Answer:
P(A)=1/7
P(B)=1/2
P(C)=1/42
P(A|C)=1/10
P(B|C)=1/10
P(A|B)=1/7
A and B are independent
A and C aren't independent
B and C aren't independent
Step-by-step explanation:
A="b falls in the middle"
- b can fall in seven possible places, but only one is the middle. So, P(A)=1/7
B="c falls to the right of b"
X=i means "b falls in the i-th position"
Y=j means "c falls in the j-th position"
if b falls in the first place, c can fall in the 2nd, 3rd, 4th, 5th, 6th or 7th place.
if b falls in the 2nd place, c can fall in the 3rd, 4th, 5th, 6th or 7th place
...
If b falls in the 6th place, c can fall in the 7th place
then:
[tex][tex]P(B)=\displaystyle\sum_{i=1}^{6}( P(X=i)\displaystyle\sum_{j=i+1}^{7} P(Y=j))=\displaystyle\sum_{i=1}^{6}( \frac{1}{7}\displaystyle\sum_{j=i+1}^{7} \frac{1}{6})=\frac{1}{42}\displaystyle\sum_{i=1}^{6}(\displaystyle\sum_{j=i+1}^{7}1)=\frac{6+5+4+3+2+1}{42}=\frac{1}{2}[/tex][/tex]
- if d falls in the 1st place, e falls in the 2nd and f in the 3rd place
- if d falls in the 2nd place, e falls in the 3rd and f in the 4th place
- if d falls in the 3rd place, e falls in the 4th and f in the 5th place
- if d falls in the 4th place, e falls in the 5th and f in the 6th place
- if d falls in the 5th place, e falls in the 6th and f in the 7th place
X=i means "d falls in the i-th position"
Y=j means "e falls in the j-th position"
Z=k means "f falls in the k-th position"
[tex]P(C)=\displaystyle\sum_{i=1}^{5}( P(X=i)P(Y=i+1)P(Z=i+2))=\displaystyle\sum_{i=1}^{5}(\frac{1}{7}\times\frac{1}{6}\times\frac{1}{5})=\frac{1}{210}\displaystyle\sum_{i=1}^{5}(1)=\frac{1}{42}[/tex]
P(A|C)=P(A∩C)/P(C)=?
A∩C:
- d falls in the 1st place, e in the 2nd, f in the 3rd and b in the 4th place
- b falls in the 4th place, d in the 5th place, e in the 6th, f in the 7th place
P(A∩C)=2*(1/7*1/6*1/5*1/4)=1/420
P(A|C)=(1/420)/(1/42)=1/10
P(B|C)=P(B∩C)/P(C)=?
X=i means "d falls in the i-th position"
Y=j means "e falls in the j-th position"
Z=k means "f falls in the k-th position"
V=k means "b falls in the k-th position"
W=k means "c falls in the k-th position"
[tex]P(B\cap C)=\displaystyle\sum_{i=1}^{3} P(X=i)P(Y=i+1)P(Z=i+2)\displaystyle\sum_{j=i+3}^{6}P(V=j)P(W=j+1)[/tex]
[tex]P(B\cap C)=\displaystyle\sum_{i=1}^{3} \frac{1}{7}\times\frac{1}{6}\times\frac{1}{5}(\displaystyle\sum_{j=i+3}^{6}\frac{1}{4}\times\frac{1}{3})=\frac{1}{2520}\displaystyle\sum_{i=1}^{3} \displaystyle\sum_{j=i+3}^{6}1=\frac{1}{420}[/tex]
P(B|C)=(1/420)/(1/42)=1/10
P(A|B)=P(B∩A)/P(B)=?
B∩A:
- b falls in the 4th place and c in the 5th
- b falls in the 4th place and c in the 6th
- b falls in the 4th place and c in the 7th
P(B∩A)=3*(1/7*1/6)=1/14
P(A|B)=(1/14)(1/2)=1/7
If one event is independent of another, P(X∩Y)=P(X)P(Y)
So:
P(A∩B)=1/14=(1/7)*(1/2)=P(A)P(B), A and B are independent
P(A∩C)=1/420≠(1/7)*(1/42)=1/294=P(A)P(C), A and C aren't independent
P(B∩C)=1/420≠(1/2)*(1/42)=1/84=P(A)P(C), B and C aren't independent
Show your work:
Express 160 pounds (lbs) in kilograms (kg). Round to the nearest hundredths.
