Answer:
static value come under the rejection value because it is less than critical value
Step-by-step explanation:
Given data
test = 300
wrong test = 30
significance level = 0.01
claim for wrong = 10 %
to find out
test the claim that less than 10 percent of the test results are wrong
solution
we take test claim null hypo thesis = 10 % = 0.10
and and alternate hypo thesis < 10% i.e. <0.10
and we know proportion of sample is = result/ test
sample proportion = 30/300 = 0.10
so the statistics of this test will be = sample proportion - hypothesis / [tex]\sqrt{hyro(1-hypo)/test}[/tex]
so statistics of this test = 0.10 - 0.10 / [tex]\sqrt{0.10(1-0.10)/300}[/tex]
so statistics of this test = 0
and α = tail area critical value for Z (0.01) = 2.33
so here static value come under the rejection value because it is less than critical value
To test the claim that less than 10 percent of the test results are wrong, we'll use a hypothesis test with a 0.01 significance level. The calculated test statistic z will determine whether to reject or fail to reject the null hypothesis.
Explanation:To test the claim that less than 10 percent of the test results are wrong, we'll use a hypothesis test with a 0.01 significance level. Let p represent the proportion of wrong test results. The null hypothesis is that p is greater than or equal to 0.10, and the alternative hypothesis is that p is less than 0.10.
We'll calculate the test statistic z = (x - np) / sqrt(np(1-p)), where x is the number of wrong test results and n is the total number of tested subjects. Using the given information, x = 30 and n = 300.
Using a z-table or calculator, we can find the z-score corresponding to a significance level of 0.01. If the calculated test statistic z is less than the z-score from the table, we reject the null hypothesis. Otherwise, we fail to reject the null hypothesis.
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Find the interest rate on a loan charging $855 simple interest on a principal of $3750 after 6 years.
Answer:
3.8%
Step-by-step explanation:
Simple interest formula is I=P*R*T
where:
I=interest
P=principal
R=rate
T=time.
So let's plug in our information we are given:
I=855
P=3750
T=6
R=?.
The equation becomes 855=3750*R*6.
Multiplication is commutative so we could write this as 3750*6*R=855.
After the multiplication of 3750 and 6 we obtain 22500*R=855.
Now we just divide both sides by 22500. This will give us:
R=855/22500 which when entered into the calculator as 855 division sign 22500 gives us 0.038 or 3.8%.
The diameters of red delicious apples of an orchard have a normal distribution with a mean of 3 inches and a standard deviation of 0.5 inch. One apple will be randomly chosen. What is the probability of picking an apple with diameter greater than 3.76 inches?
To find the probability of picking an apple with a diameter greater than 3.76 inches from a normally distributed population with a mean of 3 inches and a standard deviation of 0.5 inches, we calculate a z-score and then find the corresponding probability using a z-table or calculator.
Explanation:The question is about finding the probability in a situation that follows a normal distribution, specifically, the likelihood of picking an apple with a diameter greater than 3.76 inches given a mean of 3 inches and a standard deviation of 0.5 inches.
To solve this, we must first calculate the z-score, which is the number of standard deviations a data point (in this case, the apple size of 3.76 inches) is from the mean. The z-score is calculated as follows: Z = (X - μ) / σ, where X is the data point, μ is the mean, and σ is the standard deviation. Substituting the given values, we get Z = (3.76 - 3) / 0.5, which results in a z-score of 1.52.
Next, we will refer to the z-table to find the probability corresponding to this z-score. However, most z-tables give the probability from the mean to our z-score (the left-hand side). But we want the probability that the apple's diameter is greater than 3.76 inches, i.e., the right-hand side of the distribution curve. As a result, we have to subtract the value we get from the z-table from 1 (because the cumulative probability under the entire normal curve is 1).
If a z-table is not readily available, there are many online calculators available to find this probability.
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John has won the mega-bucks lottery, which pays $1, 000, 000. Suppose he deposits the money in a savings account that pays an annual interest of 8% compounded continuously. How long will this money last if he makes annual withdrawals of $100, 000?
Answer:20.91
Step-by-step explanation:
Given
Principal amount invested=[tex]\$ 1,000,000[/tex]
Rate of interest=8%
Annual Withdrawl=[tex]\$ 100,000[/tex]
compound interest is given by
A=[tex]\left (1+ \frac{r}{100}\right )^t[/tex]
Therefore reamining Amount after certain years
Net money will become zero after t year
[tex]1,000,000\left (1+ \frac{8}{100} \right )^t - 100,000\left ( \frac{\left ( 1.08\right )^{t}-1}{0.08}\right )[/tex]=0
[tex]0.8\left ( 1.08\right )^t=\left ( 1.08\right )^{t}-1[/tex]
t=20.91 years
Translate the following ordinary-language sentences into logical symbolic form using capital letters for simple phrases and the standard symbols – “·,” “˅,” “¬,” “≡,” “⊃” – for the logical operators. 1. Either existing home sales will decrease or new housing starts will increase and unemployment will decrease only if the Federal Reserve decreases long-term interest rates and foreign trade deficits decrease or foreign trade deficits increase and manufacturing rates increase. 2. Germany will vote to limit the number of immigrants it admits and so will reject Angela Merkel’s international policies unless neighboring EU countries agree to a multi-national work visa program and either the World Bank revalues the Euro relative to the US dollar or the US-Russia brokered peace treaty is signed by Syria.
P - existing home sales will decrease
Q - new housing starts will increase
R - unemployment will decrease
S - the Federal Reserve decreases long-term interest rates
T - foreign trade deficits decrease
U - foreign trade deficits increase
V - manufacturing rates increase
[tex][(P \vee Q) \wedge R] \iff (S \wedge T) \vee (U \wedge V)[/tex]
P - Germany will vote to limit the number of immigrants it admits
Q - will reject Angela Merkel’s international policies
R - neighboring EU countries agree to a multi-national work visa program
S - the World Bank revalues the Euro relative to the US dollar
T - the US-Russia brokered peace treaty is signed by Syria.
