Answer:A.
only when a nonzero net force is applied to the object.
Explanation:
Answer:
he is right its A
Explanation:
What is the molality of a solution that contains 54 grams of NaOH dissolved in 1.50 kg of water? (The molar mass of NaOH 40.00 grams/moles.)
Answer:
0.900 mol/kg
Explanation:
Molality is moles of solute per kilograms of solvent.
Converting 54 grams of NaOH to moles:
54 g NaOH × (1 mol NaOH / 40.00 g NaOH) = 1.35 mol NaOH
So the molality is:
m = (1.35 mol) / (1.50 kg)
m = 0.900 mol/kg
Convert grams of NaOH to moles:
The formula to convert grams to moles is:[tex]\text{moles of NaOH} = \frac{\text{mass of NaOH (g)}}{\text{molar mass of NaOH (g/mol)}}[/tex]
Given that the mass of NaOH is 54 grams and its molar mass is 40.00 g/mol:
[tex]\text{moles of NaOH} = \frac{54 \text{ g}}{40.00 \text{ g/mol}} = 1.35 \text{ moles}[/tex]
Determine the mass of the solvent (water):
The mass of water is given as 1.50 kg.
Convert this mass into kilograms (if necessary):
Since 1.50 kg is already in the correct unit, no conversion is needed here.
Calculate molality (m):
The formula for molality is:
[tex]\text{molality (m)} = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}}[/tex]
Substitute the values into the formula:
[tex]\text{molality} = \frac{1.35 \text{ moles}}{1.50 \text{ kg}} = 0.90 \text{ m}[/tex]
What chemical phenomenon accounts for the elasticity seen in solids?
covalent bonds
hydrogen bonds
ionic bonds
all of the above
The elasticity in solids is primarily due to covalent bonds. These bonds allow atoms to move slightly and then return to their original positions. Other types of bonds such as ionic and hydrogen can also contribute, but typically covalent bonds are the main factor.
Explanation:The chemical phenomenon that accounts for the elasticity seen in solids is primarily due to covalent bonds.
These bonds hold the atoms together in the solid and allow them to move slightly and then return to their original positions. Other bonds like ionic and hydrogen bonds can also contribute to some extent, but typically, covalent bonds play the largest role. If a force is applied to a solid, it can stretch or deform, but it will return to its original shape when the force is removed because of the elasticity provided by these bonds.
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Twenty is the _________________ of potassium.
A) charge
B) atomic mass
C) atomic number
D) number of neutrons
Answer:
I think it's D) Guess why? I searched it up!
Organized elements into four groups based on properties
Answer:
Lavoisier
Explanation:
If the mass of a person is 600kg on Earth what is the persons mass on the moon
Answer:
The mass of the person would remain 600kg.
Explanation:
mass refers to the amount of matter in a particular object. therefore even though the moon has less gravitational force than the Earths, it still would have the same mass since the person is made up of the same amount of matter on Earth and in the moon.
when asked about weight, it would be 1000N. but in mass , same 600kg.
I NEED ANSWER ASAP
A block of ice has the density of 0.97 g/cm3 . How much of it will sink below the surface of the water?
About 97 percent of the ice will sink below water.
All—100 percent—of the ice will sink below water.
About 3 percent of the ice will sink below water.
None—0 percent—of the ice will sink below the water.
Answer:
97% will sink below the water
Explanation:
Waters density is 1 g/cm3
If an object's density is greater than 1g/cm3, it will sink. If it's less then it would float. 1-0.97 = 0.03. Only 3% of the ice would show while 97 will be under.
Answer:
About 97 percent of the ice will sink below water.
Explanation:
Let the volume that is submerged into the water is given as V1
so at equilibrium condition we can say that buoyancy force on it is balanced by weight of the block
so we have
[tex]\pho_{water} V_1 g = \rho_{ice} V g[/tex]
now we have
[tex]\frac{V_1}{V} = \frac{\rho_{ice}}{\rho_{water}}[/tex]
[tex]\frac{V_1}{V} = \frac{0.97}{1}[/tex]
so the percentage of block that is submerged into the water is given as
volume percent submerged = 97 %
Would earth orbiting the sun be known as
A. Newton’s First Law of Motion
B. Newton’s Second Law of Motion
C. Newton’s Third Law of Motion
All three of Newton's laws of motion, as well as his law of universal gravity, are involved in the explanation of orbits.