Answer:
160 lbs = 72.57kg
Step-by-step explanation:
This can be solved as a rule of three problem.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.
Unit conversion problems, like this one, is an example of a direct relationship between measures.
Each lb has 0.45kg. How many kg are there in 160lbs. So:
1lb - 0.45kg
160 lbs - xkg
[tex]x = 0.45*160[/tex]
[tex]x = 72.57[/tex] kg
160 lbs = 72.57kg
If the probability that a bird will lay an egg is 75%, the probability that the egg will hatch is 50%, and the probability that the chick will be eaten by a snake before it fledges is 20%, what is the probability that a parent will have progeny that survive to adulthood?
(A) 30%
(B) 14.5%
(C) 7.5%
(D) 2%
Answer: (A) 30%
Step-by-step explanation:
Given : The probability that a bird will lay an egg =0.75
The probability that the egg will hatch =0.50
Now, the probability that the egg will lay an egg and hatch = [tex]0.75\times0.50[/tex]
Also,The probability that the chick will be eaten by a snake before it fledges =0.20
Then, the probability that the chick will not be eaten by a snake before it fledges : 1-0.20=0.80
Now, the probability that a parent will have progeny that survive to adulthood will be :-
[tex]0.75\times0.50\times0.80=0.30=30\%[/tex]
Hence, the probability that a parent will have progeny that survive to adulthood = 30%
Round the following number to the indicated place. 66.1086 to hundredths
Answer:
66.11
Step-by-step explanation:
We are given that a number
66.1086
We have to round the number to hundredths
Place of 6=One;s
Place of second 6=Tens
Place of 1=Tenths
Place of 0=Hundredths
Place of 8=Thousandths
Place of 6=Ten thousandths
Thousandths place is 8 which is greater than 5 therefore, one will be added to hundredth place and other number on the left side of hundredth place remain same and the numbers on the right side of hundredth place will be replace by zero.
Therefore, the given number round to hundredths=66.11
1. The volume of a cube is increasing at a rate of 1200 cm/min at the moment when the lengths of the sides are 20cm. How fast are the lengths of the sides increasing at that [10] moment?
Answer:
[tex]1\,\,cm/min[/tex]
Step-by-step explanation:
Let V be the volume of cube and x be it's side .
We know that volume of cube is [tex]\left ( side \right )^{3}[/tex] i.e., [tex]x^3[/tex]
Given :
[tex]\frac{\mathrm{d} V}{\mathrm{d} t}=1200\,\,cm^3/min[/tex]
[tex]x=20\,\,cm[/tex]
To find : [tex]\frac{\mathrm{d} x}{\mathrm{d} t}[/tex]
Solution :
Consider equation [tex]V=x^3[/tex]
On differentiating both sides with respect to t , we get
[tex]\frac{\mathrm{d} V}{\mathrm{d} t}=3x^2\left ( \frac{\mathrm{d} x}{\mathrm{d} t} \right )\\1200=3(20)^2\left ( \frac{\mathrm{d} x}{\mathrm{d} t} \right )\\\frac{\mathrm{d} x}{\mathrm{d} t} =\frac{1200}{3(20)^2}=\frac{1200}{3\times 400}=\frac{1200}{1200}=1\,\,cm/min[/tex]
So,
Length of the side is increasing at the rate of [tex]1\,\,cm/min[/tex]
A group of friends goes out for single-scoop ice-cream cones. There are sugar cones, cake cones and waffle cones. But there are only five flavors of ice-cream left (peppermint, horehound, chocolate malt, gingerbread, and squirrel). How many cone/ice cream combinations can be ordered?
Answer: 15
Step-by-step explanation:
Given : The number of kinds of ice-cream cones ( sugar cones, cake cones and waffle cones)=3
The number of flavors of ice-creams =5
By using the fundamental principle of counting , we have
The number of possible cone/ice cream combinations can be ordered will be :-
[tex]5\times3=15[/tex]
Hence, the number of possible cone/ice cream combinations can be ordered =15
A man in a maze makes three consecutive displacements. His first displacement is 6.70 m westward, and the second is 11.0 m northward. At the end of his third displacement he is back to where he started. Use the graphical method to find the magnitude and direction of his third displacement.
