Answer:
d) The image would be dimmer
Explanation:
When inverted image of an object is viewed on a screen from the side facing a converging lens, the
lens focuses the diverging, and blurred light rays from the distance object through refraction of the rays two times.Then the rays is converge by the double bending cl at a focal point behind the lens inorder for a sharper image to be be observed.
But when an opaque card is then introduced to cover only the upper half of the lens then the image becomes dimmer because of the reduction in the light intensity on the screen by 50%
When the opaque card should be introduced so here the image should be considered as the dimmer.
Inverted image:At the time when the inverted image should be viewed on the screen that faced the converging lens so here the lens should be focused on the diverging also there should be blurred light rays from the distance object via the refraction of the rays.
However, at the time there is the opaque card so here the image should be dimmer since there is the decrease in the light intensity by 50%/
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A mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 30. cm3. If the combustion of this mixture releases 984 J of energy, to what volume (in L) will the gases expand against a constant pressure of 648 torr if all the energy of combustion is converted into work to push back the piston?
Answer:
Explanation:
Given
Original volume V1=30cm^3 converting to L
=30/1000=0.03L
Constant pressure P= 648 tors
Converting to atm; 648 tors*1atm/760 torr=0.853 atm
Work=984J= 984**1L/101.33=9.7L.atm
Note before
W= -P(Vfinal-Vinitial)
-9.7/0.853+0.03L=11.68L
Answer:
Final expanded volume 11.43 L
Explanation:
The picture attached shows the solution
If the speed of a wave is 150 m/s and it’s frequency is 2 Hz , what is its wavelength ?
Answer:
75 m
Explanation:
wavelength = frequency/ speed = 75 m
a force of 20N pushes an object of mass 5.0kg along a rough surface of 5.0N
Answer:
I'm sorry, I don't think there is any answer to give seeing as no question has been asked
Answer:
No question
Explanation: Sorry
Several years from now you have graduated with an engineering/physics degree from OSU and have been hired by a nanoengineering firm as an intern. You have been assigned to work under a top engineer from the company. Their current project is to design a microscopic oscillator as a time keeping device. The engineering design involves placing a negative charge at the center of a very small positively charged metal ring. Your boss claims that the negative charge will undergo simple harmonic motion of displaced away from the center of the ring. Furthermore, they claim they can change the period (timing) of oscillation by adjusting the amount of charge on the ring. The first task they give you is to check the validity of their design.Consider a charge −???? located a small distance z above the center of a positively charged ring with total charge +Q and radius R. Write an expression for the net force exerted on the charge −???? due to the ring of charge. What is the magnitude of the force on the charge −???? if it is at the location z = 0?
Complete Question in order
See the first image attached
Answer and Explanation:
The three images attached discussed the solution to this question
second Image
Third Image
and Fourth Image
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At the surface of the moon, the acceleration due to the gravity of the moon is x. At a distance from the center of the moon equal to four times the radius of the moon, the acceleration due to the gravity of the moon is _____.
Answer:
Gravity at a distance of 4R will be reduced to 1/16 th.
Explanation:
Given:
At the surface of the moon, the acceleration due to the gravity of the moon is x.
We have to find the gravity a t a distance of 4 times from the center of the moon.
Let the radius of the moon be "R".
And
The value of acceleration due to gravity is [tex]g_m[/tex] .
Formula:
⇒ [tex]g_m=\frac{GM}{R^2}[/tex] ...where M is the mass of the moon.
Now
Gravity of the moon at the its surface:
⇒ [tex]g_m=\frac{GM}{R^2}[/tex] ...equation (i)
Gravity of the moon at a distance of [tex]4R[/tex]:
⇒ [tex]g_m_1=\frac{GM}{(4R)^2}[/tex]
⇒ [tex]g_m_1=\frac{GM}{16R^2}[/tex] ...equation (ii)
Dividing equation (i) with (ii) to find the relationship between the two.
⇒ [tex]\frac{g_m_1}{g_m} =\frac{GM}{16R^2}\times \frac{R^2}{GM}[/tex]
⇒ [tex]\frac{g_m_1}{g_m} =\frac{1}{16}[/tex]
⇒ [tex]g_m_1 =g_m(\frac{1}{16})[/tex]
⇒ [tex]g_m_1 =x(\frac{1}{16})[/tex] ...as gm=x at the surface.
