Which expression is equivalent to 6x2– 19x – 55?

Answers

Answer 1
(6x+11)(x-5) when it’s factored and completed i hope this helps you !
Answer 2

Answer:

( 6x + 11 ) ( x - 5 )

Step-by-step explanation:

Let

6x2 - 19x - 55 = 0

6x2 - (30-11)x - 55 = 0

6x2 - 30x + 11x - 55 = 0

6x ( x - 5 ) + 11 ( x - 5 ) = 0

( 6x + 11 ) ( x - 5 ) = 0

Therefore, ( 6x + 11 ) ( x - 5 ) = 6x2 - 19x - 55


Related Questions

Write 1.47 as a mixed number or a fraction In simplest form

Answers

Answer:

[tex]\frac{147}{100}[/tex]

Step-by-step explanation:

This is the answer because 147 ÷ 100 = 1.47

What is the solution to the system of equations graphed below?
- 3x+2
y = 5x + 28

Answers

Answer:

(-3.25, 11.75)

Step-by-step explanation:

We only need two points to plot the graph of each equation.

[tex]y=-3x+2\\\\for\ x=0\to y=-3(0)+2=0+2=2\to(0,\ 2)\\for\ x=1\to y=-3(1)+3=-3+2=-1\to(1,\ -1)\\\\y=5x+28\\\\for\ x=-4\to y=5(-4)+28=-20+28=8\to(-4,\ 8)\\for\ x=-6\to y=5(-6)+28=-30+28=-2\to(-6,\ -2)[/tex]

Look at the picture.

Read the coordinates of the intersection of the line (solution).

The equation of a circle in general form is ​ x2+y2+20x+12y+15=0 ​ . What is the equation of the circle in standard form?

Answers

ANSWER

[tex]{(x + 10)}^{2} + {(y + 6)}^{2} = 121[/tex]

EXPLANATION

The equation of the circle in general form is given as:

[tex] {x}^{2} + {y}^{2} + 20x + 12y + 15 = 0[/tex]

To obtain the standard form, we need to complete the squares.

We rearrange the terms to obtain:

[tex] {x}^{2} + 20x + {y}^{2} + 12y = - 15 [/tex]

Add the square of half the coefficient of the linear terms to both sides to get:

[tex]{x}^{2} + 20x +100 + {y}^{2} + 12y + 36 = - 15 + 100 + 36[/tex]

Factor the perfect square trinomial and simplify the RHS.

[tex]{(x + 10)}^{2} + {(y + 6)}^{2} = 121[/tex]

This is the equation of the circle in standard form.

Latesha’s mother puts $85 in Latesha’s lunch account at school. Each day Latesha uses $3 from her account for lunch. The table below represents this situation. Latesha’s Lunch Account Day Amount Left in Account ($) 0 $85 1 2 3 4 5 How much is left in Latesha’s lunch account after she has had lunch for 5 days?

A.$15
B.$67
C.$70
D.82

Answers

The answer is C. (70).
The easiest way to explain this is to use a table. You could you other methods like by using a proportion but this way is easier.

Answer:

=70$

Step-by-step explanation:

The total in her account at day zero =85$

Lunch for five days= 3$×5

=15$

Total in her account= Initial amount - Expenditure on lunch

=85$-15$

=70$

The balance in Latesha's Lunch Account after having lunch for five day=70$

Find the area of quadrilateral ABCD. [Hint: the diagonal divides the quadrilateral into two triangles.]
A. 26.47 units²
B. 28.53 units²
C. 27.28 units²
D. 33.08 units²

Answers

Answer:

B) 28.53 unit²

Step-by-step explanation:

The diagonal AD divides the quadrilateral in two triangles:

Triangle ABDTriangle ACD

Area of Quadrilateral will be equal to the sum of Areas of both triangles.

i.e.

