Answer: 21
Step-by-step explanation:
Given : A bag containing five red marbles, two green ones, one transparent one, four yellow ones, and two orange ones .
Total marbles other than red or green = 1+4+2=7
Now, the number of combinations to select five marbles from the set of 7 will be :-
[tex]7C_5=\dfrac{7!}{5!(7-5)!}=\dfrac{7\times6\times5!}{5!\times2!}=21[/tex]
Hence, the number of possible sets of five marbles are there in which none of them are red or green =21
fill in the missing number 8×____=4×8
Answer:
4
Step-by-step explanation:
8 *4 is the same as 4*8; commutative property
Answer:
[tex]4[/tex]
Step-by-step explanation:
8 x 4 is exactly the same as 4 x 8, both equaling 32.
No matter how insert 4 and 8, it will always be the same
[tex]x \times y = y \times x [/tex]
^^^
Mathematics with applications in the management, Natural, and Social Sciences Twelfth edition
Chapter 6: Systems of Linear Equations and Matrices
6.1 Exercises
23.) According to Google Trends, popular interest in LED lightbulbs has been soaring. while interest in CFLs has been dropping. The following equations approximate the Google Trends rating (on a scale from 0-100) in year x, where x = 10 corresponds to the year 2010. ( Data from www.google.com/trends.)
LED: -25x + 6y = 20
CFL: 15x + 2y = 322
When did interest in ED lighting Surpass CFL lighting? Round your answer to the nearest year.
Answer: 2014
Step-by-step explanation:
LED: -25x + 6y = 20
CFL: 15x + 2y = 322
we need to find which year it was the same to know where LED lighting surpassed CFL lighting
-25x + 6y = 20
15x + 2y = 322 (-3)
-25x + 6y = 20
-45x - 6y = -966
-70x = -946
x = 13.51
The nearest year would be 14 which is 2014
By solving the system of equations, we find that the interest in ED lighting surpassed CFL lighting around the year 2014.
Explanation:To find out when the interest in ED lighting surpassed CFL lighting, we'll need to solve the system of equations given by:
LED: -25x + 6y = 20
CFL: 15x + 2y = 322
We can use substitution or elimination methods to solve this system of equations. For the elimination method, multiply the first equation by 2 and the second equation by 6 to make the y-coefficients equal:
-50x + 12y = 40
90x + 12y = 1932
Now, subtract the first equation from the second:
140x = 1892. Hence, x = 1892/140 = 13.51
So, the interest in ED lighting surpassed CFL lighting in the year 2013.51. Since we round to the nearest year, we can say that this happened around the year 2014.
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a store light flashes every 60 minutes while another light flashes open every 24 minutesif both stores begin flashing at 10 am what time will they both flash together again
Answer:
Both lights flash at 1:00
Step-by-step explanation:
they flash together every 2*7=14 minutes
in 60 minutes there are 4*14=56 minutes
they flash together at 1:56
more minutes brings you to 2:00
they flash together at 2:10 (4+10=14)
that leaves 50 minutes left in the hour
they flash three times which uses up 42 minutes
this brings you to 2:52 (10+42=52)
8 more minutes brings you to 3:00
in 6 more minutes (8+6=14) it will be 3:06 and they will flash together
Find a general solution of y" + 4y = 0.
Answer:
[tex]y(x)=C_{1}cos2x+C_{2}sin(2x)[/tex]
Step-by-step explanation:
It is a linear homogeneous differential equation with constant coefficients:
y" + 4y = 0
Its characteristic equation:
r^2+4=0
r1=2i
r2=-2i
We use these roots in order to find the general solution:
[tex]y(x)=C_{1}cos2x+C_{2}sin(2x)[/tex]
Find the missing length to the nearest tenth of a meter of the
right triangle. One side is 1.4m and the other is 3.1. What is the
third side?
Answer:
length of the third side may be either 3.4 m or 2.8 m.
Step-by-step explanation:
Measure of two sides of a right triangle are 1.4 m and the other side is 3.1 m.
then we have to find the measure of third side.
