Answer:
60.75
Step-by-step explanation:
Since he earns a 4.5% commission
you need to find 4.5% of $1,350
1350 x 0.045 = 60.75
Valerie has 127.00 in her wallet and earns 15.50 per hour . Which equation show this situation
Answer:
Step-by-step explanation:
Point A is at (-5, –4) and point B is at (5,-3).
What is the midpoint of line segment AB?
The midpoint of the line segment AB with points A at (-5, -4) and B at (5, -3) can be found by averaging the x and y coordinates of the two points. The x-coordinate of the midpoint is 0 and the y-coordinate is -3.5, hence the midpoint is (0, -3.5).
Explanation:The subject of this question is Mathematics, specifically discussing the concept of finding the midpoint of a line segment in a 2D coordinate system. The midpoint of a line segment can be calculated using the coordinates of the two ends of the line segment. To find it, you add the coordinates (x, y) of the two points and divide each sum by 2. In this case, the coordinates of points A and B are (-5, -4) and (5, -3) respectively. Thus, the x-coordinate of the midpoint is (-5 + 5)/2 = 0 and the y-coordinate of the midpoint is (-3 - 4)/2 = -3.5. Therefore, the midpoint of line segment AB is at (0, -3.5).
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3t^6 x 8t^-6
^ this is an exponent signal^
x is multipulcation
Answer:
24
Step-by-step explanation:
3t⁶ × 8(t^-6)
3 × 8 × t⁶ × t^-6
24 × t^(6-6)
24 × t⁰
24 × 1
24
According to the Bureau of Labor Statistics, students who have an after-school job spend an average of 42 fewer minutes per day on schoolwork than students who don't work. If the school year is 180 days, how many more hours per year would the average non-working student spend on schoolwork than the average student with an after-school job?
Answer:
126 hrs
Step-by-step explanation:
-Given the school year has 180 days and the non-working student spends 42 minutes more than the working student.
-The total time during the school year is calculated as;
[tex]Total Time=Time/day \times No \ of \ Days\\\\=42\ minutes \times 180\\\\=7560\ minutes[/tex]
We convert our calculated time in hour(1hr=60 minutes):
[tex]=\frac{7560\ mins}{60\ mins}\\\\=126\ hrs[/tex]
Hence, the average non-working spends an average of 126 hrs that the working student.
Answer:
weekday,Weekday
Step-by-step explanation:
HAVE A GREAT DAY!!!!!! :)) wrong question lol
Sam's math teacher offered after school tutoring 16 out of the 30 days
in November to help students review for the mid-term exam. Which
decimal is equivalent to the fraction of days that tutoring was offered
in November?
Answer: 1.875 days
Step-by-step explanation:
Hi, to answer this question we simple have to divide the total day of the month (30 days) by the number of days that she offers tutoring (16).
Mathematically speaking:
30 /16 =1.875 days
1.875 days is equivalent to the fraction of days that tutoring was offered in November
Feel free to ask for more if needed or if you did not understand something.
Answer:0.533
Step-by-step explanation:
Sam's mathematics teacher offered after school tutoring 16 days out of the 30 days that were in November in order to help students review for the mid-term exam.
To convert this to a decimal, we divide the number of days tutorial was offered in November by the number of days in November. This will be:
= 16/30
= 0.533
The decimal that is equivalent to the fraction is 0.533.
The table shows transportation from five different bank accounts. Fill in the missing numbers
There is no answer, there is no table.
Which are characteristics of the graph of the function f(x) = (x + 1)2 + 2? Check all that apply
The domain is all real numbers,
The range is all real numbers greater than or equal to 1
The y-intercept is 3.
The graph of the function is 1 unit up and 2 units to the Daft from the graph of y = x2
The graph has two x-intercepts
Answer:
The domain is all real numbers
The y-intercept is 3.
Step-by-step explanation:
Let's analyze each statement separately. The function is
[tex]f(x)=(x+1)^2+2[/tex]
We have the following statements:
The domain is all real numbers, --> TRUE. The domain of a function is the set of values that the variable x can take. For this function, there are no restriction on the values that x can take, so the domain is all real numbers.
The range is all real numbers greater than or equal to 1 --> FALSE. The range of a function is the set of values that the variable y can take. For this function, we see that the factor [tex](x+1)^2[/tex] is always equal or greater than zero; this means that the minimum of the function is [tex]f(x)=2[/tex], so the range is all real numbers greater than or equal to 2.
