Calc AB! Please show work, the answers are provided. I need all work for part A AND B!!!
Need ASAP!

Calc AB! Please Show Work, The Answers Are Provided. I Need All Work For Part A AND B!!!Need ASAP!

Answers

Answer 1

Step-by-step explanation:

24. A

B' ( t ) = 10 [ 20 CDS ( t/10) ] = 2 COS ( t/10 )

B' ( 7 ) = 1.5

After 7 days the number of beds in use is increasing at the rate of 1 1/2 beds per day.

24.B

2 COS ( t/10) =0

using calculator t = 15.7

B (12) = 20 Sin (1.2) + 50 = 68.6 = 69

B (15.7) = 20 Sin (1.57) + 50 = 70

B (20) = 20 SIn (20) + 50 = 68.25 = 68

Maximum number of beds in use occurs in afternoon of 15th day and is 70 beds.

I hope that helps and I hope  it's right  


Related Questions

The students want to make care packages for unhoused people for winter season. They would like to put 5 boxes of tissues into each care package. If they have 450 boxes pack, how many tissue boxes will they need to complete the boxes?

Answers

Answer: 50 tissue boxes

Step-by-step explanation:

The students want to make care packages for unhoused people for winter season.

They would like to put 5 boxes of tissues into each care package.

If they have 450 boxes pack, to determine how many tissue boxes that they need to complete the boxes, we will divide the total number of boxes pack that they have by the number of tissues that will go into one pack. It becomes

450/9 = 50

The office building is 48 floors high. Half of the floors have 18 windows each and half of the floors have 36 windows each. How many windows does the building have in all?

Answers

Answer:

1296 windows

Step-by-step explanation:

HALF of the floors, means

HALF of 48, that is:

48 * 0.5 = 24

Thus, we can say:

24 floors each have 18 windows, and

24 floors each have 36 windows

Total Number of Windows:

24 * 18 = 432 windows

24 * 36 = 864 windows

Total = 432 + 864 = 1296 windows

Answer:

1296 windows are present in the building

Explanation:

Given the office building is 48 floors high

Half of floors have 18 windows each

Then , half of floors =[tex]\frac{48}{2}[/tex] = 24 floors

Total windows on half of the floors, that is 24 floors

= [tex]18\times 24[/tex]

= 432 windows

Also, half of the floors have 36 windows each

Total windows on rest half floors (24 floors)

=[tex]36 \times 24[/tex]

= 864 windows

Total windows = 432 + 864 = 1296 windows

Therefore, 1296 windows are present in the building

Harry has a small business cleaning kitchens and bathrooms. He usually cleans a bathroom in 1 hour and cleans a kitchen in 45 minutes. He never works more than 15 hours in a week. Harry earns $60 per bathroom and $20 per kitchen job. He does not do more than 8 bathroom jobs per week (the smell gets to him). Find a combination of bathroom and kitchen jobs per week that will maximize his income and state the amount.

Answers

Answer:

8 bathroom jobs and 9 kitchen jobs

Step-by-step explanation:

B=60

K=20

8*60=480

9*20=180

that would give harry 660 dollars in a week. HOWEVER- we have to make sure that its equal to or less than 15 hours of work.

8*1h= 8 hours in bathroom

9*45m=6.75hr in kitchen

8 hours+6.75 hours=14.75hr 14.75 hr<15hr so it works.

A rectangular area of 36 f t2 is to be fenced off. Three sides will use fencing costing $1 per foot and the remaining side will use fencing costing $3 per foot. Find the dimensions of the rectangle of least cost. Make sure to use a careful calculus argument, including the argument that the dimensions you find do in fact result in the least cost (i.e. minimizes the cost function).

Answers

Answer:

x = 8,49 ft

y  = 4,24  ft  

Step-by-step explanation:

Let  x be the longer side of rectangle   and  y  the shorter

Area of rectangle     =    36 ft²     36  =  x* y   ⇒ y =36/x

Perimeter of rectangle:

P  =  2x   +   2y    for convinience we will write it as    P  = ( 2x + y ) + y

C(x,y)   =  1 * ( 2x  +  y  )  +  3* y

The cost equation as function of x is:

C(x)  =  2x  + 36/x   + 108/x

C(x)  =  2x  + 144/x

Taking derivatives on both sides of the equation

C´(x)  = 2  - 144/x²

C´(x)  = 0         2  - 144/x² = 0       ⇒  2x²  -144 = 0    ⇒  x² =  72

x = 8,49 ft       y  = 36/8.49    y  = 4,24  ft    

How can we be sure that value will give us a minimun

We get second derivative

C´(x)  = 2  - 144/x²      ⇒C´´(x)  = 2x (144)/ x⁴

so C´´(x) > 0

condition for a minimum

Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = x2z2i + y2z2j + xyzk, S is the part of the paraboloid z = x2 + y2 that lies inside the cylinder x2 + y2 = 16, oriented upward.

