Answer:
Part 1) The ordered pair is (0,0)
Part 2) The ordered pair is (-2,-4)
Part 3) The ordered pair is (4,8)
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]y/x=k[/tex] or [tex]y=kx[/tex]
In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin
In this problem we have a direct variation
[tex]y=2x[/tex]
Complete the ordered pairs
Part 1) we have (0,?)
For x=0
Substitute in the equation and solve for y
[tex]y=2(0)=0[/tex]
therefore
The ordered pair is (0,0)
Part 2) we have (-2,?)
For x=-2
Substitute in the equation and solve for y
[tex]y=2(-2)=-4[/tex]
therefore
The ordered pair is (-2,-4)
Part 3) we have (4,?)
For x=4
Substitute in the equation and solve for y
[tex]y=2(4)=8[/tex]
therefore
The ordered pair is (4,8)
check graphically whether the pair of equations 2x-y=1 and x+2y=3 is consistent if so solve them graphically
plz plz help me with this problem plz!!!!!
Answer:
A(1,1)
Step-by-step explanation:
the system is :
2x-y=1
x+2y=3
so :
y = 2x-1 .....the line color : red
y= (-1/2)x+3/2......the line color : blue
the pair solution is the intersection point for this line : A(1 ; 1)
Which of the following is the correct graph of the solution to the inequality-18>-5x+2>-48
Answer:
Step-by-step explanation:
we have
[tex]18 > -5x+2 > -48[/tex]
This is a compound inequality
Remember that
A compound inequality i can divide in a system of two inequalities
so
[tex]18 > -5x+2[/tex] -----> inequality A
[tex]-5x+2 > -48[/tex] ---> inequality B
step 1
Solve the inequality A
[tex]18 > -5x+2[/tex]
Multiply by -1 both sides
[tex]-18< 5x-2[/tex]
[tex]-18+2< 5x[/tex]
[tex]-16< 5x[/tex]
Divide by 5 both sides
[tex]-3.2< x[/tex]
Rewrite
[tex]x > -3.2[/tex]
The solution of the inequality A is the interval ----> (-3.2,∞)
step 2
Solve the inequality B
[tex]-5x+2 > -48[/tex]
Multiply by -1 both sides
[tex]5x-2 < 48[/tex]
[tex]5x < 48+2[/tex]
[tex]5x < 50[/tex]
Divide by 5 both sides
[tex]x < 10[/tex]
The solution of the inequality B is the interval ----> (-∞, 10)
step 3
Find the solution of the compound inequality
(-3.2,∞) ∩ (-∞, 10)=(-3.2,10)
All real numbers greater than -3.2 and less than 10
The graph in the attached figure
Please answer this correctly
Answer:
Step-by-step explanation:
If we divide 9,795 by 7 we get:
=1399.28571429
Rounding to the nearest hundredth:
Underline the hundredths place: 1399.28571429
Look to the right. If it is 5 or above 5 then we give it a shove.
If it is 4 or less than 4, we let it go.
In our case it is 5. We will add 1 in 8, then it will become 9. 28 will be rounded off as 29.
Therefore the answer after rounding off to the nearest hundredth is 1399.29....
Winslow plans to grow 12 kinds of vegetables in her garden. She has 34 seeds of each kind of vegetables. A neighbor gives her 10 more packets of seeds. Each packet has 25 seeds. How many seeds does Winslow have in all????
Answer: 658
Step-by-step explanation:
If Winslow wants to plant 12 vegetables and has 34 seeds of each kind of vegetable, then she has 12*34 seeds.
12*34=408
If a neighbor giver her 10 more packets, each with 25 seeds, she has 10*25 more seeds.
10*25=250
Then we add 408+250 to get 658 seeds
In △ABC, m∠A=72°, c=61, and m∠B=16°. Find the perimeter of the triangle.
Answer:
136
Step-by-step explanation:
The perimeter of the triangle is about 136
Further explanationFirstly , let us learn about trigonometry in mathematics.
