At standard pressure the boiling point of an unsaturated nano3(aq) solution increases when

Answers

Answer 1
Missing question:
(1) the solution is diluted with water.
(2) some of the NaNO3(aq) solution is removed.
(3) the solution is stirred.
(4) more NaNO3(s) is dissolved in the solution.
Answer is: (4) more NaNO3(s) is dissolved in the solution.
Unsaturated solution means that more of a substance can be dissolve (in this case sodium nitrate). If more sodium nitrate is dissolved, molality of solution is increased, eo ipso boiling point of solution.
Answer 2

Answer:

4

Explanation:


Related Questions

magnesium reacts with aluminum chloride. if you have 40g of each, how many grams of Al can you make? what is the LR? how much excess is left over after the reaction takes place

Answers

Q1)
Magnesium reacts with AlCl₃ and displaces Al.
3Mg + 2AlCl₃ ---> 3MgCl₂ + 2Al
stoichiometry of Mg to AlCl₃ is 3:2
Mass of Al₂Cl₃ present - 40 g
Therefore number of Al moles - 40 g/ 133.3 g/mol = 0.3 mol
Mass of Mg present - 40 g
Therefore number of moles - 40 g/ 24.3 g/mol = 1.6 mol
If Mg is the limiting reactant;
number of AlCl₃ moles that react with 3 mol of Mg  - 2 mol
Therefore number of AlCl₃ moles with 1.6 mol - 2/3 x 1.6 = 1.07 mol
However only 0.3 mol of Al present, therefore Mg is in excess and AlCl₃ is the limiting reactant .

Q2)
stoichiometry of AlCl₃ to Al is 2:2 
SInce AlCl₃ is the limiting reactant, the amount of Al produced depends on the amount of limiting reactant present.
Number of AlCl₃ moles reacted - 0.3 mol
Since molar ratio of AlCl₃ to Al is 1:1
the number of Al moles produced - 0.3 mol
The mass of Al produced - 0.3 mol x 27 g/mol = 8.1 g

Q3) AlCl₃ is the limiting reactant. limiting reactant is the reagent which is fully used up in the reaction. Reagent in excess is the reactant which is present in excess, amount present is more than what is required for the reaction.
Number of AlCl₃ moles reacted - 0.3 mol
Number of Mg moles reacted with 2 mol of AlCl₃ - 3 mol
Therefore with 0.3  mol of AlCl₃ - 3/2 x 0.3 mol = 0.45 mol
Number of Mg moles present initially - 1.6 mol 
moles reacted - 0.45 mol
therefore excess moles left after the reaction - 1.6 - 0.45 = 1.15 mol

Uranium is a metallic element that is used in nuclear reactors and nuclear weapons. the vast majority of uranium found on earth is in the form of uranium-238, an isotope with a mass number of 238, while the uranium that is used for nuclear reactors and weapons is uranium-235, an isotope with a mass number of 235. what is the atomic difference between uranium-235 and uranium-238? uranium-235 has three fewer protons than uranium-238. uranium-235 has three fewer neutrons than uranium-238. uranium-235 has three fewer electrons than uranium-238. uranium-235 has three fewer atoms than uranium-238.

Answers

Answer:

U-235 and U-238 are two radioactive isotopes of Uranium. The main difference between U-235 and U-238 is that the number of neutrons present in the U-235 nucleus is 143 whereas the number of protons present in the U-238 nucleus is 146.

Explanation:

If a solution containing 51.429 g of mercury(ii) perchlorate is allowed to react completely with a solution containing 16.642 g of sodium sulfate, how many grams of solid precipitate will be formed?

Answers

Hg(No3)2  +NaSO4   --->2NaNO3  +  HgSO4(s)
calculate  the moles  of   each  reactant
moles=mass/molar  mass

moles of  Hg(NO3)2=  51.429g/  324.6  g/mol(molar  mass  of  Hg(NO3)2)=0.158  moles

moles Na2SO4  16.642g/142g/mol=  0.117  moles  of  Na2SO4

Na2SO4  is  the  limiting  reagent in  the   equation   and  by  use  mole  ratio  Na2So4  to  HgSO4  is  1:1   therefore  the  moles  of  HgSO4  =0.117  moles

mass  of  HgSO4=moles  x  molar   mass  of  HgSo4=  0.117 g x  303.6g/mol=  35.5212  grams

PLEASE HELP!!



