Calculate the mass of water produced when 3.03 g of butane reacts with excess oxygen.

In the given chemical reaction, if equal volumes of ethane ([tex]C_{2} H_{6}[/tex]) and oxygen ([tex]O_{2}[/tex]) are combined, ethane will be the gas left over after the reaction due to its larger required volume of oxygen for complete combustion. The exact volume of ethane remaining can be calculated using stoichiometry and the proportions of the balanced equation.

The balanced chemical reaction is

[tex]\[2C_2H_6(g) + 7O_2(g) \rightarrow 4CO_2(g) + 6H_2O(g)\][/tex]This implies that 2 moles of ethane [tex]C_{2} H_{6}[/tex] react with 7 moles of oxygen([tex]O_{2}[/tex]) to produce carbon dioxide ([tex]CO_{2}[/tex]) and water ([tex]H_{2} O[/tex]) by the process of combustion. As per Avogardo's law, the volume of gases is directly proportional to the number of moles, when the conditions (pressure, temperature) are kept constant.

Since you are starting with equal volumes of ethane and oxygen (14 L), and since ethane requires more oxygen to react (3.5 volumes of oxygen for each volume of ethane), there will not be enough oxygen present to react with all of ethane. Thus, it will be ethane ([tex]C_{2} H_{6}[/tex]) gas that is leftover after the reaction. The volume of that gas remaining can be calculated using stoichiometry and the proportions of the balanced equation.

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The density of urine decreases when a diabetic secretes too much sugar.

When there is excess sugar in the blood, the kidneys release extra water.

The result is a more dilute and therefore less dense urine.

The urine from a non-diabetic person usually has a density of 1.010 g/mL to 1.025 g/mL.

The urine from a diabetic person often has a density less than 1.008 g/mL.

The terms of a equation, the momentum of an object is equal to the mass of the object times the velocity of the object. where m is the mass and v is the velocity

Explanation: Genuine diamonds and imitation diamonds are different in terms of their strengths.

Strength is directly related to the density of the molecule.

High density means the molecule is hard as there will be no voids and the particles are closer to each other.

Lower density means that the molecule is soft because there will be voids present and the particles will be away from each other.

Genuine diamonds are hard in nature and hence they have high density while imitation diamonds can be broken down easily and hence they have has lower density.

The answer to your question is,

Metalloids. They are a mix of elements that are both metals and non-metals in one.

-Mabel <3

Answer:

The answer is 1.55 × 1024 on edg.

Explanation:

number with fewer significant figures.

the first and second answers i hope this helps :3

It would be Calcium: Ca

We can tell which atom has 20 electrons by looking on the periodic table. If we look at number 20 (the atomic number shows how many electrons and protons an atom has) it is Calcium (symbol Ca).

Correct answer=

gold is an element, it has a symbol of An

Hope it helped

Gold is an element, not a compound or a mixture. It is represented on the periodic table by the symbol Au and cannot be broken down into a simpler substance.

Gold is an element, not a compound or a mixture. It's one of the 118 known chemical elements, and it's represented on the periodic table by the symbol Au (from the Latin 'aurum'). As an element, gold consists of only one type of atom and cannot be broken down into a simpler substance. It differs from a compound, which is formed from two or more elements bonded together, and a mixture, where you can physically separate the individual components that make it up.

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Answer:

the answer is d

Explanation:

Answer: Option (D) is the correct answer.

Explanation:

When we use an object or substance in excess then it is likely that the substance will run out with time. But at the same time, if we use that substance according to its requirement and try to conserve it as much as we can then we can preserve the substance.

Hence, it is good to avoid wastage of a substance and balance its use according to the need.

Therefore, we can conclude that in the given situation yes, there is a problem with the solution as the need to conserve copper must be balanced with use.

             The three possible stereoisomers of 1,3-cyclopentanediol are as follow,

                  i) (1S,3R)-1,3-Cyclopentanediol

                  ii) (1R,3R)-1,3-Cyclopentanediol

                  iii)  (1S,3S)-1,3-Cyclopentanediol

Structures of all three compounds are attached below.

Stereoisomers: Also known as spatial isomers are those isomers which have same molecular formula and structural formula but the groups about the chiral center occupy different orientation in space.

Enantiomers: These are stereoisomers of each other which are non-identical mirror-images of each other.

Diastereomers: These are stereoisomers which are not mirror images of each other.

