In this type of problems what we have to do is unit conversion. In order to do so we need all the equivalences which we will be mentioning during the explanation of the problem:
First of all the answer is asked to be in acre-feet and we can see the data we are getting from the rain is in [tex]in*Km^{2}[/tex] not even a volume unit.
To calculate the volume of poured rain we need to have both numbers in the same units, we will convert [tex]Km^{2}[/tex] to [tex]in^{2}[/tex] using the equivalence [tex]1 Km^{2}=1550001600in^{2}[/tex] like this:
[tex]101Km^{2}*\frac{1550001600in^{2} }{1Km^{2}}=156550161600in^{2}[/tex]
it is possible now to calculate the volume ([tex]Volume_{cuboid}=Area*Height[/tex]) like this:
[tex]Volume_{cuboid}=156550161600in^{2}*2.5in=391375404000in^{3}[/tex]
Now we just need to convert this volume to acre-feet and we will do so using the equivalence [tex]1acre-foot=751271680in^{3}[/tex] like this:
[tex]391375404000in^{3}*\frac{1acre-foot}{751271680in^{3}}=5199.50403658 acre-feet[/tex]
5199.50403658 acre-feet would be the answer to our problem
Find the area of the triangle
Answer:
A ≈ 14.079 square units
Step-by-step explanation:
Area of a triangle is one half the base times the height.
A = ½ bh
A = ½ (10) (2x)
A = 10x
We need to find the value of x.
Starting with the triangle on the left, use Pythagorean theorem to find the length of the base.
(3x)² = (2x)² + a²
9x² = 4x² + a²
a² = 5x²
a = x√5
Repeat for the triangle on the right:
(x + 6)² = (2x)² + b²
x² + 12x + 36 = 4x² + b²
b² = -3x² + 12x + 36
The two bases add up to 10:
a + b = 10
Subtract a from both sides, then square both sides:
b = 10 − a
b² = 100 − 20a + a²
Substitute and simplify:
-3x² + 12x + 36 = 100 − 20(x√5) + 5x²
0 = 64 − (12 + 20√5) x + 8x²
0 = 2x² − (3 + 5√5) x + 16
Solve with quadratic formula:
x = [ -b ± √(b² − 4ac) ] / 2a
x = [ (3 + 5√5) ± √((-(3 + 5√5))² − 4(2)(16)) ] / 2(2)
x = [ (3 + 5√5) ± √(9 + 30√5 + 125 − 128) ] / 4
x = [ (3 + 5√5) ± √(6 + 30√5) ] / 4
x ≈ 1.4079, 5.6823
If we substitute 5.6823 into our a and b equations, we find that a = 12.706 and b = 7.322, which add up to 20.028, not 10.
So x ≈ 1.4079.
Therefore the area is:
A ≈ 14.079
Show in fact that 1=9m + 20n for some integers m and n
Answer:
[tex]1=9\cdot 9+20\cdpt (-4)=81-80[/tex]
Step-by-step explanation:
The greatest common divisor between 9 and 20 is 1, so we know the equation [tex] 1=9m+20n[/tex] has a solution. A solution can be found either by inspection, or by applying Euclidean algorithm.
By inspection we just list some multiples of 9:
9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99
and also list some mutiples of 20:
20, 40, 60, 80, 100, 120
And so we see that we can find a multiple of 9 (81) which is 1 away from a multiple of 20 (80). Which is the solution given at the start.
For the Euclidean algorithm, we should divide the greatest of the two numbers, by the smallest one, and keep track of the remainder:
20 = 9 * 2 + 2
Then we divide 9 by the remainder we got, which is 2:
9 = 2 * 4 + 1
we would continue doing this until getting a remainder of 1 (which we just did). Finally we "solve" for 1, from the last equation:
9 - 2*4 = 1
And then we solve for 2 from the first equation, and plug that in into the previous equation:
20 - 9*2 =2
9 - ( 20 - 9*2)*4 = 1
which does give us the same solution: [tex] 9\cdot 9 +20\cdot (-4)=1[/tex]
Let f be continuous on [0, a] and differentiable on (0, a), Prove that if f(a)=0 then there is at least one value of x in (0, a), such that f(x)= -xf'(x).(5marks) (%4h) 4
Answer:
See picture attached
Step-by-step explanation:
Problem 8 - Simple and Compound Interest
At an effective annual rate of interest of 5.3%, the present value of $7425.70 due in t years is $3250. Determine t
Problem 4 - Simple and Compound Interest
How much would you invest today to have $9500 in 8 years if the effective annual rate of interest is 4%?