So,
We can say that the gravity at a distance of 4R will be reduced to 1/16 th.
Answer: The acceleration due to gravity on the surface of the moon is 1.620 m/s2. 2) The radius of the Earth is 6.38 x 106 m.
Now, remove the positive charge by dragging it back to the basket, and drag one negative charge toward the middle of the screen. Determine how the voltage is different from that of the positive charge. How does the voltage differ from that of the positive charge? The voltage distribution does not change. The voltages become negative instead of positive and keep the same magnitudes. The voltages are positive, but the magnitude increases with increasing distance.
Answer:
The correct option is;
The voltages become negative instead of positive and keep the same magnitudes
Explanation:
Here we have that there is a change in direction from positive to negative with the direction pointing to opposite of the initial direction whereby the field strength does not change due to the reversal of the. Therefore the voltage becomes negative instead of negative while keeping the the magnitude.
That is there is a electric field reversal or a change electric field direction.
A satellite views the earth at an angle of 20°. What is the arc measure
Answer:
The arc measure is 20°.
Answer:160
Explanation:edg
To verify her suspicion that a rock specimen is hollow, a geologist weighs the specimen in air and in water. She finds that the specimen weighs twice as much in air as it does in water. The density of the solid part of the specimen is 5.0×103kg/m35.0×10
3
kg/m
3
. What fraction of the specimen's apparent volume is solid?
Answer:
Fraction of the specimen's is 0.4.
Explanation:
We know,
Mass = volume × density
Weigh= mass × g
= volume × density× g
= density× g × volume
[tex]=\rho.g.V[/tex]
An object weighs less submerged due to buoyant force acting on it.
[tex]\therefore W_{wet}= W_{dry}-B[/tex]
[tex]B= W_{dry}-W_{wet}[/tex]
[tex]=W_{\textrm{fluid displaced}}[/tex]
[tex]=\rho_{fluid}. g.V_{submerged}[/tex]
Given that, the weighs of the specimen in dry is twice of the weighs in air.
[tex]W_{wet}=\frac 12W_{dry}[/tex]
Then ,
[tex]B= W_{dry}-W_{wet}[/tex]
[tex]= W_{dry}-\frac12W_{dry}[/tex]
[tex]=\frac12W_{dry}[/tex]
[tex]=\rho_{Rock}. g.V_{Rock}[/tex]
Therefore,
[tex]\rho_{fluid}. g.V_{submerged}=\frac12\rho_{Rock}. g.V_{Rock}[/tex]
[tex]\Rightarrow \rho_{Rock}. g.V_{Rock}=2\rho_{fluid}. g.V_{submerged}[/tex]
[tex]\Rightarrow \frac{.V_{Rock}}{V_{submerged}}=\frac{2\rho_{fluid}. g}{\rho_{Rock}.g}[/tex]
[tex]\Rightarrow \frac{.V_{Rock}}{V_{submerged}}=\frac{2\rho_{fluid}}{\rho_{Rock}}[/tex]
[tex]\Rightarrow \frac{.V_{Rock}}{V_{submerged}}=\frac{2\times 1.0 \times 10^3\ kg /m^3}{5.0\times 10^3 \ kg/m^3}[/tex]
=0.4
Fraction of the specimen's is 0.4.
How does the eye and brain work together to give you perception of color
Answer:
The human eye and brain together translate light into color. Light receptors within the eye transmit messages to the brain, which produces the familiar sensations of color. ... Rather, the surface of an object reflects some colors and absorbs all the others. We perceive only the reflected colors.
Explanation:
Final answer:
The eye and brain work together to perceive color. Light enters the eye and is detected by cones in the retina, which send signals to the brain. The brain processes these signals and combines information from different cones to create the perception of color.
Explanation:
The eye and brain work together to give you perception of color through a complex process. When light enters the eye, it is detected by special cells called cones in the retina. These cones are sensitive to different wavelengths of light and send signals to the brain. The brain then processes these signals and combines the information from different cones to create the perception of color.
For example, if you see a red object, the red cones in your eye will be activated and send signals to the brain. The brain then interprets these signals as the color red. Similarly, the green cones are activated by green light and the blue cones by blue light. By combining the information from all three types of cones, the brain is able to perceive a wide range of colors.
A setting Sun appears red due to the
a. scattering of lower frequencies by larger particles in the air.
b. light's longer path through the air at sunset.
c. absorption by smaller particles in the air.
d. lower frequencies of light emitted during sunset.
