Consider 2NH3(g)+3CuO(s)→N2(g)+3Cu(s)+3H2O(g) 2NH 3 ​ (g)+3CuO(s)→N 2 ​ (g)+3Cu(s)+3H 2 ​ O(g). What volume (in mL) of NH3 NH 3 ​ is required to completely react 45.2 g of CuO at STP? Enter your solution as a numerical value with no units.

Answers

Answer 1
the volume of  in Ml  of NH3  required  to completely  react  with  45.2 g  of CUO   at  STP  is 8489.6 Ml

 calculation
calculate the moles  of CUO  used
moles= mass/molar mass
45.2 g/79.5 g/mol =0.569 moles

Reacting  equation 
2NH3  + 3CUO = N2  +3CU  +3H2O
by  use of reacting  ratio  between  NH3 to CUO  which jis  2:3 the moles of  NH3  = 0.569 x2/3 = 0.379 moles

At STP  1  mole  = 22.4 L
what about  0.379 moles

=0.379  x22.4  = 8.4896  L

in  Ml  = 8.4896  x1000 =8489.6 ml


Related Questions

What is the percent of MgSO4 in magnesium sulfate heptahydrate

Answers

 All you need to do is add up the mass of each component, as if it was 1 gm mole. 

So you have MgSO4.7H2O 

Mg = 24.3, S = 32 O = 16 H = 1 

24.3 + 32 + 64 + 14 + 112 = 246.3 

Water H2O is 18 so 7 moles of water is 126. 

So in 246.3 gm of magnesium sulphate heptahydrate contains 126 gm of water. 

Percentage = 100 x 126/246.3 = 51.16 %

) determine the theoretical yield and the percent yield if 21.8 g of k2co3 is produced from reacting 27.9 g ko2 with 29.0 l of co2 (at stp). the molar mass of ko2 = 71.10 g/mol and k2co3 = 138.21 g/mol.

Answers

Answer : The theoretical yield of [tex]K_2CO_3[/tex] = 27.089 g

The percent yield of [tex]K_2CO_3[/tex]  is, 80.47 %

Explanation :  Given,

Mass of [tex]KO_2[/tex] = 27.9 g

Volume of [tex]CO_2[/tex] = 29.0 L  (At STP)

Molar mass of [tex]KO_2[/tex] = 71.10 g/mole

Molar mass of [tex]CO_2[/tex] = 44 g/mole

Molar mass of [tex]K_2CO_3[/tex] = 138.21 g/mole

First we have to calculate the moles of [tex]CO_2[/tex] and [tex]KO_2[/tex].

At STP,

As, 22.4 L volume of [tex]CO_2[/tex] present in 1 mole of [tex]CO_2[/tex]

So, 29.0 L volume of [tex]CO_2[/tex] present in [tex]\frac{29.0}{22.4}=1.29[/tex] mole of [tex]CO_2[/tex]

[tex]\text{Moles of }KO_2=\frac{\text{Mass of }KO_2}{\text{Molar mass of }KO_2}=\frac{27.9g}{71.10g/mole}=0.392mole[/tex]

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

[tex]4KO_2+2CO_2\rightarrow 2K_2CO_3+3O_2[/tex]

From the balanced reaction we conclude that

As, 4 moles of [tex]KO_2[/tex] react with 2 mole of [tex]CO_2[/tex]

So, 0.392 moles of [tex]KO_2[/tex] react with [tex]\frac{2}{4}\times 0.392=0.196[/tex] moles of [tex]CO_2[/tex]

From this we conclude that, [tex]CO_2[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]KO_2[/tex] is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of [tex]K_2CO_3[/tex].

As, 4 moles of [tex]KO_2[/tex] react to give 2 moles of [tex]K_2CO_3[/tex]

So, 0.392 moles of [tex]KO_2[/tex] react to give [tex]\frac{2}{4}\times 0.392=0.196[/tex] moles of [tex]K_2CO_3[/tex]

Now we have to calculate the mass of [tex]K_2CO_3[/tex].