Problem 8 - Simple and Compound Interest
At an effective annual rate of interest of 5.3%, the present value of $7425.70 due in t years is $3250. Determine t ?
Answer:
P8) [tex]t=7.02 years[/tex]
P4) Today you have to invest $6941.55
P8) Is the same P8 above
Step-by-step explanation:
P8) First of all, we can list the knowns [tex]VP=7425.70[/tex], [tex]I=3250[/tex] and [tex]i=5.3[/tex]%, so we use [tex]VF=VP+I=7425.70+3250=10675.70[/tex] then we use [tex]t=\frac{ln(VF/VP)}{ln(1+i)}=\frac{ln(10675.70/7425.70)}{ln(1+0.053)} =\frac{0.363}{0.051}=7.02 years[/tex]
P4) First of all, we can list the knowns [tex]VF=9500[/tex], [tex]t=8[/tex] and [tex]i=4[/tex]%, so we use [tex]VP=\frac{VF}{(1+i)^{t} } =\frac{9500}{(1+0.04)^{8} } =6941.55[/tex]
P8) Is the same P8 above
Two sections of statistics are offered, the first at 8 a.m. and the second at 10 a.m. The 8 a.m. section has 25 women, and the 10 a.m. section has 15 women. A student claims this is evidence that women prefer earlier statistics classes than men do. What information is missing that might contradict this claim?
Answer: The conclusion cannot be confirmed unless we have the statistic of the men.
Step-by-step explanation: Only looking at the number of women in both times 8 am and 10 am, will not determine if the men prefer of do no prefer earlier classes. We would need the men's statistics as well for both time slots. There may be more men among the 8 am slot e.g 25 women and 30 men. There is incomplete information to come up with a sound conclusion.
Suppose U is a nonempty subset of the vector space V over eld F. Prove that U is a
subspace if and only if cv + w 2 U for any c 2 F and any v;w 2 U
Answer:
The additive identity of [tex]V[/tex], denoted here by [tex]0_{V}[/tex], must be an element of [tex]U[/tex]. With this in mind and the provided properties you can prove it as follows.
Step-by-step explanation:
In order to a set be a vector space it is required that the set has two operations, the sum and scalar multiplication, and the following properties are also required:
Conmutativity. AssociativityAdditive IdentityInverse additiveMultiplicative identityDistributive properties.Now, if you have that [tex]V[/tex] is a vector space over a field [tex]\mathbb{K}[/tex] and [tex]U\subset V[/tex] is a subset that contains the additive identity [tex]e=0_{V}[/tex] then [tex]U[/tex] and [tex]cv+w \in U[/tex] provided that [tex]u,v\in U, c\in \mathbb{K}[/tex], then [tex]U[/tex] is a closed set under the operations of sum and scalar multiplicattion, then it is a vector space since the properties listed above are inherited from V since the elements of [tex]U[/tex] are elements of V. Then [tex]U[/tex] is a subspace of [tex]V[/tex].
Now if we know that [tex]U[/tex] is a subspace of [tex]V[/tex] then [tex]U[/tex] is a vector space, and clearly it satisfies the properties [tex]cv+w\in U[/tex] whenever [tex]v,w\in U, c\in \mathbb{K}[/tex] and [tex]0_{V}\in U[/tex].
This is an useful criteria to determine whether a given set is subspace of a vector space.
Prove that the square of any even number is always a multiple of 4.
Answer and Explanation:
To prove : The square of any even number is always a multiple of 4.
Proof :
The even numbers is defined as number end with 0,2,4,6,8 or the even number are multiple of 2.
Let the general even number be '2n'.
Squaring the number [tex](2n)^2=2^2\times n^2[/tex]
[tex](2n)^2=4n^2[/tex]
As 4 is the multiple of n².