Answers

Answer:

[tex]\displaystyle \iint_S {\text{curl \bold{F}} \cdot} \, dS = \boxed{\bold{0}}[/tex]

General Formulas and Concepts:

Calculus

Integration Rule [Reverse Power Rule]:

[tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:

[tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:

[tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:

[tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Methods: U-Substitution + U-Solve

Multivariable Calculus

Partial Derivatives

Triple Integrals

Cylindrical Coordinate Conversions:

[tex]\displaystyle x = r \cos \theta[/tex][tex]\displaystyle y = r \sin \theta[/tex][tex]\displaystyle z = z[/tex][tex]\displaystyle r^2 = x^2 + y^2[/tex][tex]\displaystyle \tan \theta = \frac{y}{x}[/tex]

Integral Conversion [Cylindrical Coordinates]:

[tex]\displaystyle \iiint_T {f(r, \theta, z)} \, dV = \iiint_T {f(r, \theta, z)r} \, dz \, dr \, d\theta[/tex]

Vector Calculus

Surface Area Differential:

[tex]\displaystyle dS = \textbf{n} \cdot d\sigma[/tex]

Del (Operator):

[tex]\displaystyle \nabla = \hat{\i} \frac{\partial}{\partial x} + \hat{\j} \frac{\partial}{\partial y} + \hat{\text{k}} \frac{\partial}{\partial z}[/tex]

[tex]\displaystyle \text{div \bf{F}} = \nabla \cdot \textbf{F}[/tex][tex]\displaystyle \text{curl \bf{F}} = \nabla \times \textbf{F}[/tex]

Stokes’ Theorem:

[tex]\displaystyle \oint_C {\textbf{F} \cdot } \, d\textbf{r} = \iint_S {\big( \nabla \times \textbf{F} \big) \cdot \textbf{n}} \, d\sigma[/tex]

Divergence Theorem:

[tex]\displaystyle \iint_S {\big( \nabla \times \textbf{F} \big) \cdot \textbf{n}} \, d\sigma = \iiint_D {\nabla \cdot \textbf{F}} \, dV[/tex]

Step-by-step explanation:

Step 1: Define

Identify given.

[tex]\displaystyle \textbf{F} (x, y, z) = x^2z^2 \hat{\i} + y^2z^2 \hat{\j} + xyz \hat{\text{k}}[/tex]

[tex]\displaystyle \text{Region:} \left \{ {{\text{Paraboloid:} \ z = x^2 + y^2} \atop {\text{Cylinder:} \ x^2 + y^2 = 16}} \right[/tex]

Step 2: Integrate Pt. 1

Find div F:
[tex]\displaystyle \text{div } \textbf{F} = \frac{\partial}{\partial x} x^2z^2 + \frac{\partial}{\partial y} y^2z^2 + \frac{\partial}{\partial z} xyz[/tex][div F] Differentiate [Partial Derivatives]:
[tex]\displaystyle \text{div } \textbf{F} = 2xz^2 + 2yz^2 + xy[/tex][Divergence Theorem] Substitute in div F:
[tex]\displaystyle \iint_S {\text{curl } \textbf{F} \cdot} \, dS = \iiint_D {2xz^2 + 2yz^2 + xy} \, dV[/tex]

Step 3: Integrate Pt. 2

Convert region from rectangular coordinates to cylindrical coordinates.

[tex]\displaystyle \text{Region:} \left \{ {{\text{Paraboloid:} \ z = x^2 + y^2} \atop {\text{Cylinder:} \ x^2 + y^2 = 16}} \right \rightarrow \left \{ {{\text{Paraboloid:} \ z = r^2} \atop {\text{Cylinder:} \ r^2 = 16}} \right[/tex]

Identifying limits, we have the bounds:

[tex]\displaystyle \left\{ \begin{array}{ccc} 0 \leq z \leq r^2 \\ 0 \leq r \leq 4 \\ 0 \leq \theta \leq 2 \pi \end{array}[/tex]

Step 4: Integrate Pt. 3

[Integral] Substitute in variables and region:
[tex]\displaystyle \iint_S {\text{curl } \textbf{F} \cdot} \, dS = \int\limits^{2 \pi}_0 \int\limits^4_0 \int\limits^{r^2}_0 {r \bigg( 2z^2r \cos \theta + 2z^2r \sin \theta +r^2 \cos \theta \sin \theta \bigg)} \, dz \, dr \, d\theta[/tex]

We evaluate the Stokes' Divergence Theorem Integral using basic integration techniques listed under "Calculus".