Answer:
a. scattering of lower frequencies by larger particles in the air.
b. light's longer path through the air at sunset.
Explanation:
Sun light has to travel several distances through the earth's atmosphere during Sun set and Sun rise. This light gets scattered by air molecules present and the shorter wave length blue gets upwards and red comes down. That is why the sun light appears red in our eyes.
105. A cable with a linear density of μ=0.2kg/m is hung from telephone poles. The tension in the cable is 500.00 N. The distance between poles is 20 meters. The wind blows across the line, causing the cable resonate. A standing waves pattern is produced that has 4.5 wavelengths between the two poles. The speed of sound at the current temperature T=20°C is 343.00m/s . What are the frequency and wavelength of the hum?
Answer: 11.5 Hz, 29.83 m
Explanation:
Given
Linear density of the cable, μ = 0.2 kg/m
Tensión in the cables, T = 500 N
Wavelength of the wave, = 4.5 Waves
Distance between the poles, L = 20 m
Temperature of, t = 20° C
Speed of sound, v = 343 m/s
λ = length / number of waves =
λ = 20 / 4.5
λ = 4.44 m
Frequency of a standing wave is the same as frequency of a hum. Calculated using the formula
F = n/2L * √(T/μ)
F = 1/λ * √(T/μ)
F = 1/4.44 * √(500/0.2)
F = 0.23 * √2500
F = 0.23 * 50
F = 11.5 Hz
Wavelength of the hum,
λ = v/f
λ = 343 / 11.5
λ = 29.83 m
The wavelength of the hum produced by the cable is approximately 4.44 meters, and the frequency is approximately 11.26 Hz, calculated using the known linear density, tension, and distance between poles.
Explanation:The student is asking about the properties of a standing wave created when the wind blows across a cable hung between two poles. Given the linear density (µ) of 0.2 kg/m, the tension in the cable (500 N), and the distance between poles (20 meters), we are to find the frequency and wavelength of the hum produced by the cable.
Firstly, we can calculate the wavelength (λ) of the wave using the information that 4.5 wavelengths fit between the two poles that are 20 meters apart:
λ = 20 meters / 4.5 wavelengths = 4.44 meters (approx)
Next, we can find the speed (v) of the wave on the cable using the formula:
v = sqrt(T / µ)
Plugging in the given values, we get:
v = sqrt(500 N / 0.2 kg/m) = sqrt(2500 m2/s2)
v = 50 m/s
Now, using the wave speed (v) and the wavelength (λ), we can calculate the frequency (f) of the wave using the formula:
f = v / λ
f = 50 m/s / 4.44 m = 11.26 Hz (approx)
Therefore, the wavelength is approximately 4.44 meters, and the frequency of the hum is approximately 11.26 Hz.
Work is done on a ball when a soccer player kicks it. Is the player still doing work on the ball as it rolls across the ground? Explain
Answer:
Energy is conserved.
Explanation:
According to law of conservation of energy ,energy can neither be created nor be destroyed .
When the player kicks the soccer ball, the kinetic energy is transferred to the ball and it will roll for a while and then stops. The combination of force and distance is called as work.Greater the force faster the ball will go.
The force with which the soccer player player kicked the ball will be having it effects on the ball. As the ball rolls in the ground kinetic energy which the ball got from the player will be lost in the form of heat due to friction.
According to the Newton first law of motion,the object continues to remain in rest or move with constant speed unless acted upon by the external force.
A grinding stone with a mass of 50 kg and a radius of .75 m is rotating with an angular velocity of 30 rev/s. A second, smaller stone with a mass of 20 kg and a radius of .5 m is dropped onto the first without slipping. What is the new angular velocity of the two stones?
Answer:
The new angular velocity of the two stones = 160.064 rad/s
Explanation:
This is a case of conservation of angular momentum.
For initial case:
Mass = 50 kg
Radius = 0.75 m
Angular velocity N = 30 rev/s
We must convert to rad/s w
w = 2¶N = 2 x 3.142 x 30 = 188.52 rad/s
Moment of inertia I = m x r^2
I = 50 x 0.75^2 = 28.125 kgm2
Angular momentum = I x w
= 28.125 x 188.52 = 5302.125 kgm2-rad/s
For second case smaller stone has
m = 20 kg
Radius = 0.5 m
I = m x r^2 = 20 x 0.5^2 = 5 kgm2
Therefore,
Total moment of inertia of new system is
I = 28.125 + 5 = 33.125 kgm2
Final angular momentum = I x Wf
Where Wf = final angular speed of the system.