The y-intercept is 3. --> TRUE. The y-intercept is the value of the function when x = 0. For this function, if we substitute x = 0, we find:
[tex]f(0)=(0+1)^2+2=1^2+2=3[/tex]
The graph of the function is 1 unit up and 2 units to the left from the graph of [tex]y=x^2[/tex] --> FALSE. The graph of a function is scaled n units up when [tex]g(x)=f(x)+n[/tex]; in this case, we see that the factor n in our fuction is n = 2, so the function is actually scaled 2 units up, not 1.
The graph has two x-intercepts --> FALSE. The x-intercept of a graph is the value of x when [tex]f(x)=0[/tex]. If we require [tex]f(x)=0[/tex] for our function, we get:
[tex]0=(x+1)^2+2\\\rightarrow (x+1)^2=-2[/tex]
However, this equation has no solutions: so, the graph has no x-intercepts.
The graph of the function [tex]f(x) = (x + 1)^2 + 2[/tex] has a domain of all real numbers, a range of all real numbers greater than or equal to 2, a y-intercept of 3, and is 1 unit left and 2 units upwards shifted from the base graph [tex]y = x^2[/tex]. It has one x-intercept, not two.
Explanation:The function in question is f(x) = (x + 1)2 + 2. To analyze its characteristics, we first need to look at its general shape, domain, and range. Since it is based on the parent function f(x) = x2, which is a parabola, the transformations will affect the position but not the overall shape or domain.
The domain is all real numbers because for any x-value, there is a corresponding y-value. This applies to all quadratic functions.The range is all real numbers greater than or equal to 2, not 1. The minimum point of the graph occurs when the squared term is zero, which in this case is at f(-1) = 2.The y-intercept is the value of the function when x=0. Substituting into the function gives f(0) = (0 + 1)2 + 2 = 3.The graph is a standard parabola that opens upward. It is shifted 1 unit to the left (not Daft) and 2 units upwards from the graph of y = x2.The graph has only one x-intercept (not two), which can be found by setting the function equal to zero and solving for x.
Judy currently has one credit card. She owes $500 and the credit card has a rate of 15%
per month. How much does Judy owe 8 months from now?
$ 1,100
Step-by-step explanation:
Well use the simple interest equation;
A = P(1 + rt)
Where:
A = Total Accrued Amount (principal + interest)
P = Principal Amount
I = Interest Amount
r = Rate of Interest per year in decimal; r = R/100
R = Rate of Interest per year as a percent; R = r * 100
t = Time Period involved in months or years
A = 500 (1 + 0.15*8)
A = 500 (2.2)
= 1100
The diameter of a circle is 13 m find it’s circumference in terms of pi
Answer:
C = (13)π meters
Step-by-step explanation:
Its circumference is C = πd, which here has the value C = (13)π meters.
Final answer:
The circumference of a circle with a diameter of 13 meters is 13
meters, using the formula C =
d where C is the circumference and d is the diameter.
Explanation:
The question involves finding the circumference of a circle when given its diameter, in terms of
(pi). The diameter of the circle is provided as 13 meters. To find the circumference, we use the formula C =
d, where C is the circumference, r is the radius, and d is the diameter of the circle. Since the diameter is twice the radius (d = 2r), the formula can also be written as C = 2
r. However, since we are given the diameter, we use the first formula.
For this particular problem, we have d = 13 meters. Thus, the circumference of the circle calculated in terms of pi is:
C = imes d
C = imes 13 m
The circumference of the circle in terms of pi is therefore 13
meters.
What is the area of this composite figure, in square centimeters? A triangle with base of 11 centimeters and height of 6 centimeters is on top of a rectangle with length 16 centimeters and width 11 centimeters. Whats the area? A.176 B.209 C.242 or D.264 ??? IS it B?
Answer:
209
Step-by-step explanation:
i hoped this helped saying no one else wanted to answer have a nice day
The solution is , 209 is the area of this composite figure, in square centimeters.
What is the area of triangle?Area of triangle is defined as the total region that is enclosed by the three sides of any particular triangle.
Formula: area= 1/2× base × height
here, we have,
given that,
A triangle with base of 11 centimeters and height of 6 centimeters is on top of a rectangle with length 16 centimeters and width 11 centimeters.
now, we know,
area of triangle:
area= 1/2× base × height
A = 1/2 * 11 * 6
=33
again,
we have,
Area of a rectangle (A) is the product of its length (l) and width (w).
A= l. w
so, A = 16* 11
=176
finally, the area of this composite figure, in square centimeters is,
33+176 = 209
Hence, The solution is , 209 is the area of this composite figure, in square centimeters.
