Answer:
letter C
Step-by-step explanation:
She substitue the X-Intercept, (3,0), for B
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Which is the area of the rectangle?
Answer:
The answer to your question is the letter C. 13248 square units
Step-by-step explanation:
Data
Right triangle Rectangle
short leg = 69 base = x + 100
hypotenuse = 115
Process
1.- Calculate the long leg of the right triangle.
c² = a² + b²
b² = c² - a²
b² = 115² - 69²
b² = 13225 - 4761
b² = 8464
b = 92
2.- Calculate the length of the base of the rectangle
base = 92 + 100
base = 192
3.- calculate the area of the rectangle
Area = 192 x 69
= 13248 square units
On a recent administration of a state bar exam, 22% of the test takers passed the test, 78% of those who passed were first-time test takers, and 60% of those who failed were first-time test takers. What percent of first-time test takers passed the test
Answer:
Step-by-step explanation:
%17 because you take %78 of %22
(the second part is more tricky...
17% were first time takers who past.
%60 of %78 = %46.8 = percentage of people who were first time takers who failed.
so total percentage of first time takers = 46.8 +17 = %63.8.
Then 17/63.8 X %100 = percent of first time takers who passed.
=26.6 percent therefore %27 is correct.
The surface area of a spherical beach volleyball is
approximately 1387 square centimeters. Which of the
following is closest to the radius, in centimeters, of the
volleyball?
6.9
. 10.5
• 18.6
• 21.0
Answer: 18.1 inches
Step-by-step explanation: A volleyball is spherical in shape, and the surface area of a sphere is giving by the formula
from the data giving, the surface area was calculated to be 227 square inches. from the above formula, we define the radius, r to be the subject of formula, we arrive at
if we substitute for the surface area, we arrive at
Hence the radius of the volleyball will be 18.1 inches
Hope this helps
How many square yards of cement are needed to create the walkway around the rectangular pool?
A:176 square yards
B:196 square yards
C:208 square yards
D:280 square yards
The amount of cement is needed to create the walkway around the rectangular pool will be 176 square yards . Then the correct option is A.
What is Geometry?It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
The area is the combination of two rectangles of 12 by 4, and four triangles of 4 by 4, and two rectangles of 6 by 4.
Then the area will be
A = 2(12 x 4) + 4(1/2 x 4 x 4) + 2(6 x 4)
A = 96 + 32 + 48
A = 176 square yards
Then the correct option is A.
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In the lab, Leila has two solutions that contain alcohol and is mixing them with each other. Solution A is alcohol and Solution B is alcohol. She uses milliliters of Solution A. How many milliliters of Solution B does she use, if the resulting mixture is a alcohol solution?
Final answer:
The concentrations of Solution A, Solution B, and the final alcohol mixture are needed to determine how many milliliters of Solution B to mix with Solution A. Without these specifics, we provide a general approach using the method of allegations and unit conversion.
Explanation:
The student's question pertains to the mixing of two solutions with different concentrations of alcohol to achieve a specific concentration in the resulting mixture. We cannot provide a direct answer to the question as stated because the concentrations of Solution A, Solution B, and the resulting mixtures are not specified. To calculate the amount of Solution B needed, we must know the concentration (percentage by volume or molarity) of alcohol in Solution A and Solution B, as well as the desired concentration of the final mixture.
For instance, if we were given a situation where Solution A is 60% alcohol and we need to mix it with Solution B, which is 40% alcohol, to make a resulting mixture that is 50% alcohol, we could use the method of allegations to find the correct proportions. Using the formula:
Solution A concentration + Solution B concentration = Total concentration of mixture
We can then solve for the unknown by inputting the given values and applying algebraic methods to find the volume of Solution B.
Assuming we use mL for milliliters and L for liters, to accurately measure and mix the solutions, we may also need to convert units between mL and L, taking into account that there are 1,000 milliliters in 1 liter.
For a sample of 100 men, the median weight is 155 lbs., the first quartile is 150 lbs., and the third quartile is 162 lbs. Select all of the answers that create a true statement. Approximately 25 men in the sample weigh
Answer:
Refer below.
