Answer : The order of potential energy from least to greatest is,
(3) < (1) < (4) < (2)
Explanation :
Formula used :
[tex]P.E=m\times g\times h[/tex]
where,
P.E = potential energy
m = mass of an object
g = gravity constant = [tex]9.8m/s^2[/tex]
h = height
Now we have to calculate the potential energy of following options.
(1) Tiles a 15-kilogram stone found at a height of 3 meters.
[tex]P.E=15Kg\times 9.8m/s^2\times 3m=441J[/tex]
(2) 10 kilograms of water stored at a height of 9 meters.
[tex]P.E=10Kg\times 9.8m/s^2\times 9m=882J[/tex]
(3) 1-kilogram ball located 20 meters.
[tex]P.E=1Kg\times 9.8m/s^2\times 20m=196J[/tex]
(4) In the area box of books weighing 25 kilograms placed on a shelf 2 meters high.
[tex]P.E=25Kg\times 9.8m/s^2\times 2m=490J[/tex]
From this we conclude that, the order of potential energy from least to greatest is,
(3) < (1) < (4) < (2)
Answer:
The objects in order from least to greatest potential energy:
[tex]Ball < Stone < book < Water[/tex]
Explanation:
Potential energy is an energy of the body due to its position.
[tex]P.E=mgh[/tex]
m = mas of the body
g = Acceleration due to gravity
h = Height at which body is placed
Potential energy of the stone:
m = 15 kg, h = 3 m , g = [tex]9.8 m/s^2[/tex]
[tex]P.E_1=15 kg\times 9.8 m/s^2\times 3 m=441 J[/tex]
Potential energy of the water:
m = 10 kg, h = 9 m , g = [tex]9.8 m/s^2[/tex]
[tex]P.E_2=10 kg\times 9.8 m/s^2\times 9 m=882 J[/tex]
Potential energy of the ball :
m = 1 kg, h = 20 m , g = [tex]9.8 m/s^2[/tex]
[tex]P.E_3=1 kg\times 9.8 m/s^2\times 20 m=196 J[/tex]
Potential energy of the book :
m = 25 kg, h = 2 m , g = [tex]9.8 m/s^2[/tex]
[tex]P.E_4=25 kg\times 9.8 m/s^2\times 2 m=490 J[/tex]
The potential energies in order from least to greatest :
[tex]P.E_3<P.E_1<P.E_4<P.E_2[/tex]
The objects in order from least to greatest potential energy:
[tex]Ball < Stone < book < Water[/tex]
What is the difference between traits and characteristics?
A Characteristic is the unique assets, talents, and qualities of a person. On the other hand, a trait is a feature of a person that is hereditary or inherited from parents or offspring. The characteristics are usually something that a person can learn and built by absorption, a trait, on the other hand, is something you have since birth.
Answer:
the person on top is correct
Explanation:
Lithium is a metal with an oxidation number of 1+ and oxygen is a nonmetal with an oxidation number of 2-. which chemical formula represents the compound formed by these two elements?
a.li2o
b.li3o
c.lio
d.lio2
Answer: Option (a) is the correct answer.
Explanation:
According to the cross multiplication method, charges present on the combining atoms cross multiply with the atoms in order to keep the molecule formed neutral.
For example, oxidation number of lithium is +1 and oxidation number of oxygen is -2.
So, when both of them chemically combine with each other then lithium atom will get multiplied by 2 whereas oxygen atom will get multiplied by 1.
Therefore, we can conclude that formula of this chemical compound will be [tex]Li_{2}O[/tex].
How much energy is required to decompose 800 g of pcl3, according to the reaction below? the molar mass of pcl3 is 137.32 g/mol and may be useful. 4 pcl3(g) → p4(s) + 6 cl2(g) δh∘rxn = +1207 kj how much energy is required to decompose 800 of , according to the reaction below? the molar mass of is 137.32 and may be useful. 4 (g) (s) + 6 (g) = +1207 1.76×103 kj 4.53×103 kj 2.31×103 kj 6.72×103 kj 5.90×103 kj?
The amount of energy required to decompose 800 g of [tex]{\text{PC}}{{\text{l}}_{\text{3}}}[/tex] is [tex]\boxed{{\text{1757}}{\text{.8 kJ}}}[/tex].
