''(x). This gives us f''(x) = 150x^4 - 120x^2. We substitute the obtained critical points into the second derivative. If f''(x) > 0, then the point is a relative minimum, if f''(x) < 0, it's a relative maximum. If neither, we need to consider higher order derivatives or other methods.

The second derivative is negative at x = 0, so that position is a relative maximum. The second derivative is positive at x = ±√(4/3), so these positions are relative minima.

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A student takes a true-false test that has 10 questions and guesses randomly at each answer. Let X be the number of questions answered correctly. Find P(Fewer than 3). Round your answer to 2 decimal places.

Answers

Answer:

P(Fewer than 3) = 0.05.

Step-by-step explanation:

We are given that a student takes a true-false test that has 10 questions and guesses randomly at each answer.

The above situation can be represented through Binomial distribution;

[tex]P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....[/tex]

where, n = number of trials (samples) taken = 10 questions

            r = number of success = fewer than 3

           p = probability of success which in our question is probability

                that question is answered correctly, i.e; 50%

LET X = Number of questions answered correctly

So, it means X ~ Binom(n = 10, p = 0.50)

Now, Probability that Fewer than 3 questions are answered correctly is given by = P(X < 3)

P(X < 3)  = P(X = 0) + P(X = 1) + P(X = 2)

=  [tex]\binom{10}{0}\times 0.50^{0} \times (1-0.50)^{10-0}+ \binom{10}{1}\times 0.50^{1} \times (1-0.50)^{10-1}+ \binom{10}{2}\times 0.50^{2} \times (1-0.50)^{10-2}[/tex]

=  [tex]1 \times 0.50^{10} + 10 \times 0.50^{10} +45 \times 0.50^{10}[/tex]

=  0.05

Hence, the P(Fewer than 3) is 0.05.

Final answer:

To find the probability of the student passing the test with at least a 70 percent, we can use the binomial probability formula. The probability of the student passing the test with at least 70 percent is 0.1719 (rounded to 2 decimal places).

Explanation:

To find the probability of the student passing the test with at least a 70 percent, we need to find the probability of the student answering 7, 8, 9, or 10 questions correctly out of the 10 questions. Since the student randomly guesses at each answer, the probability of guessing correctly is 0.5. Now we can calculate the probability using the binomial probability formula:

P(X ≥ 7) = P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

P(X = k) = C(10, k) * (0.5)^k * (0.5)^(10-k), where C(n, r) is the binomial coefficient (n choose r).

Calculating each probability and summing them up, we get P(X ≥ 7) = 0.171875. Therefore, the probability of the student passing the test with at least 70 percent is 0.1719 (rounded to 2 decimal places).


Round your answer to the nearest hundredth. Again.

Answers

Given:

In the given triangle ΔABC,

AB = 9 unit

AC = 2 unit

To find the value of ∠ABC.

Formula

From trigonometric ratio we get,

[tex]sin \theta = \frac{opposite}{hypotenuse}[/tex]

Let us take, ∠ABC = [tex]\theta[/tex]

With respect [tex]\theta[/tex], AC is the opposite side and AB is the hypotenuse.

So,

[tex]sin \theta = \frac{AC}{AB}[/tex]

or, [tex]sin \theta[/tex] = [tex]\frac{2}{9}[/tex]

or, [tex]\theta = sin^{-1} (\frac{2}{9} )[/tex]

or, [tex]\theta= 12.84^\circ[/tex]

Hence,

The value of ∠ABC is 12.84°.

Which prism has an area of 6 cubic units?
A prism has a length of 1 and one-half, height of 1, and width of 3.
A prism has a length of 2, height of 1 and one-half, and width of 2.
A prism has a length of 1 and one-fourth, height of 1, and width of 4.
A prism has a length of 3, height of 1 and one-fourth, and width of 2.

Answers

Answer:

A prism that has a length of 2, height of 1 and one-half, and width of 2.

Step-by-step explanation:

The formula for calculating the area of a prism is base area × height

Volume = L×W×H

L is the length of the prism

W is the width

H is the height.

To determine the prism that has an area of 6 cubic units, we will substitute the values in the option in the formula.

Using option D i.e prism that has a length of 2, height of 1 and one-half, and width of 2.

