Bryce has two small buckets each containing numbered tiles. The tiles in bucket A are the odd numbers from 1 to 31, one tile per number. The tiles in bucket B are the even numbers from 2 to 32, one tile per number. Bryce draws one tile from bucket A. On the number line below "Bucket A," select the point that represents the probability of drawing a tile that is a prime number from bucket A. He then draws one tile from bucket B. On the number line below "Bucket B," select the point that represents the probability of drawing a tile that is evenly divisible by 6 from bucket B.

Answers

Answer 1
A," select the point that represents the probability of drawing a tile that is a prime number from bucket A
Answer 2

total number of prime numbers in bucket A = 10(  3 5 7 11 13 17 19 23 29 31)

Probability = favorable outcomes/ total outcomes = 10/31

total number of numbers evenly divisible by 6 in bucket B = 5(6 12 18 24 30)

probability = 5/31


Related Questions

Help me with 1-6 please

Answers

1.
8x = 16
X= 2

2.
=0
Hope this help

In the living world, there is a great deal of genetic variation. The genetic information of dogs differs from the genetic information of cats. The genetic information of plants differs from the genetic information of bacteria. Your genetic information differs from your father's genetic information, and so on.

Answers

i think it is asexual reproduction

To solve the equation 3x−2=4x−1 3 x − 2 = 4 x − 1 , Veronica graphs the functions f(x)=3x−2 f ( x ) = 3 x − 2 and g(x)=4x−1 g ( x ) = 4 x − 1 on the same set of coordinate axes.
Which statement describes the solution of the equation ​ 3x−2=4x−1


The solution of the equation is the y-coordinate of the ordered pair where the graphs of the two functions intersect.

The solution of the equation is the y-intercept of the linear equations.

The solution of the equation is the x-coordinate of the ordered pair where the graphs of the two functions intersect.

The solution of the equation cannot be found graphically. Veronica should solve the equation algebraically.

Answers

The solution of the equation is the x-coordinate of the ordered pair where the graphs of the two functions intersect. (3rd selection)

The length of the legs in a right triangle are 14 in and 22 in. Find the length of the hypotenuse. Round your answer to the tenths place.

Answers

Use Pythagorean Theorem
a^2 + b^2= c^2 to find hypotenuse

a= 14 in
b= 22 in
c= unknown hypotenuse

a^2 + b^2= c^2
(14)^2 + (22)^2= c^2
196 + 484= c^2
680= c^2
take square root of 680
26.0768= c
round to nearest tenth
26.1 in= c

ANSWER: the hypotenuse is 26.1 (rounded to nearest tenth)

Hope this helps! :)

Which best summarizes the Pythagorean theorem

Answers

Final answer:

The Pythagorean theorem, usually applied in right-angled triangles, states the square of the hypotenuse equals the sum of the squares of the other two sides. This can be summarized by the equation: a² + b² = c². It is a fundamental principle in geometry.

Explanation:

The Pythagorean theorem is a mathematical principle that applies specifically to right-angled triangles. The theorem, credited to the ancient Greek philosopher Pythagoras, stipulates that the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. This relationship can be represented by the equation: a² + b² = c², where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

For example, if one side of the triangle (a) is 3 units and the other side (b) is 4 units, the length of the hypotenuse (c) can be calculated using the Pythagorean theorem. The calculation would be set as follows: 3² + 4² = c². When solved, it results in c = √(3² + 4²) = √(9 + 16) = √25 = 5 units. Therefore, the length of the hypotenuse in this case is 5 units.

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If angle c = 90° , c= 17, and a= 15, then b =

Answers

By either the law of cosines or the Pythagorean theorem,
  b = √(c^2 -a^2) = √(289 -225) = √64
  b = 8


how do you get the percent of 20% off 7.12

Answers

0.20 represents 20%. So...
Multiply 7.12 by 0.20 to get 20% of 7.12
You can multiply any number by 0.20 to get 20% of that number!

Use completing the square to solve for x in the equation (x-12)(x+4)=9.
a. x = –1 or 15
b. x = 1 or 7
c. x=4+√41
d. x=4+√73

Answers

For a quadratic of the form [tex]x^2+bx=-c[/tex], we can solve by completing the square.

First, we must expand the expression and convert it to the form above.

[tex](x-12)(x+4)=9\\x^2+4x-12x-48=9\\x^2-8x=57[/tex]

Completing the square is like forcing a quadratic to be factored like a perfect square trinomial. To do so, we add the square of half of the coefficient b, [tex]( \frac{b}{2})^2[/tex], to both sides of the equation.

