ASAP PLEASE:

Segment RS is congruent to segment DF. Which congruence statement is true?

- RS ≅ DF
- RS ≅ SFD
- RS ≅ SF
- RS ≅ RD

ASAP PLEASE:Segment RS Is Congruent To Segment DF. Which Congruence Statement Is True?- RS DF- RS SFD-

Answers

Answer 1

Answer:

A. [tex]\text{ Arc RS}\cong \text{Arc DF}[/tex]

Step-by-step explanation:

We have been given a circle and we are told that segment RS is congruent to segment DF.

We can see that segment RS corresponds to arc RS and segment DF corresponds to arc DF.

As both segments are congruent, therefore, both arcs will be congruent as well.

We can represent this information as:

[tex]\text{ Arc RS}\cong \text{Arc DF}[/tex]

Therefore, option A is the correct choice.


Related Questions

Jake went on a road trip with his family this summer. On Monday, they drove 629 miles. Tuesday, they drove 215 miles. On Wednesday, they only drove 111 miles. And, on Thursday, they drove 588 miles. Estimate the total number of miles Jake's family traveled by rounding each value to the hundreds place. 1,200 1,300 1,400 1,500

Answers

*Note:  This symbol ≈ means approximately. 

629 ≈ 600
215 ≈ 200
111 ≈ 100
588 ≈ 600

Now, we add the simplified numbers up: 600 + 200 + 100 + 600 = 1500. So, your answer is or 1,500.

Answer:

D

Step-by-step explanation:

Find the range of each function for the domain {-4, -2, 0, 1.5, 4}. f(x) = 5x^2 + 4

Answers

Substitute x with the members of the domain.
f(x) = 5x² + 4

Substitute with the domain of -4
f(x) = 5x² + 4
f(-4) = 5(-4)² + 4
f(-4) = 5(16) + 4
f(-4) = 80 + 4
f(-4) = 84

Substitute with the domain of -2
f(x) = 5x² + 4
f(-2) = 5(-2)² + 4
f(-2) = 5(4) + 4
f(-2) = 20 + 4
f(-2) = 24

Substitute with the domain of 0
f(x) = 5x² + 4
f(0) = 5(0)² + 4
f(0) = 5(0) + 4
f(0) = 0 + 4
f(0) = 4

Substitute with the domain of 1.5
f(x) = 5x² + 4
f(1.5) = 5(1.5)² + 4
f(1.5) = 5(2.25) + 4
f(1.5) = 11.25 + 4
f(1.5) = 15.25

Substitute with the domain of 4
f(x) = 5x² + 4
f(4) = 5(4)² + 4
f(4) = 5(16) + 4
f(4) = 80 + 4
f(4) = 84

The range of the function for those domain is {4, 24, 15.25, 84}
Final answer:

To find the range of the function f(x) = 5x^2 + 4 for the given domain {-4, -2, 0, 1.5, 4}, evaluate the function for each value in the domain and find the minimum and maximum outputs. The range of the function is {4, 84}.

Explanation:

To find the range of the function f(x) = 5x^2 + 4 for the given domain {-4, -2, 0, 1.5, 4}, we need to evaluate the function for each value in the domain and find the minimum and maximum outputs.

Substitute -4 into the function: f(-4) = 5(-4)^2 + 4 = 84Substitute -2 into the function: f(-2) = 5(-2)^2 + 4 = 24Substitute 0 into the function: f(0) = 5(0)^2 + 4 = 4Substitute 1.5 into the function: f(1.5) = 5(1.5)^2 + 4 = 16.75Substitute 4 into the function: f(4) = 5(4)^2 + 4 = 84

The range of the function is the set of all possible outputs. In this case, the minimum output is 4 and the maximum output is 84. Therefore, the range of the function is {4, 84}.

Sam used 2 gallons of gas to drive 50 miles and 4 gallons of gas to drive 100 miles. Is this a proportional relationship? Explain your reasoning.

