Answer: [tex]\dfrac{1}{3}[/tex]
Step-by-step explanation:
Given : An opaque bag contains 5 green marbles, 3 blue marbles and 2 red marbles.
Total marbles = 5+3+2=10
Now, if it given that the a red marble is already drawn, then the total marbles left in the bag = 10-1=9
But the number of blue marbles remains the same.
Now, the probability of drawing a blue marble given the first marble was red :-
[tex]=\dfrac{\text{Number of blue marbles}}{\text{Total marbles left}}\\\\=\dfrac{3}{9}=\dfrac{1}{3}[/tex]
Hence, the required probability = [tex]\dfrac{1}{3}[/tex]
Three married couples have purchased theater tickets and are seated in a row consisting of just six seats. If they take their seats in a completely random fashion (random order), what is the probability that Jim and Paula (husband and wife) sit in the two seats on the far left?
Answer:
The required probability is : [tex]\frac{1}{15}[/tex]
Step-by-step explanation:
Three married couples have purchased theater tickets and are seated in a row consisting of just six seats.
First we will check the total arrangements that is 6! ways.
6! = [tex]6\times5\times4\times3\times2\times1=720[/tex]
Jim and Paula can sit at far left in 2 ways and the remaining 4 in 4! ways,.
So, probability will be = [tex]2\times\frac{4!}{6!}[/tex]
= [tex]2\times\frac{24}{720}[/tex]
= [tex]\frac{48}{720}[/tex]
= [tex]\frac{1}{15}[/tex]
How would I find r?
Answer:
r = 29
Step-by-step explanation:
We assume your diagram is showing ...
CD = CB = rAB = x = 29To find r, use the relationship between the side lengths of the triangle.
__
In a 30°-60°-90° triangle, the ratio of shortest to longest sides is 1 : 2. Therefore, we have ...
CD/CA = r/(r+29) = 1/2
2r = r +29 . . . . . . multiply by 2(r+29)
r = 29 . . . . . . . . . .subtract r
_____
The knowledge of 30°-60°-90° triangle relationships can come from any of several sources. One such source is consideration of what happens when you cut an equilateral triangle along its altitude. (The short side is half the long side of the resulting 30-60-90 triangle.)
Another source is the sine ratio of the 30° angle (trigonometry). Sin(30°) = CD/CA = 1/2.
(a⁷ - a⁴) ÷ (a³ + a²)
Answer:
a^4 - a^3 + a^2 - 2a - (2)/(a + 1)
The simplified form of (a⁷ - a⁴) ÷ (a³ + a²) is a³ - a⁴.
The given expression is: (a⁷ - a⁴) ÷ (a³ + a²)
To simplify it:
Factor out common terms: a⁴(a³ - 1) / a²(a + 1)
Cancel out common factors: a⁴(a³ - 1) / a²(a + 1) = a³ - a⁴
Therefore, the simplified form of (a⁷ - a⁴) ÷ (a³ + a²) is a³ - a⁴.
x-3y=6
x=3y+4
solve for x and y
Answer:
1) x = 6, y = -2 + 1/3x
2)
Step-by-step explanation:
1) x-3y=6
-3y=6-x, 6-x/-3y
y = -2 + 1/3x
x - 3(-2+1/3x) = 6
x - 6 + x = 6
2x =12
x = 6
2) x=3y+4
-3y = -x+4
y = -x/-3 +4/-3
y = 1/3x + -4/3
x = 3(1/3x + -4/3)
I am unsure about x on number two...
Use the graphs of f and g to solve Exercises 87, 88, and 89.
87. Find the domain of f + g.
88. Find the domain of [tex]\frac{f}{g}[/tex].
89. Graph f + g.
(You can just explain how to graph it for #89.)