[tex]\neg (R \wedge (S \vee T))\implies (P \implies R)\\[/tex]
At Southern States University (SSU) there are 399 students taking Finite Mathematics or Statistics. 238 are taking Finite Mathematics, 184 are taking Statistics, and 23 are taking both Finite Mathematics and Statistics. How many are taking Finite Mathematics but not Statistics?
Answer:
215
Step-by-step explanation:
The 238 taking Finite Math includes those taking Finite Math and Statistics. Subtracting out the 23 who are taking both leaves 215 taking Finite Math only.
215 students are taking Finite Mathematics but not Statistics.
To find out how many students are taking Finite Mathematics but not Statistics at Southern States University (SSU), let's break down the information given and use set theory concepts.
Total number of students taking either Finite Mathematics or Statistics: 399
Number of students taking Finite Mathematics: 238
Number of students taking Statistics: 184
Number of students taking both Finite Mathematics and Statistics: 23
First, we need to figure out how many students are taking only Finite Mathematics. We can do this by subtracting the number of students taking both Finite Mathematics and Statistics from the total number of students taking Finite Mathematics.
Number of students taking only Finite Mathematics = Total taking Finite Mathematics - Total taking both Finite Mathematics and Statistics
So,
Number of students taking only Finite Mathematics = 238 - 23
Number of students taking only Finite Mathematics = 215
Find the volume of the solid obtained by rotating the region bounded by the x-axis, the y-axis, the line y=2, and y=e^x about the y-axis. Round your answer to three decimal places.
Answer:
0.592
Step-by-step explanation:
The volume of the solid, rounded to three decimal places is 18.257.
The volume of the solid obtained by rotating the region around the y-axis can be found using the method of discs or washers. Since the region is bounded by the x-axis, the y-axis, the line y=2, and the curve [tex]y=e^x[/tex], we will integrate with respect to y.
The volume V of the solid of revolution is given by the integral:
[tex]\[ V = \pi \int_{a}^{b} [R(y)]^2 dy - \pi \int_{a}^{b} [r(y)]^2 dy \][/tex]
where [tex]\( R(y) \)[/tex] is the outer radius and [tex]\( r(y) \)[/tex] is the inner radius of the discs or washers.
In this case, the outer radius [tex]\( R(y) \)[/tex] is given by the line y=2, which is a horizontal line, so the outer radius is constant and equal to 2. The inner radius [tex]\( r(y) \)[/tex] is given by the curve [tex]y=e^x[/tex]. To express x in terms of y, we take the natural logarithm of both sides to get [tex]\( x = \ln(y) \)[/tex].
Now we can set up our integrals:
[tex]\[ V = \pi \int_{0}^{2} [2]^2 dy - \pi \int_{0}^{2} [\ln(y)]^2 dy \][/tex]
[tex]\[ V = \pi \int_{0}^{2} 4 dy - \pi \int_{0}^{2} [\ln(y)]^2 dy \][/tex]
The first integral is straight forward:
[tex]\[ \pi \int_{0}^{2} 4 dy = \pi \left[ 4y \right]_{0}^{2} = \pi [4(2) - 4(0)] = 8\pi \][/tex]
The second integral requires integration by parts. Let [tex]\( u = [\ln(y)]^2 \)[/tex]and [tex]\( dv = dy \)[/tex], then [tex]\( du = \frac{2\ln(y)}{y} dy \)[/tex] and [tex]\( v = y \)[/tex]. Applying integration by parts gives:
[tex]\[ \pi \int_{0}^{2} [\ln(y)]^2 dy = \pi \left[ y[\ln(y)]^2 - \int_{0}^{2} 2\ln(y) dy \right] \][/tex]
Now, we need to integrate [tex]\( 2\ln(y) \)[/tex] by parts again, with [tex]\( u = \ln(y) \)[/tex] and [tex]\( dv = dy \)[/tex], then [tex]\( du = \frac{1}{y} dy \)[/tex] and [tex]\( v = y \)[/tex]. This gives:
[tex]\[ \int_{0}^{2} 2\ln(y) dy = \left[ 2y\ln(y) - \int_{0}^{2} 2 dy \right] \][/tex]
[tex]\[ \int_{0}^{2} 2\ln(y) dy = \left[ 2y\ln(y) - 2y \right]_{0}^{2} \][/tex]
[tex]\[ \int_{0}^{2} 2\ln(y) dy = 2(2)\ln(2) - 2(2) - (0) \][/tex]
[tex]\[ \int_{0}^{2} 2\ln(y) dy = 4\ln(2) - 4 \][/tex]
Putting it all together:
[tex]\[ \pi \int_{0}^{2} [\ln(y)]^2 dy = \pi \left[ y[\ln(y)]^2 - (4\ln(2) - 4) \right]_{0}^{2} \][/tex]
[tex]\[ \pi \int_{0}^{2} [\ln(y)]^2 dy = \pi \left[ 2[\ln(2)]^2 - (4\ln(2) - 4) \right] - \pi \left[ \lim_{y \to 0} y[\ln(y)]^2 - (4\ln(2) - 4) \right] \][/tex]
The limit as y approaches 0 of [tex]\( y[\ln(y)]^2 \)[/tex] is 0, so we have:
[tex]\[ \pi \int_{0}^{2} [\ln(y)]^2 dy = \pi \left[ 2[\ln(2)]^2 - 4\ln(2) + 4 \right] \][/tex]
[tex]\[ \pi \int_{0}^{2} [\ln(y)]^2 dy = 2\pi[\ln(2)]^2 - 4\pi\ln(2) + 4\pi \][/tex]
Now, subtract this from the first integral:
[tex]\[ V = 8\pi - (2\pi[\ln(2)]^2 - 4\pi\ln(2) + 4\pi) \][/tex]
[tex]\[ V = 8\pi - 2\pi[\ln(2)]^2 + 4\pi\ln(2) - 4\pi \][/tex]
[tex]\[ V = 4\pi + 4\pi\ln(2) - 2\pi[\ln(2)]^2 \][/tex]
[tex]\[ V = 4\pi(1 + \ln(2) - \frac{1}{2}[\ln(2)]^2) \][/tex]
Rounded to three decimal places, the volume is:
[tex]\[ V \approx 4\pi(1 + \ln(2) - \frac{1}{2}[\ln(2)]^2) \approx 4\pi(1 + 0.693 - \frac{1}{2}(0.693)^2) \][/tex]
[tex]\[ V \approx 4\pi(1 + 0.693 - 0.240) \][/tex]
[tex]\[ V \approx 4\pi(1.453) \][/tex]
[tex]\[ V \approx 5.812\pi \][/tex]
[tex]\[ V \approx 18.257 \][/tex]
Therefore, the volume of the solid, rounded to three decimal places, is:
[tex]\[ \boxed{18.257} \][/tex].