Step-by-step explanation:
True statements for Approximately 25 men in the sample weigh are:
More than 150 lbs.
More than 162 lbs.
Between 150 and 155 lbs.
Between 155 and 162 lbs.
Based on the experimental data, approximately 25 men in this sample weigh:
More than 150 lbs.More than 162 lbs.Between 150 and 155 lbs.Between 155 and 162 lbs.What is a boxplot?A boxplot simply refers to a type of chart that can be used for the graphical representation of the five-number summary of any data set, especially based on skewness, locality, and spread.
Additionally, the five-number summary of a data comprises the following:
MinimumFirst quartileMedianThird quartileMaximumIn this scenario, the true statement is that approximately 25 men in this sample would weigh:
More than 150 lbs.More than 162 lbs.Between 150 and 155 lbs.Between 155 and 162 lbs.Read more on boxplots here: https://brainly.com/question/14277132
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Examine the diagram. 2 lines intersect a horizontal line to form 3 angles. The angles are 1, 90 degrees, 2. Which statement is true about angles 1 and 2?
Answer:
answer 1
Step-by-step explanation:
Answer:A
Step-by-step explanation:
Carol has a bag containing 3 red chips, 10 blue chips, and 7 green chips. Estimate the probability (as a fraction or decimal) of Carol reaching into her bag and pulling out a green chip. *
Answer:
Step-by-step explanation:
We take all the blues and all the reds and 1 green and divide it at the total number of bages.
14/20
The probability of Carol pulling a green chip from the bag is 7 out of 20. This is calculated by dividing the number of green chips by the total number of chips.
Explanation:The subject of this question is Probability which falls under Mathematics. In this particular question, Carol has a total of 20 chips: 3 red, 10 blue, and 7 green.
Probability is calculated as 'the number of ways an event can occur' divided by 'the total number of outcomes'. Here, the event is pulling out a green chip. There are 7 green chips, and 20 total chips. So, the probability would be calculated as:
Number of green chips (Favorable outcomes) / Total chips (Total outcomes)
Which translates to: 7/20
That means, the probability of pulling out a green chip from the bag is 7 out of 20 times, if we repeat this experiment infinite times under the same conditions.
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When Mai turned 21, she invested $2000 in an individual Retirement Account that has grown at a rate of 10% compounded annually. If the account continues to grow at that rate, what will be its value when Mai turns 65?
Final answer:
When Mai turns 65, the value of her individual Retirement Account will be $61,917.28.
Explanation:
To calculate the future value of an investment with compound interest, we can use the formula:
FV = P(1+r)^n
Where FV is the future value, P is the principal amount (initial investment), r is the interest rate (as a decimal), and n is the number of compounding periods.
In this case, Mai invested $2000 and the interest rate is 10% compounded annually.
So, when Mai turns 65, the number of compounding periods would be 65 - 21 = 44 years.
Plugging in the values into the formula:
FV = $2000(1+0.10)^44 = $61,917.28
Therefore, the value of Mai's individual Retirement Account when she turns 65 will be $61,917.28.
The mean number of words per minute (WPM) read by sixth graders is 8888 with a standard deviation of 1414 WPM. If 137137 sixth graders are randomly selected, what is the probability that the sample mean would be greater than 89.8789.87 WPM? Round your answer to four decimal places.
Noticing that there is a pattern of repetition in the question (the numbers are repeated twice), we are assuming that the mean number of words per minute is 88, the standard deviation is of 14 WPM, as well as the number of sixth graders is 137, and that there is a need to estimate the probability that the sample mean would be greater than 89.87.
Answer:
"The probability that the sample mean would be greater than 89.87 WPM" is about [tex] \\ P(z>1.56) = 0.0594[/tex].
Step-by-step explanation:
This is a problem of the distribution of sample means. Roughly speaking, we have the probability distribution of samples obtained from the same population. Each sample mean is an estimation of the population mean, and we know that this distribution behaves normally for samples sizes equal or greater than 30 [tex] \\ n \geq 30[/tex]. Mathematically
[tex] \\ \overline{X} \sim N(\mu, \frac{\sigma}{\sqrt{n}})[/tex] [1]
In words, the latter distribution has a mean that equals the population mean, and a standard deviation that also equals the population standard deviation divided by the square root of the sample size.