Given the following balanced reaction between hydrochloric acid and oxygen gas to produce water and chlorine gas, how many grams of chlorine gas, Cl2, are produced from 27.8 g of hydrochloric acid and excess oxygen? (To find the molar mass in the problem, use the periodic table and round the mass to the hundreds place for calculation.)

4HCI(aq) +O2 ->2CI2 (g)+ 2H2O (I),

Answers

number of moles of HCl = [tex] \frac{mass (g)}{molar mass} [/tex]
                = [tex] \frac{27.8 g}{36.45} [/tex] = 0.763 mole
From balanced equation:
4 moles of HCl give 2 moles Cl2
0.763 mole HCl give ?? mole Cl2
by cross multiplication :
= 0.38 mole Cl2
mass of Cl2 = moles x molar mass = 0.38 x 70.9 = 27 g 

Answer : The mass of chlorine gas produced are, 26.95 grams.

Explanation : Given,

Mass of HCl = 27.8 g

Molar mass of HCl = 36.46 g/mole

First we have to calculate the moles of hydrochloric acid.

[tex]\text{Moles of HCl}=\frac{\text{Mass of HCl}}{\text{Molar mass of HCl}}=\frac{27.8g}{36.46g/mole}=0.76mole[/tex]

Now we have to calculate the moles of chlorine gas.

The given balanced chemical reaction is,

[tex]4HCI(aq)+O_2\rightarrow 2CI_2(g)+2H_2O(I)[/tex]

From the given balanced chemical reaction, we conclude that

As, 4 moles of hydrochloric acid react to give 2 moles of chlorine gas

So, 0.76 moles of hydrochloric acid react to give [tex]\frac{2}{4}\times 0.76=0.38[/tex] moles of chlorine gas

Now we have to calculate the mass of chlorine gas.

[tex]\text{Mass of }Cl_2=\text{Moles of }Cl_2\times \text{Molar mass of }Cl_2[/tex]

Molar mass of [tex]Cl_2[/tex] = 70.91 g/mole

[tex]\text{Mass of }Cl_2=0.38mole\times 70.91g/mole=26.95g[/tex]

Therefore, the mass of chlorine gas produced are, 26.95 grams.

In part a, you found the amount of product (3.00 mol p2o5 ) formed from the given amount of phosphorus and excess oxygen. in part b, you found the amount of product (2.60 mol p2o5 ) formed from the given amount of oxygen and excess phosphorus.now, determine how many moles of p2o5 are produced from the given amounts of phosphorus and oxygen.express your answer to three significant figures and include the appropriate units.

Answers

Answer is: 2,6 moles of P₂O₅ are produced from the given amounts of phosphorus and oxygen.
Chemical reaction: P₄ + 5O₂ → 2P₂O₅.
m(P₄) = 186 g.
n(P₄) = m(P₄) ÷ M(P₄).
n(P₄) = 186 g ÷ 123,9 g/mol.
n(P₄) = 1,5 mol.
m(O₂) = 208 g.
n(O₂) = 208 g ÷ 32 g/mol.
n(O₂) = 6,5 mol; limiting reactant.
From chemical reaction: n(O₂) : n(P₂O₅) = 5 : 2.
n(P₂O₅) = 2 · 6,5 mol ÷ 5.
n(P₂O₅) = 2,6 mol.

Answer:

The correct answer is 2.60 moles.

Explanation:

The balanced equation is:  

4P + 5O₂ ⇒ 2P₂O₅

The number of moles of O₂, n = mass/molar mass

208 g / 32 g/mol = 6.5 mol

From the balanced equation,  

5 moles of O₂ reacts with 2 moles of P₂O₅

So, 6.5 moles of O₂ reacts with M moles of P₂O₅

M = 6.5 × 2/5

= 2.6 moles

Therefore, the required moles of P₂O₅ are 2.60 moles.  