Area of ABCD = Area of ABD + Area of ACD

Area of Triangle ABD:

Area of a triangle is given as:

[tex]Area = \frac{1}{2} \times base \times height[/tex]

Base = AB = 2.89

Height = AD = 8.6

Using these values, we get:

[tex]Area = \frac{1}{2} \times 2.89 \times 8.6 = 12.43[/tex]

Thus, Area of Triangle ABD is 12.43 square units

Area of Triangle ACD:

Base = AC = 4.3

Height = CD = 7.58

Using the values in formula of area, we get:

[tex]Area = \frac{1}{2} \times 4.3 \times 7.58 = 16.30[/tex]

Thus, Area of Triangle ACD is 16.30 square units

Area of Quadrilateral ABCD:

The Area of the quadrilateral will be = 12.43 + 16.30 = 28.73 units²

None of the option gives the exact answer, however, option B gives the closest most answer. So I'll go with option B) 28.53 unit²

the number of three-digit numbers with distinct digits that be formed using the digits 1,2,3,5,8 and 9 is . The probability that both the first digit and the last digit of the three-digit number are even numbers .

Answers

Answer:

a)120

b)6.67%

Step-by-step explanation:

Given:

No. of digits given= 6

Digits given= 1,2,3,5,8,9

Number to be formed should be 3-digits, as we have to choose 3 digits from given 6-digits so the no. of combinations will be

6P3= 6!/3!

      = 6*5*4*3*2*1/3*2*1

      =6*5*4

      =120

Now finding the probability that both the first digit and the last digit of the three-digit number are even numbers:

As the first and last digits can only be even

then the form of number can be

a)2n8 or

b)8n2

where n can be 1,3,5 or 9

4*2=8

so there can be 8 three-digit numbers with both the first digit and the last digit even numbers

And probability = 8/120

                          = 0.0667

                          =6.67%

The probability that both the first digit and the last digit of the three-digit number are even numbers is 6.67% !

1.

[tex]6\cdot5\cdot4=120[/tex]

2.

[tex]|\Omega|=120\\|A|=2\cdot4\cdot1=8\\\\P(A)=\dfrac{8}{120}=\dfrac{1}{15}\approx6.7\%[/tex]

Use the intercepts from the graph below to determine the equation of the function.

A) 4x-3y=12
B) -4x-3y=12
C) 4x-3y=-12
D) -4x+3y=-12

Answers

ANSWER

C) 4x-3y=-12

EXPLANATION

The intercept form of a straight line is given by:

[tex] \frac{x}{x - intercept} + \frac{y}{y - intercept} = 1[/tex]

From the the x-intercept is -3 and the y-intercept is 4.

This is because each box is one unit each.

We substitute the intercepts to get:

[tex] \frac{x}{ - 3} + \frac{y}{4} = 1[/tex]

We now multiply through by -12 to get

[tex] - 12 \times \frac{x}{ - 3} + - 12 \times \frac{y}{4} = 1 \times - 12[/tex]

[tex]4x - 3y = -12[/tex]

The correct choice is C.

Bianca has a stamp collection of 5 cent stamps and 7 cent stamps. She has 3 less 7 cent stamps as 5 cent stamps. If the collection has a face value of 87 cents, how many of each does she have?

She has ____ 5 cent stamps and ____ 7 cent stamps.

Answers

Answer:

She has 9 5 cent stamps and 6 7 cent stamps.

Step-by-step explanation:

Let the number of five cent stamps be represented by F and the number of seven cent stamps be represented by S.

The difference between the number of five cent and seven cent stamps is 3

F-S=3

The sum of the collection from each type of stamp is 87 cents

5F+7S=87

Let us solve the equations simultaneously.

F-S=3

5F+7S=87

Using substitution method,

F= 3+S

5(3+S)+7S=87

15+5S+7S=87

12S=87-15

12S=72

S=6

F=3+S

=3+6=9

Therefore the number of five cent stamps is 9 and seven cent stamps is 6.

Answer:

Number of 5 cent stamps = 9

Number of 7 cent stamps = 6

Step-by-step explanation:

We are given that Bianca has a stamp collection of 5 cent stamps and 7 cent stamps in which there are 3 less 7 cent stamps as 5 cent stamps.

If the total face value of stamps is 87 cents, we are to find the number of stamps of each value.

