A balloon contains 0.158 mol of gas and has a volume of 2.46 l. if an additional 0.113 mol of gas is added to the balloon (at the same temperature and pressure), what is its final volume?
Answer is: final volume is 4.21 liters.
Use Avogadro's Law (the Volume Amount Law): If the amount of gas in a container is increased, the volume increases.
The volume-amount fraction will always be the same value if the pressure and temperature remain constant.
V₁ / n₁ = V₂ / n₂.
2.46 l / 0.158 mol = V₂ / 0.271 mol.
V₂ = 4.21 l.
To find the final volume of the balloon, we can use the combined gas law equation. The initial pressure is calculated using the number of moles and volume. This pressure, along with the final number of moles, initial volume, and constant temperature, can be used to find the final volume.
Explanation:To solve this problem, we can use the combined gas law equation (P1V1/T1 = P2V2/T2) which relates the pressure, volume, and temperature of a gas. Since the temperature and pressure remain constant, we can use the equation to find the final volume. First, calculate the initial pressure by dividing the number of moles by the volume. Then substitute the initial pressure, final number of moles, and initial volume into the equation, and solve for the final volume.
Given:
N1 = 0.158 mol
N2 = 0.113 mol
V1 = 2.46 L
V2 = ?
P1 = N1/V1
Substituting the values:
P1 = 0.158 mol / 2.46 L = 0.0642 atm
Now, substitute the values into the combined gas law equation:
P1V1/T1 = P2V2/T2
Solving for V2:
V2 = (P1V1T2) / (P2T1)
Since the temperature and pressure remain constant, we can write the equation as:
V2 = (P1V1) / P2
Substituting the values:
V2 = (0.0642 atm * 2.46 L) / (0.113 mol) = 1.396 L
The final volume of the balloon is 1.396 L.
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Diffusion of nonpolar molecules would not be affected by
Diffusion of nonpolar molecules is does not affected by charge. Because they have no partial charges. Hence option d is correct.
What is diffusion?Diffusion of substance is the spreading or transfer of compounds based on concentration gradient or pressure gradient. Molecules diffuses from higher concentration region to lower concentration region.
Non-polar molecules are those which have no permanent dipole moment. They have no partial charges formed during chemical bonding. Whereas, polar compounds are those having permanent dipole moment and are having partial charges.
All other factors, such as temperature, pressure, concentration and molecular size will affect the rate of diffusion. Thus for non-polar compounds charge is affecting the diffusion.
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Your question is incomplete but your complete question probably was:
Diffusion of nonpolar molecules would not be affected by
a.molecule size.
b.steepness of the concentration gradient.
c.temperature.
d.charge.
e.steepness of the pressure gradient
Which equation expresses Newtons second law of motion
A 41.0 ml barium hydroxide solution of molarity 3.41 m is diluted with water to form 279 ml of solution. calculate the molarity of the solution
The molarity of the diluted barium hydroxide solution is approximately 0.5018 M.
The molarity of the diluted solution is calculated by using the formula for molarity (M), which is:
[tex]\[ M = \frac{\text{moles of solute (n)}}{\text{volume of solution (V)}} \][/tex]
When a solution is diluted, the number of moles of solute remains constant. Therefore, we can equate the moles of solute in the concentrated solution to the moles of solute in the diluted solution:
[tex]\[ n_{\text{concentrated}} = n_{\text{diluted}} \][/tex]
Given that the molarity (M) is the number of moles of solute per liter of solution, we can write:
[tex]\[ M_{\text{concentrated}} \times V_{\text{concentrated}} = M_{\text{diluted}} \times V_{\text{diluted}} \][/tex]
We are given:
- [tex]\( M_{\text{concentrated}} = 3.41 \)[/tex] M (molarity of the concentrated barium hydroxide solution)
- [tex]\( V_{\text{concentrated}} = 41.0 \)[/tex] ml (volume of the concentrated solution, which we will convert to liters)
- [tex]\( V_{\text{diluted}} = 279 \)[/tex] ml (volume of the diluted solution, which we will also convert to liters)
First, we convert the volumes from milliliters to liters:
[tex]\( V_{\text{concentrated}} = 41.0 \) ml \( = 41.0 \times 10^{-3} \) L\\ \( V_{\text{diluted}} = 279 \) ml \( = 279 \times 10^{-3} \) L[/tex]
Now we can solve for [tex]\( M_{\text{diluted}} \)[/tex]:
[tex]\[ M_{\text{diluted}} = \frac{M_{\text{concentrated}} \times V_{\text{concentrated}}}{V_{\text{diluted}}} \] \[ M_{\text{diluted}} = \frac{3.41 \times 41.0 \times 10^{-3}}{279 \times 10^{-3}} \] \[ M_{\text{diluted}} = \frac{3.41 \times 41.0}{279} \] \[ M_{\text{diluted}} = \frac{140.01}{279} \] \[ M_{\text{diluted}} \approx 0.5018 \text{ M} \][/tex]
If 5.400 g of c6h6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °c, what is the final temperature of the water?