Moreover, we know that the variable Z follows a normal standard distribution, i.e., a normal distribution that has a population mean [tex] \\ \mu = 0[/tex] and a population standard deviation [tex] \\ \sigma = 1[/tex].
[tex] \\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex] [2]
From the question, we know that
The population mean is [tex] \\ \mu = 88[/tex] WPMThe population standard deviation is [tex] \\ \sigma = 14[/tex] WPMWe also know the size of the sample for this case: [tex] \\ n = 137[/tex] sixth graders.
We need to estimate the probability that a sample mean being greater than [tex] \\ \overline{X} = 89.87[/tex] WPM in the distribution of sample means. We can use the formula [2] to find this question.
The probability that the sample mean would be greater than 89.87 WPM
[tex] \\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex] \\ Z = \frac{89.87 - 88}{\frac{14}{\sqrt{137}}}[/tex]
[tex] \\ Z = \frac{1.87}{\frac{14}{\sqrt{137}}}[/tex]
[tex] \\ Z = 1.5634 \approx 1.56[/tex]
This is a standardized value and it tells us that the sample with mean 89.87 is 1.56 standard deviations above the mean of the sampling distribution.
We can consult the probability of P(z<1.56) in any cumulative standard normal table available in Statistics books or on the Internet. Of course, this probability is the same that [tex] \\ P(\overline{X} < 89.87)[/tex]. Then
[tex] \\ P(z<1.56) = 0.94062 \approx 0.9406[/tex]
However, we are looking for P(z>1.56), which is the complement probability of the previous probability. Therefore
[tex] \\ P(z>1.56) = 1 - P(z<1.56) = 1 - 0.9406[/tex]
[tex] \\ P(z>1.56) = P(\overline{X}>89.87) = 0.0594[/tex]
Thus, "The probability that the sample mean would be greater than 89.87 WPM" is about [tex] \\ P(z>1.56) = 0.0594[/tex].
Prompt
Describe a simulation used to determine a game of darts.
Plzzzzz help???
Answer:
Anonymous simulation would be used to determine a game of darts.
The simulation which can be used to determine the game of darts is anonymous simulation.
What is Dart Game?Dart game is a game which is played in real by throwing darts over the dart boards which has to be pointed at a fixed places which gives the points.
Simulation games are the games which aims in designing the game as a context of various real life activities.
It aims in helping the real world to train, analyze and predict things in a way of entertainment.
The simulator which can be used to determine the game of darts is anonymous simulator.
Hence the description of the simulator which can be used to determine a game of darts is anonymous simulator.
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you plant 10 tulips bulbs and eight of them bloom if you plant 5 more tulips how many of those would bloom
Answer:4
Step-by-step explanation: Odd 5/4 and 10/8 are both equal
Answer:
Your answer should be 4...
Step-by-step explanation:
In the first time you planted, you planted 10 total bulbs, and 8 of them bloomed. That means that 80% of the bulbs that you planted bloomed. So if you plant 5 more bulbs, theoretically your answer should be 4, since 80% of 5 is 4.
I'm sorry if this answer isn't a lot of help, there isn't a lot of information to go off of.
If someone could answer this problem and explain how to do it that would be a HUGE help thanks-
Answer:
10 meters
Step-by-step explanation:
The triangles are similar, by a scale factor of 2, so if QR is 10, then ST is 1/2 or 5
We can use trig functions to find SP
sin P = opp/ hyp
sin 30 =5/SP
SP sin 30 =5
Divide each side by sin 30
SP = 5 / sin 30
SP =10
Answer:
C. 10 meters
Step-by-step explanation:
sin(30) = QR/QP
½ = 10/QP
QP = 20
PS = ½ × 20
PS = 10
The length of the shadow of a pole on level ground increases by 90 metres when the angle of elevation of the sun changes from 58 degrees to 36 degrees. calculate and correct to three s.f , the height of the pole
Answer:
120 m
Step-by-step explanation:
Let the length of the pole be a and the shadow be b at 58° and b+90 at 36°.
