What is the length of segment NQ?

Answer:

x= 21

Step-by-step explanation:

Could i get brainliest please? :D

Answer:

x=21

Step-by-step explanation:

143=(6x+17)

143-17=6x+17-17

126=6x

126/6=6x/6

21=x

Hope this helps :)

Answer:

to simplify this problem the answer would be 12sqrt5 - 6sqrt2 but I cannot explain it.

Step-by-step explanation:

Step-by-step explanation:

[tex]6 \sqrt{20} - 3 \sqrt{8} \\ = 6 \sqrt{4 \times 5} - 3 \sqrt{4 \times 2} \\ = 6 \times 2 \sqrt{5} - 3 \times 2 \sqrt{2} \\ = 12 \sqrt{5} - 6 \sqrt{2} \\ [/tex]

Answer:

try half a mole or  3.01 x 10^23 atoms of it.

Step-by-step explanation:

because 12g of carbon cas 1 mole so 6 would have 0.5 : )

Answer:

16 dollars and 80 cents plz give branliest

Step-by-step explanation:

Find 10 percent

14 / 10 = 1.4

double it

1.4 * 2 = 2.8

Add 2.8 to 14

to get 16.8

Answer:

if the equation y equals 1/5 x + 2 is changed to y equals 1/5 x - 4, then the graph of the line will translate 6 units downwards.

Step-by-step explanation:

Answer:

8/9

Step-by-step explanation:

Answer:

The third one is correct, the others bend the truth as they can touch but not overlap. As the third one states 'They are organized in equal intervals.'  this means they share an equal growth opportunity within their own column, their own height and nominated place within the histogram. The bars are of equal width and correspond to the equal class intervals. But on rare occasions like size classes they can be shown as a wider variant within their groups. Example would be showing a wider column say on classes at a school as the width and data being achieved forces a true event of variant sizes in education upon the base of the graph, this rarely applies to staff graphs as planning for schools is a wider data share than say offices using these types of graphs. Work development would use just data percentages along with the frequencies is one example so group size are stated in the reports to support more specific data in the graphs instead.

Step-by-step explanation:

To display numerical data that has been organized into equal intervals. The bars should touch the adjacent bars but not overlap. These intervals allow you to see the frequency distribution of the data, or how many pieces of data are in each interval.

Answer:

c

Step-by-step explanation:

Answer:

Timmy should have 2 apples

Step-by-step explanation:

Answer: 8 apples

Step-by-step explanation:

10-2=8

you have to subtract the whole by the part the get the other part that equals the whole

There are 5 faces of a given polyhedron.

A polynomial is a mathematical equation that solely uses the operations addition, subtraction, multiplication, and non-negative integer exponentiation of variables. Variables are sometimes known as indeterminate in mathematics. Majorly used polynomials are binomial and trinomial.

Euler's formula states that for a polyhedron with V vertices, E edges, and F faces,

V - E + F = 2.

In this case, we know that the polyhedron has 12 edges and 9 vertices. Let's use Euler's formula to solve for the number of faces:

9 - 12 + F = 2

F = 2 + 12 - 9

F = 5

Therefore, the polyhedron has 5 faces.

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Step-by-step explanation:

[tex]a \: \: \: \: 1 \\ \\ b \: \: \: \: 4 \\ \\ c \: \: \: \: 3 \\ \\ d \: \: \: \: 2[/tex]

Answer:

549.16

Step-by-step explanation:

83.08/pi=diameter (26.44)

26.44 / 2 = 13.22 (radius)

area=3.14*(13.22)^2

Answer:

The answer is 550

Step-by-step explanation:

83.08/pi=diameter (26.44)

26.44 / 2 = 13.22 (radius)

area=3.14*(13.22)^2

Answer:

1000 times

Step-by-step explanation:

2000/2=1000

To be sure check

2x1000=2000

To find out how many times larger 2000 is than 2, you simply divide 2000 by 2. This results in 2000 being 1000 times larger than 2.

The question wants to know how many times larger 2000 is than 2. To find this, we simply divide 2000 by 2. The reason we divide is because division allows us to see how many times one number fits into another. In this case, when we divide 2000 by 2, we get 1000. Therefore, 2000 is 1000 times larger than 2.

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Answer:

-2

Step-by-step explanation:

The value of  f(6) for the function f(x) = 1/2 x - 5 will be -2.