[tex]\displaystyle \begin{aligned}\iint_S {\text{curl } \textbf{F} \cdot} \, dS & = \int\limits^{2 \pi}_0 \int\limits^4_0 \int\limits^{r^2}_0 {r \bigg( 2z^2r \cos \theta + 2z^2r \sin \theta +r^2 \cos \theta \sin \theta \bigg)} \, dz \, dr \, d\theta \\& = \frac{1}{3} \int\limits^{2 \pi}_0 \int\limits^4_0 {zr^2 \bigg[ 2z^2 \big( \cos \theta + \sin \theta \big) + 3r \sin \theta \cos \theta \bigg] \bigg| \limits^{z = r^2}_{z = 0}} \, dr \, d\theta \\\end{aligned}[/tex]

[tex]\displaystyle \begin{aligned}\iint_S {\text{curl } \textbf{F} \cdot} \, dS & = \frac{1}{3} \int\limits^{2 \pi}_0 \int\limits^4_0 {r^5 \bigg[ 2r^3 \big( \cos \theta + \sin \theta \big) + 3 \sin \theta \cos \theta \bigg]} \, dr \, d\theta \\& = \frac{1}{54} \int\limits^{2 \pi}_0 {r^6 \bigg[ 4r^3 \big( \cos \theta + \sin \theta \big) + 9 \sin \theta \cos \theta \bigg] \bigg| \limits^{r = 4}_{r = 0}} \, d\theta \\\end{aligned}[/tex]

[tex]\displaystyle \begin{aligned}\iint_S {\text{curl } \textbf{F} \cdot} \, dS & = \frac{2048}{27} \int\limits^{2 \pi}_0 {\cos \theta \Big( 9 \sin \theta + 256 \Big) + 256 \sin \theta} \, d\theta \\& = \frac{-1024}{243} \bigg[ 4608 \cos \theta - \bigg( 9 \sin \theta + 256 \bigg)^2 \bigg] \bigg| \limits^{\theta = 2 \pi}_{\theta = 0} \\& = \boxed{\bold{0}}\end{aligned}[/tex]

∴ we have calculated the Stokes' Theorem integral with the given region and function using the Divergence Theorem.

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Topic: Multivariable Calculus

Final answer:

The Stokes' theorem is applied to convert a surface integral of a curl of a vector into a line integral. This is done by identifying the curl of the given vector field F and setting up the limits of the integral based on given bounds. The integral is then evaluated.

Explanation:

Stokes' theorem is used in vector calculus to simplify certain types of surface integrals. It transforms a surface integral of a curl of a vector field into a line integral. F(x, y, z) = x2z2i + y2z2j + xyzk, here, is the given vector field. The surface S is the part of the paraboloid that lies within the cylinder x² + y² = 16. The theorem is used to evaluate the integral S curl F · dS, by treating the surface integral as a line integral. The line integral can be easier to evaluate. The exact process involves identifying the curl of F, setting up the bounds of the integral based on the restrictions given, and then computing the integral.

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An investor has ​$80,000 to invest in a CD and a mutual fund. The CD yields 8​% and the mutual fund yields 6​%. The mutual fund requires a minimum investment of ​$9,000​, and the investor requires that at least twice as much should be invested in CDs as in the mutual fund. How much should be invested in CDs and how much in the mutual fund to maximize the​ return? What is the maximum​ return?

Answers

Answer:

mutual fund: $9000CDs: $71000return: $6220, an average of 7.775%

Step-by-step explanation:

Since the mutual fund is the lower yield vehicle, only the minimum should be invested there.

The investments and returns should be ...

  mutual fund: $9000, return = 6% × $9000 = $540

  CD: $71000, return = 8% × $71000 = $5680

The maximum return is ...

  $540 +5680 = $6220

Final answer:

To maximize the return, we need to find the amount to be invested in CDs and the mutual fund. The amount to be invested in CDs is $53,333.33 and the amount to be invested in the mutual fund is $26,666.67. The maximum return is $5,333.33.

Explanation:

To maximize the return, we need to find the amount to be invested in CDs and the mutual fund. Let's assume the amount invested in the mutual fund is x dollars. Since the investor requires at least twice as much to be invested in CDs, the amount invested in CDs will be 2x dollars. The total investment amount is $80,000, so we can write the equation: x + 2x = $80,000. Simplifying the equation, we have 3x = $80,000. Dividing both sides by 3, we get x = $26,666.67 (rounded to two decimal places).

The amount to be invested in CDs is 2 times x, which is $53,333.33 (rounded to two decimal places). Therefore, the maximum return can be calculated by multiplying the amount invested in CDs and the mutual fund by their respective interest rates and adding them. The return from the CDs would be 8% of $53,333.33 and the return from the mutual fund would be 6% of $26,666.67. Calculating the returns and adding them, we get the maximum return as $5,333.33 (rounded to two decimal places).

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The thermostat in Steffi’s house is set to 56°F. The actual temperature variance in her house can be modeled by the inequality |t − 56|= 3. Plot the range of possible temperatures in her house.

Answers

Answer:

Step-by-step explanation:

|t − 56|= 3 states that the temperature, t, can be as low as (56-3)°F, or 53°F, and as high as (56+3)°F, or 59°F.

On a number line, plot a dark dot at both 53°F and 59°F, and then connect these two dots with a solid line.

The maximum and minimum values of temperature are 59°F and  53°F respectively.

What is inequality?

A difference between two values indicates whether one is smaller, larger, or basically not similar to the other.

A mathematical phrase in which the sides are not equal is referred to as being unequal. In essence, a comparison of any two values reveals whether one is less than, larger than, or equal to the value on the opposite side of the equation.

Given the inequality

|t − 56|= 3

Now,

Taking positive value ;

t - 56 = 3

t = 59

Now taking negative value

-(t-56) = 3

t = -3 + 56 =  53

Hence "The maximum and minimum values of temperature are 59°F and  53°F respectively".