Further explanation:
Decomposition reactions:
The opposite of combination reactions is called a decomposition reaction. Here, a single reactant gets broken into two or more products. Such reactions are usually endothermic because energy is required to break the existing bonds between the reactant molecules.
Examples of decomposition reactions are as follows:
(a) [tex]2{{\text{H}}_2}{{\text{O}}_2}\to2{{\text{H}}_2}{\text{O}}+{{\text{O}}_2}[/tex]
(b) [tex]2{\text{NaCl}}\to{\text{2Na + C}}{{\text{l}}_2}[/tex]
Stoichiometry of a reaction is used to determine the amount of species present in the reaction by the relationship between reactants and products. It is used to determine moles of a chemical species when moles of other chemical species present in the reaction is given.
Consider the general reaction,
[tex]{\text{A}}+2{\text{B}}\to3{\text{C}}[/tex]
Here,
A and B are reactants.
C is the product.
One mole of A reacts with two moles of B to produce three moles of C. The stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3 and the stoichiometric ratio between B and C is 2:3.
The decomposition of [tex]{\text{PC}{\text{l}_3}[/tex] occurs as follows:
[tex]{\text{4PC}}{{\text{l}}_3} \to {{\text{P}}_4} + 6{\text{C}}{{\text{l}}_2}[/tex]
The formula to calculate the moles of [tex]{\text{PC}}{{\text{l}}_3}[/tex] is as follows:
[tex]{\text{Moles of PC}}{{\text{l}}_3}=\frac{{{\text{Given mass of PC}}{{\text{l}}_3}}}{{{\text{Molar mass of PC}}{{\text{l}}_3}}}[/tex] …… (1)
The given mass of [tex]{\text{PC}}{{\text{l}}_3}[/tex]is 800 g.
The molar mass of [tex]{\text{PC}}{{\text{l}}_3}[/tex]is 137.33 g/mol.
Substitute these values in equation (1).
[tex]\begin{aligned}{\text{Moles of PC}}{{\text{l}}_3}&=\left( {{\text{800 g}}}\right)\left({\frac{{{\text{1 mol}}}}{{{\text{137}}{\text{.33 g}}}}}\right)\\&=5.8253\;{\text{mol}}\\\end{aligned}[/tex]
From the balanced chemical reaction of decomposition of [tex]{\text{PC}}{{\text{l}}_3}[/tex], 4 moles of [tex]{\text{PC}}{{\text{l}}_3}[/tex] require 1207 kJ of energy. So the amount of energy required to decompose 5.8253 moles of [tex]{\text{PC}}{{\text{l}}_3}[/tex] is calculated as follows:
[tex]\begin{aligned}{\text{Amount of energy required}}&=\left({5.8253\;{\text{mol PC}}{{\text{l}}_3}}\right)\left({\frac{{{\text{1207 kJ}}}}{{{\text{4 mol PC}}{{\text{l}}_3}}}}\right)\\&={\text{1757}}{\text{.7842}}\;{\text{kJ}}\\&\approx{\text{1757}}{\text{.8 kJ}}\\\end{aligned}[/tex]
So the amount of energy required to decompose 800 g of [tex]{\mathbf{PC}}{{\mathbf{l}}_{\mathbf{3}}}[/tex] is 1757.8 kJ.
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Mole Concept
Keywords: PCl3, P4, Cl2, 6 Cl2, 4 PCl3, amount of energy, 1757.8 kJ, moles of PCl3, molar mass, given mass, 800 g, 137.33 g/mol, stoichiometry, reactant, product, decomposition reaction, 1207 kJ.
To determine the quantity of energy required to decompose 800 grams of [tex]PCl_3[/tex] is 1,757.82 kJ.
Given the following data:
Mass of [tex]PCl_3[/tex] = 800 gramsMolar mass of [tex]PCl_3[/tex] = 137.32 g/molTo determine the quantity of energy required to decompose 800 grams of [tex]PCl_3[/tex]:
First of all, we would write the properly balanced chemical equation for the decomposition of [tex]PCl_3[/tex]:
[tex]4PCl_3_{(g)} --->P_4_{(s)} +6Cl_2_{(g)} \ \;\delta h^{\circ}rxn =+1207 \;kJ[/tex]
Next, we would find the number of moles of [tex]PCl_3[/tex] contained in the chemical equation:
[tex]Number\;of\;moles = \frac{Mass}{molar\;mass}\\\\Number\;of\;moles = \frac{800}{137.32 }[/tex]
Number of moles = 5.8254 moles.