Meso Compounds: These are those isomers which are superimposible on its mirror image.

You must use 134 g O₂ to produce 118 g H₂O.

[tex]\%\text{ yield} = \frac{\text{actual yield}}{\text{theoretical yield}} \times 100 \%[/tex]

[tex]\text{Theoretical yield} = \text{Actual yield}\times \frac{100\%}{\%\text{ yield}} = \text{118 g }\times \frac{100 \%}{78.2 \%} = \text{150.9 g}[/tex]

M_r:          32.00    18.02  

         2H₂ + O₂ ⟶ 2H₂O

Moles of H₂O = 150.9 g H₂O × (1 mol H₂O/18.02 g H₂O) = 8.374 mol H₂O

Moles of O₂ = 8.374 mol H₂O × (1 mol O₂/2 mol H₂O) = 4.187 mol O₂

Mass of O₂ = 4.1877 mol O₂ × (32.00 g O₂/1 mol O₂) = 134 g O₂

I am not exactly sure the answer that you are looking for, but I will guess on what you might be looking for. If the weight of an object is greater than the weight of the liquid it's being put into, the object will sink. Although, it isn't necessarily just based upon weight, it is more dependent on density to decide if it'll float or sink.

Answer:

It will sink

Explanation:

Hi, this is the result of the Archimedes principle, that states that the push force an object receives from the liquid it is submerged in, is proportional to the volume it displace.

As can be seen in the figure, there are two opposite forces interacting, the weight of the object (P) and the push force (E).

In equations:

[tex]P=m*g[/tex] where g is gravity

[tex]E=\rho_{liq}*V_{liq}*g[/tex]

Also [tex]\rho_{liq}*V_{liq}=m_{liq}[/tex]

So: [tex]\frac{P}{E}=\frac{m*g}{m_{liq}*g}[/tex]

[tex]\frac{P}{E}=\frac{m}{m_{liq}}[/tex]

If m is higher than m_liq, it means that P is higher than E and the object will sink.

Erosion caused the grand canyon to form

This would be either chemical weathering or erosion.

See, the rock was broken down and cracked by any sort of weathering or erosion. It could've been caused by either one of those, honestly.

Have a great day :)

The reaction used 82 g of the unknown chemical.

The word equation is  

Chemical 1 + Chemical 2 → Products  

     32 g    +         x g        →     114 g  

The Law of Conservation of Mass tells us the total mass of the reactants must equal the mass of the products. Then  

32 g + x g = 114 g  

x = 114 – 32 = 82

The mass of Chemical 2 was 82 g.  

Copper wire

Metal is one of best conductors for heat

Answer is: enthalpy is 155.65 kJ.

Reaction 1: N₂(g) + O₂(g) → 2NO(g); ΔrH₁ = 180.7 kJ.

Reaction 2: 2NO(g) + O₂(g) → 2NO₂(g); ΔrH₂ = -113.1 kJ.

Reaction 3: 2N₂O → 2N₂(g) + O₂(g); ∆rH₃ = -163.2 kJ.

Reaction 4: N₂O(g) + NO₂(g) → 3NO(g); ΔrH₄ = ?.

Using Hess's law reaction number 4 is sum of reaction number 1 and half of reaction number 3 minus half of the reaction number 2.

ΔrH₄ = ΔrH₁ + 1/2ΔrH₃ - 1/2ΔrH₂.

ΔrH₄ = 180.7 kJ + 1/2 · (-163.2 kJ) - 1/2 · (-113.1 kJ).

ΔrH₄ = 155.65 kJ.

Hess's law states that the enthalpy change in the chemical reaction is same, whether the reaction takes place in one or several steps. For the given equation, the enthalpy change of overall reaction is 155. 65 kJ.

[tex]\begin{aligned}\text{N}_2(\text{g})2\text{NO}(\text{g})+\text{O}_2(\text{g})\text{O}_2(\text{g})2\text{N}_2\text{O}(\text{g})\rightarrow2\text{NO}(\text{g}),2\text{NO}_2(\text{g}),2\text{N}_2(\text{g})+\text{O}_2(\text{g})\end{aligned}[/tex]

Given that,

1. The enthalpy change for the reaction between nitrogen and oxygen to form nitrogen oxide is:

2. The enthalpy change in the reaction between nitrogen oxide and oxygen to form nitrogen dioxide will be:

3.  The enthalpy change in breakdown of nitrous oxide to form nitrogen and oxygen:

4. The reaction between nitrous oxide and nitrogen dioxide will from nitrogen oxide as:

Using Hess's law on the fourth reaction, we get sum of first reaction and halved the enthalpy change of second and third reaction.