The final temperature of the water : 30.506 °C
Further explanationThe law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released
Qin = Qout
Heat can be calculated using the formula:
Q = mc∆T
m = mass, g
∆T = temperature difference, °C / K
From reaction:
2C₆H₆ (l) + 15O₂ (g) ⟶12CO₂ (g) + 6H₂O (l) +6542 kJ, heat released by +6542 kJ to burn 2 moles of C₆H₆
If there are 5.400 g of C₆H₆ then the number of moles:
mol = mass: molar mass C₆H₆
mol = 5.4 : 78
mol C₆H₆ = 0.0692
so the heat released in combustion 0.0692 mol C₆H₆:
[tex]\rm Q=heat=\dfrac{0.0692}{2}\times 6542\:kJ\\\\Q=226.353\:kJ[/tex]
the heat produced from the burning is added to 5691 g of water at 21 C
So :
Q = m . c . ∆T (specific heat of water = 4,186 joules / gram ° C)
226353 = 5691 . 4.186.∆T
[tex]\rm \Delta T=\dfrac{226353}{5691\times 4.186}\\\\\Delta T=9.506\\\\\Delta T=T(final)-Ti(initial)\\\\9.506=T_f-21\\\\T_f=30.506\:C[/tex]
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Based on the entries in the following table, which element is most commonly bonded to the acidic hydrogen? table some weak acids in water at 25 ∘c
Final answer:
Hydrogen bonding in acids, solvation energy terms, and the impact of strong acids on conjugate bases are crucial concepts in understanding acid dissociation and acid-base behavior in solution.
Explanation:
Hydrogen bonding occurs when a hydrogen atom, part of a polar covalent bond, is bonded to a more electronegative atom. In the case of acids, hydrogen bonds form between the hydrogen atom of the acid (H-A) and water molecules. This results in the acid dissociation process, where the acid molecule becomes an anion.
Solvation energy terms play a crucial role in driving hydrogen ion transfer in solution. Despite thermodynamic considerations indicating that most strong Brønsted acids should not act as acids towards water, solvation energy terms, aided by entropic effects, drive hydrogen ion transfer in solution.
In general, strong acids form very weak conjugate bases, while weak acids form stronger conjugate bases. Water has a leveling effect on dissolved acids, generating hydronium and hydroxide ions, the strongest acid and base in water.
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According to Ampere, which of the following sets of current-carrying wires would repel each other? The arrow point indicates the direction of the current in each wire.
Answer: Option (c) is the correct answer.
Explanation:
When current passes through a wire then a magnetic field is formed. Therefore, when two wires carry current in the same direction then both the wires with have respective magnetic fields in the same direction and their total magnetic field will be large.
But when current between two wires flow in opposite direction then the magnetic field produced will also be in opposite direction. Therefore, both the magnetic fields cancel each other out. Thus, total magnetic field will be small.
As a result, wires which carry current in the opposite direction repel each other.
