Compare the dotplot to a histogram of the data. (Select all that apply.)

(A) Histograms show the frequency of individual data values.
(B) The raw data can be retrieved from the dotplot, but not the histogram.
(C) Dotplots show the frequency of individual data values.
(D) The raw data can be retrieved from the histogram, but not the dotplot.

This sequence has generating function

[tex]F(x)=\displaystyle\sum_{k\ge0}k^3x^k[/tex]

(if we include [tex]k=0[/tex] for a moment)

Recall that for [tex]|x|<1[/tex], we have

[tex]\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k[/tex]

Take the derivative to get

[tex]\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k[/tex]

[tex]\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k[/tex]

Take the derivative again:

[tex]\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k[/tex]

[tex]\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k[/tex]

Take the derivative one more time:

[tex]\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k[/tex]

[tex]\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k[/tex]

so we have

[tex]\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}[/tex]

Answer:

[tex]x=-\frac{7}{2}[/tex] Extrema point.

The function does not have inflection points.

Step-by-step explanation:

To find the extrema points we have:

[tex]f'(x)=0[/tex]

Then:

[tex]f(x)=(2x+7)^4[/tex]

[tex]f'(x)=4(2x+7)^3(2)[/tex]

[tex]f'(x)=8(2x+7)^3[/tex]

Now:

[tex]f'(x)=8(2x+7)^3=0[/tex]

[tex]8(2x+7)^3=0[/tex]

[tex](2x+7)^3=0[/tex]

[tex]2x+7=0[/tex]

[tex]2x=-7[/tex]

[tex]x=-\frac{7}{2}[/tex]

To find the inflection points we need to calculate [tex]f''(x)=0[/tex] but due to that que have just one extrema point, the function does not have inflection points.

Answer:

Company A is a better deal than Company B for the number of miles greater than 295 miles

Step-by-step explanation:

Let

y ----> the charge per week in dollars

x ----> the number of miles

we have

Company A

[tex]y=331.35[/tex] -----> equation A

Company B

[tex]y=0.53x+175[/tex] -----> equation B

Solve the system by substitution

Equate equation A and equation B and solve for x

[tex]331.35=0.53x+175[/tex]

[tex]0.53x=331.35-175\\0.53x=156.35\\x=295\ mi[/tex]

For x=295 miles the charge in Company A and Company B is the same

therefore

Company A is a better deal than Company B for the number of miles greater than 295 miles

Answer:

0.2s is the time from the initial launch of the warhead to impact.

Step-by-step explanation:

This is a rule of three problem

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.

In this problem, our measures have a direct relationship.

The problem states that in a second, the warhead travels 489 meters. How long it takes to travel 100 meters? So

1s - 489m

xs - 100m

489x = 100

[tex]x = \frac{100}{489}[/tex]

x = 0.2s.

0.2s is the time from the initial launch of the warhead to impact.

Answer:

The probability that a student is proficient in mathematics, but not in reading is, 0.10.

The probability that a student is proficient in reading, but not in mathematics is, 0.17

Step-by-step explanation:

Let's define the events:

L: The student is proficient in reading

M: The student is proficient in math

The probabilities are given by:

[tex]P (L) = 0.81\\P (M) = 0.74\\P (L\bigcap M) = 0.64[/tex]

[tex]P (M\bigcap L^c) = P (M) - P (M\bigcap L) = 0.74 - 0.64 = 0.1\\P (M^c\bigcap L) = P (L) - P (M\bigcap L) = 0.81 - 0.64 = 0.17[/tex]

The probability that a student is proficient in mathematics, but not in reading is, 0.10.

The probability that a student is proficient in reading, but not in mathematics is, 0.17

As per the question,

Let a be any positive integer and b = 4.

According to Euclid division lemma , a = 4q + r

where 0 ≤ r < b.

Thus,

r = 0, 1, 2, 3

Since, a is an odd integer, and

The only valid value of r = 1 and 3

So a = 4q + 1 or 4q + 3

Case 1 :- When a = 4q + 1

On squaring both sides, we get

a² = (4q + 1)²

   = 16q² + 8q + 1

   = 8(2q² + q) + 1

   = 8m + 1 , where m = 2q² + q

Case 2 :- when a = 4q + 3

On squaring both sides, we get

a² = (4q + 3)²

   = 16q² + 24q + 9

   = 8 (2q² + 3q + 1) + 1

   = 8m +1, where m = 2q² + 3q +1

Now,

We can see that at every odd values of r, square of a is in the form of 8m +1.

