Assume that when adults with smartphones are randomly​ selected, 51​% use them in meetings or classes. If 11 adult smartphone users are randomly​ selected, find the probability that fewer than 5 of them use their smartphones in meetings or classes.

Answers

Answer 1

Answer:

The probability is 0.2356.

Step-by-step explanation:

Let X is the event of using the smartphone in meetings or classes,

Given,

The probability of using the smartphone in meetings or classes, p = 51 % = 0.51,

So, the probability of not using smartphone in meetings or classes, q = 1 - p = 1 - 0.51 = 0.49,

Thus, the probability that fewer than 5 of them use their smartphones in meetings or classes.

P(X<5) = P(X=0) + P(X=1) + P(X=2) + P(X=3)+P(X=4)

Since, binomial distribution formula is,

[tex]P(x) = ^nC_r p^x q^{n-x}[/tex]

Where, [tex]^nC_r=\frac{n!}{r!(n-r)!}[/tex]

Here, n = 11,

Hence,  the probability that fewer than 5 of them use their smartphones in meetings or classes

[tex]=^{11}C_0 (0.5)^0 0.49^{11}+^{11}C_1 (0.5)^1 0.49^{10}+^{11}C_2 (0.5)^2 0.49^{9}+^{11}C_3 (0.5)^3 0.49^{8}+^{11}C_4 (0.5)^4 0.49^{7} [/tex]

[tex]=(0.5)^0 0.49^{11}+11(0.5)0.49^{10} + 55(0.5)^2 0.49^{9}+165 (0.5)^3 0.49^{8} +330(0.5)^4 0.49^{7} [/tex]

[tex]=0.235596671797[/tex]

[tex]\approx 0.2356[/tex]


Related Questions

A 4:1 scale drawing of a bearing is shown on an A-size print. Using a ruler, you measure the inside diameter of the part on the paper and you get 1.50 inches. What is the actual part size in inches? A. 6.0 B. 1.5 C.4.0 D 375

Answers

Answer:

A. 6.0

Step-by-step explanation:

We have been given that the the inside diameter of the part on the paper is 1.50 inches.

We have been given that scale is 4:1 for actual size to drawing side.

[tex]\text{Scale}=\frac{\text{Actual size}}{\text{Map size}}=\frac{4}{1}[/tex]

Upon substituting 1.50 in our given proportion, we will get:

[tex]\frac{\text{Actual size}}{1.50\text{ inches}}=\frac{4}{1}[/tex]

[tex]\frac{\text{Actual size}}{1.50\text{inches}}\times 1.50\text{ inches}=\frac{4}{1}\times 1.50\text{ inches}[/tex]

[tex]\text{Actual size}=4\times 1.50\text{ inches}[/tex]

[tex]\text{Actual size}=6.0\text{ inches}[/tex]

Therefore, the actual size is 6.0 inches and option A is the correct choice.

M1Q1.) Which plot represents a stemplot of the data?

Answers

Answer:

answer 1

Step-by-step explanation:

Since there's only 1 value in the 90-99 groups it is either 1 or 3.

Furthermore, there are only 2 values starting with 10.

This only fits with answer 1

The answer is A.

A stem plot shows every number with the tens place and above being on the left side while the ones place is on the right side.

For example,

9 is in the tens place while 4 is in the ones place. So, this would look like:

9 | 4

There is only one number with a "9" in the tens place and there is only two numbers with "10" in the tens place. This only sastisfys the first option.

Best of Luck!

A dart is thrown upward with an initial velocity of 66 ft/s at an angle of elevation of 54°. Consider the position of the dart at any time t. Neglect air resistance. (Assume t is in seconds.) Find parametric equations that model the problem situation.

Answers

Final answer:

The parametric equations that model the problem situation in this case are x(t) = v0x * t,  [tex]y(t) = v0y * t - (1/2) * g * t^2,[/tex], and vy(t) = v0y - g * t.

Explanation:

To find parametric equations that model the problem situation, we need to consider the horizontal and vertical components of the motion separately.

Horizontal Component:

The horizontal velocity remains constant throughout the motion. Therefore, the horizontal position can be given by the equation:

x(t) = v0x * t

where x(t) is the horizontal position at time t and v0x is the initial horizontal velocity.

Vertical Component:

The vertical position depends on the initial velocity, acceleration due to gravity, and time. We can use the following equations:

[tex]y(t) = v0y * t - (1/2) * g * t^2,[/tex]

vy(t) = v0y - g * t

where y(t) is the vertical position at time t, v0y is the initial vertical velocity, g is the acceleration due to gravity (approximately 32 ft/s2), and vy(t) is the vertical velocity at time t.