So, If we square any even number it is always a multiple of 4.
For example,
[tex]2^2=4=4\times 1\\4^2=16=4\times 4\\6^2=36=4\times 9\\8^2=64=4\times 16[/tex]
Hence proved.
Determine the angles made by the vector V= (-35)i + (-41)j with the positive x-and y-axes. Write the unit vector n in the direction of V. Answers: ex= 9,0y i n =
Answer:
angle made by the vector with positive x axis,
[tex]\theta\ =\ 49.51^o[/tex]
the angle by the positive direction of y axis,
[tex]\alpha\ =\ 40.48^o[/tex]
unit vector in the direction of the given vector,
[tex]\hat{n}\ =\ \dfrac{(-35)i+(-41)j}{53.9}[/tex]
Step-by-step explanation:
Given vector is
[tex]\vec{V}=\ (-35)i\ +\ (-41)j[/tex]
we have to calculate the angle made by the vector with positive x and y axis,
The angle made by the vector with positive x axis can be given by,
[tex]tan\theta\ =\ \dfrac{-41}{-35}[/tex]
[tex]=>\ \theta\ =\ tan^{-1}\dfrac{-41}{-35}[/tex]
[tex]=>\ \theta\ =\ 49.51^o[/tex]
And the angle by the positive direction of y axis can be given by
[tex]\alpha\ =\ 90^o-\theta[/tex]
[tex]=\ 90^o-49.51^o[/tex]
[tex]=\ 40.48^o[/tex]
Now, we will calculate the unit vector in the direction of the given vector.
So,
[tex]\hat{n}\ =\ \dfrac{\vec{A}}{|\vec{A}|}[/tex]
[tex]=\ \dfrac{(-35i)+(-41)j}{\sqrt{(-35)^2+(-41)^2}}[/tex]
[tex]=\ \dfrac{(-35)i+(-41)j}{53.9}[/tex]
What percent of 1600 is 2?
Answer: 0.125%
Step-by-step explanation:
Let 1600 corresponds to the 100% value and 2 is a part of the total 100% value 1600.
The formula to find the percent of a part :_
[tex]\%=\dfrac{\text{Part}}{\text{Total}}\times100[/tex]
Substitute Part= 2 and Total = 1600 in the formula, we get :-
[tex]\%=\dfrac{2}{1600}\times100\\\\\Rightarrow\ \%=\dfrac{1}{8}\%=0.125\%[/tex]
Therefore, 2 is 0.125% of 1600.
Hence, the percent of 1600 is 2 = 0.125%
To find what percent of 1600 is 2, divide 2 by 1600 and multiply by 100, resulting in 0.125%. Thus, 2 is 0.125% of 1600.
To determine what percent of 1600 is 2, you can use the formula for percentage:
Percentage = (Part / Whole) × 100
Here, the part is 2 and the whole is 1600. Plug these values into the formula:
Percentage = (2 / 1600) × 100
First, perform the division:
2 / 1600 = 0.00125
Next, multiply by 100 to convert to a percentage:
0.00125 × 100 = 0.125%
Therefore, 2 is 0.125% of 1600.
What is buffer and what is dissolve? (4 pts)
Answer:
The buffer is the solution which basically oppose pH change upon the expansion of an acidic or fundamental parts. It can kill limited quantities of included corrosive or base, in this way keeping up the pH of the arrangement generally stable and steady.
Acidic buffer is the arrangements are usually produced using weak acidic nature and also by the sodium salt.
Dissolve is the process of break down is to make a solute go into an solution. Dissolving is likewise called disintegration. Regularly, this includes a strong going into a fluid stage, however disintegration can include different changes too.
For instance, when compounds structure, one strong breaks down into another to frame a strong arrangement.
The radius of the Earth is 6370km, the atmospheric pressure at sea level is 1 bar and the density at sea level is 1.2 kg/m^3.
Estimate the mass of the atmosphere assuming the height of the atmosphere is 11km.
Answer:
The mass of atmosphere equals [tex]6742.368\times 10^{15}kg[/tex]
Step-by-step explanation:
Since the earth can be assumed to be as sphere ,to calculate the mass of the atmosphere we need to calculate the volume of the atmosphere.