Also we know, a = 4q +1 and 4q +3 are not divisible by 2 means these all numbers are odd numbers.

Hence , it is clear that square of an odd positive is in form of 8m +1

Therefore, the solution to the system of equations is:

x=0

y=-3t+4

z=t

We can solve the system of equations using Gaussian elimination with back-substitution. Here's how:

Steps to solve:

1. Eliminate x from the second and fourth equations:

x+y+3z=4

0=0 (2x+5y+15z=20)-(x+2y+6z=8)

3y+9z=12

-x+2y+6z=8

2. Eliminate y from the fourth equation:

x+y+3z=4

0=0

3y+9z=12

3y+9z=12 (3y+9z=12)-(3y+9z=12)

0=0

3. Since the last equation is always true, we can ignore it.

4. Solve the remaining equations:

x+y+3z=4

0=0

3y+9z=12

From the second equation, we know that y=-3z+4. Substituting this into the first equation, we get:

x+(-3z+4)+3z=4

x+4=4

x=0

Now that we know x=0, we can substitute it back into the third equation to solve for z:

3(-3z+4)+9z=12

-9z+12+9z=12

12=12

This equation is always true, so there are infinitely many solutions. We can express x, y, and z in terms of the parameter t as follows:

x=0

y=-3z+4

z=t

Complete Question:

Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTION. If the system has an infinite number of solutions, express x, y, and z in terms of the parameter t.)

3x + 3y + 9z = 12

x + y + 3z = 4

2x + 5y + 15z = 20

-x + 2y + 6z = 8

(x, y, z) =

Answer:

10.50x ≤ 205

The maximum number of tickets, x, would be 19.

Step-by-step explanation:

Given,

The cost of one ticket = $ 10.50,

The cost of x tickets = 10.50x dollars,

Since,  the total cost can not exceed  $ 205,

⇒ 10.50x ≤ 205

∵ 10.50 > 0 thus, when we multiply both sides by 1/10.50 the inequality sign will not change,

⇒ x ≤  [tex]\frac{205}{10.50}[/tex] ≈ 19.52

Hence, the maximum number of tickets would be 19.

Answer:

Step-by-step explanation:

Given that

[tex]r(t) = (6cost, 6sint, t), 0\leq t\leq 2\pi\\r'(t) = (-6sint, 6cost, 1),\\||r'(t)||=\sqrt{(-6sint)^2 +(6cost)^2+1} =\sqrt{37}[/tex]

Hence arc length = [tex]\int\limits^a_b {||r'(t)||} \, dt[/tex]

Here a = 0 b = 2pi and r'(t) = sqrt 37

Hence integrate to get

[tex]\int\limits^{2\pi}  _0  {\sqrt{37} } \, dt\\ =\sqrt{37} (t)\\=2\pi\sqrt{37}[/tex]

Answer:

Width = 15.

Length = 22.

Step-by-step explanation:

If the length is L then the width W =  1/2L + 4.

The perimeter = 2L + 2W, so

2L + 2(1/2L + 4) = 74

2L + L + 8 = 74

3L = 66

L = 22.

So W = 1/2 *22 + 4 = 11 + 4

= 15.

Answer:

5 rows.

Step-by-step explanation:

Imagine having 10 in each row. If you had 5 rows that means you have 5 groups of 10.

Answer:

Step-by-step explanation:

10 goes into 50, 5 times. I know this because if you multiply 10x5 it gives you 50!