Determine whether S is a basis for P3. S = {4t - 12,5 +t3,5 +3t,-3t2 +2/3

Answers

Answer:

Yes , S is a basis for [tex]P_3[/tex].

Step-by-step explanation:

Given

S=[tex]\left\{4t-12,5+t^3,5+3t,-3t^2+\frac{2}{3}\righ\}[/tex].

We can make a matrix

Let A=[tex]\begin{bmatrix}-12&4&0&0\\5&0&0&1\\5&3&0&0\\\frac{2}{3}&0&-3&0\end{bmatrix}[/tex]

All rows and columns are linearly indepedent and S span [tex]P_3[/tex].Hence, S is a basis of [tex]P_3[/tex]

Linearly independent means any row or any column should not combination of any rows or columns.

Because  a subset of V with n elements is a basis if and only if it is linearly independent.

Basis:- If B is a subset  of a vector space V over a field F .B is basis of V if satisfied the following conditions:

1.The elements of B are linearly independent.

2.Every element of vector V spanned by the elements of B.

A decade-old study found that the proportion of high school seniors who felt that "getting rich" was an important personal goal was 72% . Suppose that we have reason to believe that this proportion has changed, and we wish to carry out a hypothesis test to see if our belief can be supported. State the null hypothesis and the alternative hypothesis that we would use for this test.

Answers

Answer: [tex]H_0:p\leq0.72[/tex]

[tex]H_a:p\neq0.72[/tex]

Step-by-step explanation:

Given :  A decade-old study found that the proportion of high school seniors who felt that "getting rich" was an important personal goal was 72% .

Let 'p' be the new proportion of high school seniors who felt that "getting rich" was an important personal goal .

Claim : [tex]p\neq0.72[/tex]

We know that the null hypothesis has equal sign.

Therefore , the null hypothesis for the given situation will be opposite to the given claim will be :-

[tex]H_0:p=0.72[/tex]

And the alternative hypothesis must be :-

[tex]H_a:p\neq0.72[/tex]

Hence,  the null hypothesis and the alternative hypothesis that we would use for this test :

[tex]H_0:p\leq0.72[/tex]

[tex]H_a:p\neq0.72[/tex]

Final answer:

To test the belief that the proportion of high school seniors valuing wealth has changed, we would use H0: p = 0.72 as the null hypothesis and Ha: p

Explanation:

To conduct a hypothesis test regarding the proportion of high school seniors who believe that "getting rich" is an important goal, we state the null hypothesis (H0) and the alternative hypothesis (Ha). The null hypothesis is the statement that the proportion remains the same, while the alternative hypothesis states that the proportion has changed.

For a proportion of high school seniors who believe that getting rich is an important goal, if the decade-old study showed a proportion of 72%, we would have:

H0: p = 0.72

Ha: p ≠ 0.72

In the hypothetical scenario with a disease prevalence of 9.5% in the general population and finding 7% in a local survey, we would determine the null and alternative hypotheses regarding whether the local proportion is less than the national average as follows:

H0: p ≥ 0.095

Ha: p < 0.095

When conducting a hypothesis test, the null hypothesis typically represents no change or no effect, while the alternative hypothesis represents a change, difference, or effect that we are trying to detect.

(From Textbook) A company makes dog food out of chicken and grain. Chicken has 10 grams of protein and 5 grams of fat per ounce, and grain has 2 grams of protein and 2 grams of fat per ounce. A bag of dog food must contain at least 200 grams of protein and at least 150 grams of fat. If chicken costs 10 cents per ounce and grain costs 1 cent per ounce, how many ounces of each should the company use in each bag of dog food in order to minimize cost?

Answers

Answer:

The company use 0 ounces of chicken and 100 ounces of grain in each bag of dog food in order to minimize cost.

Step-by-step explanation:

Let x be the number of ounces of chicken

let y be the number of ounces of grains

We are given that Chicken has 10 grams of protein and 5 grams of fat per ounce.

Chicken has protein in 1 ounce = 10

Chicken has protein in x ounces = 10x

Chicken has fat in 1 ounce = 5

Chicken has fat in x ounces = 5x

We are also given that grain has 2 grams of protein and 2 grams of fat per ounce

Grain has protein in 1 ounce = 2

Grain has protein in y ounces = 2y

Grain has fat in 1 ounce = 2

Grain has fat in y ounces =2y

Now we are given that . A bag of dog food must contain at least 200 grams of protein and at least 150 grams of fat.