= 33.125 x Wf = 33.125Wf
Equating the two angular moment, we have,
5302.125 = 33.125Wf
Wf = 5302.125/33.125 = 160.064 rad/s
Answer:
[tex]\dot n = 25.471\,\frac{rev}{s}[/tex]
Explanation:
The situation is described reasonably by the Principle of Angular Conservation:
[tex]\frac{1}{2}\cdot (50\,kg)\cdot (0.75\,m)^{2}\cdot \left(30\,\frac{rev}{s} \right) = \frac{1}{2}\cdot \left[(50\,kg)\cdot (0.75\,m)^{2}+ (20\,kg)\cdot (0.5\,m)^{2} \right] \cdot \dot n[/tex]
The final angular velocity is:
[tex]\dot n = 25.471\,\frac{rev}{s}[/tex]
What imaginary line marks the southern end of the tropical zone
Answer:
The tropic of Capricorn
Explanation:
This line runs 23.5 degrees south of the equator.
The pressure at the bottom of a jug filled with water does not depend on
Coulomb measured the deflection of sphere A when spheres A and B had equal charges and were a distance d apart. He then made the charge on B one-third the charge on A. How far apart would the two spheres then have had to be for A to have had the same deflection that it had before
Answer:
The new separation is [tex]\bf{(d/\sqrt{3})}[/tex].
Explanation:
The expression of the force between two spheres is given by
[tex]F = k\dfrac{q_{A}q_{B}}{d^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)[/tex]
where, [tex]q_{A}[/tex] is the charge on sphere A, [tex]q_{B}[/tex] is the charge on sphere B, [tex]k[/tex] is constant and [tex]d[/tex] i the separation between two spheres.
The new value of charge on sphere B is [tex]q_{B}^{n} = \dfrac{q_{A}}{3}[/tex]. Consider the new separation between the spheres be [tex]d'[/tex]. Under the new configuration the force between the spheres is given by
[tex]F = k \dfrac{q_{A}(q_{A}/3)}{d'^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)[/tex]
Equating equation (1) and equation (2), we have
[tex]~~~~&& \dfrac{1}{d'^{2}} = \dfrac{1}{3d^{2}}\\&or,& d' = \dfrac{d}{\sqrt{3}}[/tex]
So, the new separation is [tex](d/\sqrt{3})[/tex].
A thin uniform rod of mass M and length L is bent at its center so that the two segments are perpendicular to each other. Find its moment of inertia about an axis perpendicular to its plane and passing through the point where the two segments meet.
Answer:
[tex]\frac{1}{12}ML^2[/tex]
Explanation:
The moments of the whole object is the sum of the moments of the 2 segments of rod at their ends of which length is L/2 and mass M/2:
[tex]I = 2I_{end} = 2\frac{1}{3}\frac{M}{2}\left(\frac{L}{2}\right)^2[/tex]
[tex]I = \frac{1}{3}M\frac{L^2}{4}[/tex]
[tex]I = \frac{1}{12}ML^2[/tex]
All particles made of quarks are called _____.
electrons
gluons
hadrons
nucleons
Answer:
All particles made of quarks are called hadrons.
All particles madeup of two or more quarks held together by a force are called ; ( C ) Hadrons
What are Hadrons ?Hadrons are subatomic particles which are made of two or more quarks which are held firmly by a force similar to electric force. An example of Hadron is Baryon which contains three quarks which are held closely together.
Hence we can conclude that All particles made of quarks are called Hadrons
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a company makes garden statues by pouring concrete into a mold. the amount of concrete used to make a statue of a deer weighs 3600 N. if the base of the deer statue is 0.60 meters long and 0.40 meters wide, how much pressure will the statue exert on the ground
Answer:
Pressure exerted by statue = [tex]15 kN/m^{2}[/tex]
Explanation:
Weight of the statue (F)= 3600 N
Area of the base of statue(A) = Length of the base x Width of the base
=0.6 m x 0.4 m =0.24 m
Pressure is defined as force per unit area.