Then, as the pole and its shadow form a right triangle, we have:
a/b = tan (58°) a/(b+90) = tan (36°)As,
tan (58°) ≈ 1.6tan (36°) ≈ 0.727The equations change to:
a = 1.6ba = 0.727 (b+90)Comparing the two equations:
1.6b = 0.727b + 0.727*901.6b - 0.727b = 65.430.873b = 65.43b = 65.43/0.873b ≈ 75Then
a = 1.6b = 1.6*75 = 120 mluna had 50$ when she got to the carnival. After riding 12 rides, she had 26$ left. WHat was the price of each ride. what is the equationthat could be use to represent this situation
Answer 2 dollars a ride.
Step-by-step explanation:
26=50-12x
x=2
x
how do I subtract fractions
The sample mean foot length of a simple random sample of 25 third-graders is 22.5 cm. The standard error of the mean is 0.8 cm. Which one of the following is a correct interpretation for the standard error of the mean? A.The typical distance between each individual foot length in the sample and the sample mean foot length is approximately 0.8 cm. B.The typical distance between one sample mean foot length and another sample mean foot length is 0.8 cm. C.The typical distance between each individual foot length in the population and the true mean foot length is approximately 0.8 cm. D.The typical distance between means of samples of size 25 and the population mean foot length is approximately 0.8 cm E.The typical distance between each individual foot length in the sample and the true mean foot length is approximately 0.8 cm.
The standard error of the mean pertains to the variability of the mean between different samples, rather than the variability of individual measurements. Therefore, the correct interpretation is D. The typical distance between means of samples of size 25 and the population mean foot length is approximately 0.8 cm.
Explanation:The most accurate interpretation for the standard error of the mean in the context of the given problem is: D. "The typical distance between means of samples of size 25 and the population mean foot length is approximately 0.8 cm".
The standard error of the mean (SEM) demonstrates the standard deviation of the sampling distribution of the means. It measures how far the sample mean of the data is likely to be from the true population mean. SEM gives us an estimate of the precision of our sample mean in relation to the true population mean. It's important to recognize that SEM is not about the dispersion of individual measurements, but rather about the dispersion of sample means.
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Doing a recent trip to a zoo, The wild life club paid a total of $350 for admission for its members. Adults paid $7.50 each for admission, wow studios paid for a discount ticket cost five dollars each. Is 22 adult swim on the trip, how many students went on the trip?
Answer:
37 students
Step-by-step explanation:
Final answer:
To determine the number of students on the trip, multiply the number of adults by their ticket cost, subtract this from the total cost, and then divide the remainder by the student ticket cost to find that 37 students went on the trip.
Explanation:
The question involves a group pricing problem where the wildlife club spent $350 on zoo admission, adults tickets cost $7.50 each, and student tickets cost $5 each. If there were 22 adults on the trip, we need to calculate the number of students who attended.
To solve this, we first calculate the total cost for adult admissions by multiplying the number of adults by the cost per adult ticket: 22 adults × $7.50/adult = $165. Then, we subtract this amount from the total cost to determine the amount spent on student tickets: $350 total - $165 for adults = $185 for students.
Finally, we divide the remaining amount by the cost per student ticket to find the number of student tickets: $185 ÷ $5/student = 37 students. Therefore, 37 students went on the trip.
1. Find the measure of ZBOD. Then, classify the angle as acute, right, or obtuse.
To
Is
pompy
jagram
90 200
sajt
5700
80 70 80
70 60 500
120 130 140
50 1.60
glosslesund
20 120 110
40
30
OEI OOT OSTO
acesso
30
20
30
20
180 170 160 1
10
0
iedad
50 160 170
10
570 180
A) mZBOD = 125º; obtuse
B) mZBOD = 35°; acute
C) mZBOD = 90°; right
D) mZBOD = 160°; obtuse
Analyze this data, and match each percentage to the description it represents. Round your answers to the nearest whole number. 30% 44% 21% 8% 42% 78% the percentage of hatchbacks that run on gasoline arrowRight the percentage of diesel vehicles that are hatchbacks arrowRight the percentage of SUVs that run on gasoline arrowRight the percentage of gasoline vehicles that are sedans arrowRight the percentage of sedans that run on diesel arrowRight the percentage of gasoline vehicles that are SUVs arrowRight
Answer:
(a)The percentage of hatchbacks that run on gasoline.=78%
(b) The percentage of diesel vehicles that are hatchbacks.=21%
(c)The percentage of SUVs that run on gasoline=30%
(d)The percentage of gasoline vehicles that are sedans=42%
(e)The percentage of sedans that run on diesel =44%
(f)The percentage of gasoline vehicles that SUVs.=8%
Step-by-step explanation:
This table gives information about vehicles sold at a dealership in a month.
