At the moment the acceleration of the blue ball is 9.40 m/s2, what is the ratio of the magnitudes of the force of air resistance to the force of gravity acting on the blue ball? use 9.81 m/s2 for the standard value of g at the location of the experiment.

Answers

Answer 1
Let us see. We have that Newton's Law holds in this case, so [tex]\sum{F}=m*a[/tex] where a is the acceleration of the ball, F the forces acting on it and m its mass. There are 2 forces acting on it, the force of gravity W and air resistance R. We can easily see that these two act in opposite directions (gravity towards the ground, resistance upwards), so |ΣF|=W-R (1) . We have that W=m*g where g=9.81 m/s2. We also have that ΣF=9.40*m. From this relationship, substituting into (1) all the known values, we get that R=m(9.81*-9.40)=m*0,41. We take then the ratio R/W. This is equal to:[tex] \frac{0.41 m }{9.81m} =0.042=4.2\%[/tex]. This is our final answer.
Answer 2

The ratio of the magnitudes of the force of air resistance to the force of gravity acting on the ball is approximately 1:24.

The student is asking about the ratio of the force of air resistance to the force of gravity acting on a blue ball, when the ball has an acceleration of 9.40 m/s2. To calculate this ratio, we can use Newton's second law, F = ma, where F is the force, m is the mass of the ball, and a is the acceleration of the ball due to the net force acting on it. If we denote the force of air resistance as Fair and the force of gravity as Fgrav, we can write Fnet = Fgrav - Fair, since the air resistance works in the opposite direction of gravity.

Given that the acceleration due to gravity is approximately 9.81 m/s2, the force due to gravity (weight) can be expressed as Fgrav = mg. Here, the acceleration is less than g due to air resistance, thus we can write Fnet = ma = mg - Fair. Since the acceleration of the ball is given as 9.40 m/s2, we can now express Fair as mg - ma. Taking the ratio of Fair to mg (the weight), we get:

(mg - ma) / mg = (g - a) / g = (9.81 - 9.40) / 9.81.

Therefore, the ratio of the magnitudes of the force of air resistance to the force of gravity is equal to 0.0418, which simplifies to approximately 1:24.


Related Questions

500 ml of four different liquids are heated to 50oC. According to the specific heat data, which liquid will cool to 35oC in the shortest amount of time?

Answers

That would be Gasoline.

Answer:C) gasoline

Explanation:

Specific heat is the measure of the heat energy required to increase or decrease the temperature of a substance by a certain temperature interval. Gasoline has the lowest specific heat; that means it takes less energy to lower or raise the temperature of gasoline compared to the other three liquids.

Chanel has some cotton candy that came in a cloudy shape. She wants to make it more dense. Which describes the candy before and after Chanel manipulated it?
1)The candy before was a cube, and the candy after was a ball.
2)The candy before was compacted, and the candy after was fluffy.
3)The candy before was fluffy, and the candy after was compacted.
4)The candy before was a ball, and the candy after was a cube.

Answers

Answer: Option (C) is the correct answer.

Explanation:

As we known that density is the amount of mass divided by volume of the substance.

Mathematically,    Density = [tex]\frac{mass}{volume}[/tex]

So, when candy was present in the shape of a cloud then it means that it was fluffy as it has more volume.

Since, density is inversely proportional to volume therefore, with increase in volume there will occur a decrease in density.

But when the candy will become compact then there will occur a decrease in its volume. Hence, then there will occur an increase in the density of the candy.

Thus, we can conclude that the statement candy before was fluffy, and the candy after was compacted best describes the candy before and after Chanel manipulated it.

In terms of the torque needed to rotate your leg as you run, would it be better to have a long calf and short thigh or vice versa? a) Long calf, short thigh b) Short calf, long thigh c) Does not matter

Answers

Final answer:

Having a short calf and long thigh would result in better torque for leg rotation during running, as a longer lever arm (thigh) from the pivot point (knee) allows for greater torque. However, proportions should be balanced for optimal running biomechanics.