Answer:

Look to the attached figure

Step-by-step explanation:

* Lets revise the steps of constructing with the same length of a given

 segment

- Use a ruler to draw a segment PQ of length 2 inches long

- Mark a point M that will be one endpoint of the new line segment

- Set the compasses pin on the point P of the line segment PQ

- Open the compass to the point Q

- The compasses width is now equal to the length of the segment PQ

- Without changing the compasses width place the pin of the compass

 at point M and draw an arc where the other endpoint will be on it

- Pick a point N on the arc that will be the other endpoint of the new

 line segment

- Draw a line from M to N

- The length of MN = The length of PQ

- The attached figure for more understand

Answer:

The distance is:  

[tex]\displaystyle\frac{3\sqrt{142}}{10}[/tex]

Step-by-step explanation:

We re-write the equation of the line in the format:

[tex]\displaystyle\frac{x+2}{3}=\frac{y+\frac{3}{2}}{2}=\frac{z+\frac{4}{3}}{\frac{5}{3}} [/tex]

Notice we divided the fraction of y by 2/2, and the fraction of z by 3/3.

In that equation, the director vector of the line is built with the denominators of the equation of the line, thus:

[tex]\displaystyle\vec{v}=\left< 3, 2, \frac{5}{3}\right> [/tex]

Then the parametric equations of the line along that vector and passing through the point (-2, 3, -4) are:

[tex]x=-2+3t\\y=3+2t\\\displaystyle z=-4+\frac{5}{3}t[/tex]

We plug them into the equation of the plane to get the intersection of that line and the plane, since that intersection is the image on the plane of the point (-2, 3, -4)  parallel to the given line:

[tex]\displaystyle x+y+z=3\to -2+3t+3+2t-4+\frac{5}{3}t=3[/tex]

Then we solve that equation for t, to get:

[tex]\displaystyle \frac{20}{3}t-3=3\to t=\frac{9}{10}[/tex]

Then plugging that value of t into the parametric equations of the line we get the coordinates of the intersection:

[tex]\displaystyle x=-2+3\left(\frac{9}{10}\right)=\frac{7}{10}\\\displaystyle y=3+2\left(\frac{9}{10}\right)=\frac{24}{5} \\\displaystyle z=-4+\frac{5}{3}\left(\frac{9}{10}\right)=-\frac{5}{2}[/tex]

Then to find the distance we just use the distance formula:

[tex]\displaystyle d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}[/tex]

So we get:

[tex]\displaystyle d=\sqrt{\left(-2-\frac{7}{10}\right)^2+\left(3-\frac{24}{5}\right)^2+\left(-4 +\frac{5}{2}\right)^2}=\frac{3\sqrt{142}}{10}[/tex]

Step-by-step explanation:

Let's consider C is a matrix given by

[tex]\left[\begin{array}{ccc}a&b&c\\d&e&f\\g&h&i\end{array}\right][/tex]

them determinant of matrix C can be written as

[tex]\begin{vmatrix}a & b & c\\ d & e & f\\  g & h & i \end{vmatrix}\ =\ 4.....(1)[/tex]

Now,

[tex]det (C+C)\ =\ \begin{vmatrix}a & b & c\\ d & e & f\\  g & h & i \end{vmatrix}\ +\ \begin{vmatrix}a & b & c\\ d & e & f\\  g & h & i \end{vmatrix}[/tex]

                  [tex]=\ \begin{vmatrix}2a & 2b & 2c\\ 2d & 2e & 2f\\  2g & 2h & 2i \end{vmatrix}[/tex]

                   [tex]=\ 2\times 2\times 2\times \begin{vmatrix}a & b & c\\ d & e & f\\  g & h & i \end{vmatrix}[/tex]

                   [tex]=\ 8\times 4\ \ \ \ \ \ \ \         from\ eq.(1)[/tex]

                    = 32      

Hence, det (C+C) = 32

Answer:

2x - y - 7 = 0

Step-by-step explanation:

Since the slope of parallel line are same.

So, we can easily use formula,

y - y₁ = m ( x ₋ x₁)

where, (x₁, y₁) = (8, 9)

and m is a slope of line passing through (x₁, y₁).

and since the slope of parallel lines are same, so here we use slope of parallel line for calculation.

and, Slope = m = [tex]\dfrac{y_{b}-y_{a}}{x_{b}-x_{a}}[/tex]

here, (xₐ, yₐ) = (2, 7)

and, [tex](y_{a},y_{b}) = (1, 5 )[/tex]

⇒ m = [tex]\dfrac{5-7}{1-2}[/tex]

⇒ m = 2

Putting all values above formula. We get,

y - 9 = 2 ( x ₋ 8)

⇒ y - 9 = 2x - 16

⇒ 2x - y - 7 = 0

which is required equation.