So, equation becomes:

[tex]10x+2y\geq 200[/tex] ---A

[tex]5x+2y\geq 150[/tex]  ---B

Since x and y represent the ounces .

So, [tex]x\geq 0[/tex] ---C and [tex]y\geq 0[/tex] ----D

Plot A ,B ,C and D on the graph

Refer the attached graph so , the corner points are (0,100),(10,50) and (30,0)

We are also given that chicken costs 10 cents per ounce and grain costs 1 cent per ounce

So, Cost function becomes : [tex]c=10x+y[/tex]

At(0,100)

[tex]c=10x+y[/tex]

[tex]c=10(0)+100[/tex]

[tex]c=100[/tex]

At(10,50)

[tex]c=10x+y[/tex]

[tex]c=10(10)+50[/tex]

[tex]c=150[/tex]

At(30,0)

[tex]c=10x+y[/tex]

[tex]c=10(30)+0[/tex]

[tex]c=300[/tex]

Minimum cost is 100 cents at (0,100)

So,  the company use 0 ounces of chicken and 100 ounces of grain in each bag of dog food in order to minimize cost.

Please help me with this

Answers

Answer:

Yes, the triangles are congruent by Hypotenuse angle congruence

Step-by-step explanation:

we know that

The Hypotenuse-Angle Congruence  states that If the hypotenuse and an acute angle of a right triangle are congruent to the hypotenuse and corresponding acute angle of another right triangle, then the triangles are congruent.

In this problem

The hypotenuse and an acute angle of the right triangle in the left are congruent to the hypotenuse and corresponding acute angle of the right triangle in the right

therefore

The triangles are congruent by Hypotenuse angle congruence

All tangents to the circle are congruent and form a square. The perimeter of square ACEG is 24 cm. What is the length of line segment BC?

Answers

Answer:

3 cm

Step-by-step explanation:

The perimeter of the square is 24 cm, so the side length is 6 cm.

I assume B is the point between A and C where the tangent line intersects the circle.  If so, B is the midpoint of AC, so it is half the length.  Therefore, BC = 3 cm.

The length of line segment BC is 3 cm.

What is a Square ?

A square is a polygon with four sides , all the sides of the square are equal.

It is given that the tangents of the circle are forming a square ,

The perimeter of the square is 24 cm.

the length of line segment BC = ?

The perimeter of the square is 4a

where a is the side of the square.

Substituting the values

24 = 4 * a

a = 6 cm

B is the mid point of the tangent length and therefore

BC = 6 /2 = 3 cm

Therefore , the length of line segment BC is 3 cm.

The missing image is attached with the answer.

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Identify the radius and center.

x^2 + y^2 - 8x - 6y + 16 = 0

Answers

Hello!

The answer is:

Center: (4,3)

Radius: 3 units.

Why?

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

[tex]x^2+y^2-8x-6y+16=0[/tex]

So, solving we have:

[tex]x^2-8x+y^2-6y=-16[/tex]

[tex](x^2-8x+(\frac{8}{2})^{2} )+(y^2-6y+(\frac{6}{2})^{2})=-16+(\frac{8}{2})^{2}+(\frac{6}{2})^{2}\\\\(x^2-8x+16)+(y^2-6y+9)=-16+16+9\\\\(x^2-4)+(y^2-3)=9[/tex]

Now, we have that:

[tex]h=4\\k=3\\r=\sqrt{9}=3[/tex]

So,

Center: (4,3)

Radius: 3 units.

Have a nice day!

Note: I have attached a picture for better understanding.

By completing the square on the given equation, the center of the circle is found to be (4, 3) and the radius is 3.

This process will transform the equation into a standard form of a circle equation, which is (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius of the circle.

To start, we can rewrite the original equation by adding and subtracting the necessary constants inside the square terms:

x^2 - 8x can become (x - 4)^2 by adding and then subtracting 16 inside the equation.y^2 - 6y can become (y - 3)^2 by adding and then subtracting 9 inside the equation.

Therefore, after completing the square, we get (x - 4)^2 + (y - 3)^2 = 1. Hence, the center of the circle is (4, 3) and the radius is 3.