L = 2units, H = 1 1/2 units , W = 2units

Substituting in the formula for finding the volume

V = 2×2×3/2

Volume of the prism = 6cubic units

Answer:

B

Step-by-step explanation:

What is the volume of the following rectangular prism

Answers

Answer:

7  2/3

Step-by-step explanation:

Multiply 4/3 by 23/4

Standardization of a Normal Distribution: Bryce reads in the latest issue of Pigskin Roundup that the average number of rushing yards per game by NCAA Division II starting running backs is 50 with a standard deviation of 8 yards. If the number of yards per game (X) is normally distributed, what is the probability that a randomly selected running back has 64 or fewer rushing yards

Answers

Answer:

[tex]P(X<64)=P(\frac{X-\mu}{\sigma}<\frac{64-\mu}{\sigma})=P(Z<\frac{64-50}{8})=P(z<1.75)[/tex]

And we can find this probability using the normal standard table or excel and we got:

[tex]P(z<1.75)=0.9599[/tex]

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the number of rushing yards of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(50,8)[/tex]  

Where [tex]\mu=50[/tex] and [tex]\sigma=8[/tex]

We are interested on this probability

[tex]P(X<64)[/tex]

And the best way to solve this problem is using the normal standard distribution and the z score given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

If we apply this formula to our probability we got this:

[tex]P(X<64)=P(\frac{X-\mu}{\sigma}<\frac{64-\mu}{\sigma})=P(Z<\frac{64-50}{8})=P(z<1.75)[/tex]

And we can find this probability using the normal standard table or excel and we got:

[tex]P(z<1.75)=0.9599[/tex]

In a recent survey in a Statistics class, it was determined that only 74% of the students attend class on Fridays. From past data it was noted that 88% of those who went to class on Fridays pass the course, while only 20% of those who did not go to class on Fridays passed the course.
a.What percentage of students is expected to pass the course?
b.Given that a person passes the course, what is the probability that he/she attended classes on Fridays?

Answers

Answer:

a) 83%

b) 0.892

Step-by-step explanation:

percentage that attends class on friday = 74%

percentage that pass because they attend class on friday = 88%

percentage that pass but did not go to school on friday = 20%

a) percentage of students expected to pass the course

  = (74% x 88%) +(88% x 20%)

   = 0.6512 + 0.176

   = 0.8272

   = 83%

b) If a person passes the course, what is the probability that he/she attended classes on Fridays

        = 74% divided by 83%

        = 0.892

Traders often buy foreign currency in hope of making money when the currency's value changes. For example, on a particular day, one U.S. dollar could purchase 0.8869 Euros, and one Euro could purchase 143.1126 yen. Let fix) represent the number of Euros you can buy with x dollars, and let g(x) represent the number of yen you can buy with x Euros. (a) Find a function that relates dollars to Euros fx)Simplify your answer.) (b) Find a function that relates Euros to yen. gxSimplify your answer.) (c) Use the results of parts (a) and (b) to find a function that relates dollars to yen. That is, find (g o f)(x)-g(fx g(f(x)) Simplify your answer. Use integers or decimals for any numbers in the expression. Round to four decimal places as needed.) (d) What is g(1000))? g(f(1000)) Type an integer or decimal rounded to one decimal place as needed.)

Answers

Answer:

(a)f(x)=0.8869x

(b)g(x)=143.1126x

(c)g(f(x))=126.9266x

(d)g(f(1000))=126926.6 Yen

Step-by-step explanation:

Given on a particular day

One U.S. dollar could purchase 0.8869 EurosOne Euro could purchase 143.1126 yen

(a)If x represents the number of Dollars

Since one can purchase 0.8869 Euro with 1 USD, the function f(x) is a direct relationship where x is dollars and f(x) is in Euros.

f(x)=0.8869x

(b)If x represents the number of Euros

Since one can purchase 143.1126 yen with 1 Euros, the function g(x) is a direct relationship where x is Euros and g(x) is in Yen.

g(x)=143.1126x

(c)Given:

g(x)=143.1126xf(x)=0.8869x

g(f(x))=143.1126(0.8869x)

g(f(x))=126.9266x

(d)g(f(1000))

g(f(x))=126.9266xg(f(1000))=126.9266 X 1000 =126926.6 Yen

A study of 178 cases of disease X were identified from a state registry. A total of 220 control subjects were then recruited from random-digit dial procedure. 16 cases had been exposed, compared to only 8 controls. How likely were cases to report an exposure compared with controls

Answers

Answer:

2.47 times more likely.