The complete question is:
Find the volume of the solid obtained by rotating the region bounded by the x-axis, the y-axis, the line y=2, and [tex]y=e^x[/tex] about the y-axis. Round your answer to three decimal places.
Continuing the previous problem, use the data points (1950, 0.75) and (1997, 5.15) to find the slope. Show all work necessary for your calculations. If necessary, round your answer to the hundredths place. What does the slope represent in the context of the problem?
Answer:
Slope is 0.094,
It represents the average rate of change.
Step-by-step explanation:
Since, the slope is the ratio of difference in y-coordinates and the difference in x-coordinates,
Also, in a order pair, first element shows the x-coordinate and second element shows the y-coordinate.
Here, the data points are (1950, 0.75) and (1997, 5.15),
Thus, the slope is,
[tex]m=\frac{5.15-0.75}{1997-1950}[/tex]
[tex]=\frac{4.4}{47}[/tex]
[tex]=0.0936170212766[/tex]
[tex]\approx 0.094[/tex]
Also, Slope represents the average rate of change.
Find a second independent solution y1=x xy"-xy'+y=0
We can use reduction of order. Given that [tex]y_1(x)=x[/tex] is a known solution, we look for a solution of the form [tex]y_2(x)=v(x)y_1(x)[/tex]. It has derivatives [tex]{y_2}'=v'y_1+v{y_1}'[/tex] and [tex]{y_2}''=v''y_1+2v'{y_1}'+v{y_1}''[/tex]. Substituting these into the ODE gives
[tex]x(xv''+2v')-x(xv'+v)+xv=0[/tex]
[tex]x^2v''+(2x-x^2)v'=0[/tex]
Let [tex]w(x)=v'(x)[/tex] so that [tex]w'(x)=v''(x)[/tex] and we get an ODE linear in [tex]w[/tex]:
[tex]x^2w'+(2x-x^2)w=0[/tex]
Divide both sides by [tex]e^x[/tex]:
[tex]x^2e^{-x}w'+(2x-x^2)e^{-x}w=0/tex]
Since [tex](x^2e^{-x})=(2x-x^2)e^{-x}[/tex], we can condense the left side as the derivative of a product:
[tex](x^2e^{-x}w)'=0[/tex]
Integrate both sides and solve for [tex]w(x)[/tex]:
[tex]x^2e^{-x}w=C\implies w=\dfrac{Ce^x}{x^2}[/tex]
Integrate both sides again to solve for [tex]v(x)[/tex]. Unfortunately, there is no closed form for the integral of the right side, but we can leave the result in the form of a definite integral:
[tex]v=\displaystyle C_2+C_1\int_{x_0}^x\frac{e^t}{t^2}\,\mathrm dt[/tex]
where [tex]x_0[/tex] is any point on an interval over which a solution to the ODE exists.
Finally, multiply by [tex]y_1(x)[/tex] to solve for [tex]y_2(x)[/tex]:
[tex]y_2=\displaystyle C_2x+C_1x\int_{x_0}^x\frac{e^t}{t^2}\,\mathrm dt[/tex]
[tex]y_1(x)[/tex] already accounts for the [tex]C_2x[/tex] term above, so the second independent solution is
[tex]y_2=x\displaystyle\int_{x_0}^x\frac{e^t}{t^2}\,\mathrm dt[/tex]
Compute the entry (the number in the second row and second column) of the product matrix resulting from the following multiplication:
[1 2] [9 6]
[3 4] [5 7]
Answer:
The entry on the second row and second column of the product matrix is [tex]c_{22} = 40[/tex].
Step-by-step explanation:
Let's define as A and B the given matrixes:
[tex]A = \left[\begin{array}{cc}1&2\\3&4\end{array}\right][/tex]
[tex]B = \left[\begin{array}{cc}9&6\\5&7\end{array}\right][/tex]
The product matrix C entry in the first row and first column [tex]c_{1,1}[/tex] or [tex]c_{11}[/tex] can be computer multiplying first row of A by first column of B (see example attached).
The product matrix C entry in the first row and second column [tex]c_{1,2}[/tex] or [tex]c_{12}[/tex] can be computer multiplying first row of A by second column of B.
The product matrix C entry in the second row and first column [tex]c_{2,1}[/tex] or [tex]c_{21}[/tex] can be computer multiplying second row of A by first column of B.
The product matrix C entry in the second row and second column [tex]c_{2,2}[/tex] or [tex]c_{22}[/tex] can be computer multiplying second row of A by second column of B.
Then, let's compute [tex]c_{22}[/tex] by doing the dot product between [3 4] and [6 7]...
[tex]c_{22} = [3 4] . [6 7] = 3*4 + 4*7 = 12 + 28 = 40[/tex]
Find the volumes of the solids generated by revolving the triangle with vertices (2, 2), (2, 6), and (5, 6) about a) the x-axis, b) the y-axis, c) the line x=7, and d) the line y=2.
[tex]\displaystyle\pi\int_2^5\left(6^2-\left(\frac43x-\frac23\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(20+x-x^2)\,\mathrm dx=\boxed{56\pi}[/tex]
About the [tex]y[/tex]-axis (shell method):[tex]\displaystyle2\pi\int_2^5x\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5x(5-x)\,\mathrm dx=\boxed{36\pi}[/tex]
About [tex]x=7[/tex] (shell method):[tex]\displaystyle2\pi\int_2^5(7-x)\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5(35-12x+x^2)\,\mathrm dx=\boxed{48\pi}[/tex]
About [tex]y=2[/tex] (washer method):[tex]\displaystyle\pi\int_2^5\left((6-2)^2-\left(\frac43x-\frac23-2\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(5+4x-x^2)\,\mathrm dx=\boxed{32\pi}[/tex]
The y-coordinates of the two intersection points of the triangle and the line y=2 (Option d).