Answers and explanations:
87. The domain of added functions includes the restrictions of both. So the range of the added function in this question is [-4, 3]
88. When finding the domain of a divided function we do the same as adding, but with an extra rule: g can't equal zero. So for this question the domain is (-4, 3)
89. To graph f + g you add the y-values for each x-value. I added a picture to help explain this one!
Answer:
87. [-4, 3]
88. (-4, 3)
89. See Attachment
General Formulas and Concepts:
Algebra I
Reading a Cartesian PlaneCoordinates (x, y)FunctionsFunction NotationDomains - the set of x-values that can be inputted into a function f(x)[Interval Notation] - Brackets are inclusive, (Parenthesis) are exclusiveStep-by-step explanation:
*Notes:
When adding functions, the domain of the new function is defined as the intersections of the domains of f and gWhen dividing functions, the domain of the new function is defined as the intersections of the domains of f and g except for the points where g(x) = 0 (this is because we cannot divide by 0)Step 1: Define
Identify the domains of each function.
Domain of f(x): [-4, 3]
Domain of g(x): [-5, 5]
Step 2: Find 87.
Determine the x-values for each function that overlap/intersect.
f(x) and g(x) have intersect from -4 to 3.
Domain f + g: [-4, 3]
Step 3: Find 88.
Determine the x-values for which g(x) = 0.
The function g(x) equals 0 at x = -4 and x = 3. Therefore, these x-values are excluded in the domain.
Domain of f/g: (-4, 3)
Step 4: Find 89.
To draw a graph of the f + g, we must combine the y-values for each x-value domain in a t-chart and plot by hand.
x | f(x) x | g(x) x | f + g
-4 5 -4 0 -4 5
-3 4 -3 1 -3 5
-2 3 -2 2 -2 5
-1 3 -1 2 -1 5
0 2 0 1 0 3
1 1 1 1 1 2
2 -1 2 1 2 0
3 -3 3 0 3 -3
For Emily's birthday, her father treated her and five friends to a dinner at a restaurant at the mall. Emily and her friends ordered three pizza dinners at $6.25 each and three chicken baskets at $7.50 each. All six people ordered soft drinks costing $1.25 each. The sales tax on the meal was 4.5%, and the tip was 15%. What was the total cost of the meal, including the sales tax and the tip?
Answer:
$58.26.
Step-by-step explanation:
Total cost without sales tax and tip = 3 * 6.25 + 3 * 7.50 + 6 *1.25
= $48.75
Plus Sales tax and tip:
= 48.75 + 0.045*48.74 + 0.15*48.75
= $58.26.
Answer:
58.25
Step-by-step explanation:
At Central Online High School, 4510045100 of the students have a dog, 3010030100 have a cat, and 1810018100 have both a dog and a cat. What is the probability that a student who has a dog also has a cat? Enter your answer as a reduced fraction with the / symbol, like this: 3/14
Answer: [tex]\dfrac{2}{5}[/tex]
Step-by-step explanation:
Given : The proportion of students have a dog : [tex]P(D)=\dfrac{45}{100}[/tex]
The proportion of students have a cat : [tex]P(C)=\dfrac{30}{100}[/tex]
The proportion of students have both a dog and a cat : [tex]P(C\cap D)=\dfrac{18}{100}[/tex]
Now, the conditional probability that a student who has a dog also has a cat will be :-
[tex]P(C|D)=\dfrac{P(C\cap D)}{P(D)}\\\\\\\Rightarrow\ P(C|D)=\dfrac{\dfrac{18}{100}}{\dfrac{45}{100}}\\\\\\\Rightarrow\ P(C|D)=\dfrac{18}{45}=\dfrac{2}{5}[/tex]
Hence, the probability that a student who has a dog also has a cat = [tex]\dfrac{2}{5}[/tex]
Answer:
3/5
Step-by-step explanation: I just did the test and got it right. This was after I tried 2/5 and got it wrong.
Suppose that, in some distant part of the universe, there is a star with four orbiting planets . One planet makes a trip around the star in 6 earth years , the second planet takes 9 earth years, the third takes 15 earth years and the fourth takes 18 earth years . Suppose that at some time the planets are lined up. How many years will it take for them to all line up
Answer: 90 Earth years.