By stoichiometry:
4 moles of [tex]PCl_3[/tex] = 1207 kJ
5.8254 moles of [tex]PCl_3[/tex] = X kJ
Cross-multiplying, we have:
[tex]4 \times X = 1207 \times 5.8254\\\\4X=7,031.2578\\\\X=\frac{7,031.2578}{4}[/tex]
Energy, X = 1,757.82 kJ
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Give the product of the reaction of excess benzene (2 equivalents) with dichloromethane and alcl3.
In the presence of AlCl3, excess benzene reacts with dichloromethane to undergo a Friedel-Crafts alkylation, resulting in the product 1,2,4-trichloro-5,5-diphenylpentane.
Explanation:When dichloromethane is treated with excess benzene in the presence of an aluminum chloride catalyst (AlCl3), a Friedel-Crafts alkylation occurs. This is a type of electrophilic aromatic substitution reaction that introduces an alkyl group into the benzene ring. Here, the final product would be a dichloromethylated benzene molecule.
However, considering biselective alkylation resulting from the use of 2 equivalents of benzene, the product would be 1,2,4-trichloro-5,5-diphenylpentane. The reaction would be as follows: 2 equivalents of Benzene + CH2Cl2 (Dichloromethane) ->[AlCl3 catalyst] 1,2,4-trichloro-5,5-diphenyl pentane
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To learn more about the genetic material of plant and animal cells, where would a person look?
A.in the lysosomes
B.in the nucleus
C.inside the chloroplasts
D.on the cell wall
Asexual reproduction involves
A.
two parents and results in offspring that are identical to one parent.
B.
only one parent and results in offspring that are very different from the parent.
C.
two parents and results in offspring that are different from both parents.
D.
only one parent and results in offspring that are identical to the parent.
Answer:
d) only one parent and results in offspring that are identical to the parent.
Explanation:
just did the study island
Final answer:
Asexual reproduction requires only one parent and gives rise to genetically identical offspring, seen in processes like binary fission.
Explanation:
Asexual reproduction involves only one parent and results in offspring that are genetically identical to the parent. This method of reproduction is seen in all prokaryotes and some eukaryotes, through various mechanisms such as binary fission, fragmentation, and budding.
In binary fission, a common form of asexual reproduction, the parent cell divides to form two identical daughter cells.
Asexual reproduction requires only one parent and gives rise to genetically identical offspring, seen in processes like binary fission.
How can a charged atom (an ion) attract a neutral atom? 1. the charged atom can hit the neutral atom and make it positively charged or negatively charged. 2. an ion polarizes a nearby neutral atom, so that the part of the atom nearer to the ion acquires a charge opposite to the charge of the ion, and the part of the atom farther from the ion acquires a charge of the same sign as the ion. 3. the charged atom can produce secondary electrons to interact with the neutral atom and make it positively charged or negatively charged. 4. the charged atom can emit x-rays to induce ionization of the neutral atom?
How many milliliters of 0.200 m fecl3 are needed to react with an excess of na2s to produce 1.38 g of fe2s3 if the percent yield for the reaction is 65.0%? 3 na2s(aq) + 2 fecl3(aq) → fe2s3(s) + 6 nacl(aq)?
100mL of [tex]\rm \bold { Fe_2Cl_3}[/tex] is needed to react with an excess of [tex]\rm \bold {Na_2 S}[/tex] to produce 1.38 g of [tex]\rm \bold { Fe_2S_3}[/tex] .
The reaction is
[tex]\rm \bold{3 Na_2S(aq) + 2 FeCl_2(aq) \rightarrow Fe_2S_3(s) + 6 NaCl(aq)}[/tex]
The mass of [tex]\rm \bold { Fe_2S_3}[/tex] is 1.38 g
The number of moles of [tex]\rm \bold { Fe_2S_3}[/tex] will be 0.00664 moles.
If the if the percent yield for the reaction is 65.0% or 0.65.
[tex]\rm \bold { Theoritical Yield = \frac{0.00664}{0.65} }\\\\\rm \bold { Theoritical Yield = 0.01 Moles}[/tex]
Since 2 mole of [tex]\rm \bold { Fe_2Cl_3}[/tex] is needed to produce 1 mole of [tex]\rm \bold { Fe_2S_3}[/tex].
