Bashir works in a weather station and has launched a weather ballon. The height of the baloon is 4 kilometers and it is 1 kilometer from the station. In kilometers, what is the approximate distance between the station and the balloon?
(a) 3.0
(b) 3.9
(c) 4.1
(d) 5.3

Final answer:

The expanded form of the algebraic expression (2x + 1)(3x - 8) is 6x² - 13x - 8.

Explanation:

To expand the algebraic expression (2x + 1)(3x - 8), we'll use the distributive property, which states that a(b + c) = ab + ac. First, we multiply 2x by each term in the second parentheses (3x and -8), and then we multiply 1 by each term in the second parentheses. Let's do this step by step:

Now, we combine these terms:

6x² - 16x + 3x - 8

Simplify by combining like terms:

6x² - 13x - 8

Therefore, the expanded form of (2x + 1)(3x - 8) is 6x² - 13x - 8.

its kinda upside down

Answer:

Option 4: [tex]\frac{8\frac{1}{2} }{\frac{5}{6} } =x[/tex]

Step-by-step explanation:

Total length of the board = [tex]8\frac{1}{2}[/tex] feet

Length of the smaller board to be cut = [tex]\frac{5}{6}[/tex] feet

So,

[tex]8\frac{1}{2} =\frac{5}{6} +\frac{5}{6} +\frac{5}{6} ....x[/tex] times.

[tex]8\frac{1}{2} =x(\frac{5}{6} )[/tex]

[tex]\frac{8\frac{1}{2} }{\frac{5}{6} } =x[/tex]

well 251 cannot go into 5 as a whole number because its way bigger than 5 so, it will be a decimal.

Your answer is

5/251 = 0.01992031872

4.

In both cases divide the number of laps by the number of minutes to find the unit rate in laps per minute.

30 laps in 12 minutes: (30 laps)/(12 minutes) = 2.5 laps/minute

120 laps in 48 minutes: (120 laps)/(48 minutes) = 2.5 laps per minute

The rates are equivalent.

6.

I can't see the dimensions of the picture.

Do this:

Do these two divisions.

Divide the width by the length of the poster and of the picture.

Poster: (60 inches)/(100 inches) = 0.6

Picture: (width of picture)/(length of picture) = ?

If the second division also equals 0.6, then the ratios are equivalent.

Answer:

The cafeteria provides three meals per day.

Reason 1

Yes, they vary directly  

As number of days increases ,Total number of meals i.e

1st day ⇒ 3

2nd day⇒6

3 rd day⇒9

4th day⇒12

......................

.........................

increases.

Total number of Meals = k×Number of days

But there is another possibility also

Reason 2

1 st day ⇒ 3

2nd day ⇒3

3rd day⇒ 3

.....................

.....................

As you can see from the above expression On each day number of meals is  

constant.

So we can say that ,

On each Day=Constant amount of meal=3

So, there is no Proportionality between Days and Meal.

[tex]7\sqrt{32}-6\sqrt{72}=7\sqrt{16\cdot2}-6\sqrt{36\cdot2}\\\\=7\cdot\sqrt{16}\cdot\sqrt2-6\cdot\sqrt{36}\cdot\sqrt2\\\\=7\cdot4\cdot\sqrt2-6\cdot6\cdot\sqrt2=28\sqrt2-36\sqrt2\\\\=-8\sqrt2[/tex]

[tex]Used:\\\\\sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}[/tex]

Jackie spent $39.15 on the dress.

The answer is actually x ≥ -3/4

Answer: 19.44 hours or 19 hours and 26 minutes.

Step-by-step explanation:

1. To lose 1 pound, a 200-person must burn 3,500 calories. Therefore, to lose 2 pounds that person must burn 7,000 calories.

2. If the person burns 180 calories by walking for 30 minutes or [tex]\frac{1}{2}[/tex] hour, to calculate the time in hours the person has to walk to lose 2 pounds, you can multiply 7,000 calories by  [tex]\frac{1}{2}[/tex] hour and divide by 180 calories:

[tex]time=\frac{(7,000Cal)(\frac{1}{2}h)}{180Cal}\\time=19.44h[/tex]

3. You have:

[tex]minutes=(0.44)(60)\\minutes=26.4min\\minutes=26min[/tex]

4. Then, you can express it as following:

19 hours and 26 minutes

To lose two pounds, a 200-pound person who burns 180 calories per 30-minute walk needs to burn 7,000 calories in total. This can be found by dividing the total amount to burn (7,000) by the amount burned per walk (180) and converting the result from minutes to hours and minutes.