Answer:
The man had a displacement of 12.88 m southeastward
Step-by-step explanation:
The path of man forms a right triangle. The first two magnitudes given in the problem form the legs and the displacement that we must calculate forms the hypotenuse of the triangle. To do this we will use the equation of the pythagorean theorem.
H = magnitude of displacement
[tex]H^2 = \sqrt{L_1^2 + L_2^2} = \sqrt{6.70^2 + 11.0^2} = \sqrt{165.89} =12.88 m[/tex]
using the graphic method, we will realize that the displacement is oriented towards the southeast
Find the greatest common divisor of 252 and 60
Answer:
12
Step-by-step explanation:
The greatest common divisor(gcd) is also known by the name highest common factor(hcf), greatest common factor(gcf).
Greatest common factor of two number can be defined as the highest integer that divides both the number.
We have to find greatest common divisor of 252 and 60.
The prime factorization of 252 is:
252 = 2×2×3×3×7
The prime factorization of 60 is:.
60 = 2×2×3×5
Common factors are: 2×2×3
Hence, greatest common divisor of 252 and 60 = 2×2×3 = 12
Ben earns $9 per hour and $6 for each delivery he makes.He wants to earn more than $155 in an 8 hour work day.What is the least number of deliveries he must make to reach his goal?
Answer:
Ben must make at least 14 deliveries to reach his goal.
Step-by-step explanation:
The problem states that Ben earns $9 per hour and $6 for each delivery he makes. So his daily earnings can be modeled by the following function.
[tex]E(h,d) = 9h + 6d[/tex],
in which h is the number of hours he works and d is the number of deliveries he makes.
He wants to earn more than $155 in an 8 hour work day.What is the least number of deliveries he must make to reach his goal?
This question asks what is the value of d, when E = $156 and h = 8. So:
[tex]E(h,d) = 9h + 6d[/tex]
[tex]156 = 9*8 + 6d[/tex]
[tex]156 = 72 + 6d[/tex]
[tex]6d = 84[/tex]
[tex]d = \frac{84}{6}[/tex]
d = 14
Ben must make at least 14 deliveries to reach his goal.
Consider a fair coin which when tossed results in either heads (H) or tails (T). If the coin is tossed TWO times 1. List all possible outcomes. (Order matters here. So, HT and TH are not the same outcome.) 2. Write the sample space. 3. List ALL possible events and compute the probability of each event, assuming that the probability of each possible outcome from part (a) is equal. (Keep in mind that there should be many more events than outcomes and not all events will have the same probability.)
Answer:
Sample space = {(T,T), (T,H), (HT), (HH)}
Step-by-step explanation:
We are given a fair coin which when tossed one times either gives heads(H) or tails(T).
Now, the same coin is tossed two times.
1) All the possible outcomes
Tails followed by tails
Rails followed by heads
Heads followed by a tail
Heads followed by heads
2) Sample space
{(T,T), (T,H), (HT), (HH)}
3) Formula:
[tex]Probability = \displaystyle\frac{\text{Favourable outcome}}{\text{Total number of outcome}}[/tex]
Using the above formula, we can compute the following probabilities.
Probability((T,T)) =[tex]\frac{1}{4}[/tex]
Probability((T,H)) =[tex]\frac{1}{4}[/tex]
Probability((H,T)) =[tex]\frac{1}{4}[/tex]
Probability((H, H)) =[tex]\frac{1}{4}[/tex]
Probability(Atleast one tails) = [tex]\frac{3}{4}[/tex]
Probability(Atleast one heads) = [tex]\frac{3}{4}[/tex]
Probability(Exactly one tails) = [tex]\frac{2}{4}[/tex]
Probability(Exactly one heads) = [tex]\frac{2}{4}[/tex]