[tex]\rm \bold { Fe_2Cl_3}[/tex] concentration is 0.020 mol
To find the from molarity formula
[tex]\rm \bold { V = \frac{n}{M} = \frac{0.020 mol}{ 0.2 M} / = 0.1 liter = 100 ml}\\\\\rm \bold { V = \frac{0.020 mol}{ 0.2 M} }\\\\\rm \bold { V = 0.1 liter = 100 ml}[/tex]
Hence we can conclude that 100mL of [tex]\rm \bold { Fe_2Cl_3}[/tex] is needed to react with an excess of [tex]\rm \bold {Na_2 S}[/tex] to produce 1.38 g of [tex]\rm \bold { Fe_2S_3}[/tex] .
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For 520.0 ml of a buffer solution that is 0.175 m in hc2h3o2 and 0.165 m in nac2h3o2, calculate the initial ph and the final ph after adding 0.020 mol of hcl.
At high pressures, real gases do not behave ideally. calculate the pressure exerted by 18.0 g h2 at 20.0°c in a 1.00 l container assuming in part 1 non-ideal behavior and in part 2 ideal behavior.
An unknown substance has the composition of 77.87% C, 2.63% H and 55.62% O. The compound has a molar mass of 345.2 g/mole. What is the molecular formula?
If the δh°soln of hno3 is –33.3 kj/mol, then how much heat is evolved by dissolving 0.150 mol hno3 in 100.0 ml of water?
By using the equation q = nΔH, where 'q' is the heat evolved or absorbed, 'n' is the number of moles, and 'ΔH' is the enthalpy change per mole, it is calculated that 5.0 kJ of heat is evolved when 0.150 mol of HNO3 is dissolved in 100.0 ml of water.
Explanation:The amount of heat released or absorbed in a reaction is typically calculated using the equation q = nΔH, where 'q' is the heat evolved or absorbed, 'n' is the number of moles, and 'ΔH' is the enthalpy change per mole. Given that the enthalpy of dissolving HNO3, ΔH°soln, is -33.3 kJ/mol, and we are dissolving 0.150 mol HNO3, we can substitute these values into the equation.
So, q = nΔH = 0.150 mol * -33.3 kJ/mol = -5.0 kJ.
The negative sign indicates that the heat is evolved (released), as per the question. Thus, 5.0 kJ of heat is evolved by dissolving 0.150 mol HNO3 in 100.0 ml of water.
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When 0.150 mol of HNO3 is dissolved in 100.0 ml of water, 5 kJ of heat is released. This is calculated using the equation q = n x δh°soln over the negative valence of the enthalpy change -33.3 KJ/mol.
Explanation:The amount of heat evolved from dissolving a substance in solution can be found using the equation q = n x δh°soln, where q is the heat evolved, n is the number of moles, and δh°soln is the enthalpy change per mole of solute. In this case, you have been given the enthalpy change per mole of HNO3 (δh°soln) as -33.3 kJ/mol, and the number of moles (n) as 0.150 mol. Plugging these into the equation gives q = 0.150 mol x -33.3 kJ/mol = -5 kj. This means that 5 kJ of heat is released when 0.150 mol of HNO3 is dissolved in 100.0 ml of water.
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An object that is traveling around another body in space is in ______ around that body
An object traveling around another body in space is in orbit. This balance between inertia and gravitational pull defines the path and shape of the orbit, which can be circular or elliptical.
An object that is traveling around another body in space is in orbit around that body. An orbit is a regular, repeating path that one object in space takes around another one. An object in orbit is in a delicate balance between the inertia of its motion in a straight line and the gravitational pull that the other body exerts on it. Familiar examples include the Earth orbiting the Sun or the Moon orbiting Earth. The shape of an orbit can be circular or elliptical, and the mechanics of orbits are governed by the laws of physics, particularly by Newton's Law of Universal Gravitation and his laws of motion.
The decomposition of hi has a rate constant of 1.80 × 10-3 m-1s-1. how much hi remains after 8.50 min if the initial concentration of hi is 4.78 m?
when the ph of a solution changes from a ph of 5 to a ph of 3 the hydronium ion concentration is
When the pH of a solution changes from 5 to 3, the hydronium ion concentration increases significantly.