In this explanation, we will explore how to find the volumes of solids formed by revolving a triangle with given vertices about different axes and lines. We'll use basic calculus principles to calculate the volumes and understand the concept of rotation in three-dimensional space.
a) To find the volume of the solid generated by revolving the triangle about the x-axis, we imagine rotating the triangle in a circular motion around the x-axis. This forms a three-dimensional shape known as a "solid of revolution."* To calculate the volume, we integrate the cross-sectional area of each infinitesimally thin slice of the solid perpendicular to the x-axis, from the x-coordinate of the leftmost point to the rightmost point.
Let's use the "disk method" to integrate the cross-sectional areas. Each disk has a radius equal to the y-coordinate of the triangle at a particular x-coordinate. The formula for the volume using the disk method is:
Vx = ∫[from a to b] π * (y)² dx
Where (a, b) are the x-coordinates of the leftmost and rightmost points of the triangle, and y represents the y-coordinate of the triangle at a specific x.
b) Similarly, to find the volume of the solid formed by revolving the triangle about the y-axis, we use the "washer method". In this case, the inner radius of each washer is given by the x-coordinate of the triangle at a particular y-coordinate. The formula for the volume using the washer method is:
Vy = ∫[from c to d] π * (x)² dy
Where (c, d) are the y-coordinates of the bottommost and topmost points of the triangle, and x represents the x-coordinate of the triangle at a specific y.
c) To find the volume of the solid formed by revolving the triangle about the line x=7, we use the "shell method".
We integrate the circumference of each cylindrical shell formed between the triangle and the line x=7. The formula for the volume using the shell method is:
V7 = ∫[from e to f] 2π * (x-7) * y dx
Where (e, f) are the x-coordinates of the two intersection points of the triangle and the line x=7.
d) Lastly, to find the volume of the solid formed by revolving the triangle about the line y=2, we can use the shell method as well, considering cylindrical shells formed between the triangle and the line y=2. The formula for the volume using the shell method is:
Vy=2 = ∫[from g to h] 2π * (y-2) * x dy
Where (g, h) are the y-coordinates of the two intersection points of the triangle and the line y=2.
By calculating the integrals using these formulas, we can find the volumes of the solids generated by revolving the triangle about the specified axes and lines. Remember to always set up the integral limits correctly based on the x or y coordinates of the triangle's vertices.
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(show the supposition, proof and conclusion)
Use proof by contradiction to show that If a and b are rational numbers with b ≠ 0 and x is an irrational number, then a + bx is irrational.
Answer:
Step-by-step explanation:
We are given that a and b are rational numbers where [tex]b\neq0[/tex] and x is irrational number .
We have to prove a+bx is irrational number by contradiction.
Supposition:let a+bx is a rational number then it can be written in [tex]\frac{p}{q}[/tex] form
[tex]a+bx=\frac{p}{q}[/tex] where [tex]q\neq0[/tex] where p and q are integers.
Proof:[tex]a+bx=\frac{p}{q}[/tex]
After dividing p and q by common factor except 1 then we get
[tex]a+bx=\frac{r}{s}[/tex]
r and s are coprime therefore, there is no common factor of r and s except 1.
[tex]a+bx=\frac{r}{s}[/tex] where r and s are integers.
[tex]bx=\frac{r}{s}-a[/tex]
[tex]x=\frac{\frac{r}{s}-a}{b}[/tex]
When we subtract one rational from other rational number then we get again a rational number and we divide one rational by other rational number then we get quotient number which is also rational.
Therefore, the number on the right hand of equal to is rational number but x is a irrational number .A rational number is not equal to an irrational number .Therefore, it is contradict by taking a+bx is a rational number .Hence, a+bx is an irrational number.
Conclusion: a+bx is an irrational number.
A recipe that makes 3 dozen peanut butter cookies calls for 1 and 1/4 cups of flour. How much flour would you need to make 7 dozen cookies?
Answer:
[tex]2\frac{11}{12}[/tex] cups of flour are nedeed
Step-by-step explanation:
we know that
3 dozen peanut butter cookies calls for 1 and 1/4 cups of flour
Convert mixed number to an improper fraction
[tex]1\frac{1}{4}\ cups=\frac{1*4+1}{4}=\frac{5}{4}\ cups[/tex]
using proportion
Find out how much flour would you need to make 7 dozen cookies
Let
x ----> the number of cups of flour
[tex]\frac{3}{(5/4)}\frac{dozen}{cups}=\frac{7}{x}\frac{dozen}{cups} \\ \\x=7*(5/4)/3\\ \\x=\frac{35}{12}\ cups[/tex]
Convert to mixed number
[tex]\frac{35}{12}\ cups=\frac{24}{12}+\frac{11}{12}=2\frac{11}{12}\ cups[/tex]
Answer:
2.92 or 2 and 23/25 cups are required for 7 dozen cookies
Step-by-step explanation:
Determine the required number of flour for 3 dozen cookies. Use it to find flour required for 7 dozen cookies.
Dozen cookies Flour
3 1 + 1/4
7 x
Cross multiply to find the value of x
3x = 7(1+1/4)
3x = 7(5/4)
12x = 35
x = 2.92 cups or 2 and 23/25 cups
Therefore, 2.92 cups or 2 and 23/25 cups of flour are required for 7 dozen peanut butter cookies.
!!
A company builds a new wing for its east branch and knows that each additional room will gain $1200 of profit. The construction company will cost $44,000 to construct the wing.
How many rooms are need to break even? (Hint: You must PAY the fee to the construction company.)
If you wanted to make twice as much profit as you spent, how many rooms would need to be built?
Answer:
a. 37 rooms are need to break even.
b. 73 rooms are required to make twice as much profit as you spent.
Step-by-step explanation:
Revenue of the company from each additional room is $1200.
Total construction cost = $44,000.