Step-by-step explanation:

16 out of 178 cases were reported for exposure.

And 8 out of 220 control reported for exposure.

Chances that a case would be reported for exposure = (16/178) = 0.0898876404

Chances that one control would report for exposure = (8/220) = 0.0363636364

Comparing both, how likely were cases to report an exposure compared with controls

= (0.0898876404) ÷ (0.0363636364)

= 2.4719101085 = 2.47 times more likely.

Hope this Helps!!

Is this expression true or false? 5 ÷ 1/9 = 45

Answers

1/9 as a decimal is .111 so 5 divided by .111 is 45.04

Answer:

False

Step-by-step explanation:

Common sense

simplified expression -6x+2/3(9-15x)-2

Answers

Answer:

-16x+4

Step-by-step explanation:

-6x+2/3(9-15x)-2

Distribute

-6x +2/3 *9 +2/3*(-15x) -2

-6x +6 -10x -2

Combine like terms

-6x-10x +6-2

-16x+4

A new centrifugal pump is being considered for an application involving the pumping of ammonia. The specification is that the flow rate be more than 5 gallons per minute (gpm). In an initial study, eight runs were made. The average flow rate was 6.5gpm and the standard deviation was 1.9 gpm. If the mean flow rate is found to meet the specification, the pump will be put into service.

1. State the appropriate null and alternate hypotheses

2. Find the P-value

3. Should the pump be put into service? Explain.

Answers

Answer:

1) We need to conduct a hypothesis in order to check if the true mean is higher than 5 gpm, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 5[/tex]  

Alternative hypothesis:[tex]\mu > 5[/tex]  

2) [tex]df=n-1=8-1=7[/tex]  

Since is a one sided test the p value would be:  

[tex]p_v =P(t_{(7)}>2.233)=0.0304[/tex]  

3) For this case is we use a significance level of 1% or 99% of confidencewe see that [tex]p_v >\alpha[/tex] and we don't have enough evidence to conclude that the specification is satified. But if we use a value of significance [tex]\alpha=0.05[/tex] or 95% of confidence we see that [tex]p_v <\alpha[/tex] and we have enough evidence to conclude that the specification is satisfied.

Step-by-step explanation:

Data given and notation  

[tex]\bar X=6.5[/tex] represent the sample mean

[tex]s=1.9[/tex] represent the sample standard deviation

[tex]n=8[/tex] sample size  

[tex]\mu_o =5[/tex] represent the value that we want to test

[tex]\alpha[/tex] represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

[tex]p_v[/tex] represent the p value for the test (variable of interest)  

Part 1: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 5 gpm, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 5[/tex]  

Alternative hypothesis:[tex]\mu > 5[/tex]  

If we analyze the size for the sample is <30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex]  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

[tex]t=\frac{6.5-5}{\frac{1.9}{\sqrt{8}}}=2.233[/tex]    

Part 2: P-value

The first step is calculate the degrees of freedom, on this case:  

[tex]df=n-1=8-1=7[/tex]  

Since is a one sided test the p value would be:  

[tex]p_v =P(t_{(7)}>2.233)=0.0304[/tex]  

Part d: Conclusion  

If we compare the p value and the significance level given [tex]\alpha=0.01[/tex] we see that [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant higher compared to the height of men in 1960 at 1% of signficance.  

Part 3

For this case is we use a significance level of 1% or 99% of confidencewe see that [tex]p_v >\alpha[/tex] and we don't have enough evidence to conclude that the specification is satified. But if we use a value of significance [tex]\alpha=0.05[/tex] or 95% of confidence we see that [tex]p_v <\alpha[/tex] and we have enough evidence to conclude that the specification is satisfied.

An ant moves along the x-axis from left to right at 5 inches per second. A spider moves along the y-axis from up to down at 3 inches per second. At a certain instant, the ant is 4 inches to the right of the origin and the spider is 8 inches above the origin. At this instant, what is the rate of change of the distance between the spider and the ant

Answers

Answer: The rate of change of the distance between the spider and the ant is 4.92 inches/sec

Step-by-step explanation: Please see the attachments below

A certain drug is used to treat asthma. In a clinical trial of the​ drug, 23 of 277 treated subjects experienced headaches​ (based on data from the​ manufacturer). The accompanying calculator display shows results from a test of the claim that less than 10​% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.01 significance level to complete parts​ (a) through​ (e) below.

a. What is test statistic?
b. What is p-value?
c. What is the null hypothesis, and what can we conclude about it?
d. Decide whether to reject the null hypothesis?
e. What is the final conclusion?