If the third side of the triangle is its hypotenuse then
(Third side)² = (1.4)² + (3.1)²
Third side = [tex]\sqrt{(1.4)^{2}+(3.1)^{2}}[/tex]
= [tex]\sqrt{1.96+9.61}[/tex]
= [tex]\sqrt{11.57}[/tex]
= 3.4 m
If the third side is one of the perpendicular sides of the triangle and 3.1 m is hypotenuse, then
(Third side)² + (1.4)² = (3.1)²
(Third side)²= (3.1)² - (1.4)²
Third side = [tex]\sqrt{(3.1)^{2}-(1.4)^{2}}[/tex]
= [tex]\sqrt{9.61-1.96}[/tex]
= [tex]\sqrt{7.65}[/tex]
= 2.76 m
≈ 2.8 m
Therefore, length of the third side may be either 3.4 m or 2.8 m.
the number of employees at a certain company is described by the
function P(t)= 300 (1.5)2t where t is the time in years.
how long does it take for the number of employess at this company
to increase by 10%.
Answer:
It will take 0.1175 years or the number of employees at this company to increase by 10%.
Step-by-step explanation:
We are given that the number of employees at a certain company is described by the function [tex]P(t)= 300 (1.5)^{2t}[/tex]
Initial no. of employees = 300
Increase% = 10%
So, New no. of employees = [tex]300+\frac{10}{100} \times 300[/tex]
= [tex]330[/tex]
Now we are supposed find how long does it take for the number of employees at this company to increase by 10%.
So, [tex]330= 300 (1.5)^{2t}[/tex]
[tex]\frac{330}{300}= (1.5)^{2t}[/tex]
[tex]1.1= (1.5)^{2t}[/tex]
[tex]t=0.1175[/tex]
So, it will take 0.1175 years or the number of employees at this company to increase by 10%.
Arithmetic Modular Composite Numbers (4 marks). Carry out the following calcula- tions by hand by using the Chinese Remainder Theorem to split each operation into two operations modulo smaller numbers. You must show your work to receive full credit (a) 23 x 36 mod 55 (b) 29 x 51 mod 91
Answer:
a) 23 x 36 (mod 55) = 3 (mod 55)
b) 23 x 36 (mod 55) = 23 (mod 91)
Step-by-step explanation:
The Chinese Remainder Theorem lets us split a composite modulo into its prime components and solve for smaller numbers.
a) Using the Chinese Remainder Theorem, we have that 55 = 11 x 5
Since 11 and 5 are relatively prime numbers, we can use the Theorem and rewrite 23 x 36 mod 55 as: 23 x 36 (mod 11) and 23 x 36 (mod 5).
First we will work with 23 x 36 (mod 11)
[tex](23)(36)(mod 11) = (1)(3) (mod 11)[/tex] (Since 23 is congruent to 1 modulo 11 and 36 is congruent to 3 modulo 11)
Now we do the same with 23 x 36 (mod 5)
[tex](23)(36) (mod 5) = (3)(1) (mod5) = 3 (mod 5)[/tex]
Now we will use the Chinese Remainder Theorem to solve this pair of equations:
x = 3 (mod 11) and x = 3(mod 5)
[tex]x=5y+3\\5y+3=3(mod 11)\\5y=0(mod 11)\\y=0 (mod 11)\\y=11z\\x=5(11z)+3\\x=55z + 3\\x=3(mod 55)\\[/tex]
b) We are going to use the same procedure from a)
91 = 13 x 7
29 x 51 (mod 91) = 29 x 51 (mod 13) and 29 x 51 (mod 7)
29 x 51 (mod 13) = 3 x 12 (mod 13) = 36 (mod 13) = 10 (mod 13)
29 x 51 (mod 7) = 1 x 2 (mod 7) = 2 (mod 7)
Our pair of equations is x = 10 (mod 13) and x = 2 (mod 7)
[tex]x= 7y + 2\\7y + 2 = 10(mod13)\\7y= 8(mod13)\\y= 3 (mod 13)\\y=13y+3\\x=7(13y+3) + 2\\x=91y +21+2\\x=91y+23\\x= 23 (mod 91)[/tex]
A solution for direct IV bolus injection contains 125 mg of drug in each 25 mL of injection. What is the concentration of drug in terms of μg/μL?
Answer:
The concentration of the drug is 5ug/uL
Step-by-step explanation:
The first step of the problem is the conversion of the quantities of the drug in mg and mL to ug and uL.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.
Unit conversion problems, like this one, is an example of a direct relationship between measures.