The number associated with a mole is called __________. a. Dalton’s number c. Newton’s number b. Avogadro’s number d. Pauli’s number

Answers

The number associated with a mole is called Avogadro's Number. 

Avogadro's number is a constant, it is the amount of atoms or molecules in a substance given by a mole. It is a rather large number, it is [tex]6.0221409x 10^{23} [/tex].

For additional information, Newton's  work is the laws of motion, Dalton's works deal with the Atom and Pauli's works involve the law of Nature and Pauli principle.

Which planet is not an outer planet? A. Mars B. Uranus C. Neptune D. Jupiter

Answers

The answer to your question is MARS

#1: Which of the following scientists came up with the first widely recognized atomic theory?

A. John Dalton

B. Antione Lavoisier

C. Robert Millikan

D. J.J. Thomson

***My answer: A. John Dalton
is that right??,

Answers

Yes that answer is correct. John dalton was an english scientist who lived during the 18th and 19th centuries and he is most famous for proposing the modern first widely recognized atomic theory. But, it is thought that his theory is influenced by the ideas of another scientist called Bryan Higgins .

Snow melting in sunshine is an example of which type of change

Answers

it is physical change

A chemist needs to prepare a solution of 1.7 m nacl. if 400. ml of the solution are required how many grams of nacl are needed? molar mass nacl = 58.5 g/mol

Answers

C=1.7M; M=58.5gmol-¹; V=400ml=400g; m=?
C=n/V
but n=m/V
=>C=m/MV
=>m=CMV
=1.7 x 58.5 x 400
=39780g

Magnesium sulfate heptahydrate is heated until all the water is driven off. The sample loses 11.80 grams upon heating. What was the mass of the original sample?

Answers

Hello!

The initial mass of Magnesium Sulfate Heptahydrate (MgSO₄·7H₂O) is 23,08 g

The chemical reaction for the dehydrating of Magnesium Sulfate Heptahydrate (MgSO₄·7H₂O) is the following:

MgSO₄·7H₂O(s) + Δ → MgSO₄(s) + 7H₂O(g)

We know that the sample loses 11,80 g upon heating. That mass is the mass of Water that is released as vapor. Knowing that piece of information, we can apply the following conversion factor to go from the mass of water to the moles of water and back to the mass of the original compound (mi).

[tex]mi=11,80gH_2O* \frac{1 mol H_2O}{18gH_2O}* \frac{1molMgSO_4.7H_2O}{7molH_2O}* \frac{246,47 g MgSO_4.7H_2O}{1 mol MgSO_4.7H_2O} \\ \\ mi=23,08gMgSO_4.7H_2O [/tex]

Have a nice day!

Connect It Imagine that you can see the particles of ice, liquid water, and water vapor. Describe how these three states of water differ.

Answers

Particle of ice is much closer together. Particle of liquid water moves much more freely than ice but is still slower than water vapor. Particles of liquid water are also spaced out a bit farther than ice. Water vapor moves around fast and there are many of them. They are the most spread out.

Why is it hard for scientists to change lead into gold?



Scientists would have to change the number of protons in lead atoms.


Scientists would have to change the number of electrons in lead atoms.


Scientists would have to change the number of neutrons in lead atoms.


Scientists would have to change the number of protons and neutrons in lead atoms.

Answers

Scientists would have to change the number of protons in lead atoms
Final answer:

Changing lead into gold requires changing the number of protons in the lead atoms, a process known as nuclear transmutation. This process is highly complex, energy intensive and has many potential risks, making it unfeasible as a method of gold production.

Explanation:

The process of changing one element into another, such as changing lead into gold, would require the manipulation of its atomic structure. The atomic structure of an atom is primarily dictated by the number of protons it has, which determines its atomic number and essentially defines the kind of element it is. In the case of lead and gold, lead has 82 protons and gold has 79 protons.

To turn lead into gold, scientists would have to remove 3 protons from each atom, which is an incredibly difficult task. This process, known as nuclear transmutation, would require a significant amount of energy and highly advanced technology. Even then, the process is far from efficient and produces a number of problems including the release of harmful radiation and the production of unstable, radioactive isotopes.