Explanation:

In terms of the torque needed to rotate your leg as you run, it would be better to have a short calf and long thigh. This is because torque is the rotational equivalent of force and is calculated by multiplying the force by the distance from the pivot point. In this case, the pivot point is the knee.

Therefore, a longer thigh would result in a greater torque because the force (muscle contraction) is applied further from the pivot point (knee). Conversely, a short calf means less mass is being rotated around the pivot point, reducing the torque needed for movement.

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In terms of the torque needed to rotate your leg as you run, it be better to have b) Short calf, long thigh

In terms of the torque needed to rotate your leg as you run, it would be better to have a short calf and long thigh.

This is because torque is the rotational equivalent of force, and it depends on both the magnitude of the force and the distance from the pivot point where the force is applied. In running, the longer the distance from the pivot point (knee), the more torque is generated by the same muscle force. A long thigh and short calf combination helps in maximizing this distance, thereby reducing the effort required to achieve the same angular acceleration of the leg.

Let's break this down step-by-step:

Torque (τ) is defined as τ = r × F, where r is the distance from the pivot point (in this case, the knee) and F is the force applied by the muscles.For a given force, increasing the distance r will increase the torque, making it easier to rotate the leg.A long thigh means a greater r from the hip pivot point, increasing the torque generated for the same muscle effort.A short calf means less weight and less moment of inertia that needs to be rotated, making the rotation more efficient.

How much work does an elevator motor do to lift a 1200-kg elevator car a height of 80 m at constant speed?

Answers

The increase in gravitational potential energy of the elevator car when is lifted to a height of 80 m is given by
[tex]\Delta U=mg \Delta h[/tex]
where m=1200 kg is the mass of the elevator car, [tex]g=9.81 m/s^2[/tex] is the gravitational acceleration, and [tex] \Delta h=80 m[/tex] is the variation of height of the elevator car. If we plug these numbers into the equation, we find:
[tex]\Delta U=(1200 kg)(9.81 m/s^2)(80 m)=9.42 \cdot 10^5 J[/tex]

For the work-energy theorem, the work done by the motor to lift the elevator must be equal to the energy acquired by the elevator car: but the energy acquired by the elevator car is [tex]9.42 \cdot 10^5 J[/tex], therefore the work done by the motor is exactly equal to this value:
[tex]W=\Delta U=9.42 \cdot 10^5 J[/tex]

Answer:

Work = 940800 J

Explanation:

As we know that work done is defined as

Work = (Force)(displacement in the direction of force)

here elevator motor lift a mass of 1200 kg

so in order to lift it up motor must have to apply the force same as the weight so that it will move up with constant speed.

so here we have

[tex]F = mg[/tex]

[tex]F = (1200 kg)(9.8 m/s^2)[/tex]

[tex]F = 11760 N[/tex]

now it is displaced upwards by distance d = 80 m

so here we have

[tex]W = (11760)\times (80)[/tex]

[tex]W = 940800 J[/tex]

so above is the work done by the elevator to lift it upwards

What are three machines that depend on gravity to work

Answers

Hello!

There are lot's of machines that depend on gravity to work! Here's a few:

• Lever

• Screw

• Wheel

• Pulley

Which of the following correctly describes the first animals that appeared?
A.) these were large creatures, similar to dinosaurs
B.) these were bony creatures that lived only in wet environments
C.) these were soft and boneless creatures
D.) these were large creatures that lived only in dry environments

Answers

A.) These were large creatures, similar to dinosaurs.

An unmanned spacecraft leaves for Venus. Which statements about the spacecrafts journey are true?

A)The weight of the spacecraft keeps changing.
B)The mass of the spacecraft keeps changing
C)The weight of the spacecraft remains the same
D) The mass of the spacecraft remains the same
E)The gravotational pull on the spacecraft remains the same
Hint: There is more than one answer

Answers

Answer:

A)The weight of the spacecraft keeps changing.