Assuming [tex]t[/tex] to be the number of 5 cent stamps and [tex]s[/tex] to be the 7 cent stamps so we can write it as:

[tex]0.05t+0.07s=0.87[/tex] --- (1)

[tex]s=t-3[/tex] --- (2)

Substituting this value of [tex]s[/tex] from (2) in (1):

[tex]0.05t+0.07(t-3)=0.87[/tex]

[tex]0.05s+0.07t-0.21=0.87[/tex]

[tex]0.12t=1.08[/tex]

[tex]t=9[/tex]

Number of 5 cent stamps = 9

Number of 7 cent stamps = 9 - 3 = 6

Solve for x: 5 over x equals 4 over quantity x plus 3

5
3
−3
−15

Answers

Answer:

x = - 15

Step-by-step explanation:

The equation is  [tex]\frac{5}{x}=\frac{4}{x+3}[/tex]

We now cross mulitply and do algebra to figure the value of x (shown below):

[tex]\frac{5}{x}=\frac{4}{x+3}\\5(x+3)=4(x)\\5x+15=4x\\5x-4x=-15\\x=-15[/tex]

Hence x = -15

Answer:

D

Step-by-step explanation:

one x-intercept for a parabola is at the point (2, 0). use the quadratic formula to find the other x-intercept for the parabola defined by y=x^2-3x+2​

Answers

Answer:

Step-by-step explanation:

There are 3 ways to find the other x intercept.

1) Polynomial Long Division.

Divide x^2 - 3x + 2 by the binomial x - 2, because by the Factor Theorem if a is a root of a polynomial then x - a is a factor of said polynomial.

2) Just solving for x when y = 0, by using the quadratic formula.

[tex]x^2 - 3x + 2 = 0\\x_{12} = \frac{3 \pm \sqrt{9 - 4(1)(2)}}{2} = \frac{3 \pm 1}{2} = 2, 1[/tex].

So the other x - intercept is at (1, 0)

3) Using Vietta's Theorem regarding the solutions of a quadratic

Namely, the sum of the solutions of a quadratic equation is equal to the quotient between the negative coefficient of the linear term divided by the coefficient of the quadratic term.

[tex]x_1 + x_2 = \frac{-b}{a}[/tex]

And the product between the solutions of a quadratic equation is just the quotient between the constant term and the coefficient of the quadratic term.

[tex]x_1 \cdot x_2 = \frac{c}{a}[/tex]

These relations between the solutions give us a brief idea of what the solutions should be like.

square root of 3 x^2 times square root of 4x

Answers

[tex]\bf \sqrt{3x^2}\cdot \sqrt{4x}\implies \sqrt{3x^2\cdot 4x}\implies \sqrt{12x^2x}\implies \sqrt{4\cdot 3\cdot x^2x} \\\\\\ \sqrt{2^2\cdot 3\cdot x^2x}\implies 2x\sqrt{3x}[/tex]

Need help with this problem h+-3=4 please

Answers

Answer:

h=7

Step-by-step explanation:

[tex]h+(-3)=4[/tex]

may be rewritten as

[tex]h-3=4[/tex]

as adding a negative is the same as subtracting a positive.

To solve, add 3 to both sides.

[tex]h-3=4\\h=7[/tex]

Answer:

h=7

Step-by-step explanation:

1) Add three to both sides

2) You should get h=7

15.5
tons

155 tons =how many
pounds

Answers

15.5 tons=31000
155 tons=310000
(Plz
Mark brainliest)

A jet plane travels 2 times the speed of a commercial airplane. The distance between Vancouver

and Regina is 1730 km. If the flight from Vancouver to Regina on a commercial airplane takes

140 minutes longer than a jet plane, what is the time of a commercial plane ride of this route? (please show steps:))

Answers

Answer:

The time of a commercial airplane is 280 minutes

Step-by-step explanation:

Let

x -----> the speed of a commercial airplane

y ----> the speed of a jet plane

t -----> the time that a jet airplane takes  from Vancouver to Regina

we know that

The speed is equal to divide the distance by the time

y=2x ----> equation A

The speed of a commercial airplane is equal to

x=1,730/(t+140) ----> equation B

The speed of a jet airplane is equal to

y=1,730/t -----> equation C

substitute equation B and equation C in equation A

1,730/t=2(1,730/(t+140))

Solve for t

1/t=(2/(t+140))

t+140=2t

2t-t=140

t=140 minutes

The time of a commercial airplane is

t+140=140+140=280 minutes

Tom has 8 toys each toy weighs either 20 grams or 40 grams or 50 grams he has a diffrent number of toys (at least one) of each weight What is the smallest possible total weight of Tom's toys​

Answers

Answer:

110

Step-by-step explanation:

He said he had atleast 1 of each. Hope it helps.