What is the answer to (n+4) +7 =
(n+4) +7 remove the parenthesis
n+4+7 add the same number answer is n +11
1. Suppose that A , B and C are sets. Show that A \ (B U C) (A \ B) n (A \ C).
Step-by-step explanation:
We want to show that
[tex]=A \setminus (B \cup C) = (A\setminus B) \cap (A\setminus C)[/tex]
To prove it we just use the definition of [tex]X\setminus Y = X \cap Y^c[/tex]
So, we start from the left hand side:
[tex]=A \setminus (B \cup C) = A \cap (B \cup C)^c[/tex] (by definition)
[tex]=A \cap (B^c \cap C^c)[/tex] (by DeMorgan's laws)
[tex]=A \cap B^c \cap C^c[/tex] (since intersection is associative)
[tex]=A \cap B^c \cap A \cap C^c[/tex] (since intersecting once or twice A doesn't make any difference)
[tex]=(A \cap B^c) \cap (A \cap C^c)[/tex] (since again intersection is associative)
[tex]=(A\setminus B) \cap (A \setminus C)[/tex] (by definition)
And so we have reached our right hand side.
Justin deposited $2,000 into an account 5 years ago. Simple interest was paid on the account. He has just withdrawn $2,876. What interest rate did he earn on the account?
Answer: [tex]8.76\%[/tex]
Step-by-step explanation:
The formula to find the final amount after getting simple interest :
[tex]A=P(1+rt)[/tex], where P is the principal amount , r is rate of interest ( in decimal )and t is time(years).
Given : Justin deposited $2,000 into an account 5 years ago.
i.e. P = $2,000 and t= 5 years
He has just withdrawn $2,876.
i.e. we assume that A = $2876
Now, Put all the values in the formula , we get
[tex](2876)=(2000)(1+r(5))\\\\\Rightarrow\ 1+5r=\dfrac{2876}{2000}\\\\\Rightarrow\ 1+5r=1.438\\\\\Righhtarrow\ 5r=0.438\\\\\Rightarrow\ r=\dfrac{0.438}{5}=0.0876[/tex]
In percent, [tex]r=0.0876\times100=8.76\%[/tex]
hence, He earned [tex]8.76\%[/tex] of interest on account.
Given:
An = [6 n/(-4 n + 9)]
For both of the following answer blanks, decide whether the given sequence or series is convergent or divergent. If convergent, enter the limit (for a sequence) or the sum (for a series). If divergent, enter INF if it diverges to infinity, MINF if it diverges to minus infinity, or DIV otherwise.
(a) The sequence {An }._________________
(b) The series ∑n=1[infinity]( An )________________
The given sequence is convergent with a limit of -3/2, while the series is divergent since its terms do not approach zero
Explanation:The sequence in question is An = [6*n/(-4*n + 9)]. To find out if this sequence is convergent or divergent, we need to take the limit as n approaches infinity. As n approaches infinity, the 'n' in the numerator and the 'n' in the denominator will dominate, making the sequence asymptotically equivalent to -6/4 = -3/2. Thus, the sequence is convergent, and its limit is -3/2.
On the other hand, the series ∑n=1[infinity]( An ) is the sum of the terms in the sequence. We can see that as n approaches infinity, the terms of this series do not approach zero, which is a necessary condition for a series to be convergent (using the nth term test). Therefore, the series is divergent.
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A recipe calls for 1 cup of ground almonds. How many ounces of ground almonds should you use for this recipe if 1 pint of ground almonds weighs 0.42 pounds?
Answer: There are 3.36 ounces of ground almonds in 1 cup.
Step-by-step explanation:
Since we have given that
1 pint = 0.42 pounds
As we know that
1 cup = 0.5 pints
1 pound = 16 ounces
So, We need to find the number of ounces.
As 1 pint = 0.42 pounds = 0.42 × 16 = 6.72 ounces
0.5 pints is given by
[tex]6.72\times 0.5\\\\=3.36\ ounces[/tex]
Hence, there are 3.36 ounces of ground almonds in 1 cup.
To find out how many ounces are in one cup of ground almonds if 1 pint (2 cups) weighs 0.42 pounds, you divide 0.42 pounds by 2 to get the weight per cup, then multiply by 16 to convert pounds to ounces, resulting in 3.36 ounces per cup.
The question involves converting weight measurements from one unit to another, specifically from pounds to ounces. To do this, you use the conversion factor of 16, because there are 16 ounces in 1 pound. Applying this to the recipe question:
1 pint of ground almonds weighs 0.42 pounds. Since 1 pint equals 2 cups, this weight corresponds to 2 cups of ground almonds.