D) The mass of the spacecraft remains the same

Explanation:

As we know that the acceleration due to gravity depends on the height from the surface

As we know that the force due to gravity on objects near the surface is given as

[tex]F = \frac{Gm_1m_2}{(R+h)^2}[/tex]

here we know that

R = radius of planet

h = height from the surface of planet

So as we move away at more height the gravitational attraction force will keep on decreasing.

This gravitational attraction force of planet is also known as weight so we can say that the weight of the object will keep on changing while object move away.

Also we know that mass of object is quantity of the matter which always remains constant.

Jack (mass 52.0 kg ) is sliding due east with speed 8.00 m/s on the surface of a frozen pond. he collides with jill (mass 49.0 kg ), who is initially at rest. after the collision, jack is traveling at 5.00 m/s in a direction 34.0∘ north of east. ignore friction. part a what is the direction of the jill's velocity after the collision?

Answers

Final answer:

Using the law of conservation of momentum, it is determined that after her collision with Jack, Jill will move in a direction that is south of east.

Explanation:

This problem involves the principle of conservation of momentum. In this case, we have a two-body collision, where Mass1 (Jack, with mass 52kg and initial velocity 8m/s due east) collides with Mass2 (Jill, with mass 49.0kg and initially at rest). After the collision, Jack is traveling at a direction 34.0° north of east (let's call this direction east') with a speed of 5m/s. The initial momentum (Mass1 + Mass2) should be equal to the final momentum if we ignore the friction.

Before the collision, the total momentum was Momentum1 initial = Mass1 x Velocity1 initial = 52kg x 8m/s = 416 kg m/s, all in an eastward direction. Momentum2 initial = 0, as Jill was at rest.

After the collision, the final momentum of Jack becomes Momentum1 final = Mass1 x Velocity1 final = 52kg x 5m/s = 260 kg m/s, directed 34° north of east.

According to the law of conservation of momentum, the total initial momentum must equal the total final momentum. Hence, the final momentum of Jill will be Momentum2 final = Momentum1 initial - Momentum1 final = 156 kg m/s. This quantity only gives us the magnitude of the momentum, but we can calculate the direction based on Jack’s final direction. Given that momentum is a vector quantity, the principle of vector composition lets us infer that Jill’s final direction must be south of east to balance the north-of-east component of Jack's final momentum.


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An experiment that produces waves on a string is analyzed, and the experimental value for the wave speed is found to be 66 m/s. If the accepted value for the wave speed is 63 m/s, what is the percent error? 0.045% 0.048% 4.5% 4.8%

Answers

4.8 is the correct answer

Answer:

4.8%

Explanation:

percentage error can be calculated as the difference between the theoretical and experimental value divided by the experimental value expressed in percentage.

The percentage error can be  computed mathematically as

(accepted value - experimental value)/accepted value × 100

accepted value = 63 m/s

experimental value = 66 m/s

difference = 63 - 66 = -3 m/s

use the absolute value = 3 m/s

percentage error = (accepted value - experimental value)/accepted value × 100

percentage error = 3/63 × 100

percentage error = 300/63

percentage error = 4.76%

percentage error = 4.8%

A certain shade of blue has a frequency of 7.15 × 1014 hz. what is the energy of exactly one photon of this light?

Answers

The energy carried by a single photon of frequency f is given by:
[tex]E=hf[/tex]
where [tex]h=6.6 \cdot 10^{-34} m^2 kg s^{-1}[/tex] is the Planck constant. In our problem, the frequency of the photon is [tex]f=7.15 \cdot 10^{14}Hz[/tex], and by using these numbers we can find the energy of the photon:
[tex]E=(6.6\cdot 10^{-34}m^2 kg s^{-1})(7.15 \cdot 10^{14}Hz)=4.7 \cdot 10^{-19}J[/tex]

What is the maximum velocity for the pacific plate?