At break even condition, total revenue is equal to total cost. In other words, the profit of the firm is zero at break even.
Let x be the number of rooms that are need to break even.
Total revenue of x room is
[tex]TR=1200x[/tex]
At break even,
Total revenue = Total cost
[tex]1200x=44000[/tex]
Divide both sides by 1200.
[tex]x=\frac{44000}{1200}=36.6667\approx 37[/tex]
Therefore, 37 rooms are need to break even.
Let y be the number of rooms to make twice as much profit as you spent.
Total revenue of y room is
[tex]TR=1200y[/tex]
Total revenue = 2 × Total cost
[tex]1200x=2\times 44000[/tex]
[tex]1200x=88000[/tex]
Divide both sides by 1200.
[tex]y=\frac{88000}{1200}=73.33\approx 73[/tex]
Therefore 73 rooms are required to make twice as much profit as you spent.
The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 5 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes.
Answer: 0.75
Step-by-step explanation:
Given : Interval for uniform distribution : [0 minute, 5 minutes]
The probability density function will be :-
[tex]f(x)=\dfrac{1}{5-0}=\dfrac{1}{5}=0.2\ \ ,\ 0<x<5[/tex]
The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
[tex]P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75[/tex]
Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75
The probability that a randomly selected passenger has a waiting time greater than 1.25 minutes is 1.
Explanation:To find the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes, we need to find the area under the probability density function (PDF) curve for values greater than 1.25. Since the waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 5 minutes, the PDF is a rectangle with height 1/5 and base 5. The area of the rectangle represents the probability.
The probability of a waiting time greater than 1.25 minutes is the ratio of the area of the rectangle representing waiting times greater than 1.25 minutes to the total area of the rectangle representing all waiting times.
To calculate this probability, we first need to find the area of the rectangle representing waiting times greater than 1.25 minutes. Since the base of the rectangle is 5 minutes and the height is 1/5, the area is given by:
Area = base * height = 5 * (1/5) = 1
The total area of the rectangle representing all waiting times is the area of the entire rectangle, which is also equal to:
Area = base * height = 5 * (1/5) = 1
Therefore, the probability of a randomly selected passenger having a waiting time greater than 1.25 minutes is:
Probability = Area of waiting times greater than 1.25 minutes / Total area = 1/1 = 1
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find a general solution of
t *(dy/dt)-(y^2)*lnt+y=0
[tex]t\dfrac{\mathrm dy}{\mathrm dt}-y^2\ln t+y=0[/tex]
Divide both sides by [tex]y(t)^2[/tex]:
[tex]ty^{-2}\dfrac{\mathrm dy}{\mathrm dt}-\ln t+y^{-1}=0[/tex]
Substitute [tex]v(t)=y(t)^{-1}[/tex], so that [tex]\dfrac{\mathrm dv}{\mathrm dt}=-y(t)^{-2}\dfrac{\mathrm dy}{\mathrm dt}[/tex].
[tex]-t\dfrac{\mathrm dv}{\mathrm dt}-\ln t+v=0[/tex]
[tex]t\dfrac{\mathrm dv}{\mathrm dt}-v=\ln t[/tex]
Divide both sides by [tex]t^2[/tex]:
[tex]\dfrac1t\dfrac{\mathrm dv}{\mathrm dt}-\dfrac1{t^2}v=\dfrac{\ln t}{t^2}[/tex]
The left side can be condensed as the derivative of a product:
[tex]\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac1tv\right]=\dfrac{\ln t}{t^2}[/tex]
Integrate both sides. The integral on the right side can be done by parts.
[tex]\displaystyle\int\frac{\ln t}{t^2}\,\mathrm dt=-\frac{\ln t}t+\int\frac{\mathrm dt}{t^2}=-\frac{\ln t}t-\frac1t+C[/tex]
[tex]\dfrac1tv=-\dfrac{\ln t}t-\dfrac1t+C[/tex]
[tex]v=-\ln t-1+Ct[/tex]
Now solve for [tex]y(t)[/tex].
[tex]y^{-1}=-\ln t-1+Ct[/tex]
[tex]\boxed{y(t)=\dfrac1{Ct-\ln t-1}}[/tex]
A survey of 400 randomly selected high school students determined that 68 play organized sports. (a) What is the probability that a randomly selected high school student plays organized sports? (b) Interpret this probability.
Answer: a) The probability that a randomly selected high school student plays organized sports = 0.17
b) The randomly selected high school student is unlikely to play organized sports.
Step-by-step explanation:
Given : A survey of 400 randomly selected high school students determined that 68 play organized sports.
Then , the probability that a randomly selected high school student plays organized sports is given by :-
[tex]\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}\\\\=\dfrac{68}{400}=0.17[/tex]
In percent , the probability that a randomly selected high school student plays organized sports is 17%.
since 17% lies in the interval of unlikely events (0%, 25%).
It means that the randomly selected high school student is unlikely to play organized sports.
The probability that a randomly selected high school student plays organized sports is 0.17, which means there is a 17% chance, or a 1 in 6 chance, that a randomly picked student plays organized sports.
Explanation:This question relates to the field of Statistics, particularly to the concept of Probability. In this problem, we are provided with a total number of High School students (400), and a number of students who play organized sports (68).
To find the probability, you would divide the number of students who play sports by the total number of students. That is, Probability = Number with desired characteristic (play sports) / Total number In this case, it would be 68 / 400 = 0.17
Interpreting the probability means describing what it represents in practical terms. Here, a probability of 0.17 means that if you were to randomly select a high school student, there is a 17% chance, or around 1 in 6 chance, that this student plays organized sports.
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The distance between my house and Memphis is 150 km. If I drive in my car, it takes me 72 min to make the first 100 km of the drive. If I keep traveling at the same rate, how many more minutes will it take to drive the remaining distance? Round your answer to the nearest tenth.
Set up a ratio:
You drove 72 minutes and 100 km = 72/100
You want the number of minutes (x) to drive 150 km = x/150
Set the ratios to equal each other and solve for x:
72/100 = x/150
Cross multiply:
(72 * 150) = 100 * x)
Simplify:
10,800/100x
Divide both sides by 100:
x = 10800/100 = 108
This means it would take 108 minutes to drive 150 km.