The volume of atmosphere can be found by subtracting the volume of earth from the volume of the sphere formed by envelop of atmosphere around the earth as indicated in the attached figure
Mathematically we have
[tex]V_{atmosphere}=V_{shell}-V_{earth}\\\\V_{atmosphere}=\frac{4\pi (R_{e}+h)^{3}}{3}-\frac{4\pi R_{e}^{3}}{3}\\\\V_{atmosphere}=\frac{4\pi }{3}((6370+11)^{3}-(6370)^{3})\\\\V_{atmosphere}=5618.64\times 10^{6}km^{3}\\\\\\V_{atmosphere}=5618.64\times 10^{15}m^{3}[/tex]\
Now since it is given that 1 cubic meter of atmosphere weighs 1.2 kilogram thus the mass of the whole atmosphere equals
[tex]Mass_{atmosphere}=1.2\times 5618.64\times 10^{15}kg\\\\Mass_{atmosphere}=6742.368\times 10^{15}kg[/tex]
To estimate the mass of the atmosphere, we use the formula Mass = Density × Volume. First, calculate the volume of the atmosphere using the formula for the volume of a cylinder. Then, substitute the given values into the formula and calculate the mass using the formula Mass = Density × Volume.
Explanation:To estimate the mass of the atmosphere, we can use the formula:
Mass = Density × Volume
First, we need to find the volume of the atmosphere. The height of the atmosphere is given as 11 km, so we can calculate the volume using the formula for the volume of a cylinder:
Volume = π × (radius2) × height
Next, we substitute the given values into the formula:
Volume = π × (6370 km)2 × 11 km
Finally, we calculate the mass using the formula:
Mass = Density × Volume
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1. In a college, each student ID card is linked with a unique 5-digit pin from the set {0,1,2,3,4,5,6,7,8,9}. A) Find the number of ID cards possible. B) Find the number of ID cards possible if the 5-digit number is an odd number? C) Recalculate A&B if the digits are not allowed to be repeated
The total number of ID cards possible without repeating digits is 10 x 9 x 8 x 7 x 6 = 30,240.
In a college, the number of ID cards possible can be found by calculating the number of possible options for each digit in the 5-digit pin.
Since each digit can be any number from the set {0,1,2,3,4,5,6,7,8,9}, there are 10 options for each digit. Therefore, the total number of ID cards possible is 10 x 10 x 10 x 10 x 10 = 100,000.
If the 5-digit number is to be an odd number, then the last digit can only be one of the odd numbers {1, 3, 5, 7, 9}. So there are 5 options for the last digit, and for each of the other four digits, there are still 10 options. Therefore, the total number of ID cards possible with an odd 5-digit number is 10 x 10 x 10 x 10 x 5 = 50,000.If the digits are not allowed to be repeated, then for the first digit, there are still 10 options. But for each of the other four digits, there are now 9 options since one digit has been used already. Therefore, the total number of ID cards possible without repeating digits is 10 x 9 x 8 x 7 x 6 = 30,240.Convert 72degrees into radians
Answer:
72° = 1.25 radians
Step-by-step explanation:
As we know that,
[tex]1 degree = \frac{\pi}{180} radians[/tex]
Thus, [tex]72^{\circ} = 72\times\frac{\pi}{180}radians[/tex]
⇒ [tex]72^{\circ} =\frac{2\pi}{5}radians[/tex]
⇒ 72° = 1.25 radians {∵ Using π = 22÷ 7 or 3.14}
Both degrees and radians are used to measure the angle. They are units of angle.
what’s the answer to k and m ? please explain how you found the answer .
Answer:
Step-by-step explanation:
So what multiplied by what is equal to 0.64? Well you know that 8*8 is equal to positive 64, and since 0.64 is just 64 moved down two decimal spaces, you do the same with 8. So For k, it's 0.8
For m, you do the same. So what multiplied by what is equal to 0.25? Well you know that 5*5 is equal to positive 25, and since 0.25 is just 25 moved down two decimal spaces, you do the same with 5. So For m, it's 0.5.