Furthermore, changing the number of neutrons and electrons in a lead atom alone would not turn it into gold; the number of protons must be changed. So the correct statement from the options provided is that scientists would have to change the number of protons in lead atoms to transform it into gold. However, due to the immense difficulty and possible risks involved, this is not a viable option for gold production.

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#1: Which of the following is a brittle solid?

A. chlorine

B. bromine

C. iodine

D. sulfur

**my answer; C. iodine

is that right?,

Answers

Iodine

Brittle materials absorb relatively little energy prior to fracture

Iodine Is a poor conductor of electricity. It is composed of covalent bonds and is a brittle solid at room temperature.

What happens to the temperature of a thermometer near an endothermic reaction?

Answers

The temperature shown on the thermometer decreases,as the temperature of the surrounding area decreases. This is due to the energy which is being taken in from the surroundings for the reaction, so as to break the bonds.

what is the structure of XeO2F2???i know its hybridization as sp3d but cannot quite understand its diagram in free space,help anyone???

Answers

The shape of XeO₂F₂ is Trigonal bi-pyramidal see-saw tetrahedron (see attached pictures)
- As you said the hybridization of Xe here is sp³d so its geometry has to be Trigonal bi-pyramidal in which F atom located on axial positions but for the final shape we exclude lone pair on Xe to give see-saw shape (see second picture) 
- Remember that we have 5 pairs (4 bond pairs + 1 lone pair) and we have to place lone pair at equatorial position.

If a base is added to water, what will occur?

Answers

This will increase the concentration of [OH-] ions.
For example:
- Ammonia NH3 (base):
NH3(aq) + H2O (l) → NH4+  + OH-

and 
-NaOH:
NaOH(s) + H2O(l) → Na+ + OH-
and KOH:
KOH(s) → K+(aq) + OH-(aq)

So we can see that the base increase the [OH-] & increase the characteristic anion [OH-] of the solvent.
Final answer:

Adding a base to water triggers a base ionization reaction, resulting in the formation of hydroxide ions and a conjugate acid, which increases the solution's pH. Strong bases fully dissociate, while weak bases only partially ionize.

Explanation:

When a base is added to water, a base ionization reaction occurs. This reaction involves the transfer of protons from water molecules to the base molecules, producing hydroxide ions (OH-) and a conjugate acid of the base. For instance, if we take pyridine, C5NH5, as a base, adding it to water will result in the formation of hydroxide ions and pyridinium ions. This process increases the pH of the solution as it raises the concentration of hydroxide ions. Strong bases, like soluble ionic hydroxides (e.g., NaOH), dissociate completely in water, leading to a significant increase in OH- concentration, while weak bases yield a smaller proportion of hydroxide ions.

A general reaction for base ionization can be represented as B(aq) + H₂O(l) ⇒ HB*(aq) + OH⁻(aq), where B is the base and HB* is the conjugate acid formed. This reaction is essential for understanding acid-base chemistry, where bases are seen as proton acceptors and their strength can be gauged by how completely they ionize in water.

For the reaction represented by the equation pb(no3)2 + 2ki → pbi2 + 2kno3, how many moles of lead(ii) iodide are produced from 300. g of potassium iodide and an excess of pb(no3)2?
a. 11.0 mol selected:
b. 1.81 mol
c. 3.61 mol
d. 0.904 mol

Answers

Number of moles equals of potassium iodide;

The molar mass of potassium iodide is 166 g/mole

Moles = 300/166

            = 1.8072moles

According to the equation;

2 moles of KI produces 1 mole of PbI2 9lead (ii) iodide

Therefore; the number of moles of lead (ii) iodide produced will be;

                = 1.8072/2

                = 0.9036moles

Thus the number of moles of lead (ii) iodide is 0.904 mole

Answer : The correct option is, (d) 0.904 mole

Explanation : Given,

Mass of potassium iodide = 300 g

Atomic mass of potassium iodide = 166 g /mole

First we have to calculate the moles of potassium iodide.