How does the energy of a system change during a phase change?
Answer:
They are changes in bonding energy between the molecules. If heat is coming into a substance during a phase change, then this energy is used to break the bonds between the molecules of the substance. ... At the moment of melting the average kinetic energy of the molecules does not change.
Explanation:
(please help ;-;) Which of the following statements about the water cycle is true?
Organisms in the biosphere do not influence the water cycle.
The water cycle only continues during daylight hours.
Plants play a vital role in the water cycle.
Precipitation that falls to the ground ends up only as groundwater.
Answer:
I guess that the answer is plants play a vital role In the water cycle.
Answer:
Plants play a vital role in the water cycle.
Explanation:
Vegetation plays an important role in the water cycle by preventing soil erosion and increasing groundwater levels. In areas with thick vegetation cover, the foliage cover breaks the force of precipitation falling on the ground, which may otherwise cause erosion.
The time required for one cycle, a complete motion that returns to its starting point, is called the _____.
Answer:
period
Explanation:
Answer:
The time required for one cycle, a complete motion that returns to its starting point, is called the period .
Explanation:
Any motion that repeats at regular time intervals is called periodic motion. This kind a motion has some characteristics like the period. Other important characteristic is the frequency, which is the number of complete cycles in a given time, that is, the inverse of the period.
A rider on a water slide goes through three different kinds of motion, as illustrated in the figure below. Use the data and the details from the figure to answer the following questions. Remember, when an object is in a circular motion it is accelerated toward the center of the circle with acceleration a = v2/r
a) At the end of the first section of the motion, riders are moving at approximately what speed? Show your work for partial credit.
A. 3 m/s B. 6 m/s C. 9 m/s D. 12 m/s
b) Suppose the acceleration during the second section of the motion is too large to be comfortable for the riders. What change could be made to decrease the acceleration during this section?
A. Reduce the radius of the circular segment
B. Increase the radius of the circular segment
C. Increase the angle of the ramp.
D. Increase the length f the ramp.
c) What is the vertical component of the velocity of the rider as he hits the water? Show your work for partial credit.
A. 2.4 m/s B. 3.4 m/s C. 5.2 m/s D. 9.1 m/s
d) Suppose the designers of the water slide want to adjust the height h above the water so that the riders land twice as far away from the bottom of the slide. What would be the necessary height above the water? Show your work for partial credit.
A. 1.2 m B. 1.8 m C. 2.4 m D. 3.0 m
e) During which section of the motion is the magnitude of the acceleration experienced by the rider the greatest?
A. The first B. The second C. The third D. It is the same in all sections
a) C. 9 m/s
First of all, let's calculate the difference in height between the starting point of the motion and the end point of the first section. It is given by:
[tex]\Delta h = L sin \theta[/tex]
where
L = 6.0 m
[tex]\theta=45^{\circ}[/tex]
Substituting,
[tex]\Delta h = (6.0)(sin 45^{\circ})=4.2 m[/tex]
Assuming the rider starts from rest, its initial speed is zero. For the law of conservation of energy, the decrease in gravitational potential energy of the rider will be equal to its gain in kinetic energy, so we can write:
[tex]mg\Delta h = \frac{1}{2}mv^2[/tex]
where m is the rider's mass, g = 9.8 m/s^2 is the acceleration of gravity, and v is the speed at the end of the first section. Solving for v, we find:
[tex]v=\sqrt{2g\Delta h}=\sqrt{2(9.8)(4.2)}=9.1 m/s \sim 9 m/s[/tex]
b) B. Increase the radius of the circular segment
In fact, the acceleration during the second section of the motion (circular motion) is given by the formula for the centripetal acceleration:
[tex]a=\frac{v^2}{r}[/tex]
where
v is the speed at the end of the first section
r is the radius of the circle
We notice that the acceleration is
- Proportional to the square of the speed
- Inversely proportional to the radius
So, we immediately see that if we increase the radius of the circle (choice B), the acceleration will decrease.
c) B. 3.4 m/s
When the rider exits the second section of the motion, he has a speed (completely horizontal) of 9.1 m/s (calculated in part (a); it didn't change, because the speed during the second section does not change).