First step: Conversion of 125mg to ug
Each mg has 1,000ug. So:
1mg - 1,000ug
125mg - xug
x = 1,000*125
x = 125,000 ug
Second step: Conversion of 25 mL to uL
Each mL has 1,000uL. So:
1mL - 1,000uL
25mL - x uL
x = 25*1,000
x = 25,000uL
Concentration:
[tex]C = \frac{125,000 ug}{25,000uL} = 5ug/uL[/tex]
The concentration of the drug is 5ug/uL
The concentration of the drug in terms of μg/μL is 5 μg/μL
The given parameters are:
125 mg of drug in each 25 mL
The concentration (k) of the drug is then calculated as:
[tex]k = \frac{125 mg}{25mL}[/tex]
Divide
[tex]k = 5\frac{mg}{mL}[/tex]
The units of the injection and the drug is in mill-.
So, the concentration can be rewritten as:
[tex]k = 5\frac{\mu g}{\mu L}[/tex]
Hence, the concentration of the drug in terms of μg/μL is 5 μg/μL
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Write the prime factorization of the number. 18,234
Answer:
[tex]18234=2\times 3\times 3\times 1013[/tex]
Step-by-step explanation:
We are given that a number 18234
We have to find the prime factorization of the number
Prime factorization : The number written is in the product of prime numbers is called prime factorization.
In order to find the prime factorization we will find the factors of given number
[tex]18234=2\times 3\times 3\times 1013[/tex]
Hence, the prime factorization of [tex]18234=2\times 3\times 3\times 1013[/tex]
In 1970 the male incarceration rate in the U.S. was approximately 190 inmates per 100,000 population. In 2008 the rate was 960 inmates per 100,000 population. What is the percent increase in the male incarceration rate during this period?
Answer:
405.26%
Step-by-step explanation:
We have been given that in 1970 the male incarceration rate in the U.S. was approximately 190 inmates per 100,000 population. In 2008 the rate was 960 inmates per 100,000 population.
[tex]\text{Percent increase}=\frac{\text{Final amount}-\text{Initial amount}}{\text{Initial amount}}\times 100[/tex]
[tex]\text{Percent increase}=\frac{960-190}{190}\times 100[/tex]
[tex]\text{Percent increase}=\frac{770}{190}\times 100[/tex]
[tex]\text{Percent increase}=4.052631578947\times 100[/tex]
[tex]\text{Percent increase}=405.2631578947\%[/tex]
[tex]\text{Percent increase}\approx 405.26\%[/tex]
Therefore, the percent increase in the male incarceration rate during the given period is 405.26%.
Find a formula for Y(t) with Y(0)=1 and draw its graph. What is Y\infty?
a. Y'+2Y=6
b. Y'+2Y=-6
Answer:
[tex](a)\ y(t)\ =\ -2e^{-2t}+3[/tex]
[tex](b)\ y(t)\ =\ 4e^{-2t}-3[/tex]
Step-by-step explanation:
(a) Given differential equation is
Y'+2Y=6
=>(D+2)y = 6
To find the complementary function, we will write
D+2=0
=> D = -2
So, the complementary function can be given by
[tex]y_c(t)\ =\ C.e^{-2t}[/tex]
To find the particular integral, we will write
[tex]y_p(t)\ =\ \dfrac{6}{D+2}[/tex]
[tex]=\ \dfrac{6.e^{0.t}}{D+2}[/tex]
[tex]=\ \dfrac{6}{0+2}[/tex]
= 3
so, the total solution can be given by
[tex]y_(t)\ =\ C.F+P.I[/tex]
[tex]=\ C.e^{-2t}\ +\ 3[/tex]
[tex]y_(0)=C.e^{-2.0}\ +\ 3[/tex]
but according to question
1 = C +3
=> C = -2
So, the complete solution can be given by
[tex]y_(t)\ =\ -2.e^{-2.t}\ +\ 3[/tex]
(b) Given differential equation is
Y'+2Y=-6
=>(D+2)y = -6
To find the complementary function, we will write
D+2=0
=> D = -2
So, the complementary function can be given by
[tex]y_c(t)\ =\ C.e^{-2t}[/tex]
To find the particular integral, we will write
[tex]y_p(t)\ =\ \dfrac{-6}{D+2}[/tex]
[tex]=\ \dfrac{-6.e^{0.t}}{D+2}[/tex]
[tex]=\ \dfrac{-6}{0+2}[/tex]
= -3
so, the total solution can be given by
[tex]y_(t)\ =\ C.F+P.I[/tex]
[tex]=\ C.e^{-2t}\ -\ 3[/tex]
[tex]y_(0)\ =C.e^{-2.0}\ -\ 3[/tex]
but according to question
1 = C -3
=> C = 4
So, the complete solution can be given by
[tex]y_(t)\ =\ 4.e^{-2.t}\ -3[/tex]
Norgestrel and ethinyl estradiol tablets are available containing 0.5 mg of norgestrel and 50 μg of ethinyl estradiol. How many grams of each ingredient would be used in making 10,000 tablets?