Step-by-step explanation:
Analizing the information provided in the exercise, you need to find the Least Common Multiple (LCM) of the given numbers.
You can follow these steps:
1. You must descompose 6, 9, 15 and 18 into their prime factors:
[tex]6=2*3\\\\9=3*3=3^2\\\\15=3*5\\\\18=2*3*3=2*3^2[/tex]
2. Finally, you need to choose the commons and non commons with their greatest exponents and multiply them. Then you get:
[tex]L.C.M=2*3^2*5=2*9*5\\\\L.C.M=90[/tex]
Therefore, it will take 90 Earth years for them to all line up.
Complete column 3 in the table order the masses from greater to least with a rank of 1 for the greater mass.
Answer:
The answer to your question is:
Step-by-step explanation:
1.- 1.09 In the table the order will be
2.- 0.99 1.- 6
3.- 0.919 2.- 10
4.- 0.66 3.- 7
5.- 0.647 4.- 11
6.- 0.394 5.- 5
7.- 0.298 6.- 4
8.- 0.256 7.- 9
9.- 0.23 8.- 8
10.- 0.136 9.- 1
11.- 0.112 10.- 2 11.- 3
List S and list T each contain 5 positive integers, and for each list the average (arithmetic mean) of the integers in the list is 40. If the integers 30, 40, and 50 are in both lists, is the standard deviation of the integers in list S greater than the standard deviation of the integers in list T? (1) The integer 25 is in list S. (2) The integer 45 is in list T.
Answer:
Yes, SDS > SDT
Step-by-step explanation:
List S
25, 30, 40, 50, XS
Average list S = 40
So, we could write,
Average list S = 40 = (25 + 30 + 40 + 50 + XS) / 5
Solving for XS
XS = 40 x 5 – 25 – 30 – 40 – 50 = 200 – 145 = 55
SDs = SD (25, 30, 40, 50, 55) = 12.74
List T
30, 40, 45, 50, XT
Average list T = 40
So, we could write,
Average list T = 40 = (30 + 40 + 45 + 50 + XT) / 5
Solving for XT
XT = 40 x 5 – 30 – 40 – 45 – 50 = 200 – 165 = 35
SDT = SD (30, 35, 40, 45, 50) = 7.1
Even at first sight SDS > SDT because 25 is out of the range 30-50, while 45 is within that range.
List S is more spread than list T.
A lower or higher number than the mean in a list can increase the standard deviation. In this case, the standard deviation of list S is greater than list T due to the presence of 25, which is farther from the mean of 40 than the numbers in list T.
Explanation:The question asked relates to the standard deviation of two sets of positive integers, list S and list T. For each list, we calculate the standard deviation, which is a measure of how spread out the numbers are around the mean value. Based on the information provided:
The integer 25 is in list S. The integer 45 is in list T.The presence of a number lower or higher than the mean in list S or T respectively, will increase the standard deviation because the deviation or difference from the mean is greater. Remember, standard deviation measures the variation or dispersion from the average. Hence, if the integer 25 is in List S and the integer 45 is in list T, the standard deviation will be greater for list, S, considering these numbers are farther from the mean of 40 compared to the numbers in List T.
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what is the range of the following set? (-2,4), (0,3), (1,6), (-1,2)
a. (4,0,6,-1)
b. (-2,0,1,-1)
c. (-2,4,0,3,1,6,-1,2)
d. (4,3,6,2)
e. (-2,3,1,2)
Answer:
d. (4,3,6,2)
Step-by-step explanation:
The list of second numbers of the ordered pairs is the range.
___
The second number of the first pair is 4; the second number of the second pair is 3. The only 4-number answer choice containing these two numbers is (d). You don't even have to work the whole problem to make the proper choice.
Krystal and 4 friends were going to the movies. Each ticket cost $12. They bought 2 buckets of popcorn at $4.50 each and then each person bought their own soda at $4.75 each. How much money did they spend in total?