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A rectangle is drawn on a coordinate grid. The equation for one side of the rectangle is 2x – 5y = 9. Which could be the equation of another side of the rectangle?

Answers

Answer:

[tex]25x+10y+18=0[/tex]

Step-by-step explanation:

We are given that a rectangle in which the equation of one side is given by

[tex]2x-5y=9[/tex]

We have to find the equation of another side of the rectangle.

We know that the adjacent sides of rectangle are perpendicular to each other.

Differentiate the given equation w.r.t.x

[tex]2-5\frac{dy}{dx}=0[/tex]   ([tex]\frac{dx^n}{dx}=nx^{n-1}[/tex])

[tex]5\frac{dy}{dx}=2[/tex]

[tex]\frac{dy}{dx}=\frac{2}{5}[/tex]

Slope of the given side=[tex]m_1=\frac{2}{5}[/tex]

When two lines are perpendicular then

Slope of one line=[tex]-\frac{1}{Slope\;of\;another\;line}[/tex]

Slope of another side=[tex]-\frac{5}{2}[/tex]

Substitute x=0 in given equation

[tex]2(0)-5y=9[/tex]

[tex]-5y=9[/tex]

[tex]y=-\frac{9}{5}[/tex]

The equation of given side is passing through the point ([tex]0,-\frac{9}{5})[/tex].

The equation of line passing through the point [tex](x_1,y_1)[/tex] with slope m is given by

[tex]y-y_1=m(x-x_1)[/tex]

Substitute the values then we get

[tex]y+\frac{9}{5}=-\frac{5}{2}(x-0)=-\frac{5}{2}x[/tex]

[tex]y=-\frac{5}{2}x-\frac{9}{5}[/tex]

[tex]y=\frac{-25x-18}{10}[/tex]

[tex]10y=-25x-18[/tex]

[tex]25x+10y+18=0[/tex]

Hence, the equation of another side of rectangle is given by

[tex]25x+10y+18=0[/tex]

Answer:

y=2/5x-9

I just answered this and got it right.

Step-by-step explanation:

Choose the slope-intercept equation of the line that passes through the point (-2, 4) and is parallel to y = -3x + 6.

y = 1/3 x + 14/3

y = 3x + 10

y = -3x - 2

y = - 1/3 x + 10/3

Answers

Answer:

  y = -3x - 2

Step-by-step explanation:

Parallel lines have the same slope. The only answer choice with the same slope (x-coefficient = -3) as the given line is the one shown above.

Use​ Descartes' Rule of Signs to determine the possible numbers of positive and negative real zeros of f (x )equals x cubed plus 5 x squared plus 7 x plus 6f(x)=x3+5x2+7x+6. What are the possible numbers of positive real​ zeros?

Answers

Answer:

  0

Step-by-step explanation:

All of the terms have positive signs, so there are no sign changes. Zero sign changes means there are zero positive real roots.

Consider the given function and the given interval.
f(x) = 3 sqrt x, [0, 16]
(a) Find the average value fave of f on the given interval
(b) Find c such that fave = f
(c). (Round your answer to three decimal places.)

Answers

Answer:

  (a)  fave = 8

  (b)  c = 64/9

  (c)   c ≈ 7.111

Step-by-step explanation:

(a) The average value of the function is its integral over the interval, divided by the width of the interval.

  [tex]f_{ave}=\displaystyle\frac{1}{16-0}\int_0^{16} {3x^{\frac{1}{2}}} \, dx=\left.\frac{x^{3/2}}{8}\right|_0^{16}=8[/tex]

__

(b) We want ...

  f(c) = 8

  3√c = 8 . . . . . use f(c)

  √c = 8/3 . . . . . divide by 3

  c = (8/3)² . . . . square

  c = 64/9

__

(c) c ≈ 7.111

Final answer:

To find the average value of a function, evaluate the definite integral over the interval and divide by the length of the interval.

Explanation:

To find the average value of a function on a given interval, we need to evaluate the definite integral of the function over the interval and divide it by the length of the interval.

For the given function f(x) = 3√x on the interval [0, 16], the average value fave is given by:

fave = (1/[16-0]) * ∫(0 to 16) 3√x dx

Simplifying this integral, we get:

fave = 3/16 * (2/3) * (16^(3/2) - 0^(3/2)) = 4(16 - 0) = 64

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Consider an employee's whose earnings, in dollars, are according to the continuous stream f(t)=5,000e0.1t for t>0, where t is measured in years. How many years will it take them to earn a combined total of $100,000? Give your answer in years to the nearest year.

Answers

It will take approximately 10.986 years for the employee to earn a combined total of $100,000. Rounding to the nearest year, it will take approximately 11 years for the employee to reach this earnings milestone.

