An sample of water with a mass of 123.00 kg is heated from 25 C to 97 C. If the specific heat of water is 1 J-1 kg K-1 then how much energy is required?

Answer:

4.81×10⁻⁴ g K

Explanation:

Convert atoms to moles:

7.40×10¹⁸ atoms K × (1 mol K / 6.02×10²³ atoms) = 1.23×10⁻⁵ mol K

Convert moles to mass:

1.23×10⁻⁵ mol K × (39.1 g K / mol K) = 4.81×10⁻⁴ g K

Answer:

3Ag⁺ + 3NO₃⁻ + 3Na⁺ + PO₄³⁻ → Ag₃PO₄(s) + 3Na⁺ + 3NO₃⁻

Explanation:

An ionic equation is a chemical equation where the electrolytes in aqueous solution are expressed as dissociated ions.

For the reaction:

3AgNO₃(aq) + Na₃PO₄(aq) → Ag₃PO₄(s) + 3 NaNO₃(aq)

AgNO₃(aq), Na₃PO₄(aq) and NaNO₃(aq) are dissociated in water thus:

AgNO₃(aq) → Ag⁺ + NO₃⁻

Na₃PO₄(aq) → 3Na⁺ + PO₄³⁻

NaNO₃(aq) → Na⁺ + NO₃⁻

The ionic equation is:

3Ag⁺ + 3NO₃⁻ + 3Na⁺ + PO₄³⁻ → Ag₃PO₄(s) + 3Na⁺ + 3NO₃⁻

I hope it helps!

Answer:

Explanation:

For any system in equilibrium, the molar concentration of all the species on the reactant side are related to those on the product side by a constant known as the equilibrium constant [tex]K_{eq}[/tex].

For a given reaction:

              aA + bB ⇄ cC

 [tex]K_{eq}[/tex] =   [tex]\frac{[C]^{c} }{[A]^{a} [B]^{b} }[/tex]

The reaction equation is given as:

     [tex]CO_{g}[/tex] + 2H₂[tex]_{g}[/tex] ⇆CH₃OH [tex]_{g}[/tex]

Note: All the species are in gaseous phase.

            [tex]K_{eq}[/tex] = [tex]\frac{[CH_{3}OH ]}{[CO] [H_{2}] }[/tex]

Answer: [tex]K_c=\frac{[CH_3OH]{[CO][H_2]^2}[/tex]

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. It is expressed as [tex]K_{eq}[/tex]

[tex]CO(g)+2H_2(g)\rightarrow CH_3OH(g)[/tex]

The equilibrium constant in terms of concentration is written as :

[tex]K_eq=\frac{[CH_3OH]{[CO][H_2]^2}[/tex]

Thus the correct answer choice is B.

Na2C03 is formed through the reaction of

NaOH and H2CO3 namely sodium hydroxide and carbonic acid

NaOH -> strong base

H2CO3-> weak acid

Answer:

A. a weak acid and a strong base

Explanation:

An acid-base reaction is a chemical reaction between an acid and a base to form salt and water. The reaction is also known as a neutralization reaction.

An acid is a compound that when in aqueous solution it dissociate to form an hydrogen ion(H+).

A base is a compound that when in aqueous solution it produces an hydroxide ion(OH-) .

A strong acid is an acid that completely dissociate in an aqueous solution.

A strong base is a base that completely dissociate in an aqueous solution.

The reaction that produce a salt like sodium carbonate is a chemical reaction between a weak acid and a strong base. The chemical reaction can be represented as follows

H2CO3 + 2NaOH → Na2CO3 + 2H2O

H2CO3 is a weak acid as it partially dissociate in aqueous solution.

NaOH is a strong base as it completely dissociate in aqueous solution.

Answer:

Reactivity

Explanation:

The scenario shows that baking soda is reactive enough to produce bubbles with vinegar but not enough to do so in pure water.

Flammability, color change, and boiling point are all wrong.  The scenario says nothing about these properties.

Answer:

Reactivity (Znk Elite Answerer is right)

Explanation:

I just took a test and I got it right. Even if the question says select all that apply there is only 1 answer and it is reactivity

Answer:

Na₂CO₃•H₂O

Explanation:

After it is heated, the remaining mass is the mass of sodium carbonate.