Answer:
5g of norgestel are used in making 10,000 tablets.
0.5g of ethinyl estradiol are used in making 10,000 tablets.
Step-by-step explanation:
This problem can be solved as a rule of three problem.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.
Unit conversion problems, like this one, is an example of a direct relationship between measures.
First step: Grams of norgestrel
Each tablet contais 0.5mg of norgestrel. How many miligrams are in 10,000 tablets?
1 tablet - 0.5 mg
10,000 tablets - x mg
x = 10,000*0.5
x = 5,000 mg
Now we have to convert 5,000 mg to g. Each g has 1,000 mg. So:
1g - 1,000 mg
xg - 5,000 mg
1,000x = 5,000
[tex]x = \frac{5,000}{1,000}[/tex]
x = 5g,
5g of norgestel are used in making 10,000 tablets.
Final step: Grams of ethinyl estradiol
50ug = 0.05 mg.
So
1 tablet - 0.05mg
10,000 tablets - xg
x = 10,000*0.05
x = 500 g
Now we have to convert 500 mg to g. Each g has 1,000 mg. So:
1g - 1,000 mg
xg - 500 mg
1,000x = 500
[tex]x = \frac{500}{1,000}[/tex]
x = 0.5g,
0.5g of ethinyl estradiol are used in making 10,000 tablets.
Use Gauss's approach to find the following sums (do not use formulas) a 1+2+3+4 998 b. 1+3+5 7+ 1001 a The sum of the sequence is
Answer:
(a) 498501
(b) 251001
Step-by-step explanation:
According Gauss's approach, the sum of a series is
[tex]sum=\frac{n(a_1+a_n)}{2}[/tex] .... (1)
where, n is number of terms.
(a)
The given series is
1+2+3+4+...+998
here,
[tex]a_1=1[/tex]
[tex]a_n=998[/tex]
[tex]n=998[/tex]
Substitute [tex]a_1=1[/tex], [tex]a_n=998[/tex] and [tex]n=998[/tex] in equation (1).
[tex]sum=\frac{998(1+998)}{2}[/tex]
[tex]sum=499(999)[/tex]
[tex]sum=498501[/tex]
Therefore the sum of series is 498501.
(b)
The given series is
1+3+5+7+...+ 1001
The given series is the sum of dd natural numbers.
In 1001 natural numbers 500 are even numbers and 501 are odd number because alternative numbers are even.
[tex]a_1=1[/tex]
[tex]a_n=1001[/tex]
[tex]n=501[/tex]
Substitute [tex]a_1=1[/tex], [tex]a_n=1001[/tex] and [tex]n=501[/tex] in equation (1).
[tex]sum=\frac{501(1+1001)}{2}[/tex]
[tex]sum=\frac{501(1002)}{2}[/tex]
[tex]sum=501(501)[/tex]
[tex]sum=251001[/tex]
Therefore the sum of series is 251001.
To find the sum of the sequences using Gauss's approach, we create pairs from the sequence that each have the same sum and then multiply the number of pairs by this common sum. For 1 to 998, this results in 499 pairs each summing to 999. For 1, 3, 5, ... to 1001, there are 501 pairs each summing to 1002.
The student is asking how to find the sum of two sequences using Gauss's approach, which does not involve the use of formulas. This approach, also known as Gauss's trick, involves pairing numbers from opposite ends of a sequence and then multiplying the number of pairs by the common sum of each pair to find the total sum.