Answer:

The smallest possible total weight of Tom's toys​ is:

                          210 grams

Step-by-step explanation:

It is given that:

Tom has 8 toys each toy weighs either 20 grams or 40 grams or 50 grams.

Also, he  has a different number of toys (at least one) of each weight.

Now, the smallest possible weight of Tom's toy is such that:

He has one toy of 50 grams , one of 40 grams and the other's are of smallest weight i.e. 20 grams.

This means he has 6 toys of 20 grams.

One of 40 grams.

One of 50 grams.

Hence,

Total weight= 20×6+40+50

i.e.

Total weight= 120+90

i.e.

Total weight= 210 grams.

Find the reciprocal of the expression.
The quantity 10 multiplied by b end of quantity divided by the quantity 2 multiplied by b plus 8 end of quantity.

A. Negative the quantity of the quantity 10 multiplied by b end of quantity divided by the quantity 2 multiplied by b plus 8 end of quantity end of quantity.

B. The quantity 2 multiplied by b plus 8 end of quantity divided by the quantity 10 multiplied by b end of quantity.

C. The quantity 10 multiplied by b plus 8 end of quantity divided by the quantity 2 multiplied by b end of quantity.

D. Negative the quantity of the quantity 2 multiplied by b plus 8 end of quantity divided by the quantity 10 multiplied by b end of quantity end of quantity.


Answers

Answer:

Option B

Step-by-step explanation:

we know that

To find the reciprocal of a fraction, flip the fraction.

Remember that

A number multiplied by its reciprocal is equal to 1

In this problem we have

[tex]\frac{10b}{2b+8}[/tex]

Flip the fraction

[tex]\frac{2b+8}{10b}[/tex] -----> reciprocal

therefore

The reciprocal is

The quantity 2 multiplied by b plus 8 end of quantity divided by the quantity 10 multiplied by b end of quantity.

What is the sum of the complex numbers below?
(5+7i)+(-2+6i)
A. -3 +13i
B. 3+13i
C. -3-13i
D. 3-13i​

Answers

Answer:

B

Step-by-step explanation:

Given

(5 + 7i) + (- 2 + 6i ) ← remove parenthesis and collect like terms

= 5 + 7i - 2 + 6i

= 3 + 13i → B

The sum of the complex number is 3 + 13i.

Option B is the correct answer.

We have,

To find the sum of the complex numbers (5+7i) and (-2+6i), you can simply add the real parts together and add the imaginary parts together separately.

Real part: 5 + (-2) = 3

Imaginary part: 7i + 6i = 13i

Combining the real and imaginary parts, we get:

Sum = 3 + 13i

Therefore,

The sum of the complex number is 3 + 13i.

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how to divide (x^2+5x-6)/(x-1)

Answers

Answer:

x+6

Step-by-step explanation:

Let's see if the numerator is factorable.

Since the coefficient of x^2 is 1 (a=1), all you have to do is find two numbers that multiply to be -6  (c) and add up to be 5 (b).

Those numbers are 6 and -1.

So the factored form of the numerator is (x+6)(x-1)

So when you divide (x+6)(x-1) by (x-1) you get (x+6) because (x-1)/(x-1)=1 for number x except x=1 (since that would lead to division by 0).

Anyways, this is what I'm saying:

[tex]\frac{(x+6)(x-1)}{(x-1)}=\frac{(x+6)\xout{(x-1)}}{\xout{(x-1)}}[/tex]

[tex]x+6[/tex]

Determine the scale factor of 5 to 10

Answers

there's a scale factor of two!

five times two is ten.

hope this helps! :) xx

A football coach is trying to decide: when a team ahead late in the game, which strategy is better?