Fill in the table in the photo
Answer:
see the attachment
Step-by-step explanation:
If the growth is 7 feet in 2 weeks and the rate is constant, then it will be half that in one week, or 3.5 feet per week. At week 3, it will be 3.5 feet more than at week 2. The table below shows this progression.
The point (0, 0) means there was no measurable growth when time was starting to be measured (at week 0).
Mr. and Mrs. Wong purchased their new house for $350,000. They made a down payment of 20%, and amortized the rest over 30 years. If the interest rate is 4.2%, which of the following is their correct monthly mortgage payment?
Answer:
$1,369.25
Step-by-step explanation:
Mr. and Mrs. Wong purchased their new house for $350,000.
They made a down payment of 20%
Down payment = 20% of 350000
= $70,000
Loan amount, P = $350,000 - $70,000
= $280,000
Rate of interest, r = 4.2% or 0.042
Time, t = 30 years
Number of period, n = 12 ( monthly )
Formula: [tex]E=\dfrac{P\cdot \frac{r}{n}}{1-(1+\frac{r}{n})^{-n\cdot t}}[/tex]
Substitute the values into formula
[tex]E=\dfrac{280000\cdot \frac{0.042}{12}}{1-(1+\frac{0.042}{12})^{-12\cdot 30}}[/tex]
E = $1,369.25
Hence, The monthly payment for their mortgage will be $1,369.25
A sample of iron ore has a density of 7.87 what is its mass? Show all of your work. If it measures 7.5 cm x 2.53 em x 7.15 cm,
Answer:
Mass=1068gr
Step-by-step explanation:
Volume= 7.5 cm x 2.53 cm x 7.15 cm=135.7cm^3
Density=7.87gr/cm^3
Mass=Density*Volume=135.7*7.87=1068gr
Jacob made a circle-shaped poster for his geometry class.
If the radius of circle-shaped poster is 10 inches, what is the
circumference?
Use 3.14 for .
Answer: [tex]62.8\text{ inches}[/tex]
Step-by-step explanation:
The circumference of a circle is given by :-
[tex]C=2\pi r[/tex], where r is the radius of the circle.
Given : Radius of a circle = 10 inches
Then, the circumference of circle will be :_
[tex]C=2(3.14) (10)\\\\\Rightarrow\ C=62.8\text{ inches}[/tex]
Hence, the circumference of the circle will be [tex]62.8\text{ inches}[/tex]
How to do exponents a quicker way!! Please help my brother!
Let a graph have vertices {L, M, N, O, P, Q, R, S} and edge set {{L,R}, {M,P}, {M,Q}, {N,Q}, {P,R}, {Q,S}, {R,S}} .
a. What is the degree of vertex P?
b.What is the degree of vertex O?
c.How many components does the graph have?
Answer:
a) The degree of vertex P is 2.
b) The degree of vertex O is 0.
c) The graph has 2 components.
Step-by-step explanation:
a) The edges that have P as a vertice are {M,P} and {P,R}.
b) There is no edge with extreme point O.
c) One of the components is the one with the only vertex as O and has no edges. The other component is the one with the rest of the vertices and all the edges described.
The file has a realization of the graph.
246, 299, 360, 404, 379, 199, 279, 749, 794, 849, 914
Compute the mean, median, and mode of these prices.
Find the first and third quartiles of the prices.
Answer:
Mean = 497.5
Median = 379.0
First Quartile = 289
Third Quartile = 771.5
Step-by-step explanation:
Mean is used to measure the central tendency of data which represents the whole data in the best way. It can be found as the ratio of the sum of all the observations to the total number of observations.
⇒ [tex]Mean=\frac{246+ 299+ 360+ 404+ 379+ 199+ 279+ 749+ 794+ 849+ 914}{11}[/tex]
⇒ Mean = 497.5
Median is the middle observation of given data. It can be found by following steps:
Arranging data in ascending or descending order.
Taking the average of middle two value if the total number of observation is even, and this average is our median.
or, if we odd number of observation then the most middle value is our median.
Here, number of observation is 11.
So the middle value is (11+1)÷2 = 6th term
⇒ Median = 379
The mode is the observation which has a high number of repetitions (frequency).