Answers

yes because the unit rate is 25 miles per gallon. both of these ratios simplify down to that unit rate. since they simplify down to the same unit rate, they are proportional

Sam's gas usage is a proportional relationship because he gets a constant 25 miles per gallon in both given scenarios.

Yes, this is a proportional relationship. To determine proportionality, we can calculate the gas mileage for each scenario. Gas mileage is calculated by dividing the number of miles driven by the number of gallons used. For the first scenario, the gas mileage is 50 miles / 2 gallons = 25 miles per gallon. In the second scenario, the gas mileage is 100 miles / 4 gallons = 25 miles per gallon. Since the gas mileage is the same in both cases, it indicates a proportional relationship.

HELP ME PLEASE!!
Does each transformation map a triangle in Quadrant II to Quadrant I?

Select Yes or No for A-C.

Answers

the answer:
A: yes
b: no
C:yes

Hannah completed 3/4 of her homework on Saturday morning and 1/8 ofit on Saturday night. How much more homework does she need to complete?

Answers

She has done 7/8, so she needs to do 1/8 to complete.
1/8

You have a least common denominator. 3/4 is the same as 6/8. 6/8 + 1/8 = 7/8 leaving a remainder of 1/8

128,96,72,54,...find the common ratio

Answers

Final answer:

To find the common ratio of the given sequence, divide each term by the previous term. The common ratio is 0.75.

Explanation:

The given sequence is: 128, 96, 72, 54, ...

To find the common ratio, we need to determine the ratio between consecutive terms. We can do this by dividing each term by the previous term.

Ratio between the 2nd and 1st terms: 96/128 = 0.75

Ratio between the 3rd and 2nd terms: 72/96 = 0.75

Ratio between the 4th and 3rd terms: 54/72 = 0.75

Since the ratio is the same for all consecutive terms, we can conclude that the common ratio of this geometric sequence is 0.75.

The correct common ratio for the given sequence is [tex]\(\frac{3}{4}\) or 0.75.[/tex]

To find the common ratio of the sequence, we divide each term by the previous term and look for a consistent value:

1. For the second term, \(96\), divided by the first term, [tex]\(128\)[/tex], we get:

[tex]\[ \frac{96}{128} = \frac{3}{4} = 0.75 \][/tex]

2. For the third term, [tex]\(72\),[/tex] divided by the second term, [tex]\(96\),[/tex] we get:

[tex]\[ \frac{72}{96} = \frac{3}{4} = 0.75 \][/tex]

3. For the fourth term, [tex]\(54\),[/tex] divided by the third term, [tex]\(72\)[/tex], we get:

[tex]\[ \frac{54}{72} = \frac{3}{4} = 0.75 \][/tex]

How to find common difference of arithmetic sequence given first and last term?

Answers

Yeah there is a way... Lemme give a typical question...
Find the common difference of an arithmetic progression whose first term Is 1 and last term is 1023...

First term = T¹ =a
Last term = Tn = a + (n-1)d

Since your given the values of the first and the last term... You can substitute

Tn = 1 + (1023-1)d

1023 = 1 + 1022d

1022d = 1023 - 1

1022d = 1022

common difference = 1...

So there is a way....

You can get the common difference using the two terms given...

Hope this helped...

Final answer:

To find the common difference, subtract the first term from the last term and divide by the number of terms minus 1.

Explanation:

To find the common difference of an arithmetic sequence given the first and last term, you can use the formula: common difference = (last term - first term) / (number of terms - 1). First, subtract the first term from the last term. Then, subtract 1 from the number of terms. Finally, divide the result of the subtraction by the number of terms minus 1 to find the common difference.

The graph shows the amount of money the Phillips family spent each month on groceries.
When did the greatest month-to-month increase in spending occur?
July–August
April–May
June–July
May–June

Answers

Your answer is from July to August.

Answer:

Option A. July-August.

Step-by-step explanation:

Phillips family spent each month on groceries. The amount of money in each month is shown in a graph.