A certain kind of relationship called a function binds inputs to essentially one output.

A function can be regarded as a computer, which is helpful.

In other terms, a function is a relationship between variables, and the type of relationship that exists between the variables defines the function, such as y = sinx and y = x +6.

The machine will only accept specified inputs, described as the function's domain, and will potentially produce one output for each input.

Given the function

f(x) = 1/2 x - 5

value of function at x = 6

f(6) = (1/2)6 - 5

f(6) = 3 - 5 = -2

Hence, value of function f(x) at x = 6 will be -2.

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Answer:

1 6   p i   s q u a r e s   i s    m y    f i n a l    a n s w e r ! ! !   y o u r   w e l c o m e

6 × 3 = ( 10 × 5 ) - ( 16 × 2 )

Hope this helps you!

Answer:

6 x 3=(6 x 5) - (6 x 2)

Step-by-step explanation:

Answer:

Brian is correct.

Step-by-step explanation:

An accute triangle has to have every angle being less then 90 degrees or else it is a right triangle

Answer:The measure of angle C is 50°

Step-by-step explanation:

The sum of all inside angles must add up to 180°

80+50=130

130+C

C=50

130+50=180

Answer:

B and C

Step-by-step explanation:

i did on ed

Answer:

B and C

Step-by-step explanation:

Answer:

of a stretched cosine curve, trigonometric videos, worksheets, games and activities that are suitable for ... More Lessons on Finding An Equation for Sine or Cosine Graphs ... We have included a tool that with plot the sine graph f(x) = A sin(B(x-h))+ k, given the values A, B, h and k.

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

Multiply the total number of tiles by the fraction of tiles that are blue

24 *3/8

24/8 *3

3*3

9

The expression could represent the dog kennel is (x + 2)(x + 6)²

What expression could represent the dog kennel

From the question, we have the following parameters that can be used in our computation:

Volume = x³ + 14x² + 60x + 72

Height = x + 2

Dividing the Volume by the Height , we have

            x² + 12x+ 36

x + 2  |  x³ + 14x² + 60x + 72

            x³ + 2x²

--------------------------------------------------------

                       12x² + 60x + 72

                       12x² + 24x

--------------------------------------------------------

                       36x + 72

                       36x + 72

--------------------------------------------------------

                                  0

So, we have

x³ + 14x² + 60x + 72 = (x + 2)(x² + 12x+ 36)

Expand

x³ + 14x² + 60x + 72 = (x + 2)(x + 6)²

Hence, the expression could represent the dog kennel is (x + 2)(x + 6)²

Answer:

ship one.

Step-by-step explanation:

you are using Pythagoras

Answer: I asked this question as well, and got "ship one is closer to the coast guard" however I still need work to support that answer. Is it right?

Answer:

$3.84

Step-by-step explanation

move the decimal back two place - .28, it is a mark up so add a 1 at the beginning - 1.28 - multiply - 3 x 1.28 = 3.84

After Angela and David eat their portions, there is [tex]\( \frac{1}{4} \)[/tex] of the chocolate cake, [tex]\( \frac{3}{8} \)[/tex] of the vanilla cake, and [tex]\( \frac{1}{4} \)[/tex] of the strawberry cake left.

To compare how much cake Angela and David eat, let's calculate the total fraction of each cake consumed by each person:

For Angela:

- Chocolate cake: [tex]\( \frac{4}{8} = \frac{1}{2} \)[/tex]

- Vanilla cake: [tex]\( \frac{2}{8} = \frac{1}{4} \)[/tex]

- Strawberry cake: [tex]\( \frac{2}{4} = \frac{1}{2} \)[/tex]

Total cake eaten by Angela: [tex]\( \frac{1}{2} + \frac{1}{4} + \frac{1}{2} = \frac{5}{4} \)[/tex]

For David:

- Chocolate cake: [tex]\( \frac{1}{4} \)[/tex]

- Vanilla cake: [tex]\( \frac{3}{8} \)[/tex]

- Strawberry cake: [tex]\( \frac{1}{2} \)[/tex]

Total cake eaten by David: [tex]\( \frac{1}{4} + \frac{3}{8} + \frac{1}{2} = \frac{13}{8} \)[/tex]

Since [tex]\( \frac{13}{8} > \frac{5}{4} \),[/tex] David eats more cake than Angela.