[tex]\text{Moles of KI}=\frac{\text{Mass of KI}}{\text{Molar mass of KI}}=\frac{300g}{166g/mole}=1.807mole[/tex]

Now we have to calculate the moles of lead(ii) iodide.

The given balanced chemical reaction is,

[tex]Pb(NO_3)_2+2KI\rightarrow PbI_2+2KNO_3[/tex]

From the given balanced chemical reaction, we conclude that

As, 2 moles of potassium iodide react to give 1 mole of  lead(ii) iodide

So, 1.807 moles of potassium iodide react to give [tex]\frac{1.807}{2}=0.904[/tex] mole of  lead(ii) iodide

Therefore, the number of moles of lead(ii) iodide produced are, 0.904 mole

At room temperature, the surface tension of water is 72.0 mJ·m–2. What is the energy required to change a spherical drop of water with a diameter of 1.20 mm to five smaller spherical drops of equal size? The surface area of a sphere of radius r is 4π r2 and the volume is 4π r3/3.

Answers

It is given that the surface area of sphere is 4 π r² and its volume is (4/3 π r³)
With a diameter of 1.2 mm you have a radius of 0.6 mm so the surface area about 4.5 mm² and the volume is about 0.9 mm³ 
The total surface energy of the original droplet is (4.5 x 10⁻⁶ m x 72) = 3.24 x 10⁻⁴mJ
The five smaller droplets need to have the same volume as the original so:
5 V = 0.9 mm³ so the volume of smaller sphere will equal 0.18 mm³
Since this smaller volume still have volume (4/3 π r³) so r = 0.35 mm
Each of the smaller droplets has a surface are = 1.54 mm² 
The surface energy of the 5 smaller droplet is then (5 x 1.54 x 10⁻⁶ m x 72) = 5.54 x 10⁻⁴ mJ
From this radius the surface energy of all smaller droplets is 5.54 x 10⁻⁴ and the difference in energy is (5.54 x 10⁻⁴) - (3.24 x 10⁻⁴) = 2.3 x 10⁻⁴ mJ
Therefore we need about 2.3 x 10⁻⁴ mJ of energy to change a spherical droplet of water of diameter 1.2 mm into 5 identical smaller droplets

When it says Lithium crystallizes in a body centered cubic unit cell. what is the mass of one unit cell....

I did my math, but it says I have to multiply by 2. I am confused in why I have to do that?

I also have trouble understanding what is a body-centered cubic cell.

Answers

The solution to this problem is:

2 x 6.94 g divided by (6.02*10^23)
= 2.30*10^-23

Therefore,
(6.94^2)/(6.02 x10^23)
=2.30 x 10^-23
The answer is 2.30 x 10^-23.

A player uses a hockey stick to push a puck at a constant velocity across the ice. The weight of the puck is 1.70 N. The coefficient of friction is 0.0600. With what force must the player push the puck so that his force just equals the frictional force?

Answers

Force = mass × acceleration

static force = coefficient of friction × normal force 
1.70 = 0.0600 × normal force...
normal force = 1.70 ÷ 0.0600.. to obtain.... 

Answer: The minimum force by which player should hit the puck to move it is 0.102 N.

Explanation:

Weight of the puck = 1.70 N

This weight of the puck is the force acting normal to the surface that is:

N = 1.70 N

The coefficient of friction =[tex]\mu _f=0.0600[/tex]

Frictional force = [tex]F_f=\mu _f\times N=0.0600\times 1.70 N=0.102 N[/tex]

The minimum force by which player should hit the puck to move it is 0.102 N.

Which of the following accurately describes the behavior of water when subjected to temperature change?

A. A mass of water will expand if heated from 0°C to 2°C.
B. The volume of water will increase if cooled from 3°C to 2°C.
C. The volume of water will decrease if heated from 6°C to 7°C.
D. A mass of water will contract if cooled from 1°C to 0°C.

Answers

I believe this is the best one:
B. The volume of water will increase if cooled from 3°C to 2°C.