To determine how much time this 200-pound person needs to walk to lose two pounds of weight, we need to first calculate the total amount of calories he or she needs to burn. Since it requires a 3,500-calorie deficit to lose one pound of weight, two pounds would require burning a total of 7,000 calories. Given that this person burns 180 calories per 30-minute walk, we can calculate the total amount of time required to burn these calories by walking. First, calculate the total walks needed by dividing the total calories to burn (7,000) by the amount of calories burned per walk (180). Then convert the result from minutes to hours and minutes.

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Note the place values:

1 : hundred

6 : tens

7 : ones

.

4 : tenths

3 : hundredths

Look at the place value for 3. It is in the hundredths value, therefore, Hundredths is your answer

~Rise Above the Ordinary

Answer: The yarn will be cut into 26 sections.

Step-by-step explanation:

Since we have given that

Length of piece of yarn = [tex]6\dfrac{1}{2}=\dfrac{13}{2}\ feet[/tex]

Length of section = [tex]\dfrac{1}{4}\ feet[/tex]

We need to find the number of sections that will be cut into:

So, the number of sections would be

[tex]\dfrac{13}{2}\div \dfrac{1}{4}\\\\=\dfrac{13}{2}\times \dfrac{4}{1}\\\\=13\times 2\\\\=26[/tex]

Hence, the yarn will be cut into 26 sections.

midpoint = (2, 4 )

using the midpoint formula

midpoint = [ [tex]\frac{1}{2}[/tex] (1 + 3 ), [tex]\frac{1}{2}[/tex] (2 + 6 )] = (2, 4)

The midpoint of the line segment with given endpoints A(1,2) and B(3,6) can be found using the formula for a midpoint, which is ((x1+x2)/2, (y1+y2)/2). Substituting the coordinates of points A and B into this formula gives us the midpoint coordinates as (2,4). So the midpoint is (2,4).

The question is asking for the midpoint of the line segment with given endpoints A(1,2) and B(3,6). We can calculate this using the formula for the midpoint of a segment, which is ((x1+x2)/2, (y1+y2)/2). In this case:

Substituting these values into the formula gives us the midpoint = ((1+3)/2, (2+6)/2) = (2,4). Therefore, the coordinates of the midpoint of the segment with the given endpoints A(1,2) and B(3,6) are (2, 4).

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Sean's height when he was 5 years old is given as follows:

39.5 inches.

The slope-intercept representation of a linear function is given by the equation shown as follows:

y = mx + b

The coefficients m and b have the meaning presented as follows:

Jose grew at an average of 2 3/4 inches per year, hence the slope is given as follows:

m = 2.75.

Thus:

J(x) = 2.75x + b.

Jose was 63 inches tall when he was 13 years old(8 years after he was 5 years old), hence the intercept b is given as follows:

63 = 2.75(8) + b

b = 63 - 2.75 x 8

b = 41 inches.

When Jose and Sean were 5 years old Jose was 1 1/2 inches taller than Sean, hence Sean's height is given as follows:

41 - 1.5 = 39.5 inches.

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Because the 6 in the hundredths place is bigger than 5( the maximum) the tenths place will automatically round up to the next following number. The answer will be 146.6

Hey, there! For this question, we can just start by plugging in the known values. [tex](f + g)(x)[/tex] can be rewritten as [tex](\frac{x}{2} - 3 + 3x^2 + x - 6)(x)[/tex].

Combine like terms: [tex](\frac{x}{2} + x - 3 - 6 + 3x^2)(x)[/tex]

If you add x to [tex]\frac{x}{2}[/tex], x will become [tex]\frac{2x}{2}[/tex], which means that x/2 + x = 3/2x.

--> [tex](\frac{3}{2}x - 9 + 3x^2)(x)[/tex]

If you rearrange this, then your answer will be option b. Hope this helps.

       f(x) = [tex]\frac{x}{2}[/tex] - 3

    + g(x) = 3x² + x - 6

f(x) + g(x) = 3x² + [tex]\frac{x}{2}[/tex] + x  -3 - 6

              = 3x² + [tex]\frac{3}{2}x[/tex] - 9

Answer: B

Steps to Solve:

1.  634 / 2 = 317

2. 317 + 66 = 383

Answer:

A = $383

Notes:

Read the question, this problem is not that hard to solve!