Answers

Answer:

a) The test statistic is z=-0.94

b) The p-value is 0.1736

c) The null hypothesis is [tex]H_0:p=0.10[/tex], we can conclude that, if the result is not significant at 0.01 level, we fail to reject the null hypothesis

d) We fail to reject the null hypothesis at 0.01 significance level.

e) We do not have sufficient  evidence to reject the claim that, less than 10​% of the treated subjects experienced headaches.

Step-by-step explanation:

The test statistic is defined by:

[tex]Z=\frac{\hat p-p_0}{\sqrt{\frac{p_0(1-p_0)}{n} } }[/tex]

It was given that, 23 of 277 treated in the clinical trial of the​ drug subjects experienced headaches.

This means that:

[tex]\hat p=\frac{23}{277}\approx 0.083[/tex]  and n=277

The  claim is that, less than 10​% of treated subjects experienced headaches. This means:

[tex]p_0=\frac{10}{100}=0.1[/tex]

We substitute the values into the formula to obtain:

[tex]Z=\frac{0.083-0.1}{\sqrt{\frac{0.1(1-0.1)}{277} } }[/tex]

The test statistics becomes:

[tex]Z=-0.94[/tex]

b) From the normal distribution table, the p-value corresponds to Z=-0.94 .

Since this is a left-tailed test, the p-value corresponds to area under the normal curve that is to the left of z=-0.94

P(Z<-0.94)=0.173609.

c) Since the claim is that, less than 10​% of treated subjects experienced headaches, the null hypothesis is

[tex]H_0:p=0.10[/tex]

The alternate hypothesis will be:

[tex]H_1:p\:<\:0.10[/tex]

This implies that, the result is not significant at 0.01 alpha level.

d) We need to compare the p-value to the significance level. If the significance level is greater than the null hypothesis, we reject the null hypothesis.

Since 0.01<0.1736, we fail to reject the null hypothesis.

d) Conclusion: There is no enough evidence to reject the claim that, less than 10​% of treated subjects experienced headaches.

Answer:

(a)Test statistic[tex]z_{score}=-0.94[/tex]

(b) p-value=0.1736

(c)Null hypothesis,

    [tex]H_0:p=0.10[/tex]

(d)[tex]\alpha>p[/tex], we reject the null hypothesis.

(e)We have experimental values to reject the claim.

Step-by-step explanation:

Given information;

n=277

Significance level [tex]\alpha[/tex]=0.01

By normal distribution,

[tex]z_{score}=\frac{\widehat{p}-p_0}{\frac{\sqrt {p_0(1-p_0)}}{n}}[/tex]

[tex]\widehat{p}=\frac{23}{277}=0.83[/tex]

[tex]p_0=10[/tex]%=0.1

On substitution,

[tex]z_{score}=\frac{{0.83}-0.1}{\frac{\sqrt {0.1(1-0.1)}}{277}}[/tex]

Test static,

[tex]z_{score}=-0.94[/tex]

b)From the table normal distribution,

for,[tex]z_{score}=-0.94,[/tex]

[tex]P(z<-0.94)=0.173609[/tex]

(c)Null hypothesis,

    [tex]H_0:p=0.10[/tex]

     Alternate hypothesis,

    [tex]H_1:p<0.10[/tex]

It implies result is not significant at

[tex]\alpha=0.01[/tex]

(d) On compare value if

[tex]\alpha>p[/tex], we reject the null hypothesis.

For more details please refer link:

https://brainly.com/question/5286270?referrer=searchResults

8. Lara subtracts 73 from 188. Which one of these
steps should she follow?
o Ungroup 8 tens as 7 tens 10 ones.
o Subtract 3 ones from 8 tens.
o Subtract 7 tens from 8 tens.

Answers

Answer: o Subtract 7 tens from 8 tens.