[tex]x^2-8x+( \frac{-8}{2})^2=57+( \frac{-8}{2})^2\\\\x^2-8x+16=57+16[/tex]

We then factor like a perfect square trinomial and simplify.

[tex](x-4)^2=73[/tex]

[tex]x-4= \pm \sqrt{73} \\\\ x = 4+\sqrt{73} \ or \ x = 4-\sqrt{73}[/tex]

Answer:

The correct answer is

D

tell whether the measure can be the side lengths of a triangle. if so classify the triangle as acute obtuse or right

Answers

Answer: All of them can be a triangle except for #11 because the two shortest sides don't add up to more than the longest side.

#10 is a Pythagorean Triple so it is a right triangle.

To determine if the triangle is an acute or obtuse triangle, we just need to plug the values into the Pythagorean Theorem. If the sum of the legs squared is greater than the hypotenuse, it's an acute triangle. If the sum of the legs square is less than the hypotenuse, it's an obtuse triangle.


Using this logic, 7 & 12 will be obtuse while 8 & 9 will be acute.


Final answer:

Using the Triangle Inequality Theorem and the Pythagorean theorem, we can determine if a given set of measures can form a triangle, and if so, what type of triangle (acute, obtuse, or right) it is. We find that measures a) 4,7,9; b) 10,13,16; c) 8,8,11; d) 9,12,15 and f) 4.5,6,10.2 can all form triangles, but e) 5,14,20 cannot. The triangles formed are respectively acute, obtuse, acute, right, and obtuse.

Explanation:Triangular Side Lengths and Identification

In the discipline of Mathematics, specifically Geometry, we use the Triangle Inequality Theorem and the Pythagorean theorem to determine if given measures can constitute the sides of a triangle and also classify the triangle. The Triangle Inequality Theorem states that the sum of the lengths of any two sides of a triangle must be larger than the length of the third side. The Pythagorean theorem (a² + b² = c²) is especially used to identity right triangles, but can also support in the identification of obtuse and acute triangles.

4,7,9 - These lengths can form a triangle. Since 4² + 7² > 9², the triangle is acute.10,13,16 - These lengths can form a triangle. However, since 10² + 13² < 16², the triangle is obtuse.8,8,11 - These lengths can form a triangle. Since 8² + 8² > 11², the triangle is acute.9,12,15 - These lengths can form a triangle. As 9² + 12² = 15², this is a right triangle.5,14,20 - These lengths cannot form a triangle as 5 + 14 < 20, which means it violates the Triangle Inequality Theorem.4.5,6,10.2 - These lengths can form a triangle. As 4.5² + 6² < 10.2², it is an obtuse triangle.

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Write the following equation in standard form: x^5+2x^3+6x+1/5

Answers

I think it’s 2x^3+x^5+6x+1/5

Not totally sure

Answer:

[tex]x^5+2x^3+6x+\frac{1}{5}[/tex]

Step-by-step explanation:

We have been given an equation [tex]x^5+2x^3+6x+\frac{1}{5}[/tex]. We are asked to write our given equation in standard form.

We know that to write an equation in standard form, we need to write the degree terms in descending order.

Upon looking at our given equation, we can see that all terms are in descending order of degree, therefore, our given equation is already writen in standard form.

The area of the ice surface of a skating rink is about 221 yd2. The rink is about the shape of a rectangle where the ice-surface width is 4 yd longer than its length. Find the dimensions of the surface

Answers

Let
x----------> length of rectangle  surface
y---------->width of rectangle surface

we know that
x*y=221------------> equation 1
and
y=x+4--------------> equation 2

I substitute 2 in 1
x*[x+4]=221--------> x²+4x-221=0

using a graph tool---------> to calculate the quadratic equation

see the attached figure
the solution is
x=13
y=x+4-------> y=13+7-----> y=17

the answer is 
the length of rectangle surface is 13 yd
the width of rectangle surface is 17 yd

"The dimensions of the ice surface are approximately 25 yd in length and 29 yd in width.