[tex]Hence,\ pressure\ by\ statue= \frac{Force(F)}{Area(A)}=\frac{3600}{0.24} = 15000\ N/m^{2}[/tex]
Pressure exerted by statue = 15000 [tex]N/m^{2} = 15 kN/m^{2}[/tex]
The pressure exerted by the deer statue on the ground is approximately 15000 Pa.
Explanation:Pressure is a measure of the force exerted per unit area. In physics, it is defined as the force acting perpendicular to the surface of an object divided by the area over which the force is applied.
To calculate pressure (P), we use the formula [tex]\(P = \frac{force}{area}\).[/tex] The force exerted by the statue is its weight, which is the gravitational force acting on it, given by [tex]\(F = mg\)[/tex], where (m) is the mass and (g) is the acceleration due to gravity (approximately 9.8 m/s²).
Given the weight of the statue [tex]\(3600 \, N\),[/tex] we find the mass using [tex]\(F = mg\)[/tex], rearranging to [tex]\(m = \frac{F}{g}\)[/tex], which gives [tex]\(m \approx \frac{3600 \, N}{9.8 \, m/s^2} \approx 367.35 \, kg\)[/tex].
Now, we find the area (\(A\)) of the base of the statue:[tex]\(A = \text{length} \times \text{width} = 0.60 \, m \times 0.40 \, m = 0.24 \, m^2\).[/tex]
Finally, we use the pressure formula [tex](P = \frac{F}{A}\): \(P \approx \frac{3600 \, N}{0.24 \, m^2} \approx 15000 \, Pa\).[/tex]
Two wave pulses with equal positive amplitudes pass each other on a string, one is traveling toward the right and the other toward the left. At the point that they occupy the same region of space at the same time
constructive interference occurs
destructive interference occurs.
a standing wave is produced.
a traveling wave is produced.
a wave pulse is produced.
Answer:
Constructive interference occurs
Explanation
This is because at the point they both occupy the same region of space at the same time, there is a superposition of the waves causing them to add up. Since their amplitudes are equal and positive, they are in phase. and thus there is increase the resultant amplitude..This increase in amplitude is due to constructive interference.
Two wave pulses with equal positive amplitudes moving in opposite directions on a string will result in constructive interference where their displacements add up leading to an increased amplitude at the point of overlap. This is a momentary or transient event.
Explanation:When two wave pulses with equal positive amplitudes meet each other on a string, moving in opposite directions, what we experience is constructive interference. This happens because the displacement of the two waves at every point adds up. Essentially, they combine to produce a wave of increased amplitude. In this case, the resultant wave would have an amplitude that's twice that of the individual wave pulses. Please note: this phenomenon happens only at the instant when both waves overlap and not any time before or after that. In other words, it's a transient or temporary phenomenon, not a permanent one, causing a momentary increase in the height of the wave at the point of intersection.
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You find it takes 200 J of heat to take 4 kg of an unknown substance from 200 K to 240 K. It does not change phases during this interval. If you added 300 J of heat to the substance instead of 200 J, what would be its final temperature?
Answer:
300 K
Explanation:
First, we have find the specific heat capacity of the unknown substance.
The heat gained by the substance is given by the formula:
H = m*c*(T2 - T1)
Where m = mass of the substance
c = specific heat capacity
T2 = final temperature
T1 = initial temperature
From the question:
H = 200J
m = 4 kg
T1 = 200K
T2 = 240 K
Therefore:
200 = 4 * c * (240 - 200)
200 = 4 * c * 40
200 = 160 * c
c = 200/160
c = 1.25 J/kgK
The heat capacity of the substance is 1.25 J/kgK.
If 300 J of heat is added, the new heat becomes 500 J.
Hence, we need to find the final temperature, T2, when heat is 500 J.
Using the same formula:
500 = 4 * 1.25 * (T2 - 200)
500 = 5 * (T2 - 200)
100 = T2 - 200
=> T2 = 100 + 200 = 300 K
The new final temperature of the unknown substance is 300K.
Think about multiplying the mass of each student by a factor to calculate each student's kinetic energy. Is there a
common factor that works for every student? If so, what's this factor?
Answer:
Multiplying the mass of any student by a factor of 4.5 gives the kinetic energy of the student.