------------------Gasoline-------Diesel
Hatchback------18---------------5
Sedan------------15---------------12
SUV----------------3----------------7
(a)The percentage of hatchbacks that run on gasoline.
Total Number of Hatchbacks=23
Number that run on Gasoline=18
Percentage that run on gasoline=(17/23)X100=78%
(b) The percentage of diesel vehicles that are hatchbacks.
Total Number of Diesel Vehicles=5+12+7=24
Number of Diesel Hatchbacks=5
Percentage of diesel vehicles that are hatchbacks=(5÷24)X100=21%
(c)The percentage of SUVs that run on gasoline
Total Number of SUVs=10
Number of Gasoline SUVs=3
Percentage of SUVs that run on gasoline=(3÷10)X100=30%
(d)The percentage of gasoline vehicles that are sedans.
Total Number of Gasoline Vehicles=18+15+3=36
Number of Gasoline sedans=15
Percentage of Sedans that run on gasoline=(15÷36)X100=42%
(e)The percentage of sedans that run on diesel
Total Number of Sedans=15+12=27
Number of Diesel Sedans=12
Percentage of sedan that run on diesel=(12÷27)X100=44%
(f)The percentage of gasoline vehicles that SUVs.
Total Number of Gasoline Vehicles=18+15+3=36
Number of Gasoline SUVs=3
Percentage of SUVs that run on gasoline=(3÷36)X100=8%
Answer:
(a)The percentage of hatchbacks that run on gasoline.=78%
(b) The percentage of diesel vehicles that are hatchbacks.=21%
(c)The percentage of SUVs that run on gasoline=30%
(d)The percentage of gasoline vehicles that are sedans=42%
(e)The percentage of sedans that run on diesel =44%
(f)The percentage of gasoline vehicles that SUVs.=8%
Step-by-step explanation:
hope that helps
30n^3+42m^4n^8 = FIND THE GCF
Answer:
The GCF is 6n^3
Step-by-step explanation:
ANSWER PLZZZZ FAST! Read CAREFULLY FOR THE SAKE OF GOD!
Answer:
103.62
Step-by-step explanation:
[tex]C = \pi d\\3.14 * 33 =103.62[/tex]
Complete the equation describing how x and y are related
Answer:
y=6x-2
Step-by-step explanation:
Answer:
y is 6
Step-by-step explanation:
they are very similar in alot of ways but im not sure how to discribe im good at putting them onto a graph
my question is that is 22.7 degrees colder than 96.5 degrees?
Answer:
73.8 degrees because 96.5-22.7=73.8
Step-by-step explanation:
To solve the system of linear equations 8x+ 5y - 18 and 6x+y --2 by using the linear combination method, Amos decided
that he should first multiply the second equation by -5 and then add the two equations together to eliminate the y-terms.
Answer:
The answer is A.
Step-by-step explanation:
(Only if your question "Amos’s solution is (2, –14). What did he do wrong? ")
Trust me, I got it right
A polling company took before an 5 polls in the week that a mayoral 66%,56%, 55%, 60% 63% of the total votes. That candidate recieved 64 % of the total vote during the actual election. Find the percent errot in the average of the company's polling results to the nearest tenth of a percent. Show your work.
Answer:
6.7%
Step-by-step explanation:
In this question, we are to calculate the percentage error in in the average polling results calculated.
Firstly, what this means is that we calculate the average of the total votes.