Suppose the ΔABC is a right triangle and ∠A is 90°.
sin ∠A = opposite / hypotenusecos ∠A = adjacent / hypotenusetan ∠A = opposite / adjacentThere are several trigonometric identities that need to be recalled, i.e.
[tex]cosec ~ A = \frac{1}{sin ~ A}[/tex]
[tex]sec ~ A = \frac{1}{cos ~ A}[/tex]
[tex]cot ~ A = \frac{1}{tan ~ A}[/tex]
[tex]tan ~ A = \frac{sin ~ A}{cos ~ A}[/tex]
Let us now tackle the problem!
This problem is about Sine Rule.
First of all, we will calculate the ∠C :
∠A + ∠B + ∠C = 180°
72° + 16° + ∠C = 180°
∠C = 180° - 72° - 16°
∠C = 92°
Next, we will use the Sine Rule to find the length of the other side of the triangle.
[tex]\frac{c}{\sin \angle C} = \frac{b}{\sin \angle B}[/tex]
[tex]\frac{61}{\sin 92^o} = \frac{b}{\sin 16^o}[/tex]
[tex]b \approx \boxed {16.82}[/tex]
[tex]\frac{c}{\sin \angle C} = \frac{a}{\sin \angle A}[/tex]
[tex]\frac{61}{\sin 92^o} = \frac{a}{\sin 72^o}[/tex]
[tex]a \approx \boxed {58.05}[/tex]
Finally, we can find the perimeter of a triangle with the following formula
[tex]\text{Perimeter of the triangle} = a + b + c[/tex]
[tex]\text{Perimeter of the triangle} = 58.05 + 16.82 + 61[/tex]
[tex]\text{Perimeter of the triangle} \approx \boxed {136}[/tex]
Learn moreCalculate Angle in Triangle : https://brainly.com/question/12438587Periodic Functions and Trigonometry : https://brainly.com/question/9718382Trigonometry Formula : https://brainly.com/question/12668178Answer detailsGrade: College
Subject: Mathematics
Chapter: Trigonometry
Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse
Georgia filled her kitchen sink up with water so that she could do the dishes. When she was done with the dishes, she pulled out the drain stopper so the water could begin to drain out of the sink.
A linear model of this situation contains the values (2, 8.4) and (4, 7.8), where x represents the number of seconds, and y represents the water level in the sink, in inches.
What is the rate of change in this linear model?
A.
-0.3 of an inch per second
B.
0.3 of an inch per second
C.
-9 inches per second
D.
-0.6 of an inch per second
Answer:
A) -0.3 of an inch per second
Step-by-step explanation:
You'll have to put (2, 8.4) and (4, 7.8) into the slope formula.
It's represented as (∆y)/(∆x) = m
(y1 + y2)/(x1 + x2) = m
You subtract both y's in the numerator and subtract both x's in the denominator.
Like this:
(8.4-7.8)/(2-4) = m
(0.6)/(-2) = m
-0.3 = m
Answer:
y = (-0.3 in/sec)x + 9.0 in
Step-by-step explanation:
(2, 8.4) and (4, 7.8) are points on a linear graph.
As we go from (2, 8.4) to (4, 7.8), x increases by 2 and y decreases by 0.6.
Thus, the slope of the line is m = rise / run = -0.6 / 2, or m = -0.3 inches/sec
Let's use the slope-intercept form of the equation of a straight line, with m = -0.3 in/sec and one point being (2, 8.4).
Then y = mx + b becomes 8.4 = (-0.3 in/sec)(2) + b, or
8.4 = -0.6 + b. Thus, b = 9.0, and the desired equation is thus:
y = (-0.3 in/sec)x + 9.0 in
The system of equations y = 2x - 1 and y = - 1/4 x + 3 is shown on the graph below.
