can someone help me with this one math problem ? picture is below

y=0.5(x−1)

Hope i helped

y=2x+1, replace x by y and vice versa

x=2y+1 now solve for y

y=0.5(x-1)

Answer:

Angie will need to save $2.50 for 8 more weeks to get $50

Step-by-step explanation:

Angie has already saved $30

12(2.5)=30

So since she needs $20 more you divide 20 by 2.5 and you get your answer.

20/2.5=8 weeks

Angie has saved $2.50 per week for the past 12 weeks, so she has saved a total of 2.50*12 = $30.00. To reach her goal of $50.00, she needs to save another 50-30 = $20.00. At her current rate of saving, it will take her 20/2.5 = 8 more weeks to reach her goal.

To calculate the total amount of money Angie has saved so far, we simply multiply the amount of money she saves each week by the number of weeks she has been saving.

In this case, Angie saves $2.50 per week and she has been saving for 12 weeks, so she has saved a total of $2.50 per week x 12 weeks = $30.

To calculate the amount of money Angie still needs to save, we simply subtract the amount of money she has saved so far from her goal amount.

In this case, Angie's goal amount is $50 and she has saved $30 so far, so she still needs to save $50 - $30 = $20.

To find out how many more weeks it will take Angie to reach her goal, we simply divide the amount of money she still needs to save by the amount of money she saves each week.

In this case, Angie still needs to save $20 and she saves $2.50 per week, so it will take her $20 / $2.50 per week = 8 weeks to reach her goal.

Therefore, it will take Angie 8 more weeks to save a total of $50.

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Question:-

Angie has saved $2.50 of her allowance every week for the past 12 weeks. If she continues saving the same amount each week, how many more weeks will it take her to save a total $50?

Let x=dog-walking job

Let y= car was attendant

Inequality: 7.50x+6y>92

Inequality: x+y<20

50-500=450

450/15=30

30 weeks

Albert needs 30 weeks to save $500, starting with an initial $50 and depositing $15 each week after.

The subject of this problem is saving money over time. Albert starts with an initial amount of $50. Each week afterward, he adds an additional $15 to his savings. If he wants to save a total of $500, we need to figure out how many weeks that will take.

Since Albert already starts with $50, we first subtract that from $500, the total he wants to save, which leaves $450.

Then, we divide 450 by the amount Albert saves each week, $15. This equals 30, meaning it will take Albert 30 weeks to save $500.

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the answer is c. (18)(60)t would give you the amount of corn removed from the silo to be subtracted from the original amount, which would tell you how much corn is in the silo after t  hours. hope this helps :)

Answer:

[tex](4y^6)^3 - (10z^2)^3[/tex]

Step-by-step explanation:

Given: [tex]64y^{18}- 1000z^6[/tex]

Solution:

Option 1) [tex](4y^6)^3 - (10z^2)^3[/tex]

[tex]64y^{18} - 1000z^6[/tex]

So, Option 1 is equivalent to [tex]64y^{18}- 1000z^6[/tex]

Option 2)[tex](16y^6)^3 -(10z^2)^3[/tex]

[tex]4096y^{18} -1000z^6[/tex]

So, Option 2 is not equivalent to [tex]64y^{18}- 1000z^6[/tex]

Option 3)[tex](16y^6)^3 -(100z^2)^3[/tex]

[tex]4096y^{18} -1000000z^6[/tex]

So, Option 3 is not equivalent to [tex]64y^{18}- 1000z^6[/tex]

Option 4)[tex](4y^6)^3 -(100z^2)^3[/tex]

[tex]64y^{18} -1000000z^6[/tex]

So, Option 4 is not equivalent to [tex]64y^{18}- 1000z^6[/tex]

Hence [tex](4y^6)^3 - (10z^2)^3[/tex] is equivalent to [tex]64y^{18}- 1000z^6[/tex]

So, Option A is correct.

Length, Width, and Height or lwh

A, D, and E. Length, width, and height

Lets set up an equation to easier understand this.