[tex]\text{Mass of }K_2CO_3=\text{Moles of }K_2CO_3\times \text{Molar mass of }K_2CO_3[/tex]

[tex]\text{Mass of }K_2CO_3=(0.196mole)\times (138.21g/mole)=27.089g[/tex]

The theoretical yield of [tex]K_2CO_3[/tex] = 27.089 g

The actual yield of [tex]K_2CO_3[/tex] = 21.8 g

Now we have to calculate the percent yield of [tex]K_2CO_3[/tex]

[tex]\%\text{ yield of }K_2CO_3=\frac{\text{Actual yield of }K_2CO_3}{\text{Theoretical yield of }K_2CO_3}\times 100=\frac{21.8g}{27.089g}\times 100=80.47\%[/tex]

Therefore, the percent yield of [tex]K_2CO_3[/tex]  is, 80.47 %

The theoretical yield of K₂CO₃ is 54.17 g and the percent yield is 40.24%.

Percent yield is the percent ratio of actual yield to the theoretical yield. It is calculated to be the experimental yield divided by theoretical yield multiplied by 100%. If the actual and theoretical yield ​are the same, the percent yield is 100%

In chemistry, yield is a measure of the quantity of moles of a product formed in relation to the reactant consumed, obtained in a chemical reaction, usually expressed as a percentage.

Given,

Mass of K₂O = 27.9g

Molar Mass of K₂O = 71.1 g/mol

Mass of CO₂ = 29.01g

The reaction can be written as -

K₂O + CO₂ = K₂CO₃

Moles of K₂O = 27.9 / 71.1 = 0.392 moles

Moles of CO₂ = 29 / 22.4 = 1.29 moles

Since moles of K₂O is lesser, it is the limiting reagent.

From the reaction, 1 mole of K₂O gives 1 mole of K₂CO₃

so, 0.392 moles of K₂CO₃ is produced.

Theoretical yield of K₂CO₃ = 0.392 × 138.21 = 54.17 g

Actual yield = 21.8 g

Percent yield = (21.8 / 54.17) × 100

= 40.24%

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At 350°c, keq = 1.67 × 10-2 for the reversible reaction 2hi (g) ⇌ h2 (g) + i2 (g). what is the concentration of hi at equilibrium if [ h2 ] is 2.44 × 10-3 m and [ i2 ] is 7.18 × 10-5 m?

Answers

according to the reversible reaction equation:

2Hi(g) ↔ H2(g) + i2(g)

and when Keq is the concentration of the products / the concentration of the reactants.

Keq = [H2][i2]/[Hi]^2

when we have Keq = 1.67 x 10^-2

[H2] = 2.44 x 10^-3

[i2] = 7.18 x 10^-5

so, by substitution:

1.67 x 10^-2 = (2.44 x 10^-3)*(7.18x10^-5)/[Hi]^2

∴[Hi] = 0.0033 M

The equilibrium constant expression for the reaction 2HI (g) ⇌ H₂ (g) + I₂ (g) and given concentrations of H₂ and I₂ , we calculated the concentration of HI at equilibrium to be approximately 3.24 × 10⁻³ M. We used the equilibrium constant Keq = 1.67 × 10⁻² to solve for [HI].

To find the concentration of HI at equilibrium for the reaction 2HI (g) ⇌ H₂. (g) + I₂ (g) given Keq, [H₂] and [I₂], we can use the equilibrium constant expression:

Keq = [H2][I₂] / [HI]₂

Given data:

Keq = 1.67 × 10⁻²[H₂] = 2.44 × 10⁻³M[I₂] = 7.18 × 10⁻⁵ M

Plug these values into the equilibrium expression and solve for [HI]:

Keq = [H₂][I₂] / [HI]₂1.67 × 10⁻² = (2.44 × 10⁻³)(7.18 × 10⁻⁵) / [HI]₂

First, calculate the numerator:

(2.44 × 10⁻³)(7.18 × 10⁻⁵) = 1.75192 × 10⁻⁷

Now plug this back into the equation:

1.67 × 10⁻² = 1.75192 × 10⁻⁷ / [HI]₂

Solving for [HI]₂ :

[HI]₂ = 1.75192 × 10⁻⁷ / 1.67 × 10⁻² ≈ 1.0496 × 10⁻⁵

Taking the square root to find [HI]:

[HI] = √(1.0496 × 10⁻⁵) ≈ 3.24 × 10⁻³ M


Correct question is: At 350°C , keq = 1.67 × 10⁻² for the reversible reaction 2HI (g) ⇌ H₂ (g) + I₂ (g). what is the concentration of hi at equilibrium if [ H₂ ] is 2.44 × 10⁻³ m and [ I₂ ] is 7.18 × 10⁻⁵ m?

Are the statements about hydrogen bonding of the compound below with water true or false? this compound can act as a hydrogen-bond donor. this compound can act as a hydrogen-bond acceptor

Answers

I searched for complete question (as your question is missing with structure) and found the structure of compound attached below.