30.2 g Na₂CO₃

Mass is conserved, so the difference is the mass of the water:

35.4 g − 30.2 g = 5.2 g H₂O

Convert masses to moles:

30.2 g Na₂CO₃ × (1 mol Na₂CO₃ / 106 g Na₂CO₃) = 0.285 mol Na₂CO₃

5.2 g H₂O × (1 mol H₂O / 18.0 g H₂O) = 0.289 mol H₂O

Normalize by dividing by the smallest:

0.285 / 0.285 = 1.00 mol Na₂CO₃

0.289 / 0.285 = 1.01 mol H₂O

The ratio is approximately 1:1.  So the formula of the hydrate is Na₂CO₃•H₂O.

Na₂CO₃•H₂O

Given:

Question:

What is the formula for the hydrate?

Problem-solving:

We will solve problems related to The Law of Definite Proportion (Proust's Law).

"The ratio of the masses of elements in each compound is always constant. Put differently, a given compound invariably contains a similar proportion of elements by mass."

The heating reaction of the hydrate of sodium carbonate is as follows:

[tex]\boxed{ \ Na_2CO_3.nH_2O \xrightarrow{\text{heat}} Na_2CO_3 + nH_2O \ }[/tex]

Condition:

[tex]\boxed{ \ Na_2CO_3.nH_2O \xrightarrow{\text{heat}} Na_2CO_3 + nH_2O \ }[/tex]

         35.4 g                 30.2 g       5.2 g

We want to determine the amount of water (with the symbol n) so that the formula for the hydrate can be known.

Recall that [tex]\boxed{ \ Moles = \frac{Mass \ (g)}{Mr} \ }[/tex]

Let us prepare the number of moles of Na₂CO₃ and H₂O respectively.

Finally, we use the mole ratio to write the formula. Find the water-to-anhydrate mole ratio.

[tex]\boxed{ \ Na_2CO_3 \ : \ H_2O = 1 \ : \ n  \ }[/tex]

[tex]\boxed{ \ H_2O \ : \ Na_2CO_3 = n \ : \ 1  \ }[/tex]

[tex]\boxed{ \ n \ : \ 1 = 0.289 \ : \ 0.285 \ }[/tex]

[tex]\boxed{ \ n = \frac{0.289}{0.285} \times 1 \ }[/tex]

Thus, the value of n after rounding is [tex]\boxed{ \ n = 1 \ }[/tex]

Substitute n = 1 into Na₂CO₃•nH₂O.

Therefore, the formula for the hydrate is [tex]\boxed{\boxed{ \ Na_2CO_3.H_2O \ }} [/tex]

Keywords: 35.40 gram, hydrate of sodium carbonate, Na₂CO₃•nH₂O, heating, a constant mass, its final weight, 30.2 g, what is the formula for the hydrate? the law of definite proportion, Proust's law, anhydrate, the mole ratio

Answer:

0.0057034 or 5.7034 * 10^-3

Answer:

131 K

Explanation:

The only variables are volume and temperature, so we can use Charles' Law:

V1/T1 = V2/T2

Data:

V1 = 2.00 L; T1  = 210 K

V2 =  1.25 L; T2 = ?

Calculation:

2.00/210 = 1.25/T2

Multiply each side by the lowest common denominator (210T2)

2.00T2 = 1.25 ×210

2.00T2 = 262.5

       T2 = 262.5/2.00 = 131 K

The gas was cooled to 131 K.

Answer:

This one is easy. It's the Avogadros' Hypothesis or Avogadros' Law, where the equal volumes of gases in SAME conditions have an equal amount of molecules!

Answer:

Avagadro’s law states at constant temperature and pressure, volume is directly proportional to the number of molecules of the gas.

For example  

At STP that is standard temperature and pressure at which T = 273K and P = 1 atm

Volume occupied by 1 mole ([tex]6.022\times 10^{23}[/tex] gas molecules) of any gas is equal to 22.4L

That is

1 mole = 22.4L

2 mole = 44.8 L

3 mole = 67.2 L

So 1 mole of [tex]CO_2[/tex] gas =22.4L ([tex]6.022\times 10^{23}[/tex] gas molecules)

1 mole of [tex]H_2[/tex] gas =22.4L ([tex]6.022\times 10^{23}[/tex] gas molecules)

1 mole of [tex]Cl_2[/tex] gas =22.4L ([tex]6.022\times 10^{23}[/tex] gas molecules)

The chemical reaction has been the formation of product with the reaction of reactants. The chemical reaction has been differentiated as synthesis, decomposition, replacement reaction.