Answer:

y=2x-8

Step-by-step explanation:

In order to solve this you first have to calculate the slope of the parallel line, since that would be equal to the slope of our line:

[tex]Slope=\frac{y2-y1}{x2-x1}[/tex]

Now we insert the values into the formula:

[tex]Slope=\frac{y2-y1}{x2-x1}\\Slope=\frac{5-7}{1-2}\\Slope= \frac{-2}{-1}\\ Slope:2[/tex]

And remember that the formula for general line is:

[tex]Y-y1= M(x-x1)\\y-9=2(x-8=\\y=2x-16+9\\y=2x-7[/tex]

So the equation for the line passing through point 8,9 and parallel to the line joining 2,7 and 1,5 would be y=2x-7

Answer: 3253

Step-by-step explanation:

Given : A test requires that you answer either part A or part B.

Part A consists of 7 true-false questions.

i.e.  there are 2 choices to answer each question.

Now, the number of ways to answer Part A : [tex]2^7=128[/tex]    (1)

Part B consists of 5 multiple-choice questions with one correct answer out of five.

i.e.  there are 5 choices to answer each question.

Now, the number of ways to answer Part B : [tex]5^5=3125[/tex]                           (2)

Now, the number of  different ways to completed answer sheets are possible=  [tex]128+3125=3253[/tex]          [Add (1) and (2) ]

The number of different completed answer sheets possible is 400,000.

To find the number of different completed answer sheets, we need to determine the number of ways to choose either part A or part B, and then calculate the number of possible combinations for each part.

For part A, since there are 7 true-false questions, each with 2 choices (true or false), there are 2^7 = 128 possible answer combinations.

For part B, since there are 5 multiple-choice questions, each with 5 choices, there are 5^5 = 3125 possible answer combinations.

To calculate the total number of different completed answer sheets, we multiply the number of choices for part A (128) by the number of choices for part B (3125), giving us a total of 128 * 3125 = 400,000 possible answer sheets.

Answer:

27.19°

Step-by-step explanation:

According to the picture attached, we can find the distance between the two vectors using cosine law

[tex]a^{2} =b^{2} +c^{2} -2ab*cosA\\a=\sqrt{b^{2} +c^{2} -2ab*cosA} \\\\a=\sqrt{2.1^{2} +8.9^{2} -2(2.1)(8.9)*cos21}\\a=6.98\\\\[/tex]

Then we can get C angle by applying one more time cosine law between a and b

[tex]c^{2} =a^{2} +b^{2} -2ab*cosC\\\\c^{2} -a^{2} -b^{2}= -2ab*cosC\\\\\frac{c^{2} -a^{2} -b^{2}}{-2ab}=cosC\\ \\CosC=\frac{8.9^{2} -6.98^{2} -2.1^{2}}{-2*6.98*2.1}\\ \\CosC=-0.89\\\\ArcCos(-0.89)=C\\\\C=152.81[/tex]

We can see that the C angle is complement of the angle we are looking for, so we take away 180 degrees to get the answer

[tex]180=C+?\\\\180-C=?\\\\180-152.81=C\\\\27.19=C[/tex]

27.19 degrees is our answer!

Answer:

80 %

Step-by-step explanation:

Hi there!

To find the percent of hot dogs with mustard we must divide the number of hotdogs with mustard by the number of total hotdogs, and multiply this number by 100:

[tex]P = \frac{N_{withMustard}}{N_{total}}*100= 100*(4/5) = 80[/tex]

Greetings!