I don't think D) because water expands from 4°C to 0°C

"When liquid water is cooled, it contracts like one would expect until a temp of approximately 4 degrees Celsius is reached. After that, it expands slightly until it reaches the freezing point."

The answer option which accurately describes the behavior of water when subjected to temperature change is: B. The volume of water will increase if cooled from 3°C to 2°C.

Water refers to a liquid molecule that is typically made up of two (2) main chemical elements in the following proportion;

Two atoms of hydrogen.One atom of oxygen.

Generally, the volume of water is directly proportional to its temperature.

Hence, an increase in the temperature of water causes the volume of water to increase because its molecules gain energy and move more rapidly, which in turn makes the water molecules to be further apart.

When water is cooled, it contracts (decrease in volume) until a temperature of approximately four degree Celsius (4°C) is reached and then it begins to expand (increase in volume) at lower temperatures (3°C to 2°C), until it reaches its freezing point, which is typically at zero degree Celsius (0°C).

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2H2S + 3O2 mc008-1.jpg 2SO2 + 2H2O Which option gives the correct mole ratios?

Answers

Consider the balanced equation below.

2H2S + 3O2 ---> 2SO2 + 2H2O

Which option gives the correct mole ratios?
H2S:SO2 = 2:2 and O2:H2O = 3:2
H2S:SO2 = 2:3 and O2:H2O = 3:2
H2S:SO2 = 4:4 and O2:H2O = 5:4
H2S:SO2 = 4:6 and O2:H2O = 4:4



is the aswer   H2S:SO2=2:2 and O2:H2O=3:2

Which of the following is an example of an Arrhenius base?

A. CaCO3
B. KOH
C. NH3
D. HCl

Answers

An Arrhenius base adds ions into water when added to the water hence it increases the concentration of ions in aqueous solution. Therefore, KOH is an example because the ions added to the water are called OH-ions.

Answer: B. [tex]KOH[/tex]

Explanation:

According to the Arrhenius concept, an acid is a substance that ionizes in the water to give hydronium ion or hydrogen ion [tex](H^+)[/tex] and a bases is a substance that ionizes in the water to give hydroxide ion [tex](OH^-)[/tex].

According to the Bronsted Lowry conjugate acid-base theory, an acid is defined as a substance which donates protons and a base is defined as a substance which accepts protons.

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

[tex]KOH\rightarrow K^++OH^-[/tex]: is a Arrhenius base.

[tex]NH_3+H^+\rightarrow NH_4^+[/tex] : is a lewis base as it donates the lone pair of electrons.

[tex]HCl\rightarrow H^++Cl^-[/tex] is a Arrhenius acid and bronsted lowry acid.

Which is the correct symbol for the atom with 42 protons and 49 neutrons?

Answers

Explanation:

Number of protons present in an atom are actually the atomic number of atom. Each element will have different atomic number.

Hence, each element is different in nature. On the other hand, atomic mass is the sum of number of protons and number of neutrons present in an element.

For example, Molybdenum is the element with 42 protons and 49 neutrons. Molybdenum is represented by the symbol Mo.

Therefore, we can conclude that Mo is the correct symbol for the atom with 42 protons and 49 neutrons.

The correct symbol for the atom with 42 protons and 49 neutrons is ^91Mo.

Atomic notation explained.

The correct symbol for the atom with 42 protons and 49 neutrons is ^91Mo.

In atomic notation, the image for an component consists of the nuclear number (number of protons) as a subscript and the mass number (entirety of protons and neutrons) as a superscript.

For the given atom with 42 protons and 49 neutrons, the overall mass number is 42 + 49 = 91. Hence, the image for this particle is ^91Mo, speaking to the component Molybdenum (Moment) with a mass number of 91.

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Describe how to separate a mixture of pigments from an ink cartridge.

Answers

To separate it you would use a type of powder or corn starch

Which scientist arranged the elements in order of increasing atomic number, rather than increasing atomic mass? Antoine Lavoisier Dmitri Mendeleev Henry Moseley John Newlands

Answers

the answer is Henry Moseley

The answer is: Henry Moseley.