[tex]\begin{aligned}\Delta\text{rH}_4&=\Delta\text{rH}_1+\frac{1}{2}\Delta\text{rH}_3-\frac{1}{2}\Delta\text{rH}_2\\&=180.7\text{kJ}+\frac{1}{2}\times(-163.2\text{kJ})-\frac{1}{2}\times(-113.1\text{kJ})\\&=155.65\text{kJ}\end{aligned}[/tex]

Therefore, the enthalpy change for the equation will be 155.65 kJ.

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The partial pressure of N2 gas in the flask, after subtracting the vapor pressure of water from the total pressure, is 720 torr.

To determine the partial pressure of N2 gas collected over water, we must subtract the vapor pressure of water from the total pressure of the collected gas according to Dalton's law of partial pressures. Given that the total pressure is 760 torr and the vapor pressure of water at 34°C is 40.0 torr, we can perform the following calculation:

Total pressure = Partial pressure of N2 + Vapor pressure of water .

Therefore, Partial pressure of N2 = Total pressure - Vapor pressure of water

Partial pressure of N2 = 760 torr - 40.0 torr

Partial pressure of N2 = 720 torr

The partial pressure of N2 gas in the flask is 720 torr.

The partial pressure of N2 gas in the flask is 720 torr.

To find the partial pressure of N2 gas, we need to subtract the vapor pressure of water from the total pressure of the collected gas. The total pressure is given as 760 torr, and the vapor pressure of water at 34°C is 40.0 torr.

The partial pressure of a gas in a mixture is calculated using Dalton's Law of Partial Pressures, which states that the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of each individual gas. Mathematically, this can be expressed as:

[tex]\[ P_{\text{total}} = P_{\text{gas 1}} + P_{\text{gas 2}} + \ldots + P_{\text{gas }n} \][/tex]

where [tex]\( P_{\text{total}} \)[/tex] is the total pressure and [tex]\( P_{\text{gas }i} \)[/tex] is the partial pressure of the i-th gas.

In this case, the total pressure [tex]\( P_{\text{total}} \)[/tex] is 760 torr, and it is composed of the partial pressure of N2 gas [tex]\( P_{\text{N2}} \)[/tex] and the vapor pressure of water [tex]\( P_{\text{H2O}} \)[/tex]:

[tex]\[ P_{\text{total}} = P_{\text{N2}} + P_{\text{H2O}} \][/tex]

We can rearrange this equation to solve for [tex]\( P_{\text{N2}} \)[/tex]:

[tex]\[ P_{\text{N2}} = P_{\text{total}} - P_{\text{H2O}} \][/tex]

Substituting the given values:

[tex]\[ P_{\text{N2}} = 760 \text{ torr} - 40.0 \text{ torr} \] \[ P_{\text{N2}} = 720 \text{ torr} \][/tex]

Therefore, the partial pressure of N2 gas in the flask is 720 torr.

Given, weight of the woman = 55 kg

For the first 10 kg, fluid required is 100 mL/kg

So for the first 10 kg volume of fluid required is 100 ml/kg  x 10 kg = 1000 ml = 1 L

For the second 10 kg, fluid required is 50 mL/kg

So for the second 10 kg volume of fluid required is 50 ml/kg x 10 kg = 500 ml = 0.5 L

For the remaining (55 kg - 20 kg ) or 35 kg, fluid required is 20mL/kg

Now for the the remaining 35 kg  volume of fluid required is 20 ml/kg x 35 kg = 700 ml = 0.7 L

The total volume of fluid per day required by a 55 kg woman = 1L + 0.5L + 0.7L = 2.2 L

The volume of fluid per day needed by a 55kg woman, based on the given guide to fluid requirements, is 1000mL for the first 10kg, 500mL for the next 10kg, and 700mL for the remaining weight, totaling 2200mL or 2.2 liters per day when rounded to two significant figures.

To calculate the volume of fluid per day needed by a 55kg woman based on the rough guide to fluid requirements, we use the following method:

For the first 10kg of body weight: 100mL/kg.

For the next 10kg of body weight: 50mL/kg.