If 3.0 moles of x and 4.0 moles of y react according to the hypothetical reaction below, how many moles of the excess reactant will be left over at the end of the reaction? x + 2 y yields xy2
Which compound will form an acidic solution when dissolved in water? which compound will form an acidic solution when dissolved in water? nano2 khso4 kbr ba(no3)2?
Among the compounds NaNO2, KHSO4, KBr, and Ba(NO3)2, KHSO4 forms an acidic solution when dissolved in water. It can donate a proton, subsequently increasing the concentration of hydronium ions. The other compounds do not result in an increased concentration of hydronium ions and thus, do not form acidic solutions.
Explanation:When you're determining which of these compounds--NaNO2, KHSO4, KBr, Ba(NO3)2--forms an acidic solution when dissolved in water, it's important to understand how compounds behave in water. Most notably, you should know that an acidic solution contains a greater concentration of hydronium ions (H3O+) than hydroxide ions (OH-).
Sulfuric acid is a diprotic acid, which means it can donate two protons. It forms both sulfates and hydrogen sulfates in solution, and most of these compounds moderate the pH when dissolved in water. Consequently, KHSO4 is the compound that will result in an acidic solution, since upon dissolution, it can donate a proton and thereby increase the concentration of H3O+ ions.
As a note, the other compounds listed (NaNO2, KBr, Ba(NO3)2) do not increase the concentration of H3O+ ions; thus, they won't form acidic solutions. For instance, Ba(NO3)2 in a neutralization reaction with water will form a neutral salt and water.
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A chemical reaction takes place in which energy is absorbed arrange the characteristics of the reaction in order from start to finish
Which statement(s) correctly describe the fissionable material used in a nuclear power plant?
renewable resource unstable isotopes source of thermal energy poses health problems
Ans: unstable isotopes
source of thermal energy
poses health problems
A nuclear power plant generates nuclear energy which is a non-renewable resource. Essentially a heavy unstable radioisotope splits in a nuclear reactor and generates large amounts of heat. Hence a nuclear power plant is a source of thermal energy.
The fissionable material in a reactors core is usually a radioisotope like Uranium(U-235). The splitting of the uranium nucleus also generates other radioactive fission products, which might leak into the surroundings in case of any accidents. Hence, nuclear reactors pose health problems.
Ionizing radiation can harm a person's health right away at large levels, and at very high doses, it can even result in radiation sickness and death. Ionizing radiation can have negative health effects at low levels, including cataracts, cardiovascular disease, and cancer. All the given options are correct.
What is a fissionable material?Because the binding energy produced by a neutron's absorption is more than the critical energy needed for fission, uranium-235 is a fissile substance and fissions with low-energy thermal neutrons. Nuclear explosions, fast-neutron reactors, and thermal-neutron reactors can all be powered by fissile material.
The fuel that nuclear power plants most frequently use for nuclear fission is uranium. Even though uranium is a common metal found in rocks all over the world, it is regarded as a nonrenewable energy source. Because the atoms of a particular type of uranium, known as U-235, are simple to separate, nuclear power plants use it as fuel.
Inside a nuclear power plant's reactor, fission occurs. The core of the reactor is where the uranium fuel is located.
Thus the given options are correct.
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A certain hydrocarbon (a compound consisting of carbon and hydrogen) is 82.66% carbon by mass and has a molar mass of 58.12 g. determine the molecular formula of this hydrocarbon.
The molecular formula of the hydrocarbon is C4H8.
Explanation:The molecular formula of the hydrocarbon can be determined using the given information. Since the compound is 82.66% carbon by mass, we can assume that the remaining percentage is hydrogen. The molar mass of the compound is 58.12 g/mol.
To find the molecular formula, we need to determine the empirical formula first. We assume 100 g of the compound, so 82.66 g is carbon and 17.34 g is hydrogen. Using the molar mass and the atomic masses of carbon and hydrogen, we can determine the moles of each element.
The empirical formula is CH2, and the molar mass of CH2 is 14.03 g/mol. To find the molecular formula, we divide the molar mass of the compound (58.12 g/mol) by the molar mass of CH2 (14.03 g/mol). The result is approximately 4.15. We round this to the nearest whole number, which gives us a molecular formula of C4H8.