Answers

Calculating the Velocity of the Pacific Plate. Standard 3.5: 

When a guitar string plays the note "a," the string vibrates at 440 hz ?

Answers

Answer:

440hz

Explanation: Guitars do in fact play at 440 herts for the note a

A block of mass m1 = 3.5 kg moves with velocity v1 = 6.3 m/s on a frictionless surface. it collides with block of mass m2 = 1.7 kg which is initially stationary. the blocks stick together and encounter a rough surface. the blocks eventually come to a stop after traveling a distance d = 1.85 m . what is the coefficient of kinetic friction on the rough surface? μk =

Answers

Final answer:

The calculation involves combining the masses after collision, calculating the final velocity using the law of conservation of momentum and then finding the frictional work done. Using the work-energy theorem, we can solve for the coefficient of kinetic friction.

Explanation:

The question is asking to find the coefficient of kinetic friction on the rough surface where two blocks m1 and m2 have collided and eventually come to a stop after traveling a certain distance. We first need to combine the mass of both blocks as they stick together and this results in a total mass (m1 + m2 = 3.5 kg + 1.7 kg = 5.2 kg). After collision, we can use the law of conservation of momentum to calculate the final velocity when both blocks stick together (m1*v1 + m2*v2 = (m1 + m2) * v_final).

Substituting known values (3.5 kg * 6.3 m/s + 1.7 kg * 0 m/s = 5.2 kg * v_final), we get v_final = 4.425 m/s.

Now, to find the coefficient of kinetic friction, we will use the equation of work-energy theorem where Workdone by friction = Change in kinetic energy. The work done by frictional force is equal to the force of friction multiplied by the distance, and force of friction equals the coefficient of kinetic friction times the normal force (which is mass times gravity in this case).

Thus, the equation would be: μk * m1 * g * d = ½ * m1 * v1^2 (since the final velocity is zero). Substituting the known values into this equation, we can solve to find the coefficient μk.

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"why might a good electrical conductor also be a good thermal conductor"

Answers

A good electrical conductor is a material that has a lot of free charges that can easily move across the material, and with a large mean free path.

Now let's assume that one side of the material is at higher temperature than the other side. The charges on the hotter side move faster than the charges on the cooler side, so the faster charges transfer part of their energy to the charges of the cooler side by collisions. The larger the number of free charges (and the larger their mean free path), the faster is this transmission of energy (which is basically transmission of heat), so the larger is the thermal conductivity of the material, so a good electrical conductor is generally also a good thermal conductor.

Two charged parallel plates are 0.25 meters away from each other. The field between the plates is 600 . What is the electric potential difference?

Answers

I assume that "600" is [tex]600 V/m[/tex].

The relationship between the intensity of the electric field E and the potential difference [tex]\Delta V[/tex] is given by
[tex]\Delta V = Ed[/tex]
where d is the distance between the two points at which the potential difference is calculated.
Using [tex]E=600 V/m[/tex] and [tex]d=0.25 m[/tex], we find
[tex]\Delta V=Ed=(600 V/m)(0.25 m)=150 V[/tex]

Answer:

ΔV = 150 V

Explanation:

A mass of 15 kg of air in a piston-cylinder device is heated from 25 to 77°c by passing current through a resis tance heater inside the cylinder. the pressure inside the cylin der is held constant at 300 kpa during the process, and a heat loss of 60 kj occurs. determine the electric energy supplied, in kwh

Answers

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
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Which statement explains why the moon's gravity is able to create high and low tides

Answers

the moon is revolving more slowly than the earth is rotating 

why were you able to see the effects of the magnetic fields using iron filings

Answers

The iron filings aligned themselves in a pattern, along with the magnet connecting the north and south poles. This creates the “magnetic field”. Interacting with a metal object in between the magnetic properties of the metal interact with the magnet, expressing signs of magnetic force acting on it and the metal, pulled together letting you see the see the effects of the magnetic fields using iron filings. 
Iron filing are soft magnetic materials. The are highly attracted by magnets. 
They are used in the study of magnetic fields.
Another reason why they are used because they are light and and they can aline themselves in the paths of the magnetic fields. This way the fields patterns can be seen clearly.