1/1.5 = 3.7/x   (x represents the unknown km)

We know that whatever you do to the top you do to the bottom.

And we can see that 1 x 1.5 = 1.5

So we can multiply the same thing by 3.7

1.5 x 3.7 = 5.55

So in this case you would travel 5.55 km in 3.7 seconds.

GOOD LUCK :)

The new formula for B6 cell will be B6=A6*2

Answer:

B6 =A6*2

Step-by-step explanation:

In Excel, the rectangular box where the rows and column intersect is called cell. The raws are represented by  1, 2, 3, 4, ................, the columns are represented by A, B, C, D,........,The notation of a cell is 'column row',

When we fill a formula in a cell then it can be proceed in below cells.

Here, the given formula,

B5=A5*2

Since, B6 is the below cell of the cell B5,

And, A6 is the below cell of the cell A5,

Thus, the new formula would be,

B6 =A6*2

The ratio of the total number of players on the soccer team to the number of senior players is 1.41 to 1, found by dividing the total number of players (24) by the number of seniors (17).

The question is asking for the ratio of the total number of players on the team to the number of senior players. To get the total number of players, you should add the number of juniors and seniors together. This is, 7 juniors + 17 seniors = 24 total players. The ratio is then calculated as the total number of players divided by the number of seniors, which is, 24 total players ÷ 17 seniors. This simplifies to approximately 1.41 to 1.

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the answer is D

you divide 46.06 by 22 and it will give you the cost of what each employee needs to contribute

Answer:

Option D

the weights would be the best deal is [tex]2\frac{7}{8}[/tex]

Step-by-step explanation:

The price of all meat packages are marked $12.99.

To find the best deal we have to show that the weight of which  package will be greatest.

The weight of each packages are written as a mixed fraction as follows;

[tex]2\frac{2}{3} , 2\frac{9}{11} , 2\frac{4}{5} , 2\frac{7}{8}[/tex]

Now, convert these improper fraction into proper fraction.

[tex]2\frac{2}{3}=\frac{8}{3}[/tex]

[tex]2\frac{9}{11}=\frac{31}{11}[/tex]

[tex]2\frac{4}{5}=\frac{24}{5}[/tex]

[tex]2\frac{7}{8}=\frac{23}{8}[/tex]

To make their denominators same,

the LCM(Least common multiples) of the denominators(11, 3, 5, 8) is 1320.

So,

[tex]\frac{8}{3}= \frac{8\cdot 440}{3\cdot 440} =\frac{3520}{1320}[/tex]

[tex]\frac{31}{11}= \frac{31\cdot 120}{11\cdot 120} =\frac{3720}{1320}[/tex]

[tex]\frac{14}{5} =\frac{14\cdot 264}{5\cdot 264}= \frac{3696}{1320}[/tex]

[tex]\frac{23}{8}=\frac{23\cdot 165}{8\cdot 165} =\frac{3795}{1320}[/tex]

As, you can see that the only fraction is greatest is [tex]\frac{3795}{1320}[/tex]

therefore, the weight [tex]2\frac{7}{8}[/tex] would be the best deal.

Th wholesale would be $30

The box containing 24 crayons has more crayons than the box with 16, indicating a greater quantity of colors available for artistic expression.

Compare the quantities of crayons in each box: 24 crayons in one box and 16 in the other. By recognizing the numerical difference, infer that the box with 24 crayons has more than the one with 16. The use of the phrase "more crayons" in the sentence reflects this numerical comparison, providing a concise and accurate description of the quantity disparity between the two boxes.

This interpretation aligns with the fundamental understanding that a larger numerical value signifies a greater quantity, facilitating a clear and straightforward expression of the comparison between the two sets of crayons.

You know that:

Farah packs 4 outfits for 3 days of vacation.

Then Farah packs:

Answer: correct choices are B, D and E.

Answer:

We have been given that  for every 3 days of vacation, Farah packs 4 outfits.