Here frequency of all observation is same. So, it is multi- modal data.
First Quartile is the middle value between Minimum value and Median of data after arranging data in ascending order.
First Quartile (Q₁) = 289
The third Quartile is the middle value between Median and Maximum Value of data after arranging data in ascending order.
Third Quartile (Q₃) = 771.5
Instructions for a chemical procedure state to mix salt, baking soda, and water in a 20:15:10 ratio by mass. How many grams of water would be required to make a mixture that contains 24 grams of baking soda?
Answer:
16 g of water.
Step-by-step explanation:
salt : baking soda : water = 20 : 15 : 10
If we have 24 g of baking soda that is 24/15 = 8/5 times of 15.
So by proportion the amount of water would be 10 * 8/5 = 16 grams.
The mass of water in the mixture is 16 gm
What is Ratio and Proportion ?When a number is divisible by another number then they can be written in the form of ratio p :q , When two ratios are equal they are said to be in proportion.
It is given that
salt, baking soda, and water in a 20:15:10 ratio by mass are mixed
mixture contains 24 grams of baking soda
Mass of Water = ?
Baking Soda : Water = 15 : 10
Let the mass of water is x
then the ratio is 24 : x
As both these ratios are equal
15 : 10 = 24 : x
15 / 10 = 24 / x
x = 24 * 10 / 15
x = 16 gm
Therefore the mass of water in the mixture is 16 gm.
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The formulas below are the cost and revenue functions for a company that manufactures and sells small radios. a. Use the formulas shown to write the company's profit function, P, from producing and selling x radios. b. Find the company's profit if 21,000 radios are produced and sold C(x) 224,000+32x and R(x) 46x a. The company's profit function is P(x)-(Simplify your answer.)
Answer:
(a) The profit function is P(x)=14x-224,000.
(b) The company's profit at x=21000 is 70,000.
Step-by-step explanation:
Cost function is
[tex]C(x)=224,000+32x[/tex]
Revenue function is
[tex]R(x)=46x[/tex]
where, x is number of radios.
(a)
Formula for profit:
Profit = Revenue - Cost
The profit function is
[tex]P(x)=R(x)-C(x)[/tex]
[tex]P(x)=46x-(224,000+32x)[/tex]
[tex]P(x)=46x-224,000-32x[/tex]
[tex]P(x)=14x-224,000[/tex]
The profit function is P(x)=14x-224,000.
(b)
Substitute x=21000 in the above equation to find the company's profit if 21,000 radios are produced and sold.
[tex]P(21000)=14(21000)-224,000[/tex]
[tex]P(21000)=294000-224,000[/tex]
[tex]P(21000)=70,000[/tex]
Therefore the company's profit at x=21000 is 70,000.
The profit function for a company is found by subtracting the cost function from the revenue function. Given the cost and revenue functions, the profit function simplifies to P(x) = 14x - 224,000. If 21,000 radios are sold, the company will take a loss of $56,000.
Explanation:Profit function in a company can be obtained by subtracting total cost from total revenue, it can be represented as P(x) = R(x) - C(x). Here, R(x) is the revenue function and C(x) is the cost function.
Given, the cost function of the company C(x) is 224,000 + 32x and the revenue function R(x) is 46x. Substituting these values into our profit function we get, P(x) = 46x - (224,000 + 32x), simplifying it leads to P(x) = 46x - 224,000 - 32x, which can be further simplified to P(x) = 14x - 224,000.
For part b of the question, if 21,000 radios are produced and sold, we substitute x=21,000 into the profit function. Hence, P(21000) = 14*21000 - 224,000 = -56,000. This indicates that the company will experience a loss when 21,000 radios are produced and sold.
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A 12-m3 oxygen tank is at 17°C and 850 kPa absolute. The valve is opened, and some oxygen is released until the pressure in the tank drops to 650 kPa. Calculate the mass of oxygen that has been released from the tank if the temperature in the tank does not change during the process.