The vertical component of his velocity is instead zero, since his motion is completely horizontal. Therefore, we can use the following SUVAT equation along the vertical direction:
[tex]v_y^2 - u_y^2 = 2g\Delta h[/tex]
where
[tex]v_y[/tex] is the vertical component of the velocity as the rider hits the water
[tex]u_y=0[/tex] is the vertical component of the velocity as the rider starts the 3rd section
[tex]\Delta h = 0.60 m[/tex] is the difference in height
Solving for [tex]v_y[/tex],
[tex]v_y = \sqrt{2g\Delta h}=\sqrt{2(9.8)(0.60)}=3.4 m/s[/tex]
d) C. 2.4 m
We want here the rider to land twice as far compared to before.
The horizontal distance travelled by the rider in section 3 is entirely determined by his horizontal motion. The horizontal component of the velocity, which is constant, is
[tex]v_x = 9.1 m/s[/tex]
calculated at part (a) and remained unchanged during section 2. The horizontal distance travelled during section 3 is
[tex]d=v_x t[/tex] (1)
where t is the time of the fall. This can be rewritten as
[tex]t=\frac{d}{v_x}[/tex]
We also know that the vertical displacement is:
[tex]h=\frac{1}{2}gt^2[/tex]
Substituting t from (1) into this equation, we find
[tex]h=\frac{gd^2}{2v_x^2}[/tex]
So we see that the height needed is proportional to the square of the distance: [tex]h \propto d^2[/tex]. Therefore, in order to land at twice the previous distance, the height must be 4 times the previous one, so:
[tex]h=4 (0.6 m)=2.4 m[/tex]
e) B. The second
We need to calculate the acceleration in each section.
In section 1 (motion along the slope), it is:
[tex]a=g sin \theta = (9.8)(sin 45^{\circ})=6.9 m/s^2[/tex]
In section 2 (circular motion), the acceleration is the centripetal acceleration:
[tex]a=\frac{v^2}{r}=\frac{9.1^2}{1.5}=55.2 m/s^2[/tex]
In section 3, the motion is free fall, so the acceleration is equal to the acceleration of gravity:
[tex]a=g=9.8 m/s^2[/tex]
Therefore, the rider experiences the largest acceleration in section 2.
This answer explains how to calculate the speed, acceleration, and vertical component of velocity for a rider on a water slide, as well as how to adjust the height to change the landing distance and determine the section with the greatest acceleration.
Explanation:To answer these questions about the rider on the water slide, we need to use the formula for acceleration in circular motion, which is a = v2/r. For question a, we can use the given information to calculate the speed at the end of the first section of motion. For question b, reducing the radius of the circular segment would decrease the acceleration during the second section. For question c, we need to calculate the vertical component of the rider's velocity as he hits the water. For question d, we can use the concept of projectile motion to determine the necessary height above the water to land twice as far away. Finally, for question e, we need to determine during which section of the motion the magnitude of the acceleration experienced by the rider is the greatest.
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All of the following would be useful in trying to obtain procedural information to replicate an experiment previously published except for a lab journal used in the original experiment. a published scientific journal. a dictionary. a peer-reviewed article
Answer:
I am pretty sure that the answer would be a peer reviewed article.
Explanation:
I saw this because, an encyclopedia, published scientific journal, and a lab journal used in the original experiment, are all reliable sources of information.
Answer:
A dictionary
Explanation:
did the quiz
3. If a car accelerates from rest at a constant 5.5 m/s, how long will it take for the car to reach a
velocity of 28 m/s?
Answer: 2.54 s
Explanation:
If we are talking about a constant acceleration, we can use the following equation:
[tex]V_{f}=V_{o}+2at[/tex]
Where:
[tex]V_{f}=28 m/s[/tex] is the final velocity of the car
[tex]V_{o}=0t[/tex] is the finitial velocity of the car (it started from rest)
[tex]a=5.5 m/s^{2}[/tex] is the constant acceleration of the car
[tex]t[/tex] is the time it takes to reach [tex]V_{f}[/tex] with the given constant velocity
Hence:
[tex]V_{f}=2at[/tex]
Clearing [tex]t[/tex]:
[tex]t=\frac{V_{f}}{2a}[/tex]
[tex]t=\frac{28 m/s}{2a(5.5 m/s^{2})}[/tex]
Finally:
[tex]t=2.54 s[/tex]
Final answer:
It takes approximately 5.09 seconds for the car to accelerate from rest to a velocity of 28 m/s with a constant acceleration of 5.5 m/s².