The following reaction has been classified as:

The reaction has been following the synthesis of the product with a mixture of reactants. Thus, it has been given as the synthesis reaction.

There has been replacement of Ca by Ag in calcium chloride and replacement of Ag by Ca in silver nitrate. There has been two replacement. Thus, the reaction has been a double replacement reaction.

The reaction has replacement of Cu by Zn in copper sulfate. It has been a single replacement, thus the reaction has been a single replacement reaction.

There has breakdown of the compound for the formation of product. Thus, the reaction has been a decomposition reaction.

Learn more about chemical reaction, here:

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Answer:

synthesis and combustion

double replacement

single replacement

decomposition only

Explanation:

in that order, i got it correct

Answer:

its write for the first person who did it

Explanation:

Answer:

Reaction 1: 3700

Reaction 2: 3200

pt 2

Reaction 1: 0.00823

Reaction 2: 0.00397

pt 3

reaction 1: -450

reaction2: -81

Explanation:

Answer:

Explanation:

Specific heat capacity can be defined as the heat required to raise the temperature of a unit mass of a substance by 1kelvin.

The heat capacity on the other hand, expresses the heat required to raise the temperature of  asubstance by 1kelvin.

When we use specific heat capacity, we are particular about the amount of heat that would be needed to actually cause a temperature change in a unit of a substance. This suggests that even if we don't have a complete substance, we can be sure that by knowing the mass of a unit of a body one can easily estimate how much heat is required to raise its temperature. The specific heat is fundamental in calculating the heat capacity of a body. Without the value of the specific heat, we cannot evalutate the heat capacity of a body.

Answer:

Radiocarbon dating can be used to determine the age of a sample less than 50,000 years old - C

Answer:

Approximately 0.074 grams.

Explanation:

How does the electroplating works for copper? Copper exists as copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] in the copper(II) nitrate [tex]\rm Cu{(NO_3)}_2[/tex] solution. It takes two moles of electrons to reduce one mole of copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] to metallic copper [tex]\rm Cu[/tex].

[tex]\rm Cu^{2+}\;(aq) + 2\;e^{-} \to Cu\;(s)[/tex]. (Reduction half of the ionic equation.)

Start by finding the charge on the electrons that have been supplied to this electrochemical cell. After that,

For a constant direct current [tex]I[/tex], the charge [tex]Q[/tex] that has been delivered in time [tex]t[/tex] is equal to

[tex]Q = I \cdot t[/tex].

In case

[tex]Q[/tex] will be in Coulombs [tex]\mathrm{C}[/tex] (which is the same as [tex]\mathrm{A\cdot s}[/tex].)

For this electrochemical cell,

[tex]Q = I\cdot t = \rm 0.75\;A \times 300\;s = 225\;C[/tex].

The Faraday's Constant gives the size of charge (in Coulombs) on one mole of electrons.

[tex]F \approx \rm 96485.33212\;C\cdot mol^{-1}[/tex].

[tex]\displaystyle n(\mathrm{e^{-}}) = \frac{Q}{F} = \rm \frac{225\;C}{96485.33212\;C\cdot mol^{-1}}\approx 0.00233196\;mol[/tex].

Assume that copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] are in excess. Refer to the reduction half-equation, it takes two moles of electrons to deposit one mole of metallic copper.

[tex]\displaystyle \frac{n(\mathrm{Cu})}{n(\mathrm{e^{-}})} = \frac{1}{2}[/tex].

[tex]n(\mathrm{e^{-}})=\rm 0.00233196\;mol[/tex]. As a result,

[tex]\displaystyle n(\mathrm{Cu}) = n(\mathrm{e^{-}})\cdot \frac{n(\mathrm{Cu})}{n(\mathrm{e^{-}})} = \rm 0.00233196\;mol\times \frac{1}{2} = 0.00116598\; mol[/tex].

The Relative atomic mass of copper is [tex]63.546[/tex].

[tex]\begin{aligned}m(\mathrm{Cu})& = n(\mathrm{Cu}) \cdot M(\mathrm{Cu})\\& = \rm 0.00116598\; mol\times 63.546\; g\cdot mol^{-1}\\&\rm \approx 0.074\;g\end{aligned}[/tex].