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16.85 - 3.9 what is the answer
A 16.46
B 12.95
C 20.75
D 16.811
Write the following expressions in standard form:
⅘ (¼ − 5)
Answer:
Step-by-step explanation:
[tex]\frac{4}{5}(\frac{1}{4}-5)=\frac{4}{5}*\frac{1}{4}-\frac{4}{5}*5\\\\=\frac{1}{5}-4\\\\=\frac{1}{5}-\frac{4*5}{1*5}\\\\=\frac{1}{5}-\frac{20}{5}\\\\=\frac{1-20}{5}\\\\=\frac{-19}{5}[/tex]
Find the real numbers x and y.
22 + yi = 20 - X+3i.
x=
y=
Answer:
x = - 2, y = 3
Step-by-step explanation:
Given
22 + yi = 20 - x + 3i
Compare the coefficients of like terms on both sides, that is
22 = 20 - x ( subtract 20 from both sides )
2 = - x ( multiply both sides by - 1 )
x = - 2
And
yi = 3i , hence y = 3
Select a composite number to break into factors. Continue
factoring until all factors are prime.
56
Answer:
The factors are 7 * 2 * 2 * 2
Step-by-step explanation:
Step 1: Find all of the factors
56
28 2
14 2
7 2
Answer: The factors are 7 * 2 * 2 * 2
Write an expression to show how many meters are equivalent to x centimeters.
Answer:
1 metre = 100 centimetres
Step-by-step explanation:
Identify the independent and dependent variable in your equation
Answer:
The independent variable is the variable that can be changed.
The dependent variable is wjat you measure in an experiment
You are considering purchasing deep-dish caramel apple pies from a local baker. You currently make a very popular deep-dish apple pie but it is labor-intensive and you want to weigh your options. Currently, it costs you $13.45 to make each pie. There is also a $0.21 labor cost per slice for your pie and each of your pies serves 8 slices. The local baker will charge you $75 for 4 pies. Each bakery-made pie serves 12 slices and will cost you $1.36 per pie in labor. Show a cost comparison for each option.
Step-by-step explanation:
your bakery1 pie in total: $13.66
1 slice: $1.70
local bakery1 pie in total: $20.11 (75+1.36×4)÷4
1 slice: $1.67
What is the 72nd term of -27, -11, 5
Answer:
1109
Step-by-step explanation:
The first term is -27, and the common difference is 16.
The nth term is:
a = a₁ + d (n − 1)
a = -27 + 16 (n − 1)
a = -27 + 16n − 16
a = 16n − 43
The 72nd term is:
a = 16(72) − 43
a = 1109
The 72nd term of the arithmetic sequence -27, -11, 5 is 1109.
The sequence provided, -27, -11, 5, is arithmetic, which means it has a common difference between consecutive terms. To find the 72nd term in this sequence, we first determine the common difference by subtracting the first term from the second term, so the common difference (d) is
[tex]-11 - (-27) = 16.[/tex]
The nth term of an arithmetic sequence can be found using the formula
[tex]a_n = a_1 + (n - 1) * d[/tex], where
[tex]a_n[/tex] is the nth term,
[tex]a_1[/tex] is the first term, and
n is the term number. Applying this formula to find the 72nd term, we get:
[tex]a_{72} = -27 + (72 - 1) * 16 \\a_{72} = -27 + 71 * 16 \\a_{72} = -27 + 1136 \\a_{72} = 1109.[/tex]
Therefore, the 72nd term of the sequence is 1109.
There are k players, with player i having value vi > 0, i= 1, ..., K. In every period, two of the players play a game, while the other k -2 wait in an ordered line. The loser of a game joins the end of the line, and the winner then plays a new game against the player who is first in line. Whenever i and j play, i wins with probability
A geometric random variable represents the number of games played until a player loses. The probability can be calculated using the formula P(X = k) = (1-p)^(k-1) * p, where p is the probability of losing a game and k is the number of games.
Explanation:A geometric random variable, denoted as X, represents the number of games played until a player loses. It is a type of random variable in probability theory. We can calculate the probability that it takes a certain number of games until the player loses by using the formula P(X = k) = (1-p)^(k-1) * p, where p is the probability of losing a game and k is the number of games. For example, if p = 0.57 and we want to find the probability that it takes five games until the player loses, we can calculate P(X = 5) = (1-0.57)^(5-1) * 0.57.
Three streets intersect to form a right triangle as shown below. The parts of streets that make up the legs of this triangle are 42 yd. Long and 56 yd. Long. How long is the third side of the triangle formed by the three streets?