For the remaining weight over 20kg: 20mL/kg.

So for a 55kg woman:

For the first 10kg: 10kg x 100mL/kg = 1000mL

For the next 10kg: 10kg x 50mL/kg = 500mL

For the remaining 35kg: 35kg x 20mL/kg = 700mL

Therefore, the total fluid requirement is 1000mL + 500mL + 700mL = 2200mL, which rounded to two significant figures is 2200mL or 2.2 liters per day.

[tex]n(\text{C}_3\text{H}_7\text{OH}) = N(\text{C}_3\text{H}_7\text{OH}) / N_A\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 5.2 \times 10^{21} / (6.02 \times 10^{23})\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 8.6 \times 10^{-3} \; \text{mol}[/tex]

where [tex]N_A = 6.02 \times 10^{23}\; \text{mol}^{-1}[/tex] the Avogadro's constant that relates the number of particles to their number, in the unit moles [tex]\text{mol}[/tex].

The molar mass of propanol- mass per mole propanol- can be directly deduced from its molecular formula with reference to a modern periodic table.

[tex]M(\text{C}_3\text{H}_7\text{OH}) = \underbrace{3 \times 12.01}_{\text{carbon}} + \underbrace{8 \times 1.008}_{\text{hydrogen}} + \underbrace{1\times 16.00}_{\text{oxygen}} = 60.09 \; \text{g} \cdot \text{mol}^{-1}[/tex]

[tex]8.6 \times 10^{-3} \; \text{mol}[/tex] of propanol molecules would thus have a mass of [tex]8.6 \times 10^{-3} \; \text{mol} \times 60.09 \; \text{g} \cdot \text{mol}^{-1} = 0.52 \; \text{g}[/tex]

Answer:- d. London dispersion

Explanations:- Carbon dioxide structure is given below:

                 O=C=O

It has two polar C=O bonds but even then it is non polar molecule as it's linear and the dipole moment of one C=O bond is canceled by it's opposite C=O bond.

being non polar, the only attraction forces present in it are London dispersion forces.

Answer:

d. London dispersion

Carbon dioxide is derived from the reaction between Carbon and Oxygen and the structure is as shown  below:

                O=C=O

The only intermolecular force found in carbon dioxide is the London dispersion forces and they are forces which are caused by electron movement which forms dipoles.

Carbondioxide has two polar C=O bonds in which the dipoles are cancelled out thereby making it a non polar compound. This non-polarity is what makes the only force present to be the London dispersion forces and can also be regarded as the strongest intermoelcular bond found in the compound (CO₂)

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Answer:- Frequency is [tex]4.80*10^1^4Hz[/tex] .

Solution:- The wavelength of electromagnetic radiation is given as 625 nm and we are asked to calculate the frequency. Frequency is inversely proportional to the wavelength and the formula used to calculate frequency when wavelength is given is:

[tex]\nu =\frac{c}{\lambda }[/tex]

where, [tex]\nu [/tex] is frequency, c is speed of light and [tex]\lambda [/tex] is the wavelength.

Value of speed of light is [tex]\frac{3.0*10^8m}{s}[/tex] . We need to convert the given wavelength from nm to m.

[tex]1nm=10^-^9m[/tex]

So, [tex]625nm(\frac{10^-^9m}{1nm})[/tex]

= [tex]6.25*10^-^7m[/tex]

Let's plug in the values in the formula and calculate the frequency:

[tex]\nu =\frac{3.0*10^8m.s^-^1}{6.25*10^-^7m}[/tex]

= [tex]4.80*10^1^4s^-^1[/tex] or Hz.

So, the frequency of the electromagnetic wave is [tex]4.80*10^1^4Hz[/tex] .

The frequency of an electromagnetic wave with a wavelength of 625 nm is [tex]\boxed{4.8 \times 10^{14} \text{ Hz}}.[/tex]

To find the frequency of an electromagnetic wave, one can use the relationship between the speed of light (c), the frequency (f), and the wavelength (\lambda), which is given by the equation:

[tex]\[ c = f \lambda \][/tex]

 The speed of light in a vacuum is approximately [tex]\( 3 \times 10^8 \)[/tex]meters per second (m/s). Since the wavelength is given in nanometers (nm), we need to convert it to meters to match the units of the speed of light. There are [tex]\( 10^9 \)[/tex] nanometers in a meter, so a wavelength of 625 nm is:

[tex]\[ \lambda = 625 \text{ nm} \times \frac{1 \text{ m}}{10^9 \text{ nm}} = 625 \times 10^{-9} \text{ m} \][/tex]

Now we can rearrange the equation [tex]\( c = f \lambda \)[/tex] to solve for the frequency (f):

[tex]\[ f = \frac{c}{\lambda} \][/tex]

 Substituting the values for c and \lambda:

 [tex]\[ f = \frac{3 \times 10^8 \text{ m/s}}{625 \times 10^{-9} \text{ m}} \][/tex]

[tex]\[ f = \frac{3}{625} \times 10^{14} \text{ Hz} \][/tex]

[tex]\[ f = 4.8 \times 10^{14} \text{ Hz} \][/tex]

 Therefore, the frequency of the electromagnetic wave is[tex]( 4.8 \times 10^{14} \) hertz.[/tex]

We multiply the two numbers 2.5 and 1200 because thats the distance you went every hour and it equals 3000km

The study of numbers is called mathematics.

The correct answer is 3000km.

All the data is given in the question, the data is as follows:-

Placed all the values in the formula. the solution is as follows:-

[tex]D =S*T\\= 1200*2.5\\=3000km[/tex]

Hence, the correct answer is 3000km.

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Ca = 40.1  

2 F = 38.0  

--------------  

78.1  

% F = 38.0/78.1  

Now you can calculate mass of F  

0.487 ( 255 g ) = 124 g F

Final answer:

To find the mass of fluorine in the sample, subtract the mass of chromium from the total mass of the sample. In a 36.01 g sample of CrF₃ with 18.83 g of Cr, there are 17.18 grams of fluorine.

Explanation:

The student asks how many grams of fluorine (F) are in a 36.01 g sample of chromium (III) fluoride (CrF₃) if there are 18.83 g of chromium (Cr) in the sample. To answer this, we conduct a mass difference calculation.

First, we subtract the mass of chromium (Cr) from the total mass of the sample to determine the mass of fluorine present:

Therefore, there are 17.18 grams of fluorine in the 36.01 g sample of CrF₃.

Convection: the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat.

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The equilibrium means that amount that are coming equals the amount that are going.

So the correct answers are

2. A person's income and expenses are equal every month.

3. The pressure exerted on the inside of a balloon by the gas inside is equal to the pressure exerted on the outside of the balloon by the atmosphere.

-Hiadamcom/From Agarvated

Answer:

A person's income and expenses are equal every month.

The pressure exerted on the inside of a balloon by the gas inside is equal to the pressure exerted on the outside of the balloon by the atmosphere.

Explanation:

In equilibrium there is balance always.  

Option A is incorrect. Equilibrium would be maintained if the water that falls out of the faucet is re-entered into the faucet.  

Option B is correct. As the income and expense of the person is equal, so what the person spends is equal to what he earns. So the person neither spends more than his income goes to debt nor does the person has some money left after his spending to save or invest.  

Option C is correct. As the pressure exerted on the inside of a balloon by the gas inside is equal to the pressure exerted on the outside of the balloon by the atmosphere, the balloon does not burst. The air pressure is balanced on either side of the balloon.  

Option D is incorrect. Equilibrium would be maintained if the heat gained is equal to the heat lost.  

Collision theory is reliable because it gives a repeatable measure for predicting necessary conditions for reactions, is supported by extensive experimental data, and aligns with scientific principles, only offering limitations when relativistic speeds are involved.

Collision theory is considered well-established and highly reliable because it provides a repeatable measure for predicting the conditions necessary for chemical reactions. These conditions typically include the energy threshold that reacting particles must overcome known as activation energy, and the proper orientation during collisions. This theory is supported by numerous experiments, and no experiment has so far contradicted its postulates. As with the transition from hypothesis to theory in scientific disciplines, collision theory's predictions have been consistently validated by experimental data, making it reliable in the study of reaction rates and mechanisms. It should be noted that the application of collision theory is restricted to non-relativistic speeds, as at relativistic velocities encountered in particle physics, relativistic mechanics would be necessary for correct analysis.

Furthermore, the theory's ability to generalize across various types of collisions, provided we stay in one dimension and minimize external influences such as friction, adds to its dependability. However, in practical applications, especially regarding high-energy collisions between particles like in particle accelerators, adjustments are made to account for the relativistic speeds.