Solve one of the following two non-homogeneous differential equations using whatever technique your prefer. Put an "X" through the equation you would not like me to grade. If you do not technique you prefer. Put an "X" through the equation you would not like me to grade. If you do not put an "X" through one of the equations, I will grade whichever problem I prefer to grade. a) y" - 4y + 4y = 6xe^2x b) y" + 9y = 5 cos x - 7 sin x

Answers

Answer:

a.[tex]y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}[/tex]

b[tex]y(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x[/tex]

Step-by-step explanation:

1.[tex]y''-4y'+4y=6x e^{2x}[/tex]

Auxillary equation

[tex]D^2-4D+ 4=0[/tex]

[tex](D-2)(D-2)=0[/tex]

D=2,2

Then complementary solution =[tex] C_1e^{2x}+C_2xe^{2x}[/tex]

Particular solution [tex]=\frac{6 xe^{2x}}{(D-2)^2}[/tex]

D is replace by D+2 then we get

P.I=[tex]\frac{6xe^{2x}}{0}[/tex]

P.I=[tex]\frac{e^{ax}}{D+a} \cdot .V[/tex]

where V is a function of x

P.I=[tex]\frac}x^3e^{2x}[/tex]

By integrating two times

Hence, the general solution

[tex]y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}[/tex]

b.y''+9y=5 cos x-7 sin x

Auxillary equation

[tex]D^2+9=0[/tex]

D=[tex]\pm 3i[/tex]

[tex]C.F=c_1 cos 3x+ c_2sin 3x[/tex]

P.I=[tex]\frac{5 cos x-7 sin x}{D^2+9}[/tex]

P.I=[tex]\frac{sin ax}{D^2+bD +C}[/tex]

Then  D square is replace by -a square

[tex] D^2 [/tex] is replace by - then we get

P.I=-5 cos x+7 sin x

The general solution

[tex]y(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x[/tex]

Use the continuous compound interest formula to find the indicated value. A $94,000; P $78,870; r= 7.8%; t =? t= years (Do not round until the final answer. Then round to two decimal places as needed.) TrueCar Enter your answer in the answer box. Prerequisite Skills Test for Finite Mathema eer of the heart bypass. Learn more Customize Getting Ready for Finite Mathematics Test AC 29057 12

Answers

Answer:

time period (t)  is 2.25 years

Step-by-step explanation:

Given data in question

amount (a) = $94000

principal (p) = $78870

rate (r) = 7.8 % = 0.078

to find out

time period (t)  

solution

we know that continuous compound interest formula i.e.

amount = principal [tex]e^{rt}[/tex]   ...............1

we will put all value a, p and r  in equation 1

amount = principal [tex]e^{rt}[/tex]

94000 = 78870 [tex]e^{0.078t}[/tex]

[tex]e^{0.078t}[/tex] = 94000 / 78870

now we take ln both side

ln  [tex]e^{0.078t}[/tex]  ln (94000 / 78870)

0.078 t = ln 1.19183466

0.078 t = 0.175494

t = 0.175494 /0.078  

t = 2.249923  

so time period (t)  is 2.25 years

Final answer:

In this complex interest problem, by organizing and substitifying the values into the continuous compound interest formula, we obtain t = ln(1.1911) / 0.078, which approximately equals 2.81 years when rounded to two decimal places.

Explanation:

The continuous compound interest formula is A = Pe^(rt), where P is the principal amount, r is the interest rate, t is the time in years, and A is the amount of money accumulated after n years, including interest.

In this case, we have A = $94,000, P = $78,870, r = 7.8% = 0.078, and we need to solve for t. Therefore, let's substitute the given values into the formula to solve for t:

$94,000 = $78,870 * e^(0.078t),

Solving this equation for 't' involves isolating 't' on one side. First, divide both sides by $78,870:

e^(0.078t) = $94,000 / $78,870 = 1.1911.

Take the natural logarithm (ln) of both sides:

0.078t = ln(1.1911),

Finally, divide both sides by 0.078 to solve for 't':

t = ln(1.1911) / 0.078.

With a calculator, this results in approximately t = 2.81 years when rounded to two decimal places.

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Find and identify the traces of the quadric surface x2 + y2 − z2 = 36 given the plane. x = k Find the trace. Incorrect: Your answer is incorrect. Identify the trace. circle ellipse hyperbola parabola y = k

Answers

Answer:

Hyperbola.

Step-by-step explanation:

We start from the function:

[tex]x^{2} +y^{2} -z^{2} =36[/tex]

We may get the traces if we cut the surface in planes x=k. This is equivalent to replace x for k:

[tex]k^{2}+y^{2} -z^{2}=36\\y^{2} -z^{2}=36-k^{2}[/tex]

The last equation is the equation of an hyperbola, which varies its characteristics depending on K (the plane cut).

