Chris is making a poster for Bike Safety Week. The diameter of circle A is 14 in.

If the area of circle B is the area of circle A, what is the area of circle B? (Use 3.14 for .)

Final answer:

To unfoil quickly, use the reverse foil method. Identify the first and last terms of each binomial, multiply them, and rewrite the middle term as the sum of the products. Example: (x + 2)(x - 3) = x^2 + 2x - 3x - 6.

Explanation:

To unfoil quickly, you can use a shortcut called the reverse foil method. Reverse foil allows you to quickly determine the original factors of a quadratic expression that has been expanded using the distributive property. Let's say we have the expression (x + 2)(x - 3) and we want to unfoil it. Start by identifying the first term of each binomial, which in this case is x from (x + 2) and x from (x - 3). Multiply these two terms together to get x^2. Then, identify the last term of each binomial, which is 2 from (x + 2) and -3 from (x - 3). Multiply these two terms together to get -6. Finally, rewrite the middle term of the expanded expression as the sum of the two products obtained: (x^2 + 2x - 3x - 6). In this way, you can unfoil the expression quickly and identify the original factors without having to expand it fully.

Answer:

3

Step-by-step explanation:

I know I'm late by 4 years but the answer is 3. This is because if you divide 12 by the 2 coins you'll get 6. You then need to divide it in half again because it's asking for both coins not only one. This gets you the answer of 3. I'm only writing this because other people may need help, 4 years later-

The required algebraic expression for the given statement is 11 - 2x. Option 3 is correct.

Given that,
Eleven is decreased by twice a number. To determine the correct option that shows the represents the statement using an algebraic expression.

The algebraic expression consists of constant and variable. eg x, y, z, etc.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
Let the number be x,
Eleven is decreased by twice a number.
= 11 - 2x

Thus, the required algebraic expression for the given statement is 11 - 2x. Option 3 is correct.

Learn more about algebraic expression here:

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The number of boys who attended the play is 40. Expressing this as a fraction of the total children (100), we get 40/100, which simplifies to 2/5. So, the fraction representing the number of boys on the trip is 2/5.

The provided information suggests that 60% (or 0.6) of the children on the trip, which were 100, were girls. This means the percentage or portion of girls on the trip is 0.6*100 = 60 girls. Since we're looking for the number of boys, we have to subtract this figure from the total number of children.

So, 100 total children - 60 girls = 40 boys. To express this as a fraction of the total number of children, we get 40/100. This fraction, however, can be simplified to 2/5, which is the fraction that represents the number of boys on the trip.

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Therefore, the area of trapezoid ABCD is 54 square units.

To find the area of trapezoid ABCD, we can use the properties of a trapezoid and the given information.

First, let's denote the unknown base of the trapezoid as BD = b. Since AD and BC are the other two bases, we have AD = 10 and BC = 8. The height of the trapezoid is the same as the altitude of triangle ACD, which is KC = h and is given to be such that the area of triangle ACD is 30.

The area of a triangle is given by the formula:

[tex]\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \][/tex]

 For triangle ACD, we have:

[tex]\[ 30 = \frac{1}{2} \times AD \times h \][/tex]

[tex]\[ 30 = \frac{1}{2} \times 10 \times h \][/tex]

[tex]\[ h = \frac{30 \times 2}{10} \][/tex]

[tex]\[ h = 6 \][/tex]

Now that we have the height of the trapezoid, we can calculate the area of the trapezoid using the formula:

[tex]\[ \text{Area} = \frac{1}{2} \times (\text{sum of parallel sides}) \times \text{height} \][/tex]

[tex]\[ \text{Area} = \frac{1}{2} \times (AD + BC) \times h \][/tex]

[tex]\[ \text{Area} = \frac{1}{2} \times (10 + 8) \times 6 \][/tex]

[tex]\[ \text{Area} = \frac{1}{2} \times 18 \times 6 \][/tex]

[tex]\[ \text{Area} = 9 \times 6 \][/tex]

[tex]\[ \text{Area} = 54 \][/tex]

Solution:

we are given that

Airplane has a wingspan of 15 feet.

we have been asked to find the wingspan of a model of the airplane, in inches, if the scale factor is 1:60 .

It mean for each one unit of original wingspan we are supposed to have [tex]\frac{1}{60}th[/tex] times the wingspan of model airplane.

Here the original airplane has a wingspan of 15 feet. So the model airplane has a wingspan of [tex]\frac{1}{60}*15=\frac{1}{4} ft[/tex]

Since one fit=12 inches So we can say

[tex] \frac{1}{4} ft=\frac{12}{4} inches=3 inches.[/tex]

Hence the model airplane has a wingspan of 3 inches.

Answer: I don’t know

Step-by-step explanation: I don’t know

Answer:number c + 6

Step-by-step explanation:

You're adding 6 to the number c

Answer

A is the answer

Step-by-step explanation:

I took the test

Answer:

Option D. 3g=21

Step-by-step explanation:

Let

g -----> the number of games

we know that

The number of games multiplied by 3 tickets to play a game must be equal to 21 tickets

so

The linear equation that represent this problem is

[tex]3g=21[/tex]

solve for g

Divide by 3 both sides

[tex]g=7[/tex]

Answer:

3g=21

Step-by-step explanation:

im smart (not really though){i got it right on imagine math}

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