Answer:

x=-3

|-x| = 3

|x| = 3

Step-by-step explanation:

we know that

If a number is a solution of a equation, then the number must satisfy the equation

Verify each case

case 1) we have

x=3

substitute the value of x=-3

-3=3 -----> is not true

therefore

x=-3 is not a solution of the given equation

case 2) we have

x=-3

substitute the value of x=-3

-3=-3 -----> is true

therefore

x=-3 is  a solution of the given equation

case 3) we have

|-x| = 3

substitute the value of x=-3

|-(-3)| = 3

|3| = 3

3=3-----> is true

therefore

x=-3 is a solution of the given equation

case 4) we have

|x| = 3

substitute the value of x=-3

|(-3)| = 3

3=3-----> is true

therefore

x=-3 is a solution of the given equation

case 5) we have

-|x| = 3

substitute the value of x=-3

-|(-3)| = 3

-3=3-----> is not true

therefore

x=-3 is not a solution of the given equation

Answer:

[tex]2e^{y'}y=0[/tex]

Step-by-step explanation:

The solution for this differential equation [tex]2e^{y'}y=0[/tex] have to be the trivial solution y=0. Because the function [tex]e^{x}[/tex] always have values different of zero, then the only option is the trivial solution y=0.

Step-by-step explanation:

Proposition If a, b [tex]\in[/tex] [tex]\mathbb{Z}[/tex], then [tex]a^{2}-4b \neq2[/tex]

You can prove this proposition by contradiction, you assume that the statement is not true, and then show that the consequences of this are not possible.

Suppose the proposition If a, b [tex]\in[/tex] [tex]\mathbb{Z}[/tex], then [tex]a^{2}-4b \neq2[/tex] is false. Thus there exist integers If a, b [tex]\in[/tex] [tex]\mathbb{Z}[/tex] for which [tex]a^{2}-4b=2[/tex]

From this equation you get [tex]a^{2}=4b+2=2(2b+1)[/tex] so [tex]a^{2}[/tex] is even. Since [tex]a^{2}[/tex] is even, a is even, this means [tex]a=2d[/tex] for some integer d. Next put [tex]a=2d[/tex] into [tex]a^{2}-4b=2[/tex]. You get [tex] (2d)^{2}-4b=2[/tex] so [tex]4(d)^{2}-4b=2[/tex]. Dividing by 2, you get [tex]2(d)^{2}-2b=1[/tex]. Therefore [tex]2((d)^{2}-b)=1 [/tex], and since [tex](d)^{2}-b[/tex] [tex]\in[/tex] [tex]\mathbb{Z}[/tex], it follows that 1 is even.

And that is the contradiction because 1 is not even.  In other words, we were wrong to assume the proposition was false. Thus the proposition is true.

Answer:

It isn't possible.

Step-by-step explanation:

Let G be a graph with n vertices. There are n possible degrees: 0,1,...,n-1.

Observe that a graph can not contain a vertice with degree n-1 and a vertice with degree 0 because if one of the vertices has degree n-1 means that this vertice is adjacent to all others vertices, then the other vertices has at least degree 1.

Then there are n vertices and n-1 possible degrees. By the pigeon principle there are two vertices that have the same degree.

Answer:

20%

Step-by-step explanation:

To find what percentage is $10 out of $50, we divide 10 by 50:

[tex] \frac{10}{50}=0.2[/tex]

If we want to get the result in percentage form, we simply multiply it by 100%:

[tex]0.2\cdot 100\%=20\%[/tex]

So a tip of $10 on a $50 bill is a tip of 20%.

Answer:

a) [tex]c'(t) = (2 Cos(t), -2 Sin(t), 9e^t) [/tex]

b) [tex]c'(t) = (2 Cos(t), -2 Sin(t), 9e^t) [/tex]

Step-by-step explanation:

We are given in the question:

[tex]c(t) = (2 Sin(t), 2 Cos(t), 9e^t)[/tex]

F(x,y,z) = (y, -x, z)  

a) [tex]c'(t) [/tex]

We differentiate with respect to t.

[tex]c'(t) = (2 Cos(t), -2 Sin(t), 9e^t) [/tex]

b) F(c(t))

This is a composite function.

[tex]F(c(t)) = F(2 Sin(t), 2 Cos(t), 9e^t)[/tex]

[tex]= (2 Cos(t), -2 Sin(t), 9e^t)[/tex]

Answer:

The given function is differentiable at y = 1.