Answer:
             The compound can neither act as a Hydrogen Bond Donor nor act as a Hydrogen Bond Acceptor.

Explanation:
                   For two compounds to build Hydrogen Bond Interactions it is compulsory that they must contain Hydrogen atoms which are directly attached to most electronegative atoms like Fluorine, Oxygen and Nitrogen.
                   As the given compound is 2-Butene (a non polar hydrocarbon), it lacks partial positive Hydrogen (which can act as Hydrogen Bond Donor) and a most electronegative element (F, O or N) which can act as Hydrogen Bond Acceptor. Therefore, this compound will not generate any Hydrogen Bonding with water molecules and will remain immiscible in it.

Methanol (CH₃OH) can act as both a hydrogen bond donor and acceptor due to its hydrogen atom bonded to electronegative oxygen and the oxygen's two lone pairs of electrons. This enables methanol to form a network of hydrogen bonds with water, affecting its physical properties.

The compound that can act as both a hydrogen bond donor and a hydrogen bond acceptor is methanol (CH₃OH). It contains a hydrogen atom attached to oxygen (making it a hydrogen bond donor) and two lone pairs of electrons on the oxygen (making it a hydrogen bond acceptor). A substance, like methanol, that can both donate a hydrogen atom and accept a hydrogen bond due to these features can participate in hydrogen bonding with water.

To assess whether a compound can act as a hydrogen bond donor or acceptor, one should look for a hydrogen atom bonded to a highly electronegative atom like oxygen, nitrogen, or fluorine; this structure facilitates hydrogen bond donation. For a compound to act as an acceptor, one should identify the presence of lone pairs of electrons on a highly electronegative atom, which can attract the hydrogen atom from another molecule.

Methanol's ability to act in both capacities allows it to form a network of hydrogen bonds with water molecules, thus affecting properties such as the boiling point and solubility. When drawing the hydrogen-bonded structure, we would show lines or dotted lines between the hydrogen of one methanol molecule and the oxygen of another methanol molecule or of a water molecule to represent the hydrogen bonds.

HELPPPP PLEASE ASAP!!!

Answers

Answer:

230
     Th
  90

Explanation:

The left side shows the element uranium with mass number 234 (superscript to the left of ths symbol) and atomic mass 92 (subscript to the left of the symbol).

So,  you have to find the mass number and atomic numbers missing on the right side which added to those shown for the helium atom reach 234 and 92.

This the the mathematics:

1) Mass number of U - mass number of He = 234 - 4 = 230 ⇒ the mass number of the missing element is 230.

2) atomic number of U - atomic number of He = 92 - 2 = 90 ⇒ the atomic number of the missing element is 90.

Now, you use the atomic mass to identify the element. You do it by simply searching in a periodic table. There you find that the atomic number 90 corresponds to thorium, whose symbol is Th.

Now you have that the product that completes the right side of the decay equation is:

230
     Th
  90


) what is the mass percent of a solution prepared by dissolving 18.9 grams of an unknown solid into 39.5 grams of water?

Answers

The  mass %  of  a solution  prepared  by   dissolving 18.9  grams  of  an unknown  solid into  39.5 grams of water is  calculated as  below


%(M/M) =  mass of the solute(unknown  salt)/ mass of the solvent(water)  x 100

 = 18.9 g/ 39.5 g x100  =47.85% (M/M)

Answer:

32.4%

Explanation:

Step 1: Given data

Mass of the solute = 18.9 g

Mass of the solvent = 39.5 g

Mass of the solution = Mass of the solute + Mass of the solvent = 58.4 g

Step 2: Calculate the mass percent of the solute in the solution

We use the following expression.

[tex]\% m/m =\frac{mass\ of\ the\ solute}{mass\ of\ the\ solution} \times 100\%=\frac{18.9g}{58.4g} \times 100\% =32.4\%[/tex]

Our good friend and pseudo scientist, homer simpson, attempts to analyze 300 mg of an unknown compound containing only c and h by burning it in excess oxygen. 540 mg of h2o is produced. you may assume that all the hydrogen in the compound ended up as water.