Step-by-step explanation: you subtract

Answer:

Step-by-step explanation:subtract 7 tens from 8 tens

Please help me in don't understand how to do this

Answers

Answer:

36

Step-by-step explanation:

[tex] \frac{c}{4} - 5 = 4 \\ \\ \frac{c}{4} = 4 + 5\\ \\ \frac{c}{4} = 9 \\ \\ c = 9 \times 4 \\ \\ \huge \red{ \boxed{ c = 36}}[/tex]

Can anyone help me please ASAP

Answers

Given:

It is given that the measurements of the triangle.

The measure of ∠2 is (3x + 3)°

The measure of ∠3 is (3x - 4)°

The measure of ∠4 is (5x + 8)°

We need to determine the measure of ∠1 and ∠4.

Value of x:

The value of x can be determined using the exterior angle theorem.

Applying the theorem, we have;

[tex]m \angle 4=m \angle 2+m \angle 3[/tex]

Substituting the values, we get;

[tex]5x+8=3x+3+3x-4[/tex]

[tex]5x+8=6x-1[/tex]

[tex]-x+8=-1[/tex]

     [tex]-x=-9[/tex]

        [tex]x=9[/tex]

Thus, the value of x is 9.

Measure of ∠4:

Substituting the value of x in the expression of ∠4, we get;

[tex]m\angle 4=5(9)+8[/tex]

       [tex]=45+8[/tex]

[tex]m\angle 4=53^{\circ}[/tex]

Thus, the measure of ∠4 is 53°

Measure of ∠1:

The angles 1 and 4 are linear pairs and hence these angles add up to 180°

Thus, we have;

[tex]\angle 1+ \angle 4=180^{\circ}[/tex]

Substituting the values, we get;

[tex]\angle 1+ 53^{\circ}=180^{\circ}[/tex]

         [tex]\angle 1=127^{\circ}[/tex]

Thus, the measure of ∠1 is 127°

Find the slope
(-19,-6) (15,16)

Answers

Answer:

11/17

Step-by-step explanation:

slope between two points: slope = (y2 - y1) / (x2 - x1)

(x1, y1) = (-19, -6), (x2, y2) = (15, 16)

m = (16 - ( - 6)) / (15 - ( - 19))

refine

m = 11/17

sorry it is hard to follow... i am on my phone rn :/

Final answer:

The slope between the points (-19, -6) and (15, 16) is 11/17.

Explanation:

To find the slope of the line connecting the points (-19,-6) and (15,16), we will use the slope formula which is the change in y-coordinates divided by the change in x-coordinates. Here is the process:

Identify the coordinates of the two points. Point 1 is (-19, -6), and Point 2 is (15, 16).Apply the slope formula: m = (y2 - y1) / (x2 - x1).Substitute the given values into the formula: m = (16 - (-6)) / (15 - (-19)) = (16 + 6) / (15 + 19).Simplify: m = 22 / 34.Reduce to the simplest form: m = 11 / 17.

Therefore, the slope of the line connecting the two points is 11/17.

The circle below represents one whole.

What percent is represented by the shaded area?​

Answers

The region represented by the shaded area has 25% and accounts for one-quarter of the overall circle.

The area is the space occupied by any two-dimensional figure in a plane. The area of the circle is the space occupied by the circle in a two-dimensional plane.

The formula for calculating circle area is r2, where r is the radius of the circle.

The entire area of the circle in the accompanying figure is r2. The shaded area accounts for one-fourth of the circle's overall area.

Total area =  πr²

Shaded area = ( 1 / 4 )πr²

The percentage of the shaded area will be calculated as

Shaded area = ( 1 / 4 )πr²

Shaded area = ( 0.25 )πr²

To convert it into a percentage multiply by 100.

Shaded area = ( 0.25 x 100 )πr²

Shaded area =25% πr²

Put πr² as the total area.

Shaded area =25% of Total area.

Therefore, the region represented by the shaded area has 25% and is 1/4th of the total circle.

Evaluate 6.5b - 12.03 when b= 3​

Answers

Answer:

7.47

Step-by-step explanation:

6.5b - 12.03

Let b=3

6.5(3) - 12.03

Multiply first

19.5 - 12.03

7.47

Hi I think your answer is - 5.5

6.5b b=3. So you replace B with 3 and that makes it 6.53-12.03.

wich gives you - 5.5.

A brownie recipe calls for 1 cup of sugar and 1/2 cup of flour

Answers

Answer:

Uhhhhhhhhhhhhh  yes most recipies do call for that

Step-by-step explanation:

have a nice day

You didn’t ask a question ha..
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