Explanation:
because
Answer: the question was asked to think about how to multiply a mass speech student by a factor to include the student. Kinetic energy, are there any common factors that appeal to them? The table shows mass energy and constant velocity. Let's calculate a constant factor, multiply it by mass, get the energy and see if we can do it. It's very easy. You can do it just in case. Only kinetic energy divided by mass can be produced. That is, the first is 100 and 21.5 divided by 27. Now you have the next 4.5. This is one. Then it is 162 divided by 36. This is 4.5. January 3, 202
Divide 5 by 45 to get 4.5. And hopefully you can see the patterns that are appearing here. In the fourth one, 243 divided by 54 gives 4.5. The fifth 288 divided by 64. Since it is 4.5, you can guess what it will be like. And finally, in the sixth case, it's 3 to 8.5 divided by 73. This is also equivalent to 4. Well, this common factor 4.5 was found.
What is kinetic energy?Kinetic energy is a form of energy that an object or particle has due to its movement. When work is done on an object by applying a net force that transfers energy, the object accelerates, thereby gaining kinetic energy. In physics, the kinetic energy of an object is the energy that the object has due to its motion.
This is defined as the work required to accelerate an object of a given mass from a stationary state to a specified velocity. After the body gains this energy during acceleration, the body retains this kinetic energy unless the velocity changes.
All moving objects use kinetic energy. Examples of kinetic energy are walkers, thrown baseball, bread crumbs falling from a table, and charged particles in an electric field.
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A small wooden block with mass 0.800 kg is suspended from the lower end of a light cord that is 1.44 m long. The block is initially at rest. A bullet with mass 0.0134 kg is fired at the block with a horizontal velocity v0. The bullet strikes the block and becomes embedded in it. After the collision the combined object swings on the end of the cord. When the block has risen a vertical height of 0.800 m , the tension in the cord is 4.76 N .
What was the initial speed v0 of the bullet?
Answer:
v₀ = 240 m / s
Explanation:
This problem must be solved in two parts, first we must use the conservation of the moment, then the conservation of energy.
Let's start by applying moment conservation, to the system formed by the block and bullet, in this case the forces during the crash are internal and the moment is conserved
Instant starts. Before the crash
p₀ = m v₀
Final moment. Right after the crash
[tex]p_{f}[/tex] = (m + M) v
The moment is preserved
Po =p_{f}
M v₀ = (m + M) v
v = m / (m + M) v₀ (1)
This is the speed with which the bullet block system comes out, now we can use energy conservation
Starting point. Right after the crash
Em₀ = K = ½ (m + M) v²
Final point. Highest point of the path
[tex]Em_{f}[/tex] = U = (m + M) g y
Em₀ = Em_{f}
½ (m + M) v² = (m + M) g y
v = √2 g y (2)
We substitute 1 in 2
m / (m + M) v₀ = √ 2gy
v₀ = (m + M) / m √ 2gy
Let's calculate
v₀ = (0.0134 +0.800) /0.0134 √ (2 9.8 0.8)
v₀ = 240 m / s
Answer:
298.04 m/s
Explanation:
Let m = mass of bullet = 0.0134 kg and M = mass of block = 0.800 kg.
Since the bullet becomes embedded in the block and rises a vertical height,h = 0.800 m
The kinetic energy change of mass + block = potential energy of mass + block at height, h
ΔK = -ΔU
So, 1/2(m + M)(v² - V²) = -[(m + M)gh - 0] where v is the velocity of the bullet + block at height, h. Since the tension, T is the centripetal force at height, h, it follows that
T = (m + M)v²/r r = length of cord = 1.44 m
v = √(Tr/(m + M)) = √4.76 N × 1.44 m/(0.800 + 0.0134)kg = √(6.8544/0.8134) = √8.427 = 2.9 m/s
So. 1/2(v² - V²) = -gh
v² - V² = -2gh
V = √(v² + 2gh) = √((2.9 m/s)² + 2 × 9.8 m/s² × 0.8 m) = √(8.41 + 15.68) = √24.09 = 4.91 m/s
This is the velocity of the bullet plus block at collision.
From the law of conservation of momentum,
momentum of bullet = momentum of bullet plus block
mv₀ = (m + M)V where v₀ = initial speed of bullet
v₀ = (m +M)V/m = (0.0134 kg + 0.800 kg)4.91 m/s ÷ 0.0134 kg = 3.994 ÷ 0.0134 kg = 298.04 m/s
1. The current through a light bulb connected across the terminals of a 120 V outlet is 0.50 A. At what rate does the bulb convert electric energy to light? 2. A 12.0 V battery causes a current of 2.0 A to flow through a lamp. What is the power used by the lamp? 3. What current flows through a 100. W light bulb connected to a 120. V outlet? 4. The current through a motor is 210 A. If a battery keeps a 12.0 V potential difference across the motor, what electric energy is delivered to the motor in 10.0 s?