To find out how many ounces 1 cup of ground almonds weighs, first divide the total weight by the number of cups:
0.42 pounds ÷ 2 cups = 0.21 pounds per cup.
Then, convert pounds to ounces:
0.21 pounds × 16 ounces/pound = 3.36 ounces.
So, for the recipe, you should use 3.36 ounces of ground almonds.
Before the industrial revolution in 1800 the concentration of carbon in Earth’s atmo- sphere was 280 ppm. The concentration in 2015 was 399 ppm. What is the percent increase in the amount of carbon in the atmosphere?
Answer: There is increase of 4.255 in the amount of carbon in the atmosphere.
Step-by-step explanation:
Since we have given that
Concentration of carbon in Earth's atmosphere in 1800 = 280 ppm
Concentration of carbon in Earth's atmosphere in 2015 = 399 ppm
We need to find the percentage increase in the amount of carbon in the atmosphere.
So, Difference = 399-280 = 119 ppm
so, percentage increase in the amount of carbon is given by
[tex]\dfrac{Difference}{Original}\times 100\\\\=\dfrac{119}{280}\times 100\\\\=\dfrac{11900}{280}\\\\=42.5\%[/tex]
Hence, there is increase of 4.255 in the amount of carbon in the atmosphere.
The physician orders an IV infusion of D5W 1000 ml to infuse over the next eight hours. The IV tubing that you are using delivers 10 gtt/ml. What is the correct rate of flow (drops per minute)? _gtt/min (rounded to the nearest drop)
Answer: 10gtt/ml means that in 10 drops there is a ml of the solution.
Now, you need 1000ml in 8 hours, and want to know the correct rate of flow in drops per minute.
first, 8 hours are 8*60 = 480 minutes.
then you need to infuse 1000ml in 480 minutes, so if you infuse at a constant rate, you need to infuse 1000/480 = 2.083 ml/min.
And we know that 10 drops are equivalent to 1 ml, then 2.083*10= 20.8 drops are equivalent a 2.083 ml, rounding it up, you get 21 drops for the dose.
So the correct rate of flow will be 21 drops per minute.
To find the correct rate of flow for an IV infusion, convert the time to minutes, divide the total volume by the total time to find the rate in ml/min, then multiply by the drip factor to convert to drops/min. Rounding to the nearest drop, we get 21 gtt/min.
Explanation:To calculate the correct rate of flow for an IV infusion, we need to use the given information: the volume of the IV infusion (D5W 1000 ml), the time over which it must infuse (8 hours), and the IV tubing drip factor (10 gtt/ml).
First, convert the time from hours to minutes as we're interested in drops per minute: 8 hours * 60 minutes/hour = 480 minutes.
Next, we divide the total volume by the total time: 1000 ml / 480 minutes = ~2.08 ml/min. This is the rate in ml/min.
Finally, we multiply by the drip factor to get the rate in drops per minute: 2.08 ml/min * 10 gtt/ml = 20.8 gtt/min.
Rounding to the nearest drop gives us a rate of 21 gtt/min.
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Cheese costs $4.40 per pound. Find the cost per kilogram. (1kg = 2.2lb)
Answer:
The cost is $9.70 per kilogram.
Step-by-step explanation:
This can be solved by a rule of three.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.
In this problem, the measures are the weight of the cheese and the price. As the weight increases, so does the price. It means that this is a direct rule of three.
Solution:
The problem states that cheese costs $4.40 per pound. Each kg has 2.2 pounds. How many kg are there in 1 pound. So:
1 pound - xkg
2.2 pound - 1 kg
[tex]2.2x = 1[/tex]
[tex]x = \frac{1}{2.2}[/tex]
[tex]x = 0.45[/tex]kg
Since cheese costs $4.40 per pound, and each pound has 0.45kg, cheese costs $4.40 per 0.45kg. How much does is cost for 1kg?
$4.40 - 0.45kg
$x - 1kg
[tex]0.45x = 4.40[/tex]
[tex]x = \frac{4.40}{0.45}[/tex]
[tex]x = 9.70[/tex]
The cost is $9.70 per kilogram.
"The cost per kilogram of cheese is approximately $2.00.