PH of Solution:
The relationship between pH and hydronium ion concentration
[H₃O⁺] is given by the formula:
pH = -log [H₃O⁺]
To find the hydronium ion concentrations at pH 5 and pH 3:
At pH 5: [H₃O⁺] = 10⁻⁵ M
At pH 3: [H₃O⁺] = 10⁻³ M
Thus, the hydronium ion concentration increases by a factor of 100 when the pH changes from 5 to 3
Maple syrup has a density of 1.325 g/ml, and 100.00 g of maple syrup contains 67 mg of calcium in the form of ca2+ ions. what is the molarity of calcium in maple syrup?
The molarity of calcium in maple syrup is 33.4 M.
Explanation:To find the molarity of calcium in maple syrup, we need to first convert the given amount of calcium from milligrams to grams. Since there are 1000 milligrams in a gram, 67 mg is equal to 0.067 g. Next, we divide the mass of calcium by the density of maple syrup to find the volume of maple syrup.
Volume of maple syrup = mass of calcium / density of maple syrup = 0.067 g / 1.325 g/ml = 0.0506 ml
Now, we can calculate the molarity of calcium (Ca2+) in maple syrup by dividing the moles of calcium by the volume of maple syrup in liters:
Molarity = moles of calcium / volume of maple syrup = (0.067 g / 40.08 g/mol) / (0.0506 ml / 1000 ml/L) = 33.4 M
What concentration of the barium ion, ba2+, must be exceeded to precipitate baf2 from a solution that is 1.00×10−2 m in the fluoride ion, f−? ksp for barium fluoride is 2.45×10−5 . express your answer with the appropriate units?
Answer is: concentration of the barium ion is 0.245 M.
Chemical reaction: BaF₂ → Ba²⁺ + 2F⁻.
[F⁻] = 1.00·10⁻² M.
Ksp = 2.45·10⁻⁵.
Ksp = [Ba²⁺] · [F⁻]².
[Ba²⁺] = Ksp ÷ [F⁻]².
[Ba²⁺] = 2.45·10⁻⁵ ÷ (1.00·10⁻² M)².
[Ba²⁺] = 0.245 M.
Answer: The concentration of barium ions that must exceed to precipitate the salt is 0.245 M
Explanation:
Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio. It is represented as [tex]K_{sp}[/tex]
Barium fluoride is an ionic compound formed by the combination of 1 barium ion and 2 fluoride ions.
The equilibrium reaction for the ionization of barium fluoride follows the equation:
[tex]BaF_2(s)\rightleftharpoons Ba^{2+}(aq.)+2F^-(aq.)[/tex]
The solubility product for the above reaction is:
[tex]K_{sp}=[Ba^{2+}]\times [F^-]^2[/tex]
We are given:
[tex][F^-]=1.00\times 10^{-2}M\\\\K_{sp}=2.45\times 10^{-5}[/tex]
Putting values in above equation, we get:
[tex]2.45\times 10^{-5}=[Ba^{2+}]\times (1.00\times 10^{-2})^2[/tex]
[tex][Ba^{2+}]=\frac{2.45\times 10^{-5}}{(1.00\times 10^{-2})^2}=0.245M[/tex]
Hence, the concentration of barium ions that must exceed to precipitate the salt is 0.245 M
Draw the lewis structure with the atoms arranged as hclo. include all non-bonding electronsand non-zero formal charges. do not draw cl with an expanded octet.
The Lewis structure of HClO consists of bonds from Cl to each of H and O, with Cl having 5 pairs of non-bonding electrons and O having 2 pairs.
Explanation:To create the Lewis structure for HCLO, start by counting valence electrons. Hydrogen (H) has 1, Oxygen (O) has 6, and Chlorine (Cl) has 7. This totals to 14. Next, choose the atom with the least electronegativity (Cl in this case) to be the central atom, and draw bonds to other elements. A bond to each H and O from Cl uses up 4 electrons, leaving 10. Now fill the octets of the H and O atoms.
The Lewis structure should then look like this:
H - Cl - O
With 5 pairs of non-bonding electrons around Cl and two pairs of non bonding electrons around O.
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how many moles of Na3PO4 would be required to react with 1.0 mol of AgNO3?
Answer: The number of moles of sodium phosphate required is 0.33 moles
Explanation:
We are given:
Moles of silver nitrate = 1 mole
The chemical equation for the reaction of sodium phosphate and silver nitrate follows:
[tex]Na_3PO_4+3AgNO_3\rightarrow 3NaNO_3+Ag_3PO_4[/tex]
By Stoichiometry of the reaction:
3 moles of silver nitrate reacts with 1 mole of sodium phosphate.
So, 1.0 moles of silver nitrate will react with = [tex]\frac{1}{3}\times 1.0=0.33mol[/tex] of sodium phosphate.
Hence, the number of moles of sodium phosphate required is 0.33 moles
Which of the following statements describes an interaction between the geosphere and biosphere?
A.Soil acidity affects plant growth
B.Polar animals find their habitat in frozen ice.
c. Wind energy is used to create electrical power.
DLevel of precipitation has an impact on crop yield
Answer:
The correct answer is A) Soil acidity affects plant growth.
Explanation:
What happens when you place a plant in soil and of course add water? The soil helps it grow.
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Which of the following is the best definition of a chemical change?
Answer: A change in a substance where one or more new substances form
Explanation: Apex
A mixture is two or more substances that are mixed together but not chemically combined. The substances in a mixture each keep their own properties and can be separated from the mixture.
Identify the substance in a mixture of sand, salt, sawdust, and iron filings that can easily be separated by dissolving the mixture in water.
A) sand
B) salt
C) sawdust
D) iron filings
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Draw the major organic product formed when the compound shown below undergoes a reaction with two equivalents of ch3ch2mgbr and then is treated with water.
The product of the reaction is 3-ethylpentan-3-ol .
What is the Grignard reagent?The Grignard reagent is a compound that is composed of an alkyl magnesium halide. Hence the general formula of a Grignard reagent is RMgX.
Since we are using two equivalents of ch3ch2mgbr and then is treat with water, the product compound is 3-ethylpentan-3-ol as shown in the image attached to this answer.
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Compound b (c9h9no4) is a carboxylic acid that has a nitro group attached to an aromatic ring. draw this compound based on its 1h nmr spectrum.
Vitellium (Vi) has the following composition:
Vi–188: 187.9122 amu; 10.861%
Vi–191: 190.9047 amu; 12.428%
Vi–193: 192.8938 amu; 76.711%
Based on this data, what can you predict about the average atomic mass of vitellium?
A.)It will be equal to the arithmetic mean of the masses of the three isotopes.
B.)It will be closer to the mass of Vi–188.
C.)It will be closer to the mass of Vi–193.
D.)It will be equal to the mass of Vi–193.
And I am a PLATO user so I already know it's not A!
6. The illustration below represents the Grand Canyon..
Is oil used by other organisms on Earth? If yes, explain.
Shown below is a lewis structure of the formamidinium ion. what geometry is exhibited by the two nitrogens in the formamidinium ion?
The geometry around the nitrogens in the formamidinium ion can be inferred based on principles of molecular geometry, likely exhibiting either trigonal planar or tetrahedral geometry, depending on their specific bonding and hybridization states.
Explanation:The question asks about the geometry exhibited by the two nitrogens in the formamidinium ion. To answer this, we refer to basic principles of molecular geometry and electron-pair geometry in chemistry. While the formamidinium ion isn't directly analogous to the ammonium ion, NH4+, which exhibits a tetrahedral electron-pair geometry and a tetrahedral molecular structure, we can deduce similarities based on the presence of nitrogen atoms and their bonding characteristics. In general, nitrogen atoms in amides or similar compounds tend to exhibit sp2 or sp3 hybridization, depending on their bonding and lone pairs.
In the case of the formamidinium ion, each nitrogen would likely be surrounded by three regions of electron density (due to bonds or lone pairs), suggesting an approximate trigonal planar geometry around each nitrogen if they exhibit sp2 hybridization, or a tetrahedral geometry if there's additional bonding or lone pairs leading to sp3 hybridization. However, without the explicit Lewis structure presented, it's crucial to consider the context of the ion's structure, including resonance and the role of any lone pairs or charged species in determining final geometry.
Which of the following is the correct name for the compound MgBr2?
Magnesium bromate
Magnesium bromide
Magnesium dibromide
Magnesium (1) bromide
If a reaction mixture initially contains a co concentration of 0.1470 and a cl2 concentration of 0.175 at 1000k. what is the equilibrium concentration of co at 1000 k?