Answers

Answer:

regular

Step-by-step explanation:

1. look at table

notice regular and prevent defense have different wins but same total. 2. wins have more for regular so that's your answer

Answer:

The correct option is A)

P(Win|Regular)=0.76

P(Win|Prevent )=0.58

You are more likely to win by playing regular defense.

Step-by-step explanation:

Consider the provided table.

We need to find which strategy is better.

If team play regular defense then they win 38 matches out of 50.

[tex]Probability=\frac{\text{Favorable outcomes}}{\text{Total number of outcomes}}[/tex]

[tex]P(Win|Regular)=\frac{38}{50}[/tex]

[tex]P(Win|Regular)=0.76[/tex]

If team play prevent defense then they win 29 matches out of 50.

Thus, the probability of win is:

[tex]P(Win|Prevent )=\frac{29}{50}[/tex]

[tex]P(Win|Prevent )=0.58[/tex]

Since, 0.76 is greater than 0.58

That means the probability of winning the game by playing regular defense is more as compare to playing prevent defense.

Hence, the conclusion is: You are more likely to win by playing regular defense.

Thus, the correct option is A)

P(Win|Regular)=0.76

P(Win|Prevent )=0.58

You are more likely to win by playing regular defense.

What is the slope of st.line xcosa+ysina=p? ( Find by using derivative)​

Answers

Answer:

Assume that [tex]a[/tex] and [tex]p[/tex] are constants. The slope of the line will be equal to

[tex]\displaystyle -\frac{\cos{(a)}}{\sin{(a)}} = \cot{(a)}[/tex] if [tex]\sin{a} \ne 0[/tex];Infinity if [tex]\sin{a} = 0[/tex].

Step-by-step explanation:

Rewrite the expression of the line to express [tex]y[/tex] in terms of [tex]x[/tex] and the constants.

Substract [tex]x\cdot \cos{(a)}[/tex] from both sides of the equation:

[tex]y \sin{(a)} = p - x\cos{(a)}[/tex].

In case [tex]\sin{a} \ne 0[/tex], divide both sides with [tex]\sin{a}[/tex]:

[tex]\displaystyle y = - \frac{\cos{(a)}}{\sin{(a)}}\cdot x+ \frac{p}{\sin{(a)}}[/tex].

Take the first derivative of both sides with respect to [tex]x[/tex]. [tex]\frac{p}{\sin{(a)}}[/tex] is a constant, so its first derivative will be zero.

[tex]\displaystyle \frac{dy}{dx} = - \frac{\cos{(a)}}{\sin{(a)}}[/tex].

[tex]\displaystyle \frac{dy}{dx}[/tex] is the slope of this line. The slope of this line is therefore

[tex]\displaystyle - \frac{\cos{(a)}}{\sin{(a)}} = -\cot{(a)}[/tex].

In case [tex]\sin{a} = 0[/tex], the equation of this line becomes:

[tex]y \sin{(a)} = p - x\cos{(a)}[/tex].

[tex]x\cos{(a)} = p[/tex].

[tex]\displaystyle x = \frac{p}{\cos{(a)}}[/tex],

which is the equation of a vertical line that goes through the point [tex]\displaystyle \left(0, \frac{p}{\cos{(a)}}\right)[/tex]. The slope of this line will be infinity.

Find the values of k for which the quadratic equation 2x^2 − (k + 2)x + k = 0 has real and equal roots.

Answers

Answer:

k = 2

Step-by-step explanation:

If the roots are real and equal then the condition for the discriminant is

b² - 4ac = 0

For 2x² - (k + 2)x + k = 0 ← in standard form

with a = 2, b = - (k + 2) and c = k, then

(- (k + 2))² - (4 × 2 × k ) = 0

k² + 4k + 4 - 8k = 0

k² - 4k + 4 = 0

(k - 2)² = 0

Equate factor to zero and solve for k

(k - 2)² = 0 ⇒ k - 2 = 0 ⇒ k = 2

Answer:

k = 2

Step-by-step explanation:

A quadratic equation has two equal real roots if a discriminant is equal 0.