Final answer:

When x=k or y=k is substituted into the equation of the quadric surface x² + y² - z² = 36, the resulting traces are hyperbolas. These traces represent intersections of planes parallel to coordinate planes with the quadric surface.

Explanation:

The trace of a quadric surface can be found by substituting a constant into the equation for one of the variables. The given quadric surface equation is x² + y² - z² = 36. If we substitute x = k into the equation, we get k² + y² - z² = 36. This is an equation of a hyperbola.

Similarly, for the case when y = k, we substitute this into our original equation to get x² + k² - z² = 36. This also represents a hyperbola.

The traces given by these equations represent the intersection of planes parallel to the coordinate planes and the quadric surface. In these particular cases, the traces are hyperbolas.

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A rectangle has a length 10 m less than twice its width. When 2 m are added to the​ width, the resulting figure is a square with an area of 196 m squared. Find the dimensions of the original rectangle.

Answers

Answer:

The length of the original rectangle is 14 meters and the width of the original rectangle is 12 meters

Step-by-step explanation:

Let

l ----> the length of the original rectangle

w ----> the width of the original rectangle

we know that

[tex]l=2w-10[/tex] ----> equation A

[tex]196=(w+2)^{2}[/tex] ----> area of a square

Solve for w

square root both sides

[tex](w+2)=(+/-)14[/tex]

[tex]w=14=(+/-)14-2[/tex]

[tex]w=14=14-2=12\ m[/tex]

[tex]w=14=-14-2=16\ m[/tex] -----> this solution not make sense

so

[tex]w=12\ m[/tex]

Find the value of L

[tex]l=2(12)-10=14\ m[/tex]

therefore

The length of the original rectangle is 14 meters and the width is 12 meters

Final answer:

The dimensions of the original rectangle are 12 meters (width) and 14 meters (length).

Explanation:

To find the dimensions of the original rectangle, let's first set up an equation.

Let the width of the rectangle be x meters.

The length of the rectangle is given as 10 m less than twice its width, so the length is (2x - 10) meters.

When 2 m are added to the width, the resulting figure is a square with an area of 196 m2.

The side length of a square with area A is √A, so the side length of the square is √196 = 14 meters.

Since adding 2 m to the width creates a square with side length 14 meters, we have:

x + 2 = 14

Subtracting 2 from both sides gives:

x = 12

Therefore, the dimensions of the original rectangle are 12 meters (width) and

(2*12 - 10)

= 14 meters (length).

use logarithmic differentiation to find dy/dx
y=(lnx)^x

Answers

Try this suggested solution.

An exam worth 269 points contains 36 questions. Some questions are worth 7 points, and the others are worth 8 points. How many 7 point and 8 point questions are on the test?

Answers

Answer:

There are 19 questions worth 7 points.

There are 17 questions worth 8 points.

Step-by-step explanation:

Assign variables:

Let x = number of questions worth 7 points.

Let y = number of questions worth 8 points.

First we deal with the number of questions.

There are 36 questions, so our first equation is:

x + y = 36

Now we deal with the points.

x questions worth 7 points each are worth 7x points.

y questions worth 8 points each are worth 8y points.

The total worth of all the questions is 7x + 8y.

The total worth of the exam is 269, so our second equation is

7x + 8y = 269

We have a system of 2 equations in 2 variables.

x + y = 36

7x + 8y = 269

Let's use the substitution method to solve the system of equations.

Solve the first equation for x.

x + y = 36

x = 36 - y

Substitute 36 - y in for x in the second equation.

7x + 8y = 269

7(36 - y) + 8y = 269

Distribute the 7.

252 - 7y + 8y = 269

Combine like terms.

252 + y = 269

Subtract 252 from both sides.

y = 17

There are 17 questions worth 8 points.

x + y = 36

x + 17 = 36

x = 19

There are 19 questions worth 7 points.

Check:

What does 19 questions at 7 points each and 17 questions at 8 points each add to?

19 * 7 + 17 * 8 = 133 + 136 = 269

The points add to 269, so our answer is correct.

PLEASE HELP

Write equations for the vertical and horizontal lines passing through the point (-6, -5)

Answers

Answer:

see below

Step-by-step explanation:

A horizontal line has the same y value and is a constant y value

y = -5

A vertical line has the same x value and is a constant x value

x = -6

A vertical line is a line where all of the [tex]x[/tex] values are the same. In this case, [tex]\boxed{x=-6}[/tex], so that is the equation of the line.