Final answer:

The mass of copper that can be plated from a 1.0 M Cu(NO3)2 solution using 0.75 A for 5 minutes is calculated by converting the charge passed to moles of electrons, determining the moles of copper, and then converting it to mass, resulting in approximately 0.0740 grams.

Explanation:

To calculate the mass of copper that can be plated out of a 1.0 M Cu(NO3)2 solution using a current of 0.75 A for 5.0 minutes, we apply Faraday's laws of electrolysis and use the molar mass of copper.

Firstly, calculate the total charge passed through the solution using the formula Q = It, where Q is the charge in Coulombs, I is the current in Amperes, and t is the time in seconds. For 0.75 A over 5.0 minutes (or 300 seconds), we obtain Q = (0.75 A) × (300 s) = 225 Coulombs.

Next, convert the charge to moles of electrons using the charge of one mole of electrons, known as Faraday's constant (approximately 96485 C/mol). Thus, moles of electrons = 225 C / 96485 C/mol ≈ 0.00233 mol.

Since the copper plating involves Cu2+ ions gaining two electrons to become copper atoms (Cu2+ + 2e− → Cu), the moles of copper plated will be half the moles of electrons. So, 0.00233 mol / 2 = 0.001165 mol of copper.

Finally, calculate the mass of copper by multiplying the moles of copper by its molar mass (63.55 g/mol for Cu). Thus, mass of copper = 0.001165 mol × 63.55 g/mol ≈ 0.0740 g.

Therefore, the mass of copper that can be plated out using these conditions is approximately 0.0740 grams.

Answer:

9.02×10⁻¹¹ mol NH₃

Explanation:

Convert nanograms to grams:

1.56 ng NH₃ × (1 g / 10⁹ ng) = 1.56×10⁻⁹ g NH₃

Convert grams to moles:

1.56×10⁻⁹ g NH₃ × (1 mol NH₃ / 17.3 g NH₃) = 9.02×10⁻¹¹ mol NH₃

The answer is 9.02×10⁻¹¹ mol NH₃

Convert nanograms to grams:

1.56 ng NH₃ × (1 g / 10⁹ ng) = 1.56×10⁻⁹ g NH₃

Convert grams to moles:

1.56×10⁻⁹ g NH₃ × (1 mol NH₃ / 17.3 g NH₃) = 9.02×10⁻¹¹ mol NH₃

A mass of a substance in grams is numerically equal to its molecular weight. Example: A gram-mole of salt (NaCl) is 58.44 grams.

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Answer:

A. Deposition Occurs

Explanation:

When a gas becomes ionized, deposition occurs.

Answer: Option (D) is the correct answer.

Explanation:

A plasma is defined as the state of matter in which gas exists in hot ionized formed that has similar number of positively charged ions and negatively charged electrons.

Whereas deposition is the change from gaseous to liquid or solid state in which particles come closer to each other.

Sublimation means direct conversion of solid into gaseous phase without undergoing liquid phase.

Thus, we can conclude that when a gas becomes ionized then a plasma is formed.

13 An Ionic Bond

these are the characteristics of an ionic bond compounds like NaCl have these characteristics

14 substances could be compounds or elements hence not all substances are compounds

15 It is not water. The chemical composition of water is H2O not H202

(H202 is hydrogen peroxide and is toxic)

Answer:

[tex]\boxed{\text{163.3 L}}[/tex]

Explanation:

The pressure is constant, so, to calculate the volume, we can use Charles' Law:

\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}

Data:

V₁ = ?;            T₁ =    450 K

V₂ = 103.4 L; T₂ = 284.9 K

Calculation:

[tex]\dfrac{ V_{1}}{450} = \dfrac{ 103.4}{284.9}\\\\{ V_{1}} = 450 \times \dfrac{103.4}{284.9}\\\\ = \textbf{163.3 L}\\\text{The original volume of the helium was $\boxed{\textbf{163.3 L}}$}[/tex]

The original volume of the gas is 186.94 Liters

Further Explanation;

That is;[tex]V\alpha T[/tex]

[tex]P=kT[/tex],  where k is a constant

At different temperatures and pressure then;

[tex]\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }[/tex]

In the Question;

We are given

[tex]V_{1} = ?\\T_{1} = 450\\V_{2} = 103.4 l\\T_{2} =248.9K[/tex]

Therefore;