[tex]ax^2+bx+c=0[/tex]

Discriminant [tex]b^2-4ac[/tex]

We have the equation

[tex]2x^2-(k+2)x+k=0\to a=2,\ b=-(k+2),\ c=k[/tex]

Substitute:

[tex]b^2-4ac=\bigg(-(k+2)\bigg)^2-4(2)(k)\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\=k^2+2(k)(2)+2^2-8k=k^2+4k+4-8k=k^2-4k+4\\\\b^2-4ac=0\iff k^2-4k+4=0\\\\k^2-2k-2k+4=0\\\\k(k-2)-2(k-2)=0\\\\(k-2)(k-2)=0\\\\(k-2)^2=0\iff k-2=0\qquad\text{add 2 to both sides}\\\\k=2[/tex]


Given the function f(x) = 2x – 1 and the linear function g(x), which function has a greater value when x = 3?

A.f(x) is greater.
B.g(x) is greater.
C.f(x) and g(x) are the same when x=3
D.g(x) is undefined when x=3​

Answers

Answer:

Option B. g(x) is greater

Step-by-step explanation:

step 1

Find the value of f(x) when the value of x is equal to 3

we have

f(x)=2x-1

substitute the value of x=3

f(3)=2(3)-1=5

step 2

Find the value of g(x) when the value of x is equal to 3

Observing the graph

when x=3

g(3)=7

step 3

Compare the values

f(x)=5

g(x)=7

so

g(x) > f(x)

g(x) is greater

Answer:

Correct option is:

B. g(x) is greater

Step-by-step explanation:

Firstly, we find the value of f(x) when x=3

f(x)=2x-1

substitute the value of x=3

f(3)=2×3-1=5

On observing the graph, we see that g(x)=7 when x=3

Now, on Comparing the values of f(x) and g(x) when x=3

f(3)=5

g(3)=7

so, g(x) > f(x) when x=3

So, Correct option is:

B. g(x) is greater

write a compound inequality that represents each situations all real numbers that are greater than -8 but less than 8

Answers

Answer:

[tex]-8 < x < 8[/tex]

Step-by-step explanation:

Your compound inequality will include two inequalities.

These are:

x > -8

x < 8

Put your lowest number first, ensuring that your sign is pointed in the correct direction.

[tex]-8 < x[/tex]

Next, enter your higher number, again making sure that your sign is pointing in the correct direction.

[tex]-8 < x < 8[/tex]

Answer:

-8 < r < 8

Step-by-step explanation:

Let r = real number

Greater than  >

r>-8

less than  <

r <8

We want a compound inequality so we combine these

-8 < r < 8

What type of angles are 1 and 5?



vertical
supplementary
corresponding
complementary

Answers

Answer:

corresponding

Step-by-step explanation:

Answer:

Corresponding

Step-by-step explanation:

I like to call corresponding angles, the copy and paste angles because you can copy and paste the top intersection over the bottom intersection; the angles that lay down on top of each other are the corresponding angles. 1 and 5 do this.

PLEASE HURRY
WILL GIVE BRAINLIEST

What is the equation for the hyperbola shown?

Answers

Find the answer in the attachment.

The hyperbola's equation is x² / 3600 - y² / 121 = 1, centered at the origin (0,0). Its vertices are at (60,0), (-60,0) on the x-axis, and (0,11), (0,-11) on the y-axis.

To find the equation of the hyperbola, we need to determine its center and the distances from the center to the vertices along the x and y axes. The general equation of a hyperbola centered at (h, k) is given by:

(x - h)² / a² - (y - k)² / b² = 1

Where (h, k) is the center of the hyperbola, and 'a' and 'b' are the distances from the center to the vertices along the x and y axes, respectively.

In this case, since the hyperbola is symmetric along the x and y axes, the center is at the origin (0, 0). Also, we know the distance from the center to the vertices along the x-axis is 60 units (60 and -60) and along the y-axis is 11 units (11 and -11).

So, a = 60 and b = 11.

Now we can plug these values into the equation:

x² / (60)² - y² / (11)² = 1

Simplifying further:

x² / 3600 - y² / 121 = 1

And that's the equation of the hyperbola.

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how much is 2 plus 9​

Answers

For this case we must represent the following expression algebraically, in addition to indicating its result:

"2 plus 9"

So, we have:

[tex]2 + 9 =[/tex]

By law of the signs of the sum, we have that equal signs are added and the same sign is placed:

[tex]2 + 9 = 11[/tex]

ANswer:

11

if you are paid $5.50/hour for mowing yards, and you take 3 1/3 hours to mow a yard, how much money are you owed?

Answers

[tex]\bf \begin{array}{ccll} \$&hour\\ \cline{1-2} 5.5&1\\ x&3\frac{1}{3} \end{array}\implies \cfrac{5.5}{x}=\cfrac{1}{3\frac{1}{3}}\implies \cfrac{5.5}{x}=\cfrac{1}{\frac{3\cdot 3+1}{3}}\implies \cfrac{5.5}{x}=\cfrac{1}{\frac{10}{3}}\implies \cfrac{5.5}{x}=\cfrac{\frac{1}{1}}{\frac{10}{3}} \\\\\\ \cfrac{5.5}{x}=\cfrac{1}{1}\cdot \cfrac{3}{10}\implies \cfrac{5.5}{x}=\cfrac{3}{10}\implies 55=3x\implies \stackrel{\textit{about 18 bucks and 33 cents}}{\cfrac{55}{3}=x\implies 18\frac{1}{3}=x}[/tex]

Answer:

$18.3

Step-by-step explanation:

If you are paid $5.50/hour for mowing yards, and you take 3 1/3 hours to mow a yard, you should earn $18.3.

3 1/3 hours

$5.50 and hour

$5.50 x 3 = $16.5

$5.50 / 3 = $1.8

$16.5 + $1.8 = $18.3

Therefore, you are owed $18.3.

PLEASE HELP!!! Given the functions, f(x) = 6x + 2 and g(x) = x - 7, perform the indicated operation. When applicable, state the domain restriction. (f/g)(x)

Answers

Final answer:

To find (f/g)(x) with f(x) = 6x + 2 and g(x) = x - 7, one must divide f(x) by g(x). The domain restriction occurs because division by zero is not defined, so we exclude the x value that makes g(x) zero, which is x = 7.

Explanation:

To perform the indicated operation (f/g)(x) with the given functions f(x) = 6x + 2 and g(x) = x - 7, we need to divide the function f(x) by the function g(x). This operation is equivalent to finding the quotient of the two functions, which is expressed as:

(f/g)(x) = f(x)/g(x) = (6x + 2)/(x - 7)

The domain restriction occurs when the denominator, g(x), is equal to zero since division by zero is undefined. So we must find the value of x for which g(x) = 0. Since g(x) = x - 7, setting this equal to zero gives us:

x - 7 = 0 → x = 7

Therefore, the domain of the function (f/g)(x) is all real numbers except for x = 7, because at x = 7 the function is undefined. The domain of (f/g)(x) can be expressed as - {7}, where represents the set of all real numbers.

PLEASE HELP AS FAST AS POSSIBLE PLEASE HELP PLEASE

Evaluate 0.00008 ÷ 640,000,000.

A) 1.25 × 10 -15

B) 1.25 × 10 -14

C) 1.25 × 10 -13

D) 1.25 × 10 -12

Answers

Answer:

0.00008 ÷ 640,000,000 means

8*10^-5 ÷ 6.4*10^8

so let's collect to simplify the operation

(8÷6.4)*(10^-12) -5-7=-12

then the answer becomes 1.25×10^-14 that is B

Answer:

option C

Step-by-step explanation:

Evaluate 0.00008 ÷ 640,000,000.

0.00008 can be written in standard notation

Move the decimal point to the end

so it becomes  [tex]8 \cdot 10^{-5}[/tex]

for 640,000,000 , remove all the zeros and write it in standard form

[tex]64 \cdot 10^7[/tex]

Now we divide both

[tex]\frac{8 \cdot 10^{-5}}{64 \cdot 10^7}[/tex]

Apply exponential property

a^m divide by a^n  is a^ m-n

[tex]\frac{8}{64} =0.125[/tex]

[tex]\frac{10^{-5}}{10^7}=10^{-12}[/tex]

[tex]0.125 \cdot 10^{-12}= 1.25 \cdot 10^{-13}[/tex]

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