Answer:
Water: h = 35.53 W/m².k
Engine oil: h = 18.84 W/m².k
Mercury: h = 1.19 W/m².k
Explanation:
Assuming the steady state, one-dimensional heat flow, it is clear that the added to the fluid by tube heat will be equal to the heat transfer through convection outside the tube.
Therefore,
mCΔT = hAΔT
mC = hA
h = mC/A
where,
h = convection coefficient
m = mass flow rate = 0.01 kg/s
C = specific heat capacity of fluid
A = surface area of tube = 2πrL = 2π(0.0125 m)(15 m) = 1.178 m²
FOR WATER:
C = 4186 J/Kg.k
Therefore,
h = (0.01 kg/s)(4186 J/Kg.k)/(1.178 m²)
h = 35.53 W/m².k
FOR ENGINE OIL:
C = 2220 J/Kg.k
Therefore,
h = (0.01 kg/s)(2220 J/Kg.k)/(1.178 m²)
h = 18.84 W/m².k
FOR LIQUID MERCURY:
C = 140 J/Kg.k
Therefore,
h = (0.01 kg/s)(140 J/Kg.k)/(1.178 m²)
h = 1.19 W/m².k
In this module you learned about searching, sorting and algorithms in C++ and how to implement these elements in your C++ programs. In this assignment you will implement your knowledge of searching, sorting and algorithms for charge account validation system. Write a program that lets the user enter a charge account number. Be sure to include comments throughout your code where appropriate. The program should determine if the number is valid by checking for it in the following list of valid account numbers:
814942053331743080098675596395269814449539938719751047262931356428263717502196086650316483824195904578589971890467499412545408Initialize a one-dimensional array with these values. Then use a simple linear search to locate the number entered by the user. If the user enters a number that is in the array, the program should display a message indicating that the account number is valid. If the user enters a number not in the array, the program should display a message indicating it is invalid.Next, using the same one-dimensional array, use a bubble-sort to put the array in order and perform a binary search to locate the number entered by the user. If the user enters a number that is in the array, the program should display a message indicating that the account number is valid. If the user enters a number not in the array, the program should display a message indicating it is invalid.
Question is not well presented:
The search strings in the question are not well formatted.
First thing, I'll arrange the account number in order of 7;
Meaning that the length of each account number is 7
8149420 5333174 3080098 6755963 9526981 4449539 9387197 5104726 2931356 4282637 1750219 6086650 3164838 2419590 4578589 9718904 674994 12545408
Answer:
// This program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program starts here
#include <iostream>
using namespace std;
// Initialise Function
int ArrayList(int[], int, int);
// Main Method starts at
int main()
{
// The list of account is 18; so, we Initialise an integer Variable to hold this value
const int acctlist = 18;
// Initialise an array to hold the account numbers
int List[acctlist] = { 8149420 5333174 3080098 6755963 9526981 4449539 9387197 5104726 2931356 4282637 1750219 6086650 3164838 2419590 4578589 9718904 674994 12545408
};
// Declare account number and search result Variables of type integer
int accountnumber, Result;
// Prompt user for account number
cout << "Enter a valid account number: ";
cin >> accountnumber;
// Determine if valid or not
Result = ArrayList(List, acctlist, accountnumber);
if(Result == -1){
cout << "Account number " << AcctNum << " is invalid.\n";}
else{
cout << "Account number " << List[Result] << " is valid\n";
}
return 0;
}
// Function starts here
int ArrayList(int list[], int size, int value)
{
int index = 0,
pos = -1;
bool seen = false;
// Check if Account number is seen in list
while (!seen && index < size)
{
if (list[index] == value)
{
seen = true;
}
pos = index;
}
index++;
}
return pos;
}
Compute the electrical resistivity of a cylindrical silicon specimen 7.0 mm (0.28 in.) diameter and 57 mm (2.25 in.) in length in which a current of 0.25 A passes in an axial direction. A voltage of 24 V is measured across two probes that are separated by 45 mm (1.75 in.).
6.3 In a particular technology, a small BJT operating at conducts a collector current of 100 μA. What vBE = 28VT is the corresponding saturation current? For a transistor in the same technology but with an emitter junction that is 32 times larger, what is the saturation current? What current will this transistor conduct at base–emitter voltage of the latter transistor at iC AE1 =400 μm × 400 μm and AE2 vBE vBE = 28VT ? What is the =1mA? Assume active-mode operation in all cases.
Answer:
Saturation current
Isi = 6.91 * 10^-17 A
The saturation current Is2 of transistor Q2 is 2.2 * 10-15 A
Collector current Ic2 at Vbe2 is 3.2mA
Base emitter voltage Vbe2 is 26.84 VT
Explanation:
Complete question is as follows;
Problem 6.3: In a particular technology, a small BJT operating at vBE = 28VT conducts a collector current of 100
µA. What is the corresponding saturation current?
For a transistor in the same technology but with an emitter junction that is 32 times larger, what is the saturation
current?
What current will this (second) transistor conduct at vBE = 28VT ?
What is the base-emitter voltage of the latter transistor at iC = 1 mA? Assume active-mode operation in all cases.
solution;
Please check attachment for complete solution and step by step explanation
A vapor-compression refrigeration cycle operates at steady state with Refrigerant 134a as the working fluid. Saturated vapor enters the compressor at 2 bar, and saturated liquid exits the condenser at 8 bar. The isentropic compressor efficiency is 80%. The mass flow rate of refrigerant is 7 kg/min.
1-Write the assumptions no less than three
2-Draw clear Schematic
(3) the compressor power, in kW.
(4) the refrigeration capacity, in tons.
(5) the coefficient of performance.
Answer:
(3) the compressor power, in kW. = 4.17KW
(4) the refrigeration capacity, in tons.= 4.905tons
(5) the coefficient of performance. = 4.1336
check attached files for other answers.
Explanation: