Answers
The formula for the Lateral Area of Square-based Pyramid
L.A = [tex] \frac{1}{2} [/tex] (Perimeter of the base) x Apothem
Given:
Apothem = 10 in
Side length = 5 in
Perimeter of Square = 4 x side = 4 x 5 = 20 in
L.A = [tex] \frac{1}{2} [/tex] (20)(10)
= [tex] \frac{1}{2} [/tex] (200)
= 100 in²
Answer:
100
Step-by-step explanation:
Related Questions
Solve the following automotive-services problem.
Resistance = 0.1 ohm
Current = 60 amps
Voltage = ______ ?
A. 0.6
B. 6 60
C. 600
Answers
I NEED HELP ASAP Use the Law of Detachment or the Law of Syllogism to draw a conclusion. 3. If Shauna is early for her meeting, she will gain a promotion. If Shauna wakes up early, she will be early for her meeting. Shauna wakes up early.
Answers
M = Shauna is early for her Meeting
P = Shauna gains a promotion
1. M -> P
2. W -> M
3. W
: . P
PLEASE MATH HELP!!
The area of this circle is 96π m².
What is the area of a 30º sector of this circle?
4π m²
8π m²
9π m²
16π m²
Answers
30 degrees / 360 degrees = 0.0833
0.0833 * 96 = 8
answer is 8π m²
The area of a [tex]30^{\circ}[/tex] sector of this circle is [tex]8\pi \ m^2[/tex]. The correct option is B. [tex]8\pi \ m^2[/tex].
Given,The area of circle is [tex]96 \pi \ m^2[/tex].
We have to calculate the area of [tex]30^{\circ}[/tex] sector of this circle.
Area of circle:We know that, Area of circle is,
[tex]A=\pi r^{2}[/tex]
Here, [tex]96\pi =\pi r^{2}[/tex]
Or,
[tex]r^{2} =96[/tex]
[tex]r=\sqrt{96}[/tex]
[tex]r=4\sqrt{6}[/tex]
So, radius of the circle,
[tex]r=4\sqrt{6}[/tex] [tex]m[/tex].
Now we know that Area of a Sector of Circle
Say [tex]A_{1}[/tex],
[tex]A_{1} = \frac{\Theta}{360} \pi r^{2}[/tex]
where [tex]\Theta[/tex] is the angle subtended at the center, given in degrees, and '[tex]r[/tex]' is the radius of the circle.
So,
[tex]A_{1} =\frac{30}{360} \pi (4\sqrt{6} )^{2}[/tex]
[tex]A_{1} =\frac{1}{12} \pi \times96[/tex]
[tex]A_{1} =8\pi \ m^2[/tex].
Hence the area of a [tex]30^{\circ}[/tex] sector of this circle is [tex]8\pi \ m^2[/tex]. the correct option is B [tex]8\pi \ m^2[/tex].
For more details on Area of Sector of circle follow the link:
https://brainly.com/question/3432053
The area of a triangle is 36 square meters. The base is 1 meter less than the height. What is the height of the triangle?
Answers
b = h - 1 so:-
36 = 1/2 * h * (h - 1)
h(h - 1) = 72
h^2 - h - 72 = 0
(h - 9)(h + 8)
so h = 9 or -8 ( height cannot be negative so h = 9
Answer is 9 meters
Each person in a ticket line gets either one or two tickets. You are the 51st person in line. Forty percent of the people in front of you get one ticket each, and the rest of the people in front of you get two tickets each. How many tickets will have been given out when you reach the ticket booth?
Answers
50*.4=20
50*.6=30
30*2=60
60+20=80
I need help!!!! Please if you get it right i will mark you brainliest!
Answers
hope this helps
(-1,-1) would lie in Quadrant III (3).
So, if x < 0 and y < 0, the point (x,y) would be located in Quadrant III.
Roger counted the kids in the cafeteria on Monday. There were 9 tables of 10 kids at the start of lunch. In the middle of lunch, 4 kids came in and sat down. How many kids were in the cafeteria then?
Answers
On Monday Mrs. Wise bought 3 lbs of apples at $4 per lb. On Tuesday, apples were on sale for 20% off so she bought another 5 lbs. How much money did Mrs. Wise spend on apples on Tuesday?
Answers
[tex]0.80 \times 4 = 3.2[/tex]
find 80% (20% less) of 4
[tex]3.2 \times 5 [/tex]
multiply the reduced price by the number of lbs she bought.
Zaira spent 55 hours in 2 weeks working on a science project. she worked 32 hours the first week. Write and solve an addition equation to find the amount of time she spent working the second week.
Answers
What’s one way we can check our answer to 2x10=20
Answers
to check:
20 ÷ 10 = 2
20 ÷ 2 = 10
Hope this helps :)
You have a camera with a 16 mp resolution. how many pixels are represented by that resolution?
Answers
1 MP equals--------------------------> 1 million pixels
therefore
16 MP is equal to-----------------------> X
X=16*1=16 million pixels.
the answer is 16000000 pixels (16 million pixels.)
Solve x2 + 10x = 24 by completing the square. Which is the solution set of the equation?
Answers
Answer:
-12 and 2
Step-by-step explanation:
[tex]x^2+10x=24\\[/tex]
[tex]x^2+2*5*x=24[/tex]
[tex]x^2+2*5*x+5^2-5^2=24[/tex]
[tex](x^2+2*5*x+5^2)-5^2=24[/tex]
Using the identity
[tex]a^2+2*a*b+b^2 = (a+b)^2[/tex]
we get
[tex](x+5)^2-5^2=24[/tex]
[tex](x+5)^2-25=24\\[/tex]
[tex](x+5)^2=24+25\\(x+5)^2=49\\(x+5)=+7 \\or (x+5)=-7\\[/tex]
Solving both of them we get
x=-12 or x=2
Bob is building a wooden cabin. The cabin is 303030 meters wide. He obtained a bunch of 171717 meters long wooden beams for the roof of the cabin. Naturally, he wants to place the roof beams in such an angle that each pair of opposite beams would meet exactly in the middle. What is the angle of elevation, in degrees, of the roof beams
Answers
Answer:
Step-by-step explanation:
Alright, lets get started.
Please refer the diagram I have attached.
The width of the room is 30 meters.
If two beams will be making an angle, they will half the width.
There will be a right triangle made, so using SOH CAH TOA,
[tex]cos x=\frac{adjacent}{hypotenuse}[/tex]
[tex]cos x=\frac{15}{17}[/tex]
taking cos inverse
x = [tex]cos^{-1} (\frac{15}{17} )[/tex]
x = 28.07° : Answer
Hope it will help :)
Answer:
28.07
Step-by-step explanation:
Credit to first said it
Need a smart person fast!
Quadrilateral JPRA is similar to quadrilateral KDEW . PR=27 mm , DE=15 mm , and WE=25 mm .
What is AR ?
Answers
Final answer:
To find AR in quadrilateral JPRA similar to quadrilateral KDEW, use the concept of similar triangles to determine AR = 45 mm.
Explanation:
To find AR in quadrilateral JPRA that is similar to quadrilateral KDEW, we can use the concept of similar triangles.
Calculate the scale factor between the two quadrilaterals: PR/DE = AR/WE
Substitute the known values: 27/15 = AR/25 and solve for AR which gives AR = 45 mm.
Find the dimensions of a rectangle whose perimeter is 24 feet and whose area is 27 square feet.
Answers
Jared is in charge production in a factory that makes lightbulbs. The factory made 2648 lightbulbs over the weekend. Jared wants to pull a sample of these bulbs for testing. Which sample would give Jared the most -accurate test readings ? —a sample consisting every 20th lightbulb- a sample consisting every 40th light bulb- a sample consisting every 50th lightbulb- a sample consisting every 100th light bulb?
Answers
Answer:
A
Step-by-step explanation:
Prism A is similar to Prism B. The volume of Prism A is 2080 cm³.
What is the volume of Prism B?
260 cm³
520 cm³
1040 cm³
16,640 cm³
Answers
Volume of the prism A = 2080 [tex]c m^{3} [/tex]
Let us find the ratio of the volume of prisms given in the diagram:
[tex] \frac{ V_{A}}{V_{B}} = \frac{8^{3}}{4^{3}} [/tex]
[tex] \frac{ V_{A}}{V_{B}} = 8 [/tex]
Since the condition is:
The volume of Prism A = The volume of Prism B
Therefore,
The ratio of their volumes should be 8.
[tex] \frac{ V_{A}}{V_{B}} =8 [/tex]
Since Volume of A = 2080 [tex]cm^{3} [/tex]
Plug-in the value, you would get:
[tex] \frac{2080}{8}} = V_{B}[/tex]
Ans: Volume of B = 260 [tex]cm^{3} [/tex]
The volume of prism B is [tex]\rm 260 \; cm^3[/tex] and this can be determined by taking the ratio of the volume of both the prism.
Given :
Prism A is similar to Prism B. The volume of Prism A is 2080 cm³.To determine the volume of prism B, first determine the ratio of the volume of prism A to the volume of prism B that is:
[tex]\rm \dfrac{V_A}{V_B}=\dfrac{8^3}{4^3}[/tex]
[tex]\rm \dfrac{V_A}{V_B}=8[/tex]
Now, put the value of the volume of prism A in the above expression.
[tex]\rm \dfrac{2080}{V_B} = 8[/tex]
Divide 2080 by 8 in the above equation.
[tex]\rm V_B = \dfrac{2080}{8}[/tex]
[tex]\rm V_B = 260\;cm^3[/tex]
So, the volume of prism B is [tex]\rm 260 \; cm^3[/tex].
For more information, refer to the link given below:
https://brainly.com/question/15861918
In 10 minutes, the top three finishers in a hot dog eating contest consumed a total of 130 hot dogs. the winner, person a, ate 8 more hot dogs than the runner-up, person
b. person c finished a distant third, 10 hot dogs behind person
b. how many hot dogs did each person eat?
Answers
therefore, person a ate x+8 hotdogs
and person c ate x-10 hotdogs
they all ate 130 hotdogs in total so
x + x + 8 + x - 10 = 130
3x -2 = 130
3x = 132
x = 44
so person b ate 44 hotdogs
person a ate 8 more so 52 hotdogs
and person c ate 10 less than person b so 34 hotdogs
Final answer:
The winner, Person A, ate 52 hot dogs, the runner-up, Person B, ate 44 hot dogs, and Person C finished third with 34 hot dogs.
Explanation:
The question involves solving a system of linear equations to find out how many hot dogs each participant in a hot dog eating contest ate. Let's assign variables to each person: A for the winner, B for the runner-up, and C for the third-place finisher. According to the problem, A ate 8 more hot dogs than B, and C ate 10 fewer hot dogs than B.
Here are the equations based on the information provided:
A = B + 8 (Person A ate 8 more than person B)C = B - 10 (Person C ate 10 less than person B)A + B + C = 130 (Together they ate 130 hot dogs)Now we substitute the expressions for A and C in terms of B into the third equation:
(B + 8) + B + (B - 10) = 1303B - 2 = 1303B = 132B = 44Using the value of B, we find out A and C:A = 44 + 8 = 52C = 44 - 10 = 34Therefore, Person A ate 52 hot dogs, Person B ate 44 hot dogs, and Person C ate 34 hot dogs.
Find the 11th term from the end in the AP 56, 63, 70,..., 329
Answers
56, 63, 70,..., 329
First find the common difference:
d=a2-a1
d=63-56
d=7
Formula:
an=a1+(n-1)d
First find the number of terms.
329=56+(n-1)7
329=56+7n-7
329=49+7n
280=7n
40=n
or
n=40
We have to find 40-11=29 th term ( 11 th term from the end)
a29= 56+(29-1)7
a29=56+(28)7
a29=56+196
a29=252
Answer: 252 is 11th term from the end.
3500 calories for 6 servings of pie how many calories per serving
Answers
3500/6
=583.33
What is the slope of any line parallel to y = 4x + 17
Answers
In this equation, m = 4. So, the slope of any line parallel to y = 4x + 17 is 4.
Hope this helps! (:
Slope of any line parallel to the given line is 4
Explanation:
The general form of the linear line is:
y = mx + c where m is the slope
The given line is:
y = 4x + 17
Comparing the given line with the general formula, we would find that:
slope of the line (m1) = 4
Now, for any two lines to be parallel, their slopes must be equal.
This means that:
m1 = m2
We have m1 = 4, therefore:
m2 = 4 for the two lines to be parallel.
Hope this helps :)
Arthur buys a zero coupon bond with a face value of $5000 for $4000. The bond has five years until it matures. How much would Arthur earn if he holds this bond to maturity?
Answers
Explanation:
In bonds, the face value is the value of bond when it is held to maturity. Since the face of the bond is $5,000, the value of Arthur's bond when he holds it until maturity is $5,000.
To get Arthur's earnings by holding his bond until maturity, we subtract the face value to the amount he paid for the bond. Since the face value is $5,000 and he paid $4,000 for that bond, he earned $1,000 for the bond because $5,000 - $4,000 = $1,000.
Ashley walks 1/3 of a mile each day. After 10 days, how many miles has she walked? 2 1/33 1/39 1/310 1/3
Answers
then, multiply the fractions, numerators and denominators separately
and you'll get 10/3, to simplify it'll be 3 1/3 or 3.3333
Verify the identity.
tan x plus pi divided by two = -cot x
Answers
[tex]\bf \textit{Sum and Difference Identities} \\\\ sin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta) \\\\ sin(\alpha - \beta)=sin(\alpha)cos(\beta)- cos(\alpha)sin(\beta) \\\\ cos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta) \\\\ cos(\alpha - \beta)= cos(\alpha)cos(\beta) + sin(\alpha)sin(\beta)\\\\ -------------------------------\\\\ [/tex]
[tex]\bf tan\left(x+\frac{\pi }{2} \right)=-cot(x)\\\\ -------------------------------\\\\ tan\left(x+\frac{\pi }{2} \right)\implies \cfrac{sin\left(x+\frac{\pi }{2} \right)}{cos\left(x+\frac{\pi }{2} \right)} \\\\\\ \cfrac{sin(x)cos\left(\frac{\pi }{2} \right)+cos(x)sin\left(\frac{\pi }{2} \right)}{cos(x)cos\left(\frac{\pi }{2} \right)-sin(x)sin\left(\frac{\pi }{2} \right)}\implies \cfrac{sin(x)\cdot 0~~+~~cos(x)\cdot 1}{cos(x)\cdot 0~~-~~sin(x)\cdot 1} \\\\\\ \cfrac{cos(x)}{-sin(x)}\implies -cot(x)[/tex]
Can someone help me with this problem?
Answers
someone pleaseeeeeeeeee help me!
1. Displacement vectors of 5 km north, 3 km east, 2 km south, and 3 km west combine to a total displacement of
3 km north.
13 km west.
0 km.
2 km south.
Answers
the east and west cancel out and the 5 north being greater than the two south leave you to only have to subtract the 2 south from the 5 north
Just add the vectors together. Consider north to be positive, south to be negative, west to be positive, and east to be negative. Just remember to keep north/south and east/west separate from each other. So let's start with 0 north, 0 west.
Add 5 km north. So 0 + 5 = 5, giving us 5 north, 0 west.
Add 3 km east. So 0 - 3 = -3, giving us 5 north, -3 west (or 3 east).
Add 2 km south. So 5 - 2 = 3, giving us 3 north, -3 west (or 3 east)
Add 3 km west. So -3 + 3 = 0, giving us 3 north, 0 west
We can ignore the 0 west, and as a result we're 3 km north of where we originally started. So the total displacement is "3 km north"
Solve 5kx + 6 = 7kx for x
Answers
5kx + 6 = 7kx
First, divide both sides by k to eliminate that variable:
5x + 6 = 7x
Then subtract 5x from each side:
6 = 2x
Lastly, divide each side by 2 to solve for x:
3 = x
Hope this helps!
Hope this helped!!
Xoxo~ Melis
Continue the following pattern; describe the eighth figure in this pattern
Answers
Answer:
The Eighth Figure would be an 8 by 8 square with 64 small squares
Step-by-step explanation:
The Figures shown in the picture are following a fairly simple pattern. Each variation is adding 1 row and 1 column of squares. Variation 4 has a 4 by 4 square with 16 small square (4*4 = 16). If we continue with pattern then variation 8 will be an 8 by 8 square with 64 smaller squares inside it (8*8 = 64)
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
x = y−4, 2x−5y = 3
Which one-variable linear equation represents the system of equations?
2(y-4)-5y = 3
2x-5(y-4) = 3
2x-5y = y-4
2x-5(x-4) = 3
Answers
2x-5y=3 this eqn 2..
Two things are possible here...
Its either you substitute for x in equation 2... Or you substitute for y...
x=y-4 put this in the equation 2..
2x-5y=3.. Replace the x with (y-4)
2(y-4)-5y = 3...
Since this is In the option no point in substituting for y...
Hope this helped...?
The solution is Option A.
The value of the equation is 2( y - 4 ) - 5y = 3
What is an Equation?
Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the value of x = y - 4 be equation (1)
Let the value of the equation 2x - 5y = 3 be equation (2)
Now ,
We know the value of the equation x = y -4
Substituting the value of equation (1) in equation (2) , we get
2 ( y - 4 ) - 5y = 3
So , the equation has now become ,
2 ( y - 4 ) - 5y = 3
Hence , the value of the equation is 2 ( y - 4 ) - 5y = 3
To learn more about equations click :
https://brainly.com/question/10413253
#SPJ6
Write the expression-3x2+2y2+5xy-2y+5x2-3y2 in simplest form A how many terms are in the simplified expression? B how many terms in the simplified expression negative
Answers
2x^2-y^2+5xy-2y
4 terms
A) There are 3 terms in the simplified expression. B) There are 2 terms in the simplified expression that are negative.
First, let's combine the terms that are alike. We can combine the [tex]x^2[/tex] terms and the [tex]y^2[/tex] terms:
(-3 [tex]x^2[/tex] + 5 [tex]x^2[/tex] ) + (2 [tex]y^2[/tex]- 3 [tex]y^2[/tex]) + 5xy - 2y
This gives us:
2 [tex]x^2[/tex] - [tex]y^2[/tex]+ 5xy - 2y
We can then combine the xy and y terms:
2 [tex]x^2[/tex] - ( [tex]y^2[/tex]+ 2y)
This gives us:
2 [tex]x^2[/tex] - [tex]y^2[/tex]- 2y
So, the simplified expression is 2 [tex]x^2[/tex] - [tex]y^2[/tex]- 2y.
There are 3 terms in the simplified expression.
There are 2 terms in the simplified expression that are negative.
Here is a breakdown of the steps involved in simplifying the expression:
Combine the [tex]x^2[/tex] terms and the [tex]y^2[/tex] terms.
Combine the xy and y terms.
Check to make sure that there are no common factors that can be canceled.
To learn more about expression here:
https://brainly.com/question/34132400
#SPJ3