Answers

[tex] C_{x}H_{y} + O_{2} --\ \textgreater \ x CO_{2} + \frac{y}{2} H{2}O 540mg H_{2}O* \frac{1 mmol H_{2}O}{18 mg H_{2}O} =30 mmol H_{2}O \\ \\30 mmolH_{2}O -have - 60 mmol H \\ \\ 60 mmol H* \frac{1mg H}{1 mmol H} =60 mg H \\ \\300mg C_{x}H_{y} - 60 mg H= 240 mg C \\ \\ 240 mgC* \frac{1mmol}{12mg} =20 mmol C 20 mmol C: 60 mmol H=1 mol C : 3 mol H [/tex]

Write a balanced equation to show the reaction of gaseous ethane,c2h6 with gaseous oxygen to form carbon monoxide gas,co, and water vapor

Answers

2C2H6 + 5O2 = 4co + 6h2o

Answer: The balanced chemical equation is written below.

Explanation:

Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

If supply of oxygen gas is limited, it is known as incomplete combustion and carbon monoxide gas is also produced as a product.

The chemical equation for this reaction of ethene and oxygen gas follows:

[tex]2C_2H_6+5O_2\rightarrow 4CO+6H_2O[/tex]

By Stoichiometry of the reaction:

2 moles of ethene gas reacts with 5 moles of oxygen gas to produce 4 moles of carbon monoxide gas and 6 moles of water vapor.

Hence, the balanced chemical equation is written above.

It is found that doubling the concentration of a quadruples the reaction rate and tripling the concentration of b triples the reaction rate. what is the overall order of the reaction?

Answers

Reactant A must be second order and reactant B first order. Overall = add them so 3rd order.

The reaction is second order with respect to reactant A and first order with respect to reactant B, giving an overall reaction order of 3.

To determine the overall order of a reaction, we need to find the individual orders with respect to each reactant.

1. Doubling the concentration of reactant A increases the reaction rate by a factor of four. This indicates that the reaction is second order with respect to A, because 2² = 4.

2. Tripling the concentration of reactant B increases the reaction rate by a factor of three. This means the reaction is first order with respect to B, because 3¹ = 3.

Therefore, the overall order of the reaction is the sum of the orders with respect to each reactant:

Order with respect to A: 2Order with respect to B: 1

The overall order = 2 + 1 = 3.

How much heat is required to raise the temperature of 10.35g of CCl4 from 32.1°c to 56.4°c

Answers

we are going to use this formula:

Q = M*C*ΔT

when Q is the heat required 

M is the mass of CCl4 = 10.35 g

C is the specific heat capacity of CCl4 = 0.874J/g.c

and ΔT the change in temperature = 56.4 - 32.1 °C =24.3 °C

∴ Q = 10.35g * 0.874 * 24.3 °C

       = 219.8 J

The half life of carbon is 5700 years. if you started with 100g of carbon 14 how much would remain after 4 half lives

Answers

When dealing with a half life question, you should use the half life formula which is: y = a(b)^t/h

Which equilibrium reaction will experience a shift towards the products in equilibrium position when the concentration of ni2+ is increased? view available hint(s) which equilibrium reaction will experience a shift towards the products in equilibrium position when the concentration of is increased? ni2+(aq)+6nh3(aq)⇌[ni(nh3)6]2+ [ni(h2o)6]2+(aq)+3en(aq)⇌[ni(en)3]2+(aq)+6nh3(aq) ni(oh)2(s)⇌ni2+(aq)+2oh−(aq) nis(s)⇌ni2+(aq)+s2−(aq)?

Answers

Answer is 
      Ni²(aq) + 6NH(aq) [Ni(NH)

When the concentration of Ni²⁺(aq) increases, according to the Le Chatelier’s principle system tries to become equilibrium by reducing the increased factor. To do that, the concentration of Ni²⁺(aq) should be reduced. Hence, the forward reacted should be promoted to reduce the Ni²⁺(aq) concentration.

The molecular mass of methyl ethanoate is 75.1 amu . calculate the molecular mass of propanoic acid, an isomer of methyl ethanoate. express your answer with the appropriate units.

Answers

Final answer:

The molecular mass of propanoic acid, an isomer of methyl ethanoate, is 74.09 amu, calculated by the sum of atomic masses of carbon, hydrogen, and oxygen in its molecular formula, C3H6O2.

Explanation:

To calculate the molecular mass of propanoic acid, an isomer of methyl ethanoate, we need to first understand that isomers are compounds with the same molecular formula but different structures, and hence, the same molecular mass. Propanoic acid's molecular formula is C3H6O2. Using the atomic masses of carbon (12.01 amu), hydrogen (1.01 amu), and oxygen (16.00 amu), we calculate the molecular mass as follows:

(3 × 12.01 amu) + (6 × 1.01 amu) + (2 × 16.00 amu) = 36.03 amu + 6.06 amu + 32.00 amu = 74.09 amu

Therefore, the molecular mass of propanoic acid is 74.09 amu.