Brass is an alloy of copper and zinc the two metals are melted mixed and then solidified how would you best classify brass

Answers

Hello!

Brass is a Homogeneous mixture.

Homogeneous mixtures are those in which the components are in the same proportions in all the sample. In brass, as the two metals are fused together to form an alloy, the composition is the same in the entire piece. Brass is also called a Solid Solution. Brass is not a pure substance because it has two different elements in its composition.

Have a nice day!

Brass can be classified as  [tex]\boxed{{\text{a}}{\text{. homogenous mixture and a solid solution}}}[/tex].

Further explanation:

Alloy:

An alloy is defined as combination of metals or a combination of one or more metals with non-metals. Alloys have a large range of applications, ranging from surgical tools, aerospace industry to automobile construction. Steel, solder, brass, pewter, bronze, and amalgams are some examples of alloys. Alloys can be either solid solution or a mixture of metallic phases.

Mixture:

The material that is made up of two or more substances is called a mixture. It has no fixed formula, and its composition is also varied. All the individual constituents retain their properties after the formation of the mixture.

Types of mixtures:

1. Homogeneous mixtures

Homogeneous is a Latin word that means the same. These mixtures have a uniform composition throughout. Air, orange juice, and blood are the examples of a homogenous mixture.

2. Heterogeneous mixtures

Heterogeneous is a Latin word that means different. These mixtures that have non-uniform composition throughout. Concrete, soda, and chocolate chip cookies are the examples of a heterogeneous mixture.

Characteristics of mixtures:

1. It has a variable composition and has no formula.

2. Mixtures are not formed by any chemical reactions.

3. Mixtures can be either homogeneous or heterogeneous.

4. The constituents of the mixtures can be separated by physical methods such as filtration, heating, drying, distillation, crystallization.

5. The properties of the individual particles of the mixture are retained even after the formation of mixtures.

Copper and zinc are the two metals that are first melted, mixed and then solidified to form brass. Their composition is the same throughout the whole part of brass. So brass is an example of homogeneous mixture. It is also known as solid solution where zinc acts as solute and copper is a solvent.

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1. The major contribution of Antoine Lavoisier to chemistry: https://brainly.com/question/2500879

2. Example of physical change: https://brainly.com/question/1119909

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Mixture

Keywords: mixture, characteristics, formula, composition, properties, chemical reactions, filtration, distillation, heating, crystallization, homogeneous, heterogeneous, brass, alloy, metals, non-metals, aerospace industry, automobile construction, surgical tools, solid solution, zinc and copper.

If it takes 6.02 kj of heat energy to melt a mole of ice, how much heat is absorbed when 6.30 g of water melts? 21.0 j 2.10 kj 21 kj 0.210 kj

Answers

First, let's see how many moles correspond to 6.30 g of water.
The molar weight of water is 18.01 g/mol, so
[tex]n= \frac{6.30 g}{18.01 g/mol}=0.35 mol [/tex]
Then we know it takes 6.02 kJ to melt 1 mole of ice, so if we have 0.35 mol, the amount of heat needed will be
[tex]Q=6.02 kJ \cdot 0.35 mol=2.10 kJ[/tex]

Suppose you charge a 1.0 f capacitor with two 1.5 volt batteries. how much charge was on each plate?