Now subtract the time you have already driven to fin how much more you need:
180 - 72 = 36 more minutes.
Answer:
36 min
Step-by-step explanation:
It takes 72 min to drive 100 km. 50 km are left to drive.
Half of the driving above is: It takes 36 min to drive 50 km.
A poll showed that 50.3% of Americans say they believe that some people see the future in their dreams. What is the probability of randomly selecting someone who does not believe that some people see the future in their dreams.
Answer:
The probability of randomly selecting someone who does not believe that some people see the future in their dreams =0.497.
Step-by-step explanation:
Given
Percent of Americans who Say they believe that some people see the future in their dreams=50.3%
Total percentages=100%
Therefore, Number of americans who say they believe that some people see the future in their dreams=50.3
The probability of randomly selecting someone who say they believe that some people see the future in their dreams =[tex]\frac{50.3}{100}[/tex]
Hence, the probability of randomly selecting someone who believe that some people see the future in their dreams, P(E)=0.503
Now, the probability of randomly selecting someone who does not believe that some people see the future in their dreams ,P(E')= 1-P(E)
The probability of randomly selecting someone who does not believe that some people see the future in their dreams =1-0.503
Hence,the probability of randomly selecting someone who does not believe that some people see the future in their dreams=0.497.
Answer: 0.497
Step-by-step explanation:
Let A be the event that Americans believe that some people see the future in their dreams.
Then , the probability that Americans believe that some people see the future in their dreams is given by :-
[tex]P(A)=50.3\%=0.503[/tex]
We know that the complement of a event X is given by :-
[tex]P(X')=1-P(X)[/tex]
Hence, the probability of randomly selecting someone who does not believe that some people see the future in their dreams is
[tex]P(A')=1-P(A)\\\\=1-0.503=0.497[/tex]
Let S={1,2,3,4,5,6}.
How many subsets of cardinality 4 contain at least one odd number?
Answer:
15 subsets of cardinality 4 contain at least one odd number.
Step-by-step explanation:
Here the given set,
S={1,2,3,4,5,6},
Since, a set having cardinality 4 having 4 elements,
The number of odd digits = 3 ( 1, 3, 5 )
And, the number of even digits = 3 ( 2, 4, 6 )
Thus, the total possible arrangement of a set having 4 elements out of which atleast one odd number = [tex]^3C_1\times ^3C_3+^3C_2\times ^3C_2+^3C_3\times ^3C_1[/tex]
By using [tex]^nC_r=\frac{n!}{r!(n-r)!}[/tex],
[tex]=3\times 1+3\times 3+1\times 3[/tex]
[tex]=3+9+3[/tex]
[tex]=15[/tex]
Hence, 15 subsets of cardinality 4 contain at least one odd number.
Suppose your statistics instructor gave six examinations during the semester. You received the following grades (percent correct): 79, 64, 84, 82, 92, and 77. Instead of averaging the six scores, the instructor indicated he would randomly select two grades and compute the final percent correct based on the two percents. How many different samples, without replacement, of two test grades are possible
Answer:
15 samples
Step-by-step explanation:
The total sample space consists of 6 items
{79,64,84,82,92,77}
So,
n=6
The instructor has to randomly select 2 test scores out of 6.
So, r=6
The arrangement of scores selection doesn't matter so combinations will be used.
[tex]C(n,r)=\frac{n!}{r!(n-r)!} \\C(6,2)=\frac{6!}{2!(6-2)!}\\=\frac{6!}{2!*4!}\\=\frac{6*5*4!}{2!*4!} \\=\frac{30}{2}\\=15\ ways[/tex]
Therefore, there are 15 different samples are possible without replacement ..
Use the transforms in section 4.1 to find the Laplace transform of the function. t^3/2 - e^-10t
Answer:
Laplace transformation of [tex]L(t^\frac{3}{2}-e^{-10t})[/tex]=[tex]\frac{3\sqrt{\pi} }{4 s^\frac{5}{2} }\ -\frac{1}{s+10}[/tex]
Step-by-step explanation:
Laplace transformation of [tex]L(t^\frac{3}{2}-e^{-10t} )[/tex]
[tex]L(t^\frac{3}{2})=\int_{0 }^{\infty}t^\frac{3}{2}e^{-st}dt\\substitute \ u =st\\L(t^\frac{3}{2})=\int_{0 }^{\infty}\frac{u}{s} ^\frac{3}{2}e^{-u}\frac{du}{s}=\frac{1}{s^{\frac{5}{2}}}\int_{0 }^{\infty}{u} ^\frac{3}{2}e^{-u}{du}[/tex]
the integral is now in gamma function form
[tex]\frac{1}{s^{\frac{5}{2}}}\int_{0 }^{\infty}{u} ^\frac{3}{2}e^{-u}{du}=\frac{1}{s^{\frac{5}{2}}}\Gamma(\frac{5}{2})=\frac{1}{s^{\frac{5}{2}}}\times\frac{3}{2}\times\frac{1}{2} }\Gamma (\frac{1}{2} )=\frac{3\sqrt{\pi} }{4 s^\frac{5}{2} }[/tex]
now laplace of [tex]L(e^{-10t})[/tex]
[tex]L(e^{-10t})=\frac{1}{s+10}[/tex]
hence
Laplace transformation of [tex]L(t^\frac{3}{2}-e^{-10t})[/tex]=[tex]\frac{3\sqrt{\pi} }{4 s^\frac{5}{2} }\ -\frac{1}{s+10}[/tex]
The Laplace transform of the function [tex]t^3/2 - e^-10t[/tex] is (3/2√π)/[tex]s^5/2 - 1/(s + 10)[/tex].
To find the Laplace transform of the function[tex]t^3/2 - e-10t[/tex], we use the Laplace transform properties and tables.