To determine how many years it will take for the employee to earn a combined total of $100,000, we need to set up and solve the following integral:

[tex]\[ \int_{0}^{t} 5000e^{0.1\tau} \, d\tau = 100,000 \][/tex]

Here, [tex]\( t \)[/tex] represents the time in years. The integral represents the accumulated earnings from the start (0 years) to t years based on the continuous stream function[tex]\( f(\tau) = 5000e^{0.1\tau} \).[/tex]

Let's solve this integral:

[tex]\[ \int_{0}^{t} 5000e^{0.1\tau} \, d\tau = \left. \frac{5000}{0.1}e^{0.1\tau} \right|_{0}^{t} \][/tex]

Evaluate this at the upper and lower limits:

[tex]\[ \frac{5000}{0.1}e^{0.1t} - \frac{5000}{0.1}e^{0.1 \times 0} \][/tex]

Simplify:

[tex]\[ 50000(e^{0.1t} - 1) \][/tex]

Now, set this expression equal to the target earnings of $100,000 and solve for  t :

[tex]\[ 50000(e^{0.1t} - 1) = 100,000 \][/tex]

Divide both sides by 50000:

[tex]\[ e^{0.1t} - 1 = 2 \][/tex]

Add 1 to both sides:

[tex]\[ e^{0.1t} = 3 \][/tex]

Now, take the natural logarithm (ln) of both sides:

[tex]\[ 0.1t = \ln(3) \][/tex]

Solve for t:

[tex]\[ t = \frac{\ln(3)}{0.1} \][/tex]

Using a calculator:

[tex]\[ t \approx \frac{1.0986}{0.1} \]\[ t \approx 10.986 \][/tex]

20% 20 % of the tickets sold at a water park were adult tickets. ​ ​If the park sold 55 55 tickets in all, how many adult tickets did it sell? ​

Answers

55(0.2) = 11 Adult tickets. Take the total amount and times in by 20% to get the total adult tickets sold because they consisted of 20% of the tickets.

There are three nursing positions to be filled at Lilly Hospital. Position 1 is the day nursing supervisor, position 2 is the night nursing supervisor; and position 3 is the nursing coordinator position. There are 10 candidates qualified for 3 of the positions. Determine the number of different ways that 3 positions can be filled by these applicants.a.30.b.720.c. none of these choices.d. 10.e. 120

Answers

Answer:

The correct option is B) 720.

Step-by-step explanation:

Consider the provided information.

We have 10 candidates those qualified for 3 of the positions.

There are three nursing positions to be filled at Lilly Hospital. Position 1 is the day nursing supervisor, position 2 is the night nursing supervisor; and position 3 is the nursing coordinator position.

For Position 1  we have 10 choices, if we select 1 out of 10 candidates we are left with 9 candidates.

For position 2 we have 9 candidates, if we select 1 out of 9 candidates we are left with 8 candidates.

For position 3 we have 8 candidates.

Therefore, the number of ways are: [tex]10\times 9\times 8=720[/tex]

The number of different ways that 3 positions can be filled by these applicants is 720.

Hence, the correct option is B) 720.

Final answer:

Correct Option Is (e. 120.) The number of different ways that 3 positions can be filled by the applicants is 120.

Explanation:

To determine the number of different ways that 3 positions can be filled by these applicants, we can use the concept of combinations. Since there are 10 candidates and the order of the positions does not matter, we can use the combination formula. The number of combinations of 10 candidates taken 3 at a time is given by:

C(10, 3) = 10! / (3!(10-3)!)

Simplifying this expression, we get:

C(10, 3) = 10! / (3!7!)

Calculating the factorial values, we have:

C(10, 3) = 10 * 9 * 8 / (3 * 2 * 1) = 120

Therefore, the number of different ways that 3 positions can be filled by these applicants is 120.

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Giovanni orders a pastry from the bakery. The price of the pastry before tax is $4.50. Giovanni wants to know the total price including a 10% sales tax.

Answers

Answer:

4.95

Step-by-step explanation:

You take the 4.50 and multiply it by 1.10 and it equals 4.95. Also I did it and I got it right.

The total price of the pastry is $4.95.

Given to us

price of the pastry = $4.50

sales tax = 10%

Sales tax

The sales tax on the pastry is 10% of the price of the pastry.

Tax on pastry = price of the pastry x percentage of sales tax

                       [tex]= \$4.50 \times 10\%\\= 4.5\times \dfrac{10}{100}\\= 4.50 \times 0.1\\= 0.45[/tex]          

therefore, the tax on the pastry will be $0.45

Total price of the pastry

Total price of the pastry =  Price of the pastry + tax on the pastry

                                        =   $4.50 + $0.45

                                        =  $4.95

Hence, the total price of the pastry is $4.95.

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Coach A is offering her services for an initial $6,925 in addition to $450 per hour. Coach B is offering her services for an initial $5,000 in addition to $725 per hour. When will the two coaches charge the same amount of money? The two coaches will charge the same amount of money after

Answers

Answer:

The two coaches will charge the same amount of money after working for 11 hours

Step-by-step explanation:

Let us assume for m hours, they both will charge same amount.