Let X = the large #

    Y = the small #

We have 2 unknowns, therefore we need 2 equations to solve for them:

    X + Y = 61

    X = 3Y - 7

Using the substitution method we get:

    X + Y = 61                original equation

   (3Y - 7) + Y = 61        substituting for X

    4Y - 7 = 61                combine like terms

    4Y - 7 + 7 = 61 + 7    add 7 to both sides

    4Y = 68                     simplify

    4Y/4 = 68/4               divide both sides by 4

    Y = 17                       solve for Y

    X + Y = 61                 original equation

    X + 17 = 61                replace Y with 17

    X + 17 - 17 = 61 - 17  subtract 17 from both sides

    X = 44                        solve for X

Check your answer:

       X + Y = 61          X = 3Y - 7

     44 + 17 = 61        44 = 3(17) - 7

     61 = 61  check!     44 = 51 - 7

                                 44 = 44  check!

Therefore, the larger #(X) = 44 and the smaller #(Y)= 17.

d + mq = rp

or

rp + d = mq

it took him 10 minutes to wash each car

Answer:

it is not h^48. I just took the test and its h^24!

Step-by-step explanation:

Ask if the numerator and denominator can be divided by the same number, which is called a common factor.

See if at least one number in the fraction is a prime number.

Simply just find the least common factor between the numerator and the denominator of the fraction, For example, 2/4, you know that between the two numbers, they both share the same common factor,  2, so divide 2 on the top and the bottom, and then your final  answer would be 1/2. However, if there seems to be no common factor between the numerator and the denominator for a fraction, do not simplify it any more. You cannot have a decimal as a numerator or a denominator. For example,  3/5 has no common factor so you do not have to simplify it as it is already at its most simplest form.

Hope you found this helpful:)

Y= vertical & x= horizontal

y=vertical and x=horizontal

Hope this helps ^_^

Answer:

The answer is 56.. hope I helped thanks and bye.

It would be (x^7)*(x^7)

Well, first, you must simplify each monomial and get rid of the parentheses. This can be done by adding the exponents together, as [tex]x^3[/tex] is being multiplied by [tex]4[/tex]. The same goes for [tex]x^2[/tex]. This would give you the expression: [tex]x^7*x^7[/tex]

Once again, add the two exponents together and you get your answer: [tex]x^1^4[/tex]

Answer:

y = 3x - 23

Step-by-step explanation:

y + 4 = 3(x - 9)

y + 4 = 3x - 27

y = 3x - 23

Answer:

4

Step-by-step explanation:

with th information given we can express the equation:

[tex]2x-8=\frac{x}{2} -2[/tex]

where [tex]x[/tex] is the unknown number.

to clear for [tex]x[/tex] first we multiply the equation by 2, to eliminate the fraction:

[tex]2(2x-8=\frac{x}{2}-2 )\\4x-16=x-4[/tex]

moving all terms with [tex]x[/tex] to the left:

[tex]4x-x-16=-4\\3x-16=-4[/tex]

and adding +16 to each side:

[tex]3x-16+16=-4+16\\3x=12[/tex]

and finally, dividing by 3

[tex]x=\frac{12}{4} =4[/tex]

the number is 4.

no. you many not       .....

You can use a number to compare two numbers by figuring out which one is least and which one is greater or if something is positive or negative.

Given vertices ofQuadrilateral RSTU as R(1,3), S(4,1), T(1,-3) and U(-2,-1).

We need to check if diagonals are congruent.

The coordinates of verticales diagonal RT are R(1,3) and  T(1,-3).

The coordinates of verticales diagonal SU are S(4,1), and  U(-2,-1),

By applying distance formula:

[tex]\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}[/tex]

RT = [tex]=\sqrt{\left(1-1\right)^2+\left(-3-3\right)^2}[/tex]=[tex]\sqrt{36}[/tex]

RT = 6

SU  [tex]=\sqrt{\left(-2-4\right)^2+\left(-1-1\right)^2}[/tex].

[tex]=2\sqrt{10}[/tex].

Diagonal RT is not congruent to Diagonal SU.

Therefore, Quadrilateral RSTU  is not a rectangle because the diagonals are not congruent.

So, it is False.

Final answer:

The quadrilateral RSTU is not a rectangle due to not having all right angles, making it a parallelogram.

Explanation:

The given quadrilateral RSTU is not a rectangle. To determine if it's a rectangle, we need to check if all angles are right angles, which is not the case here even if the diagonals are congruent and RS and ST are perpendicular.

Since the angles are not all right angles, the shape formed is a parallelogram. A rectangle must have all angles as right angles, so these conditions do not define a rectangle.