Answers

The charge on each plate of the capacitor is given by:
[tex]Q=C \Delta V[/tex]
where C is the capacitance of the capacitor, while [tex]\Delta V[/tex] is the potential difference applied on the two plates. Since we are using two batteries of 1.5 V, the total voltage applied is (assuming the two batteries are in series) 1.5 V+1.5 V= 3.0 V. Therefore, the charge on each plate is
[tex]Q=(1.0 F)(3.0 V)=3.0 C[/tex]

If you charge a 1.0 f capacitor with two 1.5 volt batteries, the amount of charge on each of the plates is 3colombs

The formula for calculating the charge on a capacitor is expressed as:

[tex]Q = C \triangle v[/tex]

C is the capacitance of the capacitor in farads

Δv is the change in the potential difference

Given the following parameters

C = 1.0F

For a two 1.5V batteries, v = 2(1.5) = 3V

Substitute the given parameters into the formula as shown:

[tex]Q = 1.0 \times 2(1.5)\\Q=1 \times 3.0\\Q =3Coulumbs[/tex]

Hence the amount of charge on each of the plates is 3colombs.

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Unlike metals, nonmetals exhibit high ______ and fractures easily when subjected to stress.
A) absorbance
B) brittleness
C) ductility
D) malleability

Answers

The asnwere is B) Brittleness

Answer: Option (B) is the correct answer.

Explanation:

Non-metals are the substance which are electron deficient in nature.

Some properties of non-metals are as follows.

Non-metals are dull.They are brittle, that is, they tend to break easily.They have low melting and boiling point.They do not conduct heat and electricity.The are not malleable or ductile.

Thus, we can conclude that unlike metals, nonmetals exhibit high brittleness and fractures easily when subjected to stress.


A 20.0 μf capacitor initially charged to 30.0 μc is discharged through a 1.80 kω resistor. how long does it take to reduce the capacitor's charge to 15.0 μc

Answers

The charge Q at time t on the capacitor (initially charged) in a RC-circuit is given by
[tex]Q(t)=Q_0 e^{-t/\tau}[/tex] (1)
where [tex]Q_0[/tex] is the initial charge, and [tex]\tau =RC[/tex] is the time constant of the circuit.

Using [tex]C=20 \mu F=20 \cdot 10^{-6}F[/tex] and [tex]R=18 k\Omega = 18 \cdot 10^3 \Omega[/tex] we can calculate the time constant:
[tex]\tau = RC= 0.36 s[/tex]

The problem asks for the time t at which the capacitor's charge is reduced to [tex]Q(t)=15 \mu C[/tex]. Since the initial charge is [tex]Q_0 = 30 \mu C[/tex], we can write
[tex] \frac{Q(t)}{Q_0}= \frac{15 \muC}{30 \muC} = \frac{1}{2} [/tex]
And we can rewrite equation (1) as
[tex] \frac{1}{2} = e^{-t/\tau} [/tex]

By solving this and by using [tex]\tau=0.36 s[/tex], we find
[tex]t=-\tau \ln( \frac{1}{2} )=0.25 s[/tex]
Final answer:

The time it would take for a 20.0 μF capacitor initially charged to 30.0 μC to discharge through a 1.80 kΩ resistor and reduce the capacitor's charge to 15.0 μC can be calculated using the formula for exponential decay and the time constant of the RC circuit.

Explanation:

The time it takes for a capacitor to discharge to half of its original charge can be found using the formula for exponential decay, based on the time constant (t) of the RC circuit, which is given by t = RC, where R is the resistance and C is the capacitance. The time constant represents the time it takes for the charge to decrease to about 36.8% of its initial value. Since we are looking for the time it takes to reduce to half of the initial charge, we must solve the equation 0.5 = e^(-t/RC), where e is the base of natural logarithms.

To solve for t, we can rearrange the equation to get -ln(0.5) = t/RC. Given that R = 1.80KΩ = 1.80x10^3 Ω and C = 20.0 µF = 20.0x10^-6 F, we can substitute these into the equation to find t. Therefore, the time it takes for a 20.0 μF capacitor initially charged to 30.0 µC to discharge through a 1.80 kΩ resistor to reduce the capacitor's charge to 15.0 μC can be calculated using these formulas.