Henry Gwyn Jeffreys Moseley (1887–1915) proposed that the number of positive nuclear charges (protons) in atom is equal to its atomic number in the periodic table.

Mendeleev did not know about isotopes and he arranged the elements in order of increasing relative atomic mass.

For example, positions of iodine and tellurium were reversed in Mendeleev's table, because of different isotopes, but Moseley solved anomalies like this one.

Which metal atom below cannot form a cation of several different charges?

Answers

Missing question: Cr, Mn, Fe, Ba, Cu.
Answer is: Ba (barium).
Barium is metal from second group of periodic table of elements. Barium looses two electrons and has oxidation number +2.
Chromium has different oxidation numbers, usually +3 and +6, iron has oxidation numbers +2 and +3, copper +1 and +2 in their compounds.

Only 5 questions! All you have to do is check my answers...1. A flask contains four gases: CH4, O2, C2H5, and N2. When the stopper is removed, which gas will diffuse the fastest?

CH4 <---
O2
C2H5
N2

2. Which gas effuses 2.39 times slower than nitrogen gas?

O2
Cl2
Br2 <---
I2

3. What is the molecular mass of a gas that effuses three times faster than radon?

16 g/mol
25 g/mol <---
50 g/mol
67 g/mol,

Answers


1. CH4
2. Br2
3. 25 g/mol

Graham's law indicates that the rate of diffusion is inversely proportional to the square root of its molecular weight. So the lighter the gas, the more rapid the diffusion. With that in mind, let's look at your questions:

1. A flask contains four gases: CH4, O2, C2H5, and N2. When the stopper is removed, which gas will diffuse the fastest?The answer here will be the lightest of the 4 gasses. So let's look at the molar mass of each gas:
CH4 = 16.04 g/mol
O2 = 32.00 g/mol
C2H5 = 29.06
N2 = 28.01
And CH4 is the lightest and therefore the fastest.

2. Which gas effuses 2.39 times slower than nitrogen gas? O2 Cl2 Br2 <--- I2
Let's start with the square root of 28.01 which is 5.292447449.
Now multiply by 2.39 and square the result to get the molar mass of the
desired gas which is (5.29*2.39)^2 = 12.64^2 = 159.77Now let's look at the molar masses.
O2 = 32
Cl2 = 70.91
Br2 = 159.81
I2 = 253.81
And the match goes to Br2

3. What is the molecular mass of a gas that effuses three times faster than radon? 16 g/mol 25 g/mol <--- 50 g/mol 67 g/mol,The molar mass of radon is 222 g/mol. So let's get the square root, divide by
3, then square the result. So(sqrt(222)/3)^2 = (14.89966443/3)^2 = 4.966554809^2 = 24.66666667 g/mol.And of the available choices, 25 g/mol is the best match.

PLEASE HELP!

1. Calculate the molality of a solution prepared by dissolving 175 g of KNO3 in 750 g of water. Show you work.

I know that molality=moles of solute/kilograms of solvent, but I do not understand how to get this. Thank you!!!

Answers

Molar mass KNO₃ = 101.1032 g/mol
Mass of solute = 175 g
Volume = 750 ML in liters : 750 / 1000 = 0.75 L
Number of moles:
n = mass of solute / molar mass
n = 175 / 101.1032
n = 1.7309 moles
Molarity :
M = moles of solute / volume in liters
M = 1.7309 / 0.75
= 2.307 M
hope this helps!

The molality of a solution prepared by dissolving 175 g of KNO₃ in 750 g of water is 2.3m.

What is molaity?

Molaity is used to define the concentration of any material present in any substance and it will be calculated as:

Molality = Moles of solute / kilograms of solvent

According to the question,

Mass of solute KNO₃ = 175g

Mass of solvent = 750g = 0.75kg

Moles of solute KNO₃ will be calculated as:

n = W/M, where

W = given mass

M = molar mass = 101.1 g/mol

n = 175 / 101.1 = 1.73 moles

On putting values, we get

m = 1.73 / 0.75 = 2.3m

Hence molality of given sample is 2.3m.

To know more about molality, visit the below link:

https://brainly.com/question/14973233

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