A horizontal line is a line where all of the [tex]y[/tex] values are the same.  Here, [tex]\boxed{y=-5}[/tex], so that is the second line.

help please quickly!!

Answers

Answer:

  m∠XQZ = 72°

Step-by-step explanation:

We presume the "if ..." condition is intended to mean that ray QY lies between rays QX and QZ. Then by angle addition, you get

  ∠XQY + ∠YQZ = ∠XQZ

  (4a +8) + (28) = (8a)

  36 = 4a . . . . . . . . . . . . . subtract 4a

  72 = 8a = ∠XQZ . . . . multiply by 2

Given the differential Equation y'+2y=2e^x ;solve this equation using the integration factor; solve for y to get the general solution.

Answers

[tex]y'+2y=2e^x\Longrightarrow y'=2e^x-2y[/tex]

If [tex]f'(x)=g(x)[/tex] then [tex]y=\int{g(x)dx}[/tex]

So we extract,

[tex]y=\int{2e^x-2x}dx[/tex]

Which becomes,

[tex]y=2e^x-x^2+C[/tex]

Hope this helps.

r3t40

4. Without performing the divisions, determine whether the integers 176521221 and 149235678 are divisible by 9 or 11. - Obtain the following aralization . The int e nted

Answers

Final answer:

By using the divisibility rules for 9 and 11, we can conclude that the integer 176521221 is divisible by 9 but not by 11, and the integer 149235678 is divisible by 9 but not by 11.

Explanation:

To determine whether the integers 176521221 and 149235678 are divisible by 9 or 11 without performing the division, we can use divisibility rules:

Divisibility by 9: Add up all the digits in the number. If the sum is divisible by 9, then the original number is also divisible by 9.

Divisibility by 11: Take the alternating sum of the digits. If the result is divisible by 11 (including 0), the original number is divisible by 11.

Divisibility of 176521221 by 9

1+7+6+5+2+1+2+2+1 = 27; Since 27 is divisible by 9, 176521221 is also divisible by 9.

Divisibility of 176521221 by 11

(1-7+6-5+2-1+2-2+1) = -3; Since -3 is not divisible by 11, 176521221 is not divisible by 11.

Divisibility of 149235678 by 9

1+4+9+2+3+5+6+7+8 = 45; Since 45 is divisible by 9, 149235678 is also divisible by 9.

Divisibility of 149235678 by 11

(1-4+9-2+3-5+6-7+8) = 9; Since 9 is not divisible by 11, 149235678 is not divisible by 11.

Solve the initial value problem (explicit solution). y y' - cot t = 0 y(pi/2) = -1

Answers

This ODE is separable:

[tex]yy'-\cot t=0\implies y\,\mathrm dy=\cot t\,\mathrm dt[/tex]

Integrate both sides to get

[tex]\dfrac12y^2=\ln|\sin t|+C[/tex]

Given that [tex]y\left(\frac\pi2\right)=-1[/tex], we get

[tex]\dfrac12(-1)^2=\ln|\sin\dfrac\pi2\right|+C\implies C=\dfrac12[/tex]

Then

[tex]\dfrac12y^2=\ln|\sin t|+\dfrac12[/tex]

[tex]y^2=2\ln|\sin t|+1[/tex]

[tex]y^2=\ln\sin^2t+1[/tex]

[tex]\implies\boxed{y(t)=\pm\sqrt{\ln\sin^2t+1}[/tex]

A national random sample of 654 women aged 20 – 29 years was taken, and each woman's body mass index (BMI) was measured. The sample data had mean BMI ????¯=26.8 and standard deviation ????=7.42 . What is the 95% ???? confidence interval (????,????) for the mean BMI of all young women?

Answers

Answer:

The required interval is (26.23 , 27.37)

Step-by-step explanation:

The mean is = 26.8

The standard deviation is = 7.42

n = 654

At 95% confidence interval, the z score is 1.96

To find the desired interval we will calculate as:

[tex]26.8+1.96(\frac{7.42}{\sqrt{654} } )[/tex]

And [tex]26.8-1.96(\frac{7.42}{\sqrt{654} } )[/tex]

[tex]26.8+0.57[/tex] and [tex]26.8-0.57[/tex]

= 27.37 and 26.23

So, the required interval is (26.23 , 27.37)

Final answer:

The 95% confidence interval for the mean BMI of all young women, given a sample of 654 women with a mean BMI of 26.8 and a standard deviation of 7.42 is approximately (26.23, 27.37). This is calculated by finding the standard error and then using that to find the interval around the sample mean which covers 95% of the probable values for the population mean.