Answer:
1. 60 W
2. 24 W
3. 0.83 A
4. 25200 J
Explanation:
1. What we are simply asked to look for is Electrical Power. It is the rate electrical energy is being transferred.
It is given as:
[tex]P = IV[/tex]
where I = current and V = voltage.
Therefore, Power is:
P = 0.50 * 120 = 60 W
2. Power, as given in the formula above is:
P = 2.0 * 12
P = 24.0 W
3. According to the formula of Power, current is given as:
[tex]I[/tex] = [tex]\frac{P}{V}[/tex]
Power is 100 W and voltage is 120 V, therefore, current is:
[tex]I = \frac{100}{120} \\\\\\I = 0.83 A[/tex]
4. Recall that power is the time rate of transfer of electrical energy. Mathematically:
[tex]P = \frac{E}{t}[/tex]
where t = time
This means that Electrical energy is:
[tex]E = Pt[/tex]
Recall that Power is:
[tex]P = IV[/tex]
Therefore, Electrical energy is:
[tex]E = IVt[/tex]
[tex]E = 210 * 12 * 10\\\\\\E = 25200 J[/tex]
1. At "60 W" the bulb convert electric energy to light
2. Power used by lamp will be "24.0 W".
3. The current flow will be "0.83 A".
4. The electric energy delivered to the motor will be "25200 J".
Potential difference and CurrentAccording to the question,
1. Current, I = 0.50 A
Voltage, V = 120 V
We know,
→ Power (P) = Current (I) × Voltage (V)
= 0.50 × 120
= 60 W
2. Current, I = 2.0 A
Voltage, V = 12.0 V
then,
→ P = 2.0 × 12
= 24.0 W
3. Power, P = 100 W
Voltage, V = 120 V
We know,
→ Current, I = [tex]\frac{P}{V}[/tex]
= [tex]\frac{100}{120}[/tex]
= 0.83 A
4. Current, I = 210 A
Potential difference, V = 12.0
We know,
→ E = Pt
P = IV
or,
The electrical energy be:
→ E = IVt
= 210 × 12 × 10
= 25200 J
Thus the above answer is correct.
Find out more information about power here:
https://brainly.com/question/14306881
Move the Earth so it is one box from the Sun. (Note: one box side equals about 46,000,000 miles.) Do not change the length of the velocity vector. Predict what will happen to the Earth and Sun when you hit Play?
Answer:
When we change the distance, the universal attraction force increases, so that the system is free to reach a new equilibrium, the linear speed of the earth must rise to the calculated value.
v = √ (G M / r)
Explanation:
For this exercise it is asked that if you maintain the linear speed of the Earth and bring it closer to the sun that would pass.
We pass the distance from Ro = 1.49 10¹¹ m to r = 0.736 10¹¹ m shortens, we write Newton's second law
F = m a
where the force is the universal force of attraction
F = G mM / r²
acceleration is central
a = v² / r
G m M / r² = m v² / r
v = √ (G M / r)
When we change the distance, the universal attraction force increases, so that the system is free to reach a new equilibrium, the linear speed of the earth must rise to the calculated value.
We can compare this value with that of the normal orbit
v₀ = √ (GM / R₀)
v / v₀ =√ (Ro / r)
v² r = v₀² R₀
either of these two expressions gives the relations gives the change in velocity with the radius of the orbit
A charged particle is surrounded by an electric field and a magnetic field
Answer:
yeah
Explanation:
electric fields help the charged particles interact
and isn't magnetic field the same as electric field.
A diagnostic sonogram produces a picture of internal organs by passing ultrasound through the tissue. In one application, it is used to fid the size, location, and shape of the prostate in preparation for surgery or other treatment. The speed of sound in the prostate is 1540 m/s, and a diagnostic sonogram uses ultrasound of frequency 1.40 MHz. The density of the prostate is 1060 kg/m3.1) What is the wavelength of the sonogram ultrasound? 2)What is Youngâs modulus for the prostate gland?