Refer to the Laplace transform table: Apply to each term: Combine the results: The Laplace transform of the function is L{[tex]t^3/2 - e-10t[/tex]} = (3/2√π)/[tex]s^5/2 - 1/(s + 10)[/tex].A student takes an exam containing 18 multiple choice questions. The probability of choosing a correct answer by knowledgeable guessing is 0.3. If the student makes knowledgeable guesses, what is the probability that he will get between 8 and 12 (both inclusive) questions right? Round your answer to four decimal places.
When you have to repeatedly take the same test, with constant probability of succeeding/failing, you have to use Bernoulli's distribution. It states that, if you take [tex]n[/tex] tests with "succeeding" probability [tex]p[/tex], and you want to "succeed" k of those n times, the probability is
[tex]\displaystyle P(n,k,p) = \binom{n}{k}p^k(1-p)^{n-k}[/tex]
In your case, you have n=18 (the number of tests), and p=0.3 (the probability of succeeding). We want to succeed between 8 and 12 times, which means choosing k=8,9,10,11, or 12. For example, the probability of succeeding 8 times is
[tex]\displaystyle P(18,8,0.3) = \binom{18}{8}(0.3)^8(0.7)^{10}[/tex]
you can plug the different values of k to get the probabilities of succeeding 9, 10, 11 and 12 times, and your final answer will be
[tex]P = P(18,8,0.3) + P(18,9,0.3) + P(18,10,0.3) + P(18,11,0.3) + P(18,12,0.3)[/tex]
Final answer:
In mathematics, calculate the probability of a student guessing between 8 and 12 questions right out of 18 when the probability of guessing correctly is 0.3.
Explanation:
To calculate the probability of getting between 8 and 12 questions right through knowledgeable guessing, we can use the binomial probability formula:
P(k successes in n trials) = nCk × [tex]p^k[/tex] × (1-[tex]p^{(n-k)[/tex])
where:
k = number of successes (correct answers) = 8 to 12
n = total number of questions = 18
p = probability of success (correct answer by guessing) = 0.3
(1-p) = probability of failure (incorrect answer) = 0.7
We need to calculate the probability for each possible number of correct answers between 8 and 12 and then sum them up.
Here's the calculation:
Probability of getting 8 correct:
P(8 successes in 18 trials) = 18C8 ×0.3⁸ × 0.7¹⁰ ≈ 0.076
Probability of getting 9 correct:
P(9 successes in 18 trials) = 18C9 × 0.3⁹ ×0.7⁹ ≈ 0.124
Probability of getting 10 correct:
P(10 successes in 18 trials) = 18C10 ×0.3¹⁰ ×0.7⁸ ≈ 0.122
Probability of getting 11 correct:
P(11 successes in 18 trials) = 18C11 × 0.3¹¹ × 0.7⁷ ≈ 0.072
Probability of getting 12 correct:
P(12 successes in 18 trials) = 18C12 × 0.3¹² × 0.7⁶ ≈ 0.021
Total probability:
P(8 to 12 correct) = 0.076 + 0.124 + 0.122 + 0.072 + 0.021 ≈ 0.415
Therefore, the probability that the student gets between 8 and 12 questions right by knowledgeable guessing is approximately 41.5%.
Convert 3,A5D Base 16 to Base 10
Answer:
14941.
Step-by-step explanation:
In base 16 we have that :
A=10, B=11, C=12, D=13, E=14, F=15 and the process of change is:
3: [tex]3*16^{0}= 3[/tex]
A5D= [tex]10*16^{2}+5*16^{1}+13*16^{0}= 2560+80+13=2653.[/tex]
3A5D = [tex]3*16^{3}+10*16^{2}+5*16^{1}+13*16^{0}= 12288+2560+80+13=14941.[/tex]
if ( 43.65 ) ( 8.79 ) / x = ( 0.4365 ) ( 87.9 ) then value of x is:
(a) .01 (b) 0.1 (c) 1 (d) 10 (e) 100
Answer:
(d)
Step-by-step explanation:
Multiple your numbers out first. This always makes it less hectic to look at. Multiply both sides by x to move the x to the right side. Then divide both sides by ((0.4365)(87.9)). You should get 10.
The reading speed of second grade students in a large city is approximately normal, with a mean of 9090 words per minute (wpm) and a standard deviation of 10 wpm. Complete parts (a) through (f). (a) What is the probability a randomly selected student in the city will read more than 9494 words per minute? The probability is nothing.
Answer: 0.3446
Step-by-step explanation:
Given : Mean : [tex]\mu = 90[/tex]
Standard deviation : [tex]\sigma = 10[/tex]
Also, the reading speed of second grade students in a large city is approximately normal.
Then , the formula to calculate the z-score is given by :_
[tex]z=\dfrac{x-\mu}{\sigma}[/tex]
For x = 94
[tex]z=\dfrac{94-90}{10}=0.4[/tex]
The p-value = [tex]P(z>0.4)=1-P(z<0.4)=1-0.6554217[/tex]
[tex]\\\\=0.3445783\approx0.3446[/tex]
Hence, the probability a randomly selected student in the city will read more than 94 words per minute =0.3446
Solve the system of linear equations, using the Gauss-Jordan elimination method. (If there is no solution, enter NO SOLUTION. If there are infinitely many solutions, express your answer in terms of the parameters t and/or s.)
x + 2y + z = −4
−2x − 3y − z = 2
2x + 4y + 2z = −8
(x, y, z) =
Answer:
The system of linear equations has infinitely many solutions. x=t, y=2-t and z=t-8.
Step-by-step explanation:
The given educations are
[tex]x+2y+z=-4[/tex]
[tex]-2x-3y-z=2[/tex]
[tex]2x+4y+2z=-8[/tex]
Using the Gauss-Jordan elimination method, we get
[tex]\begin{bmatrix}1 & 2 & 1\\ -2 & -3 & -1\\ 2 & 4 & 2\end{bmatrix}\begin{bmatrix}x\\ y\\ z\end{bmatrix}=\begin{bmatrix}-4\\ 2\\ -8\end{bmatrix}[/tex]
[tex]R_3\rightarrow R_3-2R_1[/tex]
[tex]\begin{bmatrix}1 & 2 &1\\ -2 & -3 & -1\\ 0 & 0 & 0\end{bmatrix}\begin{bmatrix}x\\ y\\ z\end{bmatrix}=\begin{bmatrix}-4\\ 2\\ 0\end{bmatrix}[/tex]
Since elements of bottom row are 0, therefore the system of equations have infinitely many solutions.