Answer:
Step-by-step explanation:
First you would multiply 12 by four since each person has to have a ticket ($48) next you would multiply 4.50 by two since they bought two buckets of popcorn ($9) then you would multiply 4.75 by four since they each bought their own drink ($15) then you would all three of those totals together to get the final cost of everything ($72)
Hoped that answered your question!
Answer:
$92.75
Step-by-step explanation:
Krystal and 4 friends were going to the movies.
Total person = 5
The cost of each ticket = $12.00
They bought 2 buckets of popcorn at $4.50 each
They all bought soda at $4.75 each.
Total money they spent = (12 × 5) + (4.50 × 2) + (4.75 × 5)
= 60 + 9.00 + 23.75
= $92.75
They spent $92.75 in total.
A researcher would like to evaluate the claim that large doses of Vitamin C can help prevent the common cold. One group of participants is given 500 mg of Vitamin C (500mg per day) and a second group is given a placebo (sugar pill). The researcher records the number of colds each individual experiences during the 3-month winter season. a. Identify the dependent variable for this study.
b. Is the dependent variable discreet or continuous?
c. What scale of measurement (nominal, ordinal, interval, or ratio) is used to measure the dependent variable.
Answer:
a. The dependent variable for this study is the "number of colds each individual experiences during the 3-month winter season" because it depends on the doses of vitamins and placebo.
b. The dependent variable is discrete because the number of colds is like 1,2,3,... so on.
c. The scale of measurement of the dependent variable is Ratio because the number of cold experiences can be 0.
Tessa made a mistake solving the equation 4(2x + 3 ) = -20. Select the line in which her mistake appears.
Line 1. 4 (2x + 3) = -20
Line 2. 8x + 12 = -20
Line 3. 8x = -8
Line 4. x = -1
Answer:
Line 3
Step-by-step explanation:
we have
[tex]4(2x+3)=-20[/tex]
Verify each line
Line 1
[tex]4(2x+3)=-20[/tex] ----> the given equation
Line 1 is correct
Line 2
Distribute in the left side
[tex]8x+12=-20[/tex]
Line 2 is correct
Line 3
Subtract 12 both sides
[tex]8x=-20-12[/tex]
[tex]8x=-32[/tex]
The line 3 is not correct
Tessa made a mistake in Line 3 of the problem. The correct calculation should be -20 minus 12, which equals -32. The solution for x is -4.
Explanation:The subject of this problem is Mathematics, specifically algebra. Looking at the lines of the problem you provided, we can see that Tessa's mistake lies in Line 3 when she subtracts 12 from -20 and gets -8. The correct subtraction should be -20 minus 12 = -32.
So, Line 3 would correctly be 8x = -32 . To solve for x, we would then divide -32 by 8 to get x = -4.
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Subtract 7a+3a-9 from 5a-6a-4 write your answer in the standard polynomial form
Answer:
-11a +5
Step-by-step explanation:
(5a-6a-4) -(7a+3a-9) = a(5-6-7-3) -4+9 = -11a +5
The number of vibrations n n per second of a nylon guitar string varies directly with the square root of the tension T T and inversely with the length L L of the string. If the tension is 256 256 kilograms when the number of vibrations per second is 15 15 and the length is 0.6 0.6 meters, find the tension when the length is 0.3 0.3 meters and the number of vibrations is 12 12 .
The tension when the length is 0.3 meters and the number of vibrations is 12 is 40.96 Kg.
Given, that number of vibrations 'n' per second of a nylon guitar string varies directly with the square root of the tension 'T' and inversely with the length 'L' of the string.
Formulating the relation,
[tex]n \alpha \frac{\sqrt{T} }{L}[/tex]
[tex]n = K\frac{\sqrt{T} }{L}[/tex]
[tex]L \times n = K\sqrt{T}[/tex]
Substitute the values,
T = 256 Kg
n = 15
L = 0.6
[tex]0.6 \times 15 = K \times \sqrt{256}\\K = 9/16\\K = 0.5625\\[/tex]
Now when L = 0.3 and n = 12,
[tex]0.3 \times 12 = 0.5625 \times \sqrt{T}\\\sqrt{T} = 6.4\\ T = 40.96[/tex]
Therefore tension in the string is 40.96Kg .