Answer:
Choose something close to (1.8,2.6)
Choice A
Step-by-step explanation:
Without the graph provided, I would prefer to do this algebraically.
y=2x-1
y=-1/4x+3
Since both are solved for y, I'm going to replace the first y with what the second y equals.
-1/4x+3=2x-1
I don't really like to deal with fractions quite yet so I'm going to multiply both sides by 4.
-1x+12=8x-4
I'm going to add 1x on both sides.
12=9x-4
I'm going to add 4 on both sides.
16=9x
I'm going to divide both sides by 9
16/9=x
This is the same as saying x=16/9.
Now to find y, just choose one of the equations and replace x with 16/9.
y=2x-1
y=2(16/9)-1
y=32/9-1
y=32/9-9/9
y=(32-9)/9
y=23/9
So the exact solution is (16/9,23/9).
Round these numbers to the nearest tenths you get:
(1.8, 2.6) .
To get this I just typed into my calculator 16 divided by 9 and 23 divided by 9
16 divided by 9 gave me 1.777777777777777777777777777
23 divided by 9 gave me 2.5555555555555555555555555
So choose something close to (1.8, 2.6).
So your ordered pair (1.75,2.5) is pretty close to that so choice A.
Number 28 is the only question I need please help, with steps
Answer:
f (gx) = 1/ -2(1/x^2+6x+10) + 9
Step-by-step explanation:
f (gx) = 1/ -2(1/x^2+6x+10) + 9
Answer:
The domain is all real numbers where
[tex](f \circ g)(x)=\frac{x^2+6x+10}{9x^2+54x+88}[/tex]
Step-by-step explanation:
[tex](f \circ g)(x)=f(g(x))[/tex]
So g(x) must exist before plugging it into f(x).
Let's find where g(x) doesn't exist.
[tex]x^2+6x+10[/tex] is a quadratic expression.
[tex]b^2-4ac[/tex] is the discriminant and will tell us if [tex]x^2+6x+10=0[/tex] will have any solutions. I'm trying to solve this equation because I want to figure out what to exclude from the domain. Depending on what [tex]b^2-4ac[/tex] we may not have to go full quadratic formula on this problem.
[tex]b^2-4ac=(6)^2-4(1)(10)=36-40=-4[/tex].
Since the discriminant is negative, then there are no real numbers that will make the denominator 0 here. So we have no real domain restrictions on g.
Let's go ahead and plug g into f.
[tex]f(g(x))[/tex]
[tex]f(\frac{1}{x^2+6x+10})[/tex]
I replaced g(x) with (1/(x^2+6x+10)).
[tex]\frac{1}{-2(\frac{1}{x^2+6x+10})+9}[/tex]
I replaced old input,x, in f with new input (1/(x^2+6x+10)).
Let's do some simplification now.
We do not like the mini-fraction inside the bigger fraction so we are going to multiply by any denominators contained within the mini-fractions.
I'm multiplying top and bottom by (x^2+6x+10).
[tex]\frac{1}{-2(\frac{1}{x^2+6x+10})+9} \cdot \frac{(x^2+6x+10)}{(x^2+6x+10)}[/tex]
Using distributive property:
[tex]\frac{1(x^2+6x+10)}{-2(\frac{1}{x^2+6x+10})\cdot(x^2+6x+10)+9(x^2+6x+10)}[/tex]
We are going to distribute a little more:
[tex]\frac{x^2+6x+10}{-2+9x^2+54x+90}[/tex]
Combine like terms on the bottom there (-2 and 90):
[tex]\frac{x^2+6x+10}{9x^2+54x+88}[/tex]
Now we can see if we have any domain restrictions here:
[tex]b^2-4ac=(54)^2-4(9)(88)=-252[/tex]
So again the bottom will never be zero because [tex]9x^2+54x+88=0[/tex] doesn't have any real solutions. We know this because the discriminant is negative.