Answer:
a) 1.1mm
b) 2.513kg/ms^2
Explanation:
You can use the formula for the calculation of the wavelength of a wave
f=1.40MHz=1.40*10^{6}Hz
1 )
[tex]\lambda=\frac{v}{f}=\frac{1540m/s}{1.40*10^{6}Hz}=1.1*10^{-3}m=1.1mm[/tex]
2)
The Young modulus can be computed by using the expression:
[tex]v=\sqrt{\frac{Y}{\rho}}\\\\Y=v^2\rho[/tex]
where Y is the Young modulus and p is the density of the material. Here, you have considered that the prostate gland can be taken as a vibrating membrane or string.
By replacing you obtain:
[tex]Y=(1540m/s)^2(1060kg/m^3)=2.513*10^9kg/ms^2[/tex]
hence, the Young modulus of the prostate glande is 2.513kg/ms^2
Answer:
1) 1.1 x [tex]10^{-3}[/tex] m
2)2.51 x[tex]10^{9}[/tex]Pa
Explanation:
Given:
Speed of sound in prostate 'V'= 1540m/s
frequency 'f' = 1.40 MHz = 1.40 x [tex]10^{6}[/tex]Hz
density of prostate'ρ' = 1060 kg/m3
1) As we know that the relationship of the speed of sound, its frequency, and wavelength is the same as for all waves
V= fλ
λ= V/f => 1540/1.40 x [tex]10^{6}[/tex]
λ= 1.1 x [tex]10^{-3}[/tex] m
Thus, the wavelength of the sonogram ultrasound is 1.1 x [tex]10^{-3}[/tex] m
2)The speed of sound in a solid the depends on the Young's modulus of the medium and the density
V=√Y/ρ.
V² = Y/ρ
Y= V² x ρ=> 1540² x 1060
Y= 2.51 x[tex]10^{9}[/tex]Pa
Thus, Young's modulus for the prostate gland is 2.51 x[tex]10^{9}[/tex]Pa
If a truck driver is driving at 30 mph and she makes a U-turn then starts driving 30 mph in the opposite direction did the driver speed or velocity change after changing direction
The final velocity of the truck driver does not change after making a U-turn and driving in the opposite direction.
Explanation:The final velocity of the truck driver does not change after making a U-turn and driving in the opposite direction. While the truck's speed changes, the velocity remains the same because velocity takes into account both the speed and direction of motion. Since the speed remains constant at 30 mph and the direction changes, the velocity is still 30 mph, just in the opposite direction.
Which of the following statements is FALSE?
a. After the Galveston Hurricane of 1900 the city built a 17-foot sea wall to protect Galveston from
future hurricanes.
b. One of the most devastating natural disasters to strike Texas was the Galveston Hurricane of
1900.
C. After the humcane of 1900, the city of Galveston removed 8 feet of soil to lower its elevation and
protect it from future hurricanes.
d. The rebuilding of Galveston after the hurricane of 1900 prompted the state to reorganize city
governments.
Answer:
C after the hurricane of 1900s
Explanation:
They didn’t remove 8 feet of soil they put 8 feet of soil
Un móvil, que sale desde un punto situado 3 metros a la izquierda del origen y lleva un movimiento uniforme, se sitúa a 12 metros a la derecha del origen al cabo de 3 segundos. Tras esto invierte el sentido del movimiento, empleando 4 segundos más en llegar al origen. Realiza una gráfica que represente el movimiento descrito. Obtén el desplazamiento en cada tramo. (Sol: 15 m; −12 m) Determina la distancia total recorrida por el móvil. (Sol: 27 m) Determina la velocidad del móvil en cada tramo. (Sol: 5 m/s; −3 m/s) Representa gráficamente la velocidad del móvil frente al tiempo.
Answer:
x₁ = 15 m, x₂ = 12 m , x_total = 27m, v₁ = 5 m / s , v₂ = - 3 m / s
Explanation:
In this exercise we will use the kinematics of uniform motion
v = d / t
let's apply this equation for the first move
v₁ = Δx / t = (x₂-x₀) / t
v₁ = (12- (-3)) / 3
v₁ = 5 m / s
the distance traveled is x₁ = 15 m
Now let's analyze the return movement
v₂ = Δx / dt
v₂ = (0 - 12) / 4
v₂ = - 3 m / s
The negative sign indicates that the vehicle is moving to the left
the distance traveled is x₂ = 12 m
The total dystonia is
x_total = x₁ + x₂
x_total = 15 +12
x_total = 27m
In the attached we have the graphics of the movement