[tex]V_{1} =\frac{V_{2} T_{1} }{T_{2} }[/tex]

[tex]V_{1} =\frac{(103.4 L)(450 K)}{(248.9K)}[/tex]

[tex]V_{1} = 186.94Liters[/tex]

That is;

[tex]P\alpha \frac{1}{V}[/tex]

[tex]P\alpha \frac{k}{V}[/tex], where k is a constant

[tex]\frac{P_{1}V_{1} }{T_{1} } = \frac{P_{2}V_{2} }{T_{2} }[/tex]

Keywords: Combined gas laws, Boyle's law and Charles's law

Level: High school

Subject: Chemistry

Topic: Gas laws

Sub-topic: Charles's law

Answer:

Decrease the volume or increase the number of moles by a factor of 37.

Explanation:

If the contents are a gas,

pV = nRT

If T is constant

[tex]p \propto \dfrac{n}{V}[/tex]

There are two ways to increase the pressure inside the container.

1. Decrease the volume

If you decrease the volume by a factor of 37, the pressure will increase by the same factor.

2 Increase the number of moles

If you add 36 times the number of moles, you will have 37n moles. Increasing the amount of gas by a factor of 37 increases the pressure by the same factor.

To increase the pressure inside a container by a factor of 37 while keeping the temperature constant, the volume of the gas must be reduced to 1/37th of its original volume, as per Boyle's Law, which states that pressure and volume are inversely proportional.

Assuming the temperature is held constant, to increase the pressure inside a container by a factor of 37, you must reduce the volume of the gas. This is based on Boyle's Law, which states that, for a given mass of gas at constant temperature, the pressure of the gas is inversely proportional to its volume. This means if you want to increase the pressure inside the container, you have to decrease the volume of the container correspondingly.

For instance, if the original pressure of the gas is P, and the volume is V, to increase the pressure by a factor of 37 (making it 37P), you would need to reduce the original volume (V) to V/37. This is because P1*V1 = P2*V2, where P1 and V1 are the initial conditions and P2 and V2 are the final conditions, assuming no change in the amount or temperature of the gas.

Answer:

An insulated container that measures temperature change is a calorimeter. It is used to calculate change in enthalpy (which is ΔH.)

Explanation:

Enthalpy characterize a system from the energy point of view and it depends on the changes in the temperature of the system, the pressure (which is held constant) and the volume of the system (you know this because is an isolated system. Using a calorimeter is a key step in calculating the enthalpy, let's say for a chemical reaction.

Answer:

[tex]\boxed{\text{Pressure and volume}}[/tex]

Explanation:

The measure of R is always the same, but the numbers may differ depending on the units you use.

For example, in SI units, R = 8.314 Pa·m³K⁻¹mol

If your measurement uses different units, you must either convert your units to SI or use a value of R consistent with your units.

If you use bars and litres,                       R = 0.083 14   bar·L·K⁻¹mol⁻¹.

If you use kilopascals and litres,            R = 8.314        kPa·L·K⁻¹mol

If you use atmospheres and litres,        R = 0.082 06 L·atm·K⁻¹mol⁻¹.

If you use Torr and cubic centimetres, R = 62 368     Torr·cm³ K⁻¹mol⁻¹.

The only units that don't change are "K⁻¹mol⁻¹".

[tex]\text{The quantities that affect the value of R are }\boxed{\textbf{pressure and volume}}[/tex]

Answer:

Earth has tremendous diversity of its ecosystems. Different regions are referred to as climate biomes to understand patterns of weather, biology, and natural events.

Explanation:

The greatest difference between tropical and polar climates is the difference in temperature. Tropical climates are located near the Equator and receive more sun year-round than anywhere else on Earth, while polar climates are the farthest from the Equator and receive the least sunlight and heat of any part of the globe. This makes the winters of polar climates fierce and the summers short, while practically every day in a tropical climate is hot. While both climates might bring to mind precipitation (such as rain in the tropics and snow at the poles), both can also be quite dry. Antarctica is considered the largest desert in the world, since almost no snow falls toward the center of the continent. Tropical deserts, such as the Namib of Africa, are extremely hot and dry, making it difficult for any life to survive.

Answer: In the polar climate zone, it is very cold and dry, receiving less precipitation every year. The tropical climate zone has very warm and hot temperatures all year round, receiving much rain.

Explanation: I read the lesson and it makes sense