[tex]0x+0y+0z=0\Rightarrow 0=0[/tex]
[tex]R_2\rightarrow R_2+2R_1[/tex]
[tex]\begin{bmatrix}1 & 2 &1\\ 0 & 1 & 1\\ 0 & 0 & 0\end{bmatrix}\begin{bmatrix}x\\ y\\ z\end{bmatrix}=\begin{bmatrix}-4\\ -6\\ 0\end{bmatrix}[/tex]
[tex]R_1\rightarrow R_1-R_2[/tex]
[tex]\begin{bmatrix}1 & 1 &0\\ 0 & 1 & 1\\ 0 & 0 & 0\end{bmatrix}\begin{bmatrix}x\\ y\\ z\end{bmatrix}=\begin{bmatrix}2\\ -6\\ 0\end{bmatrix}[/tex]
[tex]x+y=2[/tex]
[tex]y+z=-6[/tex]
Let x=t
[tex]t+y=2\rightarrow y=2-t[/tex]
The value of y is 2-t.
[tex](2-t)+z=-6[/tex]
[tex]z=-6-2+t[/tex]
[tex]z=t-8[/tex]
The value of z is t-8.
Therefore the he system of linear equations has infinitely many solutions. x=t, y=2-t and z=t-8.
To solve the system of linear equations using the Gauss-Jordan elimination method, perform row operations on the augmented matrix to obtain the reduced row-echelon form. The solution is x = -2, y = 1, and z = 0.
Explanation:To solve the system of linear equations using the Gauss-Jordan elimination method, we need to perform row operations to transform the augmented matrix into row-echelon form and then into reduced row-echelon form. Let's start by representing the system of equations as an augmented matrix:
[1 2 1 -4; -2 -3 -1 2; 2 4 2 -8]
Performing row operations, you can transform the augmented matrix into reduced row-echelon form, obtaining:
[1 0 0 -2; 0 1 0 1; 0 0 1 0]
The solution to the system is x = -2, y = 1, and z = 0. Therefore, (x, y, z) = (-2, 1, 0).
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Let A be a 5 × 4 matrix with a pivot in each column. Is A invertible? Why or why not?
Answer:
Matrix A is not invertible.
Step-by-step explanation:
Invertible matrix are those matrix which are square matrix or non singular matrix.
For any matrix to be invertible, matrix should be non singular i.e. det(x)[tex]\neq[/tex] 0.
But for the question given above we cannot find determinant of matrix A as it is not square matrix. so inverse of given matrix does not exist. so it is not possible to have non trival solutions.
Find an equation for a circle satisfying the given conditions. (a) Center (-1, 4), passes through (3, 7) (b) The points (7, 13) and (-3, -11) are at the ends of a diameter.
Answer:
Step-by-step explanation:
In order to find the equations we need the circle's general equation:
[tex](x-h)^{2}+(y-k)^{2}=r^2[/tex] where:
(h,k) is the center and 'r' is the radius.
A. Because the center is (-1,4) then h=-1 and k=4.
Now we can find the radius as:
[tex]distance=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}[/tex]
[tex]distance=\sqrt{(3-(-1))^{2}+(7-4)^{2}}[/tex]
[tex]distance=5[/tex] so we have r=5
Then the equation is [tex](x+1)^{2}+(y-4)^{2}=25[/tex]
B. Because we have two points defining a diameter we can find the radius as follows:
[tex]diameter=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}[/tex]
[tex]diameter=\sqrt{(7-(-3))^{2}+(13-(-11))^{2}}[/tex]
[tex]diameter=26[/tex]
[tex]radius=26/2=13[/tex]
Now let's find the center of the circle as follows:
[tex]C=(\frac{x1+x2}{2} , \frac{y1+y2}{2})[/tex]
[tex]C=(\frac{7-3}{2} , \frac{13-11}{2})[/tex]
[tex]C=(2,1)[/tex]
Then the equation is [tex](x-2)^{2}+(y-1)^{2}=169[/tex]
Let X be a continuous random variable with a uniform distribution on the interval open square brackets 0 comma 10 close square brackets. Find straight P open parentheses straight X less than 1 space or space straight X greater than 8 close parentheses.
[tex]X[/tex] has PDF
[tex]f_X(x)=\begin{cases}\frac1{10}&\text{for }0\le x\le10\\0&\text{otherwise}\end{cases}[/tex]
and thus CDF
[tex]F_X(x)=\begin{cases}0&\text{for }x<0\\\frac x{10}&\text{for }0\le x\le10\\1&\text{for }x>10\end{cases}[/tex]
Because [tex]X[/tex] is continuous, we have
[tex]P(X<1\text{ or }X>8)=1-P(1\le X\le8)=1-(P(X\le8)-P(X\le1))[/tex]
[tex]P(X<1\text{ or }X>8)=1-P(X\le 8)+P(X\le1)[/tex]
[tex]P(X<1\text{ or }X>8)=1-F_X(8)+F_X(1)[/tex]
[tex]P(X<1\text{ or }X>8)=1-\dfrac8{10}+\dfrac1{10}=\boxed{\dfrac3{10}}[/tex]
swimsuit buyer reduced a group of designer swimwear from $75.00 to $50.00 for a special sale. If 40 swimsuits sold at the reduced price and the remaining 25 swimsuits were returned to the original price after the sale, calculate the total markdowns, markdown cancellations, and net markdown achieved.
Answer:
The original price is = $75
The reduced price = $50
So, price reduced is = [tex]75-50=25[/tex] dollars
Total swimsuits are = [tex]40+25=65[/tex]
Total markdown = [tex]65\times25=1625[/tex] dollars
Now, 25 swimsuits were returned to the original price. Means 25 swimsuits were returned to $75, increasing $25 again.
So, markdown cancellation = [tex]25\times25=625[/tex] dollars
Net markdown = total markdown - markdown cancellation
= [tex]1625-625=1000[/tex] dollars