That means [tex]\text{one day vacation she packs}\frac{4}{3}outfits.[/tex]   (1)

Multiply number of vacation with [tex]\frac{4}{3}[/tex] to get number of outfits.

Choice A is correct according to equation (1)

1.Farah would pack 6 outfits for an 8-day vacation.

Choice B is other way round of A so correct.

2.Farah would pack 8 outfits for a 6-day vacation.

Choice D is correct

3.Farah would pack 16 outfits for a 12-day vacation.

Choice E is also correct.

4.Farah would pack 28 outfits for a 21-day vacation.

the first chart is multiplying by 4

the second chart is multiplying by -3

the third chart is multiplying by 1/2

the fourth chart is dividing by -3

i hope this helps you  

Your answer is False!!

Given the following fractions as of -159/396 and -26/33....As a decimal which you have to convert it to would be

-159/396=-0.41515

and

-26/33=-0.787879

Hope this helps you.

Answer:

False

Step-by-step explanation:

The slope formula:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have:

[tex](2,\ -5)\to x_1=2,\ y_1=-5\\(-1,\ -1)\to x_2=-1,\ y_2=-1[/tex]

Substitute:

[tex]m=\dfrac{-1-(-5)}{-1-2}=\dfrac{-1+5}{-3}=\dfrac{4}{-3}=-\dfrac{4}{3}[/tex]

Answer:

$48.80

Step-by-step explanation:

If they get a 60% discount, then they only pay 40% of the fare.

So what you have to do is take 40% of 122.00 = 40/100 * 122  = 4880/100 = 48.80

So the sale price is 48.80 dollars

2.31 meters in height

2.65m - 0.34m = 2.31 meters

Answer

500*b > 5280

Solution

To get this to an answer, you have to divide by 500

b > 5280/500

b must be greater than 10.56 which is the answer to 5280/500

So you should say that he needs to hit 11 home runs, because 0.56 home runs is not possible.

Answer

11 home runs

[tex]36x^{18}+60x^9y^2+25y^4=6^2x^{9\cdot2}+2\cdot6x^9\cdot5y^2+5^2y^{2\cdot2}\\\\=6^2(x^9)^2+2\cdot6x^9\cdot5y^2+5^2(y^2)^2\qquad(*)\\\\=(6x^9)^2+2\cdot6x^9\cdot5y^2+(5y^2)^2\qquad(**)\\\\=(6x^9+5y^2)^2=(6x^2+5y^2)(6x^9+5y^2)\\\\Used:\\\\(*)\qquad(a^n)^m=a^{nm}\\\\(**)\qquad(a+b)^2=a^2+2ab+b^2[/tex]

The picture is only one white dot

Question 1:

For this case we have the following pattern of numbers:

24.3, 24, 23.7, 23.4

It can be seen that subtracting 0.3 from the first number of the pattern gives [tex]24.3-0.3 = 24\\[/tex]

Equally if we subtract 0.3 successively we obtain:

[tex]24-0.3 = 23.7\\\\23.7-0.3 = 23.4\\\\23.4-0.3 = 23.1\\\\23.1-0.3 = 22.8\\[/tex]

Thus, 0.3 must be subtracted from each term and the following numbers of the pattern shall be 23.1 and 22.8

Answer:

subtract 0.3 from each term

The next two numbers of the pattern are 23.1 and 22.8

Question 2:

For this case we have the following operation:

[tex]0.52 + 0.61 = 1.13\\\\1.13> 1\\[/tex]

We note that the sum is greater than 1

The sum of two hundredth decimals does not necessarily have to be greater than 1.

Therefore, the correct option is: the sum is greater than 1 because the sum shades more than one hundredths grid.