The domain is all real numbers where
[tex](f \circ g)(x)=\frac{x^2+6x+10}{9x^2+54x+88}[/tex]
prove that cos^2A+sin^2A.cos2B=cos^2B+sin^2B.cos2A
Notice that both sides of the equation have a similar form. If we ignore angle functions we end up with,
[tex]A+A\cdot B=B+B\cdot A[/tex]
That is true if condition [tex]A=B[/tex] is met.
Otherwise it is false.
Hope this helps.
r3t40
The sundae bar at Sarah's favorite restaurant has 5 toppings. In how many ways can Sarah top her sundae if she is restricted to at most 2 toppings?
There are 16 different ways Sarah can top her sundae, considering no toppings, 1 topping or 2 toppings out of 5 available at the restaurant.
Explanation:The subject of this question is in the field of combinatorics, a branch of mathematics. We are asked to find the number of ways Sarah can top her sundae with at most 2 toppings out of 5 available. The answer will be the number of ways she can pick no topping, or 1 topping, or 2 toppings.
The number of ways to pick no toppings is 1 (just the ice cream), to pick 1 topping out of 5 is 5 (assuming all toppings are different), and to pick 2 toppings out of 5 is represented by a combination formula '5 choose 2', which means: 5! / ((5 - 2)! * 2!) = 10, where '!' denotes factorial.
So by summing these possibilities (1+5+10), we come to the conclusion that Sarah can top her sundae in 16 different ways if she is restricted to at most 2 toppings.
Learn more about Combinations here:
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Sarah can top her sundae in 6 different ways if she is restricted to at most 2 toppings.
Explanation:To calculate the number of ways or combinations, Sarah can top her sundae with at most 2 toppings, we can consider two cases. In the first case, she chooses 0 toppings. In the second case, she chooses 1 topping.
The total number of ways would be the sum of these two cases.
In the first case, she has only one choice, which is not to choose any topping.
In the second case, she can choose any one of the 5 toppings. So, the total number of ways would be 1 + 5 = 6.
Therefore, Sarah can top her sundae in 6 different ways if she is restricted to at most 2 toppings.
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There are 3,280.84 feet in a kilometer. There are 5,280 feet in a mile. To the nearest hundredth, how many kilometers are in a mile?
Answer:
1.609344 kilometers
Step-by-step explanation:
Five liters of water were poured from tank A into tank B. and ten liters of water were then poured into tank C. If tank A originally had 10 more liters of water than tank C, how many more liters of water does tank C now have than tank A?
Answer:
It would be 5 liters because you gave 5 liter to C
Step-by-step explanation:
Hope this helped! :3
Tank C now has 5 more liters of water than tank A.
Assume the initial amount of water in tank C is "x" liters.
Given that:
Tank A originally had 10 more liters of water than tank C,
The initial amount of water in tank A is "x + 10" liters.
When five liters of water were poured from tank A into tank B,
The amount of water in tank A is reduced to "(x + 10) - 5" liters,
The amount of water in tank A = "(x + 5)" liters.
When ten liters of water are poured into tank C
So, the amount of water in tank C= "x + 10" liters.
The amount of extra water in tank C is calculated as;
Difference = (Amount of water in tank C) - (Amount of water in tank A)
Difference = (x + 10) - (x + 5)
Difference = x + 10 - x - 5
Difference = 10 - 5
Difference = 5
Tank C now has 5 more liters of water than tank A by 5 liters.
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-7 + m = 8 please answer the question
Answer:
m=15
Step-by-step explanation:
-7 + m = 8
=>m=8+7
=>m=15
The point A(-6,-5) is translated using T: (x,y) - (x + 4, y + 6).
What is the distance from A to A'?
The distance from point A to A' after translation is 2 sqrt(13).
Explanation:The given points are A(-6,-5) and A' is obtained by translating A using the transformation T: (x,y) -> (x + 4, y + 6).
So the coordinates of A' are (-6 + 4, -5 + 6) which is (-2,1).
To find the distance from A to A', we can use the distance formula.
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of A and A' into the formula, we get Distance = sqrt((-2 - (-6))^2 + (1 - (-5))^2).