To find the dimensions of the ice surface, we need to solve for the length and width of the rectangle, given that the area is 221 yd² and the width is 4 yd longer than the length. Let's denote the length of the rink as l and the width as w. We can then set up the following equations based on the given information:

1. The area of a rectangle is given by the product of its length and width, so we have:

[tex]\[ l \times w = 221 \][/tex]

 2. The width is 4 yd longer than the length, so we have:

[tex]\[ w = l + 4 \][/tex]

Now we can substitute the second equation into the first equation to express the area solely in terms of the length I:

[tex]\[ l \times (l + 4) = 221 \][/tex]

Expanding the equation, we get:

[tex]\[ l^2 + 4l = 221 \][/tex]

Rearranging the terms to set the equation to zero, we have a quadratic equation:

[tex]\[ l^2 + 4l - 221 = 0 \][/tex]

To solve this quadratic equation, we can factor it or use the quadratic formula. Factoring, we look for two numbers that multiply to -221 and add up to 4. These numbers are 13 and -17. So we can rewrite the equation as:

[tex]\[ (l + 17)(l - 13) = 0 \][/tex]

Setting each factor equal to zero gives us two possible solutions for l:

[tex]\[ l + 17 = 0 \quad \text{or} \quad l - 13 = 0 \] \[ l = -17 \quad \text{or} \quad l = 13 \][/tex]

Since a negative length does not make sense in this context, we discard l = -17 and take l = 13 yd as the length of the rink.

Now we can find the width w by adding 4 yd to the length:

[tex]\[ w = l + 4 \] \[ w = 13 + 4 \] \[ w = 17 \][/tex]

However, we made a mistake in the factoring process. The correct factors of 221 that add up to 4 are 17 and 13, not -17 and 13. The correct length should be 13 yd, and the width should be:

[tex]\[ w = l + 4 \] \[ w = 13 + 4 \] \[ w = 29 \][/tex]

Therefore, the correct dimensions of the ice surface are 13 yd in length and 29 yd in width.

3/7x + 4 = -1/2

explain pls

Answers

3/7x + 4 = -1/2
subtract 4 from both sides
3/7x= -1/2 - 4
3/7x= -4 1/2
divide both sides by 3/7
x= -4 1/2 ÷ 3/7
convert -4 1/2 to improper fraction
x= (-4*1+1)/2 ÷ 3/7
x= -9/2 ÷ 3/7
multiply by reciprocal of 3/7
x= -9/2 * 7/3
multiply numerators & denominators
x= (-9*7)/(2*3)
x= -63/6
x= -10 3/6
simplify 3/6 by 3
x= -10 1/2

CHECK:
3/7x + 4 = -1/2
3/7(-63/6) + 4= -1/2
(3*-63)/(7*6) + 4= -1/2
-189/42 + 4= -1/2
-4 1/2 + 4= -1/2
-1/2= -1/2

ANSWER: x= -63/6 or -10 1/2

Hope this helps! :)

I'm having trouble answering this question and the 2/3 confuses me

Answers

The solution is: x∠-3, in written form it is x is less than negative 3.

A cylinder with a radius of 1 cm and a height of 21 cm has the same volume as a cone with a height of 7 cm. What is the radius of the cone? A) 3 cm B) 5 cm C) 7 cm D) 9 cm

No guessing tyvm!

Answers

option A is correct.

volume of cylinder = volume of cone
(22/7)(1^2)(21) =(1/3)(22/7)(r^2)(7)
9 =r^2
therefore radius = 3cm.

a square and a rectangle have the same perimeter.the square has a side length of 8xunits.the rectangle has a length of 5x+8 and a width of 10 units .what will be the perimeter of both square and rectangle

Answers

perimeter of square = 4*8x=32x
Perimeter of rectangle = 2*(5x+8)+2*10=10x+16+20=10x+36
32x=10x+36
22x=36
x=36/22
P=4*8*36/22=2*8*36/11= 56.36 units

Simplify to create an equivalent expression.
(4+2k)⋅6+3k =

Answers

the answer is
[tex]15k + 24[/tex]
because
[tex](6 \times 4 ) +( 6 \times 2k) + 3k[/tex]
equals
[tex]15k + 24[/tex]
Final answer:

To simplify the expression (4+2k)⋅6+3k, distribute 6 to both terms inside the parentheses and combine like terms.

Explanation:

To simplify the expression (4+2k)⋅6+3k, we need to distribute the 6 to both terms inside the parentheses:

(4⋅6) + (2k⋅6) + 3k

Simplifying further, we have:

24 + 12k + 3k

Combining like terms, we get:

24 + 15k

So, the simplified expression is 24 + 15k.

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Karleigh walks 5/8 mile to school every day. How far does she walk to school in 5 days?



____________________

Answers

Hello!

To figure out how far Karleigh walks in 5 days, multiply the amount she walks in one day by 5.