Some chemical reactions can proceed in just one direction . True or False ?

Answers

the answer is False. i think
it is true because Chemical reactions release the same amount of engery whether an enzyme is involved or not. 

What is the change in atomic mass when an atom emits an alpha particle? A. decreases by 2 B. decreases by 1 C. decreases by 4 D. remains the same

Answers

Answer is "C"

alpha decay is an emission of ₂⁴He nucleus. If an element undergoes an alpha decay, the mass of the daughter nucleus formed is reduced by 4 compared to mass of parent atom and atomic number is reduced by 2 compared to atomic number of parent atom.

Identify the missing daughter nucleus in the β– emission decay of 106ru below.

Answers

Answer is: the missing daughter nucleus is rhodium (Rh).

Nuclear reaction: ¹⁰⁶Ru → ¹⁰⁶Rh + e⁻(electron) + ve(electron antineutrino).

Beta decay is radioactive decay in which a beta ray and a neutrino are emitted from an atomic nucleus.There are two types of beta decay: beta minus and beta plus.

In beta minus decay, neutron is converted to a proton and an electron and an electron antineutrino.
In beta plus decay, a proton is converted to a neutron and positron and an electron neutrino, so mass number does not change.

Twice bill's number added to 17 is 7. What is his number

Answers

-5.

-5 * 2 = -10
-10 + 17 = 7
Let b=bills number
2b+17=7
Subtract 17 from both sides
2b=-10
Divide both sides by 2
b=-5
Bill’s number is -5

I hope this helps )

a section of the periodic table is shown below which of the following statements is true?

Answers

Oxygen is more reactive than fluorine because oxygen needs only one electron to fill its outermost shell.
Neon is inert because its outermost shell is complete. Neon is already in noble gas configuration and it will be very difficult to change this, essentially making it inert.

Nitrogen is inert because its outermost shell has eight electrons. Nitrogen's outermost shell only has 3 electrons so it is generally unstable and wants to gain 3 more to be in noble gas configuration.

Oxygen is more reactive than fluorine because oxygen needs only one electron to fill its outermost shell. This is just completely false, Fluorine is the most reaction element there is.

Fluorine is more reactive than neon because fluorine has to lose only one electron to fill its outermost shell. Although fluorine is more reactive, this is because it only needs to GAIN one more electron, not lose one more.

In which set are the substances arranged in order of decreasing solubility in water? (a) (c) al(oh)3 > mg(oh)2 > naoh cac03 > nahc03 > na2c03 (b) (d) bas04 > cas04 > mgs04 agcl > agbr > agl?

Answers

(A) Al(OH)₃ > Mg(OH)₂ > NaOH
polarity is increasing as the metallic character is increasing . So this order is not correct. NaOH as we all know is completely soluble in water.

(B) BaSO₄> CaSO₄ > MgSO₄
This one is also not correct because here also polarity is increasing so solubility should increase.

(C) CaCO₃> NaHCO₃ > Na₂CO₃
this is als not correct .Na₂CO₃ is more polar is completely soluble in water whereas CaCO₃ is insoluble.

(D) AgCl > AgBr > AgI
In D as we go from AgCl to AgI polarity is decreasing so solubility is decreasing .

A galvanic (voltaic) cell contains a copper cathode immersed in a copper(ii) chloride solution and a nickel anode immersed in a nickel(ii) chloride solution. the two solutions are connected with a salt bridge. write the balanced equation for the galvanic cell. phases are optional.

Answers

We can write the balanced equation for the galvanic cell by using the oxidation and reduction half-reactions. In the anode, Ni(s) is oxidized and produces aqueous Ni2+:
     Ni(s) → Ni2+
while in the cathode, Cu2+ is reduced and deposits copper:
      Cu2+ → Cu(s)
We now balance the charge of each reaction by adding electrons to the side of the equation with the greater charge:
     Ni(s) → Ni2+ + 2 e-
     Cu2+ + 2 e- → Cu(s)
Finally, we add the half-reactions to obtain the overall balanced equation for the galvanic cell:
     Cu2+(aq) + Ni(s) → Ni2+(aq) + Cu(s)

The overall reaction for the galvanic cell has been [tex]\rm Cu^2^+\;+\;Ni\;\rightarrow\;Ni^2^+\;+\;Cu[/tex].