Calculating the distance, we get Distance = sqrt((4)^2 + (6)^2) = sqrt(16 + 36) = sqrt(52) = 2 sqrt(13).
6. Solve for x in the equation x + 10 = 15.
© A. x = 25
© B.x=5
O C.x= 10
O D.x=-5
Answer:
B
Step-by-step explanation:
Given
x + 10 = 15 ( subtract 10 from both sides )
x = 5 → B
Which graph represents a linear function that has a slope of 0.5 and a y-intercept of 2?
Step-by-step explanation:
[tex]slope=\dfrac{rise}{run}=\dfrac{\Delta y}{\Delta x}\\\\\text{We have}\ m=0.5=\dfrac{1}{2}\to\Delta y=1,\ \Delta x=2\\\\\text{From given point (y-intercept: (0, 2), run 1 unit up and 2 units to the right.}\\(x+2,\ y+1)\to(0+2,\ 2+1)=(2,\ 3)\\\text{Mark new point.}\\\text{Plot the line passes throught given points.}\\\\======================\\\\\Delta x > 0-\text{run to the right}\\\Delta x<0-\text{run to the left}\\\Delta y>0-\text{run up}\\\Delta y<0-\text{run down}[/tex]
Answer:
D the last one
Help with substitution! (With pictures-2 separate questions) thanks!
Answer:
Explanation contains answer.
Step-by-step explanation:
Question 1:
I would perfer to solve the first equation for y because there is only one operation to perform on both sides and it is subtraction of 2x on both sides.
The other equation requires two steps to isolate y; subtracting 3x on both sides then multiplying both sides by -1.
So basically solving the first one for y because it has coefficient 1.
Question 2:
They solved the 2nd equation for y and plugged into itself instead of plugging it into 1st equation.
Tony has $727.29 in his checking account. He must maintain a $500 balance to avoid a fee. He wrote a check for $248.50 today. Write and solve an inequality to solve for the least amount of money he needs to deposit to avoid a fee.
727.29 + 248.50 − x ≥ 500; x ≥ $475.79
727.29 + 248.50 − x ≤ 500; x ≤ $475.79
727.29 − 248.50 + x ≥ 500; x ≥ $21.21
727.29 – 248.50 − x ≤ 500; x ≤ $21.21
Answer:
727.29 − 248.50 + x ≥ 500; x ≥ $21.21
Step-by-step explanation:
Write down all the data given :
Beginning amount : $727.29
Balance to be maintained : $ 500
Check : $248.5
Current balance = 727.29 - 248.5 = $478.79
Tony must maintain a balance of $500 so he should have at least $21.21 more (500-478.79)
727.29 - 248.5 + 21.21 = 500
500=500
x can be 21.21 or greater than that which would maintain the balance of $500 or more.
Therefore the third statement is correct.
727.29 − 248.50 + x ≥ 500; x ≥ $21.21
!!
Kite ABCD has an area of 48 ft2. Calculate the length of AC.
A. 6 ft
B. 12 ft
C. 18 ft
Answer:
B. 12ft
Step-by-step explanation:
Area of kite is 2 times the area of triangle
= 2[(1/2)(4)AC] = 48, ie., AC = 12 ft
describe the graph of the function y=x+3
Answer:
The graphical is radical function sqrt(x) shifted 3 units left
Step-by-step explanation:
The argument of the radical function is x+3, this means, that if x=-3, then y=0 since sqrt(0)=0
The parent function y=sqrt(x), something simmilar ocurrs, y=0 when x=0
This is the key difference between the two given functions.