For COACH A:

The initial Fee = $ 6,925

The per hour fee  = $450

So, the fees in m hours = m x ( Per hour fees) = m x ($450)  = 450 m

So, the total fees of Coach A in m hours = Initial Fee + fee for m hours

                                                                  = $ 6,925  + 450 m  

The total fees of Coach A in m hours  = $ 6,925  + 450 m ....  (1)

For COACH B:

The initial Fee = $ 5,000

The per hour fee  = $725

So, the fees in m hours = m x ( Per hour fees) = m x ($725)  = 725  m

So, the total fees of Coach B in m hours = Initial Fee + fee for m hours

                                                                  = $ 5,000  + 725 m  

The total fees of Coach B in m hours  =$ 5,000  + 725 m ....  (2)

Now, for m hours , they both charge the SAME AMOUNT fees

$ 6,925  + 450 m  = $ 5,000  + 725 m    ( from (1) and (2))

or, 6925 - 5000 = 725 m - 450 m

or, 1925 = 175 m

or,m = 1925 / 175 = 11

or, m = 11

Hence, the two coaches will charge the same amount of money after working for 11 hours.

A certain company has 255 employees. If an employee is to be selected at random from the company's employees, is the the probability less than 1/2 that the employee selected will be a woman who has a college degree?

(1) 130 of the company's employees do not have a college degree
(2) 125 of the company's employees are men

Answers

Answer:

a) 125 < 128

b) The maximum probability that all 130 women are with college degree is 130 < 128 (this is not possible)

The minimum probability that none of the 130 women are college holders = 0 < 128 (this is possible)

Step-by-step explanation:

Total number of employees = 255

If the probability is less than 1/2 that the employee selected will be a woman who has college degree, we have

Women with college degree < 255/2

< 128

a) if 130 of the company employee do not have college degree, we consider that all the college degree holders are women.

The women with college degree = 255 - 130

= 125

Therefore; 125 < 128 ( this is possible)

b) If 125 of the company employees are men, the number of women = 250 -125

= 130 women

The maximum probability that all 130 women are with college degree is 130 < 128 (this is not possible)

The minimum probability that none of the 130 women are college holders = 0 < 128 (this is possible)

Use the confidence interval to find the estimated margin of error. Then find the sample mean.
A biologist reports a confidence interval of (3.8,4.8 )when estimating the mean height​ (in centimeters) of a sample of seedlings.

Answers

Answer: The estimated margin of error = 0.5 centimeter

The sample mean = 4.3 centimeters

Step-by-step explanation:

The confidence interval for population  mean is given by :-

[tex]\overline{x}\pm E[/tex]

or [tex](\overline{x}-E,\ \overline{x}+E)[/tex]

, where [tex]\overline{x}[/tex] = sample mean.

E = Margin of error .

The given confidence interval : (3.8,4.8 )

Lower limit : [tex]\overline{x}-E=3.8[/tex]                (1)

Upper limit =  [tex]\overline{x}+E=4.8[/tex]                (2)

Eliminate equation (1) from (2) , we get

[tex]2E=1.0\\\\\Rightarrow\ E=\dfrac{1}{2}=0.5[/tex]

⇒ The estimated margin of error = 0.5 centimeter

Add (1) and (2) ,we get

[tex]2\overline{x}-E=8.6\\\\\Rightarrow\ \overline{x}=\dfrac{8.6}{2}=4.3[/tex]  

⇒ The sample mean = 4.3 centimeters

All questions answer help me! I need it right now! Step by step explain please!

Answers

Answer:

C

Step-by-step explanation:

Just by looking at the chart the answer concludes the correct equation for the graph hope this helps CORRECT ME IF I'M WRONG

ps: is that you on your profile picture?

Answer:

A

Step-by-step explanation:

1.9

A

A mixture of 5 pounds of fertilizer A, 13 pounds of fertilizer B, and 4 pounds of fertilizer C provides the optimal nutrients for a plant. Commercial brand X contains equal parts of fertilizer B and fertilizer C. Commercial brand Y contains one part of fertilizer A and two parts of fertilizer B. Commercial brand Z contains two parts of fertilizer A, five parts of fertilizer B, and two parts of fertilizer C. How much of each fertilizer brand is needed to obtain the desired mixture?

Answers

Final answer:

The optimal mixture to compose the desired fertilizer can be obtained using 17 lbs of Brand X, 6 lbs of Brand Y, and 8 lbs of Brand Z.

Explanation:

To solve this problem, let us denote X as the amount of brand X, Y as the amount of brand Y, and Z as the amount of brand Z. Since brand X contains equal parts of fertilizers B and C, and the optimal nutrients contain 13 lbs of B and 4 lbs of C, we can say that X = 13 lbs + 4 lbs = 17 lbs.

Brand Y contains one part of A and two parts of B. As we know from the problem that we need 5 lbs of A and 13 lbs of B, we get the equation Y = 5/3 lbs + 13/3 lbs = 6 lbs of Y. This equation is derived from the fact that for every 3 lbs of Y, you get 1.lb of A and 2 lbs of B.

Lastly, brand Z contains two parts of A, five parts of B, and four parts of C. So, Z could be calculated by the combined remainder of A, B and C i.e. (5 - 5/3 lbs) of A, (13 - 13 lbs) of B, and (4 - 4 lbs) of C which will get you approximately 8 lbs of brand Z.