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The dimensions (width and length) of room1 have been read into two variables : width1 and length1. The dimensions of room2 have been read into two other variables : width2 and length2. Write a single expression whose value is the total area of the two rooms.
To calculate the total area of two rectangular rooms, we multiply the length by the width of each room separately and then add the two results together. The formula used is Total Area = (width1 × length1) + (width2 × length2). This demonstrates a practical application of geometry in everyday situations.
Explanation:The student's question is about calculating the total area of two rectangular rooms given their lengths and widths. To find the area of a rectangle, we multiply its length by its width. Therefore, to find the total area of both rooms, we calculate the area of each room separately and then add the two areas together. The formula for the total area of the two rooms would be:
Total Area = (width1 × length1) + (width2 × length2)
By inserting the specific values for width1, length1, width2, and length2 into this formula, we can calculate the exact total area covered by both rooms.
This approach utilizes basic principles of geometry to combine the areas of the two spaces, providing a clear example of how mathematical concepts are applied in practical situations like room measurements.
If 3x-y=123x−y=123, x, minus, y, equals, 12, what is the value of \dfrac{8^x}{2^y} 2 y 8 x start fraction, 8, start superscript, x, end superscript, divided by, 2, start superscript, y, end superscript, end fraction ?
Answer:
[tex]2^{12}=4,096[/tex]
Step-by-step explanation:
You know that [tex]3x-y=12[/tex] and have to find
[tex]\dfrac{8^x}{2^y}[/tex]
Use the main properties of exponents:
1. [tex](a^m)^n=a^{m\cdot n}[/tex]
2. [tex]\dfrac{a^m}{a^n}=a^{m-n}[/tex]
Note that
[tex]8=2^3,[/tex]
then
[tex]7^x=(2^3)^x=2^{3\cdot x}=2^{3x}[/tex]
Now
[tex]\dfrac{8^x}{2^y}=\dfrac{2^{3x}}{2^y}=2^{3x-y}[/tex]
Since [tex]3x-y=12,[/tex] then [tex]2^{3x-y}=2^{12}=4,096[/tex]
Final answer:
The value of the expression [tex]\(\frac{8^x}{2^y}\)[/tex] given the equation 3x - y = 12 is 4096, since 8 can be expressed as 2^3 and the properties of exponents allow us to simplify the expression to 2^12.
Explanation:
The question involves determining the value of a mathematical expression given a specific equation.
Given the equation 3x - y = 12, we want to find the value of [tex]\(\frac{8^x}{2^y}\)[/tex].
This can be done by recognizing that 8 is a power of 2, specifically 8 = 2^3.
Thus, [tex]\(8^x = (2^3)^x = 2^{3x}\)[/tex]. Substituting back into the original expression, we get [tex]\(\frac{2^{3x}}{2^y}\)[/tex].
Using the properties of exponents, when dividing terms with the same base, we subtract the exponents: [tex]\(2^{3x - y}\)[/tex].
Since we know 3x - y = 12, we substitute 12 in place of 3x - y, giving us 2^12.
Therefore, the answer is 2^{12}, or 4096.
Alisa says it is easier to compare the numbers in set a (45,000, 1,025,680) instead of set b (492,111, 409,867). 1.What is one way you could construct an argument justifying whether Alissa conjecture is true? 2. Is Alisa's conjecture true? Justify your answer. 3. Alisa wrote a comparison for Set B using ten thousand place. Explain what strategy she could have used.
Alisa's conjecture is true because the numbers in set A differ by two magnitudes, making the comparison easier. Alisa could have compared the leading digits in the ten thousand place to determine that the numbers in set B are relatively close in magnitude.
Explanation:In order to construct an argument justifying whether Alisa's conjecture is true, we can compare the magnitude of the numbers in each set. Looking at set A, we have 45,000 and 1,025,680. The first number has four digits, while the second number has six digits, indicating a difference of two magnitudes.