[tex] \frac{5}{8} *5[/tex]
[tex] \frac{5}{8} * \frac{5}{1} [/tex]
[tex] \frac{25}{8} [/tex]

Answer:
Karleigh walks [tex] \frac{25}{8} [/tex] or 3.125 miles to school in 5 days.

the market value of Christine and genes home is 275,000 the assessed value is 230,000 the annual property tax rate is 17.50 per $1,000 Us in value what is the property tax on their home

Answers

Answer: The property tax is $4,025

To find the property tax we have to look at the assessed value of the property. In our problem, that is 230,000. Now, you just have to multiply that by the rate of 17.50 per 1000, or you have use the percent 1.75%.

This will give you the total tax of 4025.
Final answer:

To calculate the property tax on Christine and Gene's home, multiply the tax rate of 0.0175 (converted from $17.50 per $1,000) by the assessed value of $230,000. The annual property tax on their home would be $4,025.

Explanation:

The student is asking how to calculate the property tax on Christine and Gene's home. To calculate this, you need to use the assessed value of the property and the property tax rate. Here is the step-by-step calculation:

Property tax rate = $17.50 per $1,000 of assessed value.Assessed value of the home = $230,000.To find the property tax, convert the tax rate to a decimal by dividing by 1,000, resulting in 0.0175 ($17.50 / $1,000).Multiply the resulting decimal by the assessed value: Property tax = 0.0175 * $230,000.

The calculation is:

Property tax = 0.0175 * $230,000 = $4,025

Therefore, the annual property tax on their home is $4,025.

A scale drawing of a house addition shows a scale factor of 1 in. = 3.3 ft. Josh decides to make the house addition smaller, and he changes the scale of the drawing to 1 in. = 1.1 ft. What is the change in the scale factor from the old scale to the new scale? Help Please!!

Answers

It is decreased by a factor of 3. You can determine this by realizing that one inch original equals 3.3 feet, but the equals 1.1 feet, and 3.3/1.1 = 3.

The change in the scale factor from the old scale to the new scale is option A; 3 to 1.

What is Scale?

The ratio used to depict the relationship between the dimensions of a model or scaled figure and the corresponding dimensions of the real figure or object is called the scale. On the other hand, a scale factor is a value that is used to multiply all of an object's parts in order to produce an expanded or decreased figure.

Given, A scale drawing of a house addition shows a scale factor of 1 in. = 3.3 ft.

Since Josh decides to make the house addition smaller,

he changes the scale of the drawing to 1 in. = 1.1 ft.

Old: 1 inch = 3.3 feet.

New: 1 inch = 1.1 feet.

Old; 3.3 / 1.1 = 3.

New; 1.1 / 1.1 =  1

The change in the scale factor from the old scale to the new scale is option A; 3 to 1.

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ana tiene 5000000 en una cuenta bancaria. le dan un interes de 3.2%, ¿cuanto dinero trndra dentro de 2 meses y 10 dias ( todos los meses tienes 30 dias)

Answers

Ana has 5,000,000 in a bank account. they give you an interest of 3.2%, how much money will be spent within 2 months and 10 days (all months you have 30 days)?


My answer was $43,835.62.

Hope this helped☺☺

The length of an equilateral triangle is increased by 7 inches, so the perimeter is now 36 inches. Find the original length of each side of the equilateral triangle.

Answers

The original length is 5 inches per side.

A property sells for $620,000 two years after it was purchased. If the annual appreciation rate was 4%, how much did the original buyer pay for the property (round to the nearest $1,000)?

Answers

Final answer:

The original purchase price of the property, after accounting for 4% annual appreciation over two years with a final selling price of $620,000, is approximately $573,000 when rounded to the nearest $1,000.

Explanation:

The question involves finding the original price of a property given its final selling price after a period of annual appreciation. To calculate the original purchase price, we need to use the formula for compound appreciation in reverse, known as discounting. Since the appreciation is 4% per year for two years and the final selling price is $620,000, the original purchase price (P) can be found using the formula:

P = Final Price / (1 + rate of appreciation)^number of years

So, substituting the given values, we get:

P = $620,000 / (1 + 0.04)^2

Now, calculate the denominator:

(1 + 0.04)^2 = 1.0816

And then divide by the final price:

P = $620,000 / 1.0816

P = $573,029.94

When rounded to the nearest $1,000, the original purchase price is approximately $573,000.

the number 1254 is divisible by all of the following, except?

Answers

The answer should be 5

Answer:

The answer to this question is 9.

Step-by-step explanation:

Lemonade is sold in 2 L bottles how many millimeters are in a 2 L bottle of lemonade

Answers

In one lemonade bottle, there would be 2000mL. (1L = 1000mL)

Find both unit rates. 1435 points scored in 25 games + Brainliest!!