So, you would need roughly 17 lbs of brand X, 6 lbs of brand Y, and 8 lbs of brand Z to create the desired fertilizer mixture.


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A random number generator is used to create a list of 300 single-digit numbers. Of those 300 numbers, 146 are odd and 154 are even. The number 8 was generated 22 times. What is the experimental probability of an even number other than 8 being generated

Answers

Answer:

0.44

Step-by-step explanation:

The total numbers drawn = 300

Out those 146 are odd and 154 are even.

The number 8 was drawn = 22 times

So, the number of times an even number other than 8 = 154 -22 = 132

The experimental probability = The number of favorable outcomes ÷ The number of possible outcomes.

The experimental probability of an even number other than 8 being generated = [tex]\frac{132}{300}[/tex]

Simplify the above fraction to decimal, we get

= 0.44

Therefore, the answer is 0.44

Amaya has a store credit of 50.86 she plans to purchase a video game for $24.97 and a golf club accessory for $6.99 how much store credit will she have left

Answers

Amaya will have $18.90 store credit left.

Step-by-step explanation:

Available store credit = $50.86

Cost of video game = $24.97

Cost of golf club accessory = $6.99

Total amount spent = Cost of video game + cost of golf club accessory

[tex]Total\ amount\ spent=24.97+6.99\\Total\ amount\ spent=\$31.96[/tex]

Remaining store credit = Available store credit - total amount spent

[tex]Remaining\ store\ credit=50.86-31.96\\Remaining\ store\ credit=\$18.90[/tex]

Amaya will have $18.90 store credit left.

Keywords: Addition, subtraction

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I love sharks! In fact, before I became a statistician, I wanted to be a marine biologist specializing in shark research (I even went to school for it for a little while). Of particular interest to me were hammerheads and great whites.
Great white sharks are big and hungry. The lengths of 44 great white sharks tagged near False Bay, South Africa had a mean of 15.6 ft with standard deviation 2.5 feet. Based on this sample, is there evidence that the mean length of great white sharks near False Bay are greater than 15 feet? Use a significance level, α = 0.10.
State the null hypothesis.

Answers

Answer:

Null hypothesis: [tex]\mu \leq 15[/tex]

Alternative Hypothesis: [tex]\mu >15[/tex]

We have enough evidence to reject the null hypothesis at 10% level of significance.

Step-by-step explanation:

1) Data given

n =44, representing the sample size

[tex]\bar X=15.6ft[/tex] represent the sample mean for the length of great white sharks

[tex]s=2.5ft[/tex] represent the sample standard deviation for the  length of great white sharks

[tex]\alpha =0.1[/tex] significance level for the test

2) Formulas to use

On this case we are intereste on the sample mean for the  length of great white sharks, and based on the paragraph the hypothesis are given by:

Null hypothesis: [tex]\mu \leq 15[/tex]

Alternative Hypothesis: [tex]\mu >15[/tex]

since we have n>30 but we don't know the population deviation [tex]\sigma[/tex] so we will can use the t approximation. The sample mean have the following distribution

[tex]\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})[/tex]

Based on this the statistic to check the hypothesis would be given by:

[tex]t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}[/tex]

Replacing the values given we have:

[tex]t_{calc}=\frac{15.6-15}{\frac{2.5}{\sqrt{44}}}=1.592[/tex]

We can calculate the degrees of freedom with:

[tex]df=n-1=44-1=43[/tex]

With [tex]\alpha[/tex] and the degrees of freedom we can calculate the critical value, since [tex]\alpha=0.1[/tex] we need a value from the t distribution with 43 degrees of freedom that accumulates 0.1 of the area on the right or 0.9 of the area on the left.

We can use excel, a calculator or a table for this, calculating this value we got:

[tex]t_{(43,critc)}=1.302[/tex]

Since our calculatesd value was [tex]t_{calc}=1.592>t_{crit}[/tex], we can reject the null hypothesis at 0.1 level of significance.

Other way in order to have a criterion for reject or don't reject the null hypothesis is calculating the p value, on this case based on the alternative hypothesis the p value would be given by:

[tex]p_v=P(t_{(43)}>1.592)=0.0594[/tex]

So then [tex]p_v <\alpha[/tex] so we have enough evidence to reject the null hypothesis at 10% level of significance.

A rectangle is drawn so that the width is 3 feet shorter than the length. The area of the rectangle is 28 square feet. Find the length of the rectangle.

Answers

Answer:

  7 feet

Step-by-step explanation:

Assuming the dimensions are integers, we can look at the factors of 28:

  28 = 1·28 = 2·14 = 4·7

The last pair differs by 3, so can be the solution to the problem.

The length of the rectangle is 7 feet.

Write the equation of the linear relationship in slope-intercept form, using decimals as needed.
x 25 35 45 55
y 92.5 87.5 82.5 77.5

The equation that represents this relationship is y = ?

Answers

Final answer:

The equation of the linear relationship given the x and y coordinates is calculated in slope-intercept form by finding the slope and y-intercept. In this case, the equation of the line is y = -0.5x + 95.