Explanation:

The question is asking you to calculate the 95% confidence interval for the mean BMI of all young women, given a sample size of 654 women with a mean BMI of 26.8 and a standard deviation of 7.42.

In order to do this, we first need to calculate the standard error, which is the standard deviation divided by the square root of the number of observations. This gives us 7.42 divided by the square root of 654, or about 0.29032.

The 95% confidence interval is calculated by taking the mean and adding and subtracting the standard error multiplied by the relevant z-score for a 95% confidence interval, which is 1.96 (from the standard normal distribution table). So we take 26.8 plus and minus 1.96 times 0.29032, giving us a 95% confidence interval of approximately (26.23, 27.37).

So, we can say with 95% confidence that the mean BMI for all young women is between 26.23 and 27.37.

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Write an equation of the circle with center (9, -3) and radius 8.

Answers

Answer:

(x-9)^2 + (y+3)^2 = 8^2

or

(x-9)^2 + (y+3)^2 = 64

Step-by-step explanation:

An equation for a circle can be written as

(x-h)^2 + (y-k)^2 = r^2  where (h,k) is the center and r is the radius

(x-9)^2 + (y- -3)^2 = 8^2

(x-9)^2 + (y+3)^2 = 8^2

or

(x-9)^2 + (y+3)^2 = 64

Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.

Answers

[tex]\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k[/tex]

Divergence is easier to compute:

[tex]\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}[/tex]

[tex]\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}[/tex]

Curl is a bit more tedious. Denote by [tex]D_t[/tex] the differential operator, namely the derivative with respect to the variable [tex]t[/tex]. Then

[tex]\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}[/tex]

[tex]\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k[/tex]

[tex]\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k[/tex]

Final answer:

To find the curl and divergence of a given vector field, you first identify the vector's components. The curl is calculated using a determinant and the divergence is obtained by computing a dot product of the gradient operator with the vector field.

Explanation:

In order to find the curl and the divergence of the vector field F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k, we first need to identify its components. The components are as follows: e^(xy) sin z, and y tan^−1(x/z).  

The Curl of a vector field F in three dimensions is typically denoted as ∇ × F or curl F, where '∇' is the del operator. In Cartesian coordinates, this can be calculated using a determinant that involves the unit vectors î, ĵ, and k, the gradient operator, and the components of F.  

The Divergence of a vector field F in three dimensions, typically denoted as ∇ . F or div F, is obtained by computing a dot product of the gradient operator with the vector field. This can also be calculated using Cartesian coordinates.

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Jerry King is a server in a restaurant that pays a salary of $43 per day. He also averages tips of 18% of his total gross food orders. Last week he worked 4 days and had total food orders of $2,312.5. What was his total gross pay for the week? Round intermediate calculations and final answer to the nearest cent 416.25

Answers

Answer:

His total gross pay for the week is $588.25.

Step-by-step explanation:

Consider the provided information.

Jarry has a salary of $43 per day and he worked for 4 days.

Thus, the salary of 4 days is:

4 × $43= $172

The average tips is 18% of his total gross food orders.

Last week he had total food orders of $2,312.5. Therefore, the total tips he received is:

[tex]2312.5 \times(\frac{18}{100})[/tex]

[tex]2312.5 \times(0.18)[/tex]

[tex]416.25[/tex]

Total tips he received is $416.25.

His total gross pay for the week = The salary of 4 days + Total tips he received.

His total gross pay for the week = $172 + $416.25

His total gross pay for the week = $588.25

Hence, his total gross pay for the week is $588.25.

Final answer:

Jerry King's total gross pay for the week, combining his salary and the tips he made on his food orders, is $588.25, after calculating an 18% tip on his total orders and adding his daily salary for the 4 days he worked.

Explanation:

The question asks us to calculate the total gross pay for Jerry King, a server who earns both a salary and tips based on his food orders. First, we need to calculate Jerry's earnings from tips. He averages an 18% tip on his total gross food orders. Since his total food orders for the week were $2,312.5, we calculate the tips as follows:

Tips = (Total Food Orders) × (Tip Percentage)
= $2,312.5 × 18%
= $2,312.5 × 0.18
= $416.25 (rounded to the nearest cent)

Next, we calculate Jerry's salary for the week. Jerry works 4 days per week at a salary of $43 per day:

Salary = (Daily Salary) × (Number of Days Worked)
= $43 × 4
= $172

Finally, to find Jerry's total gross pay for the week, we add the salary and the tips:

Total Gross Pay = Salary + Tips
= $172 + $416.25
= $588.25 (rounded to the nearest cent)

Therefore, Jerry King's total gross pay for the week is $588.25.