To find the cost per kilogram, we need to convert the cost from dollars per pound to dollars per kilogram using the conversion factor between pounds and kilograms. Given that 1 kilogram is equal to 2.2 pounds, we can set up the following conversion:
Cost per pound of cheese = $4.40
Conversion factor = 2.2 pounds/kilogram
Now, to find the cost per kilogram, we divide the cost per pound by the conversion factor:
Cost per kilogram = Cost per pound / Conversion factor
Cost per kilogram = $4.40 / 2.2 pounds/kilogram
Performing the division, we get:
Cost per kilogram ≈ $2.00
a,b,c,d are integers and GCD(a,b)=1. if c divides a and d divides b, prove that GCD(c,d) = 1.
Answer:
One proof can be as follows:
Step-by-step explanation:
We have that [tex]g.c.d(a,b)=1[/tex] and [tex]a=cp, b=dq[/tex] for some integers [tex]p, q[/tex], since [tex]c[/tex] divides [tex]a[/tex] and [tex]d[/tex] divides [tex]b[/tex]. By the Bezout identity two numbers [tex]a,b[/tex] are relatively primes if and only if there exists integers [tex]x,y[/tex] such that
[tex]ax+by=1[/tex]
Then, we can write
[tex]1=ax+by=(cp)x+(dq)y=c(px)+d(qy)=cx'+dy'[/tex]
Then [tex]c[/tex] and [tex]d[/tex] are relatively primes, that is to say,
[tex]g.c.d(c,d)=1[/tex]
Calculate (a) the number of milligrams of metoclopramide HCl in each milliliter of the prescription:
Metoclopramide HCl 10 g
Methylparaben 50 mg
Propylparaben 20 mg
NaCl 800 mg
Purifed water qs ad 100 mL
Answer:
There are 100 milligrams of metoclopramide HCl in each milliliter of the prescription
Step-by-step explanation:
When the prescription says Purified water qs ad 100 mL means that if we were to make this, we should add the quantities given and then, fill it up with water until we have 100 mL of solution, being the key words qs ad, meaning sufficient quantity to get the amount of mixture given.
Then, knowing there is 10 grams of metoclopramide HCl per 100 mL of prescription, that means there is (1 gram = 1000 milligrams) 10000 milligrams of metoclopramide HCl per 100 mL of prescription. That is a concentration given in a mass/volume way.
Knowing the concentration, we can calculate it per mL instead of per 100 mL
[tex]Concentration_{metoclopramide HCL}= \frac{10000mg}{100mL} =100 \frac{mg}{mL}[/tex]
Find q, r in \mathbb{Z} so that 105 = 11q + r
with 0 \leq r < 11 as in the division algorithm
Answer:
[tex]q=9\,,\,r=6[/tex]
Step-by-step explanation:
Division Algorithm :
As per division algorithm , for numbers a and b , there exist numbers q and r such that [tex]a=bq+r\,\,,0\leq r< b[/tex]
Here ,
a = Dividend
b = Divisor
q = quotient
r = remainder
Given : 105 = 11q + r such that [tex]0 \leq r < 11[/tex]
Here, clearly a = 105 , b = 11
To find : q and r
Solution : On dividing 105 by 11 , we get [tex]105=11\times 9+6[/tex]
On comparing [tex]105=11\times 9+6[/tex] with [tex]a=bq+r\,\,,0\leq r< b[/tex] , we get [tex]q=9\,,\,r=6[/tex]
Bob, the proprietor of Midland Lumber, believes that the odds in favor of a business deal going through are 9 to 5. What is the (subjective) probability that this deal will not materialize? (Round your answer to three decimal places.)
Answer:
There is a 35.7% probability that this deal will not materialize.
Step-by-step explanation:
This problem can be solved by a simple system of equations.
-I am going to say that x is the probability that this deal materializes and y is the probability that this deal does not materialize.
The sum of all probabilities is always 100%. So
[tex]1) x + y = 100[/tex].
Bob, the proprietor of Midland Lumber, believes that the odds in favor of a business deal going through are 9 to 5.
Mathematically, this means that:
[tex]2) \frac{x}{y} = \frac{9}{5}[/tex]
We want to find the value of y. So, we can write x as a function of y in equation 2), and replace it in equation 1).