Now let's look at set B, which consists of 492,111 and 409,867. Both numbers in set B have six digits, so they are of the same magnitude.
Based on this analysis, we can conclude that Alisa's conjecture is true. It is indeed easier to compare the numbers in set A because their magnitudes differ by two, making the comparison more straightforward.
When comparing set B using the ten thousand place, Alisa could have used the strategy of looking at the leading digit in the ten thousand place. In this case, the leading digits are 4 and 4, indicating that the numbers in set B are relatively close in magnitude.
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11 1/2 and 13 3/4 is?
Solve for x.
1+|2+x|=9
x = 4 or x=−8
x = 5 or x=−9
x = 6 or x=−10
x = 7 or x=−11
Answer:
Step-by-step explanation:
1+|2+x|=9
1+|2+x| -1 =9-1
|2+x| = 8
2+x = 8 or 2+x = -8
x=6 or x= -10
Answer:
c
Step-by-step explanation:
i took the k12 test
A geyser Erupts every fourth day . Another geyser erupts every sixth day. Today both geysers erupted. In how many days will both geysers erupt on the same day again?
In 12 days both geysers erupt on the same day again
What is Least common multiple?The smallest number that is a multiple of each of two or more numbers.
Given:
A geyser Erupts every fourth day.
Another geyser erupts every sixth day.
so, to find how many days will both geysers erupt on the same day again
we have to find the LCM of 4 and 6
So, 4 = 2*2
6= 2*3
LCM (4, 6) =2*2*3 = 12
Hence, 12 days both geysers erupt on the same day again.
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Show that the points A (-3, 2), B (-6, 4) and C (1, 8) are vertices of a right triangle.
Answer:
See below.
Step-by-step explanation:
For the triangle to be a right triangle there must be a pair adjacent sides which are at right angles to each other - that is whose slope product = -1.
Slope of AB = (4-2)/(-6- -3) = -2/3.
Slope of BC = (8-4)/ (1 - - 6) = 2/7
Slope of AC = (8-2) / (1 - -3) = 6/4 = 3/2.
Now 3/2 * -2/3 = -1 so sides AB and AC are at right angles and the 3 points are the vertices of a right triangle.
To confirm if the points A (-3, 2), B (-6, 4) and C (1, 8) are vertices of a right triangle, we use the Pythagorean theorem. After calculating the distances between each pair of points, we found that the square of the length of the longest side equals the sum of the squares of the lengths of the other two sides, proving that they form a right triangle.
Explanation:To show that the points A (-3, 2), B (-6, 4), and C (1, 8) are vertices of a right triangle, we need to check if the square of the length of the longest side (hypotenuse) is equal to the sum of the squares of the lengths of the other two sides. This is known as the Pythagorean theorem. First, compute the distances between each pair of points using the distance formula:
AB = sqrt[(4-2)^2 + (-6-(-3))^2] = sqrt[2^2 + (-3)^2] = sqrt[4 + 9] = sqrt[13]
BC = sqrt[(8-4)^2 + (1-(-6))^2] = sqrt[4^2 + 7^2] = sqrt[16 + 49] = sqrt[65]
AC = sqrt[(8-2)^2 + (1-(-3))^2] = sqrt[6^2 + 4^2] = sqrt[36 + 16] = sqrt[52]
BC is the longest side, so we need to check if BC^2 = AB^2 + AC^2. Calculating, we find that 65 = 13 + 52, which is true. Therefore, points A, B, and C are vertices of a right triangle.
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On a coordinate plane, a curved line with minimum values of (negative 2, 0) and (1.05, negative 41), and a maximum value of (negative 0.5, 5), crosses the x-axis at (negative 2, 0), (0, 0), and (1.5, 0), and crosses the y-axis at (0, 0). Which statement is true about the end behavior of the graphed function? As the x-values go to positive infinity, the function’s values go to positive infinity. As the x-values go to zero, the function’s values go to positive infinity. As the x-values go to negative infinity, the function’s values are equal to zero. As the x-values go to negative infinity, the function’s values go to negative infinity.