Approximate amount in each month was spent :

March : $450

April  : $400

May  :  $400

June  :  $500

July  :  $300

August : $ 500

Sep.  :  $480

Oct. : $420

From the graph given, there is a greatest month to month increase in spending occur in July to August (from $300 to $500).

So Option a. July-August is the correct answer.

Refer to the figure below to complete the following item. Given: Quadrilateral ROSE is trapezoid with median If MN = 24 and ES = 10, then RO = 27 30 38

Answers

18 is you answer. Hope this helps.

Answer:

The length of RO is 38.

Step-by-step explanation:

Given information: ROSE is trapezoid with median If MN = 24 and ES = 10.

Sufficient information is not given. This question can be solved if it is given that  [tex]RO\parallel ES[/tex].

According to the properties of trapezoid the length of the median is the average of length of parallel sides.

Let [tex]RO\parallel ES[/tex] and length of RO be x.

Since MN is median, therefore

[tex]MN=\frac{RO+ES}{2}[/tex]

[tex]24=\frac{x+10}{2}[/tex]

[tex]48=x+10[/tex]

[tex]x=38[/tex]

Therefore length of RO is 38.

The first team of workers received 50 kg of cement less than the second team. for every hour of work the first team was using 150 kg of cement, while the second team was using 200 kg. in three hours the first team had 1.5 times as much remaining cement as the second team. how much cement was delivered to each team of workers

Answers

Final answer:

To find out how much cement was delivered to each team, we can set up an equation based on the information provided and solve for the unknowns.

Explanation:

Let's denote the amount of cement delivered to the second team as x kg. According to the question, the first team received 50 kg less, so they received x - 50 kg of cement.


The first team used 150 kg of cement every hour for 3 hours, so they used a total of 150 * 3 = 450 kg of cement. Therefore, they had 1.5 times as much remaining cement as the second team, which means they had 1.5 * (x - 50) kg of cement remaining.


Since we know that the remaining cement of the first team is equal to 450 kg, we can set up the following equation: 1.5 * (x - 50) = 450. Solving this equation will give us the amount of cement delivered to each team.

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The first team received 750 kg of cement, and the second team received 800 kg of cement.

Let's denote the amount of cement delivered to the first team as [tex]\( x \)[/tex]kg and to the second team as[tex]\( y \)[/tex] kg. According to the problem, we have the following information:

1. The first team received 50 kg of cement less than the second team: [tex]\( x = y - 50 \)[/tex].

2. The first team uses 150 kg of cement per hour, and the second team uses 200 kg per hour.

3. After three hours of work, the first team has 1.5 times as much remaining cement as the second team.

Let's calculate the amount of cement used by each team after three hours:

- The first team uses [tex]\( 150 \times 3 = 450 \)[/tex] kg of cement.

- The second team uses [tex]\( 200 \times 3 = 600 \)[/tex] kg of cement.

Now, let's denote the remaining cement for the first team as [tex]\( R_1 \)[/tex] and for the second team as [tex]\( R_2 \)[/tex]. We can set up the following equations:

For the first team: [tex]\( R_1 = x - 450 \)[/tex].

For the second team: [tex]\( R_2 = y - 600 \)[/tex].

According to the problem, the remaining cement for the first team is 1.5 times that of the second team: [tex]\( R_1 = 1.5 \times R_2 \).[/tex]

Substituting the expressions for[tex]\( R_1 \)[/tex] and [tex]\( R_2 \)[/tex] into the equation, we get:

[tex]\( x - 450 = 1.5 \times (y - 600) \).[/tex]

Now, we can substitute[tex]\( x = y - 50 \)[/tex] into the equation:

[tex]\( (y - 50) - 450 = 1.5 \times (y - 600) \),[/tex]

[tex]\( y - 500 = 1.5y - 900 \),[/tex]

[tex]\( 0.5y = 400 \),[/tex]

[tex]\( y = 800 \).[/tex]

Now that we have [tex]\( y \)[/tex], we can find [tex]\( x \)[/tex]:

[tex]\( x = y - 50 \),[/tex]

[tex]\( x = 800 - 50 \)[/tex],

[tex]\( x = 750 \).[/tex]

What is 5/8 ± 2/5? Please Help easy points

Answers

easy points thank you so much :^)

Mark need to make $5 for every $2 he spends for his business to succeed. If Mark spends $32, how much money will he make?