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An agitated llama may spit to assert dominance, or to ward off threats. llamas can spit a considerable distance, and people handling them need to keep this in mind. part a if the spittle from a llama is launched from an initial height of 1.8 m with a speed of 5.5 m/s, and at an angle of 13 ?? above horizontal, how far will it travel horizontally?

Answers

the answer is 4.7 m for the spàthan. this is a very question! I hope this helps my friend! :-)

The horizontal distance traveled by the spittle is 2.62 m.

The given parameters;

height of projection, h = 1.8 minitial velocity, v = 5.5 m/sangle of projection, Ф = 13°

The time of motion is calculated as;

[tex]h = v_0_yt + \frac{1}{2} gt^2\\\\1.8 = (5.5\times sin(13))t + (0.5\times 9.8)t^2\\\\1.8 = 1.24t + 4.9t^2\\\\4.9t^2 + 1.24t - 1.8= 0\\\\solve \ the \ quadratic \ equation\ using \ formula \ method;\\\\a = 4.9, \ b = 1.24, \ c = -1.8\\\\t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-1.24 \ \ +/- \ \ \sqrt{(1.24)^2 - 4(4.9\times -1.8)} }{2(4.9)} \\\\t = 0.49 \ s[/tex]

The horizontal distance traveled by the spittle is calculated as;

[tex]X = v_0_x \times t\\\\X = 5.5\times cos (13) \times 0.49\\\\X = 2.62 \ m[/tex]

Thus, the horizontal distance traveled by the spittle is 2.62 m.

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One side of the moon always faces Earth because the time it takes the moon to spin on its axis is blank the time it takes the moon to travel around Earth.

Answers

The word to fill in the blank is "equal". Because the time taken to rotate (spin on its axis) is equal to the time of revolution (going around the earth), this means that both have the same rate of angular rotation. So for every bit that the moon goes around its orbit around earth, the moon itself rotates accordingly to present the exact same side to earth.

Answer: One side of the moon always faces Earth because the time it takes the moon to spin on its axis is "the same as" the time it takes the moon to travel around Earth.

Which stage of star development comes right after the long stable phase in the life cycle? A. Nova B. Red giant C. Red dwarf D. White dwarf

Answers

The answer is B. Red Giant. This comes after the main sequence phase which is stable phase where the star is at the point where continuous conversion of hydrogen to helium, once consumed it turns into red giant.

A bag of groceries has a weight of 44 newtons. Find its approximate weight in kilograms.

Answers

You cannot convert newtons to kilograms, or pounds to kilograms,
or kilograms to pounds or newtons.

Newtons and pounds are units of FORCE.  Kilogram is a unit of MASS.


If an object weighs 44 newtons on Mars,
then its mass is about 13.5 kilograms

If an object weighs 44 newtons on the Moon,
then its mass is about 27.2 kilograms.

If an object weighs 44 newtons on Earth,
then its mass is about 4.5 kilograms.

Final answer:

To convert the weight of a bag of groceries from newtons to kilograms, divide the weight in newtons (44 N) by the acceleration due to gravity (9.8 m/s²), which gives an approximate mass of 4.49 kg.

Explanation:

To find the approximate weight of a bag of groceries in kilograms when given a weight of 44 newtons, we need to use the relation between mass, weight, and gravitational acceleration. Weight is the force due to gravity, and it's measured in newtons (N). To convert newtons to kilograms, we divide the weight by the acceleration due to gravity, which is approximately 9.8 m/s². Therefore:

Weight in kilograms = Weight in newtons ÷ gravitational acceleration

Weight in kilograms = 44 N ÷ 9.8 m/s²

Weight in kilograms ≈ 4.49 kg

This is a physics problem involving the conversion of units between the weight (force) and mass, and it requires a basic understanding of the relationship between these concepts. The result, 4.49 kg, represents the mass of the groceries that causes a weight of 44 N.

What was the speed of the cannon ball if the spring compressed 58 cm when the cannon was fired?