Triangle JKL is translated using (x, y) --> (x + 1, y - 3) after it is reflected across the x-axis. What are the
coordinates of the final image of point under this composition of transformations?
help please
Answer:
(1, - 6 )
Step-by-step explanation:
Under a reflection in the x- axis
a point (x, y ) → (x, - y )
The point J has coordinates (0, 3 ), hence
J'(0, - 3 ) ← after reflection in x- axis
A translation (x, y ) → (x + 1, y - 3 )
Means add 1 to the x- coordinate and subtract 3 from the y- coordinate
J'(0, - 3 ) → J''(0 + 1, - 3 - 3 ) → J''(1, - 6 ) ← final image
Cal is trying to raise his average weekly income to be at least $131. His first
two weekly paychecks were $128 and $135. What is the lowest amount on his next
paycheck that Cal must earn so that he can reach his goal?
a) $132
b) $131
c) $135
d) $130
Answer:
d) $130
Step-by-step explanation:
Average means you add up the numbers and divide by the number of numbers.
We want our average to be 131.
We have 128,135, and the next pay check amount.
So let's average the three numbers together.
[tex]\frac{128+135+x}{3}[/tex]
[tex]x[/tex] represent the amount on the next pay check.
We want this average to equal 131 so we have this equation to solve:
[tex]\frac{128+135+x}{3}=131[/tex]
First step: Add 128 and 135:
[tex]\frac{263+x}{3}=131[/tex]
Second step: Multiply both sides by 3:
[tex]263+x=3(131)[/tex]
Third step: Multiply 3 and 131:
[tex]263+x=393[/tex]
Fourth step: Subtract 263 on both sides:
[tex]x=393-263[/tex]
Fifth step: Subtract 393 and 263:
[tex]x=130[/tex]
d. 130
D). $130
Step-by-step explanation:In this question, we're trying to figure out what would be the lowest amount of money he earned on his next paycheck in order for his income to be an average of $131.
To do this, we would need to use some important information in the question.
Important information:
$128 paycheck$135 paycheckWith the information above, we can use that to get the answer to the question.
We know that he made $128 and $135 on his recent paychecks, but we need to find on how much he needs to make on his next paycheck in order to reach his goal average.
We would be solving for x:
128, 135, x
131, 131, 131
We would add the numbers:
128, 135, x = 263 + x
131, 131, 131 = 393
We will now solve.
[tex]393 = 263+x\\\\\text{Subtract 263 on both sides}\\\\130=x[/tex]
When you're don solving, you should get 130. This means that Cal needs to make $130 on his next paycheck in order to have an average of $131.
Checking to see if it's right:We can check to see if it's right by adding up all of the numbers and divide by how many there are (3).
[tex]128+130+135=393\\\\393\div3=131[/tex]
Now, we can confirm that D). $130 would be the correct answer.
I hope this helps you out.Good luck on your academics.Have a fantastic day!Does anyone understand this?? Please help me, will mark brainlest!! Since it’s a lot I will give 30 points, please don’t answer just for the points
Answer:
f(x)=a(x-h)^2+k =f(x)=5(3-2)^(2)-4 and f(x)=1
Step-by-step explanation:
i really hope this helps im sorry if it doesnt
Solve the quadratic equation below by completing the square. What are the
solutions?
x2 + 10x + 22 = 31
Answer:
(x+5)^2=34
Solutions: ≈ -10.831, 0.831
Step-by-step explanation:
First you divide the second term by two to complete the square. The second term divided by two is 5, 5^2 is 25 which means you need a value of 25 to factor. Add 3 to both sides so you have a value of 25 on the left side.
x^2+10x+25=34 Next, factor the left side.
(x+5)^2=34
The solutions to this equation are not rational, you could use the quadratic formula to find the exact answer or put the equation into a graphing calculator to find approximate solutions.
If one term of a proportion is not known, what can be used to find the value of that term? a. substitution c. cross-multiplication b. graphing d. adding all the numbers together
Answer:
cross multiplication
Step-by-step explanation:
factor 15x^3-6x^2-25x+10 by grouping
Answer: (5x-2)(3^2-5)
Step-by-step explanation:
So using the commutative property, we can change the equation 15x^3-6x^2-25x+10 into 15x^3-25x -6x^2+10
Let’s split that into two sections so it’s easier to see:
(15x^3-25x) - (6x^2+10)
Next let’s look at what 15x^3 and -25x have in common. They have 5x in common.
