Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.

Divide the following polynomial and then place the answer in the proper location on the grid. Write your answer in order of descending powers of y.

(y 3 - y 2 + y + 3) ÷ (y + 1)

THE ANSWER IS:
y^2-2y+3

The reason I included the correct answer is that this question has not been asked yet and I figured that someone might need to know this. Feel free to answer the question and get the points! :)

The expression that can be simplified by combining like terms is 16 c^2 + 8cd + 7c - 8d, where 8cd and -3dc are like terms and can be combined to simplify the expression to 16c^2 + 5cd + 7c - 8d.

The expression 16 c2 + 8cd + 7c - 8d can be simplified by combining like terms. Like terms in an algebraic expression are terms that have the same variable raised to the same power. Here, the terms 8cd and -3dc are like terms and can be combined.

Here's the step-by-step simplification:

This process of combining like terms helps in simplifying algebraic expressions, making them easier to work with.

After combining like terms, it's important to always check the answer to see if the simplification is reasonable and if there are any other like terms that can be combined.

So, the simplified expressions are:

1. [tex]\(6d^2 + (5c - 3d)d + 8\)[/tex]

2. [tex]\(12c^2 - (c(8d - 3)) + 4\)[/tex]

3. [tex]\(7d^2 - 3c^2 + 6d - c\)[/tex]

4. [tex]\(16c^2 + c(8d + 7) - 8d\)[/tex]

Let's simplify each expression by combining like terms:

1. [tex]\(6d^2 + 5cd - 3dc + 8\)[/tex]

  Combine like terms:

  [tex]\(6d^2 + (5cd - 3dc) + 8\)[/tex]

 [tex]\(6d^2 + (5c - 3d)d + 8\)[/tex]

2. [tex]\(12c^2 - 8d^2c + 3dc + 4\)[/tex]

  Combine like terms:

[tex]\(12c^2 - (8d^2c - 3dc) + 4\)[/tex]

  [tex]\(12c^2 - (c(8d - 3)) + 4\)[/tex]

3. [tex]\(7d^2 - 3c^2 + 6d - c\)[/tex]

  No like terms to combine.

4. [tex]\(16c^2 + 8cd + 7c - 8d\)[/tex]

  Combine like terms:

  [tex]\(16c^2 + (8cd + 7c) - 8d\)[/tex]

  [tex]\(16c^2 + c(8d + 7) - 8d\)[/tex]

Answer:

It is a rhombus.

Step-by-step explanation:

To identify the type of polygon, we will first determine if the opposite sides are parallel.  To do this, we find the slope of each line segment.  (Parallel lines have the same slope.)

For WX, m = (5-2)/(1-5) = 3/-4 = -3/4

For XY, m = (2--1)/(5-1) = 3/4

For ZY, m = (2--1)/(-3-1) = 3/-4 = -3/4

For ZW, m = (2-5)/(-3-1) = -3/-4 = 3/4

Since the slopes of WX and ZY are the same, these two sides are parallel.  Since the slopes of XY and ZW are the same, these two sides are parallel.  Since opposite sides are parallel, the figure is a parallelogram.

In order to be a rectangle, the angles would have to be right angles.  Since perpendicular lines have slopes that are negative reciprocals of each other, the slopes of adjoining sides would have to be opposite signs and flipped.  This is not the case, so the angles are not right; this means it is not a rectangle.

The only other option for a parallelogram without right angles would be a rhombus.  This is the case if the length of each side is the same.  We will use the distance formula for this:

[tex]WX=\sqrt{(5-2)^2+(1-5)^2}=\sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5\\\\XY=\sqrt{(2--1)^2+(5-1)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5\\\\YZ=\sqrt{(2--1)^2+(-3-1)^2}=\sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5\\\\ZW=\sqrt{(2-5)^2+(-3-1)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5[/tex]

Since the length of each side is the same, this figure is a rhombus.

y = k/x

Step-by-step explanation:

Answer:

11.18

Step-by-step explanation:

General Idea:

There are few exponent rules that need to be used to simplify the rational exponent to get to the answer.

Exponent rules:

[tex] Rule\; 1: a \cdot a \cdot a \cdot a =a^4\\ \\ Rule\; 2: (a^m)^n=a^{m \times n} [/tex]

Applying the concept:

Rewriting 81 as a number with an exponent using prime factorization.

[tex] 81=3 \times 3 \times 3 \times 3 = 3^4\\ \\ Applying \; Rule \; 1, \; we\; get\; \\\\81^{\frac{3}{4}}=(3^4)^{\frac{3}{4}} \\ \\ Applying \; Rule \; 2,\; we\; get\\ \\ 3^{4 \times\frac{3}{4} } = 3^{\frac{12}{4} }=3^3=3 \times 3 \times 3 = 27 [/tex]

Conclusion:

The above explanation explains why [tex] 81^{\frac{3}{4}} =27 [/tex]

[tex]c=14[/tex]

There is no extraneous solution because as we put the value of c in equation (1), it does not make the equation (1) not define.

Step-by-step explanation:

Given :

[tex]\dfrac {c-4}{c-2} = \dfrac {c-2}{c+2} - \dfrac{1}{2-c}[/tex]                   --------- (1)

Calculation :

[tex]\dfrac {c-4}{c-2} = \dfrac {(c-2)^2+(c+2)}{(c+2)(c-2)}[/tex]

[tex]c-4 = \dfrac {(c^2-4c+4)+(c+2)}{(c+2)}[/tex]

[tex](c-4)(c+2) = (c^2-3c+6)[/tex]

[tex](c^2-2c-8) = (c^2-3c+6)[/tex]

[tex]c=14[/tex]

There is no extraneous solution because as we put the value of c in equation (1), it does not make the equation (1) not define.

For more information, refer the link given below

https://brainly.com/question/11897796?referrer=searchResults

Answer:

14 and Zero

Step-by-step explanation:

Answer:

Temperature t > -15 degrees.

Step-by-step explanation:

Let t denote the temperature.

The inequality sign for above or greater is >. The inequality sign for less than is <.

It is given temperature stayed above -15 degrees.

This can be written in inequality form as t> -15 °(degrees)

The inequality to represent the temperature is t > -15°C

Given data:

To represent the situation where the temperature stayed above -15 degrees, the inequality symbol used is ">".

In an inequality, the ">" symbol means "greater than." By using this symbol,  the temperature needs to be greater than -15 degrees.

The inequality representing this situation is:

Temperature > -15°C

So, t > -15°C

If the temperature is higher than -15 degrees, the inequality is true.

To learn more about inequality equations click :

https://brainly.com/question/11897796

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