Solution:
[tex]\frac{x}{y} = \frac{9}{5}[/tex]
[tex]x = \frac{9y}{5}[/tex]
[tex]x + y = 100[/tex]
[tex]\frac{9y}{5} + y = 100[/tex]
[tex]\frac{14y}{5} = 100[/tex]
[tex]14y = 500[/tex]
[tex]y = \frac{500}{14}[/tex]
[tex]y = 35.7[/tex]
There is a 35.7% probability that this deal will not materialize.
Let p stand for "This statement is false." What can be said about the truth value of p. (Hint: Did we really assign a truth value to p? See Example 5 for a discussion of truth value assignment.)
Answer: P means "This statement is false"
then, P is a "function" of some statement,
if i write P( 3> 1932) this could be read as:
3>1932, this statement is false.
You could see that 3> 1932 is false, so P( 3>1932) is true.
Then you could se P(x) at something that is false if x is true, and true if x is false, so p is a negation.
How many grams of Total Sugars in one serving of this food can be attributed to naturally occurring sugar (i.e., NOT added sugars)?
22g
2g
12g
10g
Answer:
Taking into account the information presented in the image attached for this food.
Naturally sugar are
2 g
Step-by-step explanation:
Information presented regarding to the composition of this food is attached.
One serving has a weight of 55 g.
Total carbohydrates in one serving are 37 g. This value includes fiber and sugars.
If we detail sugars, it has 12 g of total sugars (St), where 10 g are added sugars (Sa) and all the rest Natural sugars (Sn).
Expressing sugars as an equation
St = Sa + Sn
Isolating Sn value
Sn = St - Sa
Sn = 12 g - 10 g
Sn = 2 g
Finally, Natural sugars (Sn) is 2 g.
All 22 grams of total sugars per serving in the food are naturally occurring, as the label specifies there are 0g of added sugars.
Explanation:To determine the grams of naturally occurring sugar in a serving of food, we need to examine the nutritional information provided.
According to the label, it includes 0g added sugars, which implies that all of the sugars listed are naturally occurring.
Therefore, if there are 22g total sugars in one serving of the food, and none of these are added sugars, then all 22 grams can be attributed to naturally occurring sugars.
(7)-0, at the points x 71, 72, 73, 74, and 7.5 Use Euler's method with step size 0.1 to approximate the solution to the initial value pro oblemy - 2x+y The approximate solution to y'=2x-y?.y(7)=0, at the point x = 71 is (Round to five decimal places as needed.)
Answer:
2.68
Step-by-step explanation:
We are given that [tex]x_0=7,x_1=7.1,x_2=7.2,x_3=7.3,x_4=7.4,x_5=7.5[/tex]
h=0.1
y'=2x-y
y(7)=0,f(x,y)=2x-y
[tex]x_0=7,y_0=0[/tex]
We have to find the approximate solution to the initial problem at x=7.1
[tex]y_1=y_0+hf(x_0,y_0)[/tex]
Substitute the value then, we get
[tex]y_1=0+(0.1)(2(7)-0)=0+(0.1)(14)=1.4[/tex]
[tex]y_1=1.4[/tex]
[tex]x_1=x_0+h=7+0.1=7.1[/tex]
[tex]y_2=y_1+hf(x_1,y_1)[/tex]
Substitute the values then, we get
[tex]y_2=1.4+(0.1)(2(7.1)-1.4)=1.4+(0.1)(14.2-1.4)=1.4+(0.1)(12.8)=1.4+1.28[/tex]
[tex]y_2=1.4+1.28=2.68[/tex]
Hence, the approximation solution to the initial problem at x=7.1 is =2.68
DECISION SCIENCE Assume more restrictions. The books pass through two departments: Graphics and Printing, 1. before they can be sold, X requires 3 hours in Graphics and 2 hours in printing. Y requires 1 hour in graphics and 1 hour in printing. There are 21 hours available in graphics and 19 hours in printing respectively. Solve for x and y.
