Complete the missing portion of the equation.
f(x) = 1/x^2 and g(x) =1/2x+4
f[g(x)] = 4x^2 _______
+ 16x + 16
+ 8x + 16
+16

Answer:

4700

Step-by-step explanation:

Area for rectangle is length times width (lw) so it is 50*94 = 4700

Answer:

A. x<7

Step-by-step explanation:

B. x < 28

C. x < 50

D. x < 24

These answers exceed the cat adoption facilities cat limit.

Rate as Brainliest plz

Answer:

A. x<7

Step-by-step explanation:

We know three things:

Now we want to know how many more days the facility can continue to take in cats if none of their cats get adopted.

First, we want to know how many cats until the facility exceeds the occupancy and to do it we have to subtract the occupancy minus the cats they already have:

200 - 172 = 28

With this answer, we know that if they get 28 more cats they will have 200 cats and the occupancy has to be below 200.

Now we want to know how many days will it take them to get 28 more cats:

We know that every day they get 4 cats, so we are going to divide the number of cats to get 200 by the number of cats they get every day:

28(cats) / 4(cats per day) = 7 days

So in 7 days, they will pass their occupancy, which means that they can only take cats less than 7 days.

The expression will be:

x < 7

Where:

x is how many more days they can take in cats

< means less than

Step-by-step explanation:

To solve this system of equations, you can use either substitution or elimination. Let's use the elimination method.

First, multiply the second equation by 4 to make the coefficients of \( x \) in both equations opposites:

\( (2x + 5y) \times 4 = -28 \times 4 \)

This gives us:

\( 8x + 20y = -112 \)

Now, we'll subtract the first equation from this modified second equation:

\( (8x + 20y) - (-8x + 15y) = -112 - (-28) \)

Simplify:

\( 8x + 20y + 8x - 15y = -112 + 28 \)

\( 16x + 5y = -84 \)

Now we have a new equation:

\( 16x + 5y = -84 \)

And the first equation remains the same:

\( -8x + 15y = -28 \)

Now, we can solve this system of equations by elimination or substitution. Let's continue with elimination. Multiply the first equation by 2:

\( -16x + 30y = -56 \)

Now, add this equation to the second modified equation:

\( (-16x + 30y) + (16x + 5y) = -56 - 84 \)

\( 30y + 5y = -140 \)

\( 35y = -140 \)

Divide both sides by 35:

\( y = -4 \)

Now, substitute \( y = -4 \) into one of the original equations to solve for \( x \). Let's use the first equation:

\( -8x + 15(-4) = -28 \)

\( -8x - 60 = -28 \)

Add 60 to both sides:

\( -8x = -28 + 60 \)

\( -8x = 32 \)

Divide both sides by -8:

\( x = -4 \)

So, the solution to the system of equations is \( x = -4 \) and \( y = -4 \).

Hey!

-----------------------------------------------------------

Solution:

= 7√3 + 2√9

= 7√3 + 6

= 18.124... (Non-Terminating or Irrational)

When we add a rational number and a irrational number it's always irrational.

-----------------------------------------------------------

Answer:

The answer 7√3 + 6 is irrational because the sum of a rational number and irrational number is an irrational number.

-----------------------------------------------------------

Hope This Helped! Good Luck!

Answer:

d) The sum of an Irrational number and a Rational Number is still an Irrational Number

Step-by-step explanation:

[tex]7\sqrt{3}+2\sqrt{3^2}=7\sqrt{3}+6[/tex]

Rational Number = Any number that can be written as a quotient a/b form

Irrational Number =Any number that cannot be written as quotient a/b form

Since we have an Irrational number such as [tex]7\sqrt{3}=7*1.73....[/tex]it's another non-terminating and non-repeating number if I add 6 (rational number since 6=6/1) units to as addend to this sum is still an irrational number as the sum.