To find out how much more cake David eats:

- David eats [tex]\( \frac{13}{8} - \frac{5}{4} = \frac{13}{8} - \frac{10}{8} = \frac{3}{8} \)[/tex]  more cake.

To calculate how much of each cake is left:

- Chocolate cake: [tex]\( 1 - \frac{4}{8} - \frac{1}{4} = \frac{1}{4} \)[/tex]

- Vanilla cake: [tex]\( 1 - \frac{2}{8} - \frac{3}{8} = \frac{3}{8} \)[/tex]

- Strawberry cake: [tex]\( 1 - \frac{2}{4} - \frac{1}{2} = \frac{1}{4} \)[/tex]

So, after Angela and David eat their portions, there is [tex]\( \frac{1}{4} \)[/tex] of the chocolate cake, [tex]\( \frac{3}{8} \)[/tex] of the vanilla cake, and [tex]\( \frac{1}{4} \)[/tex] of the strawberry cake left.

The volume of a cylinder with a base diameter of 8ft and height of 20ft is approximately 1005.3 cubic feet.

The volume of a cylinder can be calculated using the formula Volume = πr²h where π represents approximately the number 3.14, 'r' signifies the radius of the cylinder, and 'h' denotes the height of the cylinder.

In this case, the diameter of the cylinder is given as 8 feet, so the radius will be half of that which is 4 feet. The height is specified as 20 feet.

Substitute these values into the equation:

Volume = π * (4 ft)² * 20 ft

This simplifies to:

Volume = 3.14 * 16ft² * 20ft

By multiplying these values, we get the volume equals the product of these numbers:

Volume ≈ 1005.3 cubic ft. Hence, the volume of this cylinder to the nearest tenths is 1005.3 cubic feet.

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The volume of a cylinder with an 8ft diameter and 20ft height is approximately 1005.3 cubic feet, rounded to the nearest tenths place.

To calculate the volume of a cylinder, we use the formula V = πr²h, where V represents the volume, r is the radius of the cylinder's base, and h is the height of the cylinder. Given that the diameter of the cylinder is 8ft, the radius is half of the diameter, which is 4ft. Now, using the formula:

V = πr²h

V = π(4ft)² × 20ft

V = π16ft² × 20ft

V = π 320ft³

V = 1005.31ft³

Therefore, the volume of the cylinder is approximately 1005.3 cubic feet, rounded to the nearest tenths place.

Answer:

s²/2

Step-by-step explanation:

Area of square = 2 triangles

Find the area of the square using s²

For area of the triangle, divide by 2

The area of Jens square and the area of the triangle is A = ( 1/2 )s²

A triangle is a plane figure or polygon with three sides and three angles.

A Triangle has three vertices and the sum of the interior angles add up to 180°

Let the Triangle be ΔABC , such that

∠A + ∠B + ∠C = 180°

The area of the triangle = ( 1/2 ) x Length x Base

For a right angle triangle

From the Pythagoras Theorem , The hypotenuse² = base² + height²

if a² + b² = c² , it is a right triangle

if a² + b² < c² , it is an obtuse triangle

if a² + b² > c² , it is an acute triangle

Given data ,

Let the triangle be represented as ΔABC

Now , the measure of sides of the triangle are

AB = AC = s

From the figure , we can see that

Now , area of the triangle = ( 1/2 ) x Length x Base

On simplifying , we get

A = ( 1/2 )s²

Hence , the area of the triangle is A = ( 1/2 )s²

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Answer: the answers is y=h(x) and y=k(x)

Step-by-step explanation: on edge

A circle is a special form of an ellipse, occurring when both focal points of an ellipse coincide at one point, making its eccentricity zero.

A special form of the ellipse is called a circle. This occurs when the two focal points of an ellipse coincide at a single point, which is also the center of the circle. In mathematical terms, an ellipse whose equation is scaled down in one direction, transforming it into x² + y² = a², represents a circle with center at the origin and radius a.

Kepler's first law regarding planetary orbits also refers to this special case of an ellipse. It states that planets follow an elliptical path with the Sun at one of its focal points. When both focal points are at the same location, indicative of zero eccentricity, the orbit is not elliptical but circular.

The properties of an ellipse are crucial in understanding celestial mechanics and orbits, reflecting the significance of this special case in both mathematics and astronomy.