The galvanic cell has been given as the electrochemical cell that converts chemical energy of the reaction into electrical energy.

Balanced equation for the Galvanic cell

The galvanic cell has anode as the oxidizing electrode, whee the loss of electrons takes place, and cathode as the reducing electrode where the gain of electrons takes place.

The cathodic reaction in the cell has been:

[tex]\rm Cu^2^+\;\rightarrow\;Cu\;(s)[/tex]

The anodic reaction in the cell has been:

[tex]\rm Ni\;(s)\;\rightarrow\;Ni^2^+[/tex]

The overall reaction for the galvanic cell has been:

[tex]\rm Cu^2^+\;+\;Ni\;\rightarrow\;Ni^2^+\;+\;Cu[/tex]

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Which of the following is produced when magnesium (Mg) combusts?A. CO2
B. MgO
C. O2

D. H2O

Answers

MgO     is produced  when magnesium   is   undergo combustion

that is 2 Mg  +O2  =  2MgO

2 mole of magnesium (Mg)  during combustion reaction  react with  1 mole of oxygen (O2)   to  form  2  moles of magnesium  oxide (MgO). a  combustion  reaction is a reaction by  which a  substance react with  oxygen  and it is always  exothermic  ( releases  heat  energy)

What is the noble gas configuration for silicon? [Ne] 3s2 3p1 [Ar] 4s1 [Kr] 5s1 [Ne] 3s2 3p2

Answers

Answer: The noble gas notation for silicon atom is [tex][Ne]3s^23p^2[/tex]

Explanation:

Noble gas notation is defined as the notation in which the configuration of an atom is written in terms of previous noble gas.

Silicon is the 14th element of the periodic table having 14 electrons.

The nearest noble gas to this element is neon.

So, the noble gas notation for silicon atom = [tex][Ne]3s^23p^2[/tex]

In a future hydrogen-fuel economy, the cheapest source of h2 will certainly be water. it takes 467 kj to produce 1 mol of h atoms from water. what is the frequency, wavelength, and minimum energy of a photon that can free an h atom from water? enter your answers in scientific notation.

Answers

1 mol ≡ 6.023 x 10^23 molecules  are produced using 467000 j of energy,
then production of 1 molecule will required energy = [tex] \frac{467000}{6.023X10^2^3} [/tex] = 7.7536 x 10^(-19) j

Thus, mininum energy of a photon that can free a H-atom from water is 7.7536 x 10^(-19) j.

Now, we know that E = hv
where, h = planck's constant = 6.63  10^(34) J.s
v = frequency of photon 
∴ v = [tex] \frac{E}{h} [/tex] = [tex] \frac{7.7536 X 10^(^-^1^9^)}{6.63X10^(^-^3^4^)} [/tex] = 1.1702 X 10^(15) Hz

We also know that, wavelength (∧) = [tex] \frac{c}{v} [/tex]
                                                        = [tex] \frac{3X10^8}{1.1702X10^(^1^5^)} [/tex]
                                                        = 2.56 X 10^(-7) m

The minimum energy of a photon that can produce one hydrogen atom from water is [tex]\boxed{7.755 \times {{10}^{ - 19}}{\text{ J}}}[/tex]

The frequency of the photon is [tex]\boxed{1.17 \times {{10}^{15}}{\text{ }}{{\text{s}}^{ - 1}}}[/tex].

The wavelength of the photon is [tex]\boxed{2.563 \times {{10}^{ - 7}}{\text{ m}}}[/tex].

Further Explanation:

Frequency[tex]\left( \nu  \right)[/tex] is defined as number of times n event occurs in unit time. It is generally applied to waves including light, sound, and radio waves. It is denoted by [tex]{\nu }}[/tex] and its SI unit is Hertz (Hz).

Wavelength is the characteristic property of a wave. It is defined as the distance between two successive crests or troughs. A crest is that point where there is maximum displacement of the medium whereas trough is a point that has minimum displacement of the medium. It is represented by [tex]\lambda[/tex] and its SI unit is meter (m).

First, the energy required to produce one hydrogen atom in joule can be calculated as follows:

[tex]E\left({\text{J}}\right)=\frac{{E\left( {{\text{kJ}}}\right)\times\left({\frac{{{{10}^3}{\text{ J}}}}{{{\text{kJ}}}}}\right)}}{{{{\text{N}}_{\text{A}}}}}[/tex]           …… (1)

Here, [tex]{{\text{N}}_{\text{A}}}[/tex] is an Avogadro's number and has a value [tex]6.022 \times {10^{23}}{\text{ mo}}{{\text{l}}^{ - 1}}[/tex].