Let's illustrate this for the sequences given:
For the sequence 1, 2, 3, ..., 998, we pair the first and last numbers (1 and 998), the second and second-to-last numbers (2 and 997), and so on until we reach the middle of the list. Each pair sums up to 999. Since there are 998 numbers in total, there will be 998/2 = 499 pairs. The sum of the sequence is 499 * 999.
For the sequence 1, 3, 5, ..., 1001, we recognize that this is an arithmetic series with a common difference of 2. We can pair the first and last terms (1 and 1001) to get a sum of 1002. Since the sequence has (1001-1)/2 + 1 terms, we will have (1000/2) + 1 = 501 pairs. Thus, the sum of the sequence is 501 * 1002.
Gauss's approach to summing an arithmetic series can be visualized by considering the example of summing the first n natural numbers, which results in the formula (n² + n)/2.
Find the area of the triangle with the vertices (2,1), (10,-1),
and(-1,8).
Answer:
The area of triangle is 25 square units.
Step-by-step explanation:
Given information: Vertices of the triangle are (2,1), (10,-1), and (-1,8).
Formula for area of a triangle:
[tex]A=\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|[/tex]
The given vertices are (2,1), (10,-1), and (-1,8).
Using the above formula the area of triangle is
[tex]A=\frac{1}{2}|2(-1-8)+10(8-1)+(-1)(1-(-1))|[/tex]
[tex]A=\frac{1}{2}|2(-9)+10(7)+(-1)(1+1)|[/tex]
[tex]A=\frac{1}{2}|-18+70-2|[/tex]
On further simplification we get
[tex]A=\frac{1}{2}|50|[/tex]
[tex]A=\frac{1}{2}(50)[/tex]
[tex]A=25[/tex]
Therefore the area of triangle is 25 square units.
An oil exploration company currently has two active projects, one in Asia and the other in Europe. Let A be the event that the Asian project is successful and B be the event that the European project is successful. Suppose that A and B are independent events with P(A) = 0.5 and P(B) = 0.9..(a) If the Asian project is not successful, what is the probability that the European project is also not successful?______Explain your reasoning.(A) Since the events are independent, then A' and B' are independent, too.(B) Since the events are independent, then A' and B' are mutually exclusive.(C) Since the events are not independent, then A' and B' are mutually exclusive.(D) Since the events are independent, then A' and B' are not independent.
Answer:
The probability that the European proyect is not succesfull is 0.1
Step-by-step explanation:
Since A and B are independent, A' and B' are independent too.
The probability of B' is P(B')=1-P(B) = 1 - 0.9 = 0.1
a. Every set has an element. b. The smallest perfect number is 28. c. Is 1.5 an irrational number? d. Please find the popular approximation of pi. e. Can you extract the root of -25?
Answer:
a) False. b) False. c) No, it's Rational. d) pi=355/113 e) 5i (for Complex Set of Numbers)
Step-by-step explanation:
a) Since there is the empty set. And an axiom assures us the existence of this Set. "There is a set such no element belongs to it"
∅ has no elements.
b) A perfect number is a positive integer equals to the sum of proper divisions
The smallest is 6. Since the proper divisors of 6={3,2,1}. 6=1+2+3
28 is a perfect number, but not the smallest. It is perfect since
28 proper divisors={14,7,4,2} 28=1+2+3+4+5+6+7
c) No, An Irrational number cannot be written as a fraction a/b where "a" and "b" are integers. 1.5 is a rational one, since 3/2 =1.5
d)
[tex]\pi[/tex]=22/7 -1/791= 355/113
e) Not for Real Numbers, since it is not defined for Real numbers. But for the set of Complex 5i
9 + 22 = x + 1
HALPP
Hey!
-------------------------------------------------
Solution:
9 + 22 = x + 1
9 + 22 - x = x + 1 - x
31 - x = 1
31 - x 31 = 31 - 1
x = 30
-------------------------------------------------
Answer:
x = 30
-------------------------------------------------
Hope This Helped! Good Luck!