Explanation:
To determine the time it takes for a car to reach a certain velocity with a given acceleration from rest, we use the kinematic equation:
final velocity (v) = initial velocity (u) + acceleration (a) × time (t)
Given that the car starts from rest, the initial velocity u is 0 m/s. We are told the car accelerates at a constant rate of 5.5 m/s2 and we want to find the time when the car reaches a velocity of 28 m/s. Plugging in the values we have:
28 m/s = 0 m/s + (5.5 m/s2) × t
Solving for t, we get:
t = 28 m/s / 5.5 m/s2
t = 5.09 seconds (approximately).
So, it takes approximately 5.09 seconds for the car to accelerate from rest to 28 m/s at a constant acceleration of 5.5 m/s2.
ad for the distance from the sun tothe earth is 1.5 x 10"m. how long does it take for light from ths sun to reach the eath? give your answer n seconds
Answer:
About 8.3 minutes
Explanation:
Use the formula for velocity as the distance covered by the light divided the time it takes: [tex][tex]velocity=\frac{distance}{time}[/tex][/tex]
Use the information about the speed of light in vacuum: [tex]300000000 \frac{m}{s} = 3*10^{8} \frac{m}{s}[/tex]
and the information you are given regarding the distance between Sun and Earth: [tex]1.5 * 10^{11} m[/tex]
to solve the first velocity equation for the unknown time "t":
[tex]velocity=\frac{distance}{time} \\3*10^8\frac{m}{s} =\frac{1.5*10^11 m}{t} \\t=\frac{1.5*10^11 }{3*10^8} s= 500 s[/tex]
we can convert second into minutes by dividing by 60: 500 s = 500/60 minutes = 8.3333... minutes
What is most likely true of an atom with a mass of 15 amu?
A) There are 15 protons.
B)There are 15 electrons.
C)The total number of protons and electrons is 15.
D)The total number of protons and neutrons is 15.
The answer is D: The total number of protons and neutrons is 15.
The atomic mass of an atom is the total mass of its protons and neutrons. Protons have a mass of 1 amu, and neutrons have a mass of 1 amu. Therefore, if an atom has an atomic mass of 15 amu, then it must have 15 protons and 15 neutrons.
A: There are 15 protons. This is not necessarily true. The atomic number of an atom is the number of protons in its nucleus. The atomic number of an atom with an atomic mass of 15 could be 7 (nitrogen), 8 (oxygen), or 9 (fluorine).
B: There are 15 electrons. This is not necessarily true. The number of electrons in an atom is equal to the number of protons in the atom's nucleus. However, the electrons can be arranged in different energy levels, so the number of electrons in the outermost energy level may not be equal to the number of protons.
C: The total number of protons and electrons is 15. This is not necessarily true. The number of protons in an atom is always equal to the number of electrons in the atom. However, the number of electrons in the outermost energy level may not be equal to the number of protons.
D: The total number of protons and neutrons is 15. This is always true. The atomic mass of an atom is the total mass of its protons and neutrons. Therefore, if an atom has an atomic mass of 15 amu, then it must have 15 protons and 15 neutrons.
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Kim travelled at a speed if 18km/h for two hours. What was the distance covered?
Answer:
36 km
Explanation:
Answer:
36
Explanation:
During a baseball game, a batter hits a high
pop-up.
If the ball remains in the air for 6.37 s, how
high does it rise? The acceleration of gravity
is 9.8 m/s2.
Answer:
50.0 m
Explanation:
First of all, we can find the initial velocity of the ball, using the equation
v = u + at
where
v = 0 is the velocity of the ball at the highest position
u is the initial velocity
[tex]a=g=-9.8 m/s^2[/tex] is the acceleration of gravity
[tex]t=\frac{6.37}{2}=3.19 s[/tex] is the time the ball took to reach the maximum height (half of the time it remained in the air)
Solving for u,
[tex]u=v-at=0-(-9.8)(3.19)=31.3 m/s[/tex]
Now we can find the maximum height using the other SUVAT equation:
[tex]v^2-u^2 = 2ad[/tex]
where d is the maximum height. Solving for d,
[tex]d=\frac{v^2-u^2}{2a}=\frac{0^2-(31.3)^2}{2(-9.8)}=50.0 m[/tex]
Although the temperature gradient changes from region to region in the homosphere, there is one gradient that stays the same. it continues to decrease as you increase in altitude, no matter where you are in the homospere. what gradient?