Answer:

[tex]\frac{x+2}{x-1}[/tex]

Step-by-step explanation:

Factorise the numerator and denominator

2x² + 2x - 4 ← factor out 2 from each term

= 2(x² + x - 2)

= 2(x + 2)(x - 1) ← in factored form

2x² - 4x + 2 ← factor out 2 from each term

= 2(x² - 2x + 1)

= 2(x - 1)² ← in factored form

Thus

[tex]\frac{2x^2+2x-4}{2x^2-4x+2}[/tex]

= [tex]\frac{2(x+2)(x-1)}{2(x-1)^2}[/tex]

Cancel 2 and factor (x - 1) on numerator/ denominator, leaving

= [tex]\frac{x+2}{x-1}[/tex]

Answer:

yes

Step-by-step explanation:

The number 86.7 is a rational number. It is possible to obtain the number 86.7 by dividing the integer 867 by the integer 10, as in 867/10. Because 86.7 is a quotient that results when two integers are divided, we say that 86.7 is a rational number.

Answer:

14 units greater.

Step-by-step explanation:

Subtracting:

n + 3 - (n - 11)

= n - n + 3 + 11

= 14.

If we subtract n-11 from n+3 then we found n+3 is greater from n-11  by 14.

In mathematics difference means the difference in values means which value is how much greater than or less than from other.

We have to find how much is n+3 greater than n-11.

We have just subtract n-11 from n+3

=n+3-(n-11)

=n+3-n+11

=14

Hence n+3 is 14 number greater than n-11.

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given

[tex] \frac{x - 2}{x - 5} [/tex]

put x = 6 into equation

[tex] \frac{6 - 2}{6 - 5} [/tex]

[tex] = \frac{4}{1} [/tex]

[tex] = 4[/tex]

Final answer:

The value of the rational expression (x-2)/(x-5) when x is 6 is 4.

Explanation:

To find the value of the rational expression x-2/x-5 when x is equal to 6, simply substitute the value of x into the expression:

((6-2)/(6-5) = 4/1 = 4)

So, the value of the expression when x is 6 is 4.

Answer:

No, the phrase 20 more indicates addition.

For instance, 20 more than 50 is 70.

Answer:

r = q -6

Step-by-step explanation:

q= [tex]\frac{q}{r} -6[/tex]

[tex]\frac{\frac{q}{r} -6}{r}[/tex]

You do kcf (keep it, change it, flip it)

[tex]\frac{q}{r} -6 times \frac{r}{1}[/tex]

To solve the equation q/r - 6 = q for r, you need to isolate the variable r on one side of the equation.

To solve the equation q/r - 6 = q for r, we need to isolate the variable r on one side of the equation. First, we'll get rid of the fraction by multiplying both sides of the equation by r. This gives us r(q/r) - 6r = qr. Simplifying further, we have q - 6r = qr. Next, we'll move all the terms involving r to one side by subtracting qr from both sides of the equation. This gives us q - qr - 6r = 0. Factoring out the common factor of r from the last two terms, we have q - r(q + 6) = 0. Finally, we solve for r by dividing both sides of the equation by q + 6. So, the solution to the equation is r = q/(q + 6).

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Answer:

She is wrong and the correct answer is [tex]\frac{5}{21}[/tex].

Step-by-step explanation:

The given expression is

[tex]\frac{4}{7}-\frac{1}{3}[/tex]

Sandra says that [tex]\frac{4}{7}-\frac{1}{3}=\frac{3}{4}[/tex] because all you have to do is subtract the numerators and subtract the denominators.

She is wrong. The correct method is shown below.

Make the denominator common.

[tex]\frac{4\times 3}{7\times 3}-\frac{1\times 7}{3\times 7}[/tex]

[tex]\frac{12}{21}-\frac{7}{21}[/tex]

On further simplification we get

[tex]\frac{12-7}{21}[/tex]

[tex]\frac{5}{21}[/tex]

Therefore, the correct answer is [tex]\frac{5}{21}[/tex].

Answer:   A rational number is any number that can be written as a fraction where the numerator and denominator are counting numbers.

Hope this helps

Step-by-step explanation:

Answer:

Pythagorean theorem:

14.03 ft

Step-by-step explanation:

Answer:

76.5$

Step-by-step explanation:

8.5 x 9 = 76.5

Answer:

C

Step-by-step explanation:

The absolute value always returns a positive value, that is

| - a | = | a | = a, thus

| 3 [tex]\frac{1}{2}[/tex] | = 3 [tex]\frac{1}{2}[/tex] → C

The height of the building is 315 feet because the ratio of the building's height to the post's height is equal to the ratio of the building's shadow length to the post's shadow length.