Answer:
70 yd.
Step-by-step explanation:
The three streets at the intersection form a right triangle.
For a right triangle, the length of the longest side (called hypothenuse) is given by Pythagorean's theorem:
[tex]h=\sqrt{x^2+y^2}[/tex]
where
x is the length of the 1st side
y is the length of the 2nd side
h is the length of the hypothenuse
Here we want to find the hypothenuse.
We have:
x = 42 yd (length of the 1st side)
y = 56 yd (length of the 2nd side)
Substituting, we find h:
[tex]h=\sqrt{42^2+56^2}=70 yd[/tex]
Answer:
70
Step-by-step explanation: i don't why it only says one answer i thing brainly messed up cause it says i have no brainliest ether to.
PLEASE HELP WILL MARK BRAINLIEST!
What is measure of angle P?
Enter your answer as a decimal in the box. Round only your final answer to the nearest hundredth.
Answer:
60 degrees
Step-by-step explanation:
it is a special 30-60-90 triangle
Answer:67.4
Step-by-step explanation:
This is a basic triangle you have to memorize these angles
A suburban high school has a population of 1376 students. The number of students who participate in sports is 649. The number of students who participate in music is 433. If the probability that a student participates in either sports or music is 974 /1376, what is the probability that a student participates in both sports and music
108 / 1376 is the probability that a student participates in both sports and music.
Step-by-step explanation:
It is given that,
A suburban high school has a population of 1376 students.
Let the event A be the no.of students participated in sports.Let the event B be the no.of students participated in music.The number of students who participate in sports is 649.
The number of students who participate in music is 433.
To find the probability of event A (sports) :
P(sports) = No.of students participated in sports / Total students.
⇒ 649 / 1376
∴ P(A) = 649 / 1376
To find the probability of event B (music) :
P(music) = No.of students participated in music / Total students.
⇒ 433 / 1376
∴ P(B) = 443 / 1376
From the question, we know that the probability that a student participates in either sports or music is 974 /1376.
∴ P(A∪B) = 974 / 1376
To find the probability that a student participates in both sports and music :
The formula used here is,
P(A∩B) = P(A) + P(B) - P(A∪B)
⇒ 649 / 1376 + 433 / 1376 - 974 /1376
⇒ 108 / 1376
∴ P(A∩B) = 108 / 1376
The probability that a student participates in both sports and music is 108/1376
How to determine the probability?The given parameters are:
Total = 1376
Sport = 649
Music = 433
P(Sport or Music) = 974/1376
The required probability is:
P(Sport and Music) = P(Sport) + P(Music) - P(Sport or Music)
This gives
P(Sport and Music) = 649/1376 + 433/1376 - 974/1376
Evaluate the expression
P(Sport and Music) = 108/1376
Hence, the probability that a student participates in both sports and music is 108/1376
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i need help pls asap !!
Answer:
143
Step-by-step explanation:
Because triangles JKL and JUV are similar, the ratio of JV:LJ also applies to the ratio of UJ:JK. JV:LJ=130:60=13:6, so 17x+7=13\6*(66).
KJ=17x+7=11*13=143
Hope this helps!
Janice bought 3 new shirts. The shirts were each originally priced at $24, but she bought them each on sale for a $6 discount. Which equation can be used to find c the cost of the three shirts Janice bought ? A c=24-6 B c= (3x24) - (3x6) C c=(3x24-6
Answer:
the answer is b
Step-by-step explanation:
You have been given a one-time scholarship of $1200 for books and other academic scholarship of $2000 per year for each year that you attend college. What's the total scholarship?
Answer:
T=2000(x)+1200
Step-by-step explanation:
Let the number of years that you attend xollege be x.
Every year, you receive $2000 as academic scholarship hence for x years, you will receive $2000x
However, for books, you receive it once and rhe amount is $1200
The total expenditure will be expressed as
T=2000(x)+1200
Substitute the number of years for x with an integer to get equivalent amount received for scholarship
Why people washing their tooth
Answer:
because hygiene
Step-by-step explanation:
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a
a
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a
Let x1, x2, and x3 represent the times necessary to perform three successive repair tasks at a certain service facility. suppose they are independent, normal rv's with expected values m1, m2, and m3 and variances s21, s2, and s23, respec- tively.