Answer:
Step-by-step explanation:
The given information can be tabulated as follows:
Graphics G Printing P Total
X 3 2 5
Y 1 1 2
Available 21 19
We have the constraints as
[tex]3x+y\leq 21\\2x+y\leq 19\\x\leq 2\\y\leq 15[/tex]
Thus we have solutions as
[tex]0\leq x\leq 2\\0\leq y\leq 15[/tex]
Which nutrient category on the Nutrition Facts panel does NOT have a Daily Value or % Daily Value ascribed to it?
Dietary Fiber
Protein
Total Fat
Sodium
Answer:
Protein
Step-by-step explanation:
According to U.S. Food and Drug Administration (FDA) information, the current scientific evidence indicates that protein intake is not a matter of public concern, this is why the FDA does not request to add a % Daily Value on the Nutrition Facts panel, unless if the product is made for protein such as 'high protein' products or if this food is meant for use by childrend under 4 years old.
Answer:Protein
Step-by-step explanation: took quiz :)
Suppose you are planning to sample cat owners to determine the average number of cans of cat food they purchase monthly. The following standards have been set: a confidence level of 99 percent and an error of less than 5 units. Past research has indicated that the standard deviation should be 6 units. What is the final sample required?
Answer: 10
Step-by-step explanation:
The formula to find the sample size is given by :-
[tex]n=(\dfrac{z_{\alpha/2}\ \sigma}{E})^2[/tex]
Given : Significance level : [tex]\alpha=1-0.99=0.1[/tex]
Critical z-value=[tex]z_{\alpha/2}=2.576[/tex]
Margin of error : E=5
Standard deviation : [tex]\sigma=6[/tex]
Now, the required sample size will be :_
[tex]n=(\dfrac{(2.576)\ 6}{5})^2=9.55551744\approx10[/tex]
Hence, the final sample required to be of 10 .
Find the probability that Z is to the right of 3.05.
Answer: 0.0011
Step-by-step explanation:
By using the standard normal distribution table , the probability that Z is to the left of 3.05 is [tex]P(z<3.05)= 0.9989[/tex]
We know that the probability that Z is to the right of z is given by :-
[tex]P(Z>z)=1-P(Z<z)[/tex]
Similarly, the probability that Z is to the right of 3.05 will be :-
[tex]P(Z>3.05)=1-P(Z<3.05)=1-0.9989=0.0011[/tex]
Hence, the probability that Z is to the right of 3.05 = 0.0011
what is the answer of 2.8 plus 7.2
Answer:
10.022
Step-by-step explanation:
1. 49/9
2. 106/25
3. 10.022
4. When you add two rational numbers, each number can be written as a :
fraction
5. The sum of two fractions can always be written as a : fraction
6. Therefore, the sum of two rational numbers will always be : rational
In European roulette, the wheel is divided into 37 compartments numbered 1 through 36 and 0. (In American roulette there are 38 compartments numbered 1 through 36, 0, and 00.) One-half of the numbers 1 through 36 are red, the other half are black, and the number 0 is green. Find the expected value of the winnings on a $7 bet placed on black in European roulette. (Round your answer to three decimal places.)
Answer:
The expectation is -$0.189.
Step-by-step explanation:
Consider the provided information.
In European roulette, the wheel is divided into 37 compartments numbered 1 through 36 and 0.
One-half of the numbers 1 through 36 are red, the other half are black, and the number 0 is green.
We need to find the expected value of the winnings on a $7 bet placed on black in European roulette.
Here the half of 36 is 18.
That means 18 compartments are red and 18 are black.
The probability of getting black in European roulette is 18/37
The probability of not getting black in European roulette is 19/37. Because 18 are red and 1 is green.
If the ball lands on a black number, the player wins the amount of his bet.
The bet is ball will land on a black number.
The favorable outcomes are 18/37 and unfavorable are 19/37.
Let S be possible numerical outcomes of an experiment and P(S) be the probability.
The expectation can be calculated as:
E(x) = sum of S × P(S)
For[tex] S_1 = 7[/tex]
[tex]P(S_1) = \frac{18}{37}[/tex]
For [tex]S_2 = -7[/tex](negative sign represents the loss)
[tex]P(S_2) = \frac{19}{37}[/tex]
Now, use the above formula.
[tex]E(x) = 7\times \frac{18}{37}-7\times \frac{19}{37}\\E(x) = -0.189[/tex]
Hence, the expectation is -$0.189.