Answer: the answer is air gradient
Explanation:
How does increasing the speed of a motorbike change the amount of energy in its kinetic energy store?
Answer:
Kinetic energy is energy in motion so therefor if you increase the velocity or in your case speed the kinetic energy also has to increase
Explanation:
Answer:
If the speed of a motorbike increases, its kinetic energy will also increase.
Explanation:
Kinetic energy is the energy an object has due to its motion, and it is a function of the mass and velocity of the object:
[tex]E_{k}=\frac{m*v^{2}}{2}[/tex]
From the expression, it is easy do identify a quadratic relation between kinetic energy and velocity. Therefore, if the speed of a motorbike increases, its kinetic energy will also increase.
For example, if you increase the speed of a motorbike by 10 times, and since mass is a constant value, the kinetic energy will increase by 100 times.
Radium has a half-life of 1,660 years. Calculate the number of years until only 1/16th of a sample remains.
years
Radium has a half-life of 1,660 years.The number of years until only 1/16th of a sample remains is 6641 years.
Answer: 6641 years
Explanation:
Given that the half-life of Radium is 1660 years. The number of years to be calculated when the sample of radium could just be remained of 1/16th of its part, which can be calculated by the following means,
Half life, [tex]T_{1 / 2}=1660 \text { years }[/tex]
[tex]\frac{N}{N_{0}}=\frac{1}{16}[/tex]
t is the taken time, then,
[tex]\frac{N}{N_{0}}=e^{-\lambda t}[/tex]
[tex]\frac{N}{N_{0}}=e^{\lambda t}[/tex]
Taking ln on both sides, we get,
[tex]\lambda t=\ln \left(\frac{N}{N_{0}}\right)[/tex]
[tex]t=\frac{1}{\lambda} \ln \left(\frac{N_{0}}{N}\right)[/tex]
[tex]=\frac{T_{1 / 2}}{0.693}\left(\ln \left(\frac{N_{0}}{N}\right)\right)[/tex]
By substituting the given values,
[tex]t = \frac{1660}{0.693}(\ln 16)[/tex]
Therefore, t = 6641 years
Once you have completed a personal strategy card for an assignment, you should __________.
Answer:
keep it and use it in similar assignments
Explanation:
A personal strategy card is a form of student assessment where teachers can look at the learning process of the student and get a feedback on the next learning step to be taken by the student.
The card can a sections are;
what the topics covered and the challenges faced. Identifying the connection created from current and previous topics.The student will note down his/her experience in the topic.Re-organizing the information in topic.Writing a personal journal on all the steps covered.This information is important because it can be used as a study guide on other similar assignments .
Which scientist first proposed physical laws to mathematically describe the effect of forces on the motions of bodies?
Answer:
Issac Newton!
Explanation:
Hope this helps.
Answer: Isaac Newton
Explanation:
Isaac NewtonThe three laws of motion were first compiled by Isaac Newton in his Philosophiæ Naturalis Principia Mathematica (Mathematical Principles of Natural Philosophy), first published in 1687. Newtonused them to explain and investigate the motion of many physical objects and systems.Feb 21, 2017
Which option determines gravitational pull?
A. Acceleration
B. The sun
C. Volume
D. Mass
The correct option that determines gravitational pull is mass. Gravitational force is calculated using the masses of objects and the gravitational constant, with the formula F = mg close to the Earth's surface.
Gravitational pull and Influencing Factors
The option that determines gravitational pull is mass. According to Newton's Law of Gravity, anything that has mass attracts everything else that has mass. The gravitational force (F) between two objects can be determined by the equation F = G(M1M2)/r^2, where G is the gravitational constant, M1 and M2 are the masses of the objects, and r is the distance between the centers of the two objects. The force of gravity on an object near the Earth's surface is calculated as the mass of the object (m) multiplied by the acceleration due to gravity (g), which is F = mg.
Volume does not directly determine gravitational pull; rather, it is the total quantity of matter, or mass, within that volume that contributes to gravity. The acceleration due to gravity remains constant (g = 9.81 m/s^2 near the Earth's surface) regardless of the object's mass. While the force of gravity is relatively weak, it is sufficient to keep the planets in orbit around the sun, as demonstrated in Newton's Universal Law of Gravitation.