Answer:
x = 30
Step-by-step explanation:
9 + 22 = x + 1
9 + 22 = 31
31 = x + 1
-1 -1
30 = x
x = 30
Calculate:
3 pounds (lbs) =——grams (g)
3. Galshore of Maloat is making a journey from the island of Gont to Oranea. The distance from the two lands is 965 miles. Galshore travels in her Sea Speeder at 129 miles per hour. How long did it take Galshore to make her journey? 4. The Countess Aliskia travels from Carthmore to Glenwyr. The distance between the two places is 612.1 miles. She makes the trip in Via her golden Sky Chariot. Via, with his emerald eyes can be seen travelling at a speed of 324 miles per hour with an altitude of 3 miles above the surface of the earth. How long did it take for the Countess to complete her magnificent trip?
Answer:
3. about 7.48 hours
4. about 1.8892 hours
Step-by-step explanation:
Both of these questions make use of the relation ...
time = distance / speed
3. time = (965 mi)/(129 mi/h) ≈ 7.48062 h ≈ 7.48 h
__
4. time = (612.1 mi)/(324 mi/h) ≈ 1.889198 h ≈ 1.8892 h
(We have rounded the time to sufficient precision so that the distance at the given speed rounds to the number given.)
At a newsstand, out of 46 customers, 27 bought the Daily News, 18 bought the Tribune, and 6 bought both papers.
Use a Venn diagram to answer the following questions:
How many customers bought only one paper?
How many customers bought something other than either of the two papers?
Answer:
[tex]\text{Customer that bought only one paper}=33[/tex]
[tex]\text{Customer that bought something other than either of the two papers}=7[/tex]
Step-by-step explanation:
We have been given that at a newsstand, out of 46 customers, 27 bought the Daily News, 18 bought the Tribune, and 6 bought both papers.
[tex]\text{Customer that bought only Daily news}=27-6[/tex]
[tex]\text{Customer that bought only Daily news}=21[/tex]
[tex]\text{Customer that bought only Tribune}=18-6[/tex]
[tex]\text{Customer that bought only Tribune}=12[/tex]
The customer that bought only one paper would be the sum of customers, who bought only Daily news or Tribune.
[tex]\text{Customer that bought only one paper}=21+12[/tex]
[tex]\text{Customer that bought only one paper}=33[/tex]
Therefore, 33 customers bought only one paper.
[tex]\text{Customer that bought something other than either of the two papers}=46-(27+18-6)[/tex]
[tex]\text{Customer that bought something other than either of the two papers}=46-(45-6)[/tex]
[tex]\text{Customer that bought something other than either of the two papers}=46-39[/tex]
[tex]\text{Customer that bought something other than either of the two papers}=7[/tex]
Therefore, 7 customers bought something other than either of the two papers.
[(√4 + 3)2 – 9] / (√9 – 1)3 * 2
Answer: 1
Step-by-step explanation:
[(√4 + 3)² – 9] / (√9 – 1)³ * 2 =
[(2 + 3)² – 9] / (3 – 1)³ * 2 =
[(5)² – 9] / (2)³ * 2 =
[25 – 9] / 8 * 2 =
[16] / 16 = 1
Which number is not the square of a whole number?
Select one:
a. 100
b. 400
c. 800
d. 144
Answer:
C. 800
Step-by-step explanation:
[tex]\sqrt{100} =10; \ \sqrt{400}=20; \ \sqrt{144}=12; \ \sqrt{800}=28.284271247461900976033774484194.[/tex]
Linda enrolls for 10 credit hours for each two semsters at a cost of $600 per credit hour. in addition textbooks $400 per semster.
Linda's total cost for college for this academic year is calculated as $12,800, encompassing both tuition and textbooks. This is part of an observed trend in increasing higher education costs.
Explanation:Cost of Tuition: Linda is paying $600 per credit hour for 20 credit hours (10 each semester), so $600 * 20 = $12,000 in total for tuition.
Cost of Textbooks: She is also spending $400 per semester for textbooks, so $400 * 2 = $800 in total for textbooks.
Total Cost: Thus, Linda's total cost for the academic year would be the sum of these two costs, i.e, $12,000 + $800 = $12,800. The costs of tuition, textbooks and other expenses are part of the rising trend of higher education costs. Despite this, the value of education still remains high, as it can lead to better job prospects and higher earning potential in the future.
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3. 36 percent of 18 is 18 percent of what number?
Final answer:
To find the number of which 18 percent is equal to 36 percent of 18, you set up the equation 0.36 × 18 = 0.18 × x and solve for x to find that x equals 36.