Substitute [tex]467{\text{ kJ/mol}}[/tex] for [tex]E\left( {{\text{kJ}}} \right)[/tex] and [tex]6.022 \times {10^{23}}{\text{ mo}}{{\text{l}}^{ - 1}}[/tex] for [tex]{{\text{N}}_{\text{A}}}[/tex] in equation (1).

[tex]\begin{aligned}E\left( {\text{J}} \right)&=\frac{{\left({467{\text{ kJ/mol}}} \right) \times \left( {\frac{{{{10}^3}{\text{ J}}}}{{{\text{kJ}}}}}\right)}}{{6.022\times {{10}^{23}}{\text{ mo}}{{\text{l}}^{-1}}}}\\&=7.755\times{10^{-19}}{\text{ J}}\\\end{aligned}[/tex]

Thus the energy of a photon that can free one atom of hydrogen is [tex]7.755 \times {10^{ - 19}}{\text{ J}}[/tex].

The expression of frequency and energy is as follows:

[tex]E=hv[/tex]              …… (2)

Here, [tex]v[/tex] is a frequency of photon and h is a Plank’s constant and has a value [tex]\left({6.626\times{{10}^{-34}}{\text{ Js}}}\right)[/tex].

Rearrange equation (2) to calculate the frequency of the photon as follows:

[tex]v=\frac{E}{h}[/tex]               …… (3)

Substitute [tex]6.626\times{10^{-34}}{\text{ J}}\cdot{\text{s}}[/tex] for h and [tex]7.755 \times {10^{-19}}{\text{ J}}[/tex] for E in equation (3).

[tex]\begin{aligned}v&=\frac{{7.755\times{{10}^{-19}}{\text{ J}}}}{{6.626\times{{10}^{-34}}{\text{ Js}}}}\\&=1.17\times{10^{15}}{\text{}}{{\text{s}}^{-1}}\\\end{aligned}[/tex]

Thus the frequency of photon is [tex]1.17\times{10^{15}}{\text{}}{{\text{s}}^{-1}}[/tex].

The expression to calculate the wavelength from energy of the photon is as follows:

[tex]E = \frac{{h{\text{c}}}}{{\lambda }}}[/tex]                  …… (4)

Here [tex]{\lambda }}[/tex] is a wavelength of a photon and c is a speed of light.

Rearrange equation (4) to calculate wavelength of the photon as follows:

[tex]{\lambda }}=\frac{{h{\text{c}}}}{E}[/tex]                                 …… (5)

Substitute [tex]6.626 \times {10^{ - 34}}{\text{ J}} \cdot {\text{s}}[/tex] for h, [tex]3.0 \times {10^8}{\text{ m/s}}[/tex] for c and [tex]7.755 \times {10^{ - 19}}{\text{ J}}[/tex] for E in equation (5).

[tex]\begin{aligned}{\lambda}}=\frac{{\left({6.626\times {{10}^{-34}}{\text{ J}}\cdot {\text{s}}} \right)\left( {3.0 \times {{10}^8}{\text{ m/s}}}\right)}}{{\left({7.755\times {{10}^{ - 19}}{\text{ J}}} \right)}}\\=2.563\times {10^{-7}}{\text{m}}\\\end{aligned}[/tex]

Hence wavelength of the photon is equal to [tex]2.563 \times {10^{ - 7}}{\text{ m}}[/tex].

Learn more:

1. Ranking of photons according to the wavelength of transition: https://brainly.com/question/2055545

2. Calculate de Broglie wavelength of golf ball: https://brainly.com/question/7047430

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Structure of atom

Keywords: Hydrogen atom, cheapest source of h2, 467 kj, 1 mol of h atom, frequency wavelength.

When 0.400 mole of potassium reacts with excess water at standard temperature and pressure as shown in the equation above, the volume of hydrogen gas produced is: 2 k (s) 2 h2o (l) → 2 k (aq) 2 oh- (aq) h2 (g)?