Explanation:

In mathematics, the equation of a linear relationship can be represented in the slope-intercept form, which is y = mx + c.

Where, 'm' is the slope of the line and 'c' is the y-intercept.

Given the x and y coordinates, we can calculate the slope 'm' using the formula, m = (y2 - y1) / (x2 - x1).

For example: m = (87.5-92.5) / (35-25) = -5 / 10 = -0.5. So the slope 'm' is -0.5.

Now we can find the y-intercept 'c' by substituting the known x,y coordinates and the slope into the equation and solving for 'c'. Let's take x = 25 and y = 92.5, substituting these values, we will get c = y - mx =  92.5 - (-0.5 * 25) = 95.

So, the equation of the straight line in slope-intercept form is y = -0.5x + 95.

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2. Which coordinate divides the directed line segment from –10 at J to 23 at K in the ratio of 2 to 1? Explain.
A. 1
2. 11
C. 12​

Answers

Answer:

12

Step-by-step explanation:

x=(-10×1+23×2)÷(2+1)=36/3=12

Final answer:

The coordinate that divides the line segment from -10 at J to 23 at K in the ratio of 2 to 1 is C) 12.

Explanation:

The coordinate that divides the line segment from -10 at J to 23 at K in the ratio of 2 to 1 is 12.

To find this coordinate, we can use the concept of a section formula. Let the ratio be m:n. The coordinate divided is [tex](\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n})[/tex]. Substituting the values, we get [tex](\frac{2 ( 23) + 1 ( -10)}{2+1}, \frac{2 (0) + 1 ( 2)}{2+1})[/tex] = (12, 0).

Therefore, the required coordinate that divides the line segment in the ratio of 2 to 1 is C) 12.

At a recent track meet the fastest time in the 40-yard dash was 4.37 seconds on the slowest time was 5.08 seconds what is the difference between the fastest and slowest time

Answers

Final answer:

The difference between the fastest and slowest time in the 40-yard dash is 0.71 seconds.

Explanation:

The difference between the fastest and slowest time in the 40-yard dash can be found by subtracting the slowest time from the fastest time. In this case, the fastest time was 4.37 seconds and the slowest time was 5.08 seconds. To find the difference, we subtract 5.08 seconds from 4.37 seconds.

The difference between the fastest and slowest time is 0.71 seconds.

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Long-term studies of Belding's ground squirrels show that immigrants move nearly 2 km from where they are born and make up 1 to 8% of the males and 0.7 to 6% of the females in other populations. On an evolutionary scale, why is this significant?

Answers

Answer:

It is significant because when they migrate from one place to other it becomes a source of genetic diversity between them and other population.

Step-by-step explanation:

A sumo wrestling ring is circular and has a circumference of 4.6\pi \text{ meters}4.6π meters4, point, 6, pi, start text, space, m, e, t, e, r, s, end text. What is the area AAA of the sumo wrestling ring in square meters? Give your answer in terms of \piπpi. A=A=A, equals \text{m}^2m 2

Answers

Answer:

The area of the sumo wrestling ring is [tex]5.29 \pi[/tex]

Step-by-step explanation:

The circumference of the circular sumo wrestling ring is [tex]4.6\pi[/tex], that means its radius [tex]r[/tex] is:

[tex]2\pi r=4.6\pi[/tex]

[tex]r=\frac{4.6}{2} =\boxed{2.3\:meters.}[/tex]

Now once we have the radius [tex]r[/tex] of the sumo wrestling ring we can find its area [tex]A[/tex] by the following formula:

[tex]A=\pi r^2[/tex]

Putting in the value of [tex]r=2.3\:meters[/tex] we get:

[tex]A=\pi (2.3m)^2=\boxed{5.29\pi\:\:m^2}[/tex]

Therefore the area of the sumo wrestling ring is [tex]{5.29\pi\:\:m^2[/tex]

Answer:

5.29pi

Step-by-step explanation:

Which is the best interpretation of the solution set for the compound inequality?
3(2x + 1) > 21 or 4x + 3 < 3x +7
no solution
3 Ox<3 or x > 4
all real numbers

Answers

For this case we must find the solution set of the given inequalities:

Inequality 1:

[tex]3 (2x + 1)> 21[/tex]

Applying distributive property on the left side of inequality:

[tex]6x + 3> 21[/tex]

Subtracting 3 from both sides of the inequality:

[tex]6x> 21-3\\6x> 18[/tex]

Dividing by 6 on both sides of the inequality:

[tex]x> \frac {18} {6}\\x> 3[/tex]

Thus, the solution is given by all the values of "x" greater than 3.

Inequality 2:

[tex]4x + 3 <3x + 7[/tex]

Subtracting 3x from both sides of the inequality:

[tex]4x-3x + 3 <7\\x + 3 <7[/tex]

Subtracting 3 from both sides of the inequality:

[tex]x <7-3\\x <4[/tex]

Thus, the solution is given by all values of x less than 4.

The solution set is given by the union of the two solutions, that is, all real numbers.

Answer:

All real numbers

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