Answer:

Option C

Question 3:

For this case we have to:

[tex]a + b + c = 2\\[/tex]

Being a, b, c decimal numbers, one of them was 0.34. Suppose [tex]a = 0.34\\[/tex]

Thus: [tex]0.34 + b + c = 2\\[/tex]

We choose values ​​for b and c, in order to obtain the number 2 as a result of the sum. We can choose infinite values ​​so that equality is fulfilled

If[tex]b = 0.96[/tex] and

[tex]c = 0.7\\[/tex]

we have: [tex]0.34 + 0.96 + 0.7 = 2\\[/tex]

Thus, Holland can add to the sum [tex]b = 0.96[/tex] and [tex]c = 0.7\\[/tex]

Answer:

[tex]b = 0.96\\\\c = 0.7\\[/tex]

Question 4:

For this case we have the following subtraction:

[tex]3.5 - 2.46 = 1.16\\[/tex]

This operation is wrong, subtracting [tex]3.5-2.46[/tex] results in 1.04

Let's explain a model for Maysa:

We have the following expression

[tex]3.5 - 2.46\\[/tex]

Rewriting each number in expanded form we have:

[tex](3 + 0.5) - (2 + 0.46)\\[/tex]

Using the distributive property we have:

[tex](3 + 0.5) -2-0.46\\[/tex]

Using the associative property we have:

[tex](3-2) + (0.5-0.46)\\[/tex]

Performing each operation:

[tex]1 + 0.04 = 1.04\\[/tex]

Anwer:

The subtraction of Maysa is wrong, the correct answer is:

[tex]3.5 - 2.46 = 1.04[/tex]

Answer

Option B. Subtract 0.3 from each term.

Step-by-step explanation:

If you follow the pattern 24.3-24=0.3

similarly 24-23.7=0.3

23.7-23.4=0.3

Conclusion : We will subtract 0.3 every time in order to get the new number.

We use an exponent law here.

Since 1/xⁿ = x⁻ⁿ for positive number a and real number n, it follows that

  1 / 9⁴ = 9⁻⁴

The expression 1/9^4 can be changed to an expression using a negative exponent by applying the negative exponent rule, resulting in 9^-4.

To change the expression 1/9^4 to one using a negative exponent, we can apply the property of negative exponents which states that x^-n = 1/x^n. The expression 1/9^4 can thus be written as 9^-4 because we are in essence taking the inverse of 9 raised to the fourth power.

Here is the step-by-step explanation:

The values of data that may affect the statistical measures of center and spread are the outliers and extreme values in the female dataset.

Statistical measures of center include the mean, median, and mode, while measures of spread include the range, interquartile range (IQR), variance, and standard deviation.

 From the given box plots:

 For males:

- The minimum number of hours worked per week is approximately 15.

- The first quartile (Q1) is approximately 20.

- The median (Q2) is approximately 22.

- The third quartile (Q3) is approximately 25.

- The maximum number of hours worked per week is approximately 35.

 For females:

- The minimum number of hours worked per week is 0.

- The first quartile (Q1) is approximately 0.

- The median (Q2) is approximately 20.

- The third quartile (Q3) is approximately 25.

- The maximum number of hours worked per week is approximately 50.

In the male dataset, there are no apparent outliers or extreme values since the data is relatively compact with a narrow IQR and no data points far from the quartiles.

However, in the female dataset, there are potential outliers or extreme values:

- The minimum value of 0 hours worked per week is an outlier because it is far below the first quartile.

- The maximum value of approximately 50 hours worked per week is an extreme value because it is far above the third quartile.

These outliers and extreme values in the female dataset can significantly affect the measures of center and spread:

- The mean will be pulled down by the minimum value of 0 and up by the maximum value of 50, potentially making it less representative of the central tendency of the data.

- The range will be much larger due to the extreme maximum value.

- The IQR will not be affected by these outliers since it is based on the middle 50% of the data, but the overall spread of the data will be larger due to the presence of outliers.

- The variance and standard deviation will be increased by the presence of these outliers, indicating a larger spread in the data.

 In summary, the outliers and extreme values in the female dataset are the values that may affect the statistical measures of center and spread. These values can skew the mean, increase the variance and standard deviation, and extend the range, making these measures less indicative of the typical work hours for female students.