What are balanced forces?
Answer:
Balance forces are two forces acting in opposite directions on an object, and equal in size. Anytime there is a balanced force on an object, the object stays still or continues moving continues to move at the same speed and in the same direction.
Explanation:
pls thank me
Answer:
Balance forces are two forces acting in opposite directions on an object, and equal in size.
define average velocity and instantaneous velocity when are they same
Answer:
Look to the explanation
Explanation:
Average velocity: is the average rate of change of displacement with
respect to time
Average velocity is a measure for distance traveled in a given time
We can calculate the average velocity by the rule [tex]v=\frac{s}{t}[/tex]
where s is the displacement and t is the time
Instantaneous velocity: is the velocity of an object in motion at a
specific point (x , t)
instantaneous velocity is the limit of velocity as the change in time
approaches zero
We can calculate the instantaneous velocity by the rule [tex]v=\frac{ds}{dt}[/tex]
Average velocity is equal to the instantaneous velocity when
acceleration is zero
Which word identifies a large natural or human-made lake used to supply water?
marsh
pond
reservoir
wetland
Answer:
reservoir. C
Explanation:
Just took the test on edge 2020
A large natural or human-made lake used to supply water is a reservoir.
What is a reservoir?A reservoir is a large area of land or even a container where things especially water is stored for future use.
A reservoir of water can be natural or man-made.
It is usually found underground or on the surface.
Therefore, a large natural or human-made lake used to supply water is a reservoir.
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If Joey ran 60 meters in 10 seconds, then his velocity is ________ m/s.
Answer:
6
Explanation:
write a one or two summary paragraph discussing this experiment and the results use tye following questions 1 according to your data was your hypothisis correct be sure to refer your data when answering this question 2 summarize ang difficulties or probloms you had in performing the experiment thaf might have affected the results list at least two real world examples that apply the findings for this experiment
The experiment confirmed the initial hypothesis, supported by specific data points. Some difficulties encountered during the process could have affected the results. The findings of the experiment align with two real-world examples.
Explanation:In the experiment we conducted, we intended to test a specific hypothesis. After careful analysis of the obtained data, the results did indicate that our hypothesis was indeed correct. Observations and specific data points derived from the experiment including (insert statistical or observational evidence) clearly supports this conclusion.
The experiment was not without difficulties. Some of the issues encountered include (insert specific problems or difficulties), which might have affected some of our findings. Two real-world applications of our findings would be (insert example one) and (insert example two). These applications provide practical illustrations on why these findings contribute relevant information to our broader understanding the subject matter.
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2016 Physics A-CR
In which situations is elastic potential energy present? Check all that apply.
A bow is drawn back from its equilibrium position.
An arrow rests on a bow.
O A spring toy dart gun is unloaded.
A spring toy dart gun is loaded with a dart.
A bungee cord is connected to a tall tower.
A bungee cord is stretched with a person at the end.
Answer:
A bow is drawn back from its equilibrium position.
A spring toy dart gun is loaded with a dart.
A bungee cord is stretched with a person at the end.
Explanation:
All of these examples have to do with the elastic object being stretched but not in motion, therefore they have stored energy, or potential energy.
Answer:
A bow is drawn back from its equilibrium position.
A spring toy dart gun is loaded with a dart.
A bungee cord is connected to a tall tower.
A bungee cord is stretched with a person at the end.
Explanation:
Potential energy is defined as the energy a material posesses by it viture of position. elastic potential potential energy is a special case of potential energy which is defined as the potential energy that is stored in material that are elastic. Elastic is connected with stretching and so looking at the options , option 2 and 4 are out of the lists
what happens to your behind when you sit for too long?
Sitting for long hours without any interruption may cause painful neck, swayed back in the long run and sometimes disc damage.
Explanation:
Human bodies are designed to stand upright. Cardiovascular and bowel functions work effectively in that way. Sitting too long may weaken and deplete large leg and gluteal muscles which are significant in walking and stabilizing the body.
It also causes stress and reduced social skills. It can also lead to serious health hazards such as cardiovascular complications, diabetes, imbalances in spinal structure. To avoid all these exercises, yoga, stretching regularly is mandatory.