This problem can be solved using the concept of proportionality.

The height of the building is proportional to the length of its shadow, and the height of the post is proportional to the length of its shadow.

Express this mathematically as follows:

Building height / Post height = Shadow length / Post shadow length

Substituting the known values:

Building height / 3 feet = 105 feet / 4 inches

Convert 105 feet to inches first. 105 feet is equal to 105 × 12 = 1260 inches.

Rewrite the equation as follows:

Building height / 3 feet = 1260 inches / 4 inches

The units cancel out, and are left with:

Building height = 1260 / 4 = 315 feet

Therefore, the height of the building is 315 feet.

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Final answer:

To calculate the building's height, we set up a proportion using similar triangles. With the shadow of the building being 105 feet and the shadow of a 3-foot post being 4 inches (1/3 feet), we solve the proportion to find that the building is 315 feet tall.

Explanation:

To determine the height of the building, we can use similar triangles. The method involves setting up a proportion based on the principle that similar triangles have corresponding sides that are in the same ratio. Given the length of the building's shadow and the length of the shadow cast by a known post, we can find the building's height.

Let's define the following variables: B for the height of the building, Sb for the length of the building's shadow, P for the height of the post, and Sp for the length of the post's shadow. From the problem, Sb = 105 feet, P = 3 feet, and Sp = 4 inches, which is 1/3 feet since there are 12 inches in a foot.

Using these variables, the proportion can be set up as follows:

Plugging in the known values, we get:

By solving this proportion for B, we find that:

Therefore, the height of the building is 315 feet.

If x is 8, then plug 8 into the expression:

x+9

= (8)+9

= 17

I'm pretty sure this is correct!

Answer: 17      hope it helps (⌐■-■)

Step-by-step explanation:

Answer:

B.Associate their brand with a reference group of star athletes

Step-by-step explanation:

At a company that markets televisions, marketers learn that many of the consumers who are willing to pay for high-quality televisions are sports fans.

B.Associate their brand with a reference group of star athletes.

This seems the most appropriate answer. When a brand is associated with someone we like, it is very likely that we use the same products like that person.

Answer:

a: yes

b: no

c:yes

D: yes

Step-by-step explanation:

inal answer:

To determine divisibility by 3, the sum of the digits in a number must be divisible by 3. The numbers 27, 123, and 402 are divisible by 3, while 35 is not.

Explanation:

To determine whether a number is divisible by 3, you can use the rule that a number is divisible by 3 if the sum of its digits is divisible by 3. Here are the step-by-step examinations for each of the numbers:

27: The digits add up to 2 + 7 = 9, which is divisible by 3. Yes, 27 is divisible by 3.

35: The digits add up to 3 + 5 = 8, which is not divisible by 3. No, 35 is not divisible by 3.

123: The digits add up to 1 + 2 + 3 = 6, which is divisible by 3. Yes, 123 is divisible by 3.

402: The digits add up to 4 + 0 + 2 = 6, which is divisible by 3. Yes, 402 is divisible by 3.

Answer:

10+5

Step-by-step explanation:

It is the answer In my views

Hi there! I will try my best to help you. If the answers I give you are wrong, I am so sorry.

Answer:

1. <

2. <

3. >

7.  Apricot sulphur, large orange sulphur, white-angled sulfur, great white

9. 8 (with the sign), 7/2 (with the sign), 2

10. pi, 12 (with the sign), 3.5

11. -20, 26 (with the sign), 35 (with the sign), 13.5

12. -5.25, 3/2, 6 (with the sign), 5

Answer:

lol this is a lot

Step-by-step explanation:

Answer:

There were 121 rain jacket were collected

Step-by-step explanation:

* Lets explain how to solve the problem

- On the first day of the clothing drive, 11 rain jackets were collected

- At the end of the drive 10 times that number of rain jackets were

 collected

- We want to find how many rain jackets were collected

∵ There were 11 rain jacket were collected on the first day

∵ Ten times that number were collected at the end of the drive

- Ten times means we will multiply the number of rain jacket in

 the first day of the clothing drive by 10

∴ The number of rain jacket at the end of the drive = 10 × 11 = 110

∴ There were at the end of the drive 110 jackets

- To find the number of the rain jacket were collected is the sum

 of the number of rain jacket at the first day and at the end of

 the drive

∴ The number of rain jacket = 110 + 11 = 121

* There were 121 rain jacket were collected

Answer: 2(x+5)2+ 8x + 5+6=0

Step-by-step explanation:

2(x + 5)2 + 8x + 5 + 6=0

2(x+5)(x+5) + 8x + 11=0

2(x^2+ 10x + 25) + 8x + 11=0

2x^2 +20x + 50 + 8x + 11=0

2x^2 +28x +66=0

This is a second-degree equation, the greatest power is two. Hence it is a quadratic equation.

None of the given equations are purely quadratic in form; they include terms of higher degrees or additional constant terms. Therefore, none of them fit the criteria.

To determine which equation is quadratic in form, we need to look for equations that can be written in the form [tex]\(ax^2 + bx + c = 0\)[/tex], where [tex]\(a\), \(b\), and \(c\) are constants and \(x\)[/tex] is the variable.

Let's analyze each given equation:

[tex]1. \(2(x + 5)^2 + 8x + 5 + 6 = 0\)[/tex]

  This equation involves a quadratic term [tex]\((x + 5)^2\)[/tex], but it also includes linear and constant terms. Therefore, it is not purely quadratic in form.

2. [tex]\(x^6 + 6x + 8 = 0\)[/tex]

  This equation contains a sixth-degree term [tex]\(x^6\)[/tex], making it a polynomial of degree 6. It is not quadratic in form.

[tex]3. \(7x^6 + 36x^3 + 5 = 0\)[/tex]

  Similar to the previous equation, this equation contains a sixth-degree term [tex]\(x^6\)[/tex] and a third-degree term [tex]\(x^3\)[/tex].

It is not quadratic in form.

[tex]4. \(4x^9 + 20x^2 + 25 = 0\)[/tex]

  This equation contains a ninth-degree term [tex]\(x^9\)[/tex] and a quadratic term[tex]\(20x^2\).[/tex]

However, it also contains a constant term. Therefore, it is not purely quadratic in form.

None of the given equations are purely quadratic in form.

Answer:

That is a quadratic equation.

It can be solved by using the quadratic formula:

x = (-b +-sqr root b^2 -4*a*c) / 2 *a

In this equation a = -3

b = -4 and c = -8

x = (--4 +- sqr root (-4^2 - 4 * -3 * -8)) / (2 * -3)

x = (4 +- sqr root (16 -96)) / -6

x = 4 +- sqr root (-80) / -6

x1 = (4 +8.94427191 * i)  / -6

x2 =(4 -8.94427191 * i)  / -6

Remember that "i" is the square root of minus 1.

Step-by-step explanation:

Answer:

[tex]\large\boxed{m<1\to m\in(-\infty,\ 1)}[/tex]

Step-by-step explanation:

[tex]m<2+m<3\to m<2+m\ and\ 2+m<3\\\\m<2+m\qquad\text{subtract}\ m\ \text{from both sides}\\m-m<2+m-m\\0<2\qquad\bold{TRUE}\to m\in\mathbb{R}\ (all\ real\ numbers)\\\\2+m<3\qquad\text{subtract 2 from both sides}\\2-2+m<3-2\\m<1\\\\m\ \text{is any real number and}\ m<1.\\\\\text{Therefore}\ m<1\to m\in(-\infty,\ 1)[/tex]

you should add me on snap connorpike2

Answer:

0.029

Step-by-step explanation:

"To write 29/1000 as a decimal you have to divide numerator by the denominator of the fraction.

We divide now 29 by 1000 what we write down as 29/1000 and we get 0.029"

-Solutions easy

Answer:

NO

Step-by-step explanation:

Since you are rounding to a numbers in the 100s you need to find the closest multiple of 100 to 448, this would be 400 since the difference between 448 and 400 is 48 while the difference between 500 and 448 is 52 and 48<52