A. $80

B. $160

C. $95

Answers

Make : Spend
5 : 2

He spends $32
32 ÷ 2 = 16

Make : Spend
5 : 2 
5 x 16 : 2 x 16
80 : 32
Therefore he needs to make $80 (Answer A)

A cylinder has a radius of 10 feet and a height of 11.4 feet. What is the approximate volume of the cylinder? Use 3.14 for pi.

A: 114.0 ft3

B: 228.0 ft3

C: 2145.1 ft3

D: 3579.6 ft3

WORTH 50 POINTS!!!!!!

Answers

C: 2145.1 ft3 i hope that help
V = (pi) * r^2 * h
V = 3.14 * 10^2 * 11.4
V = 35.796 * 100
V = 3579.6 ft ^3 <==

One cubic centimeter of sand weighs 1.9 grams. Find the amount of sand that the sandcastle bucket can hold.

Answers

The solid is made up of the cuboid part and the pyramid part
The volume of the cuboid is, l×w×h
14 ×14×11 =2156 cm³
The volume of the pyramid; 1/3 base area × vertical height
that is; 1/3 ×14 ×14 ×12=784 cm³
Therefore, the the total volume = 2156 +784 =2940 cm³
but 1 cubic centimeters has a weight of 1.9 g
Thus the amount of sand will be
 2940 ×1.9=  5586 g or 5.586 kg

Answer:

5.586

Step-by-step explanation:

Which of the following polynomials corresponds to the subtraction of the multivariate polynomials 19x 3 + 44x 2 y + 17 and y 3 - 11xy 2 + 2x 2 y - 13x 3? y 3 - 6x 3 + 33x 2y + 2xy 2 + 17 20x3 - y3 + 33x 2y + 2xy 2 + 17 31x 3 - 6x 3 + 44x 2y + 11xy 2 + 17 32x 3 - y 3 + 42x 2y + 11xy 2 + 17

Answers

[tex](19x^3+44x^2y+17)-(y^3-11xy^2+2x^2y-13x^3) [/tex]
We can use the distributive property to distribute the subtraction sign:
[tex]19x^3+44x^2y+17-y^3--11xy^2-2x^2y--13x^3[/tex]
When we subtract a negative it is the same as adding a positive:
[tex]19x^3+44x^2y+17-y^3+11xy^2-2x^2y+13x^3[/tex]
Gather the like terms:
[tex]19x^3+13x^3+44x^2y-2x^2y+17-y^3+11xy^2 \\ \\=32x^3+42x^2y+17-y^3+11xy^2[/tex]
Rearrange the polynomial in order of powers to x, greatest to least:
[tex]32x^3+42x^2y+11xy^2-y^3+17[/tex]

Answer:

32 x^3 - y^3 + 42 x 2y + 11 xy^2 + 17

What are the two equations created by the inequality |x–12| + 5 < 27? y1= and y2=

Answers

First we rewrite the expression:
 | x-12 | <27-5
 | x-12 | <22
 Then
 We write the problem as a compound inequality:
 -22 <x-12 <22
 From here, we obtain 2 equations:
 -22 <x-12
 x-12 <22
 Rewriting:
 -x + 12> 22
 x-12 <22
 Answer:
 the two equations created by the inequality | x-12 | + 5 <27 are: 
 
-x + 12> 22
 x-12 <22

Answer:

y1= |x-12|

y2= 22

Which graph represents the two functions? Graph 3

Step-by-step explanation:

A local store buys used video games. For each game bought, they will pay $18 less than the original price paid for the game. Which expressions represent the total amount Jordan will receive if he sells “n” games that originally cost “d” dollars each? Check all that apply.