Factoring out 5x, we get this: 5x(3^2-5)
Next let’s look at what -6x^2and 10 have in common. They only have 2 in common, so we factor out 2.
2(-3^2+5) we can write this as -2(3^2-5)
So the end result will be : 5x(3^2-5)-2(3^2-5)
And the complete factorization will be (5x-2)(3^2-5)
Berto has $12 to put gas in his car. If gas costs $3.75 per gallon, which ordered pair relating number of gallons of
gas, x, to the total cost of the gas, y, includes the greatest amount of gas Berto can buy?
Answer:
(12, 3.2) would be the max amount of gas he could buy. (11.25, 3) for an even gallon amount.
Step-by-step explanation:
Answer:
(3.2, 12)
Step-by-step explanation:
Total cost for gas = $12
Cost per gallon = $3.75
Letting total cost of gas be y and number of gallons be x, maximum number of gallons of gas he can buy would be ;
Total cost of gas/ cost per gallon = 12 / 3.75 = 3.2 gallons
Therefore , the coordinate pair (x, y) = (3.2, 12)
solve using the quadratic formula x2+3x-3=0
Answer:
x=(-3+-sqrt15)/2
Step-by-step explanation:
Without using calculatorsoup,
we can use the quadratic formula for x^2+3x-3=0
using it we find:
x=(-b+-sqrtb^2-4ac)/2a
x=(-3+-sqrt3-4*1*-3)/2
x=(-3+-sqrt15)/2
For this case we must resolve the following expression:
[tex]x ^ 2 + 3x-3 = 0[/tex]
The roots will be given by:
[tex]x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}[/tex]
We have to:
[tex]a = 1\\\b = 3\\c = -3[/tex]
So:
[tex]x = \frac {-3 \pm \sqrt {3 ^ 2-4 (1) (- 3)}} {2 (1)}\\x = \frac {-3 \pm \sqrt {9 + 12}} {2}\\x = \frac {-3 \pm \sqrt {21}} {2}[/tex]
We have two roots:
[tex]x_ {1} = \frac {-3+ \sqrt {21}} {2} = 0.7913\\x_ {2} = \frac {-3- \sqrt {21}} {2} = - 3.7913[/tex]
Answer:
[tex]x_ {1} = \frac {-3+ \sqrt {21}} {2} = 0.7913\\x_ {2} = \frac {-3- \sqrt {21}} {2} = - 3.7913[/tex]
What are the solutions to the equation (x – 2)(x + 5) = 0?
Answer:
x = 2 or x = -5
Step-by-step explanation:
It s given that, (x – 2)(x + 5) = 0
To find the solution of given equation
Let (x – 2)(x + 5) = 0
From this we get
either (x – 2) = 0 or (x + 5) = 0
If (x - 2) = 0 then x = 2
If (x + 5) = 0 then x = -5
Therefore the solutions of given equation (x – 2)(x + 5) = 0 are,
x = 2 or x = -5
Answer: X = 2 or X = -5
Step-by-step explanation:
(X - 2) x ( X - 5) = 0
X - 2 = 0 or X - 5 = 0
Therefore X=2 or X=5
Find the equation for the line that passes through the point (−2,0), and that is perpendicular to the line with the equation 2/3x+y=−14/3.
Answer:
y = 3/2 x + 3
Step-by-step explanation:
2/3 x + y = -14/3
y = -2/3 x − 14/3
The slope of this line is -2/3. So the perpendicular slope is the opposite of the inverse:
m = -1 / (-2/3)
m = 3/2
We know the slope of the line and a point on the line, so using point-slope form:
y − 0 = 3/2 (x − (-2))
Simplifying into slope-intercept form:
y = 3/2 (x + 2)
y = 3/2 x + 3