That would be ; (66 + 56 + 55 + 60 + 63)/5 =
300/5 = 60%
we now proceed to calculate the percentage error in the company’s result.
Mathematically;
percentage error = (Actual value - expected value)/expected value * 100%
Here the actual value is 64% and the expected is 60%
% error = (64-60)/60 * 100 = 4/60 * 100 = 6.67%
This is 6.7% to the nearest tenth of a percent
Jiminy's Cricket Farm issued a bond with 15 years to maturity and a semiannual coupon rate of 5 percent 3 years ago. The bond currently sells for 92 percent of its face value. The company's tax rate is 22 percent. A. What is the pretax cost of debt? (Do not round intermediate calculations and enter your answer as a percent rounded to 2 decimal places, e.G., 32.16.) b. What is the aftertax cost of debt? (Do not round intermediate calculations and enter your answer as a percent rounded to 2 decimal places, e.G., 32.16.)
The pretax cost of debt is 5.43% and the aftertax cost of debt is 4.24%.
Explanation:To calculate the pretax cost of debt, we need to find the current yield of the bond. The current yield is the annual coupon payment divided by the market price. In this case, the coupon rate is 5% and the market price is 92% of the face value. Therefore, the current yield is (0.05 * face value) / (0.92 * face value), which simplifies to 0.0543 or 5.43%.
To calculate the aftertax cost of debt, we need to multiply the pretax cost of debt by (1 - tax rate). In this case, the tax rate is 22%. Therefore, the aftertax cost of debt is 5.43% * (1 - 0.22), which simplifies to 4.24%.
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x/10=−1
help ive got no idea it would be helpful if you could explain how as well please
Answer:
x = -10.
Step-by-step explanation:
x / 10 = -1
To solve the equation we isolate the x on one side.
Whatever operation we do one one side of the equation we have to do the same on the other side so that the balance is maintained.
Here to isolate x we multiply both sides by 10:
x
-- * 10 = -1 * 10
10
x = -10.
Hope this helps.
how old is gabriella if she was 11 years old 19 years ago
Answer:
30 years old now
Step-by-step explanation:
Add the years to her age then to determine her age now
11+19 = 30
She is 30 years old now
You need to compute the a 90% confidence interval for the population mean. How large a sample should you draw to ensure that the sample mean does not deviate from the population mean by more than 1.5? (Use 9.2 as an estimate of the population standard deviation from prior studies.)
Answer:
The sample size required is 102.
Step-by-step explanation:
The (1 - α)% confidence interval for population mean μ is:
[tex]CI=\bar x\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}[/tex]
The margin of error for this interval is:
[tex]MOE= z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}[/tex]
Given:
σ = 9.2
(1 - α)% = 90%
MOE = 1.5
The critical value of z for 90% confidence level is:
[tex]z_{0.10/2}=1.645[/tex]
*Use a z-table.
Compute the value of n as follows:
[tex]MOE= z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}[/tex]
[tex]n=[\frac{z_{\alpha/2}\times \sigma}{MOE}]^{2}[/tex]
[tex]=[\frac{1.645\times 9.2}{1.5}]^{2}\\=101.795\\\approx102[/tex]
Thus, the sample size required is 102.
To calculate the sample size for a 90% confidence interval with a 1.5 margin of error using a known standard deviation of 9.2, you would need a sample size of approximately 101.
90% Confidence Interval Sample Size Calculation
To determine the required sample size for a 90% confidence interval with a maximum margin of error of 1.5, and a known population standard deviation of 9.2, you can use the following formula:
n = (Z*σ/E)^2
Here, 'n' is the sample size, 'Z' is the Z-score corresponding to the desired confidence level, 'σ' is the population standard deviation, and 'E' is the maximum margin of error. For a 90% confidence level, the Z-score is approximately 1.645 (since 5% is in each tail of the normal distribution). Plugging in the values we have:
n = (1.645 * 9.2 / 1.5)^2
The calculation yields:
n = (15.074 / 1.5)^2
n = (10.049)^2
n = 101.0
Therefore, you would need a sample size of approximately 101 to ensure the sample mean does not deviate from the population mean by more than 1.5 with a 90% confidence interval.