Answers

I attached the full question.
We need to write down the law of conservation of momentum and energy.
The law of conservation of momentum:
[tex]m_cv_c=m_bv_b[/tex]
The law of conservation of energy:
[tex]\frac{1}{2}x^2=\frac{m_c v_c^2}{2}[/tex]
This tells us that potential energy of the compressed spring is used to stop the canon. In other words, the kinetic energy of the canon, after firing is used to do work again the force of the spring.
We can use this two equations to find the velocity of the cannonball:
[tex]\frac{1}{2}x^2=\frac{m_c v_c^2}{2}\\ v_c=\sqrt{\frac{1}{m_c}}}\cdot x[/tex]
We can now plug this in the first equation:
[tex]m_cv_c=m_bv_b\\ v_c=\sqrt{\frac{1}{m_c}}}\cdot x\\ m_c\cdot\sqrt{\frac{1}{m_c}}}\cdot x=m_bv_b\\ \sqrt{m_c}}}\cdot x=m_bv_b\\ v_b=\frac{\sqrt{m_c}x}{m_b}[/tex]
Please note that I found this question online with multiple diferent data( mass of the canon, ball etc)
You can use this formula, just plug in your numbers and you will get the correct answer.



To calculate the speed of a cannon ball using the distance the spring compressed, the spring constant is required to use energy conservation principles. Without this value, it is not possible to provide an exact answer.

To determine the speed of the cannon ball given that the spring compressed 58 cm when it was fired, we would use the conservation of energy principle where the potential energy stored in the spring is converted into the kinetic energy of the cannon ball. If we had the spring constant (k), we could use the formula for the potential energy stored in a spring, which is PE_spring = (1/2)kx² where x is the compression distance, and equate this to the kinetic energy formula KE = (1/2)mv², where m is the mass of the cannon ball, and v is the velocity we want to find. Without the specific spring constant, it is not possible to calculate the exact speed of the cannon ball.

The diagram below shows rock is affected when water enters cracks in rock,freezes and becomes ice

Answers

Final answer:

The question explores the concept of physical weathering known as frost wedging, which occurs when water freezes in rock cracks, causing the rocks to break apart. This process relates to the property of water expanding upon freezing, which explains ice's lower density and its effects on the environment and human-made structures.

Explanation:

The student's question pertains to the process by which water enters cracks in rocks, freezes, and expands into ice, which is known as frost wedging or frost weathering. This process is a type of physical weathering that occurs in cold climates when temperatures fluctuate above and below 0°C (32°F). As water freezes, it expands by approximately 9%, exerting significant pressure on the surrounding rock, eventually causing it to break apart. The phenomenon of water expanding upon freezing is due to the unique structure of ice.

Understanding ice density is significant for explaining why ice floats and how it affects aquatic ecosystems and human constructions. When water transitions to ice, its molecules form a crystalline structure that is less dense than liquid water, causing ice to float. This property of ice provides crucial insulating effects in natural bodies of water, allowing life to persist beneath the ice layer during winter. Furthermore, the expansion of water when it freezes is why we use antifreeze in engines and why pipes can burst if not properly insulated.

Larry designed an experiment to show how heat can be transferred from one place to another. The steps of the experiment are shown below. Light a candle. Place palm of the hand about 6 inches above the flame. Feel the heat from the burning candle on the palm of the hand. What does Larry's experiment most likely demonstrate?

Answers

What Larry's experiment most likely demonstrate is heat transfer by convection

Heat transfer by convection occurs when particles of heated liquid or gases travel away from the source, carrying thermal energy along. Convection above the flame of the lit candle occurs because the hot air from the candle expands, becomes less dense, and rises towards the palm.

Answer:

heat transfer by convection

Explanation:

yeah the heat just goes to your hand like "hello" now your hand is warm just don't TOUCH the fire because then it will go "HELLO" and it will be painful

Have a fantastic life and just I don't know... live life and go outside it's beautiful.

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