At y = 1, f'(z)  = 0

Step-by-step explanation:

As per the given question,

[tex]f(z)\ = (x^{2}+y^{2}-2y)+i(2x - 2xy)[/tex]

Let z = x + i y

Suppose,

[tex]u(x,y) = x^{2}+y^{2}-2y[/tex]

[tex]v(x,y) = 2x - 2xy[/tex]

On computing the partial derivatives of u and v as:

[tex]u'_{x} =2x[/tex]

[tex]u'_{y}=2y -2[/tex]

And

[tex]v'_{x} =2-2y[/tex]

[tex]v'_{y}=-2x[/tex]

According to the Cauchy-Riemann equations

[tex]u'_{x} =v'_{y} \ \ \ \ \ \ \ and\ \ \ \ \ \ u'_{y} = -v'_{x}[/tex]

Now,

[tex](u'_{x} =2x) \neq (v'_{y}=-2x)[/tex]

[tex](u'_{y}=2y -2) \ = \ (- v'_{x} =-(2-2y) =2y-2)[/tex]

Therefore,

[tex]u'_{y}=- v'_{x}[/tex] holds only.

This means,

2y - 2 = 0

⇒ y = 1

Therefore f(z) has a chance of being differentiable only at y =1.

Now we can compute the derivative

[tex]f'(z)=\frac{1}{2}[(u'_{x}+iv'_{x})-i(u'_{y}+iv'_{y})][/tex]

[tex]f'(z) =\frac{1}{2}[(2x+i(2-2y))-i(2y-2+i(-2x))][/tex]

[tex]f'(z) = i(2-2y)[/tex]

At y = 1

f'(z) = 0

Hence, the required derivative at y = 1 ,  f'(z)  = 0

Answer: [tex]20.38\ cm^2[/tex]

Step-by-step explanation:

We know that the circumference of a circle is given by :-

[tex]C=2\pi r[/tex], where r is the radius of the circle .

Given : Circumference of circle = 16 cm

Then, [tex]16=2\pi r[/tex]

i.e [tex]r=\dfrac{16}{2\pi}=\dfrac{8}{\pi}[/tex]          (1)

We know that the area of circle is given by :-

[tex]A=\pi r^2[/tex]

i.e. [tex]A=\pi (\dfrac{8}{\pi})^2[/tex]                    [From (1)]

i.e. [tex]A=\pi (\dfrac{64}{\pi^2})[/tex]

i.e. [tex]A=\dfrac{64}{\pi}[/tex]

Put [tex]\pi=3.14[/tex]

[tex]A=\dfrac{64}{3.14}=20.3821656051approx20.38\ cm^2[/tex]

Hence, area of circle = [tex]20.38\ cm^2[/tex]

Step-by-step explanation:

On a field every element different from 0 should have a multiplicative inverse. Let's check that in Z2[i] not ALL nonzero elements have multiplicative inverses.

Z2 is made of two elements: 0 and 1, and so Z2[i] is made of four elements: 0+0i,0+1i, 1+0i, 1+1i (which we can simplify from now on as 0, i, 1, 1+i respectively). Now, let's check that the element 1+i doesn't have a multiplicative inverse (we can do this by showing that no matter what we multiply it by, we're not getting 1, which is the multiplicative identity)

[tex](1+i)\cdot 0 = 0[/tex] (which is NOT 1)

[tex](1+i)\cdot i = i+i^2=i-1=1+i[/tex] (which is NOT 1) (remember -1 and 1 are the same in Z2)

[tex](1+i)\cdot 1 = 1+i[/tex] (which is NOT 1)

[tex](1+i)\cdot (1+i) = 1+i+i+i^2=1+2i-1=0+0i=0[/tex] (which is NOT 1) (remember 2 is the same as 0 in Z2)

Therefore the element 1+i doesn't have a multiplicative inverse, and so Z2[i] cannot be a field.

The confidence interval for population mean is given by :-

[tex]\hat{p}\pm E[/tex], where [tex]\hat{p}[/tex] is sample proportion and E is the margin of error .

[tex]E=z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]

Given : Significance level : [tex]\alpha:1-0.95=0.05[/tex]

Sample size : n= 64

Critical value : [tex]z_{\alpha/2}=1.96[/tex]

Sample proportion: [tex]\hat{p}=\dfrac{22}{64}\approx0.344[/tex]

[tex]E=(1.96)\sqrt{\dfrac{0.344(1-0.344)}{64}}\approx0.1164[/tex]

Hence, the margin of error = 0.1164

Now, the 95% theory-based confidence interval for the population proportion will be :

[tex]0.344\pm0.1164\\\\=(0.344-0.1164,\ 0.344+0.1164)=(0.2276,\ 0.4604)[/tex]

Hence, the  99% confidence interval is [tex](0.2276,\ 0.4604)[/tex]

When constructing a 95% theory-based confidence interval for the proportion of people that can correctly identify the different cola, the interval ranges from about 0.225 to 0.463. The margin of error is approximately 0.118.