Answer:
Released oxygen mass: 15.92 kg
Step-by-step explanation:
ideal gas law : P*V=nRT
P:pressure
V:volume
T:temperature
n:number of moles of gas
n [mol] = m [g] /M [u]
m : masa
M: masa molar = 15,999 u (oxygen)
R: ideal gas constant = 8.314472 cm^3 *MPa/K*mol =
grados K = °C + 273.15
P1*V*M/R*T = m1
P2*V*M/R*T = m2
masa released : m1-m2 = (P1-P2) * V*M/R*T
m2-m1 = 200 * 10^-3 MPa * 12 * 10^6 cm^3 * 15.999 u / 8.314472 (cm^3 * MPa/K *mol) * 290. 15 K
m2-m1= 38 397.6 * 10^3 u*mol / 2412.44 = 15916.5 g = 15.9165 kg
The question involves the use of the Ideal Gas Law to calculate the mass of oxygen released from a tank when the pressure drops. The initial and final number of moles of oxygen is calculated using the Ideal Gas Law, then the difference represents the number of moles of oxygen released. Multiplying this by the molar mass of oxygen gives the mass of oxygen released, which is about 255.808 kg.
Explanation:The Ideal Gas Law states that PV=nRT, where P is pressure in Pascals, V is volume in m3, n is the number of moles, R is the Universal Gas Constant (8.31 J/(mol.K)), and T is temperature in Kelvin. From the question, we know the initial and final pressures (P1=850 kPa, P2=650 kPa ), Volume (V=12 m3), and temperature (T=17°C = 290 K).
First, we need to calculate the initial (n1) and final (n2) number of moles using the equation n = PV/RT. Substituting the given values to the equation, we get n1= (850000*12) /(8.31*290)= 34974.48 mol and n2= (650000*12) /(8.31*290)= 26980.38 mol.
So, the mass of oxygen that has been released is the difference between the initial and final moles. It equals to 7994.1 mol. Since the molar mass of oxygen is approximately 32 g/mol, the mass of oxygen that has been released is 7994.1 mol * 32 g/mol = 255808 g or 255.808 kg. So, the mass of oxygen released from the tank is approximately 255.808 kg.
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how to make a number line from -6.2 to -9.1
Answer:
3.1
Step-by-step explanation:
because u have to take away the - sign if it is two negatives :3
Step-by-step explanation:
you draw a line (don't forget to put arrows on the end) then you put the point farthest to the left :(-9.1) and the point farthest to the right (-6.2).
in between these points you add the ponts -9,-8,-7-,6 respectively.
If P(A)equals one half , P(B)equals three fifths , and P(B/A) equals one sixth , find P( A/B)
Answer:
[tex]\frac{5}{36}[/tex]
Step-by-step explanation:
Given,
P(A) = [tex]\frac{1}{2}[/tex],
P(B) = [tex]\frac{3}{5}[/tex]
[tex]P(\frac{B}{A})=\frac{1}{6}[/tex]
[tex]\because P(\frac{B}{A})= \frac{P(A\cap B)}{P(A)}[/tex]
[tex]\implies \frac{P(A\cap B)}{P(A)} = \frac{1}{6}[/tex]
[tex]\frac{P(A\cap B)}{\frac{1}{2}}=\frac{1}{6}[/tex]
[tex]2P(A\cap B) = \frac{1}{6}[/tex]
[tex]\implies P(A\cap B) = \frac{1}{12}[/tex]
Now,
[tex]P(\frac{A}{B})=\frac{P(A\cap B) }{P(B)}= \frac{1/12}{3/5}=\frac{5}{36}[/tex]
A car and a truck start from rest at the same instant, with the car initially at some distance behind the truck. The truck has a constant acceleration of 2.10 m/s2, and the car has an acceleration of 3.40 m/s2. The car overtakes the truck after the truck has moved 60.0 m. (a) How much time does it take the car to overtake the truck
Answer:
Time take by car to overtake the truck is 7.6 seconds.
Step-by-step explanation:
Given : A car and a truck start from rest at the same instant, with the car initially at some distance behind the truck. The truck has a constant acceleration of 2.10 m/s², and the car has an acceleration of 3.40 m/s². The car overtakes the truck after the truck has moved 60.0 m.
To find : How much time does it take the car to overtake the truck ?