A regression analysis can be used to determine a. if a linear relationship exists between two categorical variables. b. a cause-and-effect relationship between two variables. c. if the difference in the population means may be zero. d. if a linear relationship exists between two quantitative variables.

Answers

Answer: Option (d) is correct.

Step-by-step explanation:

Regression analysis can be used to determine if there is any linear relationship exists between the two quantitative variables.

There are one dependent variable and one or more than one independent variable in a single regression equation.

After running a simple regression, we get to know the relationship between the dependent variable and explanatory variable.

Various statistical software are used for running regression like STATA, E- Views, SPSS, etc.  

Final answer:

Regression analysis is used primarily to determine if a linear relationship exists between two quantitative variables. While it can identify relationships between variables, it does not imply causation. It does not establish a relationship between two categorical variables or if the difference in the population means may be zero.

Explanation:

Regression analysis is a statistical methodology often used in mathematics and related fields. Primarily, it is used to determine if a linear relationship exists between two quantitative variables.

For example, you could use regression analysis to see if there is a linear relationship between the age of a car (quantitative variable) and the distance it can travel on a tank of gas (another quantitative variable).

It's important to note however that while regression analysis can identify a correlation or relationship between variables, it does not necessarily imply causation, or a cause-and-effect relationship. There could be other related variables causing the effect.

For your options, regression analysis can't be used to determine if a linear relationship exists between two categorical variables or if the difference in the population means may be zero.

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USE INDUCTIVE REASONING TO PREDICT THE NEXT LINE IN THE PATTERN. 11 X 14 = 154 11 X 15 = 165 11 X 16= 176 THE NEXT LINE IS__X__=

Answers

Answer:

11 * 17 = 187.

Step-by-step explanation:

11 * 14 = 154

11 * 15 = 165

11 * 16 =  176

So we have the series 154, 165, 176  which has a common difference of 11.

so the next line is 11*17 = 176 + 11 = 187.

A study to determine the sensitivity and specificity of a new test for macular degeneration is conducted on 2430 people. Macular degeneration occurs at a rate of 16.72%. Your sample has the same prevalence of macular degeneration. You find that 377 people with macular degeneration tested positive with the new test. You also have a total of 561 positive test results in your study. CALCULATE THE SPECIFICITY of this test.

Question 2 options:

A)

83.29%

B)

98.45%

C)

92.86%

D)

67.20%

E)

90.91%

Answers

B and A are the answers I think

Michelle wants to order cookies. It is $6 for 4 pcs, how much would it cost for 20 pcs?

Answers

6 divided by 4 is 1.5.

1.5 times 20 is 30

it would cost michelle $30 to buy 20 pieces of cookies

Answer:

$30

Step-by-step explanation:

4pcs = $6

20pcs = x

Cross multiplying, we have

x = (20pcs * $6)/4pcs

= $120/4 = $30

Find the inverse of the matrices if they Exist. Use the algorithm introduced in the section. [1 0 -2 -3 1 4 2 -3 4]

Answers

Answer:

\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]

Step-by-step explanation:

Given is a matrix 3x3 as

[tex]\left[\begin{array}{ccc}1&0&2\\-3&1&4\\2&-3&4\end{array}\right][/tex]

|A| =2 hence inverse exists.

Cofactors are 16   20   7

                        6     8    3

                         2     2    1

Hence inverse =

[tex]\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right][/tex]

A retiree receives $5120 a year interest from $40,000 placed in two bonds, one paying 14% and the other 12%. How much is invested in each bond? 3)

Answers

Final answer:

To find out how much is invested in each bond, set up a system of equations and solve for the values of x and y.

Explanation:

To find out how much is invested in each bond, we can set up a system of equations.

Let x be the amount invested in the bond paying 14% interest, and y be the amount invested in the bond paying 12% interest.

We know that the retiree receives $5120 in interest each year. So, we have the equation:

x(0.14) + y(0.12) = 5120

Since the total amount invested is $40,000, we can also write the equation:

x + y = 40000

We can now solve this system of equations using any method, such as substitution or elimination, to find the values of x and y.

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