Answers

correct answers are n(d-18) and dn - 18n

Answer:

B. [tex]n(d-18)[/tex]

D. [tex]dn-18n[/tex]

Step-by-step explanation:

Let d represent the original price paid for the game.

We have been given that a local buys used video games. For each game bought, they will pay $18 less than the original price paid for the game.

The price of used video game would be original price minus 18. We can represent this information in an expression as:

[tex]d-18[/tex]

We have been given that Jordan sold n games, so the cost of n used games would be [tex]n(d-18)[/tex].

Using distributive property we will get,

[tex]n(d-18)=dn-18n[/tex]

Therefore, option B and D are correct choices.

A trowel is in the shape of a trapezoid. For what value of x is the trapezoid am isosceles trapezoid

Answers

Final answer:

A trapezoid becomes an isosceles trapezoid when its non-parallel sides, or legs, are of equal length. Thus, for a given length x, an isosceles trapezoid requires both legs to be x in length.

Explanation:

A trapezoid is a geometric shape with one pair of parallel sides. A trapezoid becomes an isosceles trapezoid when the non-parallel sides (the legs) are equal in length. If we denote the length of the legs as x, then the trapezoid becomes an isosceles trapezoid when both legs are of equal length, meaning x equals x.

Without additional information such as the lengths of the base and height of the trapezoid or the angles within it, we cannot provide a specific numerical value for x. The key to remember here is that an isosceles trapezoid has equal length legs - so whatever value you have for one leg, the other leg must be the same for it to qualify as an isosceles trapezoid.

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Which of these is the best description of a random sample?

Answers

Can I see the option or the answer choices?

ABE Software creates customized software that sells for $3,816,981.10 total. ABE Software’s cost is $1,723,000.00 and overhead expenses are estimated at 47% of the selling price. What is ABE Software’s net profit to the nearest dollar?

Answers

$3,816,981.10 -0.47*3,816,981.10 -1,723,000.00 = $299,999.983

Net profit, rounded to the nearest dollar, is $300,000.

Today's newspaper contains a 20%-off coupon at Old Army. The $100 jacket that you want was already reduced by 40%. What as the final price that you paid for the jacket

Answers

100-40%=60
60-20%=48
$48.00 is the final price you pay.
Answer:

The final price that is paid for the jacket is:

                    $ 48

Step-by-step explanation:

The actual cost of jacket was: $ 100

The cost of the jacket was reduced by 40%

This means that the after reduction of 40% the jacket will cost:

[tex]100-\dfrac{40}{100}\times 100\\\\\\=100-40\\\\=60[/tex]

This means that the cost of jacket after 40% reduction is: $ 60

Also, there was a coupon that contains 20% off.

This means that the jacket will actually cost:

[tex]60-\dfrac{20}{100}\times 60\\\\\\=60-12\\\\\\=48[/tex]

                    The final price of jacket is:

                              $ 48

Which explains how to determine 40% of 50?

Answers

Multiply 50 by .4 or .40. Both give the same answer, which is 20.

Answers please???????

Answers

The area is the same no matter how you calculate it.
.. A = b*h
.. 10*h = 9.8*5.6
.. h = 9.8*5.6/10
.. h = 5.488

HELP FAST PLEASE

A six-feet-tall man looks off the roof of a five-story hotel. He sees a statue that is 75 ft. away from the hotel. If he is looking at the base of the statue, what angle does his sight line form with the side of the hotel? Assume that each complete story of the hotel is 12 ft. tall.

32.6 degrees
43.9 degrees
48.7 degrees
54.2 degrees

Answers

i think it is 48.7. if i get it wrong sorry

Answer: 48.7 degrees

Step-by-step explanation:

Let [tex]\theta[/tex] is the angle between the his sight line form with the side of the hotel,

Since, the building is of 5-story and a men having height 6 feet is in the fifth-story.

Thus, the total length from the eyes of the man and foot of the building = 6 + 12 × 5 = 6 + 60 = 66 feet

Also, the distance of the statue from the foot of the building = 75 feet.