Explanation:
The student has asked: "36 percent of 18 is 18 percent of what number?" To solve this equation, we need to set it up as follows:
Let's assume the number we are searching for is x. Then, according to the question,
0.36 × 18 = 0.18 × x
Now, we can solve for x by dividing both sides of the equation by 0.18:
x = (0.36 × 18) / 0.18
After doing the calculation:
x = 6.48 / 0.18
x = 36
So, 36 percent of 18 is 18 percent of 36.
For each function below, determine whether or not the function is injective and whether| or not the function is surjective. Be sure to justify your answers. (a) f : N -> N given by f(n) =n+ 2
(b) f P({1,2, 3}) -» N given by f(A) = |A| (Note: P(S) denotes the power set of a set S.)
Answer:
a) injective but not surjective. b) neither injective nor surjective.
Step-by-step explanation:
A function is injective if there aren't repeated images. To check if a function is injective we are going to suppose that for two values in the domain the image is equal, then we need to find that the two values are equal.
a) f : N → N with f(n) = n+2.
suppose that for n and m natural numbers, f(n)=f(m). Then
n+2 = m+2
n+2-2 = m
n = m.
Then, f(n) is injective.
Now, a function is surjective if every term m in the codomain there exists a pre-image of that element, that is to say, there exists an n such that f(n) = m. That is, the range of the function is equal to the codomain.
In this case, f(n) is not surjective. For example, if we would have that
n+2 = 1
n = 1-2
n = -1
but -1 is not a natural number, then for m=1 we don't have a pre image in f.
b) f: P({1, 2, 3}) → N with f(A) = |A| (amount of elements in the subset A).
Now, for {1,2,3} we can have subsets of 0, 1, 2 or 3 elements. Then, the range of the function f is {1, 2, 3} (0 is not included because 0 is not natural). Then, the range is not all the natural numbers and therefore the function is not surjective.
Now, let's check if f is injective. Let {1} and {2} subsets of {1, 2, 3}. Then
f({1}) = |{1}| = 1.
f ({2}) = |{2}| = 1.
We have two different subsets with the same image, then f is not injective.
Prove that if n or m is an odd integer, then n*m is an even integer. Proposed proof: Suppose that n*m is odd. Then n*m = 2k + 1 for some integer k. Therefore, n or m must be odd.
Answer: Ok, we have two numbers, and one of them is an odd integer, and the other is even.
Lets call M to the odd integer and N the even.
We know that a even integer can be written as 2k, where k is a random integer, and a odd integer can be written as 2j + 1, where j is also a random integer.
then M = 2k, N= 2j+1
then the product of M and N is: M*N = 2*k*(2*j + 1) = 2*(k*2*j + k)
is obvious to see that (k*2*J + k) is a integer, because k and j are integers.
then if we call g = ( k*2*J + k), we can write M*N=2g, and we already know that this is an even number. So M*N is a even integer.
The USS Enterprise was 1,123 feet in length.
A. What is the scale for a model that is 30 inches long?
B. What is the scale for a model that is 2 feet long?
Answer:
The scale for a model that is 30 inches long is 449.2 inches.
The scale for a model that is 2 feet long is 561.5 feet.
Step-by-step explanation:
Consider the provided information.
The USS Enterprise was 1,123 feet in length.
Part (A) What is the scale for a model that is 30 inches long?
1 feet = 12 inches.
First convert the length of USS enterprise in inches.
1×1,123 feet = 12×1,123 inches
1,123 feet = 13476 inches
Divide original length with the length of model.
The scale for the model is:
[tex]\frac{13476}{30}=449.2\ inches[/tex]
Hence, the scale for a model that is 30 inches long is 449.2 inches.
Part (B) What is the scale for a model that is 2 feet long?
Since, both the units are in feet, so simply divide original length with the length of model.
The scale for the model is:
[tex]\frac{1123}{2}=561.5\ feet[/tex]
Hence, the scale for a model that is 2 feet long is 561.5 feet.
At Phill's Discount Car Kingdom, you can purchase a used car for $14,000. Phill offers you two payment options: Option 1: You can apply an immediate cash rebate of $2,000 from the dealer to reduce the cost of the car and finance the rest with a loan that has an annual rate of 3.6%, with interest compounded monthly, for 3 years. You would make equal payments at the end of each month until the loan was repaid . Option 2: You can take out a 0% loan for the full price of the car in which you agree to pay the same amount at the end of each month for 3 years until the car is paid off What is the total amount that you would pay (out of pocket) for the car under each option?