Answers

the balanced ionic equation for the above reaction is as follows;
2K(s) + 2H₂O(l) ---> 2K⁺(aq) + 2OH⁻(aq) + H₂(g)
stoichiometry of K to H₂ is 2:1
K is the limiting reactant as H₂O is in excess.
number of moles of k reacted - 0.400 mol 
according to molar ratio, 
number of H₂ moles formed - 0.400 / 2 = 0.200 mol 
at Standard temperature and pressure conditions, 
molar volume is where 1 mol of any gas occupies a volume of 22.4 L
1 mol of H₂ occupies volume of 22.4 L
therefore 0.200 mol of H₂ occupies a volume of - 22.4 L/mol x 0.200 mol 
volume of H₂ is = 4.48 L

For a solution with an [oh−] of 10−8 m, what would be the value of [h+] , ph and poh, respectively? 1. 106 m, 6, 8 2. 10−6 m, 6, 8 3. 10−6 m, 8, 6 4. 10−14 m, 6, 8 5. 10−6 m, 6, 14 6. 10−14 m, 8, 6

Answers

Q1)pOH
the hydroxide ion concentration can be used to calculate the pOH of the solution 
pOH can be calculated using the following equation 
pOH = -log[OH⁻]
pOH = -log (10⁻⁸ M)
pOH = 8
therefore pOH of solution is 8

Q2) pH 
by knowing the pOH value we can calculate the pH value
since
pH + pOH = 14
and pOH = 8
therefore pH = 14 - 8
pH = 6

Q3)
pH scale is used to determine how acidic or basic a solution is
knowing the pH value we can calculate hydrogen ion concentration 
pH = -log[H⁺]
[H⁺] = antilog(-pH)
[H⁺] = antilog(-6)
[H⁺] = 10⁻⁶ M

answer is 2. 10⁻⁶ M, 6, 8

The simplest substances on Earth are called ________.

A. compounds
B. elements
C. solutions
D. molecules

Answers

the answer is element because there is no two subsances that can make up an element
The answer would be elements

A 5.018 gram sample of a certain hydrate of magnesium sulfate, mgso4•xh2o, is heated until all the water is driven off. the resulting anhydrous compound weighs 2.449 grams. what is the formula of the hydrate?

Answers

Hydrate of magnesium sulphate undergoes dehydration upon action of heat. This process can be chemically represent as follows:

MgSO4.XH2O  → MgSO4 + XH20
       (5.018 g)      (2.449 g)     (2.569 g)

Number of moles of H2O evolved = [tex] \frac{2.569}{Molecular.weight} [/tex]
                                                      = [tex] \frac{2.569}{18} [/tex]
                                                      = 0.1427
Number of moles of MgSO4 generated after decomposition,
= [tex] \frac{2.449}{Molecular.weight} [/tex]
=[tex] \frac{2.449}{120.37} [/tex]
=0.0203

Now dividing  both these numbers by the smallest one to get the mole ratio that exists between MgSO4 and H20

For H2O, [tex] \frac{0.1427}{0.0203} [/tex] = 7.02 ~7

Thus, formula of hydrate is MgSO4.7H2O

The ______________of matter depends upon how close the individual particles are together. A) identity B) mass C) state D) temperature

Answers

Actually it’s c because if the particles are extremely loose they’re most likely a gas if they lose but close they’re a liquid and if they’re organized.

Answer:

State

Explanation:

The state of matter depends on the closeness of the particles. Gases have particles that are very far apart and solids are close together. This is determined by the strength of attraction of these particles to one another.

using the chart, translate the mRNA into amino acids. (amino acids abbreviations plz)

Answers

As we know the genetic information is transferred from DNA to RNA and then from RNA to Protein synthesis in two steps.

Step 1: Transcription:
                                  In this process the DNA is converted into RNA.

Step 2: Translation:
                               In  this process the RNA is converted or translated into proteins.

mRNA is single stranded which contains the code responsible for the joining of Amino Acids in specific sequence to make variety of different proteins. This genetic code is comprised of three Nucleotide bases which code for a single amino acid.

In given problem the code is AUG-GCA. After searching the chart we found that AUG codes for Methionine (Met) while GCA codes for Alanine (Ala). Hence, these two codons will join Methionine and Alanine as shown below,

Which state of matter is most likely represented in the diagram shown below?

A square is shown with the title State of Matter. An array of circles arranged neatly in rows and columns is shown. Tiny single arcs are shown near some circles near the outer edge of the array

Gas
Solid
Liquid
Plasma

Answers

I am actually taking this test right now and I think it is Solid please let me know if I am correct

its defiantly a solid, because the particles are packed in close together and it has a definite shape and volume. water is lose and not packed in like this. and with gas, the particles would juts fly everywhere and plasma is electricity and a wild card. so its definitely a solid, trust me

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