Then by the below diagram,

[tex]tan\theta = \frac{75}{60+6}[/tex]

[tex]tan\theta = \frac{75}{66}[/tex]

[tex]\theta=48.6522227803\approx 48.7\text{ degree}[/tex]

A jar contains "x" black and "y" white balls. What is the probability that a random draw is black?

Answers

Total would be "x" plus "y".
Probability of drawing a black ball is x / (x + y)


Answer:

probability that a random draw is black = [tex]\frac{x}{x+y}[/tex].

Step-by-step explanation:

Given: A jar contains "x" black and "y" white balls.

To find: What is the probability that a random draw is black.

Solution: We have given that black balls  = x

                                                 white balls = y

                                     total balls = x + y

probability that a random draw is black = [tex]\frac{Number\ of\ outcome happen}{Total numer of outcomes}[/tex]

probability that a random draw is black = [tex]\frac{Ball\ drawn\ is\ black}{Total\ number\ of\ ball}[/tex].

probability that a random draw is black = [tex]\frac{x}{x+y}[/tex].

Therefore, probability that a random draw is black = [tex]\frac{x}{x+y}[/tex].

Please help!! A fire hydrant 2.5 feet high casts a 5 foot shadow. How tall is a street light that casts a 26 foot shadow at the same time?

Answers

13 feet I think idrk
The height is thirteen feet.

Willem bought a jacket on sale. the price was 40% off the original price of $60. how much did he pay? answer

Answers

60 * 0.4  = $24
60 - 24 = $36
He paid 36 dollars. 
Hello!

"40% off" means they're offering a discount on the jacket, so Willem eill be saving money.

To calculate how much Willem will pay after the discount, we must first find and subtract the discount from the cost of the jacket.

60 × 40% (or 0.40) = 24

Subtract this:

60 - 24 = 36

ANSWER:

Willem paid $36.00 for the jacket.

Please help with 2 questions.

Answers

For perimeter you take the larger length (15) and divide by the smaller (9) and reduce.
15/9 = 5/3 or C

For area you take the ratio for the perimeter and square it so
5/3 * 5/3 = 25/9

Which equation models the problem below if c represents the number of puppies whose eyes are closed?

There are 15 puppies in a photograph, and 11 of them have their eyes open.
How many puppies have their eyes closed?



c – 11 = 15

11 – c = 15

15 + c = 11

11 + c = 15

Answers

First you must take into account the variable that is being defined for this case:
 c = represents the number of puppies whose eyes are closed.
 We can then write the following equation:
 15 = 11 + c
 Rewriting the equation:
 11 + c = 15
 Clearing c:
 c = 15-11
 c = 4
 4 puppies have their eyes closed
 Answer:
 11 + c = 15
 4 puppies have their eyes closed

Answer:

11+c=15

Step-by-step explanation:

4 pups have their eyes closed

Question 1: if you were to calculate a confidence interval using a confidence level of 0.9 and then calculated a second confidence interval using the same data but changed the confidence level to 0.95, would the interval be more narrow or wider?

Answers

The confidence interval would be wider so that you can be more confident that the parameter you're measuring (eg: population mean mu) is inside the confidence interval. 

It's like saying "the treasure is somewhere in the country" which is fairly vague but could be true. To be more confident, you can update it to "the treasure is somewhere on the continent". It's even more vague but it increases the chances of being correct. 
Final answer:

The 95 percent confidence interval is wider than the 90 percent confidence interval because the 95 percent level of confidence includes more of the distribution. This means there is a greater level of certainty that the true value of the population mean is contained within the interval.

Explanation:

The 90 percent confidence interval is (67.18, 68.82). The 95 percent confidence interval is (67.02, 68.98). The 95 percent confidence interval is wider. If you look at the graphs, because the area 0.95 is larger than the area 0.90, it makes sense that the 95 percent confidence interval is wider. For more certainty that the confidence interval actually does contain the true value of the population mean for all statistics exam scores, the confidence interval necessarily needs to be wider.

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