Answer:
Ans. For option 1, you would pay a total of $14,677.64 and for the second option, you would pay $14,000.
Step-by-step explanation:
Hi, we need to find the amount of the equal payments that you need to make every month, given the problem´s conditions. First, let´s find the effective montly rate of this credit.
[tex]EffectiveMonthlyRate=\frac{Rate(Compounded Monthly)}{12}[/tex][tex]EffectiveMonthlyRate=\frac{0.036}{12} =0.003[/tex]
This means that the rate is 0.3% effective monthly
The period of time for this obligation is 3 years, but since the payments are made every month, we need to use 36 months instead of 3 years.
Now, we are ready to find the amount of money that you need to pay every month, for 36 months in order to pay for your car. We use the following formula.
[tex]PresentValue=\frac{A((1+r)^{n}-1) }{r(1+r)^{n} }[/tex]
Since you made a down payment of $2,000, we will only need to finance $12,000. This is the way everything should look like.
[tex]12,000=\frac{A((1+0.003)^{36}-1) }{0.003(1+0.003)^{36} }[/tex]
Let´s solve for A (annuity)
[tex]12,000=\frac{A(0.11386764 }{0.003416 }[/tex]
[tex]12,000==A(34.0757554)[/tex]}
[tex]\frac{12,000}{34.0757554} =A=352.17[/tex]
The total amount paid if you take this option is:
[tex]Amount Paid=2,000+352.17*36=14,677.64[/tex]
In the case of option 2 (0% loan-pay same amount every month for 36 months), there is no need for any calculations (because you pay $14,000 in total), but if you want to know how much to pay every month, you just go ahead and divide 14,000 by 36 which is $388.89. But at the end, this way you will pay $14,000.
Best of luck.
A graduate weighs 35.825 g. When 10 mL of water are measured in it, the weight of the graduate and water is 45.835 g. Calculate the weight of the water and express any deviation from 10 g as a percentage of error.
Answer:
Calculated weight of water = 10.01 g
percentage error = 0.1%
Step-by-step explanation:
Given:
Weight of graduate = 35.825 g
Weight of graduate + Water = 45.835 g
Now,
The weight of water = ( Weight of graduate + Water ) - Weight of graduate
or
The weight of water = 45.835 - 35.825
or
The weight of water = 10.01 g
Now,
The percentage of error = [tex]\frac{\textup{Calculated value - Actual value}}{\textup{Actual value}}\times100[/tex]
or
The percentage error = [tex]\frac{\textup{10.01 - 10}}{\textup{10}}\times100[/tex]
or
The percentage error = 0.1%
The weight of the water is 10.010 g, and the percentage of error from the expected 10 g is 0.1%
To calculate the weight of the water and express any deviation from 10 g as a percentage of error, follow these steps:
1. Calculate the weight of the water:
The weight of the water can be determined by subtracting the weight of the empty graduate from the weight of the graduate with water.
[tex]\[ \text{Weight of water} = \text{Weight of graduate and water} - \text{Weight of empty graduate} \][/tex]
Given:
- Weight of empty graduate = 35.825 g
- Weight of graduate with water = 45.835 g
[tex]\[ \text{Weight of water} = 45.835 \, \text{g} - 35.825 \, \text{g} = 10.010 \, \text{g} \][/tex]
2. Calculate the deviation from 10 g:
[tex]\[ \text{Deviation} = \text{Weight of water} - 10 \, \text{g} \][/tex]
3. Calculate the percentage of error:
[tex]\[ \text{Percentage of error} = \left( \frac{\text{Deviation}}{10 \, \text{g}} \right) \times 100\% \][/tex]
[tex]\[ \text{Percentage of error} = \left( \frac{0.010 \, \text{g}}{10 \, \text{g}} \right) \times 100\% = 0.1\% \][/tex]
Therefore, the weight of the water is 10.010 g, and the percentage of error from the expected 10 g is 0.1%.
A restaurant sold 6 hamburgers every day for a week. How many hamburgers were sold during the week
Answer:
42 hamburgers
Step-by-step explanation:
Your answer is 42.
6 x 7 = 42