Answers

In this case, the unit is points (1,435) and the time is games (25). So, we divide the unit by the rate to get the unit rate of 57.5.

On the flip side, we can treat the game as the unit and the points as the rate to get 0.017 games per point.

What force would be required to accelerate a 1,100 kg car to 0.5 m/s2?

Answers

Answer:550(N)

Step-by-step explanation:

Answer:

550 N

Step-by-step explanation:

I got the answer right.

How do I add fractions with different denominations?

Answers

1.Write down the fractions.
2.Find a common denominator.
3.Multiply both numbers on the first fraction by the bottom number of the second fraction. 
4.Multiply both numbers on the second fraction by the bottom number of the first fraction. 
5.Line both fractions up side by side with their new numbers. 
6.Add together the numerators of the two fractions. 
7.Take the common denominator that you figured out in Step 2 and add it on the bottom of your new numerator.
8.Put the new numerator on top and the new denominator on bottom.
9.Simplify and reduce.

In a six-sided dice game, a prize is won if the arithmetic mean of number rolled is 3.25-3.75. In a second game, a prize is won if the arithmetic mean is more than 4.5. In which game would you rather roll the dice 20 times or 200 times

Answers

For rolling the dice 200 times, the same logic applies. Regardless of the number of rolls, the game with the higher probability of winning, which is the second game, is preferred.

To determine which game is more favorable for rolling the dice, we need to calculate the expected value for each game. The expected value represents the average outcome of rolling the dice.

For the first game, the possible outcomes are integers between 1 and 6. The arithmetic mean should be between 3.25 and 3.75 to win a prize. So, we need to find the probability of rolling numbers that satisfy this condition.

Let's denote [tex]\( p_1 \)[/tex] as the probability of winning the first game. To find [tex]\( p_1 \)[/tex], we calculate the probability of rolling numbers between 13 and 18 (inclusive) since the sum of these numbers falls within the range of 3.25 to 3.75.

[tex]\[ p_1 = \frac{6}{6^2} = \frac{1}{6} \][/tex]

For the second game, we need the arithmetic mean to be more than 4.5. This means the sum of the numbers should be more than [tex]\( 4.5 \times 6 = 27 \)[/tex]. Since the maximum sum of rolling six dice is 36, all outcomes satisfy this condition.

Let's denote [tex]\( p_2 \)[/tex] as the probability of winning the second game. Since all outcomes are favorable, [tex]\( p_2 = 1 \)[/tex].

Now, we calculate the expected values for each game:

[tex]\[ E_1 = p_1 \times \text{Prize amount for game 1} \][/tex]

[tex]\[ E_2 = p_2 \times \text{Prize amount for game 2} \][/tex]

Given that the prize amount is the same for both games, we can compare the expected values directly.

For rolling the dice 20 times:

[tex]\[ E_1 = \frac{1}{6} \times \text{Prize amount} \][/tex]

[tex]\[ E_2 = 1 \times \text{Prize amount} \][/tex]

Since [tex]\( \frac{1}{6} \)[/tex] is less than 1, it's better to choose the game with the higher probability, which is the second game.

For rolling the dice 200 times, the same logic applies. Regardless of the number of rolls, the game with the higher probability of winning, which is the second game, is preferred.

The complete question is:

In a six-sided dice game, a prize is won if the arithmetic mean of number rolled is 3.25-3.75. In a second game, a prize is won if the arithmetic mean is more than 4.5. In which game would you rather roll the dice 20 times or 200 times

Hey Siri has to water towers one tower hold 7.35×10 to the fifth power gallons of water in the other tower holds 9.78×10 to the fifth power gallons of water what is the combined water capacity of a two Towers

Answers

Tower one- 2145046422.09Tower two- 8947346861.26
Both together- 11092393283.4

Final answer:

To find the combined capacity of the two water towers, you add their capacities together by summing the significant figures and keeping the exponent the same. The result is a combined water capacity of 17.13×105 gallons.

Explanation:

The question involves adding two large numbers that are expressed in scientific notation. To find the combined water capacity of the two water towers, we simply add the quantities together. The first tower holds 7.35×105 gallons, and the second tower holds 9.78×105 gallons.

To combine these:

Add the significant figures (the numbers before the exponent): 7.35 + 9.78.

Calculate this sum: 7.35 + 9.78 = 17.13.

Since both powers of ten are the same (105), you can keep the exponent as is.

Combine the significant figures with the exponent to get the final answer: 17.13×105 gallons.

This is the total combined water capacity of the two towers.

please help with 7,8,9

Answers

12, 23, 75

283864648474844848844998
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