Answer:
As the x-values go to positive infinity, the function’s values go to positive infinity.
Step-by-step explanation:
With the information given you can plot a rough graph (see attachment)
As the x-values go to positive infinity, the function’s values go to positive infinity. -> True
As the x-values go to zero, the function’s values go to positive infinity. -> False, x = 0 is between a maximum and a minimum
As the x-values go to negative infinity, the function’s values are equal to zero. -> False x-values go to negative infinity, the function's values go to positive infinite
As the x-values go to negative infinity, the function’s values go to negative infinity. False x-values go to negative infinity, the function's values go to positive infinite
Answer: As the x-values go to positive infinity, the function’s values go to positive infinity.
Step-by-step explanation:
just did this
Solve for y. −140=18+4(5y−2) Enter your answer in the box. y =
Answer:
y = - 7.5
Step-by-step explanation:
Given
- 140 = 18 + 4(5y - 2) ← distribute and simolify right side
- 140 = 18 + 20y - 8
- 140 = 10 + 20y ( subtract 10 from both sides )
- 150 = 20y ( divide both sides by 20 )
- 7.5 = y
Barack is solving a problem and his final units need to be in square inches. His current answer is 8 feet squared. What is the equivalent measurement in square inches
Answer:
1152 in²
Step-by-step explanation:
Barack can change the units using a suitable multiplier. It will have a numerator equal to its denominator, and will have units that cancel the square feet and give square inches:
8 ft² × ((12 in)/(1 ft))² = 8×12×12 in² = 1192 in²
_____
12 in = 1 ft . . . so numerator is equal to denominator
Malik’s recipe for 4 servings of a certain dish requires 3/2 cups of pasta. According to this recipe, what is the number of cups of pasta that Malik will use the next time he prepares this dish?(1) The next time he prepares this dish, Malik will make half as many servings as he did the last time he prepared the dish.(2) Malik used 6 cups of pasta the last time he prepared this dish.What's the best way to determine which statement is sufficient?
Answer:
1)3/4 cups of pasta
2)4
Step-by-step explanation:
1) as malik I use half the cups better divide the initial amount 3/4 by 2
C=[tex]\frac{3}{2} .\frac{1}{2} =3/4[/tex]
2)
As Malik use 6 cups, and each plate needs 3/2 cups, we divide 6 by 3/2
C=[tex]\frac{ \frac{6}{1} }{ \frac{3}{2} }=\frac{6.2}{3} =\frac{12}{3} =4[/tex]
Please please help me out with this!!!!!!!
Answer:
when x= -7
h(-7) = (-7)^2 -5
= (-1)^2*(7)^2-5
= 1*49-5
= 49-5
=44
Therefore , h(-7)=5
Answer:
h(- 7) = 44
Step-by-step explanation:
To evaluate h(- 7) substitute x = - 7 into h(x), that is
h(- 7) = (- 7)² - 5 = 49 - 5 = 44
PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!! THIS IS THE LAST DAY TO COMPLETE THIS ASSIGNMENT AND I DESPERATELY NEED TO FINISH THIS ASSIGNMENT WITH AN 100%.
Answer:
c. 7,999,999
Step-by-step explanation:
The number of possible phone numbers is the product of the number of possible digits in each position, less the excluded number:
8·10·10 · 10·10·10·10 - 1 = 8,000,000 -1 = 7,999,999
How would you find the volume of a tower created from 1,000 cans that were each 12oz in volume?
Answer:
Multiply the number of cans by the volume of each: 12,000 oz.
Step-by-step explanation:
You find the total volume of more than one can by adding the volumes of the cans involved.
For 2 cans, the volume would be ...
12 oz + 12 oz = 24 oz
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When you consider adding numbers more than a couple of times, you start looking for ways to simplify the effort. Multiplication was invented for that purpose. Here, multiplying the volume of 1 can by 1000 is the same as adding the volumes of 1000 cans.
For 1000 cans with volume of 12 oz each, the volume of the total is ...
1000 × 12 oz = 12,000 oz.