Refer to Explorations in Literature for a complete version of this passage.

Which quotations from “Here Is New York” develop the author’s viewpoint that commuters do not truly experience New York City?

Select each correct answer.

A "About 400,000 men and women come charging on to the Island each week-day morning, out of the mouths of tubes and tunnels."

B "Second, there is the New York of the commuter—the city that is devoured by locusts each day and spat out each night."

C "The commuter dies with tremendous mileage to his credit, but he is no rover."

D "Or they may work in a midtown office and may let a whole year swing round without sighting Governors Island from the sea wall."

Answer:

No correlation.

Step-by-step explanation:

A Scatter (XY) Plot has points that show the relationship between two variables.

Scatter plots use a collection of points placed using Cartesian coordinates to show values of two variables. By showing a variable on each axis, it can be detected if there is a relationship or correlation between the two variables.

Several types of correlation can be interpreted through the patterns shown in the scatter diagrams. These are: positive (values increase together), negative (one value decreases as the other increases), null (no correlation).

In the case presented, it can be clearly seen that the variables have no correlation, because the trend is not that the points form a straight line, but that there is too much dispersion.

So, the answer is:

No correlation.

Hope this helps!

I'm pretty sure its 1296π m³ Hope this helps!

Answer:

perfect competition

Step-by-step explanation:

because i did the test.

Answer:

2/9

Step-by-step explanation:

Answer: 60 cents

Step-by-step explanation:

The fraction of the word 'Supercalifragilisticexpialidocious' that has the letter 'i' is 7/34, which is already in its simplest form.

The word 'Supercalifragilisticexpialidocious' contains 34 letters. To find what fraction of this word has the letter 'i' in it, we first need to count how many times the letter 'i' appears. The letter 'i' appears 7 times in the word. Therefore, the fraction of the word that has the letter 'i' in it is 7/34.

It is important to note that this fraction can be simplified. However, since both 7 and 34 are prime numbers with respect to each other (they have no common factors other than 1), the fraction 7/34 is already in its simplest form.

1. The equation 5x^2+9x=4, can be rewritten as 5x^2+9x-4=0, where a=5 (the coefficient of the quadratic term), b = 9 (the coefficient of the linear term) and c = -4 (the independent term).

2. No attachment is shown.

3. To use the quadratic formula, the coefficients are: a = 2, b = -1 and c = 10. However, the discriminant, i. e., b^2 -4(a)(c) is negative, therefore, there is no real solution.  

4. You have to use the quadratic formula, with a = 4, b = 3 and c = -10, as follows:

[tex]x = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)} [/tex]

[tex]x = \frac{-3 \pm \sqrt{3^2 - 4(4)(-10)}}{2(4)} [/tex]

[tex]x = \frac{-3 \pm \sqrt{169}}{8} [/tex]

[tex]x_1 = \frac{-3 + 13}{8} [/tex]

[tex]x_1 = \frac{5}{4} [/tex]

[tex]x_2 = \frac{-3 - 13}{8} [/tex]

[tex]x_2 = -2 [/tex]

5. Rewriting the formula, so that all the terms are on one side and ordering the polynomial expression, gives: -x2-6x+27=0. Here a = -1, b = -6 and c = 27.  Using the quadratic formula gives

[tex]x = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)} [/tex]

[tex]x = \frac{6 \pm \sqrt{6^2 - 4(-1)(27)}}{2(-1)} [/tex]

[tex]x = \frac{6 \pm \sqrt{144}}{-2} [/tex]

[tex]x_1 = \frac{6 + 12}{-2} [/tex]

[tex]x_1 = -9 [/tex]

[tex]x_2 = \frac{6 - 12}{-2} [/tex]

[tex]x_2 = 3 [/tex]

6. When the second grade polynomial has all of its coefficients (a, b and c) different than zero, like this case, the best method for solving the equation is the quadratic formula  .

7. When the discriminant is greater than zero, there are two different solutions and when it is equal to zero, it has one double solution.

The discriminant for this case is 7^2 - 4(5)(-4) = 129. So, there are two different solutions .

8. Let's call  the sides of the rectangle a and b.

perimeter formula: 2a + 2b = 54 cm (eq. 1)

area formula: (a)(b) = 176 cm2 (eq. 2)

Isolating a in equation 1, gives (units are omitted):

2a + 2b = 54

2a = 54 - 2b

a = 27 - b (eq. 3)

Replacing equation 3 into equation 2, gives (units are omitted):

(a)(b) = 176

(27 - b)(b) = 176

-b^2 + 27b - 176 = 0

Using quadratic formula, we get

[tex]x = \frac{-27 \pm \sqrt{27^2 - 4(-1)(-176)}}{2(-1)} [/tex]

[tex]x = \frac{-27 \pm \sqrt{25}}{-2} [/tex]

[tex]x_1 = \frac{-27 + 5}{-2} [/tex]

[tex]x_1 = 11 [/tex]

[tex]x_2 = \frac{-27 - 5}{-2} [/tex]

[tex]x_2 = 16 [/tex]

Then, there are two possible values for b, 11 cm and 16 cm. Replacing these values into equation 3 gives:

a = 27 - 11 = 16 cm

a = 27 - 16 = 11 cm

Therefore, the two sides are 11 cm and 16 cm long, despite their names.

The square root of the given algebraic expression [tex]64y^{16}[/tex] is [tex]\bold{8y^8}[/tex]

"It is a mathematical statement which consists of numbers, variables and mathematical operations."

For given question,

We have been given an algebraic expression [tex]64y^{16}[/tex]

We need to find the square root of given algebraic expression.

[tex]\Rightarrow \sqrt{ 64y^{16}}\\\\= \sqrt{ 64\times y^{16}} \\\\=\sqrt{64} \times \sqrt{y^{16}} \\\\=8\times (y^{16})^{\frac{1}{2} }\\\\=8\times y^{\frac{16}{2} }\\\\= 8\times y^8[/tex]

Therefore, the square root of the given algebraic expression [tex]64y^{16}[/tex] is [tex]\bold{8y^8}[/tex]

Learn more about the algebraic expression here:

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The length of the rectangle whose area is (10r² − 11r − 6) and the width is (2r−3) is (5r+2).

A parallelogram in which adjacent sides are perpendicular to each other is called a rectangle. A rectangle is always a parallelogram and a quadrilateral but reverse statement may or may not be true.

Area of rectangel = Length × Width

Given that the area of a rectangle is 10r² − 11r − 6, while the width is 2r − 3. Therefore, it can be writen as,

[tex]\text{Area = Length}\times\text{Width}\\\\10r^2 - 11r - 6 = \text{Length} \times (2r - 3)\\\\\text{Length} = \dfrac{10r^2 - 11r - 6}{2r-3}\\\\\text{Length} = 5r+2[/tex]

Hence, the length of the rectangle is (5r+2).

Learn more about Rectangle:

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Answer:

Option a. [tex]\$6,455[/tex]  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have      

[tex]t=4\ years\\ A=\$7,160.06\\ r=0.026\\n=4[/tex]  

substitute in the formula above  and solve for P

[tex]7,160.06=P(1+\frac{0.026}{4})^{4*4}[/tex]  

[tex]7,160.06=P(1+\frac{0.026}{4})^{4*4}[/tex]  

[tex]P=7,160.06/1.109227=\$6,455[/tex]