Answer:
P(T₀ < 200) = 0.99856
P(150 < T₀ < 200) = 0.99856
Step-by-step explanation:
The expected values for each of the tasks is μ₁ = 60, μ₂ = 60, μ₃ = 60
The variances for each of the 3 tasks
σ₁² = 15, σ₂² = 15, σ₃² = 15
calculate P(T₀ < 200) and P(150 < T₀ < 200)
When independent distributions are combined, the combined mean and combined variance are given through the relation
Combined mean = Σ λᵢμᵢ
(summing all of the distributions in the manner that they are combined)
Combined variance = Σ λᵢ²σᵢ²
(summing all of the distributions in the manner that they are combined)
Distribution of total time taken for the 3 successive tasks
= X₁ + X₂ + X₃
Expected value = Combined Mean = μ₁ + μ₂ + μ₃ = 60 + 60 + 60 = 180
Combined Variance = 1²σ₁² + 1²σ₂² + 1²σ₃²
= (1² × 15) + (1² × 15) + (1² × 15)
= 45
standard deviation of the combined distribution = √(variance) = √45 = 6.708
Since each of the distributions are said to be normal, the combined distribution too, is normal.
P(T₀ < 200)
We first standardize 200
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - μ)/σ = (200 - 180)/6.708 = 2.98
The required probability
= P(T₀ < 200) = P(z < 2.98)
We'll use data from the normal probability table for these probabilities
P(T₀ < 200) = P(z < 2.98) = 0.99856
b) P(150 < T₀ < 200)
We first standardize 150 and 200
For 150
z = (x - μ)/σ = (150 - 180)/6.708 = -4.47
For 200
z = (x - μ)/σ = (200 - 180)/6.708 = 2.98
The required probability
= P(150 < T₀ < 200) = P(-4.47 < T₀ < 2.98)
We'll use data from the normal probability table for these probabilities
P(150 < T₀ < 200) = P(-4.47 < T₀ < 2.98)
= P(z < 2.98) - P(z < -4.47)
= 0.99856 - 0.0000 = 0.99856
Hope this Helps!!!
This question relates to the times needed for repair tasks at a service facility and involves concepts such as expected values, variances, and probability distributions. It also mentions sample standard deviations, estimates of population standard deviations, and sample means.
Explanation:The question is about the times necessary to perform three successive repair tasks at a service facility. Let x1, x2, and x3 represent the times for each task. Assuming they are independent, normal random variables, we can calculate the expected values and variances using the given information. For example, the expected value of x1 is m1, and the variance is s21.
The question also refers to different figures that represent probability distributions for the repair times. In Figure 5.19, the shaded area represents the probability that the repair time is less than three. In Figure 5.18, the shaded area represents the probability that the repair time is greater than two. These figures provide visual representations of the probabilities associated with the repair times.
Finally, the question mentions the concepts of sample standard deviations, estimates of population standard deviations, sample means, and population means. These concepts are relevant for analyzing the repair times and understanding the characteristics of the data.
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Can someone help me with this problem please??
The class has 14 boys, 12 girls, and 1 teacher. What is the ratio of girls to the class?
Group of answer choices
12:27
14/12
27 to 12
12/14
Answer:
12:27
Step-by-step explanation:
Answer:
12:27
Step-by-step explanation:
Algebra 1 unit 7 Exam question- Will mark brainliest if answered quickly and correctly
Answer:
[tex]=50m^{\frac{5}{3}}n^{\frac{3}{8}}[/tex]
Step-by-step explanation:
[tex]\left(5m^{\frac{4}{3}}\cdot \:5n^{\frac{1}{4}}\right)\left(m^{\frac{1}{3}}\cdot \:2n^{\frac{1}{8}}\right)[/tex]
[tex]=m^{\frac{4}{3}}\cdot \:5^{1+1}n^{\frac{1}{4}}m^{\frac{1}{3}}\cdot \:2n^{\frac{1}{8}}[/tex]
[tex]=m^{\frac{4}{3}}\cdot \:5^2n^{\frac{1}{4}}m^{\frac{1}{3}}\cdot \:2n^{\frac{1}{8}}[/tex]
[tex]=5^2n^{\frac{1}{4}}m^{\frac{4}{3}+\frac{1}{3}}\cdot \:2n^{\frac{1}{8}}[/tex]
[tex]=5^2m^{\frac{4}{3}+\frac{1}{3}}\cdot \:2n^{\frac{1}{4}+\frac{1}{8}}[/tex]
[tex]=5^2\cdot \:2m^{\frac{5}{3}}n^{\frac{1}{4}+\frac{1}{8}}[/tex]
[tex]=5^2\cdot \:2m^{\frac{5}{3}}n^{\frac{3}{8}}[/tex]
[tex]=50m^{\frac{5}{3}}n^{\frac{3}{8}}[/tex]