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When writing 6,020,000 in scientific notation, it is correctly written as: 6.02 x 106 6.02 x 10-6 602. x 106 0.602 x 10-8
6.02 x 10^6 is correct it's not negative because youre moving in the positive direction in terms of sci not.
Please help! ill give medal
26. Write the general chemical formula for an acid, and discuss what each component of the formula represents. (3 points)
When copper (ii) carbonate is heated if forms copper (ii) oxide and carbon dioxide?
Many manufacturing processes involve chemical reactions that reach equilibrium. Why would chemists adjust conditions to favor the forward reaction in a process
Determine the number of particles in each of the following. Show the unit conversion method. A. 0.250 mol silver B. 8.56 x 10-3 mol NaCl C. 35.4 mol CO2 D. 0.425 mol N2
The number of particles in A is 1.506 x 10²³, in B is 5.156 x 10²⁰, in C is 2.131 x 10²⁵, and in D is 2.559 x 10²³.
What is the number of particles in the given elements or compounds?To determine the number of particles in each of the following substances, it is required to use Avogadro's number, which is 6.022 x 10²³ particles per mole. We can use dimensional analysis, also known as the unit conversion method, to convert from moles to particles.
A. 0.250 mol silver
Number of particles = 0.250 mol x 6.022 x 10²³ particles/mol
Number of particles = 1.506 x 10²³ particles
B. 8.56 x 10⁻³ mol NaCl
Number of particles = 8.56 x 10⁻³ mol x 6.022 x 10²³ particles/mol
Number of particles = 5.156 x 10²⁰ particles
C. 35.4 mol CO₂
Number of particles = 35.4 mol x 6.022 x 10²³ particles/mol
Number of particles = 2.131 x 10²⁵ particles
D. 0.425 mol N₂
Number of particles = 0.425 mol x 6.022 x 10²³ particles/mol
Number of particles = 2.559 x 10²³ particles
Therefore, there are approximately 1.506 x 10²³ particles in 0.250 mol of silver, 5.156 x 10²⁰ particles in 8.56 x 10⁻³ mol of NaCl, 2.131 x 10²⁵ particles in 35.4 mol of CO₂, and 2.559 x 10²³ particles in 0.425 mol of N₂.
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Dissolving 25.00 g cucl2 in enough water to make 250 ml of solution gives a solution concentration equal to
The concentration of the solution made by dissolving 25.00 g of CuCl2 in enough water to make 250 mL of solution is 0.74 M.
Explanation:In this question, we are dealing with molarity calculation. The molarity of a solution is determined by the formula: Molarity (M) = moles of solute/volume of solution in liters. But first, we need to convert the mass of CuCl2 into moles. CuCl2 has a molar mass of about 134.45 g/mol. So, we divide 25.00 g CuCl2 by 134.45 g/mol which equals 0.185 moles. The volume of the solution is 250 mL, which we convert to liters to match the units in the molarity formula. This gives us 0.250 L. We now substitute these values into the molarity formula - M = 0.185 moles/0.250 L = 0.74 M. Therefore, the concentration of the solution is 0.74 M.
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Calculate the mass of water produced when 6.97 g of butane reacts with excess oxygen
Summarize your conclusion about how temperature difference and humidity affect weather conditions
Answer:
Increasing the temperature Decreases the humidity and vice versa
Explanation:
When the temperature is increasing, the air can hold more water molecules ,thereby making the humidity to reduce. A high humidity will make the weather to be more hotter because the body sweat will not evaporate easily. A low humidity makes the weather cooler due to the fact the body sweat evaporate easily .
An atom of potassium loses one electron. what does it become a negative potassium, positive potassium
The astronaut then measures the abundance of magnesium on the new planet, obtaining the following results:
Isotope Abundance (%) Mass (amu)
86 Sr 9.46 85.91
87 Sr 7.00 86.91
88 Sr 83.54 87.91
What is the atomic mass of magnesium for this planet?