Solution :
According to question,
Taking the origin to be the truck position when it is at rest.
The car overtakes the truck after the truck has moved 60.0 m.
Using the equation to find time,
[tex]x-x_o=v_ot+\frac{1}{2}at^2[/tex]
Where, [tex]x_o=0[/tex] initial distance
[tex]v_o=0[/tex] initial velocity
a= 2.10 m/s² is the acceleration of the truck
x=60 m is the distance truck moved.
Substitute the value in the formula,
[tex]60-0=0(t)+\frac{1}{2}\times 2.10\times t^2[/tex]
[tex]60=1.05\times t^2[/tex]
[tex]t^2=\frac{60}{1.05}[/tex]
[tex]t=\sqrt{\frac{60}{1.05}}[/tex]
[tex]t=7.55[/tex]
Therefore, Time take by car to overtake the truck is 7.6 seconds.
Two sides of a triangle are 4 m and 5 m in length. Express the area A of the triangle in terms of the angle Q between these two sides.
Answer:
The area of the triangle, as a function of the angle between the two given sides, is: [tex]A(Q) = 10sin(Q)\ m^{2}[/tex]
Step-by-step explanation:
We know that the area of a triangle is given by the formula A = b*h/2, where b stands for the base and h for the height.
In our problem, we can choose anyone of them as the base. Let us choose, for example, b = 5 m. Now that we know the value of the base, we can use the value of the other side (4 m) and the angle between these two sides (Q) to calculate the height:
[tex]h = (4 m)sin(Q)[/tex]
Therefore, the are of the triangle, as a function of the angle between these two sides is:
[tex]A(Q) = b*h/2 =5*4*sin(Q)/2\ m^{2} = 10sin(Q)\ m^{2}[/tex]
Hey guys, I was having a hard time with the following question and was wondering if someone can clear it up for me.
Solve sinθ+1 = cos2θ on the interval 0 ≤ θ < 2π
The concentration of DDT (C14H9Cl5), in milligrams per liter, is:
(1) a nominal variable
(2) an ordinal variable
(3) an interval variable
(4) a ratio variable.
Answer:
The correct option is 4) a ratio variable.
Step-by-step explanation:
Consider the provided information.
Nominal variables are pertaining to names or It merely name differences, it is a qualitative variables.
Ordinal variable: It is a rank-order observations in which order matters but difference between the value doesn't matters. It is a qualitative variables.
Interval variable: It is useful if the difference between two values is meaningful. It is a quantitative variables.
Ratio variable: this variable has all the properties of an interval variable, also it has a clear definition of 0.0. It is a quantitative variables.
Now consider the provided information.
The concentration is in milligrams per liter which is a quantitative variable.
Among the provided options only ratio variable and interval variable is quantitative variable. So option A and B are incorrect.
Since the milligrams per liter can be zero point which is not the characteristic of interval scale. Thus, the option C is incorrect.
The zero point is characteristic of ratio variable. Thus, the concentration of DDT (C14H9Cl5), in milligrams per liter, is ratio variable.
Hence, the correct option is 4) a ratio variable.
Final answer:
The concentration of DDT in milligrams per liter is best described as a ratio variable, as it is measured on a numeric scale that includes a true zero, allowing for meaningful comparisons and arithmetic operations.
Explanation:
The concentration of DDT, which is a chemical compound with the formula C14H9Cl5, in a given volume of solution is a measure that can be categorized using levels of measurement in statistics. In this context, concentration is measured in milligrams per liter (mg/L), which is a unit that indicates the mass of the substance (DDT) in a specific volume of the liquid (water).
Among the four types of variables listed (nominal, ordinal, interval, and ratio), the concentration of DDT in mg/L is best described as a ratio variable. This is because it has a true zero point (0 mg/L indicates the absence of DDT), and the difference between any two concentrations has a meaningful interpretation. Additionally, you can perform a full range of arithmetic operations on ratio variables.
Nominal variables are categorical and do not have a numeric order. Ordinal variables are categorical with a clear order, whereas interval variables have a numeric scale without a true zero. However, for measurements like concentration of DDT, that have a true zero and are continuous, the appropriate level of measurement is the ratio level.