This question pertains to a theory-based confidence interval for the population proportion. In this case, the proportion (p) is the number of people who correctly identified the different cola, which is 22 out of 64, or 0.34375. First, we need to calculate the standard error (SE), which is the square root of [ p(1-p) / n ], where n is the sample size. So, SE = sqrt[ 0.34375(1-0.34375) / 64 ] ≈ 0.0602.

The 95% confidence interval can be calculated as p ± Z * SE, where Z is the Z-score from the standard normal distribution corresponding to the desired level of confidence. For a 95% confidence interval, Z = 1.96. Plug the values into the equation gives us the interval [0.34375 - 1.96(0.0602), 0.34375 + 1.96(0.0602)] which is approximately [0.225, 0.463].

The margin of error is the difference between the endpoint of the interval and the sample proportion, which can be calculated as Z*SE. So the margin of error = 1.96(0.0602) ≈ 0.118.

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Answer:

5) True. G is the Number of grams of fuel, g, needed to raise the temperature of a solution, α, to a temperature of 312◦F.

Step-by-step explanation:

Hi!

Let's examine better this equation: [tex]g=\frac{312}{a}[/tex]

What we have here 312 is a dependent variable, and it is inversely proportional to a. The more a increases the more g decreases.

1) Number of degrees that a skateboarder turns when making "α" rotations

[tex]g=\frac{312}{a}[/tex]

1 rotation ----------- 312°

2 rotation ----------- 156°

Here we have a problem. The skateboarder must necessarily and randomly turn 312°, and its fractions. But in a circle, the rotation cannot follow this pattern.

False

2) The total number of groups, g, with "α" students each that can be made if there are 312 students to be grouped.

[tex]g=\frac{312}{a}[/tex]

1 group --------------- 312 students

2 groups ------------ 156 students

5 groups -------------62.4 students

Even though 312 is divisible for 1,2,3,4 it is not for 5,7,9, and the group is a countable, natural category.

False

3) Weight of a bag containing "α" grapefruits if each piece of fruit weighs 312 grams

[tex]g=\frac{312}{a}[/tex]

g=1 bag with 1 grapefruit-------------- 312 g

g=1 bag with 2 grapefruits ---------- 156 g

That doesn't make sense, since for this description. The best should be g=312a and not g=312/a.

False

4) The total number of goats that can graze on 312 acres if each acre can feed "α" goats.

Since there's a relation

1 acre can feed ----------------- 1 goat

312 acres can feed ----------------g

g= 312/1 = 312 acres can feed 1 goat (1 acre for 1 goat)

g=312/2= since 312 acres can feed 156 goats (1 acre for 2 goats)

g =312/3 = 312 acres can feed 104 (1 acre for 3 goats)

Clearly, this function g=312/a does not describe this since the ratio is not the same, as long as we bring more goats to graze on those 312 acres.

False

5) Number of grams of fuel, g, needed to raise the temperature of a solution, α, to a temperature of 312◦F

g= number of grams of a fuel

a= initial temperature of a solution

g=312/a

Let's pick a=100 F initial temperature

g=312/100

g=3.12 grams

Let's now pick 200F as our initial temperature.

g=312/200 g=1.56 grams of solution

The more heat needed to raise, the more fuel necessary. Then True

Answer:

The present value (or initial investment) is $4000.00

Step-by-step explanation:

I'm going to assume that the correct formula here is

[tex]A(t)=P(1+r)^t[/tex]

and we are looking to solve for P, the principle investment.  We know that A(t) is 4370.91; r is .03 and t is 3:

[tex]4370.91=P(1+.03)^3[/tex] and

[tex]4370.91=P(1.03)^3[/tex] and

4370.91 = 1.092727P so

P = 4000.00