Express your answer to two decimal places, and include the appropriate units.
Answer: The average atomic mass of Strontium is 87.65 u
Explanation:
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
[tex]\text{Average atomcic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i[/tex] .....(1)
For [tex]_{38}^{86}\textrm{Sr}[/tex] isotope:Mass of [tex]_{38}^{86}\textrm{Sr}[/tex] isotope = 85.91 u
Percentage abundance of [tex]_{38}^{86}\textrm{Sr}[/tex] isotope = 9.46 %
Fractional abundance of [tex]_{38}^{86}\textrm{Sr}[/tex] isotope = 0.09460
For [tex]_{38}^{87}\textrm{Sr}[/tex] isotope:Mass of [tex]_{38}^{87}\textrm{Sr}[/tex] isotope = 86.91 u
Percentage abundance of [tex]_{38}^{87}\textrm{Sr}[/tex] isotope = 7.00 %
Fractional abundance of [tex]_{38}^{87}\textrm{Sr}[/tex] isotope = 0.0700
For [tex]_{38}^{88}\textrm{Sr}[/tex] isotope:Mass of [tex]_{38}^{88}\textrm{Sr}[/tex] isotope = 87.91 u
Percentage abundance of [tex]_{38}^{88}\textrm{Sr}[/tex] isotope = 83.54 %
Fractional abundance of [tex]_{38}^{88}\textrm{Sr}[/tex] isotope = 0.8354
Putting values in equation 1, we get:
[tex]\text{Average atomic mass of Sr}=[(85.91\times 0.0946)+(86.91\times 0.0700)+(87.91\times 0.8354)][/tex]
[tex]\text{Average atomic mass of Sr}=87.65u[/tex]
Hence, the average atomic mass of Strontium is 87.65 u
Assuming complete dissociation, what is the ph of a 4.02 mg/l ba(oh)2 solution?
Answer: The pH of the solution is 9.68
Explanation:
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}[/tex]
We are given:
Mass of solute (barium hydroxide) = 4.02 mg = 0.00402 g (Conversion factor: 1 g = 1000 mg)
Molar mass of barium hydroxide = 171.34 g/mol
Volume of solution = 1 L
Putting values in above equation, we get:
[tex]\text{Molarity of solution}=\frac{0.00402g}{171.34g/mol\times 1L}\\\\\text{Molarity of solution}=2.4\times 10^{-5}M[/tex]
To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOH of the solution, we use the equation:
[tex]pOH=-\log[OH^-][/tex]
On complete dissociation, 1 mole of barium hydroxide produces 2 moles of hydroxide ions
We are given:
[tex][OH^-]=4.8\times 10^{-5}M[/tex]
Putting values in above equation, we get:
[tex]pOH=-\log(4.8\times 10^{-5})\\\\pOH=4.32[/tex]
To calculate pH of the solution, we use the equation:
[tex]pH+pOH=14\\pH=14-4.32=9.68[/tex]
Hence, the pH of the solution is 9.68
Considering the definition of pH, pOH and strong base, the pH of a 4.02 mg/L Ba(OH)₂ solution is 9.67.
You have a 4.02 mg/L Ba(OH)₂ solution. Being the molar mass (that is, the mass of one mole of a substance, which can be an element or a compound.) of barium hydroxide 171.34 g/mole, and being 1 mg=0.001 g then, the amount of moles that contain 4.02 mg of Ba(OH)₂ can be calculated as:
[tex]4.02 mgx\frac{0.001 grams}{1 mg} x\frac{1 mole}{171.34 grams} =[/tex] 2.35×10⁻⁵ moles
Then, the concentration of the Ba(OH)₂ solution is 2.35×10⁻⁵[tex]\frac{moles}{L}[/tex]=2.35×10⁻⁵ M.
On the other side, a Strong Base is that base that in an aqueous solution completely dissociates into the cation and hydroxide ion.
In this case, Ba(OH)₂ is a strong base. Then, the dissociation reaction will be:
Ba(OH)₂ → Ba²⁺ + 2 OH⁻
Since Ba(OH)₂ will completely dissociate in water, you can observe that the concentration of OH⁻ will be twice the concentration of Ba(OH)₂.
So, [OH⁻]= 2×2.35×10⁻⁵ M
[OH⁻]= 4.7×10⁻⁵ M
pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
So, in this case:
pOH= - log (4.7×10⁻⁵ M)
pOH= 4.33
pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
The following relationship can be established between pH and pOH:
pH + pOH= 14
Being pOH= 4.33, pH is calculated as:
pH + 4.33= 14
pH= 14 - 4.33
pH= 9.67
Finally, the pH of a 4.02 mg/L Ba(OH)₂ solution is 9.67.
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Answer:
- Both of their valence electrons are at p subshell.
- They have the first subshell full of electrons.
- Both of them have just 1 electron at the last p subshell.
Explanation:
Hello,
In this case, we could understand their electron structures by identifying their electron configurations as shown below:
[tex]B^5\rightarrow 1s^2,2s^2,2p^1\\Al^{13}\rightarrow 1s^2,2s^2,2p^6,3s^2,3p^1[/tex]
In such a way, we could notice the following similarities:
- Both of their valence electrons are at p subshell.
- They have the first subshell full of electrons.
- Both of them have just 1 electron at the last p subshell.
Best regards.
What is the estimated effective nuclear charge, Z eff, experienced by an electron in a 3p orbital of a chlorine atom?
a. -1
b. 5
c. 7
d. 17,
The estimated effective nuclear charge (Zeff) experienced by an electron in the 3p orbital of a chlorine atom is approximately 7, as inner electrons shield the nucleus' full charge of 17. This is derived from considering the electron configuration of chlorine and the shielding effects provided by inner electrons.
Explanation:The question is asking about the effective nuclear charge (Zeff) experienced by an electron in the 3p orbital of a chlorine atom. The effective nuclear charge is the net positive charge an electron feels after accounting for the shielding effect of the other electrons. A neutral chlorine atom has an atomic number of 17, which means there are 17 protons in the nucleus. However, the effective nuclear charge felt by an electron in the 3p orbital is not the full charge of 17 due to the shielding of the electrons in closer orbitals.
The electron configuration of a neutral chlorine atom is 1s22s22p63s23p5. The 10 electrons in the 1s, 2s, and 2p orbitals shield the 3p electrons from the full nuclear charge. Using Slater's rules, one can estimate the effective nuclear charge felt by a 3p electron. The value of Zeff is typically between 1 and the actual nuclear charge (Z), which is 17 for chlorine. The exact Zeff would require taking into account the actual amount of shielding provided by the inner electrons, which tends to be a complex calculation considering electron-electron interactions and the distribution of electron density.
However, based on Slater's rules and shielding effects, a rough estimate for the Zeff would be closer to the chlorine's atomic number (17) than to 1, making options a (-1) and b (5) incorrect. Since the 10 inner electrons shield the nuclear charge, a reasonable estimate for Zeff for a 3p electron in chlorine might be around 7 (17 nuclear charge - 10 shielding electrons), but advanced calculations are required for a precise value. Therefore, answer choice c (7) seems to be the most appropriate estimate based on basic principles.
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0 ml of a 1.20 m solution is diluted to a total volume of 228 ml. a 114-ml portion of that solution is diluted by adding 111 ml of water. what is the final concentration? assume the volumes are additive.
The final concentration of the solution after the described dilution process is approximately 0.00855 M.
Let's first ascertain the original dilution's concentration. Using the dilution equation:
[tex]C_1V_1 = C_2V_2[/tex]Where:
C₁ = 1.20 M (initial concentration)V₁ = 0 mlV₂ = 228 mlC₂ = final concentration after the first dilutionSince 0 ml is a typo, let us assume the starting volume V₁ is enough such as 1 mL. Plugging in the values:
(1.20 M)(1 ml) = (C₂)(228 ml)C₂ = 1.20 / 228Now, calculate the concentration after the second dilution:
V₁ = 114 mlV₂ = 114 ml + 111 ml = 225 mlUsing the intermediate solution:
[tex]C_1V_1 = C_2V_2[/tex]
The final concentration after the second dilution is about 0.00855 M.
Consider the following reaction. 2Fe2O3 --> 4Fe + 3O2 deltaH = +824.2KJ The formation of 42.0 g of O2 results in? 1) the absorption of 361 kJ of heat. 2) the absorption of 11500 kJ of heat. 3) the absorption of 1080 kJ of heat.
The formation of oxygen in the reaction, the absorption of 361 kJ of heat takes place.
The heat of formation of oxygen will be
[tex]\rm \Delta H[/tex] is +824.2 kJ.
The positive sign of H denotes that the reaction accepts energy from the surroundings. It is an endothermic reaction.
In the reaction the % formation of Oxygen is :
Total product formed = 7 moles
Oxygen formed = 3 moles
% Oxygen formed = [tex]\rm \frac{3}{7}\;\times\;100[/tex]
% oxygen formed = 42.85 %
The total enthalpy for the formation of product is +824.2 kJ.
The enthalpy for the formation of 42.85 % Oxygen = +824.2 [tex]\times[/tex] 42.85 / 100 kJ.
The enthalpy of the formation of oxygen in the reaction will be 353.22 kJ.
The closest is 361 kJ.
So, for the formation of oxygen in the reaction, the absorption of 361 kJ of heat takes place.
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What equals the molar mass of a element
The molar mass of an element is equal to the element's atomic weight mentioned in the periodic table.
What is molar mass?
Molar mass of a compound or a molecule is defined as the mass of the elements which are present in it.The molar mass is considered to be a bulk quantity not a molecular quantity. It is often an average of the of the masses at many instances.
The molecular mass and formula mass are used as synonym for the molar mass.It does not depend on the amount of substance which is present in the sample.It has units of gram/mole.
Molar masses of an element are given as relative atomic masses while that of compounds is the sum of relative atomic masses which are present in the compound.The element's molar mass is mentioned in the box of the element's symbol in the periodic table.
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which of the following is an inorganic compound?
h2o water molecule
ch3(ch2)3ch3 pentane
c4h10 butane
c6h12o6 glucose,
Given concentration equilibrium constants (1) h3o +(aq) + noâ 2 (aq) ââ½ hno2(aq) + h2o, kc = 3.86 Ã 103 , (2) 2 h2o(â) ââ½ h3o +(aq) + ohâ(aq), kw = 1.0 Ã 10â14 , calculate kc for the reaction noâ 2 (aq) + h2o(â) ââ½ hno2(aq) + ohâ(aq).
Final answer:
To calculate the equilibrium constant for the reaction NO− 2 (aq) + H2O(l) → HNO2(aq) + OH−(aq), reverse the first given reaction, H3O+ + NO− 2 → HNO2 + H2O with Kc = 3.86 × 10³, and divide by the autoionization constant of water, Kw = 1.0 × 10−14, to obtain Kc = 3.86 × 10³17.
Explanation:
To calculate the equilibrium constant (Kc) for the chemical reaction NO− 2 (aq) + H2O(l) → HNO2(aq) + OH−(aq), we need to use the given equilibrium constants for related reactions and the autoionization of water.
The first reaction is:
H3O+ (aq) + NO− 2 (aq) ⇌ HNO2(aq) + H2O(l), Kc = 3.86 × 10³.The second reaction is the autoionization of water:
2H2O(l) ⇌ H3O+ (aq) + OH−(aq), Kw = 1.0 × 10−14.By reversing the first reaction and dividing its Kc by Kw, we can obtain the equilibrium constant for the reaction NO− 2 (aq) + H2O(l) → HNO2(aq) + OH−(aq):
Kc for the desired reaction = Kc for H3O+ + NO− 2 → HNO2 + H2O / KwKc for NO− 2 + H2O → HNO2 + OH− = 3.86 